Answer:
x= -19
Step-by-step explanation:
2x-4x-9=29
-2x=29+9
x=38/-2
= -19
Answer:
[tex]x=2-\sqrt{42}[/tex] and [tex]x=2+\sqrt{42} \\[/tex]
Step-by-step explanation:
Solve using the quadratic formula, which is [tex]x=\frac{-b + \sqrt{b^{2}-4ac }}{2a}[/tex] and [tex]x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}[/tex]
tan 12 = 22/x
Please help !!! Last answer says 4.7
Answer:
103.5
Step-by-step explanation:
Multiply x on both sides
xtan12 = 22
Now divide tan12 to isolate x
x = (22) / (tan(12))
Now we know that calculator should be in degree mode because the answer choices do not have the radian mode answer. When your calculator is in Degree mode and you calculate this value you get approximately 103.5
The value of x if tan 12 = 22/x is 103.5
Given the trigonometric expression:
tan 12 = 22/x
We need to get the value of "x"
Cross multiply
x tan12 = 22
x = 22/tan12
x = 22/0.2126
x = 103.529
Hence the value of x if tan 12 = 22/x is 103.5
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What’s the correct answer for this?
Answer:
B. The radius
Step-by-step explanation:
The area of a sector of a circle is ½ r² ∅, where r is the radius and ∅ the angle in radians subtended by the arc at the centre of the circle so we need to know the radius for it
Whats the theorum called for working out the missing side of a triangle?
Answer:
The Pythagorean Theorum
Step-by-step explanation:
you can literally search it and see that it is right!
A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric fence. With 1100 m of wire at your disposal, what is the largest area you can enclose, and what are its dimensions?
Answer:
Length = 550 m
Width = 275 m
Area = 151,250 m2
Step-by-step explanation:
One side of the farmland is bounded by the river, so the perimeter we will need to enclose is:
[tex]Perimeter = Length + 2*Width = 1100\ m[/tex]
And the area of the farmland is given by:
[tex]Area = Length * Width[/tex]
From the Perimeter equation, we have that:
[tex]Length = 1100 - 2*Width[/tex]
Using this in the area equation, we have:
[tex]Area = (1100 - 2*Width) * Width[/tex]
[tex]Area = 1100*Width - 2*Width^2[/tex]
Now, to find the largest area, we need to find the vertex of this quadratic equation, and we can do that using the formula:
[tex]Width = -b/2a[/tex]
[tex]Width = -1100/(-4)[/tex]
[tex]Width = 275\ m[/tex]
This width will give the maximum area of the farmland. Now, finding the length and the maximum area:
[tex]Length = 1100 - 2*Width = 1100 - 550 = 550\ m[/tex]
[tex]Area = Length * Width = 550 * 275 = 151250\ m2[/tex]
Eleanor can drive an average of 374 Miles on one tank of gas. How many miles can she drive on 15 tanks of gas
Answer:
5,610 Miles
Step-by-step explanation:
To solve this you would need to multiply the average miles by how many tanks of gas she will use.
374 * 15 = 5,610
So, Eleanor can drive 5,610 miles with 15 tanks of gas.
James makes fruit punch by mixing fruit jucie and lemonade in the ratio 1:4 she needs to make 40 liters of punch for a party How much of each ingredient does she need? Fruit juice ? Liters Lemonade ?liters
Part 2
During the party Josie decides to make some more.
She has 4 litres of fruit juice left and plenty of lemonade.
How much extra punch can she make?
Part 3
To make the second batch of punch go further Josie adds 2 more litres of lemonade.
What is the ratio of fruit juice to lemonade in the second batch?
Answer:
Part 1.
Juice = 8 L.
Lemonade = 32 L.
Part 2.
20 L punch Josie can make.
Part 3.
New ratio juice : lemonade = 2 : 9
Step-by-step explanation:
Part 1.
1+4 = 5 parts altogether, 1 parts for juice and 4 parts for lemonade.
40 : 5 = 8 L is 1 part.
Juice - 1 part - 8 L.
Lemonade - 4 parts - 4*8 = 32 L.
Part 2.
1 parts of juice needs 4 parts of lemonade
4 L of juice needs x L of lemonade
1 : 4 = 4 : x
x = 4*4/1 = 16 L lemonade
4+ 16 = 20 L punch Josie can make
Part 3.
It was 4 L of juice and 16 L of lemonade.
After 2 L lemonade was added, we have 4 L of juice and (16+2) = 18 L of lemonade.
4 L juice : 18 L lemonade = 4/2 L juice : 18/2 L lemonade =
= 2 L juice: 9L lemonade
New ratio juice : lemonade = 2 : 9
In a study investigating the effect of car speed on accident severity, 5000 reports of fatal automobile accidents were examined, and the vehicle speed at impact was recorded for each one. For these 5000 accidents, the average speed was 42 mph and the standard deviation was 15 mph. A histogram revealed that the vehicle speed at impact distribution was approximately normal.
a. Roughly what proportion of vehicle speeds were between 27 and 57 mph?
b. Roughly what proportion of vehicle speeds exceeded 57 mph?
Answer:
(a) Roughly 68% of vehicle speeds were between 27 and 57 mph.
(b) Roughly 16% of vehicle speeds exceeded 57 mph.
Step-by-step explanation:
We are given that in a study investigating the effect of car speed on accident severity, 5000 reports of fatal automobile accidents were examined.
For these 5000 accidents, the average speed was 42 mph and the standard deviation was 15 mph.
Let X = vehicle speed at impact
SO, X ~ Normal([tex](\mu=42,\sigma^{2} = 15^{2}[/tex])
Here, [tex]\mu[/tex] = population average speed = 42 mph
[tex]\sigma[/tex] = standard deviation = 15 mph
Since, the distribution is approximately normal; so the 68-95-99.7 empirical rule states that;
68% of the data values lies within one standard deviation points.95% of the data values lies within two standard deviation points.99.7% of the data values lies within three standard deviation points.(a) Since, it is stated above that 68% of the data values lies within one standard deviation points, that means;
68% data values will lie between [ [tex]\mu-\sigma , \mu+\sigma[/tex] ] , i.e;
[ [tex]\mu-\sigma , \mu+\sigma[/tex] ] = [42 + 15 , 42 - 15]
= [57 , 27]
So, it means that roughly 68% of vehicle speeds were between 27 and 57 mph.
(b) We have observed above that roughly 68% of vehicle speeds were between 27 and 57 mph which leads us to the conclusion that (100% - 68% = 32%) of the data values will be outside this range.
It is stated that of this 32%, half of the data values will be less than 27 mph and half of the data values will be more than 57 mph.
This means that roughly 16% of vehicle speeds exceeded 57 mph.
George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at the easternmost point. The illustration below shows their starting positions and running directions. They start running toward each other at constant speeds. George runs at 9 feet per second. Paula takes 50 seconds to run a lap of the track. George and Paula pass each other after 14 seconds.
After running for 4 minutes, how far east of his starting point is George?
Answer:
George is 43.20 ft East of his starting point.
Step-by-step explanation:
Let Paula's speed be x ft/s
George's speed = 9 ft/s
Note that speed = (distance)/(time)
Distance = (speed) × (time)
George takes 50 s to run a lap of the track at a speed of y ft/s
Meaning that the length of the circular track = y × 50 = 50y ft
George and Paula meet 14 seconds after the start of the run.
Distance covered by George in 14 seconds = 9 × 14 = 126 ft
Distance covered by Paula in 14 seconds = y × 14 = 14y ft
But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track
That is,
126 + 14y = 50y
50y - 14y = 126
36y = 126
y = (126/36) = 3.5 ft/s.
Hence, Paula's speed = 3.5 ft/s
Length of the circular track = 50y = 50 × 3.5 = 175 ft
So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of
9 × 240 = 2160 ft.
2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.
Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft
So, 60 ft along a circular track subtends an angle θ at the centre of the circle.
Length of an arc = (θ/360°) × 2πr
2πr = total length of the circular track = 175
r = (175/2π) = 27.85 ft
Length of an arc = (θ/360) × 2πr
60 = (θ/360°) × 175
(θ/360°) = (60/175) = 0.343
θ = 0.343 × 360° = 123.45°
The image of this incomplete lap is shown in the attached image,
The distance of George from his starting point along the centre of the circular track = (r + a)
But, a can be obtained using trigonometric relations.
Cos 56.55° = (a/r) = (a/27.85)
a = 27.85 cos 56.55° = 15.35 ft
r + a = 27.85 + 15.35 = 43.20 ft.
Hence, George is 43.20 ft East of his starting point.
Hope this Helps!!!
At the beginning of the week, Josh had 32 computer games, 133% as many computer games than Peter had. By the end of the week, Josh gave Peter 25% of his computer games. How many computer games did Josh and Peter each have bythe end of the week?
a. Josh had 8 games; Peter had 24 games.
b. Josh had 24 games; Peter had 8 games.
c. Josh had 24 games; Peter had 32 games.
d. Josh had 32 games; Peter had 24 games.
Answer:
The correct answer is letter c. Josh had 24 games and Peter had 32 by the end of the week.
Step-by-step explanation:
We know that Josh has a total of 32 games, while that value is 133% as many as Peter's, therefore the number of games Peter had at the beginning of the week is:
[tex]josh = \frac{133}{100}*peter\\peter = \frac{josh}{1.33}\\peter = \frac{32}{1.33}\\peter = 24.06[/tex]
At the beginning of the week Peter had 24 games. At the end of the week Josh gave Peter 25% of his games, therefore Peter's total is:
[tex]peter = 24 + 0.25*josh\\peter = 24 + 0.25*32\\peter = 24 + 8 = 32[/tex]
While Josh had:
[tex]josh = 32 - 8 = 24[/tex]
The correct answer is letter c.
PLEASE HELP ME!!! (WILL MARK BRAINLIEST!
Answer:
A) 13/20
Step-by-step explanation:
65% in simplest form,
65/100
= 13/20 (Divided by five)
Answer:
[tex]\frac{13}{20}[/tex].
Step-by-step explanation:
We can begin by converting 65% to a fraction over 100. 65% converts to 0.65, or [tex]\frac{65}{100}[/tex].
We can simplify this down. Both 65 and 100 share a common factor of 5, which allows us to produce a new fraction:
[tex]\frac{65}{100} = \frac{13}{20}[/tex]
Therefore, the simplified version is [tex]\frac{13}{20}[/tex].
................
...
...
Answer:
C............PAC-MAN
Step-by-step explanation:
a cereal box is an example of a
Answer: recantagle
Step-by-step explanation:
Simplify the number into simplest radical form.
Answer:
4 sqrt(6)
Step-by-step explanation:
sqrt(96)
We know sqrt(ab) =sqrt(a) sqrt(b)
sqrt(16*6)
sqrt(16) sqrt(6)
4 sqrt(6)
Please help will mark brainliest.
Answer:
parallel lines both have slope 1/3; non-parallel lines both have length 5
Step-by-step explanation:
It generally works well to follow instructions.
A graph of the points shows you that the parallel sides are RA and PT. The difference between the end points of these segments are ...
A - R = (6, 8) -(-3, 5) = (9, 3) = (Δx, Δy)
So, the slope of RA is Δy/Δx = 3/9 = 1/3
And the other difference and slope are ...
P -T = (9, 4) -(-3, 0) = (12, 4) ⇒ Δy/Δx = 4/12 = 1/3
The slope of RA is the same as the slope of PT, so those segments are parallel.
__
The length of segment TR can be found from the differences of the end point coordinates:
R - T = (-3, 5) -(-3, 0) = (0, 5)
Since these points are on the same vertical line, this tells us the segment length is 5.
The other difference of coordinates is ...
A - P = (6, 8) -(9, 4) = (-3, 4)
The distance formula tells us the length of AP is then ...
AP = √((-3)² +4²) = √25 = 5
Non-parallel sides TR and AP have the same lengths, so the trapezoid is isosceles.
In the diagram below, AB is parallel to CD. What is the value of x?
А. 150
В. 60
С. 120
D. 30
Answer:
x=150 because these are supplementary angles
The radius of a circle is 10.7 m. Find the circumference
to the nearest tenth.
Answer:
2 x [tex]\pi[/tex] x 10.7 = 67.2
Step-by-step explanation:
Step-by-step explanation:
c=2πr
c=2×π×10.7m
c=67.2m
so about 67
11 — 9y = — 6у +8
solve for y
pleaseee
Answer:
-The value of [tex]y[/tex]:
[tex]y = 1[/tex]
Step-by-step explanation:
-Find the value of [tex]y[/tex]:
[tex]11- 9y = -6y + 8[/tex]
-Add both sides by [tex]6y[/tex] and combine [tex]9y[/tex] and [tex]6y[/tex] together:
[tex]11- 9y + 6y = -6y + 6y+ 8[/tex]
[tex]11 - 3y = 8[/tex]
-Subtract both sides by [tex]11[/tex]:
[tex]11 - 11 - 3y = 8 -11[/tex]
[tex]-3y = -3[/tex]
-Divide both sides by [tex]-3[/tex]:
[tex]\frac{-3y}{-3} = \frac{-3}{-3}[/tex]
[tex]y = 1[/tex]
So the final answer is [tex]y = 1[/tex] .
Determine the discriminant for the quadratic equation -3=x2+4x+1. Based on the discriminant value, how many real number
solutions does the equation have?
Discriminant = b2-4ac
0
1
2
o 12
Save and Exit
Next
Submit
Mark this and return
le
Step-by-step explanation:
work is shown and pictured
The discriminant of quadratic equation is,
⇒ D = 0
What is Quadratic equation?
The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. The quadratic equation has the following generic form: ax² + bx + c = 0
We have to given that;
Quadratic equation is,
⇒ - 3 = x² + 4x + 1
Now, We can write as;
⇒ x² + 4x + 1 + 3 = 0
⇒ x² + 4x + 4 = 0
Hence, Discriminant of quadratic equation is,
⇒ D = b² - 4ac
⇒ D = (4)² - 4×1×4
⇒ D = 16 - 16
⇒ D = 0
Thus, The discriminant of quadratic equation is,
⇒ D = 0
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In a large population, 64% of the people have been vaccinated. If 5 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated? Give your answer as a decimal to 4 places.
Answer:
0.9940
Step-by-step explanation:
P(at least 1) = 1 − P(zero)
P(at least 1) = 1 − (1 − 0.64)⁵
P(at least 1) = 1 − (0.36)⁵
P(at least 1) = 0.9940
The probability that at least one of them has been vaccinated is 0.9939.
What is binomial distribution?
The binomial distribution is the discrete probability distribution that gives only two possible results in an experiment, either success or failure. It helps to check the probability of getting “x” successes in “n” independent trials of a binomial experiment.
For the given situation,
Number of people vaccinated = 64% = 0.64
The formula of binomial distribution is
[tex]P(x:n,p) = nC_{x} p^x (1-p)^{n-x}[/tex]
Here x is the number of successes, x ≤ 1
n is the number of trials, n = 5
p is the probability of a success on a single trial, p = 0.64 and
where, [tex]nC_{x}=\frac{n!}{x!(n-x)!}[/tex]
The probability is [tex]P(X \leq 1)=1-P(X=0)[/tex]
[tex]P(X=0)= 5C_{0} (0.64)^{0} (1-0.64)^{5-0}[/tex]
⇒ [tex]P(X=0)= 1(1) (0.36)^{5}[/tex]
⇒ [tex]P(X=0)= 0.0060[/tex]
Thus, [tex]P(X \leq 1)=1-P(X=0)\\[/tex]
⇒ [tex]P(X \leq 1)=1-0.0060[/tex]
⇒ [tex]P(X \leq 1)=0.9939[/tex]
Hence we can conclude that the probability that at least one of them has been vaccinated is 0.9939.
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(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proportions of boys and girls under 10 years old who are afraid of spiders. Assume the "worst case" scenario for the value of both sample proportions. We want a 99% confidence level and for the error to be smaller than 0.08.
(b) Again find the sample size required, as in part (a), but with the knowledge that a similar student last year found that the proportion of boys afraid of spiders is 0.7 and the proportion of girls afraid of spiders was 0.69.
Answer:
a) The size of each of the two samples(equal), n = 518
b) Sample size, n = 439
Step-by-step explanation:
For clarity and easiness of expression, the complete solution to this question is handwritten and attached as files. Check the attached files below for the explanations.
Any help would be greatly appreciated.
There are 300 raffle tickets.
The prizes are as follows:
First prize - voucher for meal at local restaurant
Second prize - food hamper
Third prize - chocolate cake
4x homemade jams
3x homemade pickles
A prize is won after the first raffle ticket is drawn.
What is the probability of winning a prize when the next ticket is drawn?
Answer: 0.007
Step-by-step explanation:
Suppose that you have a ticket.
We have 3 prizes, and 300 tickets.
After the first tiket is drawn, someone win a prize, so now we have 299 tikets left and 2 prizes left.
Then, for the next draw, you have p = 1/299 of wining a prize.
If you did not win there, the probability for the third price is p = 1/298 (because there are 2 less tickets now)
Then the probability of winning at least one prize is:
P = 1/299 + 1/298 = 0.007
In this diagram, BAC – EDF. If the
area of BAC = 24 in2, what is the
area of EDF?
Help please
If the area of ΔBAC = 24 in², the area of ΔEDF is 6 in².
What are similar triangles?If two triangles' angles are congruent and their corresponding sides are proportionate, they are considered similar. To put it another way, similar triangles are the same in shape but not necessarily in size. If ΔPQR and ΔMNO are two similar triangles, then we can write it as ΔPQR ∼ ΔMNO.
Statement:The square of the ratio of any pair of their respective sides is equal to the ratio of the areas of two similar triangles.
How to solve this problem?Since ΔBAC ∼ ΔEDF, we can use the above statement to find the area of ΔEDF. Let the area of ΔEDF be x in². Given that length of EF and BC is 2 in and 4 in respectively.
So, we have to solve this equation,
24/x = 4²/2²
Now, 24/x = 16/4
i.e. 24/x = 4
i.e. 4x = 24
i.e. x = 24/4 = 6
Therefore the area of ΔEDF is 6 in².
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What is the simplified value of the exponential expression 27 1/3 ?
1/3
1/9
3
9
Answer:
3
Step-by-step explanation:
27^1/3 = cuberoot(27) = 3
What is the equation of the line perpendicular to y = 2/3x+1that passes through the point (12, -6)?
Answer:[tex]y=-\frac{3}{2} x+12[/tex]
Step-by-step explanation:
Perpendicular lines have inversely proportional slopes. So make the slope negative and switch it to its reciprocal.
2/3x would change into -3/2x
Lets write that down for a starting point for our perpendicular line.
y = -3/2x + b
We were given the x and y value via the coords. x = 12 and y = -6
Now we have -6 = -3/2(12) + b. Multiply -3 and 12 to get -36, then divide by 2 to get -18. Now it's -6 = -18 + b. Solve for b by adding 18 to both sides to get b = 12
Can someone help me with this worksheet? Will give all my points.
Answer:
Here are the formulas
Cube/Rectangular Prism:
Volume = Length*width*height
Surface area = 2(wl+hl+hw)
Lateral area= Area of vertical faces
Base area = length*width
Regular hexagonal prism:
Volume : (3sqrt3/2)*a^2*h
Surface Area = 6ah+3sqrt(3)a^2
lateral area: 6ah
base area = 3sqrt(3)s^2/2
Triangular prism
Volume: The volume of a triangular prism can be found by multiplying the base times the height.
Surface area: A triangular prism has three rectangular sides and two triangular faces. To find the area of the rectangular sides, use the formula A = lw, where A = area, l = length, and h = height. To find the area of the triangular faces, use the formula A = 1/2bh, where A = area, b = base, and h = height.
Etc.
I need HELP PLEASE HELP ME
Answer:
Graph 2
Step-by-step explanation:
You can see that all the shaded numbers are above negative 25 in that graph. Hope this helped!
Which table represents a function?
Answer:
The bottom left table
Step-by-step explanation:
the same x value cannot have different y values
1960 were polled. 279 of them preferred Rock and Roll. What is the % of these students?
Answer:
14.2% students
Step-by-step explanation:
279 / 1960 = 0.142
0.142 x 100% = 14.2 %
Round 90.2844097979 to 3 decimals
Answer:
only allow 3 decimals
90.284 is the answer we removed all others except for 3
What’s the correct answer for this?
Answer:
C
Step-by-step explanation:
Measure of Arc FED = 51+79
= 130°
Since the measures of arcs and angles are the same
Hence
<FED = 130°