Suppose that an object of mass 11.4 g is hung from a vertical spring that is stretched 10 cm as a result. What is the spring constant of this spring, in N/m

Answers

Answer 1
Neglect the mass of spring
Mg = Fspring
11.4 x 10^-3 x 9.8 = 1/2 x k 10^-2
k = 22.344 N/m

Related Questions

Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about:
30 feet
63 feet
40 feet
75 feet

Answers

Answer:

A. 30 feet

Explanation:

Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about 63 feet. Option B is correct.

What is speed?

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity.

Given conditions;

10 miles per hour ⇒ 20 feet

1 mile per hour ⇒ 2 feet

20 miles per hour ⇒ 20 × 2 feet

20 miles per hour ⇒ 20 × 2 feet

20 miles per hour ⇒40 feet

If the stopping distance is more than 20 feet at 10 miles per hour at 20 miles per hour it must be more than 40 feet.So that the correct answer is 63 feet.

Hence option B is correct.

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g The human ear can perceive sounds with frequencies ranging from 20.0 Hz to 20000 Hz. If the speed of sound is 330 m/s in air and 1500 m/s under water, what is the longest and shortest wavelength that can be heard in air and in water

Answers

Answer:  lamda max= 16,5m   lamda min=  0,0165m (air)  

lamda  max= 75m, lamda min=0,075m (water)

Explanatin

name a suitable thermometer for a winter temperature at noth pole?​

Answers

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Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80 a) Explain the different sections of the graph in as much detail as you can. b) Use the graph to determine the maximum velocity. c) Find the average velocity after 45 s. d) Find the instantaneous velocity at 45 s. ​

Answers

Answer:

because I dont know

Explanation:

first you add the multiply

The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.

What is Instantaneous velocity?

Instantaneous velocity = Position with respect to time / Time

1 ) At d = 60 m, the instantaneous velocity is zero because the car is at rest.

2 ) At d = - 40 m, t = 40 s

Instantaneous velocity = - 40 / 40

Instantaneous velocity = - 1 m / s

3 ) At t = 15 s, d = 60 m

At 60 m, the car is at rest, so the Instantaneous velocity is zero

4 ) At t = 25 s, d = 20 m

Instantaneous velocity = 20 / 25

Instantaneous velocity = 0.8 m / s

Instantaneous velocity of a given curve in a position-time graph can be found by drawing a tangent to the curve and finding the slope of the tangent. Instantaneous velocity = 0

Instantaneous velocity = - 1 m / s

Instantaneous velocity = 0

Instantaneous velocity = 0.8 m / s

Therefore, The instantaneous velocity at 60 m is zero, at - 40 m is - 1 m / s, at 15 s is zero and at 25 s is 0.8 m / s if Displacement (m) 0 20 40 40 80 80 60 400 Time (s) 10 10 20 30 40 50 60 70 80.

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A remote-control car has batteries that store 1.8 kJ of energy. When the car is
driven across a sports field there is friction dragging on the car, producing a force
of 2 N.
Complete the following sentence: If the car is 100% efficient, it could travel a
distance of metres on a single battery charge.

Answers

Answer:

Explanation:

Complete the following sentence: If the car is 100% efficient, it could travel a distance of 900 meters on a single battery charge.

    W = Fd

1800 = 2d

     d = 900

Assuming 100 % efficient means turning battery power into motion.

A car totally 100% efficient would have zero friction and could travel an infinite distance on a full battery charge.

jjjjjjjjjjjoooooooooooooooooo

Answers

Answer:

.

Explanation:

a force is something that ___ an object to ____

Answers

Answer:

which can cause an object with mass to change its volocity

d. The soccer player accelerates from rest at a rate of 3.1 m/s2. How far does he
run in 1.5 seconds? (1 point)

Answers

Answer:

= 6.975 m

Explanation:

3.1 m = 1 s2

? = 2.25 s2

(3.1 * 2.25)/1

= 6.975m

Imagine you and a friend are trying to rearrange the furniture in your classroom. You push on a desk with a force of 50 N to the right. Your friend pushes on the same desk with a force of 50 N to the left. What is the net force on the desk?

Answers

Answer:

The net force on the desk is zero.

i really need help with this. cant anyone help me?

Answers

(A)

Explanation:

The number of atoms for each element on the left side must equal that on the right side. Only (A) satisfies that condition. The other other choices have mismatching number of atoms on either side.

Answer each of the following questions regarding energy and heat transfer: ​1. Explain why it is important to understand conductors. ​2. Give a real world example where thermal conductors are used. ​3. Explain why it is important to understand insulators. ​4. Give a real world example where thermal insulators are used. ​5. Suppose you do not have electricity or gas for heating up food and you are hungry. Explain what would you do to maximize thermal energy transfer in this situation to safely cook you something to eat.

Answers

Conduction is the transfer of thermal energy between particles of matter that are touching. Thermal conduction occurs when particles of warmer matter bump into particles of cooler matter and transfer some of their thermal energy to the cooler particles. Conduction is usually faster in certain solids and liquids than in gases. Materials that are good conductors of thermal energy are called thermal conductors. Metals are especially good thermal conductors because they have freely moving electrons that can transfer thermal energy quickly and easily.

A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters. Which of the following best represents the final speed of the race car?

Answers

Answer:

Explanation:

Givens

vi = 10 m/s

a = 1.5 m/s^2

d = 600 m

vf = ?

Formula

vf^2 = vi^2 + 2*a*d

Solution

vf^2 = 10^2 + 2*1.5 * 600

vf^2 = 100 + 1800

vf^2 = 1900

sqrt(vf^2) = sqrt(1900)

vf = 43.59 m/s

100 POINTS PLEASE answer ASAP

Answers

Answer:

uhmmm

Explanation:

uhmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

If a car has a suspension system with a force constant of 5.00x104 N/m, how much energy must the car's shocks remove to dampen an oscillation starting with a maximum displacement of 0.0750 m

Answers

Answer: 140.625

Explanation: Because energy gained due to damped motion and needs to be absorbed

Helium gas is confined within a chamber that has a moveable piston. The mass of the piston is 8.7 kg; and its radius is 0.013 m. If the system is in equilibrium, what is the pressure exerted on the piston by the gas

Answers

Helium gas is in a chamber with a moveable piston, whose mass is 8.7 kg and its radius is 0.013 m. The pressure exerted on the piston by the gas is 1.6 × 10⁵ Pa.

Helium is confined in a chamber with a moveable 8.7-kg piston (m). We can calculate the weight of the piston (w) using Newton's second law of motion.

[tex]w = m \times g = 8.7kg \times 9.8 m/s^{2} = 85 N[/tex]

The radius of the piston (r) is 0.013 m. We can calculate the area of the piston (A) using the following expression.

[tex]A = \pi \times r^{2} = \pi \times (0.013)^{2} = 5.3 \times 10^{-4} m^{2}[/tex]

We can calculate the pressure exerted by the piston (P) using the following expression.

[tex]P = \frac{w}{A} = \frac{85N}{5.3 \times 10^{-4}m^{2} } = 1.6 \times 10^{5} Pa[/tex]

Since the system is in equilibrium, the pressure exerted on the piston by the gas is also 1.6 × 10⁵ Pa.

Helium gas is in a chamber with a moveable piston, whose mass is 8.7 kg and its radius is 0.013 m. The pressure exerted on the piston by the gas is 1.6 × 10⁵ Pa.

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Multiple-Concept Example 10 provides one model for solving this type of problem. Two wheels have the same mass and radius of 4.0 kg and 0.35 m, respectively. One has the shape of a hoop and the other the shape of a solid disk. The wheels start from rest and have a constant angular acceleration with respect to a rotational axis that is perpendicular to the plane of the wheel at its center. Each turns through an angle of 13 rad in 8.0 s. Find the net external torque that acts on each wheel.

Answers

Newton's second law for rotational motion allows finding the net torque for each body is:

Ring torque is:   τ  = 0.199 Nm Solid disc the torque is:   τ  = 0.995 N m

Newton's second law for rotational motion establishes a relationship between the torque, the moment of inertia, and the angular acceleration of the body.

 

               τ = I α

Where τ is the torque, I the moment of inertia and α the angular acceleration.

They indicate that the rotated angle is θ = 13 rad in a time of 8.0 s, let's use the rotational kinematics relations.

           θ = w₀ t + ½ α t²

The body starts from rest, therefore its inertial velocity is zero.

          θ = ½ α t²

          [tex]\alpha =\frac{2 \theta }{t^2}[/tex]  

Let's calculate

            α = [tex]\frac{2 \ 13^2}{8.0^2 }[/tex]

            α = 0.406 rad / s²

The moments of inertia of symmetrical bodies are tabulated:

Ring             I = m R² Solid disc    I = ½ m R²

Let's look for every torque.

Ring

         τ = m R² α

         τ = 4.0 0.35² 0.406

         τ = 0.199 N m

          τ = ½ m R² α

          τ = ½ 4.0 0.35² 0.406

          τ = 0.0995 N m

In conclusion using Newton's second law for rotational motion we can find the net torque for each body is:

Ring torque is:   τ  = 0.199 Nm Solid disc the torque is: τ  = 0.995 N m

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Why did the physicist conclude that cats can be either liquid or solid?

Answers

Answer:

Explanation:

https://www.science.org/content/article/cats-behave-liquids-tampons-play-music-and-other-advances-honored-ig-nobel-prizes

Answer:

Liquid or Both

Explanation:

Cats exist in their own three states of matter: loaf, cinnamon roll, and liquid. The last category is certainly the most confusing because cats should be solids — and of course, they can be.

Please explain what the passage mean in your own words.

Remember the Sabbath day, to keep it holy. Six days shalt thou labor, and do all thy work: But the seventh day is the Sabbath of the Lord thy God: in it thou shalt not do any work, thou, nor thy son, nor thy daughter, thy manservant, nor thy maidservant, nor thy cattle, nor thy stranger that is within thy gates: For in six days the Lord made heaven and earth, the sea, and all that in them is, and rested the seventh day: wherefore the Lord blessed the Sabbath day, and hallowed it.

Answers

Use Speedwrite.com! Type the passages into that website and it’ll put it in its own words!

Could a car drive on a frictionless surface? Explain using the terms action
force and reaction force. *

Answers

Answer:

No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place

A worker pushes 1500N crate with a horizontal force of 345N a distance of 24m.
How much work is done by the Floor on a crate?

Answers

Answer:

8280J

Explanation:

W = f x d

345 x 24 = 8280J

A car equipped with a massless spring in front collides with a stationary car as shown in the diagram. The mass of the incoming car is three times the mass of the target car. While the spring is being compressed, the cars are moving closer together, and while it is expanding they are moving farther apart, but at the instant that the spring is fully compressed, they have no relative motion, which means they are moving at the same speed. At this instant, the cars are moving with a speed of 2.4 m/s.
(a) Find the speed of the incoming car before the collision.
(b) Find the fraction of the system’s energy that is stored in the spring when
it is fully compressed.
(c) Find the final speed and direfction for both cars after the spring expands and the cars separate.

Answers

Answer:

Explanation:

Let m be target car mass

a)

conservation of momentum

(3m)u + m(0) = (3m + m)(2.4)

               3u = 4(2.4)

                u = 3.2 m/s

b)

system energy is originally in the striking car as kinetic energy

KE = ½(3m)3.2² = 15.36m J

at full compression, kinetic energy is

½(3m + m)2.4² = 11.52m J

so spring potential energy fraction of total energy is

(15.36 - 11.52)/15.36 = 0.25 or 25%

c)

The center of mass (CoM) is moving at 2.4 m/s

The CoM sees the larger mass car approach at

3.2 - 2.4 = 0.8 m/s and will see it depart at - 0.8 m/s

so a ground based observer would see it moving at

v₁ = 2.4 + -0.8 = 1.6 m/s in its original direction

The CoM sees the smaller mass car approach at

0 - 2.4 = -2.4 m/s and will see it depart at + 2.4 m/s

so a ground based observer would see it moving at

v₂ = 2.4 + 2.4 = 4.8 m/s in its original direction of the larger car

so the relative velocity of approach at 3.2 - 0 = 3.2 m/s

equals the relative velocity of departure at 4.8 - 1.6 = 3.2 m/s

checks.

Hãy giải thích các khái niệm sau và lấy ví dụ cụ thể để minh họa:
Áp suất chân không tuyệt đối, áp suất tuyệt đối, áp suất khí trời, áp suất dư và áp suất chân
không?

Answers

Hãy giải thích các khái niệm sau và lấy ví dụ cụ thể để minh họa:

A girl sitting on a beach counts six waves passing a buoy in 3.0 s. She measured the distance between the wave crests to be 1.5 meters. What is the speed of the waves the girl observed?​

Answers

wavelength=1.5mTime=3s

[tex]\\ \sf\longmapsto Frequency=\dfrac{1}{Time}=\dfrac{1}{3}=0.33s^{-1}[/tex]

Velocity be v

[tex]\\ \sf\longmapsto v=f\lambda[/tex]

[tex]\\ \sf\longmapsto V=0.33(1.5)[/tex]

[tex]\\ \sf\longmapsto V\approx 0.5ms^{-1}[/tex]

Given,

Wavelength = 1.5 metres

T = 3 seconds OR 3.0 seconds

We know that the formula of Frequency–

1/Time

According to the question we have seen that Time is 3 seconds

[tex] \sf \longmapsto \: Frequency = \frac{1}{3 .0 \: seconds} [/tex]

[tex] \sf \longmapsto \: Frequency = 0.33 seconds^{-1} [/tex]

We Know,

Velocity = Frequency

Solving Further

[tex]\sf \longmapsto Velocity =0.33 \times 1.5 [/tex]

[tex]\sf \longmapsto \: 0.5 \: m/s ^{-1}[/tex]

Therefore the speed is[tex]\sf \: 0.5 \: m/s ^ {-1}[/tex]

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 94.0 cm and diameter 2.75 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g

Answers

Answer:

Explanation:

Wt = ρVg

Wt = ρ(πD²/4)hg

Wt = 7800(π0.0275²/4)0.94(9.81)

Wt = 42.72152359...

Wt = 42.7 N

Please help on question e and F
E- what will be the total charge of the compound formed?

F what type of band will form?

Answers

Answer:

E-MgO(Magnesium Oxide)

what makes the morion mask expensive ? ​

Answers

Answer:

a lot of the masks are hand made a long time ago its really an art

Explanation:

Because it is a piece of art that is hard to craft  

Draw an energy pie chart above each of the cart’s four positions.

i. Choose your reference point for determining height.

ii. Create a pie chart that accurately represents the ratio of the three forms of energy and label the sections of the pie Eg for gravitational potential energy, Ek for kinetic energy, and Eth for thermal energy.

Answers

Answer:

Attached below! Ignore the name please. Thanks!

Explanation:

What is the value of the magnitude of the difference of vectors A and B, |A - B|?

Answers

Answer:

Let, θ be the angle between vector a and vector b.

So, the angle between vector a and vector (-b) must be (180° - θ).

Magnitude of the difference of vectors a and b

= |a - b|

= Magnitude of the resultant of the vector sum of the vectors a and (-b)

= |{√|a|^2 + |b|^2 + 2 * |a| * |b| * cos (180° - θ)}|

= |{√|a|^2 + |b|^2 - 2 * |a| * |b| * (cos θ)}|.

Explanation:

what is the distance between two corresponding points of adjacent waves?

Answers

Answer:Wavelength

Explanation: The wavelength of a wave is the distance between any two corresponding points on adjacent waves.

A car driving at 32.6 miles/hours slowed to a stop in 2.4 seconds
The driver's acceleration was
miles/hour second. Record your answer to two places past the decimal point

Answers

Explanation:

using v=u+at

0=32.6 + (a×(2.4/3600))

-32.6=(a×(2.4/3600))

a=-32.6×3600/2.4

a= -48900miles/hr^2

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