Quadrilateral EFGH is on a coordinate plane. Segment FG is on the line 3x − y = −2, and segment EH is on the 3x − y = −6. Which statement proves how segments FG and EH are related?

Answers

Answer 1

Answer:

the slope of both lines are the same.

Step-by-step explanation:

Given the following segment of the Quadrilateral EFGH on a coordinate  Segment FG is on the line 3x − y = −2,

segment EH is on the 3x − y = −6.

To determine their relationship, we can find the slope of the lines

For line FG: 3x - y = -2

Rewrite in standard form y = mx+c

-y = -3x - 2

Multiply through by-1

y = 3x + 2

Compare

mx = 3x

m = 3

The slope of the line segment FG is 3

For line EH: 3x - y = -6

Rewrite in standard form y = mx+c

-y = -3x - 6

Multiply through by-1

y = 3x + 6

Compare

mx = 3x

m = 3

The slope of the line segment EH is 3

Hence the statement that proves their relationship is that the slope of both lines are the same.

Answer 2

The slope of the lines is the same, the line segments FG and EH are parallel to each other and are the opposite sides of the quadrilateral.

What is the equation of a line?

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is constant.

The slope of the line segment FG can be found by comparing the equation with the equation of the line. Therefore,

y = mx + c

-2 = 3x - y

- 2 - 3x = -y

y = 3x + 2

Thus, the slope of the equation is 3.

The slope of the line segment EH can be found by comparing the equation with the equation of the line. Therefore,

y = mx + c

3x - y = -6

-y = 6 - 3x

y = 3x+6

Thus, the slope of the equation is 3.

Since the slope of the lines is the same, the line segments FG and EH are parallel to each other and are the opposite sides of the quadrilateral.

Learn more about Equation of Line:

https://brainly.com/question/21511618

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Quadrilateral EFGH Is On A Coordinate Plane. Segment FG Is On The Line 3x Y = 2, And Segment EH Is On

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Math Problem Below.
Match Each Expression from the column on the left to an equivalent expression in the column on the right.

Answers

Required Answer:

1. 5a - 8b + 7b + 3a

→ 5a + 3a - 8b + 7b

→ 8a - b ★

2. -5a + 8b - 7b - 3a

→ -5a - 3a + 8b - 7b

→ -8a + b ★

3. 5a + 8b - 7b + 3a

→ 5a + 3a + 8b - 7b

→ 8a + b ★

4. -5a - 8b + 7b - 3a

→ -5a - 3a - 8b + 7b

→ - 8a - b ★

Final answers ;

[tex] \boxed {\sf { 5a - 8b + 7b + 3a = 8a - b } } [/tex]

[tex] \boxed {\sf { -5a + 8b - 7b - 3a = -8a + b } } [/tex]

[tex] \boxed {\sf {5a + 8b - 7b + 3a = 8a + b } } [/tex]

[tex] \boxed {\sf {-5a - 8b + 7b - 3a = - 8a - b} } [/tex]

Question:-

5a – 8b + 7b + 3a

Solution:-

5a – 8b + 7b + 3a

= 5a + 3a – 8b + 7b

= 8a b ( Answer )

________________________________________________

Question:-

–5a + 8b – 7b – 3a

Solution:-

–5a + 8b – 7b – 3a

= –5a – 3a + 8b – 7b

= 8a + b ( Answer )

________________________________________________

Question:-

5a + 8b – 7b + 3a

Solution:-

5a + 8b – 7b + 3a

= 5a + 3a + 8b – 7b

= 8a + b ( Answer )

________________________________________________

Question:-

–5a – 8b + 7b – 3a

Solution:-

–5a – 8b + 7b – 3a

= –5a – 3a – 8b + 7b

= 8a b ( Answer )

________________________________________________

[tex] \bf Hope \: it \: helps \: you [/tex] .

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Hi there!

[tex]\large\boxed{\text{Center: (7,2); radius =} \sqrt{10}}}[/tex]

We know that the standard form of the graph of a circle is:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

Cost of Kid's tickets =16.66

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Step-by-step explanation:

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Answers

Answer:

a = 9

Step-by-step explanation:

For solve the problem we can use the Pythagorean theorem in this way

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Step-by-step explanation:

Hi,

Store A: y = 9p

Store B: y = 9p + 5

Store C: y = p + 5

Store D: y = p + f

Second Part:

Store A: T = 9n

Store B: T = 9n + 5

Store C: T = n + 5

Store D: T = p + f

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