Sabine rode on a passenger train for 480 miles between 10:30 A. M. And 6:30 P. M. A friend in a different city

Answers

Answer 1

The speed of the train is 60 miles per hour.

Sabine travel 480 miles on a passenger train between 10:30 A.M. and 6:30 P.M. What is speed of train?

We calculate in two steps:

Calculate the speed of the train

To calculate the speed of the train, we need to use the formula:

Speed = Distance / Time

Here, the distance travelled by the train is 480 miles, and the time taken is 8 hours (from 10:30 A.M. to 6:30 P.M.). So, we can calculate the speed of the train as:

Speed = 480 miles / 8 hours

Speed = 60 miles per hour

Therefore, the speed of the train is 60 miles per hour.

Explain the solution

Sabine rode on a passenger train for 480 miles between 10:30 A.M. and 6:30 P.M.

To calculate the speed of the train, we used the formula Speed = Distance / Time, where Distance is 480 miles and Time is 8 hours (since the journey was between 10:30 A.M. and 6:30 P.M.).

Substituting the values, we get the speed of the train as 60 miles per hour.

This means that the train travelled at a speed of 60 miles per hour throughout the journey, covering a distance of 480 miles in 8 hours.

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Related Questions

A 6 in.
D
X
F 6 in. G

Answers

The calculated value of x in the right triangle is 6

Calculating the value of x

from the question, we have the following parameters that can be used in our computation:

The right triangle

Where we have

x/6 = 6/x

To solve this equation, we can use the property of cross-multiplication.

So for the equation x/6 = 6/x, we can cross-multiply as follows:

x/6 = 6/x

x * x = 6 * 6

x^2 = 36

To solve for x, we need to take the square root of both sides of the equation:

√(x^2) = √36

x = 6

The value of x is 6

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Calculate the derivative of the following function, 4 y=sin(cos (8x)) ) Find the critical points of the following function f(x) = xVx+6"

Answers

The critical points of f(x) are x = -3 and x = 4.

Derivative of 4y = sin(cos(8x)):
We can find the derivative of the given function using the chain rule of differentiation. Let u = cos(8x), then we have:
y = sin(u)
dy/du = cos(u) (derivative of sin(u))
du/dx = -8sin(8x) (derivative of cos(8x) using chain rule)
dy/dx = dy/du * du/dx = cos(cos(8x)) * (-8sin(8x))
Therefore, the derivative of 4y = sin(cos(8x)) is:
dy/dx = -32sin(8x)cos(cos(8x))
Critical points of f(x) = x√(x+6):
To find the critical points of f(x), we need to find where the derivative of the function is equal to zero or undefined.
f(x) = x√(x+6)
f'(x) = (√(x+6) + x/2√(x+6))
To find the critical points, we need to set f'(x) equal to zero and solve for x:
(√(x+6) + x/2√(x+6)) = 0
Multiplying both sides by 2√(x+6), we get:
2x + 6 = -x√(x+6)
Squaring both sides, we get:
4[tex]x^2[/tex] + 24x + 36 = [tex]x^3[/tex] + 6[tex]x^2[/tex]
Rearranging, we get:
[tex]x^3[/tex] + [tex]2x^2[/tex] - 24x - 36 = 0
We can solve this cubic equation using numerical methods or by factoring.

By testing values, we can see that x = -3 is a root of the equation. Dividing the equation by (x+3), we get:
[tex]x^2[/tex]- x - 12 = 0
This quadratic equation can be factored as (x-4)(x+3) = 0.
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Can someone please help me ASAP? It’s due tomorrow.

Answers

Answer: m*n

Step-by-step explanation:

the line is parallel to the graph of y=-1/2x-1 and contains the point (-4, 5)

Answers

The equation of the line parallel to the graph of y = (-1/2)x - 1 and containing the point (-4, 5) is y = (-1/2)x + 3.

What is the equation of the parallel line?

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

Given the equation of the graph

y = (-1/2)x - 1

The equation of a line parallel to the graph of y = (-1/2)x - 1 will have the same slope as the given line, which is -1/2.

Now. using the point-slope form, we can find the equation of the line that passes through the point (-4, 5) with slope -1/2:

y - y1 = m(x - x1)

y - 5 = (-1/2)(x - (-4))

y - 5 = (-1/2)x - 2

y = (-1/2)x + 3

Therefore, the equation of the parallel line is y = (-1/2)x + 3.

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1. Mrs. Zimmerman is interested in learning about how much time seventh grade students at our school spend outdoors on a typical school day.
Select all the samples that are a part of the population. Justify your reasoning.


. The 20 students in a seventh grade math class.
B. The first 20 students to arrive at school on a particular day.
C. The seventh grade students participating in a science fair put on by the four middle schools in a school district.
D. The 10 seventh graders on the school soccer team.
E. The students on the school debate team.

Answers

A, c, D

Step-by-step explanation:

A) we can sample these 7th graders as we are looking to study 7th graders.

b) The first 20 students could be from any grade and so this option wouldn't work.

c) Involves 7th graders.

d) involves 7th graders

E) The students could be any grade level on the debate team so, this option wouldn't work.

Algebra 1. please help!!

Answers

Answer: f(t) = 2.4t - 500

Step-by-step explanation:

So first of all, we need how much she actually profits from each taco. She charges $3.25 per taco, but we cannot forget that it is not free to make a taco in the first place. It costs her $0.85 to make a taco. This means we have to subtract the 85 cents from the 3 dollars 25 cents, which means it ends up being $2.40, or as the answer choices have it, 2.4.

So now we know what the number of tacos is being multiplied by: 2.4.

2.4t is now the profit per taco multiplied by the number of tacos.

But we're not quite done yet.

She has a fixed expense of $500 a month, which means this has to be subtracted from her taco profits to find her true profit.

Putting all of this together, we get f(t)=2.4t - 500.

(t)= (profit per taco)(amount of tacos sold) - (fixed expenses)

Richard lends to Martin P154,600. 00 under the condition that simple interest will be charged at 8. 5% per annum and the debt is payable after months. How much will Martin have to pay Richard after 36 months ?

Answers

We know that after 36 months, Martin will have to pay Richard P193,969.

Hi! Based on your question, Richard lends P154,600 to Martin at an 8.5% simple interest rate per annum, and the debt is payable after 36 months. To find out how much Martin will have to pay Richard after 36 months, we'll first calculate the interest.

Simple Interest = Principal × Rate × Time
Interest = P154,600 × 8.5% × (36 months / 12 months per year)
Interest = P154,600 × 0.085 × 3
Interest = P39,369

Now, add the interest to the principal to find the total amount Martin needs to pay Richard:
Total Amount = Principal + Interest
Total Amount = P154,600 + P39,369
Total Amount = P193,969

After 36 months, Martin will have to pay Richard P193,969.

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A triangular prism is 36 millimeters long and has a triangular face with a base of 36 millimeters and a height of 24 millimeters. The other two sides of the triangle are each 30 millimeters. What is the surface area of the triangular prism?

Answers

The surface area of the triangular prism is

5752 square millimeters

How to find the surface area of the triangular prism

The surface area of the triangular prism is

= area of the two side rectangles + area of the base rectangles + area of the 2 triangles

= 2 * 36 * 30 + 36 * 36 + 2 * 1/2 * 36 * 24

= 2160 + 1296 + 1296

= 5752 square millimeters

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PLS HELP ME WITH THIS 2. QUESTIONS, 50 POINTS

( The first 2 images are from the first question, the other one is from the second)

Answers

Answer:  B   g(x)=1/4f(x)    odd

Step-by-step explanation:

First Page:

Points from the graph

Points from f(x)                         points from g(x)

(1,2)                                                (1, 1/2)

(4, 16)                                             (4, 4)

f(x) was multiplied by 1/4 to get to g(x)

Second Page:

Even functions are symmetrical about the y-axis: . Odd functions are symmetrical about the x- and y-axis: f(x)=-f(-x).

lets test for even:  does f(x)=f(-x)   =>    f(1)=f(-1)  no   -2[tex]\neq[/tex]2

see image for plotted points

lets test for odd:  does f(x)= -f(-x)   =>    f(1) = -f(-1)  yes  -2 = -2

Answer:

[tex]\textsf{B)} \quad g(x)=\dfrac{1}{4}f(x)[/tex]

[tex]\textsf{B)} \quad \textsf{odd}[/tex]

Step-by-step explanation:

Functions f(x) and g(x) are exponential functions.

From inspection of the given points on both graphs:

f(4) = 16g(4) = 4

When x = 4, the y-value of function f(x) is four times the y-value of function g(x). Therefore, function g(x) is ¹/₄ of function f(x):

[tex]g(x)=\dfrac{1}{4}f(x)[/tex]

[tex]\hrulefill[/tex]

And even function is symmetric about the y-axis:

f(x) = f(-x) for all values of x.

According to the table, f(3) = -4 and f(-3) = 4.

Therefore, as f(x) ≠ f(-x), the function is not even.

An odd function is symmetric about the origin:

f(-x) = -f(x) for all values of x.

According to the table, f(-3) = 4 and f(3) = -4. So -f(3) = -(-4) = 4.

Therefore, as f(-3) = -f(3), the function is odd.

[tex]\hrulefill[/tex]

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PLS HELP ASAP 50 POINTS AND BRAINLEIST!!!
Explain how the arc BX, central angle BCX, and inscribed BNX are connected. what are the relationships between them?

Answers

Answer:

[tex]\overset{\frown}{BX}=\angle BCX=2\angle BNX[/tex]

Step-by-step explanation:

A chord is a straight line joining two points on the circle.

Therefore, the chords in the given diagram are BN and XN.

An inscribed angle is the angle formed (vertex) when two chords meet at one point on a circle.

Therefore, the inscribed angle in the given diagram is BNX.

An intercepted arc is the arc that is between the endpoints of the chords that form the inscribed angle.

Therefore, the intercepted arc in the given diagram is BX.

The radius is a straight line joining the center to a point on the circle.

Therefore, the radii in the given diagram are CB and CX.

The central angle of a circle is the angle formed at its center by two radii.

Therefore, the central angle in the given diagram is BCX.

[tex]\hrulefill[/tex]

The measure of the central angle of a circle is equal to the measure of the corresponding intercepted arc. Therefore:

    [tex]\angle BCX=\overset{\frown}{BX}[/tex]

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:

    [tex]\angle BNX=\dfrac{1}{2}\overset{\frown}{BX}[/tex]

So the relationship between the arc BX, the central angle BCX and the inscribed angle BNX is that both the arc and central angle are equal to twice the inscribed angle:

[tex]\overset{\frown}{BX}=\angle BCX=2\angle BNX[/tex]

A rectangular mural measures 1 meter by 3 meters. Rebekah creates a new mural that is 0. 5 meters longer. What is the perimeter of Rebekah's new mural?

Answers

The perimeter of Rebakh's new mural is 9 meters.

Rebakh has created a new mural which is a rectangle. It is a two-dimensional shape with length and breadth. The original rectangular mural was having dimensions of 1 meter by 3 meters, but the mural Rebekah created was 0.5 meters longer than the original one.

So, now the new mural created by Rebakh has a width of (3 + 0.5 ) = 3.5 meters and a length of 1 meter. The perimeter is defined as the total length of the four sides of the rectangle. To find the perimeter, we will add up the length and width of the rectangle and multiply it by 2. The perimeter of the new mural, in this case, is 1 + 1 + 3.5 + 3.5 = 9 meters.

Therefore, the perimeter of Rebakh's new mural is 9 meters.

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Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Select three options. 2(x2 + 6x + 9) = 3 + 18 2(x2 + 6x) = –3 2(x2 + 6x) = 3 x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot 2(x2 + 6x + 9) = –3 + 9

Answers

Answer:

Inga can use the following steps to solve the quadratic equation 2x^2 + 12x - 3 = 0:

Divide both sides by 2 to simplify the equation: x^2 + 6x - 3/2 = 0.Add 3/2 to both sides to eliminate the constant term on the left-hand side: x^2 + 6x = 3/2.Complete the square by adding (6/2)^2 = 9 to both sides: x^2 + 6x + 9 = 3/2 + 9.Factor the left-hand side as a perfect square: (x + 3)^2 = 27/2.Take the square root of both sides, remembering to include both the positive and negative square roots: x + 3 = ±√(27/2).Simplify the square root: √(27/2) = (√27/√2) = (3√3/√2).Subtract 3 from both sides: x = -3 ± (3√3/√2).Rationalize the denominator by multiplying the numerator and denominator of the second term by √2: x = -3 ± (3√6/2).

Therefore, the steps that Inga could use to solve the quadratic equation are:

2(x^2 + 6x + 9) = -3 + 2(9) (Option 1)

2(x^2 + 6x) = 3 (Option 2)

x + 3 = ±√(27/2) (Option 3)

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Do you pay less at Payless? Mary Ann and Abigail were shopping for prom shoes and wondered


how the prices at Payless compared to the prices


at Famous Footwear. At each store, they randomly


selected 30 pairs of shoes and recorded the price of


each pair. The table shows summary statistics for


the two samples of shoes. 28


Store


Mean


SD


Famous Footwear


$45. 66


$16. 54


Payless


$21. 39 $7. 47


Do these data provide convincing evidence at the


0. 05 significance level that shoes cost less


, on


average, at Payless than at Famous Footwear?


a =

Answers

To test whether shoes cost less on average at Payless than at Famous Footwear, we can conduct a two-sample t-test for the difference in means.

The null hypothesis is that there is no difference in the mean prices between the two stores, and the alternative hypothesis is that the mean price at Payless is less than the mean price at Famous Footwear.

We can calculate the t-statistic using the formula:

t = [tex](x1 - x2 - 0) / sqrt(s1^2/n1 + s2^2/n2)[/tex]

where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

Substituting the values given in the table, we get:

t =[tex](21.39 - 45.66 - 0) / sqrt((7.47^2/30) + (16.54^2/30))[/tex] = -10.78

The degrees of freedom for this test is (30-1) + (30-1) = 58.

Using a t-table or calculator, we find the p-value to be very small, much less than 0.05.

Therefore, we reject the null hypothesis and conclude that there is convincing evidence at the 0.05 significance level that shoes cost less on average at Payless than at Famous Footwear.

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Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 13)(0,13) and (5, 416)(5,416)

Answers

The exponential function in the form y = [tex]ab^x[/tex] that goes through the points (0, 13) and (5, 416) is y = 13 * [tex]2^x[/tex].

To write an exponential function in the form y = [tex]ab^x[/tex] that goes through the points (0, 13) and (5, 416), follow these steps:

1. Use the point (0, 13) to determine the value of a. Since the x-coordinate is 0, we have y = a * b⁰, which simplifies to y = a. Therefore, a = 13.

2. Use the point (5, 416) to determine the value of b. Plug in the values for x and y, as well as the value of a we just found: 416 = 13 * b⁵.

3. Solve for b: b⁵ = 416 / 13 = 32. Taking the fifth root of both sides, we get b = 2.

So, the exponential function in the form y = [tex]ab^x[/tex] that goes through the points (0, 13) and (5, 416) is y = 13 * [tex]2^x[/tex].

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A ramp at a dog park is made of three sections. The incline and decline pieces are the same length, 13√37 inches. The center is 10√41 inches long. What is the total length of the ramp? Give your answer as a radical expression.

Answers

The total length of the ramp is 222.18 inches

How to find the total length?

Let's denote the length of the incline and decline pieces by x, and use the given information to form an equation in terms of x:

Length of incline + length of decline = 2(13√37) inches

= 26√37 inches

The total length of the ramp is the sum of the lengths of all three sections:

Total length = Length of incline + Length of center + Length of decline

Total length = 26√37 inches + 10√41  inches

Total length = 222.18 inches

Therefore, the total length of the ramp is 222.18 inches

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please can someone help i really need help thank you

Answers

The equation of the function h(x) from the transformation is h(x) = f(x + 1)

Describing the transformation of f(x) to h(x).

From the question, we have the following parameters that can be used in our computation:

The functions f(x), g(x) and h(x)

In the graph, we can see that

The graph of f(x) is the parent functionThe graph of h(x) is a shift of 1 unit left

Horizontal Shift = 1 unit left

This is represented as

h(x) = f(x + 1)

This means that the transformation of f(x) to h(x) is f(x) is shifted left 1 unit to h(x).

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When the mortgage is completely paid off for Mark and Lynne’s house, it will be 3 times as old as it is now. If they have 12 years left on the mortgage, how old is the house right now?

Answers

The house is currently 6 years old.

It is mentioned that when the mortgage is completely paid off for Mark and Lynne's house, it will be 3 times as old as it is now. They have 12 years left on the mortgage.

Let's denote the current age of the house as x. When the mortgage is paid off, the house will be x + 12 years old (since they have 12 years left on the mortgage). At that point, the house will be 3 times its current age, so we can write the equation:

x + 12 = 3x

Now we can solve for x:
12 = 2x
x = 6

So, the house is currently 6 years old.

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Find the absolute maximum and absolute minimum values off on the given interval. f(x) = 3x^4 – 4x^3-12x^2 + 1, {-2, 3] absolute minimum value
absolute maximum value

Answers

The absolute maximum value of f(x) on the interval [-2,3] is 201 and occurs at x = -2, and the absolute minimum value of f(x) on the interval [-2,3] is -79 and occurs at x = 2.

To find the absolute maximum and absolute minimum values of f(x) on the interval [-2,3], we need to first find the critical points of the function and evaluate the function at these points as well as at the endpoints of the interval.

To find the critical points, we need to find where the derivative of the function equals zero or does not exist. Taking the derivative of f(x), we get:

f'(x) = 12x^3 - 12x^2 - 24x

Setting this equal to zero and factoring out 12x, we get:

12x(x^2 - x - 2) = 0

Using the quadratic formula to solve for x^2 - x - 2 = 0, we get:

x = -1, 0, 2

These are our critical points.

Now we evaluate f(x) at the critical points and the endpoints of the interval:

f(-2) = 201
f(-1) = 6
f(0) = 1
f(2) = -79
f(3) = 16

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Dilate the figure by the scale factor. Then enter


the new coordinates.


(-1. 4)


A


K = 3


SB


(3,2)


1962,-2)


A’ ([?], []).


B'(]], [])


C), D

Answers

Dilating the figure by a scale factor of 3, the new coordinates are:

A' (-3, 12)

B' (9, 6)

C' (5886, -6)

D (unknown)

To dilate a figure by a scale factor, we need to multiply the coordinates of each point by the scale factor. Given the scale factor K = 3, we can dilate the figure using the formula:

New x-coordinate = K * original x-coordinate

New y-coordinate = K * original y-coordinate

Let's apply this to the given coordinates:

(-1, 4)

New x-coordinate = 3 * (-1) = -3

New y-coordinate = 3 * 4 = 12

A' (-3, 12)

(3, 2)

New x-coordinate = 3 * 3 = 9

New y-coordinate = 3 * 2 = 6

B' (9, 6)

(1962, -2)

New x-coordinate = 3 * 1962 = 5886

New y-coordinate = 3 * (-2) = -6

C' (5886, -6)

Dilating the figure by a scale factor of 3, the new coordinates are:

A' (-3, 12)

B' (9, 6)

C' (5886, -6)

D (unknown)

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80.0% complete


question


a customer wants you to enlarge a photo to 234 its current height. the photo’s current height is 314 inches. what should its enlarged height be, in inches?

Answers

If the photo’s current height is 314 inches, the enlarged height should be approximately 547.6 inches (rounded to one decimal place), which is 80.0% larger than the current height.

To calculate the enlarged height, you need to find out the percentage increase in height from the current height to the desired height.

The desired height is 234 inches, which is 234/314 = 0.744 or 74.4% of the current height.

To find the actual enlarged height, you need to increase the current height by 74.4%.

Enlarged height = current height + (current height x percentage increase)
Enlarged height = 314 + (314 x 0.744)
Enlarged height = 314 + 233.616
Enlarged height = 547.616

Therefore, the enlarged height should be approximately 547.6 inches (rounded to one decimal place), which is 80.0% larger than the current height.

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A company manufactures and sells x microwaves per month. The monthly price-demand equation is: p(x) = 280 – 0.4z (a) Assuming that the manufacture would like to charge between $100 and $500 for microwaves, find the price that maximizes the revenue. (b) What is the maximum revenue from selling microwaves?

Answers

The price that maximizes revenue for the given monthly price-demand equation with price range between $100 and $500 is $220.

(b) The maximum revenue from selling microwaves can be found by multiplying the price that maximizes revenue by the corresponding quantity of microwaves sold. Using the price-demand equation p(x) = 280 - 0.4x, we can find the quantity that corresponds to the price that maximizes revenue as follows:p(x) = 280 - 0.4x220 = 280 - 0.4x0.4x = 60x = 150Therefore, the quantity that corresponds to the price that maximizes revenue is x = 150. The maximum revenue can be found by multiplying the price and quantity:Revenue = Price * QuantityRevenue = $220 * 150Revenue = $33,000Therefore, the maximum revenue from selling microwaves is $33,000.

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Ross Times, the student newspaper of Ross College, printed a "What do you think?" column feature asking: "Do you think that the college is doing enough to provide student parking?" Anyone could mail in a response or use the paper's Web site to respond. In all, 126 answers were received.




This is an example of:




(a) a voluntary response sample.



(b) a multistage sample.



(c) a simple random sample.



(d) a convenience sample.



(e) the placebo effect

Answers

The answer is (d) a convenience sample.

This is because the sample is not randomly selected from the population of all students at Ross College. Instead, it relies on individuals who are willing and available to respond to the question through the methods provided by the newspaper.

Therefore, the sample is more likely to be composed of individuals who feel strongly about the issue of student parking or who have had particularly positive or negative experiences with it, rather than being representative of the entire population of Ross College students.

In conclusion, the Ross Times student newspaper's feature column asking for opinions on the provision of student parking at Ross College represents a convenience sample of responses, and may not be representative of the entire population of Ross College students.

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Bilquis is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 29 meters from the building. The angle of elevation from her eyes to the roof (point A) is 17°, and the angle of elevation from her eyes to the top of the antenna (point B) is 31º. If her eyes are 1. 51 meters from the ground, find the heigh[of the antenna (the distance from point A to point B). Round your answer to the nearest meter if necessary. ​

Answers

The height of the antenna is approximately 17 meters.

To solve for the height of the antenna, we need to use trigonometry. Let's call the height of the antenna "h".

First, we need to find the distance from point A to point B. We can use the angle of elevation from her eyes to the roof (17°) and the horizontal distance from the building (29m) to find the height of the building.

tan(17°) = height of building / 29m

height of building = 29m * tan(17°)

height of building = 8.20m

Now we can use the height of the building and the angle of elevation from her eyes to the top of the antenna (31°) to find the distance from point A to point B.

tan(31°) = h / 29m + 8.20m

h = (29m + 8.20m) * tan(31°)

h = 15.51m

Finally, we need to add the height of Bilquis' eyes to the height of the antenna to find the total height.

total height = h + 1.51m

total height = 17.02m

Therefore, the height of the antenna is approximately 17 meters.

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HELPPPPP FAST PLEASEEEE

Answers

Answer:

AEC is similar to BDC in terms of the type of triangle

That's all I can really say

I hope this helps :)

The circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle. (In other words, they have the same radius. ) What is the area of the rectangle (called the lane) whose length is 19 feet and whose width is the free throw line?

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So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.

What is the length of the rectangle and how many free throw line square feet?  

Since the circle at each end of the court that surrounds the free throw line is the same size as the jump ball circle, they both have the same radius. Let's call this radius "r".

The diameter of the circle is equal to the width of the lane, which is the same as the width of the free throw line. Therefore, the diameter of the circle is also 12 feet (the width of the free throw line is always 12 feet).

We know that the area of a circle is given by the formula A = πr^2, so the area of each circle is πr^2.

The rectangle (or lane) has a length of 19 feet and a width of 12 feet. Therefore, its area is simply the product of its length and width, which is:

A = 19 feet * 12 feet

A = 228 square feet

Since there are two circles, the total area of the circles is 2πr^2.

We know that the diameter of the circle is equal to the width of the lane, which is 12 feet. Therefore, the radius is half of the diameter, or:

r = 12 feet / 2

r = 6 feet

Now we can calculate the area of the circles:

A = 2πr^2

A = 2π(6 feet)^2

A = 72π square feet

Therefore, the total area of the rectangle and circles (or lane and circles) is:

A_total = A_rectangle + A_circles

A_total = 228 square feet + 72π square feet

A_total ≈ 450.39 square feet

So the area of the rectangle (or lane) whose length is 19 feet and whose width is the free throw line, together with the two circles at each end of the court that surround the free throw line, is approximately 450.39 square feet.

Learn more about the length of the rectangle

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how many times can 2 go into 1742? please its for my homework due tomorrow

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2 goes into 1742, 871 times.
871 times and that’s your answer to your question

Find the sum of all the integers between 100 and 400 that are multiples of 6. ​

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Answer:

The sum of all numbers divisible by 6 between 100 and 400 is 12450.

Step-by-step explanation:

I think this is correct.

If it isn't, I'm sorry.

In the number 217 361. 05 which digit is in the hundreds place?

Answers

Answer:3

Step-by-step explanation: We see that 217361.05 =217000+361.05 so our answer is 3

< Question 7 Σ Next Use partial fraction decomposition to evaluate the integral: (198r2 + 9r – 50 dr 99r2 - 26r - 8

Answers

The value of integral of (198r² + 9r – 50 dr  is  (16/27)ln|11r + 2| - (2/3)ln|9r - 4| + C


Now, we can write the integrand as a sum of two fractions:

(198r² + 9r - 50) / (11r + 2)(9r - 4) = A/(11r + 2) + B/(9r - 4)

To find A and B, we need to solve for them using the method of equating coefficients:

198r² + 9r - 50 = A(9r - 4) + B(11r + 2)

Setting r = 4/9 and r = -2/11, we get two equations:

198(4/9)² + 9(4/9) - 50 = A(9(4/9) - 4) + B(11(4/9) + 2)

198(-2/11)² + 9(-2/11) - 50 = A(9(-2/11) - 4) + B(11(-2/11) + 2)

Solving these equations gives A = 16/27 and B = -2/3.

So, the integral can be written as:

∫(198r² + 9r - 50) / (11r + 2)(9r - 4) dr = ∫16/27(11r + 2)^-1 dr - ∫2/3(9r - 4)^-1 dr

Integrating each term gives:

(16/27)ln|11r + 2| - (2/3)ln|9r - 4| + C

where C is the constant of integration.

In summary, using partial fraction decomposition, we can express the given integral as a sum of two simpler integrals, which can be evaluated using the natural logarithm function.

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Find the inverse for each relation: 4 points each 1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)}

Answers

To find the inverse of a relation, we need to swap the x and y coordinates of each point. The inverse of the given relation is:

{(-2, 1), (3, 2), (-3, 3), (2, 4)}

Therefore, the inverse of the relation {(1,-2), (2,3), (3,-3), (4,2)} is {(-2,1), (3,2), (-3,3), (2,4)}.
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