PLEASE HELP. Really important

PLEASE HELP. Really Important

Answers

Answer 1

Explanation:

2) C would need the least effort, because the longer the effort distance, the least the effort applied.


Related Questions

potential energy is frequintly converted into kenetic energey. kenetic energey

Answers

Answer:

When an object falls, its gravitational potential energy is changed to kinetic energy. ... Gravitational potential energy for a mass m at height h near the surface of the Earth is mgh more than the potential energy would be at height 0. (It's up to you where you choose height 0.)

Explanation:

Answer:

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Explanation:

A car accelerates from 10m/s to 20m/s over a distance of 80m. What is its acceleration?

Answers

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

The average velocity of the car is 15 m/s. The time taken to travel over the distance with this velocity is 5.3 seconds. Then the acceleration of the car is 1.8 m/s².

Wat is acceleration ?

Acceleration is a physical quantity measuring the rate  of change in velocity of a moving object. Like velocity, acceleration is a vector quantity having magnitude and direction.

Acceleration is the ratio of change in velocity to the change in time.

a = Δv/Δt

Given, the car is accelerating from 10 to 20 m/s. Hence, it travelled with average velocity of 15 m/s over the distance of 80 m.

Then , time taken  = distance/velocity

t = 80 m/15 m/s = 5.3 s

Acceleration = Δv/t = (20 -10 m/s) /5.3 s = 1.8 m/s².

Therefore, the acceleration of the car is about  1.8 m/s².

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GENTE ME AJUDEM NESTA QUESTÃO POR FAVOR, TENHO PROVA ONLINE AMANHÃ! "Um sonar de um navio de pesca localizou um cardume de sardinhas a 300 m de profundidade. Sabendo que a velocidade de propagação do som na água tem o valor de 1500 m/s, calcula o tempo que decorre desde a emissão dos ultra-sons e a sua receção no navio." Por favor!

Answers

Answer:

The time between the emission of the wave and it's reception was 0.4 seconds.

Explanation:

The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:

[tex]\text{speed} = \frac{\text{distance}}{\text{time}}[/tex]

We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:

[tex]\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}[/tex]

The time between the emission of the wave and it's reception was 0.4 seconds.

The graph shows the motion of a cyclist.



Calculate;

a) The acceleration in the first 20 s.

b) The acceleration between 20 and 30s.

c) The acceleration in the last 10 s.

d) The distance travelled by the cyclist when he was moving at a constant speed?
Show working.

Answers

Answer:

A. 0.5m/s².

B. –0.5m/s².

C. –0.5m/s².

D. 100m.

Explanation:

A. Determination of the acceleration in the first 20s.

Initial velocity (u) = 0

Final Velocity (v) = 10m/s

Time (t) = 20secs.

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (10 – 0)/20 = 10/20

a = 0.5m/s²

Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²

B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:

Initial velocity (u) = 10m/s

Final Velocity (v) = 5m/s

Time (t) = 30 – 20 = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (5 – 10)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the 20 and 30secs is

–0.5m/s².

C. Determination of the acceleration in the last 10s.

Initial velocity (u) = 5m/s

Final Velocity (v) = 0

Time (t) = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (0 – 5)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the last 10secs is

–0.5m/s².

D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.

Velocity (v) = 5m/s

Time (t) = 50 – 30 = 20secs

Displacement (d) =?

Velocity = Displacement /Time

v = d/t

5 = d/20

Cross multiply

d = 5 x 20

d = 100m

Therefore, the distance travelled by the cyclist at constant speed is 100m

People often think that Galileo dropped two objects of dramatically different mass off of the Leaning Tower of Pisa that both hit the ground at the same time. Explain why in reality this was most likely not true.

Answers

Answer: because of air resistance. See explanation for further details.

Explanation: Galileo performed an experiment to proof that the time of descent of two different masses is independent of time.

But in reality this is most likely not true because of air resistance and other fluid frictional effects in consideration.

If the experiment is performed in a vacuum, it will always be true that time is independent of masses of two falling objects.

A train is moving west with an initial velocity of 20m/s accelerates at 4m/s for 10 seconds during this time the train moves a distance ​

Answers

Answer:

400m

Explanation:

From Newton's law of motion;

S = ut + 1/2 at2

Where U is initial velocity

a is acceleration

t is velocity hence;

S is distance covered

S = 20×10 + 1/2 × 4×(10)^2

= 200 + 200 = 400m

A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the acceleration.

Answers

Answer:

Acceleration (a) = 40 m/s²

Explanation:

Given:

Initial velocity (u) = 6 m/s

Final velocity (v) = 4.4 m/s

Time taken (t) = 0.04sec

Find:

Acceleration (a) = ?

Computation:

We know that,

⇒ v = u + at

a = (v - u) / t

⇒ Acceleration (a) = (4.4 - 6) / 0.04

⇒ Acceleration (a) = (-1.6) / 0.04

Acceleration (a) = 40 m/s²

A horse runs for 15 seconds to the south at a speed of 12 m/s. What is the
displacement of the horse in this time?
A. 180 m south
B. 150 m south
C. 150 m
D. 180 m

Answers

Answer: 180 m south

Explanation:

The displacement of the horse in this time is 180 m south. The correct option is A.

What is displacement?

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Velocity is the time rate of change of displacement with time.

Given is a horse runs for 15 seconds to the south at a speed of 12 m/s. So, the displacement is

Displacement = Speed x Time

Put the values, we get

Displacement = 12 m/s x 15s

                      = 180 m

Thus, the displacement of the horse in this time is 180 m south.

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In some creatures, bioluminescence transforms
energy
energy into
OA) heat; light
OB) light; heat
OC) chemical potential; light
OD) light; chemical potential​

Answers

OB which is light and heat

Answer:

Hey!

Your answer would be option B. Light; heat...

Explanation:

In bioluminescent organisms, the energy is transformed int light energy and less then 20% of the total energy is put into Thermal Radiation!

HOPE THIS HELPS!!

Which of the following characterizes the particles in this diagram?

A. Two positive charges
B. One positive charge and one negative charge
C. Two negative charges
D. Two neutral charges

Answers

Answer:

B

Explanation:

One positive charger and one negative charger

A car starts from rest and attains a velocity of 30m/s in 5 sec . calculate the total distance travel by that car and acceleration

Answers

Answer:

Acceleration (a) = 6 m/s²

Total distance travel by car(s) = 75 meter

Explanation:

Given:

Initial velocity (u) = 0

Final velocity (v) = 30 m/s

Time (t) = 5 sec

Find:

Total distance travel by car(s) = ?

Acceleration (a) = ?

​Computation:

v = u +at

30 = 0 + a(5)

30 = a(5)

Acceleration (a) = 6 m/s²

Total distance travel by car(s) = ut +1/2(a)(t)²

Total distance travel by car(s) = 1/2(a)(t)²

Total distance travel by car(s) = (0.5)(6)(5)²

Total distance travel by car(s) = 75 meter

Just need the answer to D please

Answers

The boat has to pull with MORE force. Don't forget about the force of friction with the water, pulling the skier in the backwards direction. The force that accelerates him is the NET force ... boat force minus water resistance. So the boat force has to be greater than the net accelerating force.

Why would you expect sodium (Na) to react strongly with chlorine?

Answers

Answer:

Na is a alkaline metal, it can very easy give an electron, and form positive ion.  Cl is a very strong non-metal(halogen),  and it is able to take electron, and form negative ion. Positive and negative ion can attract to each other and form ionic bond.

WILL GIVE BRAINLIEST AND 10 POINTS!! An asteroid is hustling through the solar system, in the vicinity of the inner planets. Based on what you know about gravitational attraction, which planet is LEAST likely to attract the asteroid?

Answers

Answer:

mercury

Explanation:

The planet with the smallest mass must have the smallest gravitational pull - which is mercury, with a pull of approx. 0.38 times the Earth's gravitational pull.

What is the compound name for Srl2

Answers

Answer:

i have no idea

Explanation:

im am quite sorry

The compound name for SrI₂ is strontium iodide.

A compound is a substance formed when two or more elements chemically combine together. It is composed of atoms of different elements that are held together by chemical bonds. Compounds have unique chemical and physical properties that are different from the elements they are made of.

Strontium iodide is an ionic compound consisting of strontium cations (Sr2+) and iodide anions (I-). When strontium (Sr) and iodine (I) react, they undergo a chemical reaction to form SrI₂.

Therefore, The name of the compound SrI₂ is strontium iodide.

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The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.

Answers

Answer:

a_max = 50 cm/s^2

Explanation:

To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:

[tex]x=Acos(\omega t)[/tex]

ω: angular velocity = 10 rad/s

A: amplitude = 5 cm

The acceleration is given by:

[tex]a=\omega^2 x[/tex]

and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:

[tex]a_{max}=\omega^2 x_{max}=\omega^2A[/tex]

Then, you replace the values of w and A in order to calculate a_max:

[tex]a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}[/tex]

hence, the maximum acceleration is 50 cm/s^2

Earth is a dynamic system what exactly does this mean

Answers

Answer:

The answer to the following question is given below.

Explanation:

This means a mixture of interconnected, interlinked, or interactive elements that establish the collaborative entity or entities.  

The Earth system manages to maintain its very presence on even a macro level as well as processes in general thru the engagement of all its elements. This affects such as erosion, whereas others happen unexpectedly, such as an earthquake.  It is crucial to keep our lifestyle in mind that we can recognize all such adjustments as well as their implications.

PLEASE HELP!!!!!
When describing image formation for plane mirrors, what is an important rule
to remember about light rays?

Answers

Answer: The image formed by a plane mirror is always virtual (meaning that the light rays do not come from the image), upright and of the same shape and size as the object it is reflecting.

Answer: B. The angle when it leaves is the same as the angle when it hits

Explanation:

Apex

suppose that g (x) equals f (x + 1) - 3 which statement best compares the graph of g (x) with the graph of f (x)​

Answers

Answer:

The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.

Explanation:

f(x + q) which is left q units

f(x - q) which is right q units

f(x) + q which is up q units

f(x) - q which down q nits

and

G(x) = F(x + 1) - 3

So,

f(x + 1) shifts to left 1 unit

f(x) - 3 shifts to down 3 units

So, the correct answer is B.

The graph of G(x) is the graph of F(x) shifted 1 unit to the left and 3 units down.

An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 90.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? Given the angle, what is minimum speed at which the tranquilizer dart must leave the gun to still hit the monkey?

Answers

Answer:

The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.

Tan theta = 9 / 90 = .1      so theta = 5.71 deg

The time for the monkey to reach the ground is

t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec

So the horizontal speed of the dart must be at least

Vx = 90 m / 1.36 sec = 66.4 m/s

Vx = V cos theta

V = 66.4 m/s / cos 5.71 = 66.7 m/s

The angle of projection of the tranquilizer dart is 5.7⁰

The horizontal speed of the tranquilizer dart is 66.5 m/s

The given parameters;

vertical position of the monkey, y = 9 mhorizontal position of the veterinarian, x = 90

The angle of projection of the tranquilizer dart is calculated as;

[tex]tan(\theta) = \frac{y}{x} \\\\tan(\theta) = \frac{9}{90} \\\\tan(\theta) = 0.1\\\\\theta = tan^{-1}(0.1)\\\\\theta = 5.71 ^0[/tex]

The speed of the tranquilizer dart is calculated as;

X = v₀ₓt

where;

t is the time to reach maximum height

X is the horizontal displacement = 90 m

The time to reach maximum height is calculated as;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 9}{9.8} } \\\\t = 1.36 \ s[/tex]

The horizontal speed of the tranquilizer dart is calculated as;

[tex]X = v_0cos(\theta) \times t\\\\90 = v_0\times cos(5.71) \times 1.36\\\\90 = 1.353 v_0\\\\v_0= \frac{90}{1.353} \\\\v_0 = 66.5 \ m/s[/tex]

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HELLO ONCE MORE FRIENDS . PLEASE HELP ME.
Q.18) In the figure below, Force (F) of 2000 N is acting on the piston A and a bus is on the piston B. If the area of piston A is 50 cm2 and the area of piston B is 4000 cm2
a)Find the pressure produce of the piston B . (3 marks)


b)Find the weight of the bus on the poston B. ( 3 marks)


c)Calculate the mass of the bus. ( 3 marks)

Answers

Answer:

Do u want to talk?

Explanation:

Answer:

You found answer yet?

Explanation:

At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?

Answers

Answer:

[tex]\lambda=4.81\times 10^{-8}\ m[/tex]

Explanation:

We have,

The surface temperature of the star is 60,000 K

It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :

[tex]\lambda T=2.89\times 10^{-3}[/tex]

Here,

[tex]\lambda[/tex] = wavelength

[tex]\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m[/tex]

So, the wavelength of the star is [tex]4.81\times 10^{-8}\ m[/tex].

You get in your car to drive to school at 7:33 am and drive 10 miles north at a constant speed until 7:45
am, when you realize you left your homework on the kitchen table. You turn around and drive 10 miles
south back to your house and retrieve your homework at 8:00 am. You get back in the car and drive 15
miles north to school at a constant speed arriving at school at 8:29 am sharp, just in time to make it
before the bell rings.
e

Answers

Answer:

5.) 16.8 m/s

6.) 16.1 mph

7.) Moving fast.

Explanation:

5.) From the question, the total time will be:

7:33 am to 7:45 am = 12 minutes

As the car turns around,

7 : 45 am to 8 : 00am = 15 minutes

As you get back in the car and drive 15

miles north to school at a constant speed arriving at school at 8:29 am

8:00am to 8:29 am = 29 minutes

Total time = 12 + 15 + 29 = 56 minutes

Convert the minutes to second by multiplying the result by 60

Total time = 56 × 60 = 3360 seconds

Total distance covered will be

10 miles + 10 miles + 15 miles = 35 miles

Convert mile to meter by multiplying the result by 1609.344

35 × 1609.344 = 56327.04

Speed is a scale quantity. It only involves magnitude but no direction.

Average speed = total distance/total time

Average speed = 56327.04/3360

Average speed = 16.764 m/s

6.) Velocity = displacement/time

Velocity is a vector quantity. We will consider both the magnitude and direction

Total displacement = 10 miles - 10 miles + 15 miles = 15 miles.

Total time = 56 minutes

Convert minutes to hours by dividing it by 60

Total time = 56/60 = 0.93 hours

Substitute the time and displacement into the formula

Velocity = 15/0.93 = 16.07 mph

7.) . If you looked at your speedometer on your drive to school and it read 30mph, this value describes you move with a fast speed.

A 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees. Ignoring friction, how fast is it going when it reaches the bottom of the hill?​

Answers

Answer:

10.2 m/s

Explanation:

Using conservation of energy:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

The velocity when car reaches the bottom of the hill is 10.2 m/s.

What is mechanical energy?

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

M.E = ½ mv² + mgh

where g is the acceleration due to gravity, v is the velocity, m is the mass and h is the height of the object.

Given is a 1380 kg car starts from rest at the top of a 28.0 m long hill inclined at 11.00 degrees.

Using conservation of energy principle, we have

PE = KE

mgh = ½ mv²

v = √(2gh)

Substitute the values, we get

v = √(2 × 9.8 m/s² × 28.0 m × sin 11.0°)

v = 10.2 m/s

Thus, the velocity when car reaches the bottom of the hill is 10.2 m/s.

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why is no one helping?

Answers

Answer:

First one is hyperopia, second is myopia

Explanation:

Hyperopia is when the image is formed behind the retina.

Myopia is when images are formed infront of the retina.

a 1000 kg rhinoceros running at its top speed of 15 m/s has a kinetic energy of a.bc X 10^ J. What are the values of a.b.c. and d?

Answers

Answer:

K.E = 1.13 × 10^5 J

When compared to;

K.E = a.bc X 10^d J

We can observe that;

a = 1

b = 1

c = 3

d = 5

Explanation:

Given;

Mass of rhinoceros m = 1000kg

Velocity v = 15m/s

The kinetic energy of the body at this speed is;

K.E = 0.5×mv^2 ........1

Substituting the values of m and v into equation 1;

K.E = 0.5×1000×15^2

K.E = 112500 J

K.E = 1.13 × 10^5 J

When compared to;

K.E = a.bc X 10^d J

We can observe that;

a = 1

b = 1

c = 3

d = 5

iv. The lift raises a car of mass 850 kg to a height of 2.1 m. It uses a force of 8330 N and takes 4 seconds to raise the car. What is the power of the lift? (1 point)

Answers

Answer:

Power is 4373.25 W

Explanation:

We have,

The lift raises a car of mass 850 kg to a height of 2.1 m. It uses a force of 8330 N and takes 4 seconds to raise the car. It is required to find the power of the lift. Power is equal to the rate at which the work is done. So,

[tex]P=\dfrac{Fd}{t}\\\\P=\dfrac{8330\times 2.1}{4}\\\\P=4373.25\ W[/tex]

So, the power of the lift is 4373.25 W.

Differents between foundamental quantity and derived quantities

Answers

Answer:

fundamental quantity can simply be defined as an independent quantity while derived quantity is dependent i.e. the derive their quantities from the fundamental

Which quantity Has the same unit as potential difference

Answers

Answer:

Voltage.

Explanation:

A cork weigh 2.5 gf in air. When tied to a sinker , the total weight is 20 gf in water. If the sinker alone weighs 25gf in water, find the density of the cork

Answers

Answer:

0.333

Explanation:

Weight of the sinker in water = 25gf

Weight of cork in air and sinker in water = 25gf + 2.5gf

= 27.5gf

Weight of the cork and sinker in water = 20gf

Loss of weight of cork in water = 27.5- 20 = 7.5gf

Rd of cork = weight of cork in air/ loss of weight of cork in water

= 2.5/7.5

= 1/3

= 0.333

Hence the Relative density of the cork is 0.333

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