Please upload a picture of a piece of paper with the problem worked out, and draw the graph for extra points, there will be 6 of these, so go to my profile and find the rest, and do the same, for extra points. solve this one using the elimination method.

Answer:

29

Step-by-step explanation:

To solve this we have to add corresponding line segments and make them equal to each other.

We can see XZ is broken into XA and AZ.

We can also see that WY is broken into WA and AY.

We are given:

XA=12

AY=14

WA=3+3x

AZ=4x+1

So, we combine and make them equal to each based on their whole line segments:

[tex]12+4x+1=3+3x+14[/tex]

combine like terms

[tex]13+4x=17+3x[/tex]

subtract 13 from both sides

[tex]4x=4+3x[/tex]

subtract 3x from both sides

x=4

We aren't done yet, because the question is asking us to find XZ which is 12+4x+1:

substitute 4 for x

12+4(4)+1

multiply

12+16+1

=29

So, XZ is 29 units.

Hope this helps! :)

The height of the house by the given data is 4000ft.

We are given that;

Number of BTUs for heating= 52000

Now,

The time from minutes to hours by dividing by 60:

t=606.24​ hr

t≈0.104 hr

Then, we can plug in the values into the heat loss formula and solve for A, which is the surface area of the house:

Q=UAΔTt

52,000=0.25A×50×0.104

A=0.25×50×0.10452,000​ ft2

A≈4000 ft2

Therefore, by the algebra the answer will be 4000 ft.

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Answer:3.75 BTUs/ft

height=18 ft

Step-by-step explanation:

The perimeter of the base of the triangular prism =

The area of the base of the triangular prism =

The total surface area of the triangular prism =

A triangular prism is a three-dimensional geometric shape that consists of two parallel triangular bases connected by three rectangular or parallelogram faces. The faces that connect the two bases are called lateral faces. The lateral edges are the edges that connect the lateral faces, and the base edges are the edges that form the triangles.

The perimeter of the base of the triangular prism

p = 10cm + 10cm + 12cm = 32cm

The area of the base of the triangular prism =

base area = (1/2) bh

= 1/2 × b × h = 1/2 × 12 × 8 = 48cm².

The total surface area of the triangular prism =  (Perimeter of the base × Length of the prism) + (2 × Base Area)

= (32 + 34) + (2 × 48) = 66 + 96 = 162cm².

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The tax amount for this meal is $4.32.

To calculate the tax amount on the meal, you'll need to multiply the total bill by the tax rate. In this case, the total bill is $57.60 and the tax rate is 7.5%.

To find the tax amount, use this formula: Tax Amount = Total Bill × Tax Rate

Tax Amount = $57.60 × 0.075

Tax Amount = $4.32

The tax amount for this meal is $4.32.

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The required answer is x = 14

To solve this problem, we can use algebraic equations. Let's start by representing the number of points that Aisha has with the variable "x".

According to the problem, we know that Carter has 7.5 more points than Aisha, so we can write:
Carter = x + 7.5
An algebraic equation or polynomial equation is an equation in which both sides are polynomials (see also system of polynomial equations). These are further classified by degree: linear equation for degree one. quadratic equation for degree two.

We also know that Jamila has 4.5 more points than Carter, which means:

Jamila = (x + 7.5) + 4.5

a variable (from Latin variabilis, "changeable") is a symbol that represents a mathematical object. A variable may represent a number, a vector, a matrix, a function, the argument of a function, a set, or an element of a set.

Algebraic computations with variables as if they were explicit numbers solve a range of problems in a single computation. For example, the quadratic formula solves any quadratic equation by substituting the numeric values of the coefficients of that equation for the variables that represent them in the quadratic formula. In mathematical logic, a variable is either a symbol representing an unspecified term of the theory (a meta-variable), or a basic object of the theory that is manipulated without referring to its possible intuitive interpretation.
Finally, we know that Jamila has 26 points:

Jamila = 26

Now we can solve for x:

(x + 7.5) + 4.5 = 26

x + 12 = 26

x = 14

Therefore, Aisha has 14 points.

To show the work:

Aisha = x

Carter = x + 7.5

Jamila = (x + 7.5) + 4.5

Jamila = 26

(x + 7.5) + 4.5 = 26

x + 12 = 26

x = 14

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Answer:

16.7 units

Step-by-step explanation:

its a 45°-45°-90° right triangle, so n1=4.9

r=4.9[tex]\sqrt{2}[/tex] =6.9

perimeter = 4.9+4.9+6.9=16.7 units

Answer: Therefore, the angle of the terminal side through the point p is 315.0 degrees (to the nearest tenth of a degree).

Step-by-step explanation:

The point p = (-√2/2,√2/2) lies on the unit circle, which is centered at the origin (0,0) and has a radius of 1. To find the angle of the terminal side through this point, we need to use the trigonometric ratios of sine and cosine.

Recall that cosine is the x-coordinate of a point on the unit circle, and sine is the y-coordinate. Therefore, we have:

cos(θ) = -√2/2

sin(θ) = √2/2

We can use the inverse trigonometric functions to solve for θ. Taking the inverse cosine of -√2/2, we get:

θ = cos⁻¹(-√2/2)

Using a calculator, we find that θ is approximately 135.0 degrees.

However, we need to ensure that the angle is between 0 and 360 degrees. Since the point lies in the second quadrant (i.e., x < 0 and y > 0), we need to add 180 degrees to the angle we found. This gives:

θ = 135.0 + 180 = 315.0 degrees

The angle of the terminal side through the point p is 315.0 degrees (to the nearest tenth of a degree).

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If The area of a triangle is (27 + 13sqrt(2)) square feet. if the length of the base is (6 + sqrt(2)) feet, then the triangle's height is (27 - 13sqrt(2)) / 17 feet.

We are given the area A and the length of the base b. We can use this information to solve for the height h as follows:

A = (1/2)bh

2A = bh

h = (2A)/b

Substituting the given values, we get:

h = (2(27 + 13sqrt(2))) / (6 + sqrt(2))

We can simplify this expression by rationalizing the denominator as follows:

h = [(2(27 + 13sqrt(2))) / (6 + sqrt(2))] * [(6 - sqrt(2))/(6 - sqrt(2))]

h = [(54 - 26sqrt(2)) / (34)]

h = (27 - 13sqrt(2)) / 17

Therefore, the triangle's height is (27 - 13sqrt(2)) / 17 feet.

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The length of the top of the ladder from the ground is 10m and the distance from wall to the bottom of ladder is 1.5m

Given that an ladder leans against a wall.

We have to find the length of the top of the ladder from the ground.

We know that tan function is the ratio of opposite side and adjacent side

Let x be the opposite side

tan 68 = x/4

2.475 = x/4

x= 4×2.475

x=9.9 m

x=10 m

So, the  length of the top of the ladder from the ground is 10m.

Now let us find the distance from wall to the bottom of ladder

cosine function is the ratio of adjacent side and hypotenuse

Cos 68 = x/4

0.374 =x/4

x=0.374×4

x=1.5m

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The mean of a sample is computed by summing all the data values and dividing the sum by the number of items in the sample. Thus, the correct answer is d.

Option a is incorrect because the mean of a sample is not always equal to the mean of the population, unless the sample is a complete representation of the population (which is often not the case).

Option b is incorrect because the mean of a sample can be greater than, equal to, or smaller than the mean of the population, depending on the sampling method and the characteristics of the population.

Option c is incorrect because the sample mean is computed by summing the data values and dividing the sum by the number of items in the sample minus one only if the sample is taken from a normally distributed population and the standard deviation of the population is unknown. Otherwise, the sample mean is computed by dividing the sum of the data values by the number of items in the sample.

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The possible set of values for a, b, and c could be: a=2, b=4, c=5.

Here is a possible set of values for a, b, and c,

- a = 2 (since there are 7 houses with 1-2 bedrooms and 8 houses in total, we know that there must be at least 1 more house with 1-2 bedrooms, which could be house a)
- b = 4 (since the median number of bedrooms is 3 and there are 7+1+1=9 houses total with either 1, 2, or 3 bedrooms, we know that the median house must have either 3 or 4 bedrooms. Since b must be different from a and c, we can assign it to 4)
- c = 5 (since there are only 3 houses left and we need to assign one to each remaining number of bedrooms, we can assign c to 5)

Therefore, a possible set of values for a, b, and c could be: a=2, b=4, c=5.

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The solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.

To solve this system of linear equations, we can use Gaussian elimination, which involves adding and subtracting equations to eliminate variables. Here are the steps:

x - 3y - 2z = 6

2x - 4y - 3z = 8

-3x + 6y + 8z = -5

Step 1: Add twice the first equation to the second equation to eliminate x:

x - 3y - 2z = 6

4y + z = 20

-3x + 6y + 8z = -5

Step 2: Add three times the first equation to the third equation to eliminate x:

x - 3y - 2z = 6

4y + z = 20

9y + 2z = 13

Step 3: Solve for z in the second equation:

4y + z = 20

z = 20 - 4y

Step 4: Substitute z into the third equation and solve for y:

9y + 2z = 13

9y + 2(20 - 4y) = 13

y = -3

Step 5: Substitute y into the second equation and solve for z:

4y + z = 20

4(-3) + z = 20

z = 8

Step 6: Substitute y and z into the first equation and solve for x:

x - 3y - 2z = 6

x - 3(-3) - 2(8) = 6

x = 1

Therefore, the solution to the system of linear equations is x = 1, y = -3, and z = 8, which is option B: X=-1, y=-3, z=2.

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The text format of the question in the picture:

15. The solution the system of linear equation of

x-3y-2z = 6

2x-4y-3z = 8

(-3x+6y+8z = -5 is

A) X=-1,y=-3, z=-2 B) X=-1,y=-3, z=2 C) X=1,y=-3, z=2 D) X = 1, y = 3, z=-2

The width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

To solve the problem, we can draw a diagram and use the properties of ellipses.

First, we note that the major axis of the ellipse is 110 yards and the minor axis is 50 yards. We can find the distance between the two foci of the ellipse using the formula c^2 = a^2 - b^2, where c is the distance between the foci, and a and b are the lengths of the semi-major and semi-minor axes.

c^2 = 110^2 - 50^2

c^2 = 10800

c ≈ 104.0

Next, we draw the two foci of the ellipse and the rectangle as shown in the diagram below. We are given that the width of the rectangle is 30 yards (15 yards from either vertex). x be the length of the rectangle.

      A          B

   +-------+-------+

  /                  \

 /                    \

/                      \

C                        D

\                      /

 \                    /

  \                  /

   +-------+-------+

      E          F

We can see that the length of the rectangle is equal to the distance between points A and B, and the width of the rectangle is equal to the distance between points C and D. Using the Pythagorean theorem, we can find the length of the rectangle.

AB^2 = AE^2 + EB^2

AB^2 = (a/2)^2 + (c - b/2)^2

AB^2 = (55)^2 + (104 - 15)^2

AB^2 = 3025 + 7225

AB = sqrt(10250)

AB ≈ 101.2

Therefore, the length of the rectangle is approximately 101.2 yards.

To find the width of the rectangle, we can use the fact that the distance between points C and D is equal to twice the distance between the center of the ellipse and the minor axis. The center of the ellipse is the midpoint of the major axis, and the distance from the center to the minor axis is 25 yards.

CD = 2 * 25 = 50

Therefore, the width of the rectangle is approximately 50 yards.

In summary, the width of the rectangular playing field is approximately 50 yards if the width is located 15 yards from either vertex.

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1. The price-demand equation for the trumpets is:

   x = 238.18 - 1.09p

2. The manufacturer should set the price of each trumpet at $296.50  to break even        

3. The manufacturer should set the price of each trumpet at $138.63 to maximize profit.

In this problem, the manufacturer has conducted a customer survey and found out that the price of each trumpet affects the demand for it. We need to analyze this data and come up with a price-demand equation that helps the manufacturer set the price of each trumpet to maximize profit.

To start with, we need to assume a linear model, where the demand for the trumpets is directly proportional to the price. We can represent the demand as "x" and the price as "p". Using the data from the survey, we can form two linear equations:

110 = ap + b     (1)

128 = cp + d    (2)

Here, a, b, c, and d are constants that we need to find. We can solve these equations simultaneously to get the values of a, b, c, and d.

Subtracting equation (2) from equation (1), we get:

-18 = (a-c)p + (b-d)   (3)

Dividing both sides of equation (3) by -18, we get:

p = (d-b)/(c-a)          (4)

Using equation (4), we can find the value of p, which is the price at which the demand for trumpets is equal to the values obtained from the survey. Substituting the values from either equation (1) or (2) into equation (4), we get:

p = ($160.74 x 110 - $220.18 x 128)/(-18 x 110 + 18 x 128)

  = $186.46

Therefore, the price-demand equation for the trumpets is:

x = 238.18 - 1.09p

To answer the second question, we need to find the price of each trumpet at which the manufacturer will break even. In other words, the revenue earned from selling the trumpets should be equal to the total cost incurred in making and selling them.

We know that the one-time cost of buying equipment is $3274.78, and each trumpet costs $90.05 to make. Let's represent the break-even price as "[tex]P_{be}[/tex]". Then we can form the following equation:

110[tex]P_{be}[/tex] = 3274.78 + 110 x 90.05

Solving for [tex]P_{be}[/tex], we get:

[tex]P_{be}[/tex]= $296.50

Therefore, the manufacturer should set the price of each trumpet at $296.50 to break even.

To answer the third question, we need to find the price of each trumpet that maximizes the profit for the manufacturer.

The profit is given by the revenue earned minus the total cost incurred. Let's represent the profit as "P" and the price as "p". Then the profit equation becomes:

P = xp - (3274.78 + 90.05x)

To find the price that maximizes profit, we need to take the derivative of the profit equation with respect to p and equate it to zero.

dP/dp = x - 90.05 = 0

Solving for x, we get:

x = 90.05

Substituting this value of x into the price-demand equation, we get:

p = $138.63

Therefore, the manufacturer should set the price of each trumpet at $138.63 to maximize profit.

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Answer:

To gain our understanding of the plot (13, 10) on graph paper. We need to look at the picture reflecting or "flipping" that point over the x-axis. In this case, it "flips the point down"  the original point was in first quadrant or Quadrant |, the reflected point is in the fourth quadrant of Queadrant ||||.  The x coordinate would stay the same, but the new y coordinate would be the "opposite" sign of the original.  So the reflected point is (13, -10)

Step-by-step explanation:

(x, y) → (x, - y)

Reflection over x-axis for (13,-20) → (13, 20)

Technically some of the explanations is above /\

Thus the answer is, To gain our understanding of the plot (13, 10) on graph paper. We need to look at the picture reflecting or "flipping" that point over the x-axis. In this case, it "flips the point down"  the original point was in first quadrant or Quadrant |, the reflected point is in the fourth quadrant of Queadrant ||||.  The x coordinate would stay the same, but the new y coordinate would be the "opposite" sign of the original.  So the reflected point is (13, -10)

a. The property damage insurance covers the damage to the fence.

b. The insurance company will pay $7,000 - $1,000 = $6,000 for the fence damage.

c. The insurance company will pay $24,000 for the bus damage and $2,100 - $1,000 = $1,100 for the car damage.

d. The collision insurance policy covers the damage to Stewart's car.

e. The insurance company will pay $3,600 - $1,000 + $2,100 - $1,000 = $3,700 for the damage to the car.

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The translation of the graph from y = x² to y = (x - 2)² +1 is describe by - B.   shift of 2 units left and then shift of 1 unit up.

In geometry, a translation is a transfer that occurs either horizontally to a left or right as well as vertically up or down. It may also consist of a mix of the two.

Given data:

Parent function- y = x²

New function -  y = (x - 2)² +1

Thus, the translation of the graph from y = x² to y = (x - 2)² +1 is describe by - B.   shift of 2 units left and then shift of 1 unit up.

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Complete question:

1. Which of the following most accurately describes the translation of the graph from y = x² to y = (x - 2)² +1?

A.  shift of 2 units right and then shift of 1 unit up.

B.   shift of 2 units left and then shift of 1 unit up.

Dexter has a better chance of winning in the long run with an expected value of $4/3 per game, while Thanh has an expected loss of $1/3 per game.

This is a game of probability that involves calculating expected values. Let's first calculate the probability of drawing a black chip:

Probability of drawing a black chip = (number of black chips) / (total number of chips) = 10 / 15 = 2/3

Similarly, the probability of drawing a white chip can be calculated as:

Probability of drawing a white chip = (number of white chips) / (total number of chips) = 5 / 15 = 1/3

Now, we can calculate the expected value of winning for each player.

For Dexter:

- If he draws a black chip, he will win $7 with probability 2/3

- If he draws a white chip, he will lose $10 with probability 1/3

Expected value of winning for Dexter = (7 x 2/3) + (-10 x 1/3) = 4/3

This means that on average, Dexter will win $4/3 per game.

For Thanh:

- If Dexter draws a black chip, Thanh will lose $7 with probability 2/3

- If Dexter draws a white chip, Thanh will win $10 with probability 1/3

Expected value of winning for Thanh = (-7 x 2/3) + (10 x 1/3) = 1/3

This means that on average, Thanh will win $1/3 per game.

So, based on these calculations, Dexter has a better chance of winning in the long run with an expected value of $4/3 per game, while Thanh has an expected loss of $1/3 per game.

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The probability of 3 rainy days in a row when the probability of rain on each single day is 56% ≈ 17.6%

The probability of 3 sunny days in a row when the probability of rain on each single day is 56% ≈ 8.5%

To determine the probability of 3 rainy days in a row, you need to multiply the probability of rain on each single day (56%). In percent form, this would be:

56% × 56% × 56% = 0.56 × 0.56 × 0.56 ≈ 0.175616

To express this as a percentage rounded to the nearest tenth, we have:

0.175616 × 100% ≈ 17.6%

Now, to determine the probability of 3 sunny days in a row, you first need to find the probability of a sunny day, which is the complement of the probability of rain:

100% - 56% = 44%

Next, multiply the probability of a sunny day (44%) for three days:

44% × 44% × 44% = 0.44 × 0.44 × 0.44 ≈ 0.085184

To express this as a percentage rounded to the nearest tenth, we have:

0.085184 × 100% ≈ 8.5%

So, the probability of 3 rainy days in a row is approximately 17.6%, and the probability of 3 sunny days in a row is approximately 8.5%.

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Answer:2,2

Step-by-step explanation:

The four ordered pairs relating the side length and the corresponding perimeter are (3,20), (4,24), (5,28), and (6,32).

The rule "Add 2" to the side length of a square means that if the original side length is x, the new side length will be x+2.

The rule "Add 8" to the square's perimeter means that if the original perimeter is 4x (since a square has four equal sides), the new perimeter will be 4(x+2), which simplifies to 4x+8.

To find four ordered pairs relating the side length and corresponding perimeter, we can plug in different values for x and use the above formulas to calculate the corresponding perimeters. For example, if we choose x=3, the new side length will be 3+2=5, and the new perimeter will be 4(3+2)=20. So, one ordered pair would be (3,20).

Similarly, if we choose x=4, the new side length will be 4+2=6, and the new perimeter will be 4(4+2)=24. So, another ordered pair would be (4,24).

By choosing different values for x, we can find four ordered pairs that relate the side length and corresponding perimeter. These ordered pairs are (3,20), (4,24), (5,28), and (6,32).

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The probability of the die landing on a vowel is 1 in 5, or 20%.

In this game, the 20-sided die has the letters A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, R, S, T, and W. To calculate the probability of the die landing on a vowel, we need to identify the vowels present on the die and then determine the probability.

The vowels on this die are A, E, I, and O. There are 4 vowels out of the 20 possible outcomes, so the probability of landing on a vowel can be calculated by dividing the number of successful outcomes (vowels) by the total number of possible outcomes (20 sides).

Probability = (Number of Vowels) / (Total Sides)
Probability = 4 / 20

Now, simplify the fraction:

Probability = 1 / 5

The probability of the die landing on a vowel is 1 in 5, or 20%.

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Here are the base five numerals from 1 to 100

1, 2, 3, 4, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32, 33, 34, 40, 41, 42, 43, 44, 100.

With the base five, every number can only take on the values of 0, 1, 2, 3, or 4.

After the number 4, we carry over to the following place value and start again with 0. So, for instance, the number after 4 in base five is 10, because we've carried over to the next place value and started with 0 again.

In this way, we can count all the way up to 100 in base five, using these 25 unique numerals.

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Out of 25 students in the class, 40% are male is: Descriptive statistics.

Descriptive statistics is the process of summarizing and organizing data from a sample or population in order to provide an overview of the main characteristics. In this case, the data provided tells us that out of 25 students in the class, 40% are male.

This information is a summary of the gender distribution within this specific class, rather than making any predictions or generalizations about a larger population.

In contrast, inferential statistics is the process of using data from a sample to make predictions or draw conclusions about a larger population. If we were given data about a sample of classes and asked to estimate the proportion of male students in all classes, that would be an example of inferential statistics.

To summarize, the situation you provided, which states that out of 25 students in the class, 40% are male, is an example of descriptive statistics as it only provides a summary of the data for that specific class.

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The dimensions of the poster with an area of 392 square inches is equal to 14 inches and 28 inches.

Area of rectangular poster to print = 392 square inches

Let us assume that dimensions of the posters are,

Width of the poster is x inches and the length of the poster is y inches.

Area of the rectangular poster is,

xy = 392

Add 2 inches to the top and bottom margins for a total of 4 inches

And 1 inch to the left and right margins for a total of 2 inches.

Total area of the poster including the margins using the following equation,

Total area = (x + 2) × (y + 4)

Minimize the total area of the poster while still satisfying the area constraint.

Use the first equation to solve for one variable

And substitute it into the second equation,

y = 392/x

Total area = (x + 2) × (392/x + 4)

⇒ Total area = 4x + 392 +784/x + 8

⇒Total area = 4x + 400 +784/x

Minimize the total area, take the derivative of this expression with respect to x and set it equal to 0,

d/dx (4x + 400 +784/x ) = 0

⇒  4 + 0 - 784/x² = 0

⇒ x² = 784 /4

⇒ x = 14

Substituting this value of x back into the equation for y, we get,

y = 392/14

  = 28

Therefore, the dimensions of the poster should be 14 inches by 28 inches.

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Willka would need approximately 0.2222 L of paint to cover 1 m² and approximately 2.2222 L of paint to cover 10 m².

Willka can cover 13.5 m² with 3 liters of paint. To find equivalent ratios, we can determine how much paint is needed to cover 1 m² and then use that to find how much paint is required for other areas.

To find the amount of paint needed for 1 m², divide the area covered by the paint used:
1 m² = (13.5 m²)/(3 L) = 4.5 m²/L

Now, we can use this ratio to complete the table:

Area covered (m²) - Paint (L)
13.5               - 3
1                  - (1/4.5) = 0.2222 L (approximately)
10                 - (10/4.5) = 2.2222 L (approximately)

So, the completed table is:

Area covered (m²) - Paint (L)
13.5               - 3
1                  - 0.2222
10                 - 2.2222

Using equivalent ratios, Willka would need approximately 0.2222 L of paint to cover 1 m² and approximately 2.2222 L of paint to cover 10 m².

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The value of the double integral is zero.

The order of integration is dr dy, which means we first integrate with respect to r and then with respect to y.

Thus, we can write the integral as:

[tex]\int^0_{2\pi} \int^0_{1 + cos(a)}[/tex] r sin(θ) dr dy

Here, we have used the given limits of integration for r and y. Now, we integrate with respect to r first, treating y as a constant.

∫r sin(θ) dr = -cos(θ)r

We can substitute the limits of integration for r, which gives:

-cos(θ)(1+cos(a)) + cos(θ)(0)

Simplifying this expression, we get:

-cos(θ)(1+cos(a))

Now, we integrate this expression with respect to y, using the limits 0 to 2π for θ.

[tex]\int ^0_{2\pi}[/tex] -cos(θ)(1+cos(a)) dy

We can integrate this expression by treating cos(a) as a constant and using the formula for integrating cosine functions:

Integral of cos(x) dx = sin(x) + C

Thus, we have:

(1+cos(a)) Integral from 0 to 2π of cos(θ) dy

= - (1+cos(a)) [sin(2π) - sin(0)]

= 0

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