Please answer all three questions Pleaseeeeee tysmm <3

Answer:

first option

Step-by-step explanation:

[tex]\frac{(2g^5)^3}{(4h^2)^3}\\= \frac{8g^1^5}{64h^6} \\= \frac{g^1^5}{8h^6}[/tex]

Answer:

First figure out the angle measure of CBA and DBE to find out what Angle measure of ABE is.

Angle CBA and DBE are vertical angles, meaning they are congruent.

so set the equation as:

(2x+21)=(5x)

21=5x-2x

21=3x

x=7

It doesn't matter in which angle you plug 7 you get the same angle measure, so : 5x=5(7)=35 degrees

So to find angle measure of ABE:

We know that ABE and DBE form linear pair, so

180-35=145 degrees

145 degrees is the answer.

Hope it helps!

Answer:

∠ABE = 145°

Step-by-step explanation:

because angle CBA and ABE form a straight line, we know that they must add together to 180 degrees

and because DBE and ABE also form a straight line/angle, they must add together to 180 degrees

we can set this up as a system of equations (I will be writing ABE as "y")

2x + 21 + y = 180

5x + y = 180

We can combine this to beL

2x + 21 + y = 5x + y

 - 2x              -2x

21 + y = 3x + y

   - y       - y

21 = 3x

x = 7

If we plug this back into our original equations (which is set to 180 degrees), we can find y

2(7) + 21 + y = 180

14 + 21 + y = 180

35 + y = 180

- 35       - 35                  

y = 145

(remember, "y" is angle ABE)

we can check this value (ABE = 145) by substituting our second equation

5(x) + ABE = 180

35 + 145 = 180

       180 = 180

(TRUE)

so, the measure of ∠ ABE is 145°

hope this helps!!

The function g(x) is obtained by the transformation of the function f(x) is translated towards left by 1 unit.

A statement, principle, or policy that creates the link between two variables is known as a function.

The function f(x) is given below.

f(x) = 2ˣ

Then the function g(x) is given as

[tex]\rm g(x) = 2^{x + 1}[/tex]

The function g(x) is obtained by the transformation of the function f(x) is translated towards left by 1 unit.

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The area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

It is defined as the four-sided polygon in geometry having four edges and four corners. It has one pair of opposite congruent angles and the diagonals of a kite are perpendicular.

We have a quadrilateral shown in the picture.

The diagonal divides the quadrilateral into two triangles

The area of the quadrilateral = area of the triangle ADC + area of the

                                                   triangle ADB

= (1/2)3.42×4.39 + (1/2)5.44×3.42

= 7.5069 + 9.3024

= 16.80 square units

Thus, the area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

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Answer:

Two functions which satisfies the H(x) are f(x) = 2x - 4, (x)    = x⁵  and

f(x)  = 2x,  g(x)  = x⁵ - 2

Step-by-step explanation:

The given question is based on the decomposition of a given function into two functions

Decomposition of a function :- functional decomposition is the process of resolving a functional relationship into its constituent parts in such a way that the original function can be reconstructed from those parts by function composition

so the function given in the question is H(x) = 2x⁵ - 4

now by using the concept of decomposition of a function we can find two functions f and g

therefore,

f(x) = 2x - 4

and    g(x)    = x⁵

similarly we can find another pair which satisfies the function H(x)

f(x)  = 2x

and g(x)  = x⁵ - 2

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Part 1: Finding [tex](g\circ h)(x)[/tex]

Note that [tex](g\circ h)(x)=g(h(x))[/tex]

In this case, it is [tex]g(\sqrt{x+4})=(\sqrt{x+4})^{2}-3=x+4-3=\boxed{x+1}[/tex]

Part 2: Domain

For the domain, we need to make sure the radicand of h(x) is greater than or equal to 0, so we get [tex]x+4 \geq 0 \longrightarrow \boxed{x \geq -4}[/tex]

The composition (g ο h) = x+ 1 and the domain of the composition (g ο h) is = (-∞ , ∞).

The composition (g ο h) means that the function g(x) composes of h(x) that is g(h(x)). So we have to put the the values of h(x) in the function g(x).

Now here it is given that

g(x) = [tex]x^{2} -3[/tex] and h(x) = [tex]\sqrt[2]{x + 4}[/tex]

so to get (g ο h) we have to replace the x with the value of h(x)

That gives :

g(h(x)) = [tex]\sqrt[2]{x+4} ^{2} - 3[/tex]

g(h(x)) = x + 4 - 3 = x +1

So the composition (g ο h) = x+ 1

The domain of the function is the values of x for which the function is defined.

so the domain of the composition (g ο h) is :

g(h(x)) = x+ 1

This function is undefined for no value of x .

So its domain is (-∞ , ∞).

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Answer: The graph crosses the x-axis at x = 2.

Step-by-step explanation:

The root has a multiplicity of 3, meaning that it crosses the x axis at x=2.

Answer:

The answer is C. Hope it helps

Answer:

its $95 dollars

Step-by-step explanation:

Answer:

51° and 39°

Step-by-step explanation:

x + 4x - 165 = 90

5x = 90 + 165

5x = 255

x = 255 / 5

x = 51

4 x 51 = 204

204 - 165 = 39

2 angles are 51 and 39

The ranges of batting averages were least common among the players is 0.320-0.329 and 0.360-0.369 , Option D is the correct answer.

Average is the middle value of a set of data points , calculated by summing all the data points and then dividing by the number of points.

It is given that , 30 best batting averages for a semi-pro baseball league.

The ranges of batting averages were least common among the players

To find this , it has to be observed that which range has the lowest frequency

The range 0.320-0.329 and 0.360-0.369 has frequency of 1 which is the least among all

Hence Option D is the correct answer.

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Answer:

vector VW= w - v

vector WV= v - w

Step-by-step explanation:

there are no figures to solve the question so i'll just write the formula..

vector VW= w - v

vector WV= v - w

Answer:

The plots are (0,2) (1,-1)

Step-by-step explanation:

a slanted line starting from top left corner ending in the bottom right

Answer:

3.8918

round the 1 from the 8 to get 2

3.892

Answer: 2

Step-by-step explanation:

[tex]a_{n}=2(2)^{n-1}\\\\a_{1}=2(2)^{1-1}=2\\\\a_{2}=2(2)^{2-1}=4[/tex]

Average rate of change:

[tex]\frac{4-2}{2-1}=\boxed{2}[/tex]

should i create the world problem with 12 3 and 9?

The count of patients needing a blood transfusion can be modelled as a continuous distribution.

A continuous distribution is a distribution that can take on an infinite number of possible values. A continuous distribution is not defined at specific values. The number of patients can be 1 or 10 or 50 or even 0.

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To simplify the equation, we have y = [tex]\frac{3}{4x^2 + 24x} + 8[/tex]

Given the expression

y-8 = 3/4x [x-(-6)]

First, expand the bracket

[tex]y - 8[/tex]= [tex]\frac{3}{4x^2 + 24x}[/tex]

Make 'y' the subject of formula

y = [tex]\frac{3}{4x^2 + 24x} + 8[/tex]

Thus, to simplify the equation, we have y = [tex]\frac{3}{4x^2 + 24x} + 8[/tex]

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Answer: 72

Step-by-step explanation:

[tex]\sum^{3}_{t=0} (6t^{2}-3)=(6(0)^{2}-3)+(6(1)^{2}-3)+(6(2)^{2}-3)+(6(3)^{2}-3)=\boxed{72}[/tex]

Answer:

Step-by-step explanation:

Solution

17 = a + b

b =  a + 1                    Substitute b into the top equation

17 = a + a+1                Combine

17 = 2a + 1                  Subtract 1 from both sides

17-1 = 2a+1-1               Combine

16 = 2a                       Divide both sides by 2

16/2 = 2a/2

a = 8

b = 8 + 1 = 9

Answer

a = 8

b = 9

Answer:

1.6

Step-by-step explanation:

4,4-2.8 = 1.6

6-4.4 = 1.6

7.6-6 = 1.6

Then common difference is 1.6

Answer: Figure QRTS is congruent to figure Q'R'T'S'.

Step-by-step explanation:

A reflection is a rigid motion, and rigid motions preserve congruency.

Answer:

A = { x:x >3 ,where x --> R}

B = { x:x <4, where x --> R}

Y = { x:x is month of year with more than 30 days}

W = { x:x is all days of a week}

Answer:

8x + 100

Step-by-step explanation:

Your answer is correct! But because the equation is already set to "y =", you do not need the "f(x)" in your equation.

Answer:

[tex]\text{B}) \text{ } -3 < x < -1\\\text{D}) \text{ } 2 < x < \infty[/tex]

Step-by-step explanation:

The graph lies below the x-axis.

Answer:

4 r^3

Step-by-step explanation:

sqrt ( 16 r^6 )    = sqrt ( 4^2 * (r^3)^2  )    =   4 r^3

The cost of goods sold is $10,258 million and the Cash paid to supplier is $10,447 million.

a. Cost of goods sold

Cost of Goods Sold=Beginning Inventories + Purchases – Ending Inventories

Cost of goods sold = $1,997 + $10,392 - $2,131

Cost of goods sold = $10,258

b. Cash paid to supplier

Cash paid=2015 Beginning balance  + Purchases - 2015 Ending balance

Cash paid = $1,181 + $10,392 - $1,126

Cash paid = $10,447

Therefore the cost of goods sold is $10,258 million and the Cash paid to supplier is $10,447 million.

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Answer:

length=22 [cm].

Step-by-step explanation:

1) if the length is 'l' and the width is 'w', then it is possible

2) to write the given perimeter: 62=2(l+w), - this is the 1st equation of system;

3) to write the condition 'the length of a rectangle is 5 cm less than 3 times its width' as 3w-5=l, - this is the 2d equation of the system.

4) using two equations above it is possible to make up the next system:

[tex]\left \{ {{2(w+l)=62} \atop {3w-5=l}} \right. \ = > \ \left \{ {{w+l=31} \atop {3w-l=5}} \right. \ = > \ \left \{ {{l=22} \atop {w=9}} \right.[/tex]

5) finally, the length=22 [cm].