Please help. I’m confused on where to even start

Answer:

92.9%

Explanation:

You have been given the actual yield of the reaction. First, you need to find the theoretical yield of the reaction. To do this, you need to (1) convert grams Fe₂O₃ to moles Fe₂O₃ (via molar mass from periodic table values), then (2) convert moles Fe₂O₃ to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass).

Once you have found the theoretical yield, you need to use the percent yield equation to calculate the final answer. This number should have 3 sig figs to match the given values.

(Step 1)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

1 Fe₂O₃(s) + 3 CO(g) ---> 2 Fe(s) + 3 CO₂(g)

Molar Mass (Fe): 55.845 g/mol

50.0 g Fe₂O₃           1 mole              2 moles Fe           55.845 g
--------------------  x  ------------------  x  ---------------------  x  ----------------  = 35.0 g Fe
                               159.684 g         1 mole Fe₂O₃          1 mole

(Step 2)

                                 Actual Yield
Percent Yield  =  ---------------------------  x  100%
                             Theoretical Yield

                                32.5 g Fe
Percent Yield  =  ----------------------  x  100%  =  92.9%
                                35.0 g Fe

Answer:

Option 3

Explanation:

Heat is absorbed, so the reaction is endothermic.

In conclusion, modeling is very useful for predicting molecular polarity because chemical bonds among different atoms are generated to equal electrical charges.

Molecular polarity refers to the unequal distribution of electrical charges in the atoms of a molecule.

This unequal distribution leads to the generation of molecular poles (positive and negative) at the ends of the chemical bonds.

In conclusion, modeling is very useful for predicting molecular polarity because chemical bonds among different atoms are generated to equal electrical charges.

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Answer:

1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left

Explanation:

Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.

Adding a catalyst has no effect on equilibrium reactions.

When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.

Answer:

pH=2.3

Explanation:

One H2SO4 molecule produce two H+ ions.

So conc. of H+ = 2(0.0025)

=0.005

Now, pH=-log (conc. of H+)

=-log(0.005)

=2.3

121 g [tex]AlI_{3}[/tex] aluminum iodide, from the complete reaction of 113 grams I₂ according to the following balanced chemical equation:

2Al(s) + 3I₂(s) → 2[tex]AlI_{3}[/tex]

As per the given balanced equation,

3 moles of [tex]I_{2}[/tex] are used to give 2 moles of [tex]AlI_{3}[/tex].

Atomic weight of iodine is 127 gm/ mole

So, molecular weight of iodine molecule = 254 gm/ mole

There for , we can say that 1 mole o iodine molecule contain 254 g

So ,Given 113 gm iodine contains how many moles?

  Moles of iodine = 113/254 = 0.44 moles

from the equation we can say that 3 moles of iodine used to give 2 moles of aluminum iodide.

So, 0.44 moles of iodine gives how many moles of aluminum iodide ?

   Moles of aluminum iodide = 0.44 × 2 ÷  3

                                             = 0.2965 moles

Molecular weight of one mole of aluminum iodide = atomic weight of Al + 3( atomic weight of iodine )

      = 408 gm

∴ 1 mole of aluminum iodide = 408 gm

so, 0.2965 moles of aluminum iodide = ?

            = 0.2964 × 408

            = 121 gm  Aluminum iodide formed.

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The noble gas configurations for

Li= [He] 2s¹, Na=[Ne] 3s¹ and K =[Ar] 4s¹.

Noble gas configurations are the term for the electronic configurations of the atoms for which the electronic configuration becomes very larger i.e, for the higher atomic numbers.

For the noble gas electronic configurations, the noble gas, which is before that atom is written.

So, the Lithium can be represented as [He] 2s¹.

So, the Sodium can be represented as [Ne] 3s¹.

So, the Potassium can be represented as [Ar] 4s¹.

Hence, the noble gas configurations for Lithium= [He] 2s¹, Sodium=[Ne] 3s¹ and potassium =[Ar] 4s¹.

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Answer:

A. Along warm-water currents from warmer regions to colder regions

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Explanation:

Answer:

Verdadero!
no se en que mas quieres que te ayude? o cual realmente quieres que sea la respuesta?

Answer:

2.52 g H₂

Explanation:

To find the mass of hydrogen gas, you need to (1) convert moles H₂O to moles H₂ (via mole-to-mole ratio from reaction coefficient) and then (2) convert moles H₂ to grams H₂ (via molar mass from periodic table values). When multiplying the given value by the mole-to-mole ratio, you need to use the coefficients of the balanced equation. An reaction is balanced once there is an equal amount of each element on both sides.

(Step 1)

The unbalanced equation:

Ca(s) + H₂O(l) ----> Ca(OH)₂(aq) + H₂(g)

Reactants: 1 calcium, 2 hydrogen, 1 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

The balanced equation:

1 Ca(s) + 2 H₂O(l) ----> 1 Ca(OH)₂(aq) + 1 H₂(g)

Reactants: 1 calcium, 4 hydrogen, 2 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

(Step 2)

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

(Step 3)

 2.50 moles H₂O              1 mole H₂                  2.016 g
---------------------------  x  -------------------------  x  ----------------------  =  2.52 g H₂
                                        2 moles H₂O                1 mole

39.96 g product form when 16.7 g of calcium metal completely reacts.

Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Equation:

[tex]Ca(s) + Cl_2(g)[/tex] → [tex]CaCl_2(s)[/tex]

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

[tex]m_{ca_C_l_2}[/tex]= 16.7 g Ca x [tex]\frac{1 mol \;of \;Ca}{40g Ca}[/tex] x [tex]\frac{1 mol \;of \;CaCl_2}{1 mol \;Ca}[/tex] x [tex]\frac{111g of \;CaCl_2}{1 mol \;CaCl_2}[/tex]

[tex]m_{ca_C_l_2}[/tex] = 39.96 g

Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.

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Answer:

4.458 L

Explanation:

Assuming the pressure remains constant  and assuming 24° C and 58° C

V1/T1  = V2/T2       Where T is in Kelvin

V1/T1  *  T2  = V2

4 / ( 273.15 +24)    *    ( 273.15 + 58)    =  4.458 L

The reason for this is that water is a polar molecule and one water molecule is attracted to the other by a hydrogen bond.

The term entropy refers to the degree of disorder in a molecule. The more disorderly a molecule is, the higher its entropy.

The fact that water is a polar molecule and one water molecule is attracted to the other by a hydrogen bond thus, two water molecules represent more entropy than two hydrogen molecules plus an oxygen molecule.

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Answer:

The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

In an endothermic reaction, Keq increases as the temperature increases and vice versa.

In an exothermic reaction, Keq decreases as the temperature increases and vice versa.

Therefore, the temperature is the only factor that affects the equilibrium constant of a reaction.

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The production of ammonia will be favored at high pressure and low temperature.

The term exothermic reaction has to do with a reaction in which the forward reaction is favored at lower temperatures.

Now looking at the reaction coordinate and the equation of the reaction, we know that the production of ammonia will be favored at high pressure and low temperature.

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Answer:

A

The H+ from acid and OH- from base forms water, the other parts form the salt.

Answer:

The Red Circles: Liquid, Blue and Yellow Circles: Solid, and Purple Circles: Gas

Explanation:

Should be it based on the picture and given information.

Answer:

nitrogen compounds in the air

Explanation:

Answer:

=6×10^7metre

Explanation:

By using formula,

F=GMm/d^2

Answer:

40 g= 6.022×10²³

x=1.4×10¹⁵

x=40g×6.022×10²³/1.4×10¹⁵

x=17.77×10⁸

Answer:

The time required to decompose the substance is 360 seconds.

Answer:

can change red litmus to blue litmus

Explanation:

please mark me as brainlest

The empirical formula would be  [tex]C_2H_3O_2[/tex] and the molecular formula would be  [tex]C_4 H_6 O_4[/tex]

From the illustration:

C = 40.6 g                   H = 5.1 g                      O = 54.2 g

Divide each element by its molar weight:

C = 40.6/12 = 3.4                    H = 5.1/1 = 5.1                  O = 54.2/16 = 3.4

Divide by the smallest:

C = 3.4/3.4 = 1                        H = 5.1/3.4 = 1.5                 O = 3.4/3.4 = 1

Thus, the empirical formula is [tex]C_2H_3O_2[/tex]

To find the molecular formula:

[ [tex]C_2H_3O_2[/tex]]n = molecular formula

where n = molar mass/empirical formula mass

Empirical formula mass = 24 + 3 + 32 = 59

n = 118.084/59 = 2

Thus, the molecular formula is [tex]C_4 H_6 O_4[/tex] which is more or less the same as the empirical formula.

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The Empirical formula will be C₂H₃O₂  and the Molecular formula would be  C₄H₆O₄

Empirical formula is a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

Molecular formula is a chemical formula that gives the total number of atoms of each element in each molecule of a substance.

Given ;

Divide each element by its molar weight:

Divide by the smallest Value:

Thus, the Empirical formula is C₂H₃O₂

Now, to find the molecular formula ;

[C₂H₃O₂ ]n = molecular formula

where n = molar mass / empirical formula mass

Empirical formula mass = 24 + 3 + 32 = 59

n = 118.084 / 59 = 2

[C₂H₃O₂ ]n = molecular formula

[C₂H₃O₂ ]2 = C₄H₆O₄

Thus, the Molecular formula is C₂H₃O₂

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Answer:

Ammonia is easily made in the laboratory by heating an ammonium salt, such as ammonium chloride NH4Cl with a strong alkali, such as sodium hydroxide or calcium hydroxide.

The gas may also be made by warming concentrated ammonium hydroxide.

Explanation:

2NH4Cl + Ca(OH)2 → CaCl2 + 2H2O + 2NH3(g)

There is no delay because the effects of gravity are constantly acting on bodies of water. Hence, option D is correct.

Gravitation or just gravity is the force of attraction between any two bodies.

The Moon exerts over twice the gravitational pull of the Sun on Earth's tides because of its proximity to Earth. -The lunar tidal bulges are about twice the size of the solar tidal bulges. -The Sun's contribution to the tides is less than that of the Moon.

When the sun and moon are perfectly unaligned (they form a 90-degree angle relative to the earth), there are still tides because the moon's gravitational gradient is stronger than the sun's. The sun's gravitational gradient never completely cancels out the moon's.

Hence, option D is correct.

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