please narrate every step you make and make a 2 column proof!

thank you!!

Please Narrate Every Step You Make And Make A 2 Column Proof!thank You!!

Answers

Answer 1

Hang on ,it is already proven through given .

So The proof is of one line only

ray FEH bisects <DFG (Given)

Hence proved .


Related Questions

if(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​

Answers

Answer:

a = 4/3 and b = 0

============================

Given expression:

[tex]\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}[/tex]

Simplify it in steps:

Step 1

Bring both fractions into common denominator:

[tex]\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}[/tex]

Step 2

Simplify:

[tex]\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]

[tex]\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]

[tex]\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]

[tex]\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =[/tex]

[tex]\dfrac{4\sqrt{14} }{7-4} =[/tex]

[tex]\dfrac{4}{3} \sqrt{14} }[/tex]

Step 3

Compare the result with given expression to get:

a = 4/3 and b = 0

Divide: 1,485 ÷ 0.09

1,485 ÷ 0.09

Answers

Answer:

16500

Step-by-step explanation:

16,500 is the correct answer

The standard form of an absolute value function is f(x)-a|x-h|+k. Which of the following represents the vertex?
(-k.h)
(-h.k)
(k,b)
(h,k)

Answers

Answer:

(h, k )

Step-by-step explanation:

given the standard form of an absolute function

f(x) = a| x - h | + k , then

vertex = (h, k )

The standard form of an absolute value function is f(x) = a|x - h| + k, where (h,k) is the vertex of the absolute value function.

The correct option is (h,k).

What is a function?

The term "function" refers to a relationship between a set of inputs and outputs. Just one output is connected to each input in a function, which connects inputs in that manner. Every function has a domain, co-domain, and range.

In general, the standard form of an absolute value function is given as:

f(x) = a |x - h| + k

where:

a is a non-negative constant that determines the shape and direction of the V-shaped graph of the absolute value function

h is the horizontal shift of the graph of the function from the origin (if h > 0, the graph shifts to the right; if h < 0, the graph shifts to the left)

k is the vertical shift of the graph of the function from the origin (if k > 0, the graph shifts up; if k < 0, the graph shifts down)

The vertex of the absolute value function is the point where the graph changes direction, that is, the point where the graph changes from sloping downwards to sloping upwards or vice versa.

Since the vertex is the point of the absolute value function where the graph changes direction, it lies at the center of the V-shaped graph. Thus, the vertex is located at the point (h,k).

Therefore, in the standard form f(x) = a |x - h| + k, (h,k) represents the coordinates of the vertex of the absolute value function.

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The function y=x²-4x+8 approximates the height, y, of a bird, and its horizontal distance, x, as it flies from one
fence post to another. All distances are in feet. Complete the square to find and interpret the extreme value
(vertex).
Select two answers: one extreme value and one interpretation.
Height (feet)
Distance (feet)
A. When the bird is 4 feet away from the first fence post, it reaches its minimum height of 8 feet.
B. Minimum at (4,8)
C. When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet.
D. Minimum at (2,4)

Answers

When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet  , Minimum at (2,4)

Therefore Option C and D is the correct answer.

What is a Quadratic Function?

The equation for a quadratic function is given by

y = a(x-h)² +k²

where (h,k) is the extreme value(vertex).

Here the equation given is

y = x²-4x +8

y = x²-4x+4+4

y = (x-2)² +4

Here the value of a = 1 , h = 2 and k = 4

The extreme value is at (2,4)

Therefore When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet  , Minimum at (2,4)

Therefore Option C and D is the correct answer.

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Y=-5x +6 Y= 3x -2 Find the solution to the system of equations
X = _____
Y= _____

Answers

Answer:

x=1, y=1. (1, 1).

Step-by-step explanation:

y=-5x+6

y=3x-2

------------

-5x+6=3x-2

-5x-3x+6=-2

-8x+6=-2

-8x=-2-6

-8x=-8

8x=8

x=8/8=1

y=3(1)-2=3-2=1

Squares are cut out of the corners of a piece of 18*18 graph paper so that the sides can be folded to make an open box. What is the largest possible number of cubic units in the volume of the box if we require that the length of each edge is a whole number?

Answers

Answer:

432 mm²

Step-by-step explanation:

We need to cut out 3x3 squares from corners and make an open box. It's height will be 3mm(see the plan). So volume will be:
V = 12 * 12 * 3 = 432mm²

12. Last month, a store sold a total of 182 pairs of jeans and shorts. The
number of shorts sold was 28 fewer than twice the number of jeans sold.
How many pairs of jeans were sold?
C. 105
A 51
D. 112
B. 70

Answers

Answer:

B. 70

Explanation:

A total of 182 pairs of jeans and shorts were sold and the number of shorts sold was 28 fewer than twice the number of jeans. This can be expressed with j being the number of jeans as:

j2 - 28 = number of shorts

As the number of shorts is 28 lower than twice the number of jeans, this means it can not be C or D, as these numbers are larger than 182 when doubled. The process of elimination can be done with the remaining using our equation.

51(2) - 28 = 102 - 28 = 74
70(2) - 28 = 140 - 28 = 112

Now that we have the number of shorts sold by using the equation, we can add them with what number was used as their number of jeans.

74 + 51 = 125
112 + 70 = 182

So the number of jeans sold is B. 70.



On a coordinate plane, a circle has a center at (0, 0). Point (3, 0) lies on the circle.
Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot

Does the point (2, StartRoot 6 EndRoot) lie on the circle shown? Explain.

Yes, the distance from (3, 0) to (0, 0) is 3 units.
Yes, the distance from (0, 0) to (2, StartRoot 6 EndRoot) is 3 units.
No, the distance from (3, 0) to (2, StartRoot 6 EndRoot) is not 3 units.
No, the distance from (0, 0) to (2, StartRoot 6 EndRoot) is not 3 units.

Answers

Answer: Option (4)

Step-by-step explanation:

We know that the radius of the circle is 3.

Using the distance formula, the distance from the given point to the center is

[tex]\sqrt{(\sqrt{6}-0)^{2}+(2-0)^{2}} = \sqrt{10} \neq 3[/tex]

Answer:d

Step-by-step explanation:

Teresa is factoring this polynomial by grouping. Which common factors should be used in the next step of factoring?

10x3+3x2−20x−6

(10x3+3x2)+(−20x−6)

x2 and −2x
2x2 and −2x
x2 and −2
2x2 and −2

Answers

Answer:  [tex]x^2[/tex]  and  [tex]-2[/tex]

Step-by-step explanation:

original :

[tex](10x^3+3x^2)+(-20x-6)[/tex]

factored :

[tex]x^2(10x+3)+-2(10x+3)[/tex]

Answer :

[tex]x^2[/tex]  and  [tex]-2[/tex]

If f(x) = -3 and g(x) = 4x² + x − 4, find (ƒ+ g)(x).

Answers

Answer:

4x² + x - 7

Step-by-step explanation:

Given f(x) = -3 and g(x) = 4x² + x - 4, solve for (f + g)(x).

Step 1: Replace the function designators with the actual functions in f(x) and g(x); that gives us 4x² + x - 4 - 3.

Step 2: Simplify; that gives us the answer 4x² + x - 7.

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Mary is running a marathon which is a total of 26 miles. She is running at a pace of 7.5 miles per hour and
has already run 8 miles. If she stays at the same pace, how much time in hours does she have left? (Round your answer to the nearest tenth)

Answers

Answer: 2.4 hours

===================================================

Explanation:

She has already ran 8 miles, so she has 26-8 = 18 miles left to go.

She runs at a pace of 7.5 mph, which means she has 18/(7.5) = 2.4 hours left to go.

I used the equation distance = rate*time, and solved for time to get time = distance/rate.

--------------------

Another approach:

Here's how you can use algebra.

x = time she has left in hours

7.5x = distance covered in those x hours

7.5x+8 = total distance

7.5x+8 = 26

7.5x = 26-8

7.5x = 18

x = 18/(7.5)

x = 2.4

Point T is located at (6, –2) and point S is located at (1, 13). What are the coordinates of the point that is `\frac{4}{5}` of the way from T to S?

Answers

The coordinates of the point that is 4/5 of the way from T to S is (2,10)

How to determine the coordinates of the point?

The given parameters are:

T = (6,-2)

S = (1,13)

Location = 4/5

The location 4/5 means

Ratio, m : n = 4 : 1

The coordinate is then calculated as:

[tex](x,y) = \frac{1}{m +n} * (mx_2 + nx_1,my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{4 +1} * (4 * 1 + 1 * 6 , 4 * 13 + 1 * -2)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (10 , 50)[/tex]

This gives

(x,y) =  (2,10)

Hence, the coordinates of the point that is 4/5 of the way from T to S is (2,10)

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Factor the expression below.
36x² - 49
A. (6x + 7)(6x - 7)
B. (4x-7)(9x - 7)
C. (4x+7) (9x-7)
D. (6x-7)(6x-7)

Answers

Answer:

A. (6x + 7)(6x - 7)

Step-by-step explanation:

use difference of squares, which says a^2 - b^2 =(a+b)(a-b)

take the square roots of the two numbers, 6x and 7, and use them as a and b



It’s 12 points if you help me thank you :)

Answers

Based on the calculations, Celine would earn a total of $65.00 assuming she delivered 10 packages.

What is a function?

A function can be defined as a mathematical expression which is used to define and represent the relationship that exists between two or more variable.

Given the following function:

y = 20.00 + 0.45(x)

In this exercise, you're required to determine Celine's weekly earnings based on the number of packages she delivered. However, the number of packages delivered by Celine wasn't shown, thus, we would assume a value for the purpose of an explanation:

Assuming x = 10 packages.

Substituting the value of x into the function, we have:

y = 20.00 + 0.45(10)

y = 20.00 + 45

y = $65.00.

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Solve the following system of equations. (Hint: Use the quadratic formula.)
f(x)=2x^(2)-3x-10
g(x)=-3x^(2)+20

Answers

The solutions to the system of equation f(x) and g(x) are [tex]\frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex] and

[tex]\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]

Solving quadratic equations

Quadratic equations are equations that has a leading degree of 2. Given the following functions:

f(x)=2x^(2)-3x-10

g(x)=-3x^(2)+20

To solve, we will use the quadratic formula as shown below;

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

For the quadratic equation f(x)=2x^(2)-3x-10

a = 2

b = -3

c = -10

Substitute

[tex]x=\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(-10)}}{2(2)}\\x=\frac{3\pm\sqrt{89}}{4}\\x= \frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex]

For the quadratic equation -3x² + 20

a =-3

b = 0

c = 20

[tex]x=\frac{0\pm \sqrt{(0)^2-4(-3)(20)}}{2(-3)}\\x=\frac{\pm4\sqrt{15}}{-6}\\x=\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Answers

Answer:

Hey there : y= 3x - 3

Answer:

y = [tex]\frac{3}{2}[/tex] x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line

What is the value of x

Enter your answer in the box

X=_

Answers

Answer:

25

Step-by-step explanation:

This is an equilateral triangle so all of its angle measures, and side lengths likewise, are equal.

To find x we can use the following equation:

3x - 5 = 2x + 20 export like terms to the same side of the equation

3x - 2x = 20 + 5 (notice how terms change from "+" to "-" and vice versa)

add/subtract like terms

x = 25

After covering 4/5 of the journey, James found that he has traveled 48 km. How much of the journey is still left?

Answers

Answer:

12 km

Step-by-step explanation:

Let the total distance to be traveled = x

[tex]\sf \dfrac{4}{5} \ of \ the \ journey = 48\\\\[/tex]

        [tex]\sf \dfrac{4}{5}*x = 48\\\\[/tex]

             [tex]x = 48*\dfrac{5}{4}[/tex]

                = 12 * 5

            x = 60 Km

Distance still to traveled = 60 - 48 = 12Km

Help would be appreciated

Answers

Answer:

625 × 48 = 30,000

[tex]\sqrt[4]{30000} = 10 \sqrt[4]{3} [/tex]

answer = third option

Please Help! What is the value of x?

Answers

Answer:

4.1968

Explanation:

Given that:

angle: 25°

opposite: x

adjacent: 9

So, use the tan rule:

opposite/adjacent = tan(x)

x/9 = tan(25)

x = 9tan(25)

x = 4.1968

tanØ=Perpendicular/Basetan25=x/9x=9tan25x=4.1968

Option A

how to solve this???​

Answers

Step-by-step explanation:

[tex]\large\sf{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large \sf{=\frac{\left(\sqrt{1+sin\theta}\right)^{2}+\left(\sqrt{1-sin\theta}\right)^{2}}{\sqrt{(1-sin\theta)(1+sin\theta)}}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{=\frac{1-sin\theta+1+sin\theta}{\sqrt{1^{2}-sin^{2}\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large \sf{=\frac{2}{\sqrt{cos^{2}\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{= \frac{2}{cos\theta}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{= 2sec\theta}[/tex]

[tex]\\[/tex]

[tex]\large\sf{=RHS}[/tex]

Therefore,

[tex]\large\sf\red{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}=2sec\theta}[/tex]

x2 - x - 42
a=?
b=?
C=?



help me ​

Answers

Step-by-step explanation:

thr standard form for a quadratic equation is:

ax²+bx+c

in this example, a=1, b=(-1), c=(-42)

square root of 342354456​

Answers

Answer:

18502.8229198

Answer:

18502.82292

Step-by-step explanation:

calculator

Someone please help!!

Answers

Answer:

I believe the answer would be option D

Step-by-step explanation:

the distance formula is

[tex] \sqrt{(x - x1)^{2} + (y - y1)^{2} } [/tex]

So, substituting the values of the coordinates, you will get the answer of D

It’s 12 points thank you

Answers

The value of y when x is equal to zero will be 330.

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

The given function is;

y = 330 + 25x

We have to find the value of y when x is equal to zero.

So,

Put x = 0

y = 330 + 25x

y = 330 + 25(0)

y = 330

Hence, the value of y when x is equal to zero will be 330.

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A business rents cars for $100 a day and vans for $200 a day. One day, it rented a total of 22 vehicles
and made a total of $2900. What is a possible number of cars and vans it rented that day?

Answers

Answer:

Vans - 7

Cars - 15

Step-by-step explanation:

$200 * 7 = $1400

$100 * 15 = $1500

$1400 + $1500 = $2900

What is the distance from -5 to 0?
0, because 151=0
O 5, because 1-51=5
O5, because 1-51=-5
O-5, because 1-51 = -5
7 of 23 QUESTIONS
SUBMIT

Answers

Answer:

distance between -5 to 0 = 5 units

80
Select the correct answer.
4
What is the solution to the equation?
5√x + 7 = -2
OA -39
OB. -17
OC 25
OD. no solution

Answers

Answer:

38 is the correct solution

Kyla has the number of cherries that Denise has. If Kyla has 46 cherries, how many cherries do they have altogether?​

Answers

Answer:

92

Step-by-step explanation:

46 + 46 = 92

Answer: 92
Explanation:
46+46=92

What was the problem at kenya airways described in this case? what management, organization, and technology factors contributed to this problem?

Answers

The management, organisation, and technology factors contributed to this problem are listed below.

What was the problem at Kenya Airways ?

The  problem in the airways was that corporation didn't know its customers, the airline hasn't been able to take use of its market opportunity in recent years.

Airways was unable to evaluate and keep track of its marketing efforts.

The technology factor that contributed were:

No reliable systems for tracking and accounting.The technology used was neither accurate nor consistent.

The Organisation factors that contributed were

No communication between the organisation and the customersNo track record of the online campaigns and advertisement output Customer Relations Needed to be improved.

The Management factors that contributed were

The management never gave reviews to the organisation about the failing system The management even didn't take reviews from the customers and from the people working.

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