The sum of both sides is 2x² + 4. The length of the third side is 5x³ - 4x² + 3x - 12
What is a triangle?A triangle is a polygon that has three sides and three angles. Types of triangles are isosceles, right angled, scalene, equilateral.
Given that the perimeter of the triangle is 5x³ - 2x² + 3x - 8. The length of side one is 3x² - 4x - 1 and that of side two is -x² + 4x + 5
The sum of side one and side two is:
Sum = side 1 + side 2 = (3x² - 4x - 1) + (-x² + 4x + 5) = 2x² + 4
The sum of both sides is 2x² + 4
The third side is:
Third side = Perimeter - Sum of two sides = (5x³ - 2x² + 3x - 8) - (2x² + 4) = 5x³ - 4x² + 3x - 12
The length of the third side is 5x³ - 4x² + 3x - 12
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There are 15 tables at a wedding reception,
5 of which have purple centerpieces.
1) What is the probability that a randomly
selected table will have a purple centerpiece?
◄) Write your answer as a fraction or whole
number.
Answer:
1/3
Step-by-step explanation:
There are 15 tables and 5 have a purple centerpiece. Divide 15 by 5 to get the probability of a randomly selected table being purple.
5/15 is 5 out of 15. 5/15 simplifies to 1/3.
Is the following function even, odd, or neither? f(x)=x^4-2x^2
The given function, f(x) = x⁴ - 2x², is even function.
What is the function?The nature of the function, whether it is even or odd can be determined by applying the following rules.
Even function, f(x) = f(-x)
Odd function; f(x) = -f(-x)
The given function, f(x) = x⁴ - 2x²
Test of for even function;
f(-x) = (-x)⁴ - 2(-x)²
f(-x) = x⁴ - 2x²
so f(x) = f(-x), the function is even.
Test for odd function;
-f(-x) = - [(-x)⁴ - 2(-x)²]
-f(-x) = -x⁴ + 2x²
so, f(x) ≠ -f(-x), the function is not odd.
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The area of a circle is 36π centimeters. What is the circumference of a circle in terms of π.
7. The plot of land modeled below is composed of a right triangle and a rectangle. If Patrick wants to install a fence around the perimeter of the plot of land, how many feet of fencing will be needed
The number of feet of fencing that will be needed is illustrated below
How many feet of fencing will be needed The feet of fencing that will be needed is the perimeter of the fence
To find the perimeter of a composite figure, we need to add up the lengths of all the sides of the figure.
In this case, we add the side lengths of the rectangle to the side lengths of the right triangle and subtracting the common lengths between both shapes
Take for instance, we have
Right triangle: 3 units, 4 units and 5 unitsRectangle: 4 by 5 unitsCommon segment: 4 unitsSo, we have
Fencing = 2 * (4 + 5) + 3 + 4 + 5 - 2 * 4
Fencing = 22 units
So, the amount of fencing for the assumed dimensions is 22 units
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She has a budget of $500. Which two items together cost 34% of her budget.
The two items that together cost 34% of her budget have a summed cost of $170
Which two items together cost 34% of her budget.From the question, we have the following parameters that can be used in our computation:
She has a budget of $500.
To calculate which two items together cost 34% of her budget, we use
Amount = 34% * Budget
substitute the known values in the above equation, so, we have the following representation
Amount = 34% * 500
Evaluate
Amount = 170
Hence, the two items would have a summed cost of $170
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Solve x²-3x+ 5 = 0.
A.
3+√-29
+VE
2
and
3-
2
-29
B. 3+√29 and 3-√29
O c. 3+√-11 and 3-√-11
2
2
D. 3+√11 and 3-√11
Using the quadratic formula to solve the equation x²-3x+ 5 = 0, the resultant answer is (D) 3+√11/2 and 3-√11/2.
What is the quadratic formula?The quadratic formula in elementary algebra is a formula that yields the answer to a quadratic problem.
In addition to the quadratic formula, other methods of solving quadratic equations include factoring, completing the square, graphing, and others.
A second-order equation of the form ax² + bx + c = 0 denotes a quadratic equation, where a, b, and c are real number coefficients and a 0.
So, we have the equation:
x²-3x+ 5 = 0
Now, solve it using the quadratic formula as follows:
x²-3x+ 5 = 0
a = 1
b = -3
c = 5
x = -(-3)±√(-3)² -4*1*5/2
Solve this further:
x = 3±√11/2
Therefore, using the quadratic formula to solve the equation x²-3x+ 5 = 0, the resultant answer is (D) 3+√11/2 and 3-√11/2.
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Correct question:
Solve x²-3x+ 5 = 0.
A.3+√-29 +VE/2 and 3- 2-29
B. 3+√29 and 3-√29
C. 3+√-11 and 3-√-11/2
D. 3+√11/2 and 3-√11/2
The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 150 grams of a
radioactive isotope, how much will be left after 6 half-lives?
Use the calculator provided and round your answer to the nearest gram.
grams
What is the difference between a formal and informal proof?
A) A formal proof is much shorter, whereas an informal proof is longer.
B) A formal proof provides the reasons for steps, whereas an informal proof does not.
C) A formal proof uses equations, whereas an informal proof only uses text.
D) A formal proof uses a table or a list of steps, whereas an informal proof uses paragraphs.
Answer: D
Step-by-step explanation: formal proofs deeply uses tables or a list of steps where informal proofs are proven in paragraphs.
Let
sin A = − 24/25
with A in QIII and find the following.
sin 2A
Answer:
sin(2A) = 2sin(A)cos(A)
To find cos(A), we can use the Pythagorean theorem:
sin^2(A) + cos^2(A) = 1
cos^2(A) = 1 - sin^2(A)
cos(A) = -√(1 - sin^2(A)) (since A is in QIII, cos(A) is negative)
cos(A) = -√(1 - (-24/25)^2) = -7/25
Now we can substitute into the double angle formula:
sin(2A) = 2sin(A)cos(A)
sin(2A) = 2(-24/25)(-7/25)
sin(2A) = 336/625
Therefore, sin(2A) = 336/625.
The distance between Kingston and Sunny Place is 35 km. At 8.30 a.m. , Joel cycles from Kingstown towards Sunny place at an average speed of 12 Km/h. At the same time, Ryan cycles from Sunny place towards Kingstown, along the same route, at an average speed of 8 Km/h.
a) At what time will the cyclists meet on the way?
b)How far will each cyclist have travelled when they meet?
Answer:
Distance = Speed × Time.
Let's break down the problem into two parts:
a) At what time will the cyclists meet on the way?
Let's assume t represents the time in hours when the cyclists meet.
The distance Joel travels in t hours is given by: Distance = Speed × Time = 12t km.
The distance Ryan travels in t hours is given by: Distance = Speed × Time = 8t km.
Since they are cycling towards each other, the sum of their distances should equal the total distance between Kingston and Sunny Place, which is 35 km.
So, we can set up the equation: 12t + 8t = 35.
Simplifying the equation, we have: 20t = 35.
Dividing both sides of the equation by 20, we get: t = 35/20 = 1.75 hours.
Therefore, the cyclists will meet on the way after 1.75 hours, which is equivalent to 1 hour and 45 minutes.
b) How far will each cyclist have traveled when they meet?
To find the distance traveled by each cyclist, we can substitute the value of t into their respective equations:
Distance traveled by Joel = 12t = 12 × 1.75 = 21 km.
Distance traveled by Ryan = 8t = 8 × 1.75 = 14 km.
Therefore, when the cyclists meet, Joel would have traveled 21 km and Ryan would have traveled 14 km.
The formula A = 252e^.049t models the population of a particular city, in thousands, t years after 1998. When will the population of the city reach 373 thousand?
Answer: Approximately the year 2006
Roughly 8 years after 1998
================================================
Work Shown:
A = 373 represents a population of 373 thousand.
Plug in this value of A and solve for t. We'll need natural logs (LN) to isolate the variable.
[tex]A = 252e^{0.049t}\\\\373 = 252e^{0.049t}\\\\373/252 = e^{0.049t}\\\\1.4801587 \approx e^{0.049t}\\\\[/tex]
Apply natural logs to both sides.
[tex]\text{Ln}(1.4801587) \approx \text{Ln}\left(e^{0.049t}\right)\\\\\text{Ln}(1.4801587) \approx 0.049t*\text{Ln}\left(e\right)\\\\\text{Ln}(1.4801587) \approx 0.049t*1\\\\\text{Ln}(1.4801587) \approx 0.049t\\\\t \approx \text{Ln}(1.4801587)/0.049\\\\t \approx 8.0030472\\\\[/tex]
It takes about 8 years for the population to reach 373 thousand.
Since t = 0 starts at 1998, we get to the year 1998+8 = 2006.
Find the principal needed now to get the given amount; that is, find the present value.
To get $100 after 3 years at 9% compounded quarterly
The present value of $100 is $
(Round to the nearest cent as needed.)
The present value of $100 to be received after 3 years at 9% compounded quarterly is $73.67.
The formula for the present value of a future amount under quarterly compounding is:
PV = FV / (1 + r/4)⁴ⁿ
where PV is the present value,
FV is the future value, r is the interest rate per year, and n is the number of years.
In this case, FV = $100, r = 0.09 (9%), n = 3 years, and the interest is compounded quarterly
so the interest rate per quarter is r/4 = 0.0225.
Plugging these values into the formula, we get:
PV = $100 / (1 + 0.0225)¹² = $73.67
Therefore, the present value of $100 to be received after 3 years at 9% compounded quarterly is $73.67.
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Given the equations of two lines, describe how to determine if the lines are parallel.
Hi! To determine if two lines are parallel given their equations, follow these steps:
1. Identify the slopes of the lines from their equations.
If the equations are in the slope-intercept form (y = mx + b), the slope is the coefficient of x (m). If the equations are in standard form (Ax + By = C), you can find the slope by rearranging the equation to the slope-intercept form.
2. Compare the slopes of both lines. If the slopes are equal, the lines are parallel.
In summary, given their math equations, you need to describe their slopes and check if they are equal to determine if the lines are parallel.
Hi to confirm that two lines are parallel lines given their equation you the gradient which is the value of x in the equation y=mx + c. Where m is the gradient
PROJECT: INSCRIBED POLYGONS
You've learned about the different parts of a circle, as well as regular polygons and their angle measures. You've also learned how to use a protractor to measure angles.
In this project, you will apply this knowledge to inscribe regular polygons in a circle. If a polygon is inscribed in a circle, all of its vertices touch the circle. Here is an example of an equilateral triangle inscribed in a circle.
OBJECTIVES
Inscribe regular polygons in circles using a protractor, compass, and straight edge.
Materials
pencil and paper
protractor
compass
straight edge
Water is leaking out of an inverted conical tank at a rate of 11500.0 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 9.0 m and the the diameter at the top is 4.5 m. If the water level is rising at a rate of 21.0 cm/min when the height of the water is 2.0 m, find the rate at which water is being pumped into the tank in cubic centimeters per minute.
water is being pumped into the tank at a rate of 23.7 cm³/min.we can take the derivative of the volume formula with respect to time and solve it
what is derivative ?
In mathematics, a derivative is a measure of how much a function changes as its input value changes. More specifically, the derivative of a function is defined as the rate of change of the function at a particular point.
In the given question,
We can solve this problem using related rates, where we relate the rate of change of one variable to the rate of change of another variable.
Let's denote the height of the water in the tank by h, and the radius of the water surface by r. Then, we can use the formula for the volume of a cone to relate these variables:
V = (1/3)πr²h
We are given that the tank has height 9.0 m and diameter (and thus radius) 4.5 m at the top. We can use this information to find the relationship between h and r:
r = (1/2) × diameter = 2.25 m
h = 9.0 m - 2.0 m = 7.0 m
Now, we can take the derivative of the volume formula with respect to time:
dV/dt = (1/3)π(2r(dr/dt) + r²(dh/dt))
We want to find the rate at which water is being pumped into the tank, which is the rate of change of the volume with respect to time when the water level is rising at a rate of 21.0 cm/min. We are also given that water is leaking out of the tank at a rate of 11500.0 cm^3/min, so we can set these rates of change equal to each other:
dV/dt = (21.0 cm/min) × (1 m/100 cm)³ = 0.021 m³/min
11500.0 cm³/min = 11.5 × (1 m/100 cm)³ m³/min
Substituting these values and the values we found for r and h into the derivative formula, we get:
0.021 m³/min = (1/3)π(2(2.25 m)(dr/dt) + (2.25 m)²(11500.0 cm³/min)/(100 cm/m)³)
Simplifying and solving for dr/dt, we get:
dr/dt = [(0.021 m³/min) - (1/3)π(2(2.25 m)(11500.0 cm³/min)/(100 cm/m)³)] ÷ [(1/3)π(2(2.25 m))]
= 0.0237 m/min = 23.7 cm/min
Therefore, water is being pumped into the tank at a rate of 23.7 cm³/min.
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Rewrite the quadratic function as a product of linear factors.
f(x) = 16x^2 - 3
help pls
Answer: (4x - √3)(4x + √3).
Step-by-step explanation: Use factoring. The equation (when factored out) is: ax^2 + bx + c. Hence, the equation you wrote rewritten is: 16x^2 + 0x - 3. (√3)(√3) = 3 and (4x)(4x) = 16x^2. It is divisible.
So, the quadratic function f(x) = 16x^2 - 3 can be expressed as a product of linear factors as (4x - √3)(4x + √3).
PLEASE HELP BRO PLEASEEEE
The likelihood that a milkshake chosen at random will be a sloppy, thin, flavourless mess is 0.62.
Define probabilityThe possibility or chance of an event occurring is measured by probability. It is a number between 0 and 1, where 0 denotes that the occurrence is impossible and 1 denotes that it is unavoidable. By dividing the number of favourable outcomes by the total number of potential outcomes, the probability of an occurrence is determined.
a. The milkshake will most likely turn out to be a watery, thin, flavourless mess (2, 4, 7).
The likelihood that a milkshake chosen at random would be a sloppy, thin, flavourless mess is equal to the final result of the milkshake will be a watery, thin, flavourless mess.
=2+4+7/21
=13/21
=0.62
b. No association can be removed from this table. We are unable to forecast the result of any event since the overall number of events is random.
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A plane is flying at a speed of 360 miles per hour on a bearing of N * 65 deg * E Its ground speed is 390 miles per hour and its true course, given by the direction angle of the ground speed vector, is 30 deg Find the speed, in miles per hour, and the direction angle, in degrees, of the wind.
Answer:w = 74.66 mph
d = 19.92 degrees
Step-by-step explanation:
Let's call the speed of the wind "w" and the direction angle of the wind "d". We can use vector addition to solve for these unknowns.
First, let's find the direction of the plane. The bearing of N * 65 deg * E can be represented as a vector with an initial point at the North pole and a terminal point 65 degrees east of due north. Since the plane is flying on this bearing, its direction vector is the same as the bearing vector. We can find the components of this vector as follows:
cos(65) = x / 1
x = cos(65)
y = sin(65)
So the direction vector of the plane is <cos(65), sin(65)>.
Next, let's find the ground speed vector. We can represent this vector as the sum of the plane's airspeed vector and the wind vector:
ground speed = airspeed + wind speed
We know that the magnitude of the ground speed vector is 390 mph, and we know the direction angle of the ground speed vector is 30 degrees. We can use this information to set up two equations:
|airspeed + wind speed| = 390
tan(d) = (wind speed)_y / (wind speed)_x
Since we know the direction vector of the plane, we can express the airspeed vector in terms of this vector as follows:
airspeed = 360 <cos(65), sin(65)>
Now we can substitute the airspeed vector and the wind speed vector into the equation for the ground speed vector, and use the fact that the magnitude of the ground speed vector is 390 to solve for the components of the wind speed vector:
|360 <cos(65), sin(65)> + <(wind speed)_x, (wind speed)_y>| = 390
Squaring both sides and using the fact that cos^2(x) + sin^2(x) = 1, we get:
129600 cos^2(65) + 129600 sin^2(65) + 720(wind speed)_x cos(65) + 720(wind speed)_y sin(65) + (wind speed)_x^2 + (wind speed)_y^2 = 152100
Simplifying, we get:
51840 + 720(wind speed)_x cos(65) + 720(wind speed)_y sin(65) + (wind speed)_x^2 + (wind speed)_y^2 = 152100
Substituting the equation for the direction angle of the wind and simplifying, we get:
51840 + 720w cos(65 - d) + w^2 = 152100 tan^2(d)
We now have two equations and two unknowns: w and d. We can solve for them using algebra or a numerical solver. Using a numerical solver, we find:
w = 74.66 mph
d = 19.92 degrees
Therefore, the speed of the wind is 74.66 mph, and its direction angle is 19.92 degrees.
In circle X, m/VWU = 43°. Solve for x if mVU = (7x + 46)°. If necessary,
round your answer to the nearest tenth.
U
V
W
The measure of angle x of the circle is x = 5.7
Given data ,
Let the center of the circle be represented as x
Now , the value of x is given by
The measure of angle ∠VWU = 43°
And , the measure of arc VU = ( 7x + 46 )°
Now , from the arc theorem of circle , we get
mVU = 2 ∠VWU
On simplifying , we get
2 ( 43 ) = ( 7x + 46 )
7x + 46 = 86
Subtracting 46 on both sides , we get
7x = 40
Divide by 7 on both sides , we get
x = 5.71
Hence , the measure of x of circle is x = 5.7
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Please help Thanks
there is a FRACTION symbol two variable symbols y and x
Step-by-step explanation:
The equation of the line (by inspection) is y = 1/2 x
HELP ME PLEASEEEE The matrix below represents a system of equations.
Which matrix represents the solution to this system of equations?
The matrix that represents the solution to this system of equations is
1 0 0 2
0 1 0 -4
0 0 1 3
Therefore option B is correct.
What is a matrix in mathematics?A matrix is described as a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns, which is used to represent a mathematical object or a property of such an object.
We solve a matrix by Arranging the elements of equations in matrices and find the coefficient matrix, variable matrix, and constant matrix.
We then go ahead to write the equations in AX = B form.
we then take the inverse of A by finding the adjoint and determinant of A. Multiply the inverse of A to matrix B, thereby finding the value of variable matrix X.
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Sarah is twice Jans age. Henry is 5 years younger than Jan. The sum of all their ages is 35. How old is Sarah?
Step-by-step explanation:
let the first letter of their name represent
their age
s=2j
h=j-5
s+j+h=35
replace s AND h with the values above
2j+j+j-5=35
4j=35+5
4j=40
j=10
replace j in the equation s=2j
s=2×10
s=20
replace j in the equation h=j-5
h=10-5
h=5
i need help with this math problem if anyone can help within the next 5-30m that would be great!
Answer:
2 1/3
Step-by-step explanation:
add then multiplying to the nearest one.
[tex]8 : 1/3\\[/tex]8 : 1/3
The ratio of 8 : 1/3 is equivalent to the simplified ratio of 24 : 1.
How to simplify the ratio?To analyze and describe the ratio 8 : 1/3, we need to convert the fraction to a ratio with a whole number. One way to do this is to express the fraction as a ratio with a denominator of 3:
1/3 = 1:3
Now we can rewrite the ratio 8 : 1/3 as:
8 : 1:3
We can simplify this ratio by multiplying both terms by 3 to get rid of the fractional term:
8 × 3 : 1:3 × 3
24 : 1
Therefore, the ratio 8 : 1/3 is equivalent to the simplified ratio 24 : 1. This means that for every unit in the second part of the ratio, there are 24 units in the first part of the ratio. In other words, the first part of the ratio is 24 times larger than the second part.
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You want to determine the number of students in your school who have visited a public library. You survey 30 students at random. Twenty-four have visited a public library, and six have not. So, you conclude that 80% of the students in your school have visited a public library.
Determine whether the conclusion is valid
Answer: e
Step-by-step explanation:
Answer:Valid
Step-by-step explanation:
College Level Trig Question!
The value of theta in the given trigonometry function is 45⁰.
What is the value of theta?The value of theta in the given trigonometry function is calculated as follows;
9 sin²θ tanθ - 9 sin²θ = 0
Solve the equation as follows;
9 sin²θ tanθ = 9 sin²θ
divide both sides by 9 sin²θ;
(9 sin²θ tanθ)/9 sin²θ = 9 sin²θ /9 sin²θ
tanθ = 1
Now, solve for θ as follows;
θ = tan⁻¹ (1)
θ = 45⁰
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using the table feature of a graphing utility what would be the intensity of an earthquake with an amplitude of 200,000 micrometers for 0.5 seconds?
Using the table feature of a graphing utility the intensity of an earthquake with an amplitude of 200,000 micrometers for 0.5 seconds would be 2.16 x 10¹⁴ joules/second/meter².
How did we get this ?First, note that the intensity of an earthquake with an amplitude of 200,000 micrometers for 0.5 seconds can be calculated using the formula..
I = (1/2)ρv²
Here I Intensity
ρ = density of the medium - this is a constatnt
v = velocity of the S-waves
If we used a graphing tool
a coumun ffor v will be created
a column for the formula for velocity will also be created.
The formula for velocity is
V = A/ T
A = amplitude
T = time or period in seconds
Since A = 200,000 micrometers; and
T = 0.05 secons
v = 200,000 / 0.5
v = 400,000 micrometer/sec
Back o the table, we ahve to add another oclumn for V²
then enter the values for V²
V² = 400,000²
v² = 160,000,000,000 micrometer²/sec²
Nowe we add another column which is
I = 1/2(pv²)
I = 2.16 x 10¹⁴ joules/second/meter².
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29 Given: A = √363 and B = √27
Explain why A + B is irrational.
Explain why A B is rational.
To explain why A + B is irrational, we need to show that it cannot be expressed as a ratio of two integers.
Suppose that A + B is rational, which means we can write it as the ratio of two integers p and q (where q is not zero):
A + B = p/q
Now, we can substitute the values of A and B and simplify:
√363 + √27 = p/q
We can then rearrange the terms to isolate one of the square roots:
√363 = p/q - √27
We can square both sides of this equation to eliminate the square roots:
363 = p^2/q^2 + 27 - 2(p/q)√27
Notice that the right-hand side of this equation has a term with a square root. This means that if we assume that A + B is rational, we arrive at a contradiction: we have shown that √363 (which is equal to A) is irrational, which means that p^2/q^2 + 27 must also be irrational. However, the left-hand side of the equation is rational. Therefore, our assumption that A + B is rational must be false, and we conclude that A + B is irrational.
To explain why AB is rational, we can use the fact that the product of two rational numbers is rational.
We can rewrite A and B as follows:
A = √(363) = √(121 x 3) = √(11^2 x 3) = 11√3
B = √(27) = √(9 x 3) = √(3^2 x 3) = 3√3
Therefore, AB = 11√3 x 3√3 = 33 x 3 = 99.
Since 99 is a rational number (which can be expressed as the ratio of the integers 99 and 1), we conclude that AB is rational.
Mr. McGill is buying a car worth $35,000 and taking out a loan for the full amount. If
it is increasing at 2.5 percent yearly. How much will the loan increase to in 5 years?
A.) $39,599.29
B.)$36,599.29
C.)$18,382,656.25
D.)$40,269,30
The loan will increase to $39599.29 in 5 years
How much will the loan increase to in 5 years?From the question, we have the following parameters that can be used in our computation:
Mr. McGill is buying a car worth $35,0002.5% interest compounded annualyUsing the above as a guide, we have the following:
Amount = P * (1 + r)ᵗ
Where
P = Principal = 35000
r = Rate = 2.5%
t = time = 5
Substitute the known values in the above equation, so, we have the following representation
Amount = 35000 * (1 + 2.5%)⁵
Evaluate
Amount = 39599.29
Hence, the amount is 39599.29
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Here is a pyramid and its net.
The lateral faces are congruent triangles. The base (shaded) is a square. (All lengths are in centimeters.)
Area of the base of the pyramid is 16 square centimeters
Area of one lateral face of the pyramid is 14 square centimeters
The lateral surface area of the pyramid is 56 square centimeters
The total surface area of the pyramid is 72 square centimeters
Area of the base of the pyramid = length x length
= 4 x 4
=16 square centimeters
Area of one lateral face of the pyramid = area of a triangle
=1/2×base×height
=1/2×4×7
=14 square centimeters
The lateral surface area of the pyramid = 4 x area of one lateral face
= 4 x 14
= 56square centimeters
The total surface area of the pyramid = lateral surface area of the pyramid + area of the base
=56+16
=72 square centimeters
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