solve ... 5x + 4 < 3 - 3x

A wheel is a circle.

Given diameter of wheel = 2.8 m

Then radius of the wheel = 2.8/2 = 1.4 m

Now we know that , circumference of circle =[tex]2\pi r[/tex]

Circumference of wheel = 2 × 22/7 × 1.4

Circumference of wheel = 8.8 m

From the above we can conclude that ;

1 revolution = 8.8 m

x revolution = 484 km = 484000 m

[tex]x = \frac{1}{8.8} \times 484000 \\ \\ x = 55000[/tex]

Answer: 50 pairs.

Step-by-step explanation:

For each pair of earrings, Joshua spends $0.29 + $0.11 in materials.

So he spends $0.40 for each pair of earrings.

If he has $20, we want to know how many times he can spend $0.40.

For this, we take the quotient:

$20/$0.40 = 50

This means that we can sperate $20 into 50 times $0.40.

So he can buy enough material to make 50 pairs of earrings.

Answer:

The answer is B

Step-by-step explanation:

Answer:

d) [tex](\sqrt[8]{(10} )^{3 x}[/tex]

Step-by-step explanation:

Step(i):-

Given   [tex](\sqrt{10} )^{\frac{3 x}{4} }[/tex]

we will use formula

  [tex](a)^{m n} = (a^{m} )^{n}[/tex]

[tex](\sqrt{10} )^{\frac{3 x}{4} } =( (10)^{\frac{1}{2} } )^{\frac{3 x}{4} }[/tex]

              = [tex]( (10)^{\frac{1}{2} X\frac{3 x}{4} } )[/tex]

             = [tex]( (10)^{\frac{3 x}{8} } )[/tex]

            = [tex]((10)^{\frac{1}{8} } )^{3x}[/tex]

Step(ii):-

  we will  apply [tex](a)^{\frac{1}{n} } = \sqrt[n]{a}[/tex]

           = [tex](\sqrt[8]{(10} )^{3 x}[/tex]

Answer:

a) 17, 29, 41, 53, 65....

b) 12n + 5

Answer:

Option (1).

Step-by-step explanation:

Given  functions are f(x) = [tex]\frac{1}{x}[/tex] and g(x) = x - 2

(fog)(x) = f[g(x)]

By substituting g(x) in place of x in the function f(x),

f[g(x)] = [tex]\frac{1}{(x-2)}[/tex]

Graph of the function f[g(x)] will have,

Vertical asymptotes : x = 2

Horizontal asymptotes : y = 0

And no oblique asymptotes.

Out of four options graph number (1) matches the given characteristics of the function.

Therefore, graph (1) will be the answer.

Answer:

Original figure: (-6,-5)

final figure: (-6, 5)

Step-by-step explanation:

the point would fall at (-6, 5) because it is reflecting across the x-axis (the horizontal one) and since it is the original point is 5 away from the x-axis, the final point would be at 5 as well. the y-coordinate doesn't change because it is only reflecting over the x-axis. the shape would essentially be flipped if you reflected it over the x-axis, so the point would be on the bottom of the figure instead of the top. Hope this helps I tried my best to explain!

[tex] \dfrac{126}{21} = \dfrac{2 \times 3 \times 3 \times 7}{3 \times 7} = 6[/tex]

Answer: 6

Answer:

Range={ -5,-1,3,7). [ option C]

Please see the attached picture for full solution..

Hope it helps..

Good luck on your assignment..

Answer:

2.7 x 10⁻³

6.1 x 10⁵

9.582 x 10⁶

Step-by-step explanation:

The first digits part should be more or equal 1 and less 10

Answer:

Step-by-step explanation:

B c and d

Answer:

-5/3

Step-by-step explanation:

Answer:

27/35 is the exact answer

7/10 is an estimate

Step-by-step explanation:

4/7+2/10

Simplify the fraction

4/7+1/5

The common denominator is 35

4/7*5/5 + 1/5 *7/7

20/35 + 7/35

27/35

To estimate

4/7 is close to 1/2  

2/10 is close is 1/5

1/2 + 1/5 =

5/10 + 2/10 = 7/10

Answer:

The product x time y is zero (0)

Step-by-step explanation:

Notice that you are given a system of two equations with two unknowns, so, let's proceed to find the unknowns by the method of substitution (easiest since it is very simple to find "y" in terms of 'x" from the second equation).

Then we use that expression to substitute for "y" in the first equation and solve for x:

[tex]6x=42+y\\y=6x-42\\Then:\\2x-9y=14\\can\,\,be\,\,written\,\,as:\\2x-9(6x-42)=14\\2x-54x+372=14\\-52x=-364\\x=(-364)/(-52)\\x=7[/tex]

Now we use this result in the substitution equation to find the value of "y":

[tex]y=6x-42\\y=6\,(7)-42\\y=42-42\\y=0[/tex]

Then, the product x times y is:   7 times 0 = 0

The product renders zero (0)

Answer:

Section A

Volume of the cylindrical tool = 1413.72cm³

Section B

1) Curved Surface Area of the right circular cone = 251.33cm²

2) Volume of the right circular cone = 402.12cm³

Step-by-step explanation:

Section A

We are asked to find the volume of the cylindrical moulding tool.

Volume of a cylinder = πr²h

From the question, the cylindrical tool had a diameter of 10cm. This means the radius of the tool = Diameter ÷ 2 = 10cm ÷ 2 = 5cm

The height of the cylindrical tool = 18cm

Volume of the cylindrical tool = π × (5cm)² × 18cm

1413.7166941cm³

Approximately = 1413.72cm³

Section B

The height of a right circular cone is 6cm and its radius is 8cm.

1) Calculate its curved surface area.

The formula for the curved surface area of a right circular cone =

πrl

r = radius = 8cm

h = height = 6cm

l = √(r² +h²) = √(8² + 6²) = √100

l = 10cm

The curved surface area = πrl

= π × 8cm × 10cm

= 251.33cm²

2) Calculate the volume of the cone.

The formula for the volume of a cone=

1/3πr²h

radius (r) = 8cm

height (h) = 6cm

1/3πr²h

1/3 × π × 8² × 6

= 402.12cm³

Answer:

Yes they are equal. Hkama d d jans ans

Answer:

y < -2

Step-by-step explanation:

2y < -4

Divide both sides by 2.

y < -2

Answer:

y <-2. :::::::::::::::::::::::

Step-by-step explanation:

2y< -4 ==> y<-2

Answer:

[tex] \frac{ - 300}{49} [/tex]

or -6.122

Step-by-step explanation:

In answering this kind of questions, you must take note of BODMAS. that is;

B - Bracket

O - Of (multiplication)

D - Division

M - Multiplication

A - Addition

S - Subtraction

and you have to answer by the order above to get the correct answer. thank you

hope it helps .

Answer:

-6 176/189

Step-by-step explanation:

-8÷+12×9-4×6÷56÷7×2​=

-8÷108- 24÷56÷14=

-2/27-24×14÷56=

-2/27- 48/7=

-7 + 1/7- 2/27=

-7 + (27-14)/27*7=

-7+ 13/189=

-6 176/189

Answer:

Answer number one, x < 7/12

Answer:

A

Step-by-step explanation:

If you make he denominators equal to each other (in this case 12) the new fractions would be 3/12 and 10/12. Then you would subtract 3/12 from both sides making 7/12 on the right side. The inequality remains facing the same direction, making the answer A or x<7/12.

Answer:

a

Step-by-step explanation:

100n^2 = (10n^2)

-1 = -(1^2)

Answer:

So we can ignore the endings because they all have to same endings. We know that 10^2 = 100 We see only 2 answers that have that a and b. But we also need to get the n to the power. So we power each number in the parenthesis by 2. Only A lets you power both 10 and n at the same time.

Answer & Step-by-step explanation:

(5√2 - 4√3)(5√2 - 4√3)

We can rewrite this equation into a more simpler form.

(5√2 - 4√3)²

Now, we multiply. When multiplying, its important we multiply each term instead of combining them together.

When you multiply a radical by itself, then the base number will be by itself as the product.

So......

(5)² = 25

(4)² = 16

(√2)² = 2

(√3)² = 3

So, now the equation looks like this..

(25 * 2) + (16 * 3)

Multiply the terms.

50 + 48

Add the numbers.

50 + 48 = 98

So, your answer will be answer choice D. The radical in choice D represents the radicals that are in the problem multiplied together.

Answer:

Left side simplifies to (-2/3)^1 and the right side simplifies to (-2/3)^(-n) which means 1 = -n so n = -1.

Answer:

(8-5)/(7-2)= 3/5

Step-by-step explanation:

proper fraction

Answer:

35 and 21

Step-by-step explanation:

the sum of the two lengths of two sides must be greater than the length of the third side.

10+30=40

45 doesn't work: 40<45.

10+19=29

29<30

19 doesn't work

10+21=31

31>30

21 works

35+10=45

45>30

35 also works

Answer:

35 and 21, good luck!! sorry I'm late

Answer:

C

Step-by-step explanation:

Substitute the x- coordinate into f(x) and if the value is equal to the y- coordinate of the point then the point is on the graph.

A (0, 18)

f(0) = 3 × [tex]6^{0}[/tex] = 3 × 1 = 3 ≠ 18 ← not on graph

B (18, 1 )

f(18) = 3 × [tex]6^{18}[/tex] ≠ 1 ← not on graph

C  (1, 18 )

f(1) = 3 × [tex]6^{1}[/tex] = 3 × 6 = 18 ← on the graph

D (0, 0 )

f(0) = 3 × [tex]6^{0}[/tex] = 3 × 1 = 3 ≠ 0 ← not on graph

Answer:

6x+3

Step-by-step explanation:

8x+7-2x-4

Combine like terms

8x -2x   + 7-4

6x            +3

Answer:

Some examples of integers are -1, 0, and 1.

Answer:

21

Step-by-step explanation:

since we are looking for the value of x, we make it the subject of the formula(stand alone) and to do that + 13 would have to cross over the equality sign.when a positive number crosses over the equality sign it changes to a negative number .

Therefore,x +13=34

x=34 -13

x=21(d)

___________________________

Hey!!

Solution

4a+6=12-2a

or,4a+2a=12-6

or,6a=6

or,a=6/6

a=1

The value of a is 1.

hope it helps...

Good luck on your assignment

_________________________

value of 6a = 6* 1 = 6

In a linear equation coefficients can be positive or negative values and in which the highest power of the variable is always 1 .

according to question the linear equation given is :

4a + 6 = 12 - 2a

find = 6a ?

4a + 6 = 12 - 2a

6a = 12 - 6

6a = 6

a = 1

since , substituting value of a

6a = 6* 1 = 6

learn more about linear equation :

https://brainly.com/question/11897796?referrer=searchResults

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Answer:

[tex]=-\left(3x-1\right)\left(x-3\right)[/tex]

Step-by-step explanation:

[tex]10x-3-3x^2\\\mathrm{Factor\:out\:common\:term\:}-1\\=-\left(3x^2-10x+3\right)\\\mathrm{Factor}\:3x^2-10x+3:\quad \left(3x-1\right)\left(x-3\right)\\3x^2-10x+3\\\mathrm{Write\:in\:the\:standard\:form}\:ax^2+bx+c\\=3x^2-10x+3\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(3x^2-x\right)+\left(-9x+3\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}3x^2-x\mathrm{:\quad }x\left(3x-1\right)\\3x^2-x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\=3xx-x[/tex]

[tex]\mathrm{Factor\:out\:common\:term\:}x\\=x\left(3x-1\right)\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-9x+3\mathrm{:\quad }-3\left(3x-1\right)\\-9x+3\\\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3\\=-3\cdot \:3x+3\\\mathrm{Factor\:out\:common\:term\:}-3\\=-3\left(3x-1\right)\\=x\left(3x-1\right)-3\left(3x-1\right)\\\mathrm{Factor\:out\:common\:term\:}3x-1\\=\left(3x-1\right)\left(x-3\right)\\=-\left(3x-1\right)\left(x-3\right)[/tex]