Reddy
algebraic expressions with exponents - instruction - level f
) amelia stores her gardening supplies in two cube-shaped boxes. the smaller box has a
volume of 100 in.. amelia wants to know the total volume of both boxes.
s = length (in) of one side of the larger box.
6) write an expression to show the total
volume of the two boxes.

The proper options provided for the required equation of a circle is

At the center of the circle there rests a y-axis, so its x-coordinate is equal to 0.

The formula for a specified circle with coordinates (0, k) and radius r is  

(x - 0)² + (y - k)² = r²

Therefore, the equation ends up categorically signified by:

x2 + (y – 3)2 = 36

x2 + (y + 8)2 = 36

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The value of secθ in simplest radical form is:

[tex]sec\theta = -\frac{\sqrt{61} }{5}[/tex]

If the point is given on the terminal side of an angle, then:

Calculate the distance between the point given and the origin:

[tex]r = \sqrt{x^{2} +y^2}[/tex]

Here, x = -5 and y = -6

The secant can be found by the following trigonometric relation:

[tex]sec\theta = \frac{1}{cos\theta}[/tex]

[tex]sec\theta = \frac{1}{\frac{x}{r} }\\ \\sec\theta = \frac{r}{x}\\ \\sec\theta = \frac{\sqrt{x^{2} +y^2} }{x}\\ \\sec\theta =\frac{\sqrt{(-5)^2+(-6)^2} }{-5}\\ \\sec\theta = -\frac{\sqrt{61} }{5}[/tex]

The secant function ‘or’ Sec Theta is one of the trigonometric functions apart from sine, cosine, tangent, cosecant, and cotangent. In right-angled trigonometry, the secant function is defined as the ratio of the hypotenuse and adjacent side.

Now , the secθ functions:

[tex]sec\theta = -\frac{\sqrt{61} }{5}[/tex]

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The given question is incomplete, complete question is:

If θ is an angle in standard position and its terminal side passes through the point (-5,-6), find the exact value of secθ in simplest radical form.

The differential for the function y = 5x^3 - 9x^2 + 9x + 10 is dy/dx = 15x^2 - 18x + 9.

Given function,

y = 5x^3 - 9x^2 + 9x + 10.

2. Differentiate the function with respect to x:

dy/dx = d(5x^3)/dx - d(9x^2)/dx + d(9x)/dx + d(10)/dx

3. Apply the power rule for differentiation (d(x^n)/dx = n*x^(n-1)):

dy/dx = 3*(5x^2) - 2*(9x) + 9

4. Simplify the expression:

dy/dx = 15x^2 - 18x + 9

So, the differential for the function y = 5x^3 - 9x^2 + 9x + 10 is dy/dx = 15x^2 - 18x + 9.

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Answer:

To find the radius of the cylinder, we can use the formula for the volume of a cylinder, which is pi*(r1^2)*h, where r1 is the radius and h is the height. Given that the cylinder has a height of 6 centimeters and a volume of 302 cubic centimeters, we can solve for r1 by dividing the volume by pi times the height, and then taking the square root of the result. After rounding to the nearest whole centimeter, the radius of the cylinder is approximately 5 centimeters.

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The discount is 26%.

The discount equals the difference between the price paid for and it's par value. Discount is a kind of reduction or deduction in the cost price of a product.

Given:

[tex]\bold{Marked} \ \text{price} = \$25[/tex]

[tex]\bold{Selling} \ \text{price} = \$18.50[/tex]

So,

[tex]\text{Discount = MP - SP}[/tex]

[tex]\text{Discount} = 25-18.50[/tex]

[tex]\bold{Discount} = 6.50[/tex]

Now,

[tex]\text{D}\% = \dfrac{\text{D}}{\text{MP}} \times100[/tex]

[tex]\text{D}\% = \dfrac{6.5}{25} \times100[/tex]

[tex]\text{D}\% = 26\%[/tex]

Hence, the discount percent is 26%.

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To calculate the total dinner cost, we need to add the bill amount to the tip amount.

The tip amount is 18% of the bill amount:

Tip = 0.18 x $57.50 = $10.35

Therefore, the total dinner cost is:

Total Cost = Bill Amount + Tip Amount

Total Cost = $57.50 + $10.35

Total Cost = $67.85

So, the total dinner cost including the 18% tip is $67.85.

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Check the picture below.

[tex]52x=\cfrac{154-50x}{2}\implies 104x=154-50x\implies 154x=154\implies x=\cfrac{154}{154} \\\\\\ x=1\hspace{9em}\stackrel{ 50(1) }{\widehat{SU}=50^o}[/tex]

a). The scale factor of shape A to B is 4/5

b) The value of t is 5.6cm

The scale factor is a measure for similar figures, who look the same but have different scales or measures.

Scale factor = dimension of new length/ dimension of old length

= 4/5 = 12/15

therefore the scale factor of from shape A to shape B is 4/5.

b) 4/5 = t/7

5t = 28

divide both sides by 5

t = 28/5

t = 5.6 cm

therefore the value of t is 5.6cm

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The statement "limit as x goes to infinity of the quotient of f of x and g of x equals 5" means that as x gets larger and larger, the ratio of f(x) to g(x) approaches 5.

If f(x) grows faster than g(x) as x goes to infinity, then the ratio of f(x) to g(x) would approach infinity, not 5.

If f(x) and g(x) grow at the same rate as x goes to infinity, then the ratio of f(x) to g(x) would approach a constant value, not necessarily 5.

Therefore, the statement "limit as x goes to infinity of the quotient of f of x and g of x equals 5" shows that g(x) grows faster than f(x) as x goes to infinity. L'Hôpital's Rule is not necessary to determine this conclusion.

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Answer:

B

Step-by-step explanation:

What is a linear equation?

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

Given we can see that the line intersects with the Y-Intercept at (0,3), we can use process of elimination and erase answer choices A and D.

Now we are left with answr choices B and C, lets see where the line intersects with the X axis.

Helpful Tip:

If the line intersects with the X-Axis in between whole numbers, like for example this line intersects between 1 and 2, the slope will always be a fraction, which in this case the only fraction that we have left in answer choice B, which leads us to our answer.

If a baseball pitcher records 153 strikeouts in his first year pitching with the number of strikeouts decreasing by 31% yearly, and if the trend continues, the upper limit on the total of strikeouts over the pitcher's lifetime is 153.

The upper limit refers to the maximum value possible.

The initial number of recorded strikeouts = 153

The annual decay rate = 31%

Decay factor = 0.69 (1 - 0.31)

Let the number of strikeouts in the year = y

Let the number of years of pitching = x

y = 153(0.69)^x

For instance, if x = 3, y = 153(0.69)^3

y = 50

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The probability that a student chosen randomly from the class has a brother is approximately 0.143 or 14.3%.

To find the probability that a student chosen randomly from the class has a brother, we need to look at the number of students who have a brother and divide it by the total number of students in the class.

From the given data table, we see that there are a total of 4+2+12+10=28 students in the class. Out of these, 4 students have a brother. Therefore, the probability that a student chosen randomly from the class has a brother is:

P(having a brother) = Number of students having a brother / Total number of students

= 4 / 28

= 1/7

≈ 0.143

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The probability to get 5 and blue that is the value of P(5 and blue) = 1/24.

Hence the correct option is (B).

From the definition of Probability we can know that,

Probability of an event = (The number of outcomes favorable to the event)/(Total number of outcomes)

Here, Sample space if we roll a dice = {1, 2, 3, 4, 5, 6}

Total number of outcomes = 6

5 is one of the face value of dice.

The probability to get 5 on dice as face value = 1/6.

So, P(5) = 1/6

In picture we can see that there is total 4 space that are one blue and two yellow and one green space.

So the probability spinner land on blue space = 1/4

So, P(blue) = 1/4

Roll of dice and spin a spinner are two independent events as their outcomes do noy rely on each other.

Now the probability to get 5 and blue is given by,

= P(5 and blue)

= P(5)*P(blue)

= (1/6)*(1/4)

= 1/(6*4)

= 1/24

Hence the correct option is (B).

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Answer:

x = 4, y = 1, z = 5

Step-by-step explanation:

z + x =9....(3) we can say it's x + z = 9

x - z = - 1

x + z = 9

______ -

- 2z= - 10

z = 10/2

z = 5

if z + x = 9

5 + x = 9

x = 9 - 5

x = 4

if x + y = 5

4 + y = 5

y = 5 - 4

y = 1

There are 400,000 grains of sugar in a small bag of sugar that weighs 0.24 kilograms.

To find out how many grains of sugar are there in a small bag of sugar that weighs 0.24 kilograms, based on Marcus' estimate, follow these steps:

1. Convert the mass of the bag of sugar from kilograms to grams: 0.24 kg * 1000 g/kg = 240 g.
2. Use Marcus' estimate of the mass of a grain of sugar: 6 x 10^-4 g.
3. Divide the total mass of the bag of sugar by the mass of a single grain of sugar: 240 g / (6 x 10^-4 g/grain).

Now, let's perform the calculation:
240 g / (6 x 10^-4 g/grain) = 240 g / 0.0006 g/grain = 400,000 grains.

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The slope of the tangent line to the function [tex]s(t) = 8 - 41t^2[/tex] at t = -3 is 246.

1. Differentiate the function s(t) with respect to the independent variable t: [tex]s(t) = 8 - 41t^2[/tex].
2. Calculate the derivative s'(t).
3. Evaluate the derivative at the given value of t.
Step 1: Differentiate the function [tex]s(t) = 8 - 41t^2[/tex].
To differentiate this function, we apply the power rule for differentiation.

The derivative of a constant (8) is 0, and the derivative of 41t^2 is -82t

(since we multiply the exponent 2 by the coefficient 41 and then subtract 1 from the exponent).
Step 2: Calculate the derivative s'(t).
s'(t) = 0 - 82t
Step 3: Evaluate the derivative at the given value of t (t = -3).
s'(-3) = -82(-3) = 246
The slope of the tangent line to the function [tex]s(t) = 8 - 41t^2[/tex] at t = -3 is 246.

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For the first question:
There are 6 notes and 6 envelopes, so there are 6! (or 720) possible ways to insert the notes into the envelopes. Only one of these ways will result in all notes being inserted into the correct envelopes. Therefore, the probability is 1/720 or 0.001389.

For the second question:
(A) There are 2 gold courses and twice as many bronzes as silver courses, so there are 2 + 2x + x = 20 courses in total, where x is the number of silver courses. Solving for x, we get x = 6. Therefore, there are 2 + 6 + 12 = 20 possible courses to select from if the golfer decides to play a round at a silver or gold course.

(B) If the golfer decides to play one round per week for 3 weeks, there are 12 possible combinations of courses to play. To see why, consider the following cases:
Week 1: bronze, Week 2: silver, Week 3: gold
Week 1: bronze, Week 2: gold, Week 3: Silver
Week 1: silver, Week 2: bronze, Week 3: gold
Week 1: silver, Week 2: gold, Week 3: bronze
Week 1: gold, Week 2: bronze, Week 3: Silver
Week 1: gold, Week 2: silver, Week 3: bronze

Each case has 2 possible choices for the bronze course, 6 possible choices for the silver course, and 2 possible choices for the gold course, for a total of 2 x 6 x 2 = 24 possible combinations. However, since the order of the courses doesn't matter, we must divide by 3! (or 6) to get rid of the extra permutations. Therefore, there are 24/6 = 4 possible combinations for each case, giving a total of 6 x 4 = 24 possible combinations of courses to play.

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650 adult tickets and 350 child tickets were sold for the local high school musical.

To determine how many adult and child tickets were sold for the local high school musical, you can use a system of linear equations. Let's use the terms "x" for adult tickets and "y" for child tickets.

1. The total number of tickets sold is 1000, so we have:
x + y = 1000

2. The total amount collected from ticket sales is $7100, so we have:
8.50x + 4.50y = 7100

Now, let's solve this system of equations step-by-step:

Step 1: Solve the first equation for x:
x = 1000 - y

Step 2: Substitute the expression for x from Step 1 into the second equation:
8.50(1000 - y) + 4.50y = 7100

Step 3: Simplify the equation:
8500 - 8.50y + 4.50y = 7100

Step 4: Combine like terms:
-4.00y = -1400

Step 5: Divide both sides by -4.00:
y = 350

Step 6: Substitute the value of y back into the expression for x from Step 1:
x = 1000 - 350

Step 7: Calculate the value of x:
x = 650

So, 650 adult tickets and 350 child tickets were sold for the local high school musical.

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For the Portfolio for Unit 5 Part 1, the Car Wheel Project, you'll want to include several key components.

First, be sure to include a detailed description of the project itself, including any goals or objectives you had in mind when you started. This could include things like improving your engineering or design skills, learning more about the materials used in car wheels, or simply creating a visually impressive final product.

Next, include some documentation of your process as you worked on the project. This might include sketches, diagrams, or photos of different stages of the process. Be sure to highlight any challenges or roadblocks you encountered along the way, and how you overcame them.

Finally, be sure to include a final showcase of your completed car wheel project. This might include photos of the finished product from different angles, a video demonstrating how it works or how it was made, or even a physical prototype that you can bring in to show off.

Overall, the key to a successful portfolio for the Car Wheel Project is to demonstrate your creativity, your technical skills, and your ability to work through challenges and solve problems.

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Unit 5 Portfolio Car Wheel Project Answer the following questions: 1. How do you find the area of a circle?

2. How do you find the circumference of a circle?

3. What information do you need in order to find the area or circumference of a circle

4. To determine the number of full rotations your tires complete before you need to switch thefront and back tires, will you be working with area or circumference?

Answer:

How do you find an area of a crilce?

-Use the formula A=[tex]\pi r^2[/tex]

How do you find the cirumference of a cirlce?

-Use the formula c=2[tex]\pi r[/tex]

What information do you need in order to find the area or circumference of a cirlce?

-I believe it's the diameter.

To determine the number of full rotations your tires complete before you switch the front and back tires will you be working with area or circumference?

-Circumference. Because ifts the distance around something, like a circle, or a wheel.

(My three examples of the circumference of tires)

Bike:

C=2(3.14)r

C=2 (3.14) 8

C=50.24

Car:

C=2(3.14)r

C=2 (3.14) 20

C=125.6

Scooter:

C=2(3.14)r

C=2 (3.14) 3

C=18.24

(My tire rotations how far you'll go in 10,000 miles)

car-

20x3.1416=62.83

10,000/62.83= 159.2

scooter-

3x3.1416=9.4248

10,000/9.4248=1,061

bike-

8x3.1416=25.13

10,000/25.13=397.9

Using one of your vehicles how far can you get in a week?

-We're driving the car with twenty inch wheels and we're going seventy miles an hour. So in a week we would have driven 490 miles.

When will you need to change your tires?

-When we reach 225 miles we'd change the tires. Because these tires are heavier than the average tire they're wear out faster.

I hope this helps!!! Let me know if you need some help with anything else.

Answer:

C)4.192

Step-by-step explanation:

What is 524/125 written as a decimal?

We Take

524 divided by 125 = 4.192

So, the answer is C)4.192

The minimum value of the average cost over the interval (1, 10).To find the minimum value of the average cost, we first need to find the average cost function.

AC(x) = C(x) / x
Substituting the given cost function, we get:
AC(x) = (x^3 + 36x + 432) / x
Simplifying this expression, we get:
AC(x) = x^2 + 36 + 432/x
Now, we need to find the minimum value of this function on the given intervals. To do this, we take the derivative of the function and set it equal to zero:
AC'(x) = [tex]2x - 432/x^2[/tex] = 0
Solving for x, we get:
x = [tex](216)^{(1/3)[/tex] ≈ 6.89
This critical point lies within the interval (1, 10), so we need to check the endpoints as well as this critical point to determine the minimum value of the average cost.

Calculating the values of the average cost at these three points, we get:
AC(1) = 469
AC(6.89) ≈ 51.9
AC(10) = 78.4
Therefore, the minimum value of the average cost over the interval (1, 10) is approximately $51.9. Note that this value is rounded to the nearest tenth as requested.

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The z-score is -1.2, rounded to the tenths place.

The center of the histogram would be around the population mean of 266 days.

The standard deviation of the histogram would be the standard error of the mean, which is the standard deviation of the population divided by the square root of the sample size. Thus, the standard deviation of the histogram would be 10 / sqrt(100) = 1 day.

To calculate the z-score for a sample mean of 264.8 days, we can use the formula:

z = (sample mean - population mean) / (standard deviation / sqrt(sample size))

Substituting the given values, we get:

z = (264.8 - 266) / (10 / sqrt(100)) = -1.2

Therefore, the z-score is -1.2, rounded to the tenths place.

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Applying the inscribed angle theorem, the measure of the size of angle ∅ = 85 degrees.

If an inscribed angle in a circle is subtended by an arc, the inscribed angle theorem states that the measure of the intercepted arc would be twice the measure of the inscribed angle.

Therefore, we have:

measure of arc DF = 2(31) = 62 degrees [inscribed angle theorem]

measure of arc BD = 2(54) = 108 degrees.[inscribed angle theorem]

∅ = 1/2(measure of arc BDF) [inscribed angle theorem]

∅ = 1/2(m(DF) + m(BD))

Substitute:

∅ = 1/2(62 + 108)

∅ = 1/2(170)

∅ = 85 degrees.

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The coordinate of a point between A and B, such that the distance from A to point B is 3/11 of distance A to B, is 1.

Let's denote the unknown point between A and B as P, and let the distance from A to P be x. Then the distance from P to B is (11/3)x. Since the distance from A to B is 19 - (-3) = 22, we have the equation x + (11/3)x = 22(3/11), which simplifies to (14/3)x = 6, or x = 9/7. Therefore, the coordinate of point P is -3 + (9/7)(19 - (-3)) = 1.

To check our answer, we can verify that the distance from A to P is (10/7)(22) and the distance from P to B is (1/7)(22)(11), and that (10/7)(22) = (3/11)(22), which is indeed true.

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Answer: 27 inches sq.

Step-by-step explanation:

3*3=9

2*9=18

18+9=27

The true statements are:

The initial cost for manufacturing records is $454, regardless of the number of records ordered.

In addition to the initial cost, each record costs $0.90 to manufacture.

Each record costs a total of $454.90 to manufacture.

As according to the question the function f(x)= 454+0.9x gives the cost, in dollars, of manufacturing x vinyl records.

Hence the incorrect statements are:

"The initial cost for manufacturing records depend on the quantity ordered".

"in addition to the initial cost, each record costs $454 to manufacture".

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The correct sequence for the samples in order of least variation to greatest variation is:

Sample A: A sample of 10 people

Sample D: A sample of 20 people

Sample B: A sample of 50 people

Sample C: A sample of 100 people

The reason for this sequence is that larger sample sizes tend to provide more accurate estimates of the population parameters, while smaller sample sizes are more prone to random fluctuations and sampling error.

Therefore, sample A (with the smallest sample size of 10) is likely to have the greatest variation from the expected value, while sample C (with the largest sample size of 100) is likely to have the least variation from the expected value.

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The sum is equal to 18600.

Let's first simplify the expression inside the brackets:

(i^2 - 21 + 1) - 4 = i^2 - 24

Now we can write the sum using sigma notation:

15 Σ (i^2 - 24), i=1

Using the summation formulas of the first n squares, we have:

Σ i^2 = n(n+1)(2n+1)/6

So, substituting n = 1 to 15, we get:

15 Σ i^2 = 15 Σ n(n+1)(2n+1)/6

Now, let's use the formula for the sum of the first n integers:

Σ i = n(n+1)/2

Substituting n = 1 to 15, we get:

Σ i = 1 + 2 + ... + 15 = 15(15+1)/2 = 120

Substituting these formulas into our original expression, we have:

15 Σ (i^2 - 24), i=1

= 15 [Σ i^2 - 24Σ i], i=1

= 15 [15(15+1)(2(15)+1)/6 - 24(120)]

= 15 [1240]

= 18600

Therefore, the sum of 15 (i^2 - 24) from i = 1 to 15 is equal to 18600.

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If Peter changed more pounds into dollars than he changed into francs then Peter changed £6,168 more into dollars than into francs.

First, we need to find out how much money Peter changed into euros:

(3/10) × £20,160 = £6,048

Next, we need to find out how much money Peter changed into dollars, rupees, and francs combined:

£20,160 − £6,048 = £14,112

We can use the ratios to find out how much of this total amount goes to each currency:

- Dollars: (9/16) × £14,112 = £7,932

- Rupees: (5/16) × £14,112 = £4,420

- Francs: (2/16) × £14,112 = £1,764

We can see that Peter changed more pounds into dollars than into francs. To find out how many more, we can subtract the amount changed into francs from the amount changed into dollars:

£7,932 − £1,764 = £6,168

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The Bubba Corp would owe $109,180 in taxes based on its earnings before taxes of $206,000 and sales of $2,060,000.

To determine the taxes owed by the Bubba Corp, we first need to calculate its taxable income. Taxable income is equal to earnings before taxes minus deductions and exemptions. Assuming no deductions or exemptions, the taxable income for the Bubba Corp would be:

Taxable income = Earnings before taxes = $206,000

Next, we need to calculate the amount of taxes owed. The Bubba Corp is in the 53% tax bracket, which means that it owes 53 cents on every dollar of taxable income. Therefore, the amount of taxes owed would be:

Taxes owed = Taxable income x Tax rate

= $206,000 x 0.53

= $109,180

In summary, the Bubba Corp would owe $109,180 in taxes based on its earnings before taxes of $206,000 and sales of $2,060,000, assuming no deductions or exemptions.

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