Select only one most suitable description

Answer:

the answer is 6. 2 goes into 12 6 times resulting in the answer 6

Answer:

118.2 g H₂O

Explanation:

To find the mass of water, you need to (1) convert moles HNO₃ to moles H₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles H₂O to grams H₂O (via molar mass).

The molar mass of water can be found by combining the element's molar masses times their quantities. The ratios/conversions should be arranged in a way that allows for the cancellation of units (desired unit should be in the numerator).

Molar Mass (H₂O): 2(1 g/mol) + 16 g/mol

Molar Mass (H₂O): 18 g/mol

S + 6 HNO₃ ---> H₂SO₄ + 6 NO₂ + 2 H₂O
      ^                                                ^

19.7 moles HNO₃          2 moles H₂O                18 g
--------------------------  x  -----------------------  x  ---------------------  = 118.2 g H₂O
                                     6 moles HNO₃         1 mole H₂O

Answer:

0.217 ×2. =9.86×10moles

44

The statement which is not true is as follows:

Thus, the correct option is C.

An equilibrium may be defined as the condition in which both the reactants and products are present in concentrations that have no additional propensity to alter with time so that there is no noticeable transformation in the possessions of the system.

The causation of repulsive force was thought to be made by the overlap of atomic orbitals and in between the electrons of diverse atoms, it matters a lot.

The equilibrium distance between nuclei of two covalently bonded atoms is called the bond length of that atom. It is the atomic separation at equilibrium.

Equilibrium occurs when the attractive and repulsive forces neglected the effect of each other in a specific state.

Therefore, it is well described above.

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Answer:

6.67 mg/kg     per dose   ( 26.67 mg/kg   per day)

Explanation:

400 mg / 60 kg = 6 2/3  mg/kg  per dose

   per DAY  is  four times this number

Answer:

The answer is "B will give up two electrons to form bonds".

Explanation:

To first solve this multiple choice question, we need to identify the Atoms, A and B.

We can do this by looking at their amount of electrons.

For instance,

A = Neon = 10 Electrons

B = Magnesium = 12 Electrons

With this information we can then look at both elements charges to see what they need to form a bond.

In this case Neon doesn't want to form a bond, since they're in a complete octet, however Magnesium does not have a complete octet. So, it wants to give up two electrons to form a bond (2+ charge shows us that).

This then shows us that Option 2, "B will give up two electrons to form bonds" is correct.

Answer:

B will give up two electrons to form bonds

Explanation:

A sample of rainwater with a pH of 3.5 is sure to contain a large concentration of [tex]H_3O^+[/tex]

A pH value of 7 downward is said to be acidic. Upward of 7 is said to be basic. A pH of 7 on the dot is said to be neutral.

An acid is defined as a substance that produces  [tex]H_3O^+[/tex] as its only positively charged ion in solution.

Thus, rainwater with a pH of 3.5 is acidic and will contain a high concentration of  [tex]H_3O^+[/tex].

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The initial pH for the weak acid-strong base curve is higher than the initial pH for the strong acid-strong base curve. Hence, option A is correct.

Weak acids are acids that don't completely dissociate in solution.

A weak acid is an acetic acid. It has a of 1.8⋅[tex]10^{-5}[/tex]. Calculate how much it will dissociate in water. Since acetic acid is a weak acid so large part will not dissociate completely.

[tex]k_a=\frac{[CH_3COO^-]H^+]}{[CH_3COOH]}[/tex]

B is not true, it shows the titration curve for weak/strong acid titrated with a strong base. When choosing an indicator for colourimetric titration select one so that the pH jump at the equivalence point contains the interval p±1. Phenolphthalein has a p≈9, so to decide if it is a suitable indicator check if the pH jumps from 8 to 10 at the equivalence point.

C is not true either because of the very slow reaction.

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S=2, p=6, d=10, and f=14 the maximum number of electrons it can

accommodate.

The probability of finding an electron around the nucleus.

The principal number (n), is the number of the shell, it goes from 1 to 7 and is represented by the letter K, L, M, N, O, P, Q. The maximum number of electrons in the shells are, K = 2, L = 8, M = 18, N = 32, O = 32, P = 18, Q =8.

The secondary number (l) is the subshells, and it goes from 0 to 4 and is represented, in order, for the letter, s, p, d, f. The maximum number of electrons permitted in each subshell is s = 2, p = 6, d = 10, f = 14.

The magnetic number (ml), is represented by orbitals, and it goes from -l to +l, passing by 0. The maximum number of electrons is 2 for each one.

The spin number (ms) refers to the rotation of the electron, and it can be +1/2 or -1/2.

Hence, S=2, p=6, d=10, and f=14 the maximum number of electrons it can

accommodate.

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Number of electron pairs = \frac{1}{2}[V+N-C+A]

2

1

[V+N−C+A]

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

SbCl_5SbCl

5

:

In the given molecule, antimony is the central atom and there are five chlorine as monovalent atoms.

The number of electron pairs are 5 that means the hybridization will be sp^3dsp

3

B and geometry of the molecule will be trigonal bipyramidal.

Answer:

A large absorption at 2950 cm⁻¹ indicates that there is likely an sp³C-H functional group somewhere in the molecule. The "sp³" designation means that this is a single bond because these atoms have 4 orbitals available (s + p + p + p) for hybridizing, meaning only single bonds are possible.

The moles of nitrogen (iv) oxide produced in C and D are 0.284 moles and 68.32 moles respectively.

The mole ratio of the given reaction shows that 2 moles of dinitrogen (v) oxide produces 4 moles of nitrogen (iv) oxide when it decomposes.

B of dinitrogen (v) oxide in 15.4 g is calculated below:

Molar mass of dinitrogen (v) oxide = 108 g/mol

Moles of dinitrogen (v) oxide = 15.4/108 = 0.14 moles

Moles of  nitrogen (iv) oxide produced = 0.142 * 2 = 0.284 moles

Moles of dinitrogen (v) oxide in 3.69 kg is calculated below:

Molar mass of dinitrogen (v) oxide = 108 g/mol

Mass = 3.69 kg = 3690 g

Moles of dinitrogen (v) oxide = 3690/108 = 34.16 moles

Moles of nitrogen (iv) oxide produced = 34.16 * 2 = 68.32 moles

Therefore, the moles of nitrogen (iv) oxide produced in C and D are   0.284 moles and 68.32 moles respectively.

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Answer:

KCl

Explanation:

Ionic compounds are formed between atoms with very different electronegativity (EN) values. The elements with the highest EN values are on the top-right of the periodic table.

Ionic compounds are also generally between a metal and nonmetal. Nonmetals are located in the p-block (the right) of the periodic table and metals are pretty much everywhere else.

That being said, water (H₂O), CO, and CO₂ contain elements that have too similar of EN values to ionically bond.

However, the elements in KCl have different enough EN values to undergo ionic bonding by donating/receiving electrons from each other.

The theoretical yield of NH3 is 10.03 g while the percentage yield of NH3 is 22%.

The theoretical yield is defined as the yield of the product as obtained from the stoichiometry of the reaction.

Given that the reaction equation is; N2 + 3H2 ------> 2NH3

Number of moles of N2 = 9.80 g/28 g/mol = 0.35 moles

Number of moles of H2 = 1.77 g/ 2 g/mol = 0.885 moles

If 1 mole of N2 reacts with 3 moles of H2

0.35 moles reacts with 0.35 moles * 3 moles / 1 mole

= 1.75 moles

Hydrogen is the limiting reactant

Thus;

3 moles of H2 yields 2 moles of NH3

0.885 moles yields  0.885 moles * 2 moles/3 moles

= 0.59 moles

Theoretical yield of NH3 = 0.59 moles * 17 g/mol = 10.03 g

Percent yield = 2.21/10.03 * 100/1

= 22%

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The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ

The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions, and with everything in its standard state.

According to the balanced chemical equation ;

CH₄(g) + 2O₂(g) ⟶ CO₂(g) + 2H₂O(l)

Now,

ΔH⁰ = ΔH⁰f(products) − ΔH⁰f(reactants)

​

       = [ΔH⁰(CO₂) +ΔH⁰(H₂O)] − [ΔH⁰(CH₄) + 2ΔH⁰(O₂)]

       = [−393.5 + 2 x (−285.8)] − [−62.7 + 2 x 0]

        = − 902.4 kJ

Hence, The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ

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Answer:

'Gay-Lussac's law is a gas law that states the pressure of a gas varies directly with temperature when mass and volume are kept constant. As the temperature increases, the pressure will also increase.'

Answer:

Gay Lussac’s law says that the pressure created by a gas is proportional to the temperature of the gas when the mass is constant or the same
so, when pressure increases so does the temperature and when pressure decreases so does the temperature

The molecular weight of Cr3(AsO4)2 is 433.827.

Furthermore, the primary distinction between each is that molar mass gives the mass of a mole of a selected substance. While molecular weight is the mass of a molecule of a particular substance. At an equal time as the definition and devices are splendid for molar mass and molecular weight, the value is the same.

The sum of the atomic hundreds of all atoms in a molecule is based totally on a scale wherein the atomic loads of hydrogen, carbon, nitrogen, and oxygen are 1, 12, 14, and 16, respectively.

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Answer:

Explanation:

A

V cube = 2.2³ = 10.648 cm³

V Pt atoms = 0.75(75%) x 10.648 = 7.986 cm³

Part 1

mass of a single Pt atom = 3.24 x 10⁻²² g

mass Pt atoms  = ρ x V = 21.45 g/cm³ x 7.986 cm³ = 171.3 g

the number of Pt atoms = 171.3 : 3.24 x 10⁻²² = 5.287 x 10²³

Part 2

4/3πr³=7.986 cm³

r = 1.24 cm = 1.24 x 10¹⁰ pm

Answer: D. The energy needed to change a liquid into a gas

there are five Taste bud present tongue they are -

out of the four type of papillie present on tongue the fungiform circumvallate and folite papillie contain numerous small taste but few such type of Taste but also occur in the mucous membranes of soft palate tonsils and epiglottis all of these days but received taste is normally

each Taste bud is an oval structures formed due to modification of epithelial cells which are situated erect and vertically on the surface long sensory cells and supporting cells are found in this bird is sensory cell is spindle shaped in which a sensory here is found at its free in the century fibre of the facial and vagus cranial nerves are wrapped around the basal and of the gustatory cells each test but open on the epithelial surface through minute taste pore

Answer:

4560 torr

Explanation:

PV = K

4 x 1.5 = k

k = 6

V = k / p

V = 6 / 1

V = 6

atm to torr = 1 to 760

760 x 6 = 4560

The movements of the substance across the dialysis membrane are as following: water: Moves in both directions.

Glucose: Moves into the blood.

Urea: Moves out of the blood.

Na, K, and Ca ions: Moves in both directions.

Dialysis is a process of filtration and purification of blood by a machine. This machine helped those people whose kidney stop working and doesn't purify the blood.

Thus, the correct options are: water: Moves in both directions.

Glucose: Moves into the blood.

Urea: Moves out of the blood.

Na, K, and Ca ions: Moves in both directions.

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The variable "air pressure inside the football" in this experiment is quantitative and dependent variable. Hence, option D is correct.

The dependent variable is the variable that is being measured or tested in an experiment.

In the experiment, the scientist filled the footballs with fix quantity of pressure which was then kept for 12 hours. After 12 hours the pressure inside the footballs was again measured. Pressure here is a quantitative variable.

Since the air temperature is an independent variable. The pressure being the dependent variable depends upon the temperature of the air.

Independent variable; The variable which does not depends upon any other variable.

Dependent variable; The variable which depends upon the independent variable or varies with the change independent variable.

Qualitative variables are variables which cannot be expressed in form of numbers. They generally convey the characteristic, category, quality or type.

Whereas Quantitative variables are the variables which can be expressed in the form of numbers. These are the variables which exist along the continuous sequence.

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HAZMAT Class 6 Toxic and infectious substances.

Answer:

CLASS 2 Gases

Explanation:

Hope this helps

The most reasonable way to measure absolute zero would have been to extrapolate the ideal gas law.

This is referred to the temperature at which a thermodynamic system has the lowest form of energy.

Guillaume Amontons used gas equation to prove that absence of heat was theoretically possible which would have involved only extrapolating the ideal gas law.

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Answer: There is a very large percentage of C-12.

Explanation:

The atomic mass is must closer to that of C-12 than of C-13, meaning that there is a much larger percentage of C-12.