Answer:
M = 17 M
Explanation:
Given data:
Mass of sodium hydroxide = 678.57 g
Volume of solution = 1.00 L
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of sodium hydroxide:
Number of moles = mass/molar mass
Number of moles = 678.57 g /40 g/mol
Number of moles = 17 mol
Molarity:
M = 17 mol/1.00 L
M = 17 mol/L
M = 17 M
How many grams of C2H6 are needed to react with 54 grams of O2?
Answer:
Explanation:
in a combustion of ethane 2 moles of ethane react with 7 moles of O2
now no of moles in 54 gram of O2=mass/ molar mass
moles =54/32=1.7 moles
if 7 moles of O2 required 2 moles of ethane then 1.7 mole required=?
7 moles of O2=2 moles of C2H6
1.7 moles of O2=1.7*2/7=0.5 moles of C2H6
0.5 moles of C2H6 contain how much grams=?
mass= moles*molar mass=0.5*30=15
the number of moles in 4.5 x10^24 atoms of oxygen is?
Answer:
The answer is 7.48 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\ [/tex]
From the question we have
[tex]n = \frac{4.5 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 7.475083056...[/tex]
We have the final answer as
7.48 molesHope this helps you
What type of relationship exists between two organisms when one organism benefits from the relationship and the other organism becomes prey? (4 points)
a
Commensalism
b
Competition
c
Mutualism
d
Predation
.
.
[tex]
\bold{\huge{\fbox{\color{red}{answer}}}}[/tex]
b competition .
hope it helps u
Ammonia, NH3 is a common base with Kb of 1.8 X 10-5. For a solution of 0.150 M NH3:
Write the equation for the ionization of ammonia in water.
List all species present in the solution AND determine the concentrations of each.
Determine the pH of this solution.
The concentrations : 0.15 M
pH=11.21
Further explanationThe ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
[tex]\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}[/tex]
[tex]\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21[/tex]
How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?
a. 45 mL of a 0.10 M solution:
mL
b. 330 mL of a 0.074 M solution:
mL
Answer:
a. Approximately [tex]1.3\; \rm mL[/tex].
b. Approximately [tex]7.2\; \rm mL[/tex].
Explanation:
The unit of concentration "[tex]\rm M[/tex]" is equivalent to "[tex]\rm mol \cdot L^{-1}[/tex]", which means "moles per liter."
However, the volume of both solutions were given in mililiters [tex]\rm mL[/tex]. Convert these volumes to liters:
[tex]\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L[/tex].
[tex]\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L[/tex].
In a solution of volume [tex]V[/tex] where the concentration of a solute is [tex]c[/tex], there would be [tex]c \cdot V[/tex] (moles of) formula units of this solute.
Calculate the number of moles of [tex]\rm NaCl[/tex] formula units in each of the two solutions:
Solution in a.:
[tex]n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol[/tex].
Solution in b.:
[tex]n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol[/tex].
What volume of that [tex]3.4\; \rm M[/tex] (same as [tex]3.4 \; \rm mol \cdot L^{-1}[/tex]) [tex]\rm NaCl[/tex] solution would contain that many
For the solution in a.:
[tex]\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L[/tex].
Convert the unit of that volume to milliliters:
[tex]\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL[/tex].
Similarly, for the solution in b.:
[tex]\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L[/tex].
Convert the unit of that volume to milliliters:
[tex]\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL[/tex].
1.562 g sample of the alcohol CH3CHOHCH2CH3 is burned in an excess of oxygen. What masses of H2O and CO2 should be obtained
Answer:
[tex]m_{CO_2}=3.709gCO_2 \\\\m_{H_2O}=1.898gH_2O[/tex]
Explanation:
Hello.
In this case, since the molecular formula of the given alcohol is C₄H₁₀O (molar mass = 74.14 g/mol), we can write its combustion reaction as shown below:
[tex]C_4H_1_0O+6O_2\rightarrow 4CO_2+5H_2O[/tex]
Thus, since there is a 1:4 mole ratio with carbon dioxide (molar mass = 44..01 g/mol) and a 1:5 mole ratio with water (molar mass = 18.02 g/mol), we can compute the obtained masses as shown below:
[tex]m_{CO_2}=1.562gC_4H_1_0O*\frac{1mol}{74.14gC_4H_1_0O} *\frac{4molCO_2}{1molC_4H_1_0O} *\frac{44.01gCO_2}{1molCO_2}=3.709gCO_2 \\\\m_{H_2O}=1.562gC_4H_1_0O*\frac{1mol}{74.14gC_4H_1_0O} *\frac{5molH_2O}{1molC_4H_1_0O} *\frac{18.02gH_2O}{1molH_2O}=1.898gH_2O[/tex]
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which shows the correct order of stelps during the formation of an ionic bond
Answer:
The third one
Explanation:
When sodium atoms (Na) and chlorine atoms (CI) join to make
Answer: Potassium and fluorine
Explanation:
The two rows form bonds the easiest
Answer: #1
Explanation:
Determine the wavelength of the energy that needs to be absorbed for a 3p electron in chlorine to be promoted to the 4s subshell. Assume that Zeff=6 for a chlorine atom.
Answer:
The wavelength of the energy that needs to be absorbed = 52.36 nm
Explanation:
For this study;
Let consider the Rydgberg equation from Bohr's theory of atomic model:
i.e.
[tex]\dfrac{1}{\lambda} = R_H (Z^*)^2( \dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})[/tex]
where
Z* = effective nuclear charge of atom = Z - σ = 6
n₁ = lower orbit = 3
n₂ = higher orbit = 4
[tex]R_H[/tex] = Rydyberg constant = 1.09 × 10⁷ m⁻¹
λ = wave length of the light absorbed
∴
[tex]\dfrac{1}{\lambda} = 1.09 \times 10^7}(6)^2( \dfrac{1}{3^2}-\dfrac{1}{4^2})[/tex]
[tex]\dfrac{1}{\lambda} = 1.09 \times 10^7}(36)( \dfrac{1}{9}-\dfrac{1}{16})[/tex]
[tex]\dfrac{1}{\lambda} = 392400000\times0.0486111111[/tex]
[tex]\dfrac{1}{\lambda} =19075000[/tex]
[tex]\lambda = \dfrac{1}{19075000}[/tex]
[tex]\lambda = \dfrac{1}{1.91\times 10^7 \ m^{-1}}[/tex]
[tex]\lambda = 5.236 \times 10^{-8} m[/tex]
[tex]\lambda = 52.36 \times 10^{-9} m[/tex]
[tex]\lambda = 52.36\ n m[/tex]
Therefore, the wavelength of the energy that needs to be absorbed = 52.36 nm
Which macro nutrient is made up of carbon and hydrogen elements join together in long groups called hydrocarbons?
Answer:
organic molecules made up of carbon and hydrogen elements joined together in long groups called hydrocarbons. The arrangement of these hydrocarbon chains, and their interaction with each other, determines fat type.
The study of chemicals and their bond is called chemistry.
The correct answer is lipid.
Those molecules which are present in the cell more than the amount of 800 daltons are called macromolecules.
According to the question, the correct answer is lipid because in lipid all the molecules are made up of a long chain of carbon and hydrogen join together.
For example, palmitic is made up of 16 carbon compounds.
Hence, the correct answer is lipid.
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How many molecules (or atoms) of tin (IV) nitrate would contain 6.17 moles of
oxygen atoms?
Answer:
3.01 x 10²³ molecules
Explanation:
Given parameters:
Number of moles of oxygen atoms = 6.17moles
Unknown:
Number of molecule of tin(IV) nitrate = ?
Solution:
To solve this problem, let us write the formula of tin (IV) nitrate;
N₄O₁₂Sn
Now,
12 moles of Oxygen can be found in 1 mole of N₄O₁₂Sn
6.17 moles of oxygen will be found in [tex]\frac{6.17}{12}[/tex] = 0.5mole of N₄O₁₂Sn
So;
1 mole of a substance contains 6.02 x 10²³ molecules
0.5 mole of N₄O₁₂Sn will contain 0.5 x 6.02 x 10²³ = 3.01 x 10²³ molecules
In the Energy and Specific Heat lab, what temperature should be recorded as the final temperature of the water when measuring the food sample
Answer:
The final temperature of the water when measuring the food sample is: The temperature of the water when the food sample has finished burning completely.
Explanation:
When measuring the food sample in energy and specific heat lab, it is pertinent to note that there is an initial temperature and even while still burning, the temperature gradually increases. But since we are dealing with final, temperature, what we need is basically the final temperature of the water when the food has finished burning. This is so because that's the final temperature of the water as once the food sample has finished burning and you turn off the heat source, the temperature will start to gradually reduce from then on.
What is the coefficient of oxygen gas after balancing the following equation?
WILL GIVE 50 POINTS AND BRAINLIEST
Plate Tectonics Lab Report
Instructions: In the Plate Tectonics lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name Boundary Type
(C=Convergent, D=Divergent, or T=Transform) Year Observed
(5, 10, or 20 million years) Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas 5 Event 1-
20 Event 2-
Location Two
East Africa 5 Event 1-
10 Event 2-
20 Event 3-
Location Three
San Andreas fault zone 5 Event 1-
10 Event 2-
20 Event 3-
Location Four
Aleutian Islands 5 Event 1-
20 Event 2-
Location Five
Mid-Atlantic Ridge 5 Event 1-
10 Event 2-
20 Event 3-
Location Six
Alpine Fault 5 Event 1-
20 Event 2-
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
What types of geological events or changes occur at divergent plate boundaries?
What types of geological events or changes occur at convergent plate boundaries?
What types of geological events or changes occur at transform plate boundaries?
Explain how these geological processes and interactions have changed Earth's surface through the years. Be sure to use evidence to support your answer.
Answer:
here are what i have so far, im doing this right now
Explanation:
Plate Tectonics Lab Report
Instructions: In the Plate Tectonic lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. Y
Objective(s):
To look at interactions between continental and oceanic plates, etc.
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select three events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
• earthquakes
• mountains
• volcanoes
Location Two: Select three events that you predict will be observed. If explore two continental plates at a divergent boundary, then I will observe:
• ocean formation
• volcanoes
• seafloor spreading
you will submit your completed report
ps; you might want to change up the objective.
A geological event is a brief, spatially diverse, dynamic and ongoing occurrence in the history of the Earth.
What is geological event?A geological event is a brief, spatially diverse, dynamic (diachronous), and ongoing occurrence in the history of the Earth that aids in the modification of the Earth system and the production of geological strata. The concept of event stratigraphy initially came up as a way to identify, analyse, and correlate how significant physical and biological events have affected the overall stratigraphical record.
Israel's Dead Sea basin Holocene sediments contain seismic activity. This can be considered a record of a geological event, an earthquake, that altered the strata. Geological events can occur over timescales of order of magnitude, from just a few seconds through millions of years, as well as on a variety of spatial scales, from the local to the globe.
1. Volcanoes and minor earthquakes
2. Volcanoes, earthquakes and fold mountains.
3. Earthquakes and fold mountains.
4. Magma from volcanoes is filled with nutrients that makes land fertile.
Therefore, a geological event is a brief, spatially diverse, dynamic and ongoing occurrence in the history of the Earth.
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What two subatomic particles add up to make the mass?
calculate the number of atom of K element in 122.5g of KClO3
Answer:
6.022×10²³ atoms of K
Explanation:
Given data:
Mass of KClO₃ = 122.5 g
Number of atoms of K = ?
Solution:
First of all we will calculate the number of moles of KClO₃ .
Number of moles = mass/molar mass
Number of moles = 122.5 g/ 122.5 g/mol
Number of moles = 1 mol
One mole of KClO₃ have 1 mole of K atoms.
Number of atoms of K:
1 mole = 6.022×10²³ atoms of K
Thus in 122.5 g of KClO₃ 6.022×10²³ atoms of K are present.
Suppose 100 ml of hydrochloric acid is neutralized by exactly 46.9ml of 0.75M lithuim hydroxide . What is the concentration of the hydrochloric acid?
Answer:
0.0035M
Explanation:
Given parameters
Volume of HCl = 100mL = 0.1L
Volume of LiOH = 46.9mL = 0.0469L
Molarity of LiOH = 0.75M
Unknown:
Concentration of hydrochloric acid = ?
Solution:
The reaction equation is given as;
HCl + LiOH → LiCl + H₂O
Let us find the number of moles of the given specie which is LiOH;
Number of moles = molarity x volume;
Number of moles of LiOH = 0.75 x0.0469 = 0.035moles
From the balanced reaction equation;
1 mole of LiOH combines with 1 mole of HCl
0.035mole of LiOH will require 0.035mole of HCl
Concentration of HCl = [tex]\frac{number of moles of HCl}{volume of HCl}[/tex]
Concentration of HCl = [tex]\frac{0.035}{0.1}[/tex] = 0.0035M
An overhead view of two people at the start of a maze. The person in a purple shirt has a line running forward, right, backward, right, forward, ending with an arrowhead pointing to a large gold star. The person in a green shirt has a line running forward, right, backward, right, forward, right, backward, right, forward, ending with an arrowhead pointing to a small gold star.
Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m east, and 4 m north. Talia walked 2 m north, 6 m east, 3 m south, 4 m east, and 4 m north.
Compare their distances:
Zamir walked
meters and Talia walked
Answer:
Zamir walked
27
meters and Talia walked
19
meters.
Explanation:
27 and 19
Answer:
zamir:27 Talia:19
Explanation:
i got it right on my test :)
Calculate the volume in ) of 0.100 M Na2CO3 needed to produce 1.00 g of CaCO 3 (s) . There is an excess of CaCl 2. What’s the volume of sodium carbonate?
Answer:
100 mL of Na2CO3
Explanation:
We'll begin by calculating the number of mole in 1 g of CaCO3. This can be obtained as follow:
Mass of CaCO3 = 1 g
Molar mass of CaCO3 = 100.09 g/mol
Mole of CaCO3 =?
Mole = mass /Molar mass
Mole of CaCO3 = 1/100.09
Mole of CaCO3 = 0.01 mole
Next, we shall determine the number of mole of Na2CO3 needed to produce 0.01 mole of CaCO3.
This is illustrated below:
Na2CO3 + CaCl2 —> 2NaCl + CaCO3
From the balanced equation above,
1 mole of Na2CO3 reacted to produce 1 mole of CaCO3.
Therefore, 0.01 mole of Na2CO3 will also react to produce 0.01 mole of CaCO3.
Next, we shall determine the volume of Na2CO3 needed for the reaction as illustrated below:
Mole of Na2CO3 = 0.01 mole
Molarity of Na2CO3 = 0.1 M
Volume of Na2CO3 solution needed =?
Molarity = mole /Volume
0.1 = 0.01 / volume of Na2CO3
Cross multiply
0.1 × volume of Na2CO3 = 0.01
Divide both side by 0.1
Volume of Na2CO3 = 0.01 / 0.1
Volume of Na2CO3 = 0.1 L
Finally, we shall convert 0.1 L to millilitres (mL). This can be obtained as follow:
1 L = 1000 mL
Therefore,
0.1 L = 0.1 L × 1000 mL / 1 L
0.1 L = 100 mL
Thus, 0.1 L is equivalent to 100 mL.
Therefore, 100 mL of Na2CO3 is needed for the reaction.
The volume of sodium carbonate used in the given reaction is 0.1 liter or 100mL.
How we calculate the volume from molarity?Volume of the solution will be calculated by using the molarity as:
M = n/V, where
n is the moles of solute and this can be calculated as:
n = W/M , where
W = given or required mass
M = molar mass
Given chemical reaction is:
Na₂CO₃ + CaCl₂ → CaCO₃ + 2NaCl
Moles of 1g of CaCO₃ = 1g/100g/mole = 0.01 moles
From the stoichiometry of the reaction, it is clear that same moles of CaCO₃ produced by same moles of used Na₂CO₃.
0.01 moles of CaCO₃ = produced by 0.01 moles of Na₂CO₃
Now we calculate the volume of 0.01 moles and 0.100M of Na₂CO₃ as:
V = n/M
V= 0.01/0.100 = 0.1L or 100mL
Hence 0.1 L is the required volume.
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1. Calculate the energy of a photon with a frequency of 3x1015 Hz.
?????
Answer:
1.99 x 10⁻¹⁸J
Explanation:
Given parameters:
Frequency of the wave = 3 x 10¹⁵Hz
Unknown:
Energy of the photon = ?
Solution:
To solve this problem, we use the expression below;
E = hf
Where E is the energy, h is the Planck's constant and f is the frequency
Now insert the parameters and solve for E;
E = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J
True or False: Weathering and erosion are different names for the same process.
Answer:
False. because weathering happens first, then erosion takes place.
Explanation:
Weathering is the breaking down or dissolving of rocks and minerals on Earths surface. Once a rock has been broken down, a process called erosion transports the bits of rock and minerals away. Water, acids, salt, plants, animals, and changes in temperature are all agents of weathering and erosion.
Weathering and erosion are different names for the same process is false.
What is erosion?Erosion is defined as the geological process wherein earthen components are eroded and moved by elements like wind or water. Soil erosion primarily occurs when dirt is exposed to strong winds, copious rain, and moving water. Some human endeavors, especially farming and land clearance, increase the susceptibility of soil to erosion.
Erosion occurs when these natural forces shift the smaller rock fragments. Weathering is what happens when a rock is altered or damaged but remains in its current location. Erosion is the process through which the fragments of weathered rock are removed. The processes that reduce rocks to little particles are erosion and weathering.
Thus, weathering and erosion are different names for the same process is false.
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The limiting reactant in a chemical reaction is the reactant that
Answer:
is used
Explanation:
3.0 x 108 m/s is the
Answer:
Speed of light
Explanation:
The value 3.0 x 10⁸m/s is taken as the speed of light.
It is a constant.
It implies that light travels a distance of 3 x 10⁸ in just one second. This value is for the speed of light in a vacuum when there are not particles obstructing its movement. The speed of electromagnetic radiations in free space is also taken as the speed of light.were are you guys 123456789789456123456789123456789456
At 298 K and 1 atm which noble gas has the lowest density? Why?
1) Ne
2) Kr
3) Xe
4) Rn
Answer:
Ne
Explanation:
It has the lowest density.
Neon has the lowest density since it has the smallest atomic size and the lowest atomic number.
At a standard temperature of 298K and a pressure of 1 atm;The atomic density of an element refers to the number of atoms contained in an element per unit volume.
The size of an atom has an effect on atomic density. The size of an atom increases from left to right across the period and top to bottom down the group.
As such, on the periodic table, as we move from top to bottom down the group, the density of an atom increases.
The atomic element of the given elements are:
Neon (Ne) = 10Krypton (Kr) = 36Xenon (Xe) = 54Radon (Rn) = 36Therefore, we can conclude that Neon (Ne) will have the lowest density since it has the smallest atomic size and the lowest atomic number.
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By titration, it is found that 31.7 mL of 0.145 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.
Answer:
0.184 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above, the following data were obtained:
Mole ratio of the acid, HCl (nA) = 1
Mole ratio of the base, NaOH (nB) = 1
Next, the data obtained from the question. This includes:
Volume of the base, NaOH (Vb) = 31.7 mL Molarity of the base, NaOH (Mb) = 0.145 M
Volume of the acid, HCl (Va) = 25.0 mL
Molarity of the acid, HCl (Ma) =?
Finally, we shall determine the molarity of the acid (HCl) as shown below:
MaVa /MbVb = nA/nB
Ma × 25 / 0.145 × 31.7 = 1
Cross multiply
Ma × 25 = 0.145 × 31.7
Ma × 25 = 4.5965
Divide both side by 25
Ma = 4.5965 / 25
Ma = 0.184 M
Therefore, the molarity of the acid (HCl) is 0.184 M
Suppose you have equal masses of water, ethanol, and oil (in separate containers). You heat each one from 26 °C to 81 °C. Which one requires the most heat?
a. Oil
b. Ethanol
c. Water
Answer: c. Water
Explanation:
Heat capacity can be defined as the physical property of the matter. It is the amount of heat which is required to produce a unit change in the temperature of the material.
Water requires more amount of energy per gram of the liquid to change its temperature as compare to any other liquid like ethanol and oil. Ethanol is a volatile liquid so it will require less heat to boil but heat capacity of oil will be more than the oil. The heat capacity of water will be the highest, and it will require more heat.
How many formula units make up 20.6 g of magnesium chloride (MgCl2)?
Answer:The formula of magnesium chloride is MgCl2 . The molar mass of MgCl2 is (24.30 + 2 × 35.45) g/mol=95.20 g/mol .
Explanation:
How many grams of potassium iodide are required to make 500. milliliters of a 2.80 M KI solution.
Answer:
232.4 grams of KI solution
Explanation:
Well, we first start off by using like units. The concentration (M) of KI can be rewritten as Moles/ Liter, which makes the solution rewritten as 2.80 Moles/ 1 L.
We also know that 1000 Milliliters are equal to 1 Liter, therefore we can rewrite the 500 Milliliters as 0.500 Liters from doing a conversion (500 mL x (1 L/1000 mL)= 0.500 L).
From here we multiply the concentration by the number of liters to leave us with moles ((2.80 Moles/ 1 L) x 0.500 L= 1.4 Moles).
Now, we must find the molar mass of the KI solution, this can be done either by googleing it or adding the molar mass of each element in the compound via the periodic table. In this case, the molar mass for the Potassium in the compound is 39 g/mol while the Iodine is 127 g/mol. Those add to 166 g/mol, and now we can convert to grams from moles.
Now, we multiply the moles by the molar mass to cancel out the moles and leave us with grams. (1.4 mol x (166 g/mol)= 232.4 grams).
I hoped this helps and good luck with your semester in Chemistry!
NEED HELP ASAP
1) Is Sulfur a metal or nonmetal? _______________________
2) Which family is Calcium in? _________________________
3) What is the Element’s name for the element that has the atomic number 72?
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4) What is the atomic mass of Thallium? _________________________
5) What are all the atomic symbols for the Noble gases?
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6) What are all the Element’s names in the metalloids?
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7) What are all the atomic masses for the Actinides?
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8)How many protons does Arsenic have? __________________
9) How many electrons does Radium have? ________________
10) How many neutrons does Nickel have? ________________
I'll see what I can do here...
1) Nonmetal
2) Calcium (Ca), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table.
3) Hafnium
4) 204.3833 u
5) Not sure what you're asking, but oble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og)
6) The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At)
7) The Actinide series contains elements with atomic numbers 89 to 103 and is the third group in the periodic table.
8) 33
9) 88
10) 30
Hope this helps!