Please answer this correctly

Answer:

-3

Step-by-step explanation:

Answer:

The experimental group in this case are the group of bees that are put in the small cage.

Step-by-step explanation:

The experimental group is the group of subjects that participate in the test. They are usually assigned to the treatments in study. In some cases there is a control group, with no assigned treatment.

In this case, the bees that she put in the cage, and they are not assigned to a particular treatment. It can be considered a control group.

Answer:

work is shown and pictured

The factor of the equation x² - 9x + 14 is,

⇒ (x - 2)

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The equation is,

⇒ x² - 9x + 14

Now, We can find the factor of the expression as;

⇒ x² - 9x + 14

⇒ x² - 7x - 2x + 14

⇒ x (x - 7) - 2 (x - 7)

⇒ (x - 7) (x - 2)

Thus, The factor of the equation x² - 9x + 14 is,

⇒ (x - 2)

Learn more about the mathematical expression visit:

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Answer:

# of broken crayons    # of boces

           1-5                            1

          6-10                          4

          11-15                          5

          16-20                        3

          21-25                         1

Step-by-step explanation:

1-5: 4 (1 number)

6-10: 6, 6, 8, 9 (4 numbers)

11-15: 12, 13, 14, 14, 15 (5 numbers)

16-20: 17, 17, 19 (3 numbers)

21-25: 24 (1 number)

Answer:

Number of broken crayons Number of boxes

1-5 = 4

6-10 = 9

11-15 = 14

16-20 =19

21-25 =24

Step-by-step explanation:

To find the number of boxes compared to the number of broken crayons you have to find 5 consecutive (hence there being five boxes to fill in) numbers with a constant rate of change. Start with the largest number possible that you can pick and then find the second largest so 24 and 19 the rate of change is 5. Compared to 17 and 19 the rate of change is 2 so it doesn’t have the same rate of change but if you try 19-5 you get 14 which is an option if you subtract 14-5 you get 9 which is another option 9-5 is 4 the lowest number you could possibly pick and they all have a constant rate of change of 5 so the answer is correct.

Answer:

isosceles

Step-by-step explanation:

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

[tex]E = P*I*t[/tex]

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

[tex]T = E + P[/tex]

In this question:

Rate of 10%, so I = 0.1.

9 months, so [tex]t = \frac{9}{12} = 0.75[/tex]

How much should he pay for a note that will be worth $3,000 in 9 months?

We have to find P for which T = 3000. So

[tex]T = E + P[/tex]

[tex]3000 = E + P[/tex]

[tex]E = 3000 - P[/tex]

Then

[tex]E = P*I*t[/tex]

[tex]3000 - P = P*0.1*0.75[/tex]

[tex]1.075P = 3000[/tex]

[tex]P = \frac{3000}{1.075}[/tex]

[tex]P = 2790.7[/tex]

He should pay $2,790.7.

Answer:

At most 9.12 joules should be required for the bottom 80% of bottled water

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 8.7, \sigma = 0.5[/tex]

How much energy should be required for the bottom 80% of bottled water?

At most the 80th percentile.

The 80th percentile is X when Z has a pvalue of 0.8. So it is X when Z = 0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.84 = \frac{X - 8.7}{0.5}[/tex]

[tex]X - 8.7 = 0.84*0.5[/tex]

[tex]X = 9.12[/tex]

At most 9.12 joules should be required for the bottom 80% of bottled water

Answer: 0.0965

Step-by-step explanation:

This would happen if:

First toss: Here we must have any number that is not 6.

the options are 1, 2, 3, 4, 5 so the probablity is p1 = 5/6

The same happens for the second toss, p2 = 5/6

and for the third one: p3 = 5/6

for the fourth toss, person B must roll a 6, so the probability here is p4 = 1/6

Now, the joint probability is equal to the product of the probabilities for each toss, this is:

P = p1*p2*p3*p4 = (5/6)^3*(1/6) = 0.0965

Answer:

Step-by-step explanation:

The following is the information provided

number of students is 5

The number of math major = 3

The number of statistic major = 2

Label math students as A, B, C

And statistic students as D, E

The total number of ways to select two students from 5 students is 10

The sample space is S = {AB,AC,BC,AD,AE,BD,BE,CD,CE,DE}

Yes , in the sample space the events are equally alike

What is the probability that both selected students are statistics majors

The selected students of statistic major are DE

the probability that both selected students are statistics majors is [tex]\frac{1}{10}[/tex]

= 1/10

What is the probability that both students are math majors

The selected students of statistic major are AC,AB,BC

the probability that both selected students are math majors is [tex]\frac{3}{10}[/tex]

= 3/10

What is the probability that at least one of the students selected is a statistics major

Number of ways to select at least one of the students selected is a statistic major is {AD,AE,BD,BE,CD,CE,DE}

the probability that at least one of the students selected is a statistics major is [tex]\frac{7}{10}[/tex]

7/10

What is the probability that the selected students have different majors

Number of ways to select students with different major is  {AD,AE,BD,BE,CD,CE,}

the probability that the selected students have different majors is [tex]\frac{6}{10}[/tex]

6/10

Answer:

No.

Step-by-step explanation:

A point has no length, height or depth. It only has position.

A line has one dimensional length.

[tex]g(x)=4(x+1)-2[/tex]

[tex]g(x)=4x+4-2[/tex]

[tex]g(x)=4x+2[/tex]

Image attached below for graph.

Answer:

The correct option is (b) random.

Step-by-step explanation:

A simple random sample is a part of a statistical population in which every individual of the population has an equal probability of being selected.

Assigning each individual of the population a unique number and using a computer or random number generator for selection is a procedure to select a simple random sample.

In this case the researcher has a computer randomly generate several hundred numbers, and those numbers are used to select names from the list to form a sample.

The procedure indicates that the researcher used a simple random sampling technique to select the sample.

Thus, the correct option is (b).

Answer:

idk what you mean

Step-by-step explanation:

idk

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is [tex]\mathbf{P(X>1100n) = 0.158655}[/tex]

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

[tex]f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0[/tex]

Thus, the expected  total claim amount [tex]\mu[/tex] =  1000

The variance of the total claim amount [tex]\sigma ^2 = 1000^2[/tex]

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

[tex]P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})[/tex]

[tex]P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})[/tex]

[tex]P(X>1100n) = P(Z> \dfrac{10*100}{1000})[/tex]

[tex]P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345[/tex]

[tex]\mathbf{P(X>1100n) = 0.158655}[/tex]

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is [tex]\mathbf{P(X>1100n) = 0.158655}[/tex]

Answer:

[tex]y=0.25x+18[/tex]

Step-by-step explanation:

So first we take the equation we are given and write it in slope-intercept form (y = mx + b):

[tex]y+4= \frac{1}{4} (x+5)\\\\y+4=0.25x +1.25\\\\y=0.25x-2.75[/tex]

Now we know parallel lines have the same slope, so the line we are looking for has a slope of 0.25.

so we can start to set up our equation:

[tex]y=0.25x+b[/tex]

and then substitue in the point (8,20) to find the y-intercept.

[tex]20=0.25(8)+b\\20=2+b\\b=18[/tex]

So now we have our equation:

[tex]y=0.25x+18[/tex]

Hope this helps!

Answer:

So first subtract 14 from 32

That means that -6y+4y = 18

Simplify the left side 4-6=-2

-2y = 18

Divide by -2

-9 = y

Step-by-step explanation:

Answer:

-9

Step-by-step explanation:

-6y+14+4y=32

Combine like terms

-2y +14 = 32

Subtract 14 from each side

-2y +14-14 = 32-14

-2y =18

Divide each side by -2

-2y/-2 = 18/-2

y = -9

Answer:

y=4x

Step-by-step explanation:

an independent variable is the variable  that is changed or controlled in an experiment or observation to test the effects on the dependent variable

a dependent variable is variable being tested and measured in a scientific experiment

in this case, the number of help desk tickets  closed out is dependent on the number of hours the individual works so y is the number of tickets closed (dependent variable). The number of tickets closed of will be 4 multiplied by the number of hours worked i.e. y=4x

Answer:

a= 0

b= [tex]-\frac{\sqrt{42} }{12}[/tex]

Step-by-step explanation:

We can rewrite the expression to be:

[tex]\frac{i\sqrt{7} }{i^{2}\sqrt{24} }[/tex]

We then can cancel out the i and we get

[tex]\frac{\sqrt{7} }{\sqrt{24} i}[/tex]

Can be rewritten as

[tex]\frac{\sqrt{7} }{2\sqrt{6} i}[/tex]

We then rationalize and get

[tex]-\frac{\sqrt{42} }{12} i[/tex]

Answer:

Please show the graph choice it sounds linear xy (positive)

or parallel depending on how much pens and pencils were.

We know $18 purchased more than 1 pack so this divided by notebook shws us at least 6 per notepack paper or so many packs of pen that cost $18 ffor pens were ratio to 1 pack of paper. ie) if pens were £2 pack then while we understand it could have been as many as 9 we divide by how many we find or bought by the amount of notepaper books to determine the rate and distribution of the money.    

Step-by-step explanation:

$39 - $18 = $21 left over

21/3 = 7 packs of note paper can be purchased..

Answer:

x =-5

Step-by-step explanation:

Answer:

x=-5

Step-by-step explanation:

Answer:

28

Step-by-step explanation:

number of copies done in 5 minute 15 seconds = 147

60 seconds is equal to 1 minute

1 second is equal to 1/60 minutes

therefore 15 seconds is equal to 1/60 * 15 minutes = 1/4 minutes

thus,

number of copies done in 5 1/4 minute = 147

number of copies done in 1 minute = 147/ 5 1/4   (as 147/21 = 7)

                                                = 147/ (21/4) = 7*4 = 28

Thus, A copy machine makes 28 copies in 1 minute.

Answer:

Step-by-step explanation:

Corresponding means for population 1 and population 2 form matched pairs.

The data for the test are the differences between the mean for population 1 and mean for population 2.

μd =​ the mean for population 1 minus the mean for population 2.

Population 1 population 2 diff

19 24 - 5

25 27 - 2

31 36 - 5

52 53 - 1

49 55 - 6

34 34 0

59 66 - 7

47 51 - 4

17 20 - 3

51 55 - 4

Sample mean, xd

= (- 5 - 2 - 5 - 1 - 6 + 0 - 7 - 4 - 3 - 4)/10 = - 3.7

xd = - 3.7

Standard deviation = √(summation(x - mean)²/n

n = 10

Summation(x - mean)² = (- 5 + 3.7)^2 + (- - 2 + 3.7)^2 + (- 5 + 3.7)^2+ (- 1 + 3.7)^2 + (- 6 + 3.7)^2 + (0 + 3.7)^2 + (- 7 + 3.7)^2 + (- 4 + 3.7)^2 + (- 3 + 3.7)^2 + (- 4 + 3.7)^2 = 73.7

Standard - eviation = √(73.7/10

sd = 2.71

For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 10 - 1 = 9

The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (- 3.7 - 0)/(2.71/√10)

t = - 4.32

We would determine the probability value by using the t test calculator.

p = 0.00097

Since alpha, 0.1 > than the p value, 0.00097, then we would reject the null hypothesis. Therefore, at 0.1 level of significance, we can conclude that these data are sufficient to indicate that the mean for population 2 is larger than that for population 1.

3) for population 1,

Mean = (19 + 25 + 31 + 52 + 55 + 34 + 59 + 47 + 17 + 51)/10 = 38.4

Summation(x - mean)² = (19 - 38.4)^2 + (25 - 38.4)^2 + (31 - 38.4)^2+ (52 - 38.4)^2 + (49 - 38.4)^2 + (34 - 38.4)^2 + (59 - 38.4)^2 + (47 - 38.4)^2 + (17 - 38.4)^2 + (51 - 38.4)^2 = 2042.4

Standard deviation, s1 = √2042.4/10 = 14.3

for population 2,

Mean = (24 + 27 + 36 + 53 + 55 + 34 + 66 + 51 + 20 + 55)/10 = 42.1

Summation(x - mean)² = (24 - 42.1)^2 + (27 - 42.1)^2 + (36 - 42.1)^2 + (53 - 42.1)^2 + (55 - 42.1)^2 + (34 - 42.1)^2 + (66 - 42.1)^2 + (51 - 42.1)^2 + (20 - 42.1)^2 + (55 - 42.1)^2 = 2248.9

Standard deviation, s2 = √2248.9/10 = 15

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

For a 90% confidence interval, we would determine the z score from the t distribution table because the number of samples are small

Degree of freedom =

(n1 - 1) + (n2 - 1) = (10 - 1) + (10 - 1) = 18

z = 1.734

x1 - x2 = 38.4 - 42.1 = - 3.7

√(s1²/n1 + s2²/n2) = √(14.3²/10 + 15²/10)

= 6.55

Margin of error = 1.734 × 6.55 = 11.4

The 90% confidence interval is

- 3.7 ± 11.4

Answer:

100 muffins

Step-by-step explanation:

We can use a ratio to solve

6 cups          15 cups

-------------   = -----------

40 muffins     x muffins

Using cross products

6x = 40*15

Divide each side by 6

6x/6 = 40*15/6

x =100

100 muffins

Answer:

100 muffins

Step-by-step explanation:

If she could bake 40 muffins with 6 cups, then she could bake 80 muffins with 12 cups. Then, we have 3 cups left over, which is half of 6, meaning she can only bake half of her regular amount with 3 cups, which would be 20. 80+20=100

40+40+20=100

Answer:

A

Step-by-step explanation:

Volume of cone = (1/3) πr²h

Answer:

y = x + 5

Step-by-step explanation:

Perpendicular slope is opposite inverse so the perpendicular slope to -1x would be 1x

Then find b in y=mx+b

Plug in all the number

y=-9

x=-4

m=1

So, -4=1(-9)+b

1×-9=-9

+9 to both sides

5=b

Therefore,

y=x+5

Answer:

El tejado tenía un ancho de 31.4 m.

Step-by-step explanation:

Tenemos un techo rectangular, con un largo de 29.7 m y un ancho x, que debemos calcular.

Entonces, la superficie del tejado es:

[tex]S=29.7x\;\,\text{[m}^2\text{]}[/tex]

Las locetas tienen una superficie de 25x19 cm,  de las cuales 1/5 se pierde en la colocación. La superficie eficaz que ocupa cada loceta una vez colocada es:

[tex]S_L=(25\cdot19)\cdot(1-1/5)=475\cdot(0.8)=380\;\text{cm}^2[/tex]

Entonces, si se utilizaron 24552 locetas para cubrir todo el techo, podemos expresar la superfice del techo como:

[tex]S=24552\;\text{locetas}\;\cdot380\dfrac{\text{cm2}}{\text{loceta}}\cdot \left(\dfrac{1\text{m}}{100\text{cm}}\right)^2=\dfrac{24552\cdot380}{10000}\;\text{m2}=932.976\;\text{m2}[/tex]

Podemos calcular x igualando este último resultado con la primer ecuación:

[tex]S=29.7x=932.976\\\\x=932.976/29.7=31.413\approx31.4[/tex]

Answer:

d = 2

Step-by-step explanation:

Using the formula

A=pq/2

Dont forget to click THANKS

Answer:

618

Step-by-step explanation:

l x w

34x5

14x27

5x14

618

Answer:both sides will be equal

Step-by-step explanation: