Question 1(Multiple Choice Worth 2 points)
(Circle Graphs MC)

The circle graph describes the distribution of preferred transportation methods from a sample of 400 randomly selected San Francisco residents.

circle graph titled San Francisco Residents' Transportation with five sections labeled walk 40 percent, bicycle 8 percent, streetcar 15 percent, bus 10 percent, and cable car 27 percent

Which of the following conclusions can we draw from the circle graph?

Together, Streetcar and Cable Car are the preferred transportation for 168 residents.
Together, Walk and Streetcar are the preferred transportation for 55 residents.
Bus is the preferred transportation for 45 residents.
Bicycle is the preferred transportation for 50 residents.

Question 2(Multiple Choice Worth 2 points)
(Appropriate Measures MC)

The box plot represents the number of tickets sold for a school dance.

A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 10 and 27.

Which of the following is the appropriate measure of center for the data, and what is its value?

The mean is the best measure of center, and it equals 19.
The median is the best measure of center, and it equals 4.
The median is the best measure of center, and it equals 19.
The mean is the best measure of center, and it equals 4.

Question 3(Multiple Choice Worth 2 points)
(Comparing Data LC)

The histograms display the frequency of temperatures in two different locations in a 30-day period.

A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.

A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.

When comparing the data, which measure of center should be used to determine which location typically has the cooler temperature?

Median, because Desert Landing is symmetric
Mean, because Sunny Town is skewed
Mean, because Desert Landing is symmetric
Median, because Sunny Town is skewed

Question 4(Multiple Choice Worth 2 points)
(Appropriate Measures MC)

A charity needs to report its typical donations received. The following is a list of the donations from one week. A histogram is provided to display the data.

10, 11, 35, 39, 40, 42, 42, 45, 49, 49, 51, 51, 52, 53, 53, 54, 56, 59

A graph titled Donations to Charity in Dollars. The x-axis is labeled 10 to 19, 20 to 29, 30 to 39, 40 to 49, and 50 to 59. The y-axis is labeled Frequency. There is a shaded bar up to 2 above 10 to 19, up to 2 above 30 to 39, up to 6 above 40 to 49, and up to 8 above 50 to 59. There is no shaded bar above 20 to 29.

Which measure of variability should the charity use to accurately represent the data? Explain your answer.

The range of 13 is the most accurate to use, since the data is skewed.
The IQR of 49 is the most accurate to use to show that they need more money.
The range of 49 is the most accurate to use to show that they have plenty of money.
The IQR of 13 is the most accurate to use, since the data is skewed.

Question 5(Multiple Choice Worth 2 points)
(Making Predictions MC)

A recent conference had 900 people in attendance. In one exhibit room of 80 people, there were 65 teachers and 15 principals. What prediction can you make about the number of principals in attendance at the conference?

There were about 820 principals in attendance.
There were about 731 principals in attendance.
There were about 208 principals in attendance.
There were about 169 principals in attendance.

Question 6(Multiple Choice Worth 2 points)
(Creating Graphical Representations LC)

A teacher was interested in the subject that students preferred in a particular school. He gathered data from a random sample of 100 students in the school and wanted to create an appropriate graphical representation for the data.

Which graphical representation would be best for his data?

Stem-and-leaf plot
Histogram
Circle graph
Box plot

Answers

Answer 1

Answer:

Step-by-step explanation:

Car are the preferred transportation for 168 residents.Together, Walk and Streetcar are the preferred transportation for 55 residents.Bus is the preferred transportation for 45 residents.Bicycle is the preferred transportation for 50 residents.Question 2(Multiple Choice Worth 2 points)(Appropriate Measures MC)The box plot represents the number of tickets sold for a school dance.A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the numb


Related Questions

in a certain town, in 90 minutes 1/2 inch of rain falls. It continues at the same rate for a total of 24 hours. Which of the following statements are true about the amount of rain in the 24- hour period? show your work

Answers

The statement that is true is that the amount of rain in the 24- hour period is 8 inches

Which statement is true about the amount of rain in the 24- hour period?

From the question, we have the following parameters that can be used in our computation:

In 90 minutes 1/2 inch of rain falls

This means that

Rate = (1/2 inch)/90 minutes

So, we have

Rate = (1/2 inch)/(1.5 hour)

The amount of rain in the 24- hour period is

Amount = Rate * Time

So, we have

Amount = (1/2 inch)/(1.5 hour) * 24 hours

Evaluate

Amount = 8 inches

Hence, the amount of rain in the 24- hour period is 8 inches

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Dmitri practices his domra for 98 min during
the school week. this is 70% of the time he
must practice his instrument in one week.

Answers

The total or actual time he needs to practice is 140 min whereas he practiced for 98 min during the school week.

We need to find the total time he must practice for a week. To find the total time we assume that the total time is x min.

Given Data:

Dmitri practices time during the school week = 98 min

Dmitri practices amount of time = 70% of his total time

Total time = x

Then the equation is given as

70% × (x) = 98

0.70 × (x) = 98

x = 98 / 0.70

x = 140

Therefore, The total time of the practices is 140 min

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It is now time to complete the Independence and Exclusiveness assignment. Independence and Exclusiveness are two topics which are important to probability and often confused. Discuss the difference between two events being independent and two events being mutually exclusive. Use examples to demonstrate the difference. Remember to explain as if you are talking to someone who knows nothing about the topic. Please no gibberish if correct I will be so grateful

Answers

Two events are independent if the occurrence of one event does not affect the occurrence of the other event. In other words, the probability of one event happening is not affected by whether or not the other event happens.

A simple example would be flipping a coin and rolling a die. The outcome of the coin flip does not affect the outcome of the die roll, so these events are independent.

On the other hand, two events are mutually exclusive if they cannot happen at the same time. If one event happens, the other event cannot happen. For instance, when rolling a die, the events of getting a 1 or a 2 are mutually exclusive because it is impossible to roll both numbers at the same time.

To summarize, two events are independent if the probability of one event happening is not affected by the occurrence of the other event, while two events are mutually exclusive if they cannot happen at the same time.

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A queen-sized mattress is 20 inches longer than it is wide. A king-sized mattress is


16 inches wider than the queen-sized mattress but has the same length. The area


of the king-sized mattress is 1,280 square inches more than that of the queen-sized


mattress.


Write an equation that can be used to determine the area of the king-sized mattress.


Define all variables used

Answers

If A queen-sized mattress is 20 inches longer than it is wide. A king-sized mattress is 1280 square inches.

In mathematics, a variable is a symbol or letter that represents a value that can change or vary in a given context or problem. The area of the queen-sized mattress is x(x + 20) square inches. The equation to determine the area of the king-sized mattress is (x + 16)(x + 20) = x(x + 20) + 1280

Let x be the width of the queen-sized mattress in inches.

Then the length of the queen-sized mattress is x + 20 inches.

The width of the king-sized mattress is 16 inches wider than the queen-sized mattress, so it is x + 16 inches.

The length of the king-sized mattress is the same as the length of the queen-sized mattress, which is x + 20 inches.

We can use the formula for the area of a rectangle to find the area of each mattress:

Area of queen-sized mattress = length x width = (x + 20) x x = x^2 + 20x

Area of king-sized mattress = length x width = (x + 20) x (x + 16) = x^2 + 36x + 320

The problem tells us that the area of the king-sized mattress is 1,280 square inches more than that of the queen-sized mattress, so we can write the equation:

Area of king-sized mattress = Area of queen-sized mattress + 1,280

Substituting the expressions we found for the areas, we get:

x^2 + 36x + 320 = x^2 + 20x + 1280

Simplifying and solving for x, we get:

16x = 960

x = 60

So the width of the queen-sized mattress is 60 inches, and its length is 80 inches.

The width of the king-sized mattress is 76 inches, and its length is 80 inches.

The area of the queen-sized mattress is:

60^2 + 20(60) = 4,800 square inches

The area of the king-sized mattress is:

76^2 + 36(76) + 320 = 6,080 square inches

And we can verify that the area of the king-sized mattress is indeed 1,280 square inches more than that of the queen-sized mattress:

6,080 - 4,800 = 1,280

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Rewrite each equation without absolute value for the given conditions. y= |x+5| if x>-5

Answers

Answer:

When x is greater than -5, the expression inside the absolute value bars is positive, so we can simply remove the bars.

So the equation y = |x+5| can be rewritten as:

y = x+5 (when x > -5)

4 3 (1)/(5 )2 (3)/(5 )1 (4)/(5)

ecplict formula, in slope intercept form (4)/(5)

Answers

The explict formula, in slope intercept form is an = n/5

Calculating the explict formula, in slope intercept form

The given sequence is 1/5, 2/5, 3/5.

We can observe that this is an arithmetic sequence, where the first term is 1/5, the common difference is 1/5

To find the explicit formula for an arithmetic sequence, we can use the formula:

an = a1 + (n-1)d

Substituting the values we know for this sequence, we get:

an = 1/5 + (n - 1)*(1/5)

Evaluate

an = n/5

Thus, the nth term of this sequence can be found by substituting the value of n in the formula an = n/5

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Complete question

1/5 2/5 3/5

What is the explicit formula in slope intercept form

A 10​-ft ladder is leaning against a house when its base starts to slide away. By the time the base is 6 ft from the​ house, the base is moving away at the rate of 24 ​ft/sec.
a. What is the rate of change of the height of the top of the​ ladder?
b. At what rate is the area of the triangle formed by the​ ladder, wall, and ground changing​ then?
c. At what rate is the angle between the ladder and the ground changing​ then?

Answers

The rate of change of the height of the top of the ladder is -144/h ft/sec when the base of the ladder is 6 ft from the house.

The area of the triangle formed by the ladder, wall, and ground is decreasing at a rate of 163.2 ft^2/sec when the base of the ladder is 6 ft from the house.

The angle between the ladder and the ground is decreasing at a rate of 1/8 rad/sec when the base of the ladder is 6 ft from the house.

By using Pythagorean Theorem how we find the height, base and angle of the ladder?

The rate of change of the height of the top of the ladder, we need to use the Pythagorean Theorem:

[tex]h^2 + d^2 = L^2[/tex]

where h is the height of the top of the ladder, d is the distance of the base of the ladder from the house, and L is the length of the ladder.

Taking the derivative with respect to time, t, and using the chain rule, we get:

2h (dh/dt) + 2d (dd/dt) = 2L (dL/dt)

We are given that d = 6 ft, dd/dt = 24 ft/sec, and L = 10 ft. We need to find dh/dt when d = 6 ft.

Plugging in the values, we get:

2h (dh/dt) + 2(6)(24) = 2(10) (0) (since the ladder is not changing length)

Simplifying, we get:

2h (dh/dt) = -288

Dividing by 2h, we get:

dh/dt = -144/h

The area of the triangle formed by the ladder, wall, and ground is given by:

A = (1/2) bh

where b is the distance of the base of the ladder from the wall, and h is the height of the triangle.

Taking the derivative with respect to time, t, and using the product rule, we get:

dA/dt = (1/2) (db/dt)h + (1/2) b (dh/dt)

We are given that db/dt = -24 ft/sec, h = L, and dh/dt = -144/h. We need to find dA/dt when d = 6 ft.

Plugging in the values, we get:

dA/dt = (1/2) (-24) (10) + (1/2) (6) (-144/10)

Simplifying, we get:

dA/dt = -120 + (-43.2)dA/dt = -163.2 ft^2/sec

The rate of change of the angle between the ladder and the ground, we use the trigonometric identity:

Dividing by sec^2(theta), we get:

d(theta)/dt = (-24/h^3) - (2h^2/5)

We can plug in the value of h = (L^2 - d^2)^(1/2) = (100 - 36)^(1/2) = 8 ft when d = 6 ft to get:

d(theta)/dt = (-24/8^3) - (2(8)^2/5) = -1/8 rad/sec

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Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antiderivative.)
g(v) = 5 cos (v) - 8/√(1-v^2)
g(v) = ____

Answers

The most general antiderivative of the function g(v) = 5 cos(v) - 8/√(1-v^2) is 5 sin(v) + 8 arcsin(v) + C, where C is the constant of the antiderivative.

To find the antiderivative of the given function g(v), we can use the basic antiderivative rules. The antiderivative of 5 cos(v) is 5 sin(v), as the derivative of sin(v) is cos(v) and we only need to reverse the process.

Similarly, the antiderivative of -8/√(1-v^2) can be found using the inverse trigonometric function arcsin(v), as its derivative is -1/√(1-v^2). However, we need to include a constant of integration, denoted by C, as the antiderivative is not unique.

So the most general antiderivative of g(v) is 5 sin(v) + 8 arcsin(v) + C, where C represents the constant of the antiderivative. To check the correctness of the answer, we can differentiate it and verify if it gives us the original function g(v) as the result.

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A car left Town A for Town b. Another car left Town B for Town A at the same time. The ratio of the speeds of the two cars was 6:5 initially. After the two cars passed each other, Car A's speed was reduced by 1/6 and car B's speed was reduced by 25%. When car A arrived at Town B, Car B was still 54 km away from Town A. Find the distance between Town A and Town B. Please I need the answer quickly :]

Answers

The distance between Town A and Town B is 550 km.

Let's denote the distance between Town A and Town B as D.

When the two cars first passed each other, let's assume that car A traveled a distance of x km and car B traveled a distance of D - x km.

Let's also denote the initial speeds of car A and car B as 6s and 5s, respectively, where s is some constant representing the speed of the slower car.

The time it took for the two cars to pass each other can be calculated using the formula:

time = distance / speed

For car A, the time it took to travel x km was:

x / (6s)

For car B, the time it took to travel D - x km was:

(D - x) / (5s)

Since the two cars traveled the same amount of time until they passed each other, we can set these two expressions equal to each other:

x / (6s) = (D - x) / (5s)

Solving for x, we get:

x = 6Ds / (11s)

After the speeds of both cars were reduced, car A's speed was (5/6) * 6s = 5s, and car B's speed was (3/4) * 5s = (15/4)s.

Let's denote the time it took for car A to travel the remaining distance from x to D as t.

Then, the time it took for car B to travel a distance of (D - x - 54) km is also t.

Using the new speeds, we can write the equation:

[tex](D - x - 54) = (15/4)s * t[/tex]

Solving for t, we get:

[tex]t = (4/15)(D - x - 54) / s[/tex]

The distance car A traveled after the two cars passed each other is:

D - x = D - 6Ds / (11s) = (5/11)D

The time it took for car A to travel this distance is:

[tex]t + x / (6s) = (4/15)(D - x - 54) / s + 6Ds / (66s)[/tex]

Setting these two expressions equal to each other and solving for D, we get:

D = 550 km

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Susan is a college student with two part-time jobs. She earns $10 per hour tutoring


elementary students in math. She earns $15 per hour cleaning in the library. Her goal is


to earn at least $240 per week, but because of college, she does not work more than


20 hours each week.


Which combinations allow Susan to work no more than 20 hours in one week and earn


at least $2402


Select the three correct combinations.

Answers

The required inequalities are h + l ≤ 20, 10h + 15l ≥ 240 and 20h + 25l ≥ 440

Given, for tutoring elementary students in math Susan earns $10 per hour. She earns $15 per hour for cleaning in the library.

Let h be the number of hours Susan works in one week tutoring elementary students.

Let l be the number of hours Susan works in one week cleaning the library.

Given that each week Susan cannot work more than 20 hours.

So, h + l ≤ 20 ....(1)

Susan's total earnings must be at least $240 per week.

10h + 15l ≥ 240    ...(2)

Multiplying equation (1) by 10

10h + 10l ≤ 200    ...(3)

Adding equations (2) and (3)

20h + 25l ≥ 440

Thus, the three required inequalities are h + l ≤ 20, 10h + 15l ≥ 240 and 20h + 25l ≥ 440

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A man buys a plot of agricultural land for rs. 300000 he sells 1/3rd at a loss of 20% and 2/5ths at a gain of 25% at what price must he sell the remaining land so as to make an overall profit of 10%

Answers

Let's first calculate the amount of money the man receives from selling 1/3rd of the land and 2/5ths of the land.

1/3 of the land is (1/3) * 300000 = 100000, and he sells it at a loss of 20%, which means he sells it for 100000 - (20/100) * 100000 = 80000.

2/5 of the land is (2/5) * 300000 = 120000, and he sells it at a gain of 25%, which means he sells it for 120000 + (25/100) * 120000 = 150000.

The total money he receives from selling 1/3rd and 2/5ths of the land is 80000 + 150000 = 230000.

He bought the land for Rs. 300000 and received Rs. 230000 from selling a portion of it. So, he still has Rs. 70000 worth of land left.

To make a profit of 10%, he needs to sell the remaining land for 300000 + (10/100) * 300000 = Rs. 330000.

The remaining land is worth Rs. 70000, so he needs to sell it for Rs. 330000 - Rs. 230000 = Rs. 100000.

Therefore, he must sell the remaining land for Rs. 100000 to make an overall profit of 10%.

Astronaut Harry Skyes has a mass of approximately 85. 0 kg. What is his weight on Mercury?
Mercury's gravity = 3. 70 m/s^2​

Answers

The weight of Harry Skyes on Mercury is 32.8 kg, under the condition that Mercury's gravity = 3. 70 m/s².


The weight of astronaut Harry Skyes on Mercury can be evaluated using the formula:

Weight on Mercury = (Weight on Earth / 9.81 m/s²) × 3.7 m/s²

Given that Harry Skyes has a mass of approximately 85.0 kg, his weight on Mercury would be:

Weight on Mercury = (85.0 kg / 9.81 m/s²) × 3.7 m/s²

Weight on Mercury = 32.8 kg

Gravity affects weight severely and causes its change . Objects have mass, which is specified as how much matter an object contains. Weight is known as the pull of gravity on mass. The relation between weight and gravitational pull is such that, when on another celestial body, the difference in gravity would alter a person’s weight.

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The volume of this cone is 2,279.64 cubic millimeters. what is the height of this cone?

use ​ ≈ 3.14 and round your answer to the nearest hundredth.

Answers

The height of the cone is approximately 12.15 millimeters (rounded to the nearest hundredth).

To find the height of the cone, we need to use the formula for the volume of a cone:

V = (1/3)πr²h

where V is the volume, r is the radius, h is the height, and π is approximately equal to 3.14.

We are given the volume of the cone as 2,279.64 cubic millimeters. We can plug this value into the formula and solve for h:

2,279.64 = (1/3)πr²h

Multiplying both sides by 3 and dividing by πr², we get:

h = (3 × 2,279.64) / (π × r²)

Now, we need to find the radius of the cone. Unfortunately, we are not given this information directly. However, we can use the fact that the volume of a cone is also given by:

V = (1/3)πr²h

If we rearrange this formula to solve for r², we get:

r² = 3V / (πh)

Now, we can substitute the given values for V and h and simplify:

r² = 3(2,279.64) / (π × h) ≈ 2,304.32 / h

Taking the square root of both sides, we get:

r ≈ √(2,304.32 / h)

Now, we can substitute this expression for r into our earlier formula for h:

h = (3 × 2,279.64) / (π × r²) ≈ (6,838.92 / π) / (2,304.32 / h)

Simplifying, we get:

h ≈ 2,279.64 × h / (2,304.32 / h)

h² ≈ 2,279.64 × h / (2,304.32 / h)

h³ ≈ 2,279.64

Taking the cube root of both sides, we get:

h ≈ 12.15

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Explain the statement 3-5 sentences :



correspondence is a relation of connection



you may give examples to explain the ideas

Answers

Correspondence is a relation of connection as it establishes a link between two sets of elements, often by relating each element in one set to a specific element in the other set.

Correspondence refers to the exchange of communication or information between two or more parties. It is a relation of connection because it involves establishing a link or connection between the sender and the receiver of the message.

For example, when two people exchange letters or emails, they establish a correspondence that connects them and allows them to communicate. Similarly, in business, correspondence can refer to the exchange of official documents such as letters, memos, and reports, which establish a connection between different departments or organizations. Overall, correspondence is an important aspect of communication that helps to establish and maintain relationships between individuals and groups.

For example, in mathematics, a correspondence can be seen when matching the elements of one set to another, such as associating students with their grades. In this case, the connection is created by linking each student to their respective grade, illustrating the concept of correspondence.

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The diagonal of a table top is 40 inches and the width is 21 inches. What is the area of the table? Round to the nearest inch.

Answers

The area of the table is approximately 651 square inches.

What is Area ?

Area is a measure of the size of a two-dimensional shape or surface, such as a rectangle, circle, or triangle. It is expressed in square units, such as square inches, square feet, or square meters.

Let's use the Pythagorean theorem to find the length of the table top:

Substituting the given values, we get:

40*40 = [tex]length^{2}[/tex] + 21*21

Simplifying and solving for length, we get:

[tex]length^{2}[/tex]= 1600 - 441

[tex]length^{2}[/tex] = 961

length = 31 inches (rounded to the nearest inch)

Now that we know the length and width of the table, we can find the area by multiplying them together:

area = length x width

area = 31 x 21

area = 651 square inches (rounded to the nearest inch)

Therefore, the area of the table is approximately 651 square inches.

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Help again with math (I'm on 37/64 and I'm about to cry)

Answers

Answer:

1,215,000 cubic centimeters

Step-by-step explanation:

1. Find the volume of the cylinder

v = π r (squared) x h

v = 3.14 x 50 (squared) x 100

v = 3.14 x 2,500 x 100

v = 3.14 x 250,00

v = 785,000 cubic centimeters

2. Find the volume of the rectangular prism

v = l x w x h

v = 100 x 200 x 100

v = 2,000,000 cubic centimeters

3. Subtract

2,000,000 - 785,000 = 1,215,000 cubic centimeters

Arnav was 1.5 \text{ m}1.5 m1, point, 5, start text, space, m, end text tall. In the last couple of years, his height has increased by 20\%20%20, percent

Answers

Over the last couple of years, Arnav's height has increased by 20% so his current height is 1.8 meters.

Arnav's height initially was 1.5 meters. Over the last couple of years, his height increased by 20%. To find the new height, we can use the formula: new height = initial height × (1 + percentage increase).

In this case, the initial height is 1.5 meters and the percentage increase is 20%, which can be expressed as a decimal (0.2). Using the formula, we can calculate Arnav's new height as follows:

New height = 1.5 meters × (1 + 0.2) = 1.5 meters × 1.2 = 1.8 meters.

After the 20% increase in height over the last couple of years, Arnav's current height is 1.8 meters.

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1) If you deposited $10,000 into a bank savings account on your 18th birthday. Said account yielded 3% compounded annually, how much money would be in your account on your 58th birthday?



2)What would your answer be if the interest was compounded monthly versus


annually?

Answers

1- On the 58th birthday, the account would have $24,209.98, 2- If the interest is compounded monthly, then on the 58th birthday, the account would have $26,322.47.

1- The formula for calculating the compound interest is given by A = P(1 + r/n)(nt), where A is the final amount, P is the principal amount, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time in years. Here, P = $10,000, r = 0.03, n = 1, t = 40 years (58 - 18).

substituting the values in the formula, we get A = $10,000(1 + 0.03/1)1*40) = $24,209.98.

2) In this case, n = 12 (monthly compounding), and t = 12*40 (total number of months in 40 years). So, the formula for calculating the compound interest becomes A = P(1 + r/n)(nt) = $10,000(1 + 0.03/12)(12*40) = $26,322.47.

Since the interest is compounded more frequently, the amount at the end of 40 years is higher than when the interest is compounded annually.

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HURRY WHO IS RIGHT!!!

Answers

Answer:

Step-by-step explanation:

cat

It’s Pippa because 4/6 is 2/3. The shape got smaller since ABC goes before A’B’C’…. Hope this helps…. Let me know if I’m wrong…

One similar figure has an area that is nine times the area of another. The larger figure must have dimensions that are


times the dimensions of the smaller figure.


three


eighteen


eighty-one


nine

Answers

Since the area of a similar figure is proportional to the square of its linear dimensions, if one similar figure has an area that is nine times the area of another, the larger figure must have dimensions that are three times the dimensions of the smaller figure.

This is because the area is the square of the linear dimensions. So, if we increase the linear dimensions by a factor of 3, the area increases by a factor of 3^2 = 9.

Therefore, the answer is 3.

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anyone know the dba questions for unit 8 algebra 1 honors

Answers

a) The distance the ball rebounds on the fifth bounce is approximately 7.59 ft.

b) The total distance the ball has traveled after the fifth bounce is approximately 52.61 ft.

What is the explanation for the above response?

Let's denote the height of the ball after its nth bounce by h_n. Then we can express the relationship between the height of the ball after each bounce in terms of a recursive formula:

h_0 = 16 (initial height)

h_1 = (3/4) * h_0 (rebound distance after the first fall)

h_2 = (3/4) * h_1 (rebound distance after the second fall)

h_3 = (3/4) * h_2 (rebound distance after the third fall)

h_4 = (3/4) * h_3 (rebound distance after the fourth fall)

h_5 = (3/4) * h_4 (rebound distance after the fifth fall)

a) To find the distance the ball rebounds on the fifth bounce, we need to calculate h_5:

h_5 = (3/4) * h_4

= (3/4) * ((3/4) * ((3/4) * ((3/4) * 16)))

= (3/4)^5 * 16

= 7.59375 ft

Therefore, the ball rebounds approximately 7.59 ft on the fifth bounce.

b) To find the total distance the ball has traveled after the fifth bounce, we need to add up all of the distances traveled during the falls and rebounds:

total distance = distance of first fall + rebound distance after first fall + rebound distance after second fall + rebound distance after third fall + rebound distance after fourth fall + rebound distance after fifth fall

total distance = 16 + (3/4) * 16 + (3/4)^2 * 16 + (3/4)^3 * 16 + (3/4)^4 * 16 + (3/4)^5 * 16

total distance = 16 + 12 + 9 + 6.75 + 5.0625 + 3.7969

total distance = 52.6094 ft

Therefore, the ball travels approximately 52.61 ft after the fifth bounce.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Be sure to show and explain all work using mathematical formulas and terminology. A bouncy ball is dropped from a height of 16ft and always rebounds ¼ of the distance of the previous fall.

a) What distance does it rebound the 5th time?

b) What is the total distance the ball has travelled after this time?

Circle 1 is centered at (-3,5) and has a radius of 10 units circle 2 is centered at (7,5) and has a radius of 4 units. What transformations can be applied to circle 1 to prove that the circles are similar?

Answers

This will result in Circle 1 having the same center and radius as Circle 2, thus proving that the circles are similar.

To prove that Circle 1 and Circle 2 are similar, we can apply the following transformations to Circle 1:

1. Translation: Translate Circle 1 by moving its center from (-3, 5) to (7, 5). This is a horizontal translation of 10 units to the right.

2. Dilation: Dilate Circle 1 with a scale factor of 0.4, which will reduce its radius from 10 units to 4 units (the same as Circle 2).

These transformations will result in Circle 1 having the same center and radius as Circle 2, thus proving that the circles are similar.

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A store sells tvs for x$ they are doing a black friday sale which is 42% off, call that function f(x). they are also giving all customers a $100 rebate, call that function g(x). what is f(g(x))? and what does it mean?

Answers

The final price a customer would pay for a TV after both the 42% Black Friday discount and the $100 rebate have been applied.

Let x represent the original price of the TVs. The store is offering a Black Friday sale of 42% off, which we can represent as a function f(x) = 0.58x (since 100% - 42% = 58%). They are also giving a $100 rebate to all customers, represented by the function g(x) = x - 100.

Now, we want to find f(g(x)), which means applying the function f(x) to the result of the function g(x). So, f(g(x)) = f(x - 100).

To do this, plug in (x - 100) for x in the f(x) function: f(x - 100) = 0.58(x - 100).

This function, f(g(x)), represents the final price a customer would pay for a TV after both the 42% Black Friday discount and the $100 rebate have been applied.

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Pls help me with this! I need to finish today

Answers

Answer:

T=64

Step-by-step explanation:

Multiply both sides by 4

t/4=16

t/4×4=16×4 Cancel out the 4

t=64

Identify if the proportion is true or false12:4=9:3

Answers

true because it’s 3=3

PLEASE HELP ME WITH THIS MATH PROBLEM!!! WILL GIVE BRAINLIEST!!! 20 POINTS!!!

Answers

The average price of milk in 2018 was $6.45 per gallon.

The average price of milk in 2021 was $189.15 per gallon.

How to calculate the price

When x = 0 (which represents the year 2018), the function becomes:

3.55 + 2.90(1 + 0)³

= 3.55 + 2.90(1)³

= 3.55 + 2.90

= 6.45

The average price of milk in 2018 was $6.45 per gallon.

When x = 3 (which represents the year 2021), the function becomes:

3.55 + 2.90(1 + 3)³

= 3.55 + 2.90(4)³

= 3.55 + 2.90(64)

= 3.55 + 185.6

= 189.15

The average price of milk in 2021 was $189.15 per gallon.

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Verify that MQ:QN = 2:3 by finding the lengths of MQ and QN

Answers

The length of MQ and QN is 10 and 15 respectively and verify that MQ: QN = 2:3

The coordinate of M = (-12,-5)

The coordinate of N = (8,10)

n = 2 , m = 3

By using the section formula coordinate of Q =( [tex]\frac{mx_{1} + nx_{2} }{m+n }[/tex] , [tex]\frac{my_{1} + ny_{2} }{m+n}[/tex])

Coordinate of Q = ([tex]\frac{(-12)3 + 8(2)}{3+2}[/tex] , [tex]\frac{10(2) + 3(-5)}{2+3}[/tex])

Coordinate of Q = ( -4, 1)

Now using the distance formula

MQ = [tex]\sqrt{ (x_{2}- x_{1} )^{2} +(y_{2} -y_{1} )^{2}[/tex]

MQ = [tex]\sqrt{(-4+12)^{2}+(1+5)^{2} }[/tex]

MQ = √100

MQ = 10

Similarly,

QN = [tex]\sqrt{(8+4)^{2}+(10-1)^{2} }[/tex]

QN =  [tex]\sqrt{225}[/tex]

QN = 15

MQ:QN = 10:15

MA :QN = 2:3

Hence it is verified that MQ: QN = 2:3

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Suppose a particle moves along a continuous function such that its position is given by f(t)=1/7 t^3-4t-12 where f is the position at time t, then determines the value of r such that f(r)=0.

Answers

When we look at [tex]f(t)=1/7 t^3-4t-12[/tex], this is a cubic equation, and solving it analytically is not straightforward.

How to solve

To find the value of r such that f(r) = 0, we need to solve the equation:

[tex]1/7 r^3 - 4r - 12 = 0[/tex]

This is a cubic equation, and solving it analytically is not straightforward.

Yet, it is possible to obtain the value of r that meets the equation using numerical schemes such as Newton-Raphson or bisection. Additionally, one can take advantage of calculation tools and graphical software to calculate an estimation of r.

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To answer questions 4 - 6.

A new school opened with 225 students in 2021 and plans to increase by 13. 3% per year

until they reach full capacity.

Is this situation exponential growth or decay?

4.

5.

Write an equation that models the population of the school, P, after x years since

the opening of the school in 2021

Answers

The situation provided is exponential growth and the equation is

p = 225 * 1.133ˣ

How to determine the situation

This scenario represents a significant improvement as the number of students increases each year.

The basic approach to incremental growth is:

[tex]P = P_{0} * (1 + r)^t[/tex]

where:

P. = initial population

r = increase in decimal form

t = time in years

Here

P₀ = 225 (initial population in 2021).

r = 13.3% = 0.133 (growth rate as decimal) .

t = x (time in years from the opening of the school in 2021)

Substituting these values ​​in the formula we get:

[tex]p = 225 * (1 + 0.133)^x[/tex]

Simplifying further, we get:

p = 225 * 1.133ˣ

This is the equation that predicts school population x years after the school opens in 2021

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What are the coordinates of the vertices of d(3, a)(△abc) for a(0, 4), b(−2, 5), and
c(3, 7)? does the perimeter increase or decrease?

Answers

The coordinates of the triangle after the dilation are given as follows:

a(0, 12), b(-6, 15) and c(9, 21).

The perimeter of the triangle increases, as the side lengths are multiplied by 3, hence the perimeter is also multiplied by 3.

What is a dilation?

A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.

The scale factor for this problem is given as follows:

k = 3.

The scale factor is greater than 1, meaning that the figure is an enlargement, and thus the perimeter increases.

The original vertices of the triangle are given as follows:

a(0, 4), b(−2, 5), and c(3, 7)

Hence the vertices of the dilated triangle are given as follows:

a(0, 12), b(-6, 15) and c(9, 21).

(each coordinate of each vertex is multiplied by the scale factor of 3).

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