Solve for x

3(x+2)+4(x-5)=10

Answer:

120

Step-by-step explanation:

200 ÷ 5 = 40

40 × 3 = 120

there r 120 boys

Answer:

120

Step-by-step explanation:

200 ÷ 5 = 40

40 × 3 = 120

Answer:

7:50

Step-by-step explanation:

Mr. Wellborn arrives 50 minutes before 8:40 so that means you subtracts 50 minutes from 8:40. 8:40-50=7:50

Therefore, the answer is 7:50

Hope this helps

Answer:

The answer is 7:50 A.M

Step-by-step explanation:

First we know that 50 is less than 40 so we subtract one hour. that get 50 so the answer is 7:50!

By the way, the person who answered this is a 3rd grader!  If the answer is worng am sorry i tried my best.

Answer:

12 pounds of grapes cost $18.00

Step-by-step explanation:

The point, (12, 18) as plotted on the graph indicates that 12 pounds of grapes costs $18.

From the graph, we see that when x (pounds) = 12, y (cost) = 18.00.

Answer:

26 inches

Step-by-step explanation:

Answer:

[tex]\frac{1}{4}[/tex]

Step-by-step explanation:

15+20+25=60

15/60=[tex]\frac{1}{4}[/tex]

Answer:

i think its 4x

Step-by-step explanation:

hope it helps

Answer:

the estimated area of the fountain is 147.58 square yards and the estimated area of the path is 28.26 square yards

Step-by-step explanation:

#platolivesmatter

your welcome!!!

The area of the fountain is 147.58 square yards, and the area of the path is 28.25 square yards.

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the center.

Given

a circular fountain,

radius of fountain  = √47 yards

area of  fountain = πr²

area = π(√47)²

area = 147.58 square yards.

and fountain surrounded by a circular path,

which form a concentric circle with fountain,

the radius of the circular path from center of the fountain = √56 yards

area of the path = total area with radius √56 - an area of fountain

area of the path = π(√56)² - 147.58

area of the path = 175.84 - 147.58

area of the path = 28.26 square yards

Hence the area of the fountain is 147.58 square yards,

area of path = 28.25 square yards.

Learn more about circles;

https://brainly.com/question/29142813

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Answer:

[tex]\frac{2}{3}[/tex] (9 + 12) > 15 * [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

[tex]\frac{2}{3}[/tex] (9 + 12) = [tex]\frac{2}{3}[/tex] * 21 = 2 * 7 = 14

15 * [tex]\frac{2}{3}[/tex] = 5 * 2 = 10

14 > 10 ⇒ [tex]\frac{2}{3}[/tex] (9 + 12) > 15 * [tex]\frac{2}{3}[/tex]

Answer:

Determine the null and alternative hypotheses :  STEP 1

Draw a conclusion about the unknown  population using what is known about the sample :  STEP 4

Determine the probability at which you will conclude that the sample outcome is very unlikely :  STEP 2

Draw a random sample and calculate the sample statistic : STEP 3

Step-by-step explanation:

The correct order of the steps are :

Determine the null and alternative hypotheses :  STEP 1

Draw a conclusion about the unknown  population using what is known about the sample :  STEP 4

Determine the probability at which you will conclude that the sample outcome is very unlikely :  STEP 2

Draw a random sample and calculate the sample statistic : STEP 3

Answer:

184 in.^2

Step-by-step explanation:

The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.

area of circle

[tex]A_{circle} = \pi r^2[/tex]

[tex] \pi r^2 = 46 [/tex]

[tex] r^2 = \dfrac{46}{\pi} [/tex]

[tex] r = \sqrt{\dfrac{46}{\pi}} [/tex]

[tex] r = 3.83 ~in.[/tex]

surface area of sphere

[tex] SA = 4 \pi r^2 [/tex]

[tex] SA = 4 \times \pi \times (3.83)^2 [/tex]

[tex] SA = 184~in.^2 [/tex]

Answer:

I hope u can sleep more

Step-by-step explanation:

Answer:

ohhhhhhh

Step-by-step explanation:

yea that sucks but why can't you go to bed until 8-9?????

Answer:

The total surface area of a regular pyramidis the sum of the areas of its lateralfaces and its base. The general formula for thelateral surface area of a regular pyramidis where p represents the perimeter of thebase and SI the height of inclination.

Answer:  

Your efficiency is 80%. N is 400

Step-by-step explanation:

I hope I helped :)

Would appreciate Brainliest ;)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Have a lovely day and good luck with your school work!

I believe the answer is 400, 80%

have a blessed day!

Answer:

1 is correct 2 is correct 3 is correct  And Thats all i know

Step-by-step explanation:

Answer:

11 pounds

Step-by-step explanation:

Just divide the cats weight by 2 and then add 2

(18)/2 + 2

Answer:

1.3/20   2.4/20 or 1/5   3.9/27 or 1/3

Step-by-step explanation:

I hope this helped!

Answer:

7 hours

Step-by-step explanation:

The formular of percentile is given as;

n = (P / 100) * N

where;

n = ordinal rank

P = Percentile

N = Number of values

The grades are given as;

5.5,  7,  6,  7, 6.5,  6,  9 , 6.5,  6.5 , 6.5

Arranging in increasing order;

5.5, 6, 6, 6.5, 6.5, 6.5, 6.5, 7, 7, 9

n = (81/100) * 10 = 8.1 ≈ 8

The 81st percentile is the 8th term.

The 8th term = 7

Answer:

A -5 i think is correct

Step-by-step explanation:

ytfgg

Answer:

-6

Step-by-step explanation:

h(x) = -3x – 12 becomes h(-2) =  -3(-2) – 12 = -6

Answer:

20

Step-by-step explanation:

Answer:

7 units

Step-by-step explanation:

Answer:

$3.50

Step-by-step explanation:

14 ÷ 4 = 3.5

good luck, i hope this helps :)

Answer:

The standard deviation of this probability distribution is 1.2.

Step-by-step explanation:

We have that:

P(X = 0) = 0.25

P(X = 1) = 0.3

P(X = 2) = 0.1

P(X = 3) = 0.35

Mean:

Each value multiplied by its probability. So

[tex]M = 0*0.25 + 1*0.3 + 2*0.1 + 3*0.35 = 1.55[/tex]

Variance:

Sum of the squares of the values subtracted from the mean, and multiplied by its probability.

[tex]V = 0.25*(0-1.55)^2 + 0.3*(1-1.55)^2 + 0.1*(2-1.55)^2 + 0.35*(3-1.55)^2 = 1.4475[/tex]

Standard deviation:

Square root of the variance. So

[tex]S = \sqrt{V} = \sqrt{1.4475} = 1.2[/tex]

The standard deviation of this probability distribution is 1.2.

Answer:

240cm

Step-by-step explanation:

Answer:

don't know

Step-by-step explanation:

umm

Answer:

answer is 0

Step-by-step explanation:

Answer:

its the second and third option

Step-by-step explanation:

I took the test

In order to multiply a matrix by another matrix, we multiply the rows in the first matrix by the columns in the other matrix (How this is done is shown below)

To determine the pairs of matrices that AB=BA, we will determine AB and BA for each of the options below.

For the first option

[tex]A= \left[\begin{array}{cc}1&0&-2&1&\end{array}\right]; B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times5)+(0\times3)&(1\times0)+(0\times 2)&(-2\times5)+(1\times3)&(-2\times0)+(1\times2)&\end{array}\right]\\AB= \left[\begin{array}{cc}5+0&0+0&-10+3&0+2&\end{array}\right]\\AB = \left[\begin{array}{cc}5&0&-7&2&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(5\times1)+(0\times-2)&(5\times0)+(0\times 1)&(3\times1)+(2\times-2)&(3\times0)+(1\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}5+0&0+0&3+-4&0+2&\end{array}\right]\\BA = \left[\begin{array}{cc}5&0&-1&2&\end{array}\right] \\[/tex]

∴ AB≠BA

For the second option

[tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]; B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times3)+(0\times6)&(1\times0)+(0\times -3)&(-1\times3)+(2\times6)&(-1\times0)+(2\times-3)&\end{array}\right]\\AB= \left[\begin{array}{cc}3+0&0+0&-3+12&0+-6&\end{array}\right]\\AB = \left[\begin{array}{cc}3&0&9&-6&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(3\times1)+(0\times-1)&(3\times0)+(0\times 2)&(6\times1)+(-3\times-1)&(6\times0)+(-3\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}3+0&0+0&6+3&0+-6&\end{array}\right]\\BA = \left[\begin{array}{cc}3&0&9&-6&\end{array}\right] \\[/tex]

Here AB = BA

For the third option

[tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]; B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times5)+(0\times3)&(1\times0)+(0\times 2)&(-1\times5)+(2\times3)&(-1\times0)+(2\times2)&\end{array}\right]\\AB= \left[\begin{array}{cc}5+0&0+0&-5+6&0+4&\end{array}\right]\\AB = \left[\begin{array}{cc}5&0&1&4&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(5\times1)+(0\times-1)&(5\times0)+(0\times 2)&(3\times1)+(2\times-1)&(3\times0)+(2\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}5+0&0+0&3+-2&0+4&\end{array}\right]\\BA = \left[\begin{array}{cc}5&0&1&4&\end{array}\right] \\[/tex]

Here also, AB=BA

For the fourth option

[tex]A= \left[\begin{array}{cc}1&0&-2&1&\end{array}\right]; B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\[/tex]

[tex]AB= \left[\begin{array}{cc}(1\times3)+(0\times6)&(1\times0)+(0\times -3)&(-2\times3)+(1\times6)&(-2\times0)+(1\times-3)&\end{array}\right]\\AB= \left[\begin{array}{cc}3+0&0+0&-6+6&0+-3&\end{array}\right]\\AB = \left[\begin{array}{cc}3&0&0&-3&\end{array}\right] \\[/tex]

and

[tex]BA= \left[\begin{array}{cc}(3\times1)+(0\times-2)&(3\times0)+(0\times 1)&(6\times1)+(-3\times-2)&(6\times0)+(-3\times1)&\end{array}\right]\\BA= \left[\begin{array}{cc}3+0&0+0&6+6&0+-3&\end{array}\right]\\BA = \left[\begin{array}{cc}3&0&12&-3&\end{array}\right] \\[/tex]

Here, AB≠BA

Hence, it is only in the second and third options that AB = BA

[tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right] B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\[/tex] and [tex]A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\[/tex]

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