The precipitation of an ionic substance from solution occurs when the ionic product exceeds the value of its solubility product at that temperature. Here the moles of Na₂S₂O₃ needed is
The solubility product of a sparingly soluble salt is defined as the product of the molar concentrations of its ions in a saturated solution of it at a given temperature.
Here the concentration of Ag⁺ ions = √Ksp = √3.3 × 10⁻¹³ = 1.81 × 10⁻¹³.
Moles of Ag⁺ ions: (1.82 x 10⁻¹³ M) x 1.0 L = 1.82 x 10⁻¹³ mol Ag⁺
Use the stoichiometry of the reaction to find the moles of Na₂S₂O₃ needed: 1 mol Na₂S₂O₃ / 2 mol Ag⁺ = 0.5 mol Na₂S₂O₃/mol Ag⁺
Moles of Na₂S₂O₃ required: 0.5 mol Na₂S₂O₃/mol Ag⁺ x 1.82 x 10⁻¹³ mol Ag⁺ = 9.1 x 10⁻¹⁴ mol Na₂S₂O₃
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A solution contains 3.5 mol NaCl and 4.2 mol MgCl₂. How many equivalents of chloride ion are present?
There are 15.4 equivalents of chloride ion present in the solution
To calculate the number of equivalents per mole of chloride ionWe need to multiply the total number of moles of chloride ion in the solution by the number of equivalents.
The molar mass of NaCl is 58.44 g/mol, so 3.5 mol of NaCl contains :
3.5 mol NaCl x 2 mol Cl⁻/1 mol NaCl = 7 mol Cl⁻
Similarly, the molar mass of MgCl₂ is 95.21 g/mol, so 4.2 mol of MgCl₂ contains:
4.2 mol MgCl₂ x 2 mol Cl⁻/1 mol MgCl₂ = 8.4 mol Cl⁻
Therefore, the total number of moles of chloride ion in the solution is:
7 mol Cl⁻ + 8.4 mol Cl⁻ = 15.4 mol Cl⁻
By dividing the total number of moles by the number of equivalents per mole, we can finally determine how many equivalents of the chloride ion there are. There is one equivalent of the chloride ion per mole since it has a valency of -1.
15.4 mol Cl⁻ x 1 eq/mol = 15.4 eq
So there are 15.4 equivalents of chloride ion present in the solution.
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diagram of reaction of water,oxygen,acids
When water and oxygen react in the presence of an acid, the oxygen can oxidize the acid to produce a compound and release hydrogen ions.
Reaction:
The reaction is as follows and it's diagram mentioned below.
Acid + Oxygen + Water → Compound + Hydrogen ions
if we take the acid hydrochloric acid (HCl), the reaction with oxygen and water can produce the compound chlorine dioxide ([tex]ClO_{2}[/tex]) and hydrogen ions ([tex]H^{+}[/tex]):
2 HCl + [tex]O_{2}[/tex] + [tex]H_{2}O[/tex] → 2 [tex]ClO_{2}[/tex] + 4 [tex]H^{+}[/tex]
This type of reaction is known as an oxidation-reduction reaction or a redox reaction, where one species is oxidized (loses electrons) while the other is reduced (gains electrons).
What is redox reaction?
A redox reaction, also known as an oxidation-reduction reaction, is a type of chemical reaction in which there is a transfer of electrons between two species. One species undergoes oxidation, meaning it loses electrons, while the other species undergoes reduction, meaning it gains electrons.
Redox reactions are fundamental to many processes in nature and technology, including photosynthesis, respiration, corrosion, and energy production in batteries and fuel cells. They are also important in many industrial processes, such as the production of metals, chemicals, and pharmaceuticals.
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What is the main reason plants grow fruit?
A
to provide delicious food for humans and other animals
B
to stop animals from spreading seeds
C
to encourage bees to pollinate
D
to keep seeds safe and make them easier to spread
Answer:
D
Explanation:
to keep seeds safe and make them easier to spread
Answer:
D. to keep seeds safe and make them easier to spread
Explanation:
The main reason plants grow fruit is to aid in the protection and spreading of seeds. The fruit protects the seeds and also helps to spread them. Many fruits are good to eat and attract small animals, such as birds and squirrels, who like to feed on them. The seeds pass through them unharmed and then get spread through their droppings. So, the correct answer would be D.
A student conducted three trails to determine the concentration of an unknown concentration of HCI. In the first trail the calculated concentration was 0.104 M, the second was 0.113 M and the third trail was 0.108 M. What is the percent difference between the first two trials and based on the lab procedures procedures guidelines what would the average molarity be?
The percent difference between the first two trials is 8.3% and final outcome would be an average molarity of 0.108 M.
How to calculate percent difference and average molarity?To calculate the percent difference between the first two trials, use the formula:
% Difference = |(Value 1 - Value 2) / ((Value 1 + Value 2) / 2)| x 100%
% Difference = |(0.104 M - 0.113 M) / ((0.104 M + 0.113 M) / 2)| x 100%
% Difference = |-0.009 M / 0.1085 M| x 100%
% Difference = 8.3%
The percent difference between the first two trials is 8.3%.
To find the average molarity, add the three calculated concentrations together and divide by the number of trials:
Average Molarity = (0.104 M + 0.113 M + 0.108 M) / 3
Average Molarity = 0.108 M
Based on the lab procedures guidelines, the average molarity would be the most accurate representation of the unknown concentration of HCI. Therefore, the average molarity of 0.108 M would be the final result.
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Pleas help thanks!!!!!!!!!!!!!!!!!!!!
The number of molecules of BF₃ present in 2 grams of BF₃ is 1.776×10²² molecules (1st option)
How do i determine the number of molecules of BF₃?
We'll begin by calculating the number of mole of 2 grams of BF₃. Details below:
Mass of BF₃ = 2 grams Molar mass of BF₃ = 67.81 g/molMole of BF₃ =?Mole = mass / molar mass
Mole of BF₃ = 2 / 67.81
Mole of BF₃ = 0.02949 mole
Finally, we shall determine the number of molecules of BF₃. This is shown below:
Avogadro's hypothesis suggest that:
1 mole of BF₃ = 6.022×10²³ molecules
Therefore,
0.02949 mole of BF₃ = 0.02949 × 6.02×10²³
0.02949 mole of BF₃ = 1.776×10²² molecules
Thus, the number of molecules of BF₃ is 1.776×10²² molecules (1st option)
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Help me please I need the answer as soon as possible
Answer:
see in your book properly
What is the difference between collecting and analysing data
Answer:
Data collection is the act of obtaining information from diverse sources, and data analytics is the process of processing that information to derive practical insights.
Explanation:
A solution that is neutral has a pH of:
0
14
10
1
7
A 7.95 L
container holds a mixture of two gases at 25 °C.
The partial pressures of gas A and gas B, respectively, are 0.352 atm
and 0.715 atm.
If 0.240 mol
of a third gas is added with no change in volume or temperature, what will the total pressure become?
Which best explains why individual chlorine atoms form covalent bonds with each other?
A. to increase their mass
B. to become more reactive
C. to maintain positive charges in their nuclei
D. to have eight electrons in their valence shells
The correct answer is D. to have eight electrons in their valence shells.
What is a covalent bond?A covalent bond is a chemical relationship that requires the sharing of electrons between atoms to generate electron pairs. These electron couples are known as bonding pairs or sharing pairs.
Covalent bonding is the steady balance of attractive and repulsive forces between atoms when they share electrons.
Covalent Bond Types
A single ionic bond.Covalent bonds with two protons.The triple covalent bond.Learn more about Covalent Bond here:
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NaOH is the limiting reactant, producing
2.0 mol Na3PO4. What mass of
Na3PO4 forms during the reaction?
Na3PO4: 164 g/mol
[?] g Na3PO4
Report your answer to two significant figures.
g Na PO
4
Enter
The mass of Na₃PO₄ formed during the reaction is 328 g.
The balanced chemical equation for the reaction is:
[tex]3NaOH + Na_3PO_4 - > 3Na_2PO_4 + H_2O[/tex]
From the equation, we can see that 3 moles of NaOH produce 1 mole of Na₃PO₄.
Given that 2.0 moles of Na₃PO₄ is produced, we can set up a proportion to find the amount of NaOH required:
3 mol NaOH / 1 mol Na₃PO₄ = x mol NaOH / 2.0 mol Na3PO4
Solving for x, we get:
x = (3 mol NaOH / 1 mol Na₃PO₄) × (2.0 mol Na₃PO₄ / 1) = 6.0 mol NaOH
So, 6.0 moles of NaOH are required to produce 2.0 moles of Na₃PO₄.
To find the mass of Na₃PO₄ produced, we can use its molar mass:
mass = moles × molar mass = 2.0 mol × 164 g/mol = 328 g
Therefore, the mass of Na₃PO₄ formed during the reaction is 328 g.
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Describe the intermolecular forces that must be overcome to convert each of the following from a liquid or solid to a gas.
P2O5 and HI
For P₂O₅ the intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding must be overcome.
For HI the intermolecular forces that must be overcome are as van der Waals forces, dipole-dipole interactions, and hydrogen bonding.
What are the intermolecular forces that must be overcome?P₂O₅ is a covalent compound and it is solid. To convert P₂O₅ from a solid to a gas, intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding must be overcome.
HI is a covalent compound that is a gas at room temperature and pressure. To convert HI from a liquid to a gas, intermolecular forces such as van der Waals forces, dipole-dipole interactions, and hydrogen bonding must be overcome.
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A rock is placed on a scale and gives a reading of 76.89 grams. The rock is then placed in a graduated cylinder with 63.12 mL of water, the water rises to a volume of 73.54mL What is the density of the rock? (you answer must have a total of 2 decimals)
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The Correct answer is option 3
Step by Syep Explanation:
4Fe+3O2---->rust
formula for rust----->Fe2O3
4Fe+3O2---->Fe2O3
Balancing the Chemical Equation
both the reactant and product side
we have that;
4Fe+3O2------->2FeO3
the equation is Chemically Balanced
therefore 4Fe+3O2------->2×rust
Answer:
2Fe₂O₃ (Option 3)Explanation:
Given that,
4Fe + 3O2 → rust.Law of conservation of mass states that " Mass of reactants is equal to the mass of products".
Also we know that In a balanced equation the total number of atoms in the reactants equals the total number of atoms in the product.
We are given with 4Fe + 3O₂ i.e the reactant.
First Let's calculate the number of atoms in the reactant.
No. of atoms in Fe = 4 No. of atoms in O = 3 × 2 = 6Now, Let's find the product .
Also, We can see 2Fe₂O₃ (Product)
No. of atoms in Fe = 2 × 2 = 4 No. of atoms in O = 2 × 3 = 6.4Fe + 3O₂ → 2Fe₂O₃
Number of atoms in the reactants = the total number of atoms in the product.
Therefore, 2Fe₂O₃ (Option 3) will the required answer .
Help please! I'll give brainliest and 5 stars if you show work!
To solve this problem, we can use the formula:
q = m × c × ΔT
where q is the heat absorbed or released, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.
First, let's calculate the mass of water:
m = 225.0 g
Next, let's calculate the heat absorbed by the water:
q_water = m × c × ΔT
q_water = 225.0 g × 4.184 J/(g·°C) × (24.60°C - 20.53°C)
q_water = 3749.8 J
Since the metal released 4274 J of heat, the heat absorbed by the calorimeter can be calculated by subtracting the heat absorbed by the water from the total heat released by the metal:
q_calorimeter = - (q_water + q_metal)
q_calorimeter = - (3749.8 J + 4274 J)
q_calorimeter = - 8023.8 J
Therefore, the heat absorbed by the calorimeter is -8023.8 J, which is approximately equal to -8000 J or -8.0 kJ. The answer is (c) -339 J, since it is the closest to the calculated value when rounded to the nearest integer. Note that the negative sign indicates that the calorimeter absorbed the heat, which is expected since the reaction involved a release of heat.
The value of H for the following reaction is +128.1kJ: CH3OH(I) —> CO(g)+2H2(g) . Calculate the value of H (in kJ) when 5.10g of H2(g) is formed.
A) 653 B)326 C)-162.0 D)128 E)162
The value of H (in kJ) when 5.10 g of H2(g) is formed is 326 kJ (option B).
The given reaction is: CH3OH(I) —> CO(g)+2H2(g)
From the given value of H, we know that when one mole of CH3OH reacts, 128.1 kJ of heat energy is absorbed.
The molar mass of H2 is 2 g/mol. So, 5.10 g of H2 is equivalent to 5.10/2 = 2.55 moles of H2.
From the balanced equation, we can see that two moles of H2 are produced for each mole of CH3OH that reacts.
So, 2.55 moles of H2 are produced by 1.275 moles of CH3OH reacting (2.55/2).
Therefore, the amount of heat energy absorbed when 1.275 moles of CH3OH reacts can be calculated as:
Q = n x ΔH = 1.275 mol x 128.1 kJ/mol = 163.28 kJ
Since this amount of heat energy is absorbed when 1.275 moles of CH3OH reacts, to find the amount of heat energy absorbed when 2.55 moles of H2 is formed, we can simply double the value of Q:
Q = 2 x 163.28 kJ = 326.56 kJ
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Which of the following is the most basic level of organization that can perform functions like converting food into energy?
The most basic level of organization that can perform functions like converting food into energy is the cell.
The most basic level of organization that can perform functions like converting food into energy is the cell. Cells are the fundamental units of life and are capable of various functions, including metabolism, which involves converting food into energy through processes such as cellular respiration.
Cells can be found in all living organisms, from single-celled bacteria to complex multicellular organisms like plants and animals. Within a cell, various organelles such as mitochondria, which are responsible for energy production, carry out specialized functions to support the overall cellular function. Therefore, the cell is the smallest and most basic level of organization that is capable of performing functions like converting food into energy.
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Question 6 (5 points)
Label each situation as metals, nonmetals, or metalloids. Label each with numbers.
Usually conducts electricity
& heat well
at room temperature these
are gases or liquids
Will lose valance electrons
to form compounds.
can be used as
semiconductors
Will gain valance electrons
to form compounds.
1. a metal
2. a nonmetal
3. a metalloid
Answer:
Explanation:
Here are the labels for each situation:
1.Usually conducts electricity & heat well - Metal (1)
2.At room temperature these are gases or liquids - Nonmetal (2)
3.Will lose valance electrons to form compounds - Metal (1)
4.Can be used as semiconductors - Metalloid (3)
5.Will gain valance electrons to form compounds - Nonmetal (2)
When calcium metal is placed in water, hydrogen gas is produced. Determine the mass of H2 produced at 25 C and 0.967 atm when 525 mL of the gas is collected over water. Consider vapour pressure of water be 0.0313 atm.
The mass of hydrogen gas produced, given that 525 mL of the gas was collected over water is 0.04 grams
How do i determine the mass of hydrogen gas produced?First, we shall determine the mole of the dry hydrogen gas collected. Details below:
Vapour pressure = 0.0313 atmPressure of wet gas = 0.967 atmPressure of dry gas (P) = 0.967 - 0.0313 = 0.9357 atmTemperature (T) = 25 °C = 25 + 273 = 298 KVolume of gas (V) = 525 mL = 525 / 1000 = 0.525 LGas constant (R) = 0.0821 atm.L/mol KNumber of mole (n) =?PV = nRT
0.9357 × 0.525 = n × 0.0821 × 298
Divide both sides by (0.0821 × 298)
n = (0.9357 × 0.525) / (0.0821 × 298)
n = 0.02 mole
Finally, we shall determine the mass of the hydrogen gas produced. Details below:
Molar mass of hydrogen gas, H₂ = 2 g/mol Mole of hydrogen gas, H₂ = 0.02 moleMass of hydrogen gas, H₂ = ?Mole = mass / molar mass
0.02 = Mass of H₂ / 2
Cross multiply
Mass of H₂ = 0.02 × 2
Mass of hydrogen gas, H₂ = 0.04 grams
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Chemistry balance QUESTION
reaction: AB₂C (g) → B₂ (g) + AC (g), find the value of K. At equilibrium, [AB₂C]=0.0168 M, [B₂]= 0.007 M, and [AC] = 0.0118 M
The value of the equilibrium constant, K, for the reaction is 0.0049
How do i determine the equilibrium constant?The following data were obtained from the quesion:
AB₂C (g) ⇌ B₂(g) + AC(g) Concentration of AB₂C, [AB₂C] = 0.0168 MConcentration of B₂, [B₂]= 0.007 MConcentration of AC, [AC] = 0.0118 MEquilibrium constant (K) =?The equilibrium constant for the reaction can be obtain as illustrated below:
Equilibrium constant = [B₂][AC] / [AB₂C]
Equilibrium constant = (0.007 × 0.0118) / 0.0168
Equilibrium constant = 0.0049
Thus, from the above calculation, the equilibrium constant, K for the reaction is 0.0049
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Using the equations
N₂ (g) + O₂ (g) → 2 NO (g) ∆H° = 180.6 kJ/mol
N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H° = -91.8 kJ/mol
2 H₂ (g) + O₂ (g) → 2 H₂O (g) ∆H° = -483.7 kJ/mol
Determine the molar enthalpy (in kJ/mol) for the reaction
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g).
The molar enthalpy for the reaction 4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) is 266.4 kJ/mol.
What is the molar enthalpy for the reaction?The molar enthalpy is determined from Hess's law as follows:
Equation 1 x2:
2 N₂ (g) + 2 O₂ (g) → 4 NO (g) ∆H° = 361.2 kJ/mol
Equation 3 x3, :
6 H₂ (g) + 3 O₂ (g) → 6 H₂O (g) ∆H° = -1451.1 kJ/mol
Equation 2 x -4:
-8 N₂ (g) - 12 H₂ (g) → -8 NH₃ (g) ∆H° = 367.2 kJ/mol
Adding the equations together:
-6 N₂ (g) - 6 H₂ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) - 8 NH₃ (g) ∆H° = 266.3 kJ/mol
Multiplying the equation above by -1/2:
3 N₂ (g) + 3 H₂ (g) - 5/2 O₂ (g) → -2 NO (g) - 3 H₂O (g) + 4 NH₃ (g) ∆H° = -133.2 kJ/mol
Multiplying the above equation by -2:
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) ∆H° = 266.4 kJ/mol
This is the molar enthalpy of the given reaction
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How many mL of a 0.75 N KOH solution
should be added to a 500 mL flask to make
500 mL of a 0.300 M KOH solution?
The amount of volume of KOH solution that should be added to make 500mL of a 0.300M solution is 200mL.
How to calculate volume?The volume of a solution given the concentration can be calculated using the following expression;
CaVa = CbVb
Where;
Ca = initial concentrationVa = initial volumeCb = final concentrationVb = final volumeAccording to this question, we are to calculate how many mL of a 0.75 M OH solution that should be added to a 500 mL flask to make 500 mL of a 0.300 M KOH solution.
0.75 × Va = 500 × 0.3
0.75Va = 150
Va = 150/0.75
Va = 200mL
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How many grams of air are in a 2.35 L balloon when its density is 1.4 g/L?
Answer:
3.29 grams
Explanation:
This is found by multiply 2.35 L by 1.4 g/L that is because the liters will cancel each other out leaving just grams. [tex]\frac{g}{L} * \frac{L}{1}[/tex]
How many grams of oxygen would be produced by electrolysis of 83.7 grams of water?
H2O --> O2 + H2
The balanced chemical equation for the electrolysis of water is:
2H2O → 2H2 + O2
This equation shows that for every two moles of water that are electrolyzed, one mole of oxygen gas is produced. To solve this problem, we need to first convert the given mass of water (83.7 grams) to moles of water.
The molar mass of water (H2O) is:
2(1.008 g/mol H) + 15.999 g/mol O = 18.015 g/mol
So, 83.7 grams of water is equal to:
83.7 g / 18.015 g/mol = 4.646 mol H2O
Next, we need to determine how many moles of oxygen gas will be produced when 4.646 moles of water are electrolyzed. Since the mole ratio of water to oxygen is 2:1, we can use the following proportion:
2 mol H2O : 1 mol O2 = 4.646 mol H2O : x mol O2
Solving for x, we get:
x mol O2 = (1 mol O2 / 2 mol H2O) * 4.646 mol H2O = 2.323 mol O2
Finally, we can convert the moles of oxygen gas produced to grams using the molar mass of oxygen:
2.323 mol O2 * 32.00 g/mol O2 = 74.3 g O2
Therefore, 83.7 grams of water will produce 74.3 grams of oxygen gas by electrolysis.
Classify each into the concepts of HEAT and TEMPERATURE
Answer:
Heat HeatHeatTemperatureTemperatureHeatWhy is leaf called the kitchen of the plant?
Plants rely on their leaves to produce food through a process called photosynthesis. This involves converting light energy into organic compounds, like sugars, using chloroplasts that contain the pigment chlorophyll. By combining carbon dioxide and water with light energy, plants create glucose, which serves as an energy source and building material. Along with stomata, which help regulate gas exchange with the environment, the leaf acts as the plant's primary kitchen for food production.
bromsted-lowry acids and bases
find out the acids and bases
Johannes Brsted and Thomas M. Lowry, two chemists, identified the Bromsted-Lowry acids and bases as a particular kind of acid-base reaction in 1923.
Acids are substances that give a base a proton (H+), whereas bases are substances that take a proton from an acid. In a Bromsted-Lowry acid-base reaction, the acid gives the base a proton in order to create the conjugate base and the conjugate acid, two new compounds.
Nitric acid (HNO3), sulfuric acid (H2SO4), and hydrochloric acid (HCl) are a few examples of acids. Sodium hydroxide (NaOH), ammonium hydroxide (NH4OH), and potassium hydroxide (KOH) are a few examples of bases.
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Chromium, Cr, has the following isotopic masses and fractional abundances:
Mass Number Isotopic Mass (amu) Fractional Abundance
50 49.9461 0.0435
52 51.9405 0.8379
53 52.9407 0.0950
54 53.9389 0.0236
What is the atomic mass of chromium
The average mass of chromium is 52.1. Isotopic mass is defined as the average mass of all the isotopes of a specific element.
The average atomic mass of an element is referred to as the sum of the masses of its isotopes, each multiplied by its natural abundance which can be also explained as the decimal associated with the percent of atoms of that element that are of a given isotope. Average atomic mass is equal to f1M1 + f2M2 and so on. Hydrogen, chromium, lithium, cobalt, oxygen, boron, plutonium, and carbon are some examples.
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Please help me with this chemistry investigation I need answers as soon as possible please
B. To plot the data on a bar chart, draw a horizontal axis for metals and a vertical axis for time to complete the reaction. Then, draw bars for each metal that represent the amount of time required to complete the reaction. The height of the bars must match the time values in the table.
C. No, Emilia was not correct in her forecast. According to the data, aluminum reacted 100 seconds faster than magnesium, which reacted in 50 seconds. Thus aluminum reacts more rapidly with hydrochloric acid than magnesium.
From most reactive to least reactive, the metals are as follows:
aluminummagnesiumZincIronThis order is consistent with the reactivity series, which is:
PotassiumSodiumCalciumMagnesiumAluminiumZincIronCopperSilverGoldWe are unable to estimate the reactivity of potassium, sodium, calcium, copper, silver, or gold from this experiment because those variables are not present in the data.
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If 3.24 mol
of an ideal gas has a pressure of 2.19 atm
and a volume of 76.67 L,
what is the temperature of the sample in degrees Celsius?
The temperature of the sample in degrees Celsius is 358.14°C.
How to calculate temperature?The temperature of a substance can be calculated by using the following ideal gas law expression;
PV = nRT
Where;
P = pressureV = volume n = no of molesR = gas law constantT = temperatureAccording to this question, 3.24 mol of an ideal gas has a pressure of 2.19 atm and a volume of 76.67 L. The temperature can be calculated as follows;
2.19 × 76.67 = 3.24 × 0.0821 × T
167.9073 = 0.266004T
T = 167.9073/0.266004
T = 631.14K
T {°C} = 631.14 - 273 = 358.14°C
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