Suppose Stephen breeds snakes and wants to optimize production of offspring with both black bodies and brown eyes, which are coded for by two genes with the recessive alleles b and e, respectively. In snakes, B codes for brown bodies and E codes for red eyes. Stephen crosses two heterozygotes that produce 544 offspring. How many of these 544 offspring are predicted to have both black bodies and brown eyes?
Answers
Answer:
34
Explanation:
B codes for brown bodies.
E codes of red eyes.
b and e together code for black bodies and brown eyes.
Heterozygous brown body snake would have the genotype Bb.
Heterozygous red eyes would have the genotype Ee.
Individuals that are heteozygous for both trait would have the genotype BbEe.
Crossing two heterozygous individuals:
BbEe x BbEe
Progeny:
9 BBEE
3 B_ee
3 bbE_
1 bbee
Recall that black bodies and brown eyes requires be, hence the ratio of the progeny with black bodies and brown eyes is 1/16.
If the total number of offspring produced is 544, the number predicted to have black bodes and brown eyes would be:
1/16 x 544 = 34
Related Questions
*Hedgehogs are nocturnal and hibernate during the winter. Which of the
following is NOT true?
A)Hedgehogs eat insects and worms - they are herbivores
B)Their metabolic rate drops in winter
C)They are nocturnal as many insects are active at night
D)They hibernate as food is scarce in winter
Answers
Iron+Oxygen->Iron Oxide (Rust) 2Fe+302->Fe302 Iron Oxide, formed from Iron and Oxygen, is a new: A.Element B.Atom C.Compound D.Solution
Answers
Answer:
Compound
Explanation:
Different elements react to form a compound
The stimulus interval has a profound effect on the contraction force of the muscle. In your own words explain what happened when the muscle was stimulated in rapid succession. At which interval did the volunteer's muscle twitches begin to merge together (summate)
Answers
Answer:
The skeletal muscle is stimulated by means of action potentials that are caused by the neuromotor plate. These action potentials are one after the other and can become cumulative once the muscle fibers pass the refractory phase of the action potential.
The refractory stage is that stage in which action potentials are not admitted, therefore where the muscle fibers do not accept stimuli to contract.
Once this refractory stage is over, more action potentials can be admitted, which would be summative and the muscle fiber would contract with greater power.
Explanation:
If a muscle is repeatedly stimulated, the contraction will be weaker or the muscle will fatigue more easily, triggering muscle failure.
If the muscle is stimulated with a longer pause between contraction and contraction, the action will be performed with more power.
Every living organism begins life as a single
Answers
Answer: cell
Explanation:
Every living organism begins life as a single cell, usually called a zygote.
In perspective, with Earth being 4,500,000,000 years old and humans being around 1,400,000 years; how long out of a 24 day time period have we as humans been here.
Answers
Answer:
Day time period have we as humans been here: 26 seconds
Explanation:
4,500,000,000 years = 1 day
1,400,000 years = X
X = 0.0003111
1 day = 86,400 seconds
0.0003111 = X
X = 26 seconds
In term of the Earth in 24-hour clock, Homo sapiens appeared on our planet only in the last 26 seconds, it means that in geologic time, humans have existed for only a brief time period and thereby it is a relatively new species.
negatives about gypsy moths?
Answers
Answer:
Gypsy moths do not kill trees directly they defoliate them. Severe defoliation can add to other stresses such as weather extremes or human activities. This cumulative stress can leave trees vulnerable to disease or other pest infestation that can cause death.
Explanation:
I HOPE THIS HELPED YOU PLEASE MARK ME AS BRAINLIEST
Answer:
The rise of the gypsy moth population will eventually kill many trees, as they won’t be able to perform photosynthesis. This event will negatively affect the lumber and construction industries, as well as the beauty of public and private landscapes.
Explanation:
PLATO
Colocar la opción correcta.
a) La caña Colihue:
• Es un ejemplo de individuo y de organización Ecológica
• Es un ejemplo de organismo y pertenece a la organización Biológica
• Es un ejemplo de comunidad
• A y B son correctas
b) Las flores y los tallos:
• Son ejemplos de órganos
• Son ejemplos de organelas
• Son ejemplos de células
• Ninguna es correcta
c) El H20 es un ejemplo de:
• Atomo
• Molécula
• Organela
d) El nitrógeno es un ejemplo de:
• Molécula
• Atomo
• Partícula subatómica
e) El Bosque es un ejemplo de:
• Población
• Ecosistema
• Células vegetales
¡Ayuda, por favor!
Answers
Answer: A y B son correctas
Explanation:
Is it important before a blood transfusion to know blood types? Why? What are the benefits or consequences?
Answers
Answer:
It is extremely important to know all types of blood because if you donate the wrong type of blood to another person, he/she will get sick.
Explanation:
Hemolytic transfusion reactions can cause the most serious problems, but these are rare. These reactions can occur when your ABO or Rh blood type and that of the transfused blood do not match. If this happens, your immune system attacks the transfused red blood cells. This can be extremely life-threatening.
13. Ranchers lobbied the government to eradicate wolves from Yellowstone National Park. Five years later the deer population had increased fivefold. The following winter 70% of the deer starved to death. Explain why this was bound to happen.
Answers
Answer: The overgrowth in deer population led to a food shortage.
Explanation:
Since the eradication of the wolves, the deer had no predator to keep their total population in check. Due to the vast amount of deer the food in the area was being eaten at a faster rate. Most of the deer died do to their environment not being capable of feeding that many deer.
(I hope this helps! I tried my best.)
g One can measure ATP production from isolated mitochondria in vitro (in a test tube). Changing the pH of the solution that the mitochondria are in results in a similar change the pH of the intemembrane space. If the pH of the solution that the isolated mitochondria are in is raised and everything else remains constant, what is the effect on ATP synthesis
Answers
Answer:
This will lead to an decreases in the ATPs synthesis. This is because low pH , high acidity favours ATP synthesis, because it increases the proton concentration for electrochemical gradients needed for energy that ATPase enzymes makes used of synthesis of ATPs.
Therefore a rise in the pH(low acidity) lowers protons levels, and therefore reduced electrochemical gradients , with a drop in energy for ATPs synthesis.
Explanation:
if the ratio of the ages of kisii and esinam is 3:5 and that of Esinam and Larry is 3:5 and the sum of the ages of all three is 147 years what is the age difference between the oldest and the youngest
Answers
Answer:
The age difference between the oldest and the youngest is 48.
Explanation:
Given the following data;
The ratio of the ages of Kisii (K) and Esinam (E) is 3:5.
The ratio of the ages of Esinam (E) and Larry (L) is 3:5.
The sum of the ages of all three is 147.
Since the age of Esinam is common in both ratios, we find the lowest common multiple (LCM);
LCM of 3,5 = 15.
Hence, the ratio of the three ages is now;
K:E:L = 9:15:25
Let their ages be denoted by x;
[tex]K:E:L = 9x:15x:25x[/tex]
The sum of all three ages is;
9x + 15x + 25x = 147
49x = 147
x = 147/49
x = 3.
To find the age difference between the oldest and the youngest;
The oldest is Esinam = 25x
The youngest is Kisii = 9x
Therefore, 25x - 9x = 16x
Substituting the value of x, we have;
x = 3; 16x = 16(3) = 48.
The age difference between the oldest and the youngest is 48.
Why would a drop in blood pH have an undesirable effect on the proximal histidine's function?a. A drop in pH would make deprotonation more likely, and a deprotonated proximal histidine would be able to hydrogen bond to O2 to stabilize its binding to the heme.b. A drop in pH would make protonation more likely, and a protonated proximal histidine would not be able to donate its electron density to the iron atom.c. A drop in pH would make protonation more likely, and a protonated proximal histidine would not be able to hydrogen bond to O2 to stabilize its binding to the heme due to its positive charge.
Answers
Answer:
c. A drop in pH would make protonation more likely, and a protonated proximal histidine would not be able to hydrogen bond to O2 to stabilize its binding to the heme due to its positive charge.
Explanation:
Protonation refers to the addition of proton or H+ to the atom or molecule. If the pH of blood drop means acidic so it causes adverse effect on the function of proximal histidine because the proximal histidine gain proton and become cation. Due to this proton, proximal histidine is unable to make hydrogen bond between heme and oxygen and the blood is unable to transport more oxygen with hemoglobin from the lungs.
In experiment #2 you are asked to use the scientific method to develop and execute a method of separating a mixture of sand, salt and iron pellets. Imagine you are in a lab and notice that a plate of bacteria grow faster in the presence of sunlight. After that single observation, you come to the conclusion that sunlight causes bacteria to grow fast. What would be the next step in the scientific method for this experiment?
Answers
Answer:
1. separation can be done with help of magnetic bar and filtration.
2. the next step will be testing the hypothesis.
Explanation:
1. Separation of iron pellets from sand, and salt first
Use a magnet
Due to magnetic force iron pallets will attach with it and separation will occur from sand and salt.
After separation of iron pallets, add water to mixture of sand and salt and heat until salt get dissolved then filter the salt water.
This will help in separating all three components of mixture to separate.
2. Bacteria growth
Hypothesis must be tested-
In this case a hypothesis and conclusion is represented. Conclusion is provided that in presence of sunlight growth of bacteria is faster. So the hypothesis must be verified by scientific experiment to be a valid theory by measuring or monitoring growth in presence of sunlight.
You are monitoring the metabolism of two different cultures of the same species of yeast, which you have labeled Culture A and Culture B. One of your observations is that Culture A is using up about 10 times the amount of glucose per unit of time as Culture B. Which one of the following conclusions could you reasonably draw regarding these cultures?
A. Culture A would be accumulating lactic acid.
B. Culture A is being grown aerobically; Culture B is being grown anaerobically.
C. Only Culture A is recycling its NADH back to NAD+.
D. Culture A and Culture B are synthesizing the same amount of ATP per unit of glucose in glycolysis.
E. None of the above conclusions could be drawn from the information given.
Answers
Answer: D
Explanation: The experiment was set up using the very same species of yeast labeled differently. What this means is that they are of the same type or kind and thus would exhibit similar features from feeding to the metabolism of the food they take and subsequent production of by-products of the fermentation process. In this regard, therefore, the reasonable conclusion that can be drawn regarding these cultures is that both cultures A and B are synthesizing the same amount of ATP per unit of glucose in glycolysis (the cellular degradation of the simple sugar glucose to yield pyruvic acid, and ATP as an energy source).
Which bests describes a pilus
Answers
Answer:
A tube that extends from a bacterium
Explanation: A tube that extends from a bacterium
Answer:
A tube that extends from a bacterium
Explanation:
A channel protein specific for calcium ions was found to have a pore lined with six glutamate residues that participate in coordinating the calcium ion. What would happen to the selectivity of the pore if the Glu residues were mutated to Asp residues
Answers
Answer:
If the mutation takes place, then the shorter side chains of asp compare to Glu will affect the permeability of the transport protein to calcium ions. Specifically, the mutation will increase the sizes of the pore,which in turn decreases the selectivity for calcium ion. Hence this affect excitability of the cell.
Explanation:
phosphate from atp is removed to make adp and a free phosphate molecule
Answers
Answer:
ATP is a nucleotide consisting of an adenine base attached to a ribose sugar, which is attached to three phosphate groups. ... When one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and ATP is converted to adenosine diphosphate (ADP).
Which of the following statements is FALSE?
a.The Moon usually sets about 12 hours after it rises.
b.The Moon rises in the west and sets in the east.
c.The Full Moon rises around sunset.
d.The Moon takes a little more than 29 days to orbit the Earth.
The answer is b
Answers
Answer:
the answer is b
Explanation:
the sun sets in the south
Why is carbon the element of life?
Answers
Answer:
the ability to form stable bonds
2. Is salt water alkaline or acidic?
Answers
Answer: hh
Explanation:hhh
Why do sex-linked traits follow different patterns of inheratance than other traits
Answers
Answer:
Males and females have different sex chromosomes.
Explanation:
Sex Linked trait is controlled by the chromosomes while other traits are controlled by autosomes. The autosomal cells and traits have a constant characteristics in a human being. The chromosomal cells however vary. The male chromosome XY is different from the female chromosome XX.
This is the reason why sex-linked traits follow different patterns of inheratance than other traits as a result of the Males and females having different sex chromosomes is valid.
There are two different alleles for flower color, P and p. The image shows a purple sweet pea that is labeled with its two alleles for petal color. A purple sweet pea is labeled Upper P Upper P. Which is the genotype of the sweet pea?
Answers
Answer:
There is no diagram but the question can be answered using the description. The options to this question are:
Which is the genotype of the sweet pea?
A.heterozygous dominant
B.heterozygous recessive
C.homozygous dominant
D.homozygous recessive
The answer is C (homozygous dominant)
Explanation:
According to the question, a flower colour gene in a pea plant possesses two different alleles, P and p. Lettercase is used to illustrate that allele P (upper case) is dominant over allele p (lowercase) i.e P will be expressed over p in the flower colour gene.
According to the question, the pea plant exhibits a purple flower colour and is labelled as PP. This genotype is said to be homozygous because the same alleles (P) make up the plant's genotype. Since the allele P coding for purple coloration is dominant, the purple sweet pea is said to be HOMOZYGOUS dominant i.e. possess the same dominant alleles for that gene.
Answer:
[C] H D
(Brainly Marked It As An Inappropriate Word)
Explanation:
See Below
please send me labeled scorpion
Answers
Which statement about enzymes is true?
An enzyme functions to increase the activation energy in a reacton.
Enzymes are proteins that function as catalysts in nonliving things.
Each enzyme can catalyze many different biochemical reactions.
Enzymes and substrates fit together like a lock and key.
Answers
Answer:
Enzymes and substrates fit together like a lock and key since, in one enzymatic reaction, only the correct substrate (i.e., the key) binds to its corresponding enzyme (i.e. the lock).
Explanation:
An enzyme (or catalyst) is one protein that has catalytic functions, being therefore capable of accelerating chemical reactions. The enzymes are known to control the rate of these chemical reactions (i.e., catalysis) without suffering alterations during these processes. Thus, the enzymes are proteins that catalyze chemical reactions that are not favored under normal conditions. Moreover, one enzyme may catalyze more than one chemical transformation, as well as the same reaction may be catalyzed by two or more enzymes.
Assume that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. Further assume that each allele represented by an uppercase letter contributes 4 g to weight and that each allele represented by a lowercase letter contributes 1 g to weight. If a plant with genotype AA BB is crossed with a plant with genotype aa bb, what weights are expected in the F_a progeny?
A. 1 g
B. 4 g
C. 8 g
D. 10 g
Answers
Answer: choice D. 10g
Explanation:
The cross is AABB x aabb so the F1 progeny would have AaBb genotype.
The question states that dominant alleles(uppercase letters) contribute 4g and recessive ones contribute 1g to the weight of the plant.
so for AaBb we would have 4+1+4+1=10g.
Answer:
D.
Explanation:
Which of the following is a type of action, assistance, or information that a genetic counselor can provide? Check all that apply.
Calculate the risk of a child inheriting a genetic disorder.
Look for patterns of inheritance in a client’s family history.
Prescribe a medication to help with a client’s anxiety.
Explain causes and inheritance patterns of a genetic disorder.
Recommend the best of several long-term options for a client.
Explain what genetic tests are available and what information they would provide.
Interview a client to obtain details of the family’s medical and genetic history.
Order a test to be done without the client’s approval if it would provide useful information.
Answers
Answer: Calculate the risk of a child inheriting a genetic disorder.
Look for patterns of inheritance in a client’s family history.
Explain causes and inheritance patterns of a genetic disorder.
Recommend the best of several long-term options for a client.
Explain what genetic tests are available and what information they would provide.
Interview a client to obtain details of the family’s medical and genetic history.
Explanation:
The genetic counseling will involve the following steps:
1. The counselors check the family medical history and medical records of parents to estimate the chances of inheritance of genetic disorder or disease in a developing fetus.
2. The counselors order genetic testing.
3. The counselors evaluate the results of the tests.
4. They counsel parents based on the results and recommend them the long term options to prevent the effect of disease.
Answer:
1 2 4 6 7
Explanation:
Through logic and the prosess of elimenation I found the answers.
Samples of the octapeptide AVGWRVKS are subjected to proteolytic cleavage by either trypsin or chymotrypsin. Select the most appropriate technique for separating the digestion products of AVGWRVKS if cleaved by trypsin. salting out gel‑filtration chromatography dialysis ion‑exchange chromatography Select the most appropriate technique for separating the digestion products of AVGWRVKS if cleaved by chymotrypsin.
A. dialysis
B. gel‑filtration chromatography
C. ion‑exchange chromatography
D. salting out
Answers
Answer:
If cleaved by trypsin you will need to do gel-filtration, if cleaved by chymotrypsin you will need to do ion-exchange.
Explanation:
What are compounds called that form H+ ions when dissolved in water?
Answers
Answer:
Acid
At the simplest definition, an acid is any compound that yields hydrogen ions (H +) or hydronium ions (H 3O +) when dissolved in water. Hydronium ions are really the combination of H + ions and H 2O molecules
Explanation:
The color of the mustard plant in Lab 4 (Natural Selection) was determined by a single gene with two alleles (Y or y). The Y allele was dominant to y allele, and Y gave us a green plant, and yy a yellow-green plant. You measure the following genotype frequencies: YY = 0.5; Yy = 0.25; yy = 0.25. You calculate the following Hardy-Weinberg Frequencies: YY = 0.30; Yy = 0.56; yy = 0.14 This population looks like it has evolved. We can tell this because : Group of answer choices
Answers
Answer and Explanation:
It occurs evolution whenever the allelic frequencies in the genic pool change. If the population is not in Hardy-Weinberg equilibrium, it is because one, some, or several of the model's assumptions are not met. If we want to know if a population is evolving, we must observe the frequencies of the population, and if they change over time. If there is a change, it might also be reflected in the phenotypic frequencies.
In the exposed example there was an evident change in the population genetic frequencies.
1) Genotype frequencies: YY = 0.5; Yy = 0.25; yy = 0.25
Genic or Alleleic frequency:
Frequency of y= f(q)= √0.25 =0.5Frequency of Y= f(p)= 1- 0.5 =0.52) Hardy-Weinberg Frequencies: YY = 0.30; Yy = 0.56; yy = 0.14
Genic or Alleleic frequency:
Frequency of y= f(p)= √0.14 =0.374
Frequency of Y= f(p)= 1- 0.5 =0.626
The allelic frequencies and hence the genotypic frequencies changes, so we can assume that there was evolution.
I need the answers to this question super quick!! Thank yoh
Answers
Answer:
They are "anti" condons or "stop" condons
Explanation:
