It costs $20 a day to rent a car and $30 for a full tank of gas. If Stacy fills up the tank 3 times and has the car rented for 14 days, how much does she owe?
Answer:
$20 × 14 days = $280
&30 × 3 = $90
&280 + $90 = $370
Answer:
For car she owes=
$20 x 14 = $280
For tank she owes=
$30 x 3 = $90
Therfore in total she owes,
$280 + $90 = $370
please help I need so much help right now I feel like crying
Answer:
ok the first point there is (-4;-3)
the second point is(0;-6)
Answer the following
The set A satisfying the given inequality is A = (-[tex]\infty[/tex], -10].
What are some properties of an inequality relation?Following are some facts which are true for an inequality relation:
Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.[tex]\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)[/tex]
Since y ∈ B, -2 ≤ y ≤ 7. So,
[tex]\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\; y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.[/tex]
The set {-x | inequality (1) holds ∀ y ∈ B} is [10, [tex]\infty[/tex]) i.e.
10 ≤ -x ≤ [tex]\infty[/tex].
Multiplying -1 throughout gives
-10 ≥ x ≥ -[tex]\infty[/tex].
x, thus, lies in the range A = (-[tex]\mathbf{\infty}[/tex], -10}.
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Disclaimer: The question was incomplete. Please find the full content below.
QuestionFind the set A such that for x ∈ A
[tex]\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y[/tex]
∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.
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I need help answering these questions for geometry :)
1. What happens to the measure of the interior angles as the number of sides of the polygon increases? Explain your answer.
2.What happens to the measure of the exterior angles as the number of sides of the polygon increases? Explain your answer.
4. Explain what happens to the total sum of interior angles as the number of sides in the polygon changes.
5. Explain what happens to the total sum of exterior angles as the number of sides in the polygon changes.
The answers to the question have been written below
The changes to a polygon1. If the number of sides of the polygon should increase then the measure of the interior angle would increase by 180.
2. A regular polygon has the sum of its external angles as 360. This is solved as 360/n = 0
Hence the value of the exterior would move towards 0 as its sides increases.
4. As the total sum of the of the polygon changes, it would tend towards infinity.
5. The total sum of the exterior angles as the number of sides changes would tends towards 360 degrees.
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What is the answer for 4x+1/3=20?
Answer:
x = 59/12
Step-by-step explanation:
4x + 1/3 = 20
4x = 20 - 1/3
12x/3 = 60/3 - 1/3
12x = 60 - 1
12x = 59
x = 59/12
Check:
4*59/12 + 1/3 = 20
236/12 + 4/12 = 20
240/12 = 20
Which best describes the data set? it is nonlinear because the ""total houses built"" column does not increase at a constant additive rate. it is nonlinear because the ""months passed"" column does not increase at a constant additive rate. it is nonlinear because the increase in the ""total houses built"" compared to the increase in the ""months passed"" does not show a constant rate of change. it is linear because the increase in the ""total houses built"" compared to the increase in the ""months passed"" shows a constant rate of change.
Answer :C)It is nonlinear because the increase in the “Total Houses Built” compared to the increase in the “Months Passed” does not show a constant rate of change.
:) hope you have a great day!
PLEASE HELPPPP
one gym membership charges $10 a month with a sign-up fee of $45. Another gym does not charge patrons a sign-up fee but costs $25 a month. at what month is the total cost of both memberships the same?
Answer:
3 MonthsStep-by-step explanation:
Please give me Brainliest!
Which expression is equivalent to (startfraction x superscript negative 4 baseline y over x superscript negative 9 baseline y superscript 5 baseline endfraction) superscript negative 2? assume x not-equals 0, y not-equals 0.
The equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]
Complete questionWhich expression is equivalent to [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]
How to determine the equivalent expression?The expression is given as:
[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]
Apply the exponent law of indices
[tex](\frac{x^{-9}y^5}{x^{-4}y})^{2}[/tex]
Next, we apply the common base law of indices
[tex](x^{4 -9}y^{5-1})^2[/tex]
Evaluate the difference
[tex](x^{-5}y^4)^2[/tex]
Remove bracket
[tex]x^{-10}y^8[/tex]
Hence, the equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]
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Answer:
y^8/x^10
Step-by-step explanation:
The guy above me is right but just forgot to distribute the negative out of x. :)
Which of the following points is NOT visible if the viewing window of a graphing utility is set at:
Xmin : 6
Xmaz: 6
Ymin : —6
Ymaz : 6
The points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible the answers are D, E, and H.
What is graphing utility?A graphing calculator is a portable computer that can plot graphs, solve multiple equations at once, and carry out other variable-related activities.
We have points shown in the coordinate plane.
As the window of a graphing utility is set at:
X(min) : -6
X(max): 6
Y(min) : -6
Y(max) : 6
The points out of 6 will not be visible.
We can draw a square as shown in the attached picture.
The points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible.
Thus, the points D(-7, 5), E(-8, -3), and H(10, -5) will not be visible the answers are D, E, and H.
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What are the slope and the y-intercept of the linear function that is represented by the graph?
answer C is “The slope is Negative three-fourths, and the y-intercept is 3.”
answer D is “The slope is Negative three-fourths, and the y-intercept is 4”
Answer:
“The slope is Negative three-fourths, and the y-intercept is 3.”
Step-by-step explanation:
the graph passes through the points (0 , 3) and (4 , 0)
Then
The slope is :
[tex]=\frac{0-3}{4-0}[/tex]
[tex]=-\frac{3}{4}[/tex]
Since , the graph passes through (0 , 3)
THen the y-intercept is 3.
PLEASE HURRY WILL GIVE POINTS AND BRAINLYEST TO FIRST RIGHT!!!
Answer:
(0, 4) and (-1, 0)
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}y=2x^2+6x+4\\y=-4x^2+4\end{cases}[/tex]
Solve by substitution
Substitute the first equation into the second:
[tex]\implies 2x^2+6x+4=-4x^2+4[/tex]
Add 4x² to both sides:
[tex]\implies 2x^2+6x+4+4x^2=-4x^2+4+4x^2[/tex]
[tex]\implies 6x^2+6x+4=4[/tex]
Subtract 4 from both sides:
[tex]\implies 6x^2+6x+4-4=4-4[/tex]
[tex]\implies 6x^2+6x=0[/tex]
Factor out 6x from the left side:
[tex]\implies 6x(x+1)=0[/tex]
Therefore:
[tex]\implies 6x=0 \implies x=0[/tex]
[tex]\implies x+1=0 \implies x=-1[/tex]
To find the y-coordinates of the found x-values, substitute the found values of x into one of the equations:
[tex]x=0 \implies -4(0)^2+4=4 \implies (0,4)[/tex]
[tex]x=-1\implies -4(-1)^2+4=0\implies (-1,0)[/tex]
Therefore, the solutions to the system of equations are:
(0, 4) and (-1, 0)
Answer:
Solutions:
a) x = 0, y = 4 ⇒ (0, 4)
b) x = -1, y = 0 ⇒ (-1, 0)
Step-by-step explanation:
Given system of equations:
a) y = 2x² + 6x + 4
b) y = -4x² + 4
1. Substitute the value of y in the second equation into the first equation:
⇒ -4x² + 4 = 2x² + 6x + 4
2. Solve for x:
⇒ -4x² + 4 = 2x² + 6x + 4 [subtract 4 from both sides]
⇒ -4x² + 4 - 4 = 2x² + 6x + 4 - 4
⇒ -4x² = 2x² + 6x [subtract 2x² from both sides]
⇒ -4x² - 2x² = 2x² - 2x² + 6x
⇒ -6x² = 6x [subtract 6x from both sides]
⇒ -6x² - 6x = 6x - 6x
⇒ -6x² - 6x = 0 [factor out -6x from the equation]
⇒ -6x(x + 1) = 0
Two cases:
a)
⇒ -6x = 0 [divide both sides by -6]
⇒ -6x ÷ -6 = 0 ÷ -6
⇒ x = 0
b)
⇒ x + 1 = 0 [subtract 1 from both sides]
⇒ x + 1 - 1 = 0 - 1
⇒ x = -1
3. Find the value of y by substituting the found x values into one of the given equations:
a) x = 0:
⇒ y = -4x² + 4
⇒ y = -4(0)² + 4
⇒ y = -4(0) + 4
⇒ y = = 0 + 4
⇒ y = 4
coordinate: (0, 4)
b) x = -1:
⇒ y = -4x² + 4
⇒ y = -4(-1)² + 4
⇒ y = -4(1) + 4
⇒ y = -4 + 4
⇒ y = 0
coordinate: (-1, 0)
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What is the domain and range of the following graph?
Answer:
Domain is all x-values and range is all y values. See all of the x values and y values that are touching the graph. Also, when there is a circle/ hole, use parenthesis for the interval notation. Hope it helps!
On a coordinate plane, a right triangle has points A (negative 5, negative 6), B (negative 5, negative 2), C (negative 2, negative 2). Examine the right triangle ABC. Which rise and run would create a similar right triangle on the same line? a rise of 6 and a run of 8 a rise of 8 and a run of 6 a rise of 6 and a run of 5 a rise of 5 and a run of 6
The rise and run that would give us a similar right triangle on the same given line is: B. a rise of 8 and a run of 6.
What is the Rise and Run of Points on the Same Line?The rise/run of any two points on the same line are have the same slope value.
Given the coordinates:
A(-5, -6)B(-5, -2)The rise of triangle ABC = change in y = 4 units
The run of triangle ABC = change in x = 3 units
Rise/run = 4/3
Therefore, a rise of 8 and a run of 6 would give us: 8/6 = 4/3.
This will give us a triangle similar to triangle ABC.
Therefore, the answer is: B. a rise of 8 and a run of 6.
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[tex]\sqrt{6} /\sqrt{27}[/tex]
[tex]\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \dfrac{\sqrt{a}}{\sqrt{b}}=\sqrt{\dfrac{a}{b }},\:\quad \:a\ge 0,\:b\ge 0[/tex]
[tex]\dfrac{\sqrt{6}}{\sqrt{27}}=\sqrt{\dfrac{6}{27}}[/tex]
[tex]=\sqrt{\dfrac{6}{27}}[/tex]
[tex]\mathrm{ Cancel \ \ \dfrac{6}{27} \ \ \ ; \ \ \dfrac{2}{9} }[/tex]
[tex]=\sqrt{\dfrac{2}{9}}[/tex]
[tex]\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b }},\:\quad \:a\ge 0,\:b\ge 0[/tex]
[tex]=\sqrt{\dfrac{2}{9}}[/tex]
[tex]\sqrt{9}=3[/tex]
[tex]=\dfrac{\sqrt{2}}{3} \ \ === > \ \ \ Answer[/tex]
[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
¿Cuáles son las soluciones x1 y x2 de la ecuación x2 − 5x − 6 = 0?
Answer:
x1 = 4 y x2= 2
Step-by-step explanation:
escuchame
x2 - 5x -6 = 0
(4)^2 - 5(2) - 6 = 0
16 - 10 - 6 = 0
6 - 6 = 0
de nade :)
PLEASE HELP I WILL MARK BRAINLEST
#1
Error at sign shift due to -Correct version
[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]
[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]
[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]
#2
Not multiplied 3x with x[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]
[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]
[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]
[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]
A water sample shows 0.033 grams of some trace element for every cubic centimeter of water. Marques uses a container in the shape of a right cylinder with a diameter of 13.2 cm and a height of 19.7 cm to collect a second sample, filling the container all the way. Assuming the sample contains the same proportion of the trace element, approximately how much trace element has Marques collected? Round your answer to the nearest tenth.
Answer:
89.0 grams of trace element
Step-by-step explanation:
Step 1Find the volume of the sample container.
Given:
Container is a right cylinder with d = 13.2 cm and h = 19.7 cmVolume formula:
V = πr²h = πd²h/4Substitute to get:
V = π(13.2)²(19.7)/4 = 2695.9 cm³ (rounded)Step 2Find the volume of the trace element, using the given proportion:
2695.9*0.033 = 89.0 grams (rounded)2 Pretest: Unit 5
Question 19 of 27
Find the value of x that makes ABCD a parallelogram.
x+60°
70°
O A. x= 10°
OB. x= 30°
OC. X= 40°
OD. x = 50°
A
70°
x+60°
B
The value of x will be 50°. Then the correct option is D.
What is a parallelogram?It is a polygon with four sides. The total interior angle is 360 degrees. A parallelogram's opposite sides are parallel and equal.
Then the sum of the adjacent angle of the parallelogram is 180 degrees.
Then the value of x that makes ABCD a parallelogram will be
The one angle is x+60°.
Then the another angle will be 70°.
Then we have
x + 60° + 70° = 180°
x + 130° = 180°
x = 50°
Then the correct option is D.
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If an employer reduces the working week from 40 hours to 35 hours, with no
loss of weedy pay, calculate the percentage increase in the hourly rate of pay.
Answer:
14.285714285714 %
Step-by-step explanation:
suppose the weekly payment is of x dollars
Then
Previous payment : $(x/40) per hour
New payment : $(x/35) per hour
Then
The percentage increase in the hourly rate of pay is :
[tex]=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100[/tex]
[tex]=\frac{\frac{5x}{1400} }{\frac{x}{40} } \times100[/tex]
[tex]=\frac{5x}{1400} \times \frac{40}{x} \times100[/tex]
[tex]=\frac{200}{1400} \times100[/tex]
[tex]=\frac{1}{7} \times100[/tex]
[tex]=14.285714285714[/tex]
A packet of low fat vegetable soup has a mass of 70.5 g. find the mass of 50 such packets
Answer:
300.25
Step-by-step explanation:
The mass of 1 packet of low fat vegetable soup is 70.5g, the mass of 50 packets is 300.25g(70.5x50).
The mass of 50 low-fat vegetable soups has a mass equal to 300.25 g.
Given : The mass of 1 packet of low-fat vegetable soup is 70.5g
To find: The mass of 50 such packets
Concept: In mathematics, a product is the result of multiplication, or an expression that identifies factors to be multiplied. For example, 30 is the product of 6 and 5
The mass of 50 such packets is 70.5x50 i.e., mass of 1 pkt* number of packets given which is given to be 70.5 and 50 respectively
= 300.25 g.
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PLEASE HELP 20 POINTS
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P.
A -105
B -75
C 75
D 105
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P at; D: 105°
How to Interpret Rotation of objects?From the given image, If we connect points C of the blue quadrilateral to point C' of the rotated quadrilateral using the center of rotation P, then we will notice that ∠CPC' will be greater than 90°.
Now, the rotation is counterclockwise and it therefore means that the angle of rotation is will be positive and since ∠CPC' is greater than 90°, then we can say that the only correct option is Option D which is 105°
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Sin (5x-28) = cos (3x - 50)
By using trigonometric identities we can solve the trigonometric equation Sin (5x-28) = cos (3x - 50) for x.
What is trigonometry?Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
The question is incomplete.
The complete question is:
Solve for X given that sin(5X - 28)° = cos(3X - 50)°.
We have given:
sin(5X - 28)° = cos(3X - 50)°.
[tex]\rm \sin \left(5x-28\right)=\sin \left(\dfrac{\pi }{2}-\left(3x-50\right)\right)[/tex]
[tex]\rm \left5x-28\right= \left\dfrac{\pi }{2}-\left(3x-50\right)\right[/tex]
[tex]\rm x=\dfrac{4\pi n+156+\pi }{16}[/tex] (n = 0, 1, 2, ...)
[tex]\rm x=\dfrac{\pi +4\pi n-44}{4}[/tex]
Thus, by using trigonometric identities we can solve the trigonometric equation Sin (5x-28) = cos (3x - 50) for x.
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The least common denominator of 5/6, 2/3, and 3/5 is:
Answer:
30
Step-by-step explanation:
What is the value of 3 in this number? 728. 36
Answer:
The place value of 3 is tens
the 3 is in the value of tens
Which formulas could you use to find the volume of a right circular
cone?
OA) V = B-h where B = I-w
OB) V=B-h where B=1r'
OC) V=B-h where B = Tr
OD) V=B-h where B=1-w
Answer:
The formula for the volume of a cone is V=1/3hπr².
The depreciation method that does not initially use the residual value in depreciation calculations is the.
An asset loses value over time as a result of use, damage, or obsolescence.
What is depreciation?An asset loses value over time as a result of use, damage, or obsolescence. Depreciation is the measurement for this decline.
The depreciation method that does not initially use the residual value in depreciation calculations is the depreciating balance.
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Which equation completes the system that is satisfied by the solution (1, 1)?
02x+y = 2
O4x - 2y = 2
02x - 2y = 2
Ox+y = 4
Answer: B. 4x-2y=2
Step-by-step explanation:
We will work this out one by one. Plug in the x and y values of the solution to the equations and you will see which one is true or false.
A. [tex]2(1)+y(1)=2\\2+1\neq 2[/tex] B. [tex]4(1)-2(1)=2\\4-2=2[/tex]
C. [tex]2(1)-2(1)=2\\2-2\neq 2[/tex] D. [tex]x(1)+y(1)=4\\1+1\neq 4[/tex]
With this information, we see that B is the correct answer.
I hope this helped!! Pls mark brainliest!! :))
Think About a Plan Write an indirect proof.
Proof
Given: 41 42
Prove:
p
• What assumption should be the first step of your proof?
. In the figure, what type of angle pair do 21 and 22 form?
1) Either [tex]\ell \parallel p[/tex] or [tex]\ell[/tex] ∦ [tex]p[/tex] (only two possibilities)
2) Assume [tex]\ell \parallel p[/tex] (one of two possibilities)
3) [tex]\angle 1 \cong \angle 2[/tex] (if two parallel lines are cut by a transversal, the corresponding angles are congruent)
4) But [tex]\angle 1[/tex] is not congruent to [tex]\angle 2[/tex] (given)
5) So [tex]\ell[/tex] ∦ [tex]p[/tex] (only other possibility)
What is the equivalent exponential expression for the radical expression below? √3+7
Answer:
09 l
Step-by-step explanation:
p0-9
The equivalent exponential expression for the given radical expression √(3 + 7) is √10.
To convert the given radical expression √(3 + 7) into its equivalent exponential expression. This process involves using exponentiation to represent the radical form.
The given radical expression is √(3 + 7). To find its equivalent exponential expression, we need to express the radical in terms of an exponent.
Recall that a radical expression of the form √(a) is equivalent to raising 'a' to the power of 1/2. In this case, 'a' is the quantity inside the radical, which is 3 + 7. So, we can write:
√(3 + 7) = (3 + 7)^(1/2).
Next, we simplify the expression inside the parentheses:
3 + 7 = 10.
Now, the expression becomes:
(10)^(1/2).
To further simplify, we raise 10 to the power of 1/2. Recall that raising a number to the power of 1/2 is the same as finding the square root of that number. So:
(10)^(1/2) = √10.
Therefore, the equivalent exponential expression for the given radical expression √(3 + 7) is √10.
To summarize, we transformed the radical expression √(3 + 7) into its equivalent exponential expression √10 by using the rule that √(a) is equal to a^(1/2). By raising the expression inside the radical to the power of 1/2, we simplified it and found the square root of 10 as the final result.
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Find the nth term of this number sequence
1, 7, 13, 19, ...
Answer:
now we have to follow up with the formula n² - n¹
which is 7-1= 6
n³-n²
which is 13-7=6
so therefore the nth term=6
