Please help me I'm so bad at math and doing AFDA really doesn't help.. Its quadratic equations matching solution sets.

Answer:

[tex](a)\ x + 4 = \±\sqrt9[/tex] ---- [tex]x =\{-7,- 1\}[/tex]

[tex](b)\ x - 4 = \±\sqrt9[/tex] ---- [tex]x = \{1,7\}[/tex]

[tex](c)\ x + 3 = \±\sqrt{16}[/tex] ----- [tex]x = \{-7,1\}[/tex]

[tex](d)\ x - 3 = \±\sqrt{16}[/tex] ---- [tex]x = \{-1,7\}[/tex]

Step-by-step explanation:

Given

The attached equations

Required

Match each with the solution

[tex](a)\ x + 4 = \±\sqrt9[/tex]

Take the square root of 9

[tex]x + 4 = \±3[/tex]

Solve for x

[tex]x =- 4 \±3[/tex]

Split

[tex]x =\{- 4 -3,- 4 +3\}[/tex]

[tex]x =\{-7,- 1\}[/tex]

[tex](b)\ x - 4 = \±\sqrt9[/tex]

Take the square root of 9

[tex]x - 4 = \±3[/tex]

Solve for x

[tex]x = 4 \±3[/tex]

Split

[tex]x = \{4 -3,4+3\}[/tex]

[tex]x = \{1,7\}[/tex]

[tex](c)\ x + 3 = \±\sqrt{16}[/tex]

Take the square root of 16

[tex]x + 3 = \±4[/tex]

Solve for x

[tex]x =- 3 \±4[/tex]

Split

[tex]x = \{-3-4,-3+4\}[/tex]

[tex]x = \{-7,1\}[/tex]

[tex](d)\ x - 3 = \±\sqrt{16}[/tex]

Take the square root of 16

[tex]x - 3 = \±4[/tex]

Solve for x

[tex]x =3 \±4[/tex]

Split

[tex]x = \{3-4,3+4\}[/tex]

[tex]x = \{-1,7\}[/tex]

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