Select the two values of x that are roots of this equation.
2x^2 — 11x + 15 = 0

A. x = 5
B. x = 3
C. x = 6
D. x = 5/2

Answer:

3 ; 5/2

Step-by-step explanation:

Δ= 121 - 120 = 1

x1 = (11 + 1)/4 = 3

x2 = (11-1)/4 =5/2

The solution of the quadratic equation is x = 3 and x = 5/2. Options B and D are correct.

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

A polynomial in mathematics is an expression made up of coefficients and indeterminates and involves only the operations of multiplication, addition, subtraction, and non-negative integer exponentiation of variables.

The given qudratic equation is,

2x² — 11x + 15 = 0

The values of the zeroes of a qudratic equation are calculated by the formula written below,

[tex]x = \dfrac{(-b \pm \sqrt{(b^{2} - 4ac)})} { (2a)}[/tex]

The solution can be calculated as,

[tex]x = \dfrac{(-(-11) \pm \sqrt{((-11)^2 - 4(2)(15))})} {(2(2))}\\x = \dfrac{(11 \pm \sqrt{(121 - 120)})} { 4}\\x = \dfrac{(11 \pm 1)} { 4}[/tex]

Hence, the value of x will be 3 and 5/2 for the given quadratic equation.

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