Please help very urgent I’m on a time limit and I need the answer this is a test

Answer:

I assume you meant "y = -x+7" not "= -x +7". If that is correct then the slope is -1.

Step-by-step explanation:

The slope is the coefficient of the x in slope-intercept form. Therefore, the slope is -1.

Please give me Brainliest if this answer is correct.

Answer:

The angles are 72° and 108°

Step-by-step explanation:

Supplementary angles add up to 180°

Ratio of supplementary angles = 2 : 3

The angles are 2x , 3x

2x + 3x = 180

        5x = 180

          x = 180 ÷ 5

         x = 36°

2x = 2*36 = 72°

3x = 3*36 = 108°

The distance from the wall defined by the y-axis will be 8 feet. Then the correct option is B.

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

The table is given below.

Then the equation of the line will be

(y – 8) = [(8 – 6) / (0 – 20)](x – 0)

       y = -0.1x + 8

If the drain is at the minimum point.

Then the distance from the wall defined by the y-axis will be 8 feet.

Then the correct option is B.

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Answer:

C [tex]\sqrt{5}[/tex]

Step-by-step explanation:

Use pythagorean theorem.

[tex]x^{2}[/tex] +[tex]\sqrt{7} ^{2}[/tex] = (2[tex]\sqrt{3}) ^{2}[/tex]    

[tex]x^{2}[/tex] + 7 = 12   Subtract 7 from both sides

[tex]x^{2}[/tex] = 5           Take the square root of both sides to solve

x = [tex]\sqrt{5}[/tex]

The number of matchsticks that each side of the biggest triangle contains is; 137 matchsticks

We know that for a diagram to be a triangle, then two smallest sides must not be greater than the third side.

Now, if there are 273 matchsticks, then the greatest side of the triangle must not be less than 273/2 = 136.5 ≈ 137

Thus, the largest side will have at least 137 matchsticks

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Answer: Option 3 or C. 22

Step-by-step explanation:

I got the answer correct on Edge 2022 quiz. Trust me the answer is correct I screenshot it using the prt sc key then uploaded it. The proof is in the pic below.  :)

Answer:

B. (4, -2)

Step-by-step explanation:

Please see attachment.

Hope this helps!

If not, I am sorry.

Answer:

1st q answer is f(x) is one- to -one function and 2nd q answer is 2

Answer:

Step-by-step explanation:

Let f(x) = y

y = 2x - 3

x = y + 3 / 2

inverse of f(x) = x + 3 / 2

f [g(2)]

f [2+3/2]

f [5/2]

(2×5/2)-3

5-3

= 2

The correct answer from the task content is; Choice C; None of the above.

The equations can be evaluated as follows;

A) -x + (-x) =0

-x -x = -2x......Not True

B) x -(-x) = 0

x + x = 2x .....Not True.

On this note, it follows that none of the equations is true.

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Answer:34.96 (answer to what is her purchase price before tax)

Step-by-step explanation:38*(1-.08)

Answer:

[tex]x=(-2,\frac{5}{3} )[/tex]

Step-by-step explanation:

1)  We will use the matrix method to solve this problem.

[tex]\left[\begin{array}{ccc}-2/3&1&3\\1&0&-2\\\end{array}\right][/tex]

2) Swap Row₁ and Row₂ to make row reduction easier.

[tex]\left[\begin{array}{ccc}1&0&-2\\-2/3&1&3\\\end{array}\right][/tex]

3) Apply to Row₂ :  Row₂ + [tex]\frac{2}{3}[/tex] Row₁.

[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\end{array}\right][/tex]

4)  Simplify rows.

[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]

Note: The matrix is now in row echelon form.

The steps below are for back substitution.

5) Apply Row₁ : Row₁ - 0 Row₂.

[tex]\left[\begin{array}{ccc}1&0&-2\0\\0&1&5/3\end{array}\right][/tex]

6) Simplify rows.

[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]

Note: The matrix is now in reduced row echelon form.

7) Therefore,

[tex]x=-2\\x=\frac{5}{3}[/tex]

Answer:

83.80 = 69 + 4x
x = 3.7
Sarah can use up to 3.7 gigabytes per month to stay within her budget

Step-by-step explanation:

83.80 = 69 + 4x
14.8 = 4x
x = 3.7

The number of gigabytes of data Sarah can use while staying within her budget is 3.7 gigabyte.

Given that, Sarah pays a flat cost of $69 per month and $4 per gigabyte.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the number of gigabyte be g.

69+4g=83.80

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Now, 4g=83.80-69

⇒ 4g=14.8

⇒ g=14.8/4

⇒ g=3.7 gigabyte

Therefore, the number of gigabytes of data Sarah can use while staying within her budget is 3.7 gigabyte.

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The least number of consecutive positive integer that is required to make the sum of the reciprocals greater than three is 7.

An integer is simply a number that is not  a  fraction.

The first four consecutive positive integers are:

1, 2, 3 , 4.

Their reciprocals are:

1/1, 1/2, 1/3, 1/4; and

The sum of them are greater than 2; that is

1/1 + 1/2 + 1/3 + 1/4 = 2.08333333333 > 2

to make the expression >3

We would require the following integers

1/1 + 1/2 + 1/3 + 1/4+ (1/5) + (1/6) + (1/7) + (1/8)+ (1/9) + (1/10) + (1/11) = 3.01987734488

Thus, the additional consecutive reciprocal integers that is required to make the sum of the reciprocal of the fist four greater than 3 is 7.

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Answer:

720 Course Schedules

Step-by-step explanation:

When you choose the first course, there are 6 to choose from. When you scoose the second, there are only 5. This keeps going until the 6th course where there is only 1 choice.

You multiply these choices together. You should get 6×5×4×3×2×1

6×5=30

30×4=120

120×3=360

360×2=720

720×1=720

You then end up with 720 course schedules.

Please, make sure you understand the solution:

We can notice that x + (x - 28) = 90

2x - 28 = 90
2x = 118
x = 59

Now for y:

We can notice that y + 90 + x = 180

y + 90 + 59 = 180
y + 149 = 180
y = 180 - 149

y = 31

The surface area and volume of the real brick will be 983.2 cm²and 1738.11 cm³ respectively.

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The scale factor is ;

r = 630 cm /23

r = 27

L = 23 cm

b = 310 / 27 = 11.48 cm

h = 180/27 = 6.6 cm

The surface area of the brick;

A = 2(lb+bh+hl)

A = 2( 23 ×11.48+11.48×6.6+6.6×23)

A= 983.2 cm²

The volume of the brick is;

V= lbh

V=23 × 11.45 ×6.6

V=1738.11 cm³

Hence the surface area and volume of the real brick will be 983.2 cm² and 1738.11 cm³ respectively.

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Answer:

false

Step-by-step explanation:

if the 2 shorter segments dont add up to be equal or greater to the longest segment, then its impossible for a triangle to be formed :)

Answer:

True

Step-by-step explanation:

General formulas and concepts:
Subject: Geometry

Unit: Triangular Line Segments

Definitions:

Triangle Inequality Theorem

Steps:

Use the triangle inequality theorem:

9 + 4 > 11

13 >  11 ⇒  True

9 + 11 > 4

20 > 4 ⇒ True

4 + 11 > 9

15 > 9 ⇒ True

Conclusion:

Because the 3 segments that are given satisfy the statements of the triangle inequality theorem, they can therefore form a triangle.

Answer:

They are parallel because their slopes are equal.

Step-by-step explanation:

See attached image.

The choice is tangent rule and the distance from the base to the tower is 3. 98 meters

The trigonometric ratio to use is

tan α = opposite side/ adjacent side

This is so because the angle 86° is facing the side of the distance from the top to the base

The choice is tangent rule

adjacent  = x

Angle = 86°

Opposite side = 57

We have

tan 86° = 57/x

14. 300= 57/x

x = 57 ÷ 14.300

x = 3.98meters

Thus, the choice is tangent rule and the distance from the base to the tower is 3. 98 meters

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2) [tex]m\angle A+m\angle B+m\angle C+m\angle D=360^{\circ}[/tex]

3) Substitution property

4) Combine like terms

Answer:

16

Step-by-step explanation:

If f(x)=7x-3 and g(x)=x²,

(g•f)(1)= g(f(1))

bit : f(1) =7(1)-3 = 4

(g•f)(1)= g(f(1)) = g(4) = 1² = 16

I hope this was helpful :)

Answer:

[tex]\log_8{(3)} + \log_8{(7)}[/tex]

Step-by-step explanation:

Product Rule for Logarithms

[tex]\log_b{(mn)} = \log_b{(m)} + \log_b{(n)}[/tex]

Instead of 21 you can write 3 · 7, because 21 = 3 · 7.

[tex]\log_8{(21)} = \\= \log_8{(3 \cdot 7)} =\\= \log_8{(3)} + \log_8{(7)}[/tex]

To find the maxima and minima of the function, we need to calculate the derivative of the function. Note, before the denominator is a perfect square trinomial, so the function can be simplified as

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(x) = \frac{x^2 - x - 2}{(x - 3)^2}} \end{gathered}$}[/tex]

So the derivative is:

  [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(2x - 1)(x - 3)^2 - 2(x - 3)(x^2 - x - 2)}{(x - 3)^4} } \end{gathered}$}[/tex]

Simplifying the numerator, we get:

                 [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(x - 3)(-5x + 7)}{(x - 3)^4} = \frac{-5x + 7}{(x - 3)^3} } \end{gathered}$}[/tex]

The function will have a maximum or minimum when f'(x) = 0, that is,

                  [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{-5x + 7}{(x - 3)^3} = 0 } \end{gathered}$}[/tex]

which is true if -5x + 7 = 0. Then x = 7/5.

To determine whether x = 7/5 is a maximum, we can use the second derivative test or the first derivative test. In this case, it is easier to use the first derivative test to avoid calculating the second derivative. For this, we evaluate f'(x) at a point to the left of x = 7/5 and at a point to the right of it (as long as it is not greater than 3). Since 1 is to the left of 7/5, we evaluate:

                    [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(1) = \frac{-5 + 7}{(1 - 3)^3} = \frac{2}{-8} < 0} \end{gathered}$}[/tex]

Likewise, since 2 is to the right of 7/5, then we evaluate:

                                   [tex]\large\displaystyle\text{$\begin{gathered}\sf \displaystyle \bf{\frac{-10 + 7}{(2 - 3)^3} = \frac{-3}{-1} > 0} \end{gathered}$}[/tex]

Note that to the left of 7/5 the derivative is negative (the function decreases) and to the right of 7/5 the derivative is positive (the function increases).

The value of f(x) at 7/5 is:

                               [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f\left(\tfrac{7}{5}\right) = \frac{\tfrac{49}{25} - \tfrac{7}{5} - 2}{\tfrac{49}{25} - 6 \cdot \tfrac{7}{5} + 9} = -\frac{9}{16} } \end{gathered}$}[/tex]

This means that [tex]\bf{\left( \frac{7}{5}, -\frac{9}{16} \right)}[/tex] is a minimum (and the only extreme value of f(x)).

[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:

[tex]\text{Minimum at }\left(\dfrac{7}{5},-\dfrac{9}{16}\right)[/tex]

Step-by-step explanation:

The local maximum and minimum points of a function are stationary points (turning points).  Stationary points occur when the gradient of the function is zero.  Differentiation is an algebraic process that finds the gradient of a curve.

To find the stationary points of a function:

[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $y=\dfrac{u}{v}$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}$\\\end{minipage}}[/tex]

[tex]\text{Given function}: \quad \text{f}(x)=\dfrac{x^2-x-2}{x^2-6x+9}[/tex]

Differentiate the function using the Quotient Rule:

[tex]\text{Let }u=x^2-x-2 \implies \dfrac{\text{d}u}{\text{d}x}=2x-1[/tex]

[tex]\text{Let }v=x^2-6x+9 \implies \dfrac{\text{d}v}{\text{d}x}=2x-6[/tex]

[tex]\begin{aligned}\implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{(x^2-6x+9)(2x-1)-(x^2-x-2)(2x-6)}{(x^2-6x+9)^2}\\\\& =\dfrac{(2x^3-13x^2+24x-9)-(2x^3-8x^2+2x+12)}{(x^2-6x+9)^2}\\\\\implies \text{f}\:'(x)& =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\\end{aligned}[/tex]

Set the differentiated function to zero and solve for x:

[tex]\begin{aligned}\implies \text{f}\:'(x)& =0\\\\\implies \dfrac{-5x^2+22x-21}{(x^2-6x+9)^2} & = 0\\\\-5x^2+22x-21 & = 0\\\\-(5x-7)(x-3) & = 0\\\\\implies 5x-7 & = 0 \implies x=\dfrac{7}{5}\\\\\implies x-3 & = 0 \implies x=3\end{aligned}[/tex]

Put the x-values back into the original equation to find the y-values:

[tex]\implies \text{f}\left(\frac{7}{5}\right)=\dfrac{\left(\frac{7}{5}\right)^2-\left(\frac{7}{5}\right)-2}{\left(\frac{7}{5}\right)^2-6\left(\frac{7}{5}\right)+9}=-\dfrac{9}{16}[/tex]

[tex]\implies \text{f}(3)=\dfrac{\left(3\right)^2-\left(3\right)-2}{\left(3\right)^2-6\left(3\right)+9}=\dfrac{4}{0} \implies \text{unde}\text{fined}[/tex]

Therefore, there is a stationary point at:

[tex]\left(\dfrac{7}{5},-\dfrac{9}{16}\right)\:\text{only}[/tex]

To determine if it's a minimum or a maximum, find the second derivative of the function then input the x-value of the stationary point.

Differentiate f'(x) using the Quotient Rule:

Simplify f'(x) before differentiating:

[tex]\begin{aligned}\text{f}\:'(x) & =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{\left((x-3)^2\right)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{(x-3)^4}\\\\& = -\dfrac{(5x-7)}{(x-3)^3}\\\\\end{aligned}[/tex]

[tex]\text{Let }u=-(5x-7) \implies \dfrac{\text{d}u}{\text{d}x}=-5[/tex]

[tex]\text{Let }v=(x-3)^3 \implies \dfrac{\text{d}v}{\text{d}x}=3(x-3)^2[/tex]

[tex]\begin{aligned}\implies \dfrac{\text{d}^2y}{\text{d}x^2} & =\dfrac{-5(x-3)^3+3(5x-7)(x-3)^2}{(x-3)^6}\\\\& =\dfrac{-5(x-3)+3(5x-7)}{(x-3)^4}\\\\\implies \text{f}\:''(x)& =\dfrac{10x-6}{(x-3)^4}\end{aligned}[/tex]

Therefore:

[tex]\text{f}\:''\left(\dfrac{7}{5}\right)=\dfrac{625}{512} > 0 \implies \text{minimum}[/tex]

Answer:

C

Step-by-step explanation:

The horizontal line, y=2, is solid and shaded above, so it represents

[tex]y \geqslant 2[/tex]

The slanted line, y=x is dashed and shaded below, so it represents y<x.

The solution of the equation 4x = 20, x – 11 = 9, 5x + 6x = 22, and 5(x – 2) = 30 will be 5, 20, 2, and 8.

The solution of the equation means the value of the unknown or variable.

The equations are given below.

4x = 20

 x = 5

x – 11 = 9

      x = 20

5x + 6x = 22

       11x = 22

         x = 2

5(x – 2) = 30

   x – 2 = 6

         x = 8

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The correct answer is option D which is the probability is 1.

The complete question is given below:-

Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer. Which value represents the probability that he will win the election?

0

1/4

3/4

1

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The probability of Event E is given by,

P = favourable outcomes / Total outcomes

Jamaal is the only candidate running in the class treasurer election.

There for Total No. of outcomes = 1

Here Event E is Jamaal winning the Election.

So, No. of favorable outcome = 1

P(E) = 1 / 1

P(E) = 1

This type of event is called a SURE EVENT Because the probability of a sure event is always 1.

The Probability of Jamaal winning the election is 1. So, Option D is correct.

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The probability that he will win the election will be 1. Then the correct option is D.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

The value of the probability of an event will be varying from zero to one.

Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer.

Then the probability that he will win the election will be

If the event will certainly happen, then the probability will be one.

P = 1

Then the correct option is D.

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Answer:

135

Step-by-step explanation:

Depending on where you start, the protractor can read in different ways. Since the measure of this angle started from the left, you read the numbers at the top. If the measure would have started from the right, you read the numbers below.

A good rule of thumb is that if the angle appears to be greater than 90 degrees, or an obtuse angle, you would choose the only answer choice that is above 90 degrees.

Hope this helps!

Answer:

I am not completely sure if this is correct, but I believe the answer should be PM.
This is because the order of the letters that represents a point can be swapped, since they are still forming the same line.