Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 samples are summarized as follows conformsupplier yes no1 22 82 25 53 30 10Let A denote the event that a sample is from supplier 1 and let B denote the event that a sample conforms to specifications. Determine the number of samples in A' ∩ B, B' and A ∪ B

If the period of repayment is extended to 20 years and 25 years, the monthly payment amount will be $1,097.83 and $948.43 respectively.

Principal amount is the initial amount borrowed or invested in a loan, investment, or deposit. It is the amount that is used to calculate interest payments, and it is distinct from the interest or any other fees associated with the loan.

If the period of repayment is extended to 20 years, the monthly payment amount will be $1,097.83. This is calculated as follows:

P = Principal Amount

r = Interest rate (4.5% p.a.)

n = Number of years (20)

Monthly Payment Amount (P) = P x (r / (1 - (1 + r)⁻ⁿ))

= 160,000 x (4.5 / (1 - (1 + 4.5)⁻²⁰))

= 160,000 x (4.5 / (1 - 0.375))

= $1,097.83

Similarly, if the period of repayment is extended to 25 years, the monthly payment amount will be $948.43. This is calculated as follows:

P = Principal Amount

r = Interest rate (4.5% p.a.)

n = Number of years (25)

Monthly PaymentAmount (P) = P x (r / (1 - (1 + r)⁻ⁿ))

= 160,000 x (4.5 / (1 - (1 + 4.5)⁻²⁵))

= 160,000 x (4.5 / (1 - 0.242))

= $948.43

This is happening because when the loan period is extended, the number of payments increases, leading to a lower monthly payment amount.

This is because the total amount to be repaid remains the same, but is spread over a longer period of time, resulting in lower monthly payments. In this case, extending the loan period from 15 years to 20 years and 25 years reduces the monthly payment amount from $1,395.87 to $1,097.83 and $948.43 respectively.

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The standard deviation of stock X is 13%, which means that the actual returns for stock X are likely to be within plus or minus 13% of the expected return about 68% of the time.

Based on the given data, the expected rate of return for stock X is 16% and for stock Y is 15%. The standard deviation for stock X is 13.

To calculate the expected rate of return, we multiply each return by its probability and then sum up the results. For stock X, the calculation would be:

(0.6 x -10%) + (0.2 x 20%) + (0.2 x 30%) = -6% + 4% + 6% = 4%

For stock Y, the calculation would be:

(0.6 x 10%) + (0.2 x 15%) + (0.2 x 20%) = 6% + 3% + 4% = 13%

The standard deviation of stock X is 13%, which means that the actual returns for stock X are likely to be within plus or minus 13% of the expected return about 68% of the time.

Overall, based on the given data, stock Y appears to have a slightly higher expected return than stock X, but stock X has a higher level of risk (as indicated by its higher standard deviation).

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The statement, "measures of association such as "odds-ratios" and "rate-ratios" are accompanied by 95% confidence intervals" is True because these measure-of-associations are accompanied by 95% confidence interval.

The Measures of association such as odds ratios and rate ratios are usually accompanied by 95% confidence intervals. Confidence intervals provide a range of values within which the true population parameter is likely to fall, with a certain degree of certainty (usually 95%).

The width of the confidence interval reflects the amount of uncertainty in the estimate, with wider intervals indicating greater uncertainty. Confidence intervals are important because they provide a measure of the precision of the estimate and allow researchers to assess the significance of their findings.

Therefore, the statement is True.

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Answer:

C

Step-by-step explanation:

[tex](3x-2)(x^2-2x+3)[/tex]

[tex]3x(x^2)-3x(2x)+3x(3)-2(x^2)-2(-2x)-2(3)[/tex]

[tex]3x^3-6x^2+9x-2x^2+4x-6\\[/tex]

Now, combine like terms

[tex]3x^3-6x^2-2x^2+9x+4x-6[/tex]

[tex]-6x^2-2x^2=-8x^2\\\\9x+4x=13x[/tex]

Thus, we have:

[tex]3x^3-8x^2+13x-6[/tex]

So the answer is C. Hope this helps.

Answer:

3rd option

Step-by-step explanation:

(3x - 2)(x² - 2x + 3)

each term in the second factor is multiplied by each term in the first factor , that is

3x(x² - 2x + 3) - 2(x² - 2x + 3) ← distribute parenthesis

= 3x³ - 6x² + 9x - 2x² + 4x - 6 ← collect like terms

= 3x³ - 8x² + 13x - 6

Using the Ratio Test, the series [infinity]Σ[tex]x^k / k^6[/tex] converges for x ∈ (-1, 1] and diverges for x ∈ (-∞, -1) ∪ (1, ∞).

To use the Ratio Test, we need to evaluate limit

[tex]\lim_{k \to \infty} |x^{(k+1)} / (k+1)^6| * |k^6 / x^k|[/tex]

Simplifying, we get

[tex]\lim_{k \to \infty} |x / (k+1)|^k[/tex]

The series converges if this limit is less than 1, and diverges if it is greater than 1. If the limit is equal to 1, the Ratio Test is inconclusive.

We can rewrite the limit as

[tex]\lim_{k \to \infty} |(x / k) / (1 + 1/k)|^k[/tex]

As k approaches infinity, 1/k approaches 0, so we can ignore the term 1/k in the denominator

[tex]\lim_{k \to \infty} |(x / k) / 1|^k[/tex] = [tex]\lim_{k \to \infty} |x / k|^k[/tex]

Now, we can evaluate the limit based on the value of x

If |x| < 1, then lim |x/k| = 0, so the series converges.

If |x| > 1, then lim |x/k| = infinity, so the series diverges.

If |x| = 1, then the Ratio Test is inconclusive.

Therefore, the series converges for x ∈ (-1, 1] and diverges for x ∈ (-∞, -1) ∪ (1, ∞).

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Answer:

The answer is

not equivalent

equivalent

The normal curve can be used as an approximation to the binomial probability of at most 85 out of 136 DVDs malfunctioning, with the probability of a given DVD malfunctioning being 98%. The necessary conditions for using the normal curve as an approximation have been verified and met.

Probability is a measure of the likelihood of a certain event occurring. It is expressed as a number between 0 and 1, with 0 indicating that the event is impossible and 1 indicating that the event is certain. Probability is used to make predictions, assess risk, and make decisions in a variety of disciplines such as mathematics, finance, science, and engineering.

To verify the necessary conditions for a normal curve to be used as an approximation to the binomial probability, we must check if np ≥ 10 and nq ≥ 10, where n is the number of trials and p and q are the probabilities of success and failure, respectively. In this case, n = 136, p = 0.98 and q = 0.02. Thus, np = 134.08 ≥ 10 and nq = 2.72 ≥ 10.

Therefore, the necessary conditions for a normal curve to be used as an approximation to the binomial probability have been met. This means that the normal curve can be used as an approximation to the binomial probability of at most 85 out of 136 DVDs malfunctioning, with the probability of a given DVD malfunctioning being 98%.

In conclusion, the normal curve can be used as an approximation to the binomial probability of at most 85 out of 136 DVDs malfunctioning, with the probability of a given DVD malfunctioning being 98%. The necessary conditions for using the normal curve as an approximation have been verified and met, and so the normal curve is a valid approximation in this case.

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The probability of B for a given data is considered to be around 0.648

In the likelihood hypothesis, conditional likelihood alludes to the likelihood of an occasion A given that another occasion B has happened. In this issue, we are given the likelihood of both A and B happening (0.395) and the likelihood of A given B (0.61).

We are inquiring to discover the likelihood of occasion B.

To fathom the likelihood of B, we will utilize Bayes' hypothesis, which states that the likelihood of occasion B given occasion A is:

P(B|A) = P(A|B) * P(B) / P(A)

where P(A) is the likelihood of occasion A and P(A|B) is the likelihood of A given B. We know that P(A and B) = 0.395, so we will moreover say:

P(A) = P(A and B) + P(A and not B)

Substituting these values into Bayes' hypothesis, we will illuminate

P(B): P(B|A) = 0.61 * P(B) / (0.395 + P(B) * P(not B))

Streamlining this condition and fathoming for P(B), we get:

P(B) = 0.395 / (0.61 - 0.39)

P(B) ≈ 0.648

Hence, the likelihood of occasion B is around 0.648 (to three decimal places). This implies that occasion B is more likely to happen than not to happen, given the data we have approximately occasions A and B. 

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A standard deviation of 9 minutes. 30% of the patients wait more than how long is  31.68 minutes.

To solve this problem, we need to find the amount of time that 30% of the patients wait more than.

We can start by using the z-score formula:

z = (x - μ) / σ

where x is the wait time we're looking for, μ is the mean wait time of 27 minutes, and σ is the standard deviation of 9 minutes.

Since we want to find the wait time corresponding to the 30th percentile, we need to find the z-score that corresponds to that percentile using a standard normal distribution table. This z-score represents the number of standard deviations away from the mean that the 30th percentile is located.

The standard normal distribution table gives us a z-score of approximately 0.52 for the 30th percentile.

So, we can plug in our known values:

0.52 = ( - 27) / 9

Solving for x:

0.52 * 9 + 27 = x

4.68 + 27 = x

x = 31.68

Therefore, 30% of the patients wait more than 31.68 minutes, rounded to 2 decimal places.

Answer: 31.68 minutes.

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Using the empirical rule, we can conclude that about 95% of the male students in this school have heights between 63 inches and 73 inches.

What is empirical rule?

The empirical rule, also known as the 68-95-99.7 rule, states that for a normal distribution:

Approximately 68% of the data falls within one standard deviation of the mean

Approximately 95% of the data falls within two standard deviations of the mean

Approximately 99.7% of the data falls within three standard deviations of the mean

Since we want to find the interval of heights that represents the middle 95% of male heights from this school, we can use the second part of the empirical rule.

Step 1: Find two standard deviations above and below the mean

Two standard deviations below the mean:

68 - 2.5(2) = 63

Two standard deviations above the mean:

68 + 2.5(2) = 73

Step 2: Find the interval between these two values

The interval of heights that represents the middle 95% of male heights from this school is the interval between 63 and 73 inches.

Therefore, we can conclude that about 95% of the male students in this school have heights between 63 inches and 73 inches.

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The vector triple product and the BAC-CAB rule are as follows.

The BAC-CAB rule is a mnemonic used to remember the formula for the vector triple product. The vector triple product is the result of a cross product of two vectors, which is then crossed with another vector. The BAC-CAB rule states that:
For vectors A, B, and C:
A × (B × C) = (A·C)B - (A·B)C
where × denotes the cross product and · denotes the dot product.
In this rule, the terms BAC and CAB represent the order in which you perform the operations:
Step:1. First, take the dot product of A and C, denoted as (A·C).
Step:2. Multiply the result by vector B.
Step:3. Next, take the dot product of A and B, denoted as (A·B).
Step:4. Multiply the result by vector C.
Step:5. Finally, subtract the result of step 4 from the result of step 2.

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The area of the region included between the parabolas

The two parabolas intersect at the points (-p-1, 0) and (p+1, 0).

We can find the y-coordinates of these points by plugging in x=-p-1 and x=p+1 into the equations of the parabolas:

[tex]y^2[/tex] = 4(p + 1)(x + p + 1)

At x = -p-1: [tex]y^2[/tex] = 4(p+1)(-2) = -8(p+1)

So y = ±√(-8(p+1)) = ±2i√(2(p+1))

[tex]y^2[/tex] = 4([tex]p^2[/tex] + 1)([tex]p^2[/tex] + 1 - x)

At x = p+1: [tex]y^2[/tex] = 4([tex]p^2[/tex]+1)(0) = 0

So y = 0

Thus, the two parabolas intersect at the points (-p-1, ±2i√(2(p+1))) and (p+1, 0).

The area between the parabolas is symmetric about the y-axis, so we can just find the area of the region in the first quadrant and double it.

The equation of the upper parabola can be rewritten as y = 2i√(p+1)(x+p+1) and the equation of the lower parabola can be rewritten as y = 2√([tex]p^2[/tex]+1)(p+1-x). Setting these equal and solving for x, we get:

2i√(p+1)(x+p+1) = 2√([tex]p^2[/tex]+1)(p+1-x)

x = -p-1 + 2i(p+1)/(2+2i([tex]p^2[/tex]+1)/(p+1))

x = -p-1 + 2i(p+1)(p+1)/([tex]p^2[/tex]+1+2ip(p+1))

We want to find the real part of this complex number, which is the x-coordinate of the point of intersection in the first quadrant.

The real part of a complex number a+bi is just a, so the x-coordinate is:

Re[-p-1 + 2i(p+1)(p+1)/([tex]p^2[/tex]+1+2ip(p+1))]

= -p-1 + 2(p+1)([tex]p^2[/tex]+1)/([tex]p^2[/tex]+1+2p(p+1))

= -p-1 + 2([tex]p^3[/tex]+2p+1)/([tex]p^2[/tex]+2p+1)

= -p-1 + 2([tex]p^2[/tex]+1)

= 2p+1

Therefore, the area of the region in the first quadrant is given by:

A = ∫[0,2p+1] (2√([tex]p^2[/tex]+1)(p+1-x) - 2i√(p+1)(x+p+1)) dx

Simplifying this integral and taking the absolute value (since we're interested in area), we get:

= 2√([tex]p^2[/tex]+1) ∫[1,p+2] √(u) du, where u = p+1-x

= 2√([tex]p^2[/tex]+1) (2/3)(p+2)(3/2)

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Answer:

The answer for x is 7

Step by Step Explanation:

√(8x-65-4= -3

√(8x-55)= -3+4

√(8x-55)=1

Square both sides

8x-55=1

8x=55+1

8x=56

divide both sides by 8

x=7

The sum of the given infinite series is [tex]\frac{3}{5}[/tex]

To find the value of the sum from n=0 to infinity of (-2/3)^n, we need to use the formula for the sum of an infinite geometric series. The formula is:

[tex]Sum = \frac{a} { (1 - r)}[/tex]

where 'a' is the first term in the series, and 'r' is the common ratio between the terms. In this case, a = (-2/3)^0 = 1 and r = -2/3. Now, we can plug these values into the formula:

[tex]Sum =\frac{ 1}{ (1 - (-2/3))}\\Sum ={ 1}{ (1 + 2/3)}\\Sum ={ 1}{ / (3/3 + 2/3)}\\Sum = 1 / (5/3)\\Sum = 1 * (3/5)\\\\Sum = 3/5[/tex]
So, the value of the sum of the series is 3/5.

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For tail probability the value of z that should be used to calculate a confidence interval with a 98% confidence level is Option C: 2.326.

What is probability?

Probability is a fundamental concept in statistics and mathematics that helps to measure the likelihood or chance of an event occurring. It provides a way to quantify uncertain events or situations and make informed decisions based on that information. The probability of an event can range from 0 to 1, with 0 indicating impossibility and 1 representing certainty.

To calculate the z-value for a 98% confidence level, we need to find the area in the standard normal distribution table that corresponds to a tail probability of (1-0.98)/2 = 0.01 on each side.

Looking at the standard normal distribution table, the z-value for a tail probability of 0.01 is 2.326.

Therefore, the value of z that should be used to calculate a confidence interval with a 98% confidence level is 2.326.

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The probability that greater than 99 out of 160 students will graduate on time is 0.1011, or 10.11%

To approximate the probability that greater than 99 out of 160 students will graduate on time given that the probability for a single student is 57%, we will use the normal distribution follow the given steps:

1. Determine the mean (μ) and standard deviation (σ) of the binomial distribution.
  μ = n * p = 160 * 0.57 = 91.2
  σ = sqrt(n * p * (1-p)) = sqrt(160 * 0.57 * 0.43) ≈ 6.498

2. Convert the problem to a standard normal distribution (Z-distribution) by finding the Z-score:
  Z = (X - μ) / σ
  Since we want to find the probability of more than 99 students graduating, we will use 99.5 (continuity correction).
  Z = (99.5 - 91.2) / 6.498 ≈ 1.276

3. Look up the Z-score in a standard normal (Z) table or use a calculator to find the area to the right of Z. The area to the left of Z is 0.8989.

4. Subtract the area to the left of Z from 1 to find the area to the right (our desired probability):
  P(X > 99) = 1 - 0.8989 = 0.1011

So, the probability that greater than 99 out of 160 students will graduate on time is approximately 0.1011, or 10.11% when rounded to four decimal places.

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The type II error for the hypothesis test in this scenario would be failing to reject the null hypothesis, which means accepting the owner's claim that the average attendance at games is over 60,000, even though it may not be true.

A type II error, also known as a false negative, occurs when the null hypothesis is actually false, but the hypothesis test fails to reject it. In this case, the null hypothesis would be that the average attendance at games is 60,000 or less, while the alternative hypothesis would be that the average attendance is over 60,000, as claimed by the owner.

If the hypothesis test fails to reject the null hypothesis, it means that there is not enough evidence to conclude that the average attendance is indeed over 60,000, even though it may be true. As a result, the owner's claim would be accepted, and the team may be moved to a city with a larger stadium based on an incorrect conclusion.

Therefore, the type II error in this scenario would be failing to reject the null hypothesis, which may result in accepting the owner's claim that the average attendance at games is over 60,000, even if it is not supported by the data

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The equivalent expression of the expression are as follows:

2(m + 3) + m - 2 = 3m + 4

5(m + 1) - 1 = 5m + 4

m + m + m + 1 + 3 = 3m + 4

Two expressions are said to be equivalent if they have the same value irrespective of the value of the variable(s) in them.

Two algebraic expressions are equivalent if they have the same value when any number is substituted for the variable.

Therefore,

2(m + 3) + m - 2

2m + 6 + m - 2

2m + m + 6 - 2

3m + 4

5(m + 1) - 1

5m + 5 - 1

5m + 4

m + m + m + 1 + 3

3m + 4

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Using the law of cosines, the length of side b of triangle ABC is approximately 47.20 feet.

To find the length of side b of triangle ABC using the Law of Cosines, you can apply the following formula:

b² = a² + c² - 2ac * cos(B)

Given the information, angle B = 73.5 degrees, side a = 28.2 feet, and side c = 46.7 feet. Plug these values into the formula:

b² = (28.2)² + (46.7)² - 2(28.2)(46.7) * cos(73.5)

Calculate the values and solve for b:

b² ≈ 795.24 + 2180.89 - 2633.88 * 0.2840
b² ≈ 2228.07

Now, take the square root to find the length of side b:

b ≈ √2228.07
b ≈ 47.20 feet

So, the length of side b of triangle ABC is approximately 47.20 feet.

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The distance of last leg back to its starting point is 26 miles under the condition that  helicopter flies 10 miles due north and then 24 miles due east.
The helicopter follows a straight path back to its starting point.
So to evaluate the distance of the helicopter's last leg back to its starting point, we have to implement Pythagorean theorem formula.

c² = a² + b²

here c = Length of side,
a = 10 miles
b = 24 miles.
Staging the formula and adding the values
c² =10² + 24²
= 100 + 576
= 676

Hence,
c = √676
= 26 miles
The distance of last leg back to its starting point is 26 miles under the condition that  helicopter flies 10 miles due north and then 24 miles due east.

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The complete question is
A traffic helicopter flies 10 miles due north and then 24 miles due east. Then the helicopter flies in a straight line back to its starting point. What was the distance of the helicopter's last leg back to its starting point?



The gradient vector of f(x,y) is (-18x - 4y, -4x - 8y).

Using Lagrange multipliers, we find the extreme value(s) by solving the system of equations: -18x - 4y = 3λ, -4x - 8y = -λ, and -3x + y + 6 = 0. The only solution is (x, y) = (2, -4), and f(2, -4) = 32. This shows that f has a maximum and no minimum.


1. Find the gradient vector of f(x,y) = -9x² - 4xy - 4y² - 8: ∇f(x,y) = (-18x - 4y, -4x - 8y).
2. Define the constraint function g(x,y) = -3x + y + 6, and set ∇f(x,y) = λ∇g(x,y), where λ is the Lagrange multiplier.
3. Solve the system of equations: -18x - 4y = 3λ, -4x - 8y = -λ, and -3x + y + 6 = 0.
4. The only solution to the system is (x, y) = (2, -4), and λ = 2.
5. Plug the solution into f(x,y) to find the extreme value: f(2, -4) = 32.
6. Since there is only one extreme value, f has a maximum and no minimum.

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The function f'(x) = e7x with derivative that passes through the point P = (0,6/7) is found as f(x) = (1/7)e^(7x) + 5/7.

To find the function f(x) with derivative f'(x) = e^(7x) that passes through the point P = (0, 6/7), we need to integrate f'(x) with respect to x and then find the constant of integration, C, using the given point.
First, integrate f'(x):
∫e^(7x) dx = (1/7)e^(7x) + C
Now, use the given point P(0, 6/7) to find the value of C:
f(0) = (1/7)e^(7 * 0) + C = 6/7
(1/7)e^0 + C = 6/7
(1/7) + C = 6/7
Solving for C, we find:
C = 5/7
So, the function f(x) is:
f(x) = (1/7)e^(7x) + 5/7

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Enrique will pay $71.23 for his purchases.

To find the total cost of Enrique's purchases, add the cost of the jacket and the pants, and then add the sales tax and processing fee to get the final cost.

Where to calculate the sales tax, use the formula of multiplying the purchase price by the tax rate, which is given as $0.07 for every dollar of the purchase price.

Here we have

Enrique buys a jacket for $35 and pants for $29.

Sales tax is $0.07 for every dollar of the purchase price.

He pays a 2.75 processing fee for paying with a check.  

The total cost of Enrique's purchases before tax is:

=> $35 + $29 = $64

The sales tax is $0.07 for every dollar of the purchase price.

So, the total tax paid on the purchase is:

=> $ 64 x 0.07 = $4.48

Hence, the total cost of the purchases after tax is:

=> $64 + $4.48 = $68.48

In addition to the cost of his purchases and the sales tax, Enrique pays a $2.75 processing fee for paying with a check. So, the total cost of his purchases including tax and processing fee is:

=> $68.48 + $2.75 = $71.23

Therefore,

Enrique will pay $71.23 for his purchases.

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Complete Question:

Enrique buys a jacket for $35 and pants for $29. Sales tax is $0.07 for every dollar of the purchase price. He pays a 2.75 processing fee for paying with a check. How much will Enrique pay for his purchases?

The pooled variance is 126.48.

To calculate the pooled variance, we use the formula:

sp^2 = (SS1 + SS2) / (df1 + df2)

where SS1 and SS2 are the sum of squares for each sample, df1 and df2 are the degrees of freedom for each sample (which are equal to the sample size minus one), and sp^2 is the pooled variance.

Using the values given in the question:

SS1 = 291.6

SS2 = 12482

df1 = 10

df2 = 20

n1 = 11

n2 = 21

s1 = 5.4

We can calculate the pooled variance:

sp^2 = (SS1 + SS2) / (df1 + df2)

sp^2 = (291.6 + 12482) / (10 + 20)

sp^2 = 126.48

Therefore, the pooled variance is 126.48.

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Differentiate the functions

a) y' = 5*2⁵ˣ*ln(2) + (3/(3x-5))*(1/ln(2))

b) f'(x) = (8x-1+10)/(4x²-x+10)

c) g'(t) = 1

d) h'(x) = (1/(1+x) + 1/(1-x)) / 2.

a) y = 2⁵ˣ + log₂(3x - 5)
Differentiate using the chain rule and properties of logarithms:
y' = 5*2⁵ˣ*ln(2) + (3/(3x-5))*(1/ln(2))

b) f(x) = log(4x² - x + 10ˣ)
Apply the chain rule and properties of logarithms:
f'(x) = (8x-1+10)/(4x²-x+10)

c) g(t) = ln([tex]e^t^+^1[/tex] / (1+6t+t²))
Using properties of logarithms, we can simplify this to:
g(t) = (t+1) - ln(1+6t+t²)
Differentiate using the chain rule:
g'(t) = 1

d) h(x) = ln(4√(1+x) / (1-x))
Using properties of logarithms, we can simplify this to:
h(x) = (1/2) * ln((1+x)/(1-x))
Differentiate using the chain rule:
h'(x) = (1/(1+x) + 1/(1-x)) / 2.

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We evaluated the double integral by integrating concerning y first and then concerning x, and finally simplified the expression to get the answer is 1941.33.

To evaluate the integral, we need to first find the bounds of integration by finding the intersection point of the two curves y=x and y=2x.

Setting y=x and y=2x equal to each other, we get:

x = 2x

Solving for x, we get x=0.

So the intersection point is at (0,0).

Now, we need to find the bounds of integration along the x-axis. The curve y=x is the lower bound and y=2x is the upper bound.

Thus, the integral becomes:

∫[0,1] (4x + 2) (4x + 2) dx

Integrating with respect to x, we concerning

= (1/3) (4x + 2)^3 evaluated from x=0 to x=1

= (1/3) [(4(1) + 2)^3 - (4(0) + 2)^3]

= (1/3) (18^3 - 2^3)

= (1/3) (5832 - 8)

= 1941.33

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The value of  (3x^2 - 5x + 1) dx is x^3 - (5/2)x^2 + x + C, the integrate of  2/(3x^4) dx is 3πx - (1/2)e^(2x) + C and value of 2/(5x) dx is (2/5) ln|x| + C.

a) To integrate (3x^2 - 5x + 1) dx, we need to use the power rule of integration, which states that the integral of x^n dx = (x^(n+1))/(n+1) + C, where C is the constant of integration. Applying this rule, we get:

∫ (3x^2 - 5x + 1) dx

= (3x^3/3) - (5x^2/2) + x + C

= x^3 - (5/2)x^2 + x + C

b) To integrate 2/(3x^4) dx, we can rewrite the expression as 2x^(-4)/3 and then use the power rule of integration again:

∫ 2/(3x^4) dx

= 2/3 ∫ x^(-4) dx

= 2/3 * (-x^(-3))/3 + C

= -2/(9x^3) + C

c) To integrate (3π - e^(2x)) dx, we can use the constant multiple rule of integration and the rule for integrating e^x, which states that the integral of e^x dx = e^x + C:

∫ (3π - e^(2x)) dx

= 3πx - ∫ e^(2x) dx

= 3πx - (1/2)e^(2x) + C

d) To integrate 2/(5x) dx, we can use the power rule of integration and then simplify:

∫ 2/(5x) dx

= (2/5) ∫ x^(-1) dx

= (2/5) ln|x| + C

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The complete question is:

Evaluate the following:

a) integrate (3x ^ 2 - 5x + 1) dx

b) integrate 2/(3x ^ 4) dx

d) integrate (3pi - e ^ (2x)) dx

integrate 2/(5x) dx dx

The answers to the respective questions are as follows-a) The current monthly cost is $1267.b) The marginal cost when x = 30 is $24.6 per chair. c) The estimated monthly cost of increasing production to 32 chairs is $49.2.d) The additional monthly cost of increasing production to 32 chairs is $50.22.

a) To find the current monthly cost, we need to evaluate C(30):

C(30) = 0.002*[tex]30^{3}[/tex] + 0.07(30)*30 + 15(30) + 700

C(30) = 54 + 63 + 450 + 700

C(30) = 1267

Therefore, the current monthly cost is $1267.

b) The marginal cost is the derivative of the cost function with respect to x. So, we need to find C'(x) and evaluate it at x = 30:

C'(x) = 0.006[tex]x^{2}[/tex] + 0.14x + 15

C'(30) = 0.006*[tex]30^{2}[/tex] + 0.14(30) + 15

C'(30) = 5.4 + 4.2 + 15

C'(30) = 24.6

Therefore, the marginal cost when x = 30 is $24.6 per chair.

c) The marginal cost represents the additional cost of producing one more unit. So, to estimate the cost of increasing production to 32 chairs, we can multiply the marginal cost by the increase in production:

Cost of increasing production to 32 chairs = 24.6 x 2 = 49.2

Therefore, the estimated monthly cost of increasing production to 32 chairs is $49.2.

d) To find the actual additional monthly cost of increasing production to 32 chairs, we need to find the difference between the cost of producing 32 chairs and the cost of producing 30 chairs:

C(32) = 0.002*[tex]32^{3}[/tex] + 0.07*[tex]32^{2}[/tex] + 15(32) + 700

C(32) = 65.536 + 71.68 + 480 + 700

C(32) = 1317.216

Actual additional monthly cost of increasing production to 32 chairs = C(32) - C(30) = 1317.216 - 1267 = 50.216

Therefore, the actual additional monthly cost of increasing production to 32 chairs is $50.22.

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Answer:

The answer is A

-1/2

Step-by-step explanation:

y=sin330

270≤x≥360

cosine=posite

sin=negative

tan=negative

y=sin330°= -1/2

y= -1/2

There are twenty five groups of 1/5 in 5.

1/5 is equal to 0.2. 5 divided by 0.2 equals 25.

Or here's another way: It takes five 1/5 to make 1. So multiply it by five and you get twenty five.