Please help ASAP. Thanks so much.

Answer:

99% confidence interval is 0.07 < σ < 0.32

Step-by-step explanation:

Given that;

standard deviation s = 0.12 sec

s² = 0.12² = 0.0144

degree of freedom DF = n - 1 = 8 - 1 = 7

99% confidence interval

∝ = 1 - 99% = 1 - 0.99 = 0.01

now, we find x² critical values for ∝/2 = 0.005 and 1 - ∝/2 = ( 1 - 0.005) = 0.995, df = 7

The Lower critical value [tex]X^{2}_{\frac{\alpha }{2}},7[/tex] = 20.2777

The Upper critical value [tex]X^{2}_{1-{\frac{\alpha }{2}},7[/tex] = 0.9893

Now, confidence interval is given by

√[ ( (n-1)×s² ) / ( [tex]X^{2}_{\frac{\alpha }{2}},7[/tex] ) ] < σ < √[ ( (n-1)×s² ) / (  [tex]X^{2}_{1-{\frac{\alpha }{2}},7[/tex]  ) ]

so we substitute

√[ ( 7×0.0144 ) / ( 20.2777 ) ] < σ < √[ ( 7×0.0144 ) / ( 0.9893 ) ]

√[ ( 7×0.0144 ) / ( 20.2777 ) ] < σ < √[ ( 7×0.0144 ) / ( 0.9893 ) ]

√0.0049711 < σ < √0.10189

0.0705 < σ < 0.3192

Rounding to the nearest 2 decimal places

0.07 < σ < 0.32

Therefore; 99% confidence interval is 0.07 < σ < 0.32

Answer:

What are some awnsers :^

Answer:

37

Step-by-step explanation:

3 + 7 = 10

73 - 37 = 36

Answer:

The single decimal multiplier is 1.0296.

Step-by-step explanation:

Multipliers:

For a decrease of a%, we multiply by: [tex]\frac{100-a}{100}[/tex]

For a increase of a%, we multiply by: [tex]\frac{100+a}{100}[/tex]

For consecutive changes, we multiply the multipliers.

Decrease of 1%

Multiplication by [tex]\frac{100-1}{100} = \frac{99}{100} = 0.99[/tex]

Increase of 4%

Multiplication by [tex]\frac{100+4}{100} = \frac{104}{100} = 1.04[/tex]

Consecutive:

0.99*1.04 = 1.0296

The single decimal multiplier is 1.0296.

Answer:

the question is incorrectly written. please rewrite the question.

Answer:

No

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Identify Variables

Leg a = 7

Leg b = 16

Hypotenuse c = 18

Step 2: Check

Since we know that 305 does not equal 324, that means the side lengths do not form a Pythagorean triple.

Answer:

sin5A+sin3A=cos2A-cos6A

2SIN((5A+3A)/2)COS ((5A-3A)/2)=2SIN((2A+6A)/2)SIN((2A-6A)/2)

[tex] \frac{2 \sin(4a )cosa}{ - 2 \sin(4a) \sin(2a) } = 1[/tex]

[tex] - \frac{ \cos(a) }{2 \sin(a) \cos(a ) } = 1[/tex]

-1/2sinA=1

-1/2=sinA

sinA=sin(180+30),sin(330)

:.A=210,330

[tex]2688[/tex]

1) Simplify 2 × 8 to 16.

[tex]16 \times 12 \times 14[/tex]

2) Simplify 12 × 16 to 192.

[tex]192 \times 14[/tex]

3) Simplify.

[tex]2688[/tex]

So, therefor, the answer is, 2688.

Answer:

The slope is 300

Step-by-step explanation:

Rise over run we see two points how many times do we rise and run to get there?

(Slope= rise/run)

So you rise 300 times (Since half of 600 is 300) then you run 1 time which is 300/1 which is 300

Answer:

-0.479

Step-by-step explanation:

[tex]sin(cos(4 \frac{\pi}{3} ) = - sin( \frac{1}{2} ) = - 0.479[/tex]

Answer:

Answer is B : -1/2

Step-by-step explanation:

correct on edge

Answer:

Step-by-step explanation:

slope, m=Δ y/ Δx or m= y₂-y₁/(x₂-x₁)

m=9-(-14)/(6-4)=23/2=11.5

Answer:

D. 4 centimeters, 6 centimeters, 9 centimeters

Step-by-step explanation:

Considering side length for forming a triangle, most of the time it is about Triangle Inequality Theorem, which for 3 sides length a,b,c, it must satisfy the following set of inequalities:  

[tex]a+b>c\\a+c>b\\b+c>a[/tex]

By checking each of them only D satisfy:

[tex]4+6=10>9\\6+9=15>4\\9+4=13>6[/tex]

For simplicity you only have to check if the two shortest sides add up to be larger than the longest side:

[tex]4+6>9[/tex]

Answer:

Ik this is late but the answer is 4(4x + 7)

Step-by-step explanation:

The expression by using the greatest common factor is 4(4x + 7).

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the expression is 16x + 28. The expression by using the greatest common factor is calculated as,

E = 16x + 28

E = 4(4x + 7)

Therefore, the expression using the greatest common factor is 4(4x + 7).

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Answer: the slope is 0 if you are talking about what is the slope of 2,-3 and -2,-3 because that’s what is in the picture

Step-by-step explanation: slope is the y values over the x values

Answer:

John sells candy at the lowest price.

Step-by-step explanation:

If John sells 6 candies at 10$, then that's what's called a ratio between the price and the candy. We can double the amount of candy and the price to $20 for each 12 candies, $30 for 24, $40 for 36, etc. But it would still maintain the ratio of 6 candies for each 10$. Adam however, sells candy at 13 pieces for $20. We can divide the ratio down to 6.5 candies for 10$. But since we "can't" split a candy in half, we'll round it to 7 pieces for 10$, which costs more than 6 for 10$: Therefore, John sells candy at the lower price.

Answer:

either she's nervous and doesn't know how to talk or she's mad at you. i would say she doesn't like u but she started the convo

Answer:

[tex]\boxed {\boxed {\sf No}}[/tex]

Step-by-step explanation:

If a triangle is a right triangle, it can satisfy Pythagorean Theorem.

[tex]a^2+b^2=c^2[/tex]

where a and b are the legs and c is the hypotenuse.

12 and 84 are the legs because are they shortest. 85 is the hypotenuse because it is the longest side.

[tex]a= 12 \\b=84 \\c=85[/tex]

Substitute the values into the formula.

[tex](12)^2+(84)^2=(85)^2[/tex]

Solve the exponents.

[tex]144+7056=7225[/tex]

Add on the right side.

[tex]7200\neq 7225[/tex]

7220 is not equal to 7225, so these sides cannot be a right triangle.

Answer:

(2, -8)

Step-by-step explanation:

y=6x-20

y=-4x

since the bottom equation shows us that y=-4x, we can substitute 4x in place of y in the first equation and solve:

-4x=6x-20

-10x=-20

x=2

since the bottom equation shows y=-4x, and we already know that x=2:

y=-4(2)

y=-8

(2, -8)

Answer:

323.5 square inches

Step-by-step explanation:

The cereal box is not shown. However, the given details are enough to arrive at a solution

[tex]Length = 13.5in[/tex]

[tex]Width = 2.5in[/tex]

[tex]Height = 8in[/tex]

Required

The total surface area (TSA)

This is calculated as:

[tex]TSA = 2 * (Length * Width + Length * Height + Width * Height)[/tex]

[tex]TSA = 2 * (13.5 * 2.5 + 13.5 * 8 + 2.5 * 8)[/tex]

[tex]TSA = 2 * (161.75)[/tex]

[tex]TSA = 323.5[/tex]

Hence, the total surface area is 323.5 square inches

13.3 is the rate boom

Answer:

Step-by-step explanation:

3 219494

Answer:

[tex]Area = x^2- 25[/tex]

[tex]Area =9x^2 +24x + 16[/tex]

[tex]Length = (3x -2)[/tex]

[tex]Speed = \left(y^2-3y+1\right)[/tex]

[tex]Product = 3m^3 + 6m^2 - 6m[/tex]

Step-by-step explanation:

Solving (1):

[tex]Length = (x + 5)[/tex]

[tex]Width = (x - 5)[/tex]

Required

Calculate Area

[tex]Area = Length * Width[/tex]

[tex]Area = (x + 5) * (x - 5)[/tex]

[tex]Area = x^2 + 5x - 5x - 25[/tex]

[tex]Area = x^2- 25[/tex]

Solving (2):

Given

[tex]Length = (3x + 4)[/tex]

Required: Calculate Area

[tex]Area =Length * Length[/tex]

[tex]Area =(3x + 4) * (3x + 4)[/tex]

[tex]Area =9x^2 + 12x + 12x + 16[/tex]

[tex]Area =9x^2 +24x + 16[/tex]

Solving (3):

[tex]Area = 3x^2 + 7x - 6[/tex]

[tex]Width = x + 3[/tex]

Required: Calculate Length

[tex]Area = Length * Width[/tex]

[tex]Length = \frac{Area}{Width}[/tex]

[tex]Length = \frac{3x^2 + 7x - 6}{x + 3}[/tex]

Factorize the numerator

[tex]Length = \frac{3x^2 + 9x -2x - 6}{x + 3}[/tex]

[tex]Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}[/tex]

[tex]Length = \frac{(3x -2) (x + 3)}{x + 3}[/tex]

Divide by x + 3

[tex]Length = (3x -2)[/tex]

Solving (4):

[tex]Distance = (2y^3 - 7y^2 + 5y -1)[/tex]

[tex]Time = 2y - 1[/tex]

Required: Determine the average speed

This is calculated as:

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}[/tex]

Factorize the numerator

[tex]Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}[/tex]

[tex]Speed = \left(y^2-3y+1\right)[/tex]

Solving (5):

Multiply [tex](m^2 + 2m - 2)[/tex] by sum of [tex](m + 3)[/tex] and [tex](2m - 3)[/tex]

First, calculate the sum:

[tex]Sum = m + 3 + 2m - 3[/tex]

[tex]Sum = m + 2m+3 - 3[/tex]

[tex]Sum = 3m[/tex]

Then, the product

[tex]Product = (m^2 + 2m - 2)(3m)[/tex]

[tex]Product = 3m^3 + 6m^2 - 6m[/tex]

Answer:

Step-by-step explanation:

Solving (1):

Required

Calculate Area

Solving (2):

Given

Required: Calculate Area

Solving (3):

Required: Calculate Length

Factorize the numerator

Divide by x + 3

Solving (4):

Required: Determine the average speed

This is calculated as:

Factorize the numerator

Solving (5):

Multiply  by sum of  and  

First, calculate the sum:

Then, the product

Answer:

24, 32, 40, or 48

Step-by-step explanation:

Count by 8.

8

16

24

32

40

48

56

The multiple of 8 that is between 20 and 50 are 24, 32, 40 and 48.

A multiple in math are the numbers you get when you multiply a certain number by an integer.

Here, multiples of 8 with 50 are

8, 16, 24, 32, 40, 48

So, the multiple of 8 between 20 and 50 are 24, 32, 40 and 48

Therefore, the multiple of 8 that is between 20 and 50 are 24, 32, 40 and 48.

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Answer:

d

Step-by-step explanation:

Answer:

ummmmmmm okkkkkkkkkkk

Step-by-step explanation:

dddddddddddddddddddddddddddddd

Answer:

z = 5

Step-by-step explanation:

Answer:

[tex]\displaystyle dy = 25e^{5x}dx\\dy = 3.27 \cdot 10^7[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Calculus

Derivatives

Derivative Notation

Differentials

Basic Power Rule:

eˣ Derivative: [tex]\displaystyle \frac{dy}{dx}[e^u] = u'e^u[/tex]

Step-by-step explanation:

Part A

Step 1: Define

[tex]\displaystyle y = 5e^{5x}[/tex]

Step 2: Differentiate

Part B

Step 1: Define

[Differential] [tex]\displaystyle dy = 25e^{5x}dx[/tex]

[Given] x = 3, dx = 0.4

Step 2: Evaluate

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Differentials

Book: College Calculus 10e