Please answer all three answers

Answer: 2.67 m/s

Explanation:

Given

Mass of block A  is [tex]m_a=2\ kg[/tex]

mass of block B is [tex]m_b=3\ kg[/tex]

The initial velocity of block A [tex]u_a=5\ m/s[/tex]

the initial velocity of block B is [tex]u_b=0[/tex]

After collision velocity of block A is [tex]v_a=1\ m/s[/tex]

Conserving momentum

[tex]m_au_a+m_bu_b=m_av_a+m_bv_b\\\\2\times 5+3\times0=2\times 1+3\times v_b\\\\v_b=\dfrac{8}{3}=2.67\ m/s[/tex]

The momentum of block A after the collision is [tex]P_a=2\times 1=2\ kg.m/s[/tex]

Therefore, there is no change in sign.

Answer

t = 367.77 s = 6.13 min

Explanation:

According to the law of conservation of energy:

[tex]Heat\ Supplied\ By \ Heater = Heat\ Absorbed\ by\ Glass + Heat\ Absorbed\ by\ Water\\Pt = m_gC_g\Delta T_g + m_wC_w\Delta T_w\\[/tex]

where,

P = Electric Power of Heater =  300 W

t = time required = ?

m_g = mass of glass = 300 g = 0.3 kg

m_w = mass of water = 250 g = 0.25 kg

C_g = speicific heat of glass = 840 J/kg.°C

C_w =  specific heatof water = 4184 J/kg.°C

ΔT_g = ΔT_w = Change in Temperature of Glass and water = 100°C - 15°C

ΔT_g = ΔT_w = 85°C

Therefore,

[tex](300\ W)(t) = (0.3\ kg)(840\ J/kg.^oC)(85^oC)+(0.25\ kg)(4184\ J/kg.^oC)(85^oC)\\[/tex]

t = 367.77 s = 6.13 min

Answer:

v = 16.11 m / s

Explanation:

For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation

starting point. When the spring is compressed

        Em₀ = K_e + U = ½ k x² + m g x ’

final point. The point where it leaves the platform

        Em_f = K = ½ m v²

energy is conserved

         Em₀ = Em_f

         ½ k x² + m g x ’= ½ m v²

         v² = [tex]\frac{k}{m}[/tex]  x² + g x

let's calculate

         v² = [tex]\frac{8700}{55}[/tex]  1.25² + 9.8 1.25

         v² = 247.159 + 12.25 = 259.409

         v = 16.11 m / s

Answer:

ΔT = 0.02412 s

Explanation:

We will simply calculate the time for both the waves to travel through rail distance.

FOR THE TRAVELING THROUGH RAIL:

[tex]T_{rail} = \frac{Distance}{Speed\ of\ Sound\ in\ Rail}\\\\T_{rail} = \frac{8.8\ m}{5950\ m/s}\\\\T_{rail} = 0.00148\ s[/tex]

FOR THE WAVE TRAVELING THROUGH AIR:

[tex]T_{air} = \frac{Distance}{Speed\ of\ Sound\ in\ Air}\\\\T_{air} = \frac{8.8\ m}{343\ m/s}\\\\T_{air} = 0.0256\ s[/tex]

The separation in time between two pulses can now be given as follows:

[tex]\Delta T = T_{air}-T_{rail} \\\Delta T = 0.0256\ s - 0.00148\ s\\[/tex]

ΔT = 0.02412 s

Answer:

A) wireless communications transmitter

Explanation:

Answer:

Compact fluorescent lightbulb

Explanation:

This is because it has the shortest wavelength

Answer: C. Ribosome

Explanation: Ribosome is responsible for protein synthesis. I got it right on khan academy :) hope this helps have a blessed day.

The structure which is represented by the letter C is known as free ribosomes. Thus, the correct option for this question is C.

Ribosomes may be defined as a type of cell organelle which is spherical and glandular in shape. They occur freely in the matrix or remain bound with ER.

The major components of ribosomes may include RNA and protein. Ribosomes were first discovered by Palade in 1953. There are two types of ribosomes, ie. the 70s and 80s.

Ribosomes play an important function in the process of protein synthesis. The structure which is represented by the letter A is known as the cell membrane. The structure which is represented by the letter B is known as Cytosol.

Therefore, the structure which is represented by the letter C is known as free ribosomes. Thus, the correct option for this question is C.

To learn more about Ribosomes, refer to the link:

https://brainly.com/question/8773679

#SPJ2

Answer:

-7.2 * 10^4 kJ mol-1

Explanation:

First we obtain the change in enthalpy for the reaction;

ΔHrxn= ΔHproducts - ΔHreactants

ΔHrxn=[( −510 ) - (−110.53) + (−277.69)]

ΔHrxn= -121.78 * 3 J mol-1

The we obtain the entropy change of the reaction

ΔSrxn= ΔSproducts - ΔSreactants

ΔSrxn= [(191) - (197.67) + (160.7)]

ΔSrxn= -167.37  J K-1 mol−1

Then we calculate ΔG at 298 K

ΔG = ΔH - TΔS

ΔG = ( -121.78 * 3) - (298) (-167.37)

ΔG = -7.2 * 10^4 kJ mol-1

Answer:

Its Greater potential energy because the air is high up and that makes high energy power

Explanation:

As a liquid is cooled its molecules lose kinetic energy and their motion slows. When they've slowed to where intermolecular attractive forces exceed the collisional forces from random motion, then a phase transition from liquid to solid state takes place and the material freezes

Hope it helps u

FOLLOW MY ACCOUNT PLS PLS

Answer:

c baseball

Explanation:

the baseball traveling at 40m/seg

The time between when the bat emits the sound and when it hears the echo is 0.05 s

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s

Learn more: https://brainly.com/question/10128949

Answer:

0.0491

Explanation:

Answer:

Recessive, dominant

Explanation:

umm thats the answer

Answer:

Explanation:

The answer is chemical energy

Answer:

  U / K = 0.30

Explanation:

For this exercise we must calculate the energy at the two points.

Initial. Where are the spores

       K = ½ m v²2

Final. Higher

        U = m g h

the fraction of energy is

          U / K = 2gh /v²

let's calculate

           U / K = 2  9.8  0.20 / 3.6²

            U / K = 0.30

therefore 30% of the energy is lost

Answer:

The net force is 0.

Explanation:

If I pull to the left with 400 N and you pull to the right with 400 N, we're going in opposite directions. If the left is negative (-400N) and the right is positive (+400N), add them to get the resultant force.

Answer: its d

Explanation:

Given the information on the graph, we can confirm that this profile represents the Ocean floor profile.

Therefore, we can confirm that the profile belongs to the ocean floor profile, firstly because of the information provided, as well as it being consistent with the irregularities in the depth of the ocean floor.

To learn more about the Ocean visit:

https://brainly.com/question/11803537?referrer=searchResults

Answer:

solidification

Explanation:

a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting point—is a characteristic of that substance.

Answer:

4 photovoltaic cells are required to meet monthly energy consumption of the cabin.

Explanation:

Let suppose that PV generation system produces energy at constant energy, the number of photovoltaic system to meet energy consumption of the cabin is:

[tex]n = \frac{E}{\dot E \cdot t}[/tex] (1)

Where:

[tex]E[/tex] - Energy consumption of the PV system, in kilowatt-hours.

[tex]\dot E[/tex] - Power generation of the PV cell, in kilowatts.

[tex]t[/tex] - Working times, in hours.

If we know that [tex]E = 720\,kWh[/tex], [tex]\dot E = 0.25\,kW[/tex] and [tex]t = 720\,h[/tex], then the number of photovoltai cells is:

[tex]n = \frac{E}{\dot E \cdot t}[/tex]

[tex]n = 4[/tex]

4 photovoltaic cells are required to meet monthly energy consumption of the cabin.

Answer:

There is no graph i can aswer it soww

Explanation:

Answer:

The horizontal distance traveled by the ball before it hits the ground is 64.42 m.

Explanation:

Given;

initial velocity, u = 27.0 m/s

angle of projection, θ = 30⁰

The horizontal distance traveled by the ball before it hits the ground is known as Range;

[tex]Range = \frac{u^2 sin(2\theta)}{g} \\\\Range = \frac{(27^2)sin(2 \times 30)}{9.8} \\\\Range = 64.42 \ m[/tex]

Therefore, the horizontal distance traveled by the ball before it hits the ground is 64.42 m.

Answer:

1.8 × 10^29 kg

Explanation:

The computation of the total mass is shown below;

As we know that

The total mass of the sun is

= 2 × 10^30 kg

Since 70% of the mass involves hydrogen gas, so total mass of the hydrogen gas is

= 70% × 2 × 10^30 kg

= 1.4 × 10^30 kg

And, 13% available for fusion, so the hydrogen gas mass is

= 13% × 1.4 × 10^30 kg

= 1.8 × 10^29 kg

Answer:

Its a state of limited competition, in which a market is shared by a small number of producers or sellers.

Answer:

0.647 meters

Explanation:

i did the quiz

Answer:

D. 10 atoms

Explanation:

Answer:

  w = [tex]\sqrt{\frac{2gy}{r^2 + \frac{1}{2} R^2 } }[/tex]

Explanation:

For this exercise let's start by applying Newton's second law to the mass with the string

                W - T = m a

In this case, as the system is going down, we will assume the vertical directional down as positive.

                T = W - m a

Now we apply Newton's second law for rotational motion to the pulley of radius r. We will assume the positive counterclockwise rotations

                ∑ τ = I α

                T r = I α

the moment of inertia of the disk is

               I = ½ M R²

angular and linear acceleration are related

               a = α r

we substitute

               T r = (½ m R²) (a / r)

               T = ½ m ([tex]\frac{R}{r}[/tex] )² a

we write our two equations

               T = W - m a

               T = ½ m ([tex]\frac{R}{r}[/tex] )² a

we solve the system of equations

              W - m a = ½ m (\frac{R}{r} )² a

              m g = m a [ 1 + ½ (\frac{R}{r} )² ]

             a = [tex]\frac{g}{ 1 + \frac{1}{2} (\frac{R}{r})^2 }[/tex]

this acceleration is constant throughout the trajectory, so with the angular and lineal kinematics relations

             w² = w₀² + 2 α θ

             v² = v₀² + 2 a y

as the system is released its initial angular velocity is zero

              w² = 0 + 2 α θ

              v² = 0 + 2 a y

we look for the angular acceleration

              a =α r

              α = a / r

              α = [tex]\frac{g}{r (1 + \frac{1}{2} (\frac{R}{r})^2 }[/tex]

we look for the angle, remember that they must be measured in radians

             θ = s / r

in this case we approximate the arc to the distance

            s = y

            θ = y / r

we substitute

            w = [tex]\sqrt{2 \frac{g}{ r( \frac{1}{2} (\frac{R}{r})^2 } \frac{y}{r} }[/tex]

            w = [tex]\sqrt{\frac{2gy}{r^2 + \frac{1}{2} R^2 } }[/tex]

    for the simple case where r = R

            w = [tex]\sqrt{ \frac{2gy}{ \frac{3}{2} R^2 } }[/tex]

            w = [tex]\sqrt{ \frac{4}{3} \frac{gy}{R^2} }[/tex]

There are different types of contact forces like normal Force, spring force, applied force and tension force.

Answer:

[tex]T=208N[/tex]

Explanation:

From the question we are told that:

Neck flex angle [tex]\angle_n=40 \textdegree[/tex]

Head mass [tex]M_h=4.5kg[/tex]

Center of mass [tex]M_c= 11cm[/tex]

Distance of neck from P [tex]d_p=1.5cm[/tex]

Let

[tex]T_g=Gravitational\ force\ torque\\T_{nm}=Tension\ on\ neck\ muscle\ torque[/tex]

Generally the net Torque T_n is mathematically given by

[tex]T_n=0[/tex]

Therefore

[tex]T_g-T_{nm}=0[/tex]

Generally the equation for Torque T is mathematically given by

[tex]T=\frac{M_h*g*l_g}{d_p}[/tex]

where

[tex]l_g=M_c*sin\angle_n[/tex]

[tex]l_g=11*10^{-2}*sin40[/tex]

[tex]l_g=0.07m[/tex]

Therefore

[tex]T=\frac{4.5*9.8*0.07}{1.5*10^{-2}}[/tex]

[tex]T=208N[/tex]

Answer:

R = (18 ± 2) 10¹ Ω

ΔR = 2 10¹ Ω

Explanation:

Ohm's law relates voltage to current and resistance

           V = i R

            R = [tex]\frac{V}{i}[/tex]V / i

the absolute error of the resistance is

           ΔR = | [tex]| \frac{dR}{DV} | \ \Delta V + | \frac{dR}{di} | \ \Delta i[/tex]

the absolute value guarantees the worst case, maximum error

           ΔR = [tex]\frac{1}{i} \Delta V+ \frac{V}{i^2} \Delta i[/tex]

The error in the voltage let be approximate, if we use a scale of 10 V, in general the scales are divided into 20 divisions, the error is the reading of 1 division, let's use a rule of direct proportion

          ΔV = 1 division = 10 V / 20 divisions

          ΔV = 0.5 V

The current error must also be approximate, if we have the same number of divisions

           Δi = 50 mA / 20 divisions

           Δi = 2.5 mA

let's calculate

          ΔR = [tex]\frac{1}{45.5 \ 10^{-3}} \ 0.5 + \frac{8.2}{(45.5 \ 10^{-3})^2 } \ 2.5 \ 10^{-3}[/tex]

          ΔR = 10.99 + 9.9

          ΔR = 20.9 Ω

The absolute error must be given with a significant figure

          ΔR = 2 10¹ Ω

the resistance value is

          R = 8.2 / 45.5 10-3

          R = 180 Ω

the result should be

          R = (18 ± 2) 10¹ Ω