pls help how do i solve for x in this equation??

Answer:

177

Step-by-step explanation:

Answer:

8 un^2

Step-by-step explanation:

to find this answer you must find the area of the rectangle and then the triangle

the rectangles area is

2 * 3 = 6 un^2

the traingle is

2 * 2 * 1/2 = 2 un^2

now you add them

6 + 2 = 8 un^2

Answer:

False

Step-by-step explanation:

P is not necessarily on the angle bisector of angle A.

Attached is an example of a carefully constructed shape (so that it's easy to see the measurements):

Visually, point P is not on the angle bisector of angle A.

While having two adjacent congruent segments is necessary for P to be on the bisector of angle A, it is not sufficient.  The segments on the rays from A to the end of those segments would also need to be a pair of congruent adjacent sides (forming a kite).  For a kite, the diagonal from the point between one pair of adjacent congruent sides to the point between the other pair of adjacent congruent sides does form an angle bisector with both angles.

Step-by-step explanation:

[tex] \sin(\pi - x) + \tan(x) \cos(x) (x - \frac{\pi}{2} [/tex]

[tex] \sin( - x + \pi ) + \tan(x) ( \cos(x - \frac{\pi}{2} ) )[/tex]

Sin is odd function, so if you add pi to it, it would become switch it sign.

[tex] - \sin( - x) + \tan(x) \cos(x - \frac{\pi}{2} ) [/tex]

Also since sin is again, a odd function, we can just multiply the inside and outside by -1, and it would stay the same.

[tex] \sin(x) + \tan(x) \cos(x - \frac{\pi}{2} ) [/tex]

Cosine is basically a sine function translated pi/2 units to the right or left so

[tex] \sin(x) + \tan(x) \sin(x) [/tex]

[tex] \sin(x) ( 1 + \tan(x) )[/tex]

Option (B) FR and NR, option (C) NO and NM, and option (D) RC and RO are correct.

The measurements of the sides and angles of two or more geometrical figures determine their congruence. For example triangle's size is determined by its three sides, and its shape is determined by its three angles.

We have:

The diagram represents an unfolded paper kabuto, a samurai warrior's helmet.

Unfolded paper can be seen in the provided figure. The sheet is square.

The diagonals, in this case, are FN and AK, and the midline is CM and OI. At point R, all of these lines converge.

FR ≅ NR

AO ≅ ON

RC ≅ RO

NO ≅ NM

DV ≅ HV

Thus, option (B) FR and NR, option (C) NO and NM, and option (D) RC and RO are correct.

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Answer:

4/5

Step-by-step explanation:

Slope

    Slope y-intercept of a line: y = mx + b

Where m is the slope and b is the y-intercept.

 [tex]\sf y =\dfrac{4}{5}x-3\\\\\boxed{Slope = \dfrac{4}{5}}[/tex]

hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

⊱┈────────────────────────┈⊰

[tex]\large \bold {ANSWER}[/tex]

[tex]\large \bold {EXPLANATION}[/tex]

This line is in slope-intercept form, y=mx+b, where m represents the slope and b represents the y-intercept.

So that we can conclude that the slope is 4/5.

[tex]\huge\text{Hey there!}[/tex]

[tex]\text{4x = 19}\\\\\large\textbf{DIVIDE 4 to BOTH SIDES}\\\\\rm{\dfrac{4x}{4} = \dfrac{19}{4}}\\\\\large\textbf{SIMPLIFY IT!}\\\\\rm{x = \dfrac{19}{4}}\\\\\rm{x = 19 \div 4}\\\\\text{x = 4.75}\\\\\rm{x \approx 4.7500}\\\\\\\huge\text{Therefore, the answer should be: \boxed{\mathsf{4.7500}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

Vicks monthly interest payment is $91

Step-by-step explanation:

Total: $1800

Down payment: $500    (already paid)

Current balance need to be paid:

$1800 -  $500 = $1300

7% of  $1300 is, 1300 x 0.07 = $91

The pressure by the statue exerted on the floor will be 1200 N per square meter.

The term pressure is defined as the force per unit area.

The formula is igven below.

P = F /A

A bronze statue weighs 2400 N and has a base that is 4 m by ½ m.

Then the base area will be

A = 4 x 1/2

A = 2 square meters

Then the pressure will be

P = 2400 / 2

P = 1200 N per square meter.

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Answer:

[tex]60200cm^{2}[/tex]

Step-by-step explanation:

(I am assuming that the units for the measurements in this question are all centimeters)

Surface area = 2 * (Area of Base) + (Perimeter of base)*(Height)

  First, we'd need to solve for the area of the base by finding the area of the triangle and subtracting it from the area of the rectangle. The area of the rectangle is [tex]100 * 150 = 15000[/tex]. The area of the triangle is [tex]\frac{1}{2} * 120 * 90 = 5400[/tex]. (We can do this because it is a right triangle with leg lengths in the pattern of a 3-4-5 triangle.) Now, subtracting the area of the triangle from the rectangle, we get [tex]15000 - 54000 = 9600[/tex]. This is the area of the base.

  Next, the perimeter of the base is [tex]100 + 150 + 90 + 120 = 460[/tex]. Multiplying this by the height, we get [tex]460 * 110 = 50600[/tex].

  Finally, we add 9600 and 50900 to get [tex]9600 + 50900 = 60200[/tex].

Answer:

4/7

Step-by-step explanation:

2/3 × 6

7

4/7

and bro that's really it

The no. of different groups of players of 6 players , if the position does not matter is given by 5005 ,Option C is the right answer.

Combination is a method of selection of items from a set of distinct objects , when the position doesn't matter .

It is given that

Total number of players = 15 = n

No. of players to be selected = 6 = r

The no. of different groups of players of 6 players , if the position does not matter is given by

[tex]\rm ^nC_r = \dfrac{n!}{r! (n-r)!}[/tex]

So

[tex]\rm ^{15}C_6 = \dfrac{15!}{6! (15-6)!}\\\\\rm ^{15}C_6 = \dfrac{15!}{6! (9)!}\\\\\\^{15}C_6 = \dfrac{15 * 14 * 13* 12 * 11 * 10 }{6 *5* 4 * 3 * 2*1}\\\\ ^{15}C_6 = 5005\\[/tex]

Therefore , The no. of different groups of players of 6 players , if the position does not matter is given by 5005

Option C is the right answer.

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According to second equation of kinematics

Take positive value

Answer:

2.7 s  (1 d.p.)

Step-by-step explanation:

Use the Constant Acceleration Equations where:

Given:

[tex]\begin{aligned}\text{Using }s & =ut+\dfrac{1}{2}at^2\\\implies 55 & =11.8t+\dfrac{1}{2}(6.39)t^2\end{aligned}[/tex]

Rearrange the equation to equal zero:

[tex]\implies 3.195t^2+11.8t-55=0[/tex]

Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Use the quadratic equation to solve for t:

[tex]\implies a=3.195, \quad b=11.8, \quad c=-55[/tex]

[tex]\implies t=\dfrac{-11.8 \pm \sqrt{11.8^2-4(3.195)(-55)} }{2(3.195)}[/tex]

[tex]\implies t=2.694780675, -6.388051411[/tex]

As time is positive:

[tex]\implies t=2.694780675... \:\text{s}[/tex]

[tex]\implies t=2.7 \: \text{s (1 d.p.)}[/tex]

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(a) Given [tex]f(x) = x^3[/tex], the derivative is

[tex]f'(x)=3x^2[/tex]

which is exists for all [tex]x[/tex] in the domain of [tex]f[/tex], so [tex]]f[/tex] is differentiable everywhere and satisfies the mean value theorem. There is some number [tex]c[/tex] in the open interval (0, 2) such that

[tex]f'(c) = \dfrac{f(2) - f(0)}{2-0} \iff 3c^2 = \dfrac{8-0}2 = 4[/tex]

Solve for [tex]c[/tex] :

[tex]3c^2 = 4 \implies c^2 = \dfrac43 \implies \boxed{c = \dfrac2{\sqrt3}}[/tex]

We omit the negative square root since it doesn't belong to (0, 2). Graphically, the MVT tells us the tangent line to the curve [tex]f(x)=x^3[/tex] at [tex]x=\frac2{\sqrt3}[/tex] is parallel to the secant line through the endpoints of the given interval.

(b) [tex]f(x)=1+x+x^2[/tex] has derivative

[tex]f'(x)=1+2x[/tex]

By the MVT,

[tex]f'(c) = \dfrac{f(2)-f(0)}{2-0} \iff 1+2c = \dfrac{7-1}2 \implies \boxed{c = 1}[/tex]

(c) [tex]f(x) = \cos(2\pi x)[/tex] has derivative

[tex]f'(x) = -2\pi \sin(2\pi x)[/tex]

By the MVT,

[tex]f'(c) = \dfrac{f(2)-f(0)}{2-0} \iff -2\pi \sin(2\pi c) = \dfrac{0-0}2 \implies \sin(2\pi c) = 0 \\\\ \implies 2\pi c = n\pi \implies c = \dfrac n2[/tex]

where [tex]n[/tex] is any integer. There are 3 solutions in the interval (0, 2),

[tex]\boxed{c = \dfrac12, c = 1, c = \dfrac32}[/tex]

(Pictured is the situation with [tex]c=\frac12[/tex])

Answer:

whats the question? please explain

Answer:

For a principle amount of $1600 and rate 5.4%, the effective annual yield is 5.55% if interest is compounded annually.

Step-by-step explanation:

Concept: The annual percentage yield (APY) or the effective annual yield is the real rate of return earned on an investment, taking into account the effect of compounding interest.

The principle amount is $1600, rate is 5.4% and period is 365 days. The formula to find yield is [tex]Y = (1+\frac{r}{n} )^{n} -1[/tex]. All the values are to be inserted in the formula. Here n = 365 and r = 5.4%.

[tex]Y=(1+\frac{0.054}{365} )^{365} -1\\Y=(1.000148)^{365} -1\\Y=5.55%[/tex]

The annual yield is 5.55%.

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Answer:

b) angles 1 and 4 are congruent.

Hope it helps!

Answer:

yes.

but it will be in decimals if you divide by two. And if you divide it by another rank, it will surely give a whole number. please this all I can do for you and add me to your followers

The solution is  x ≈ 0.3 , Option A is the right Answer.

An Equation is a mathematical statement formed when two algebraic expressions are equated using an equal sign.

To find the value of

22x = 5.3

A graph has to be plotted for the line

From the graph it can be clearly seen the point at which the line intersect x axis is  x = 0.24 , which is approx equal to 0.3.

Therefore the solution is  x ≈ 0.3 ,

Option A is the right Answer.

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Answer:

6.34 min to empty

Step-by-step explanation:

80 cm x 40 cm x 30 cm = 96000 cm^3

  this volume represents  25.36 gallons of water (US)

25.36 gal / 4 gal/min = 6.34 min  to empty

Your contribution margin is $2.68 considering the price of the braised ribs and the cost of the components.

Selling price per unit less variable cost per unit equals contribution margin, often known as dollar contribution per unit. The amount of sales income referred to as "Contribution" is the fraction that is not used to pay variable expenses and hence helps to cover fixed costs.

Given ingredients for your braised greens cost 1.32$ and sells at $4

We have to find contribution margin on that

The difference between a venture's variable costs and its selling price is the contribution margin:

= Selling price - Variable cost

The selling cost is $4 and the variable costs are $1.32.

Therefore Contribution margin is as follow:

= 4 - 1.32

= $2.68

Hence your contribution margin is $2.68 considering the price of the braised ribs and the cost of the components.

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Answer:

C.) y = 3(x - 3)(x - 7)

For the function:

Writing equation:

y = a(x - h)² + k

15 = a(8 - 5)² - 12

15 = 9a - 12

9a = 15 + 12

9a = 27

a = 3

So the equation is:

y = 3(x - 5)² - 12

y = 3(x² - 10x + 25) - 12

y = 3x² - 30x + 63

y = 3(x - 3)(x - 7)

Answer:

x = 99

Step-by-step explanation:

3x + 99x = 12x

12x = 1188 divide 1188 ÷ 12

x = 99

Answer: letter B (answer is 2)

Step-by-step explanation:

Answer:

7x-1 + 2x-1 =7 ..... given

9x-2 = 7

9x = 9

x = 1

Step-by-step explanation:

This is the answer of the above condition.

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Answer:

The answer for "?" is z+1.

Step-by-step explanation: In order to solve this I recommend comparing the two equations and expanding them as much as possible, like so.

[tex](\frac{2-z}{z} =\frac{(2-z)(?)}{z^2+z} )=(\frac{2-z}{z} =\frac{(2-z)(?)}{z(z+1)} )[/tex]

Once you have the equations expanded to their maximum you can see what was added to the right side of the equation and what you need to add to the numerator in this case to make the two equations equal.

[tex](\frac{2-z}{z} =\frac{(2-z)(z+1)}{z(z+1)} )[/tex]

*Note: You can also check the solution by plugging in a number for z and checking to see that both side equal. For example if z = 3.

[tex]\\\frac{2-3}{3} =-\frac{1}{3} \\\frac{(2-3)(3+1)}{3^2+3} =-\frac{1}{3}[/tex]

So, z+1 is the answer.

The linear equation that contains the coordinate parts in the given table is: y = 1/3x + 2.

To find the linear equation that contains the coordinate parts in the table given, find the slope (m) and y-intercept (b), then substitute the values into y = mx + b.

Slope (m) using two coordinate parts, (0, 2) and (3, 3):

Slope (m) = change in y / change in x = (3 - 2)/(3 - 0)

Slope (m) = 1/3

y-intercept (b) = 2 [this is the value of y when x = 0)

Substitute the values into y = mx + b

y = 1/3x + 2.

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