Solve the equation.

[tex]\sqrt{(x+2)(x-3)} =0[/tex]

Answer:

Step-by-step explanation:

[tex]\sqrt{(x + 2)(x - 3)} = 0 \\\\ (x + 2)(x - 3) = 0 \\\\\ x^2 - 3x + 2x - 6 = 0 \\\\ x^2 - x - 6 = 0 \\\\ \Delta = (- 1)^2 - 4.1.(- 6) \\\\ \Delta = 1 + 24 \\\\ \Delta = 25 \\\\ x_1 = \frac{1 + \sqrt{25}}{2} = \frac{ 1 + 5}{2} \\\\\ x_1 = 3 \\\\\\ x_2 = \frac{1 - \sqrt{25}}{2} \\\\\\ x_2 = \frac{1 - 5}{2} \\\\\ x_2 = - 2[/tex]

S = {x E R/x = 3 and x = - 2}

I hope I've helped you

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