Answer:
3(x - 2)(2x + 3)
Step-by-step explanation:
6x² - 3x - 18 ← factor out GCF of 3 from each term
= 3(2x² - x - 6) ← factor the quadratic
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 6 = - 12 and sum = - 1
the factors are - 4 and + 3
use these factors to split the x- term
2x² - 4x + 3x - 6 ( factor the first/second and third/fourth terms )
= 2x(x - 2) + 3(x - 2) ← factor out (x - 2) from each term
= (x - 2)(2x + 3) ← in factored form
then
6x² - 3x - 18 = 3(x - 2)(2x + 3)
Center: (2, 8) radius: 3
What is the equation of a circle with the center and radius given?
Marcus is responsible for maintaining the swimming pool in his community. He adds chemicals, when needed, to lower the pH of the pool.
-The maximum pH value allowed for the pool is 7. 8.
-The pool currently has a pH value of 6. 9.
-The pH value of the pool increases by 0. 05 per hour.
Write an inequality that can be used to determine x, the number of hours before Marcus will need to add chemicals to maintain the pH for the pool
An inequality that can be used to determine x, the number of hours before Marcus will need to add chemicals to maintain the pH for the pool would be 6.9 + 0.05x ≤ 7.8
To determine the number of hours (x) before Marcus will need to add chemicals to maintain the pool's pH, we can use an inequality with the given information.
-The maximum pH value allowed for the pool is 7.8.
-The pool currently has a pH value of 6.9.
-The pH value of the pool increases by 0.05 per hour.
The inequality for this scenario would be:
6.9 + 0.05x ≤ 7.8
This inequality states that the current pH value (6.9) plus the increase in pH per hour (0.05x) should be less than or equal to the maximum allowed pH value (7.8). This will help us determine the number of hours (x) before Marcus needs to add chemicals to maintain the pH for the pool.
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8-70. Assume Figure A and Figure B, at right, are similar. Homework Help
a. If the ratio of similarity is (3)/(4), then what is the ratio of the perimeters of Figures A and B ?
b. If the perimeter of Figure A is p and the linear scale factor is r, what is the perimeter of Figure B?
c. If the area of Figure A is a and the linear scale factor is r, what is the area of Figure B?
a. The ratio of the perimeters of Figures A and B will also be (3)÷(4).
b. This is because the corresponding sides of Figure B are (3÷4) is smaller than those of Figure A, and the perimeter is the sum of all the sides.
c. The area of Figure B will be (9÷16)a.
What is perimeter ?Perimeter refers to the total length of the boundary or the outer edge of a two-dimensional closed shape. It is the sum of the lengths of all sides of the shape.
a. Since the ratio of similarity is (3)÷(4), this means that the corresponding sides of Figure A and Figure B are in the ratio of (3)÷(4). Therefore, the ratio of the perimeters of Figures A and B will also be (3)÷(4).
b. If the perimeter of Figure A is p and the linear scale factor is r, then the perimeter of Figure B will be (3÷4)p. This is because the corresponding sides of Figure B are (3÷4) is smaller than those of Figure A, and the perimeter is the sum of all the sides.
c. If the area of Figure A is a and the linear scale factor is r, then the area of Figure B will be (3÷4) square times smaller than that of Figure A. This is because the area of a similar figure proportional to the square of the linear scale factor.
Therefore, the area of Figure B will be (9÷16)a.
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Which expression is represented by the number line?
A number line going from negative 4 to positive 4. An arrow goes from negative 2. 5 to negative 1, from 0 to 3, and from 3 to negative 2. 5
The expression represented by the given number line is f(x) = -k(x+2.5)(x-3) where k > 0.
The expression represented by the given number line can be determined by identifying the values that correspond to the endpoints of each arrow and the direction of the arrow.
Starting from the left endpoint, the arrow goes from -2.5 to -1. This means that the expression is positive between -2.5 and -1. To determine the exact expression, we need to know the interval of the arrow.
The arrow starts at 0 and ends at 3, which means the expression is positive between 0 and 3. Finally, the arrow goes from 3 to -2.5, which means the expression is negative between 3 and -2.5.
Putting all of this information together, we can write the expression as:
f(x) = k(x+2.5)(x-3)
where k is a constant that determines the overall scale of the expression. Since the expression is positive between -2.5 and -1, we know that k must be negative. Since the expression is negative between 3 and -2.5, we know that k must be positive.
Therefore, the expression represented by the given number line is:
f(x) = -k(x+2.5)(x-3) where k > 0.
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White shapes are black shapes are used in a game.
Some of the shapes are circles.
All the other shapes are squares.
The ratio of the number of white shapes to the number of black shapes is 7:3
The ratio of the number of white circles to the number of white squares is 2:7
The ratio of the number of black circles to the number of black squares is 1:2
Work out what fraction of all the shapes are circles.
Give your answer as a fraction in its simplest form.
The radius of a circle measures 7 inches. A central angle of the circle measuring 4π15 radians cuts off a sector.
What is the area of the sector?
Enter your answer, as a simplified fraction
The area of sector is 14π/3 square inches for a circle having a radius of 7 inches and measures an angle of 4π/15 radians.
Radius of circle = 7 inches
Angle of circle = 4π/15 radians
The area of a sector of a circle can be calculated by using the formula:
A = (θ/2) × [tex]r^2[/tex]
A = The area of the sector
θ = central angle in radians
r = radius of the circle.
Substituting the given values in the formula:
Area = (θ/2) × [tex]r^2[/tex]
Area = (4π/15 × 1/2) × [tex]7^2[/tex]
Area= (2π/15) × 49
Area = 14π/3
Therefore, we can conclude that the area of the sector is 14π/3 square inches.
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La o florarie s-au adus ghivece de flori.in prima zi s-a vandut 1 supra 2 din numarul ghivecelor,a doua zi 1 supra 4 din numarul ramas si inca 7 ghivece iar a treia zi restul de 20 de ghivece.cate ghivece s-au vandut in fiecare zi si cate sau adus initial la florarie
S-au adus initial 68 de ghivece de flori, iar în fiecare zi s-au vândut, respectiv, 34, 17 și 17 ghivece.
Initial, la florărie s-au adus x ghivece de flori. În prima zi s-au vândut 1/2 * x ghivece. A doua zi, din numărul rămas s-au vândut 1/4 * (x - 1/2 * x) ghivece, adică 1/4 * 1/2 * x.
În plus față de acestea, s-au vândut încă 7 ghivece, deci în total în a doua zi s-au vândut 1/4 * 1/2 * x + 7 ghivece. În a treia zi s-au vândut restul de 20 de ghivece, deci numărul rămas la finalul celei de-a doua zile este x - 1/2 * x - 1/4 * 1/2 * x - 7. Trebuie să fie egal cu 20, deci avem ecuația x - 1/2 * x - 1/4 * 1/2 * x - 7 = 20.
Rezolvând această ecuație, obținem x = 128. Prin urmare, în prima zi s-au vândut 1/2 * 128 = 64 ghivece, în a doua zi s-au vândut 1/4 * 1/2 * 128 + 7 = 15 ghivece, iar în a treia zi s-au vândut restul, adică 20 ghivece.
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Homework
Saved
Quail Company is considering buying a food truck that will yield net cash inflows of $11,000 per year for seven years. The truck costs
$45,000 and has an estimated $6,700 salvage value at the end of the seventh year. (PV of $1, FV of $1. PVA of $1, and FVA of $1) (Use
appropriate factor(s) from the tables provided. Enter negative net present values, if any, as negative values. Round your present
value factor to 4 decimals. )
What is the net present value of this investment assuming a required 8% return?
Net Cash Flows x PV Factor
$
Years 1-7
'Year 7 salvage
Totals
11,000
6,700
Present Value of
Net Cash Flows
$
0
3,909
$
0. 58351 =
11
Initial investment
45,000
Net present value
The net present value of this investment, assuming a required 8% return, is approximately $13,829.
To calculate the net present value (NPV) of this investment, we'll first find the present value of the net cash flows and the salvage value, then subtract the initial investment.
For the net cash flows, we'll use the Present Value of Annuity (PVA) formula:
PVA = Net Cash Flow * [(1 - (1 + r)^(-n)) / r]
Where:
- Net Cash Flow is $11,000
- r is the required return (0.08)
- n is the number of years (7)
PVA = 11,000 * [(1 - (1 + 0.08)^(-7)) / 0.08]
PVA = 11,000 * 4.99271
PVA ≈ $54,920
Next, we'll find the present value of the salvage value at the end of year 7:
PV_salvage = Salvage Value / (1 + r)^n
PV_salvage = 6,700 / (1 + 0.08)^7
PV_salvage ≈ $3,909
Now, we can calculate the NPV by adding the present values and subtracting the initial investment:
NPV = (PVA + PV_salvage) - Initial Investment
NPV = (54,920 + 3,909) - 45,000
NPV ≈ $13,829
The net present value of this investment, assuming a required 8% return, is approximately $13,829.
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Fernando fue a comprar entradas para que él y
sus 7 amigos asistan a la Expo-Loncoche que
se realiza en La ciudad del mismo nombre.
Entre todos lograron reunir $14. 000, pero cada
entrada cuesta $ 3. 600 ¿Cuánto dinero le falta
a cada uno para comprar las entradas?
After evaluation each person is missing $1400 to purchase the tickets to enter the Expo-Loncoche that takes place in the city.
Then, the count of individuals multiplied by the price per ticket yields the total cost of the tickets. So we have to apply principles of algebraic expression.
Now, in order to solve the problem, we can first find the total cost of tickets, which is $25,200
(7 friends + Fernando = 8 people × $3,600 = $28,800).
The whole cost can then be deducted from the total amount raised,
$14,000 - $25,200 = -$11,200.
Therefore, they are short $11,200 in total.
Finally, we have to divide that sum by the required number of tickets, which is 8,
-$11,200 8 = -$1,400.
Hence, each person needs an additional $1,400 to buy tickets.
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The Complete question - Fernando went to buy tickets so that he and his 7 friends attend the Expo-Loncoche that takes place in the city of the same name. Together they managed to raise $14,000, but each the entrance costs $3,600. How much money is missing each to buy tickets?
Let f(x)= -2x+4 and g(x)= 3x^2. Find (f+g)(x) and (f-g)(x)
State the domain of each.
Evaluate the following: (f+g)(-3) and (f-g)(-3)
The scope of both functions is all real numbers.
How to solveTo compute the values of (f+g)(x) and (f-g)(x), we apply the addition and subtraction of two distinct functions, respectively:
(f+g)(x) = f(x) + g(x) = [tex](-2x + 4) + (3x^2) = 3x^2 - 2x + 4[/tex]
(f-g)(x) = f(x) - g(x) = [tex](-2x + 4) - (3x^2) = -3x^2 - 2x + 4[/tex]
The scope of both functions is all real numbers.
Subsequently, we evaluate the expressions for x = -3:
(f+g)(-3) = [tex]3(-3)^2 - 2(-3) + 4[/tex] = 3(9) + 6 + 4 = 27 +6 +4 = 37
(f-g)(-3) = [tex]-3(-3)^2 - 2(-3) + 4[/tex]= -3(9) + 6 + 4 = -27 + 6 + 4 = -17
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What is the radius of a hemisphere with a volume of 324 ft³, to the nearest tenth of a
foot?
SOND
Answer:the radius of the hemisphere with a volume of 324 ft³ is approximately 6.3 feet (to the nearest tenth).
Step-by-step explanation:
The formula for the volume of a hemisphere is:
V = (2/3) × π × r³, where V is the volume and r is the radius of the hemisphere.
We have been given the volume of the hemisphere as 324 ft³, so we can substitute this into the formula:324 = (2/3) × π × r³
To find the radius r, we need to solve for it. Dividing both sides by (2/3) × π gives:r³ = (324 / ((2/3) × π))r³ = (324 × 3) / (2 × π)r³ = 486 / π
Taking the cube root of both sides gives:r = (486 / π)^(1/3)
Using a calculator to evaluate this expression, we get:r ≈ 6.3
Sorry if the photo is sideways, can someone please help me
The length of AB is approximately 12.704 units.
How to find the length?To solve this problem, we can use trigonometry and the fact that the easel forms a 30° angle to find the length of AB.
According to given information:We know that RC is 22, and that angle R is 30°. Let's use the trigonometric function tangent to find AB:
tan(30°) = AB / RC
We can rearrange this equation to solve for AB:
AB = tan(30°) * RC
Using a calculator or trigonometric table, we find that tan(30°) = 0.5774 (rounded to four decimal places). Therefore:
AB = 0.5774 * 22
AB ≈ 12.704
So the length of AB is approximately 12.704 units.
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And 7/8 hours Greg reads 2/3 chapters what’s the unit rate in chapters per hour?
The unit rate in chapters per hour is 21/16 hours
How to calculate the unit rate?Greg read 7/8 hours in 2/3 chapter
The unit rate can be calculated as follows
7/8= 2/3
1= x
cross multiply both sides
2/3x= 7/8
x= 7/8 ÷ 2/3
x= 7/8 × 3/2
x= 21/16
Hence 21/16 chapters is read in one hour
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A random sample of 40 students from each grade level was surveyed regarding their preference for a class field trip. If there are 220 members of the 7th grade class, then how many students can be expected to prefer the zoo?
Answer:
Step-by-step explanation:
We can set up the proportion (20/40) = (x/220), where x is the number of students in the 7th grade class who prefer the zoo. Cross-multiplying this proportion gives us 40x = 20*220, which simplifies to x = 110.
Therefore, we can expect that 110 students in the 7th grade class prefer the zoo.
To explain this solution in more detail, we can use the concept of proportionality. In statistics, when we take a random sample from a larger population, we can use the proportion of the sample to estimate the proportion of the population.
If we assume that the sample is representative of the population, then the proportion of students who prefer the zoo in the sample should be similar to the proportion of students who prefer the zoo in the 7th grade class.
By setting up a proportion between the sample and the population, we can estimate the number of students in the 7th grade class who prefer the zoo. We know that 20 out of the 40 students in the sample from the 7th grade class prefer the zoo,
so we can use this proportion to estimate the number of students in the 7th grade class who prefer the zoo. Cross-multiplying the proportion gives us the equation 40x = 20*220, which we can solve for x to get x = 110.
It is important to note that this is just an estimate and that there is some degree of uncertainty involved in the estimation process. However, by using statistical methods such as proportionality, we can obtain a reasonable estimate that can help us make informed decisions.
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Heights for 16-year-old boys are normally distributed with a mean of 68. 3 in. And a
standard deviation of 2. 9 in.
Find the z-score associated with the 96th percentile.
Find the height of a 16-year-old boy in the 96th percentile.
The height of a 16-year-old boy in the 96th percentile is approximately 73.375 inches. The z-score associated with the 96th percentile is 1.75.
To find the z-score associated with the 96th percentile, we can use the following steps:
1. Locate the percentile in a standard normal distribution table or use a calculator that can compute percentiles (e.g., a graphing calculator or an online calculator).
2. For the 96th percentile, we find the corresponding z-score. Using a standard normal distribution table or an online calculator, the z-score is approximately 1.75.
So, the z-score associated with the 96th percentile is 1.75.
To find the height of a 16-year-old boy in the 96th percentile, we can use the following formula:
Height = mean + (z-score × standard deviation)
Here, the mean height is 68.3 inches, the z-score is 1.75, and the standard deviation is 2.9 inches. Plugging these values into the formula:
Height = 68.3 + (1.75 × 2.9) ≈ 68.3 + 5.075 ≈ 73.375 inches
So, the height of a 16-year-old boy in the 96th percentile is approximately 73.375 inches.
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Ethan goes to the park. The park is 85km away from his house towards south. After 2. 00 minutes,Wthan is 195km away from his house towards west. Find Ethans velocity
If after 2.00 minutes, Ethan is 195km away from his house towards west, Ethan's velocity is approximately 6393 km/h.
To find Ethan's velocity, we need to first determine the distance he traveled and the time he spent traveling.
Given:
1. Initial position: Ethan's house
2. Distance to park: 85 km south
3. Final position: 195 km west from house after 2 minutes
To find the total distance, we can use the Pythagorean theorem, as the path forms a right triangle:
Distance = √(85² + 195²) = √(7225 + 38025) = √(45250) ≈ 212.72 km
Now, let's convert the time from minutes to hours:
2 minutes = 2/60 hours ≈ 0.0333 hours
Finally, we can calculate Ethan's velocity:
Velocity = Distance / Time = 212.72 km / 0.0333 hours ≈ 6393 km/h
Ethan's velocity is approximately 6393 km/h.
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Can you help me do 1+1
Answer:
The answer to 1+1 is 2.
Answer:
2
Step-by-step explanation:
THIS IS DUE TONIGHT! PLEASE HELP ME! :c
USE STRUCTURE Complete the table to show the effect that the transformation has on the table of the parent function f(x)=x2.
g(x)is a reflection of f(x)across the x-axis.
x f(x) g(x)
-2 4
-1 1
0 0
1 1
2 4
The table of values to show the effect of the transformation is
x f(x) g(x)
-2 4 -4
-1 1 -1
0 0 0
1 1 -1
2 4 -4
Completing the table of values to show the effectFrom the question, we have the following parameters that can be used in our computation:
f(x) = x²
Also, we have
g(x) is a reflection of f(x)across the x-axis
This means that
g(x) = -f(x)
So, we have
g(x) = -x²
Using the above as a guide, we have the following:
x f(x) g(x)
-2 4 -4
-1 1 -1
0 0 0
1 1 -1
2 4 -4
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There were 16 boys and 12 girls at a soccer camp. The director wanted to make teams with the same number of boys and girls on each team. The greatest number of teams the director could make is --------. There will be ------ girls on each team
The greatest number of teams the director could make is 4, and there will be 3 girls on each team.
Since the director wants to make teams with an equal number of boys and girls, the number of teams must be a factor of both 16 and 12. The common factors of 16 and 12 are 1, 2, 4, and 8. Since the director wants to make as many teams as possible, the greatest number of teams is 4.
Each team will have 4 boys and 3 girls, so the total number of girls needed is 4 x 3 = 12. Since there are 12 girls in the camp, there will be 12/4 = 3 girls on each team. Therefore, the greatest number of teams the director could make is 4, and there will be 3 girls on each team.
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Which polynomial does the model represent? The model shows 1 black square block, 2 white thin blocks, 1 black thin block, 1 white small square block, 3 black small blocks
The polynomial represented by the model is [tex]]x^2 - x + 2[/tex]
Based on the provided model, the polynomial represented is:
1 black square block: x^2
2 white thin blocks: -2x
1 black thin block: x
1 white small square block: -1
3 black small blocks: +3
The polynomial that the model represents is:
[tex]x^2 - 2x + x - 1 + 3[/tex]
Combining like terms, we get:
[tex]x^2 - x + 2[/tex]
So, the polynomial represented by the model is [tex]x^2 - x + 2[/tex].
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Deriving the Law of Cosines
Try it
Follow these steps to derive the law of cosines.
✓ 1. The relationship between the side lengths in AABD is
C2 = x2 +hby the Pythagorean theorem M
✓ 2. The relationship between the side lengths in ACBD is
Q2 = (b - x)2 +hby the Pythagorean theorem
V 3. The equation e? = (6 – x)2 + h? is expanded y to become
22 = 62 - 2x + x2 +h?
a
h
✓ 4. Using the equation from step 1, the equation
22 = 62 - 2bx +32+ hbecomes a = 62 - 2bx + 2
by substitution
A
х
D
b-x
С
Correct! You have completed this exercise.
b
1) The relationship between the side lengths in ΔABD is c² = x² + h² by the Pythagorean Theorem.
2) . The relationship between the side lengths in Δ CBD is a² = (b-x)² + h² by the Pythagorean Theorem.
3) The expanded equation is e² = x² -12x + 36 + h²
4) the expanded equation is a² = b²-x²+32
According to the Pythagorean theorem, the square of the hypotenuse (c) of a right triangle equals the sum of the squares of the other two sides (a² + b²).
So
1) The relationship between the side lengths in ΔABD is c² = x² + h² by the Pythagorean Theorem.
2) The relationship between the side lengths in Δ CBD is a² = (b-x)² + h² by the Pythagorean Theorem.
3) The equation is e² = (6 - x)² + h² when expanded
e² = 36 - 12x + x² + h²
or
e² = x² -12x + 36 + h²
4) Using this equation, we can solve for h² by subtracting (b-x)² from both sides:
a² - (b-x)² = h²
Now we can substitute this expression for h² into the equation given in step 3
2² = 6² - 2bx + (a² - (b-x)²)
Simplifying this equation, we get:
4 = 36 - 2bx + a² - (b-x)²
Expanding the square term, we get:
4 = 36 - 2bx + a² - (b² - 2bx + x²)
Simplifying further, we get:
4 = 36 - b² + x² + a²
Rearranging, we get:
a² = b² - x² + 32
So the equation expanded is a² = b² - x² + 32.
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Full Question:
For 1 and 2, see attached image.
3) The equation e²= (6 – x)² + h² is expanded y to become ?
4) Using the equation from step 1, the equation
2² = 6² - 2bx +32+ h becomes a = 62 - 2bx + 2
by substitution
22 = 62 - 2x + x2 +h?
how many different homotheties can one of two concentric circles be projected onto the other?
Answer: If two concentric circles are projected onto each other, then there is only one homothety that maps one circle onto the other. This is because the center of the circles is the only point that remains fixed under the homothety.
suppose that 0.4% of a given population has a particular disease. a diagnostic test returns positive with probability .99 for someone who has the disease and returns negative with probability 0.97 for someone who does not have the disease. (a) (10 points) if a person is chosen at random, the test is administered, and the person tests positive, what is the probability that this person has the disease? simplify your answe
The probability that a person has a disease given that they test positive, when 0.4% of the population has the disease and the test is positive with probability 0.99 if they have the disease and 0.03 if they don't have it, is 0.116 or about 11.6%.
Let D be the event that the person has the disease and T be the event that the person tests positive. We need to calculate P(D|T), the probability that the person has the disease given that they test positive.
Using Bayes' theorem, we have
P(D|T) = P(T|D) * P(D) / P(T)
where P(T|D) is the probability of testing positive given that the person has the disease, P(D) is the prior probability of having the disease, and P(T) is the total probability of testing positive, which can be calculated as
P(T) = P(T|D) * P(D) + P(T|D') * P(D')
where P(T|D') is the probability of testing positive given that the person does not have the disease, and P(D') is the complement of P(D), which is the probability of not having the disease.
Substituting the given values, we get
P(D|T) = (0.99 * 0.004) / [(0.99 * 0.004) + (0.03 * 0.996)]
= 0.116
Therefore, the probability that the person has the disease given that they test positive is 0.116 or about 11.6%.
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What’s my gpa?
For school
Answer:
2.2
Step-by-step explanation:
To find your GPA, use the attached image:
After you've written down your numerical scores, divide it by the total classes you're taking, which is 7.
So, your GPA is 2.2
Susan set up a lemonade stand to raise money for a children's hospital. She's selling cups of lemonade for $2. 50 each and brownies for $1. 50 each. She sells 280 items and raises $540.
How much money does Susan raise from selling lemonade?
If she sells 280 items and raises $540, then Susan raises $300 from selling lemonade.
To determine how much money Susan raises from selling lemonade, we'll set up a system of equations using the given information.
Let x be the number of lemonade cups and y be the number of brownies sold. We know:
1. x + y = 280 (total items sold)
2. 2.50x + 1.50y = 540 (total money raised)
First, we'll solve for x in equation 1:
x = 280 - y
Now, substitute this expression for x in equation 2:
2.50(280 - y) + 1.50y = 540
Simplify and solve for y:
700 - 2.50y + 1.50y = 540
-1.00y = -160
y = 160
Now that we have the number of brownies (y), we can find the number of lemonade cups (x):
x = 280 - 160
x = 120
Finally, calculate the money Susan raises from selling lemonade:
Money from lemonade = 120 * $2.50 = $300
So, Susan raises $300 from selling lemonade.
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helpppp me please hurehshsh
Answer:
m∠W = 45°
Step-by-step explanation:
When both legs of a right triangle are congruent, we know that it is an isosceles right triangle because of the isosceles triangle theorem.
Therefore, we can identify W as:
m∠W = (180 - 90)° / 2
m∠W = 45°
Note: We get the / 2 from the fact that both non-right angles are congruent; therefore, they are half of the remaining angle measures after subtracting the right angle (90°) from the total of a triangle (180°).
Proctor & Gamble claims that at least half the bars of Ivory soap they produce are 99. 44% pure (or more pure) as advertised. Unilever, one of Proctor & Gamble's competitors, wishes to put this claim to the test. They sample the purity of 146 bars of Ivory soap. They find that 70 of them meet the 99. 44% purity advertised.
What type of test should be run?
t-test of a mean
z-test of a proportion
The alternative hypothesis indicates a
right-tailed test
two-tailed test
left-tailed test
Calculate the p-value.
Does Unilever have sufficient evidence to reject Proctor & Gamble's claim?
No
Yes
The test that should be run on the claim by Proctor & Gamble should be B. z-test of a proportion.
The alternative hypothesis indicates a c. left-tailed test.
The p - value is 0.2665. Unilever does not have sufficient evidence to reject Proctor & Gamble's claim, so A. no.
How to test the claim ?Conducting a z-test of a proportion is necessary in light of the proportion-based nature (at least half of the bars being 99.44% pure) of the inquiry, instead of means. Proctor & Gamble had asserted that over fifty percent of their bars exhibit 99.44% purity or better; Unilever wishes to investigate this assertion's accuracy.
Consequently, we run our test under null-hypothesis framework that considers fifty percent of bars possessing sufficient purity level and alternative hypothesis positing <50% do. The resultant course of action entails carrying out a left-tailed test.
The p - value. Find the test statistic:
z = ( 0. 4795 - 0.5) / √ ( ( 0.5 x (1 - 0.5) ) / 146)
z = - 0. 6236
z- table shows the p - value is 0. 2665 as a result.
With the p - value being higher than the normal significant level of 0. 05, Unilever should not reject Proctor & Gamble's claim.
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In a laboratory experiment, the population of bacteria in a petri dish started off at 380 and is growing exponentially at 3% per day. Write a function to represent the population of bacteria after tt days, where the hourly rate of change can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage rate of change per hour, to the nearest hundredth of a percent
The function is P(t) = 380 x [tex]1.0300^{t}[/tex], which is an exponential function, and the rate of change is 1.24% each hour.
The equation P(t) = 380 x [tex](1 + 0.03)^{t}[/tex] represents the population of bacteria after t days.
Rounding to four decimal digits and simplifying:
P(t) = 380 x [tex]0.0300^t[/tex]
We can use the following formula to determine the percentage rate of change each hour:
r = [tex]100 \times e^{(ln(1 + 0.03)/24) - 1)}[/tex]
where e is the Euler's number, ln is the natural logarithm, and r is the percentage rate of change per hour.
Rounding to the nearest tenth of a percent and simplifying:
r = 1.24%
This exponential function simulates the population of bacteria multiplying exponentially at a rate of 3% each day in a petri dish.
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suppose 44% of the doctors in a hospital are surgeons. if a sample of 738 doctors is selected, what is the probability that the sample proportion of surgeons will differ from the population proportion by more than 4% ? round your answer to four decimal places.
The probability of the the sample proportion of surgeons will be given as 1.
The z-score is a dimensionless variable that is used to express the signed, fractional number of standard deviations by which an event is above the mean value being measured. It is also known as the standard score, z-value, and normal score, among other terms. Z-scores are positive for values above the mean and negative for those below the mean.
For this case we can define the population proportion p as "true proportion of surgeons" and we can check if we can use the normal approximation for the distribution of p,
1) np = 738 x 0.44 = 324.72 > 10
2) n(1 - p) = 738 x (1 - 0.44) = 413.28 > 10
3) Random sample: We assume that the data comes from a random sample Since we can use the normal approximation the distribution for P is given by:
psimN(p,[tex]\sqrt{\frac{p(1-p)}{n} }[/tex])
With the following parameters:
Hp = 0.44
[tex]\sigma_p=\sqrt{\frac{0.44(1-0.44)}{738} }[/tex]
= 0.01827
And we want to find this probability:
P(p > 0.04)
And we can use the z score formula given by:
[tex]z=\frac{p-\mu}{\sigma}[/tex]
And if we calculate the z score for p = 0.39 we got:
[tex]z=\frac{0.04-0.44}{0.01827}[/tex] = -21.893
And we can find this probability using the complement rule and the normal standard table or excel and we got:
P(p > 0.04) = P(Z > -21.893) = 1 − P(Z < −21.893) = 1 - 0 = 1.
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Which function is a parabola?
F(x)=5-x^2
X - 2 -1 -0 0 3
G(x) 3 0 -1 0 3
1. F(x) only
2. G(x) only
3. Both f(x) and g(x)
4.neither
Answer:
1. F(x) only-----------------------
F(x) is in the format of a quadratic function:
y = ax² + bx + c, with a = - 1, b = 0, c = 5Hence it is a parabola.
The table represents a relation with two x-intercepts and two y-intercepts (points with the coordinate of 0).
We know that parabola can have maximum of one y-intercept, hence G(x) is not a parabola.
The matching answer choice is the first one.
