Answer:
B.
Explanation:
I'm not sure if it's the right answer but I think it is. I hope I helped out in some way.
Sal is experimenting with materials that dissolve in water. He finds a material that dissolves well in water. Which of these could it
be?
any pics? so i can see the question ⁉️
Constructive interference in wave patterns causes an increase in which measurement associated with waves and vibrations?
A. period
B. frequency
C. speed
D. amplitude
E. wavelength
Constructive interference in wave patterns causes an increase in amplitude measurement associated with waves and vibrations.
What is constructive interference?When two waves move in the same direction and are in phase with each other, their amplitudes are summed to produce the resultant wave.
The waves are considered to have suffered constructive interference in this case. Upward displacement occurs when waves experience constructive interference.
The medium's upward displacement is higher than the displacement of the two interfering pulses.
Hence option D is correct.
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Why are objects that fall near Earth's surface rarely in free fall?
O Gravity does not act on objects near Earth's surface.
O Air exerts forces on falling objects near Earth's surface.
O The objects do not reach terminal velocity.
O The objects can be pushed upward by gravity.
Answer:
Air exerts forces on falling objects near earth's surface
Explanation:
Falling objects are typically subject to air resistance which prevents the force of gravity on the object
Philosophy: The Big Picture Unit 8
Would an existentialist argue that the study of philosophy was a good use of a life?
A. Yes, if society valued the results of the study.
B. Yes, but only if the individual found it meaningful.
C. No, a life should be spent minimizing the role of anxiety.
D. No, there is no way that philosophy could create a meaningful life.
the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67
Answer:
[tex]\theta_c = 36.78^o[/tex]
Explanation:
The relationship between the refractive index and the critical angle is given as follows:
[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]
where,
η = refractive index = 1.67
θc = critical angle =?
Therefore,
[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]
[tex]\theta_c = 36.78^o[/tex]
SIENCE! help please its due yesterday and i didn’t do it :(
Answer: H
the lights travel through the mirr to create a bigger wider light.
hope this helps (:
if the root mean square speed of a gas particle is 200 m/s at a temperature of 400k, at what approximate temperature will urms when kelvin temperature equals 350 m/s
Answer:
The correct solution is "1230 K".
Explanation:
The given values are:
[tex](V_{rms})_1= 200 \ m/sec[/tex]
[tex](V_{rms})_2= 350 \ m/sec[/tex]
[tex]T_1=400 \ K[/tex]
As we know,
⇒ [tex]V_{rms} \propto \sqrt{T}[/tex]
or,
⇒ [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]
On substituting the values, we get
⇒ [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]
⇒ [tex]T_2=1230 \ K[/tex]
In the nitrogen cycle, plants take in nitrates and convert them into
According to Lenz's law, an induced current in the direction depicted in the picture would be created when: a. An external downward field is created or an external upward field is removed b. An external upward filed is created or an external upward field is removed c. An external downward field is created or an external downward field is removed d. An external upward field is created or an external downward field is removed
Answer:
C. An external downward field is created or an external downward field is removed
Explanation:
As we can see that from the attached figure that the induced current would be counter clockwise. So the field occur because of induced current i.e. out of page. This represent that the current is induced in order to rise the flux out of the direction of the page
Therefore because of the external field, the field out of page & flux would be reducing or the external upward field is eliminated
So option C is correct
A racing car on a straight accelerates from 100mph to 316 mph in three seconds what is the acceleration?
Answer:
72mph/sec
Explanation:
The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:
216mph / 3sec = 72mph/sec, our final answer
Hope it made sense. I would appreciate Brainliest, but no worries.
A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen spectral line with a wavelength of 656 nm is seen 60.0 cm to one side of the center. Then, the hydrogen lamp is replaced with an unknown lamp. A spectral line is seen on the screen 36.4 cm away from the center. What is the wavelength of this spectral line
Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ
sin θ = y / L
we substitute
[tex]d \ \frac{y}{L}[/tex] = m λ
with the initial data we look for the distance between the lines
d = [tex]\frac{m \lambda \ L}{y}[/tex]
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
what happens to a neutron that is not attached to a proton?
A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 5.80 ft from the mirror on the left wall and 13.7 ft from the mirror on the right wall.
Answer:
Explanation:
When the person stands 5.80 ft from the mirror of the wall.
a) The first image is found by multiplying the distance of the left mirror to the person.
i.e.
2 × 5.80 = 11.6 ft
b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.
i.e.
(2 × 13.7 ) + 11.6
= 39 ft
c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.
(2 × 5.80) + 39
= 50.6 ft
Calculate the speed of an object that travels 75m in 15s.
Calculate the work done to push a 200-N object 5-meters
What is the mass of a jet that accelerates at 4 m/s2 after a 4,000 N force from the engines?
Answer:
1000kg
Explanation:
F=MA
Rearrange the formula: M=F/A
plug in values for F (force), and A (acceleration).
M=4000/4
M=1000kg
i think.
not sure tho.
The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
What is Newton's second law of motion?Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.
Rearranging the formula to solve for mass, we get:
m = F / a
Substituting the given values, we get:
[tex]m = 4000 N / 4 m/s^2[/tex]
m = 1000 kg
Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
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In which direction does the magnetic field in the center of the coil point?
A. Left
B. Down
C. Right
D. Up
The direction of the magnetic field in the center of the coil point towards the up. So, the correct option is D.
What is right-hand grip rule ?Right-hand grip rule states that, if you are holding a current carrying conductor with your right hand, such that the curled fingers point towards the direction of current flowing through the conductor, then the thumb will point towards the direction of the magnetic field.
Here,
From the current carrying conductor given,
The current is flowing through the conductor in a direction from left to right or it can be said as, the current is flowing in a clockwise direction.
So, we can apply the right-hand grip rule in this conductor.
According to the right-hand grip rule, stretch the thumb of the right hand and point it towards the direction of flow of current in the conductor. Then the remaining curled fingers will be pointed upwards in the conductor.
Hence,
The direction of the magnetic field in the center of the coil point towards the up.
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A ball is rolling down a hill. Wich action would slow the ball down?
What is the gravitational potential energy of a 4 kg bowling ball 1 m above the ground?
Answer:
40 J
Explanation:
Gpe= mgh
=4*10*1
=40
Particle track detectors are used to measure the speed of particles if the lifetime of the particle is known. Particle-X has a lifetime of 256.2 ps. These particles are created in an experiment inside the detector by a given reaction. The particles leave 10.7 cm long tracks on average before they decay into other particles not observable by the detector. What is the average speed of the particles in terms of the speed of light
Answer:
the average speed of the particles in terms of the speed of light is 0.81c
Explanation:
Given the data in the question;
[tex]t_p[/tex] = 256.2 ps = 256.2 × 10⁻¹² s
speed of light c = 2.99 × 10⁸ m/s
d = 10.7 cm = 0.107 m
we know that; Average speed v = d/t ------- let this be equation 1
Also, given that 256.2 ps is the lifetime of particle X frame, proper time will be;
t = Y[tex]t_p[/tex] = [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) --------- let this be equation 2
Next, we input equation 2 into equation 1'
v = d / [ [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]
v = d/[tex]t_p[/tex][ √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]
v[tex]t_p[/tex]/d = √( 1 - [tex]\frac{v^2}{c^2}[/tex] )
we square both sides
( v[tex]t_p[/tex]/d )² = (√( 1 - [tex]\frac{v^2}{c^2}[/tex] ) )²
v²[tex]t_p[/tex]²/d² = 1 - [tex]\frac{v^2}{c^2}[/tex]
v²[tex]t_p[/tex]²/d² + [tex]\frac{v^2}{c^2}[/tex] = 1
v²( [tex]t_p[/tex]²/d² + [tex]\frac{1}{c^2}[/tex] ) = 1
v²( ([tex]t_p[/tex]²c² + d²)/d²c² ) = 1
∴
v² = (d²c²) / ([tex]t_p[/tex]²c² + d²)
v = √[ (d²c²) / ([tex]t_p[/tex]²c² + d²) ]
v = (dc) / √([tex]t_p[/tex]²c² + d²)
so we substitute
v = (0.107 m × c) / √( (256.2 × 10⁻¹² s)²(2.99 × 10⁸ m/s)² + (0.107 m )²)
v = 0.107c / √( 0.00586814 + 0.011449 )
v = 0.107c / √( 0.01731714 )
v = 0.107c / 0.1315946
v = 0.81c
Therefore, the average speed of the particles in terms of the speed of light is 0.81c
Which phrase best describes the structure of an atom?
A. A nucleus made up of protons, surrounded by an electron cloud
B. A nucleus made up of protons and neutrons, surrounded by
electrons in set orbits
C. A sphere made up of an equal number of protons, neutrons, and
electrons
D. A nucleus made up of protons and neutrons, surrounded by an
electron cloud
gravitational potential is the energy due to an object's:
a. motion
b. spring stretch or compression
c. position in a gravity field
d. chemical bonds.
position in a gravitation field (c)
Answer:
The answer is C. position in a gravity field
Diana has just been diagnosed with "pre-diabetes," and her doctor has instructed her to watch her intake of sugar. This is easy at home, but this weekend she will be going to a restaurant with her family. What should she do? (1 point) Order anything on the menu labeled "sugar-free" or "fat-free." Use a phone app to check the sugar content in items or ingredients on the menu. Order something off the salad options and skip the soda or dessert. Split an entrée with a friend to reduce her calorie intake at the meal.
Answer:
sugar free
Explanation:
she should most likely take anything sugar free and avoid any bread, bread can increase your blood level as well, my mother had pre diabetes and what she did was eat salads and drink vegetable smoothies until your sugar goes down. splitting an entrée won't do anything, you technically get the same amount of sugar so at the point just eat the whole meal.
A car on a roller coaster loaded with passengers has a mass of 2.0 x 10^3 kg. At the lowest point of the the track, the radius of curvature is 24 m and the roller coaster car has a tangential speed of 17 m/s
We have that the is mathematically given as
Fn=36000N
ForceQuestion Parameters:
mass of 2.0 x 10^3 kg
the radius of curvature is 24 m and
the roller coaster car has a tangential speed of 17 m/s
Generally the equation for the Force is mathematically given as
F=ma
Fn-fg=mv^2/r
Fn=m(v^2/r+g)
Therefore
Fn=2000(12^2/18+9.8)
Fn=36000N
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As you know a cube with each side 4 m in length has a volume of 64m3. Each side of the cube is now doubled in length. What is the ration if the new volume to the old volume
Answer:
The ratio of the new volume to the old volume is 8 to 1.
Explanation:
Let's first list what we know:
A cube has sides with lengths of 4 mThe volume of the cube is 64 [tex]m^3[/tex]The new cube has sides double the length of the old cubeSince the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.
The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.
Now, let's solve for the volume of the new cube:
[tex]V = s^3[/tex]
[tex]V = 8^3[/tex]
[tex]V = 512[/tex]
The volume of the new cube is 512 [tex]m^3[/tex].
The ratio of the new volume to the old volume is 512 : 64.
Let's simplify the ratio:
512 : 64
8 : 1
The ratio of the new volume to the old volume is 8 to 1.
P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)
Determine the activity of the sample of cerium when the sample was 80 seconds old
Answer is in a photo. I can only upload it to a file hosting service. link below!
bit.[tex]^{}[/tex]ly/3a8Nt8n
A pendulum with a mass of 250 g is released from its maximum displacement of 5 degrees and swings with a simple harmonic motion. If the period is 4 seconds, calculate a) the length of the pendulum, b) the amplitude, c) frequency, d) maximum velocity, e) total energy, f) maximum height.
(a) The length of the pendulum is 3.96 m.
(b) The amplitude is 7.89 m.
(c) The frequency is 0.25 Hz.
(d) The maximum velocity is 12.38 m/s.
(e) The total energy is 9.67 J.
(f) The maximum height is 3.94 m.
Length of the pendulum
The length of the pendulum at the given parameters is determined using the following formula.
[tex]T = 2\pi \sqrt{\frac{l}{gcos(\theta)} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{gcos(\theta)} }\\\\\frac{T^2}{4\pi ^2 } =\frac{l}{gcos(\theta)}\\\\l = \frac{gcos(\theta)T^2}{4\pi^2} \\\\l = \frac{(9.8)cos(5)\times (4)^2}{4\pi^2} \\\\l = 3.96 \ m[/tex]
Amplitude of the pendulumThe amplitude of the pendulum is calculated as follows;
mgLcosθ = ¹/₂FA
mgLcosθ = ¹/₂(mg)A
Lcosθ = ¹/₂A
A = 2Lcosθ
A = 2 x 3.96 x cos(5)
A = 7.89 m
Angular speed of the wave[tex]\omega = \sqrt{\frac{g}{l} } \\\\\omega = \sqrt{\frac{9.8}{3.96} } \\\\\omega = 1.57 \ rad/s[/tex]
Frequency of the waveω = 2πf
f = ω/2π
f = (1.57) / (2π)
f = 0.25 Hz
Maximum velocityThe maximum velocity is calculated as follows;
v = Aω
v = 7.89 x 1.57
v = 12.38 m/s
Total energyE = mgLcosθ
E = 0.25 x 9.8 x 3.96 x cos(5)
E = 9.67 J
Maximum height reached by the pendulumh = Lcosθ
h = 3.96 x cos(5)
h = 3.94 m
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HELP PLEASEE
when a person receives an electric shock from wires , is he most affected by a spark, corona, arc or humus solution?
Answer:
Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.
Explanation:
a jogger does 3.45 E 6 J of work and gives off 1.67 E 6 J of heat. what is the change in her internal energy? show your work
Answer:
well its burning its callories so thats it technically
Explanation:
Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have the frequency 440 Hz and the note E should be at 659 Hz. The tuner can determine this by listening to the beats between the third harmonic of the A and the second harmonic of the E. A tuner first tunes the A string very precisely by matching it to a 440 Hz tuning fork. She then strikes the A and E strings simultaneously and listens for beats between the harmonics. What beat frequency indicates that the E string is properly tuned
Answer:
The beat frequency = 2.0 Hz
Explanation:
From the given information
The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.
i.e.
[tex]f_{3A} = 3f_A[/tex]
where;
[tex]f_A =[/tex] note A fundamental freq.
replacing 440 Hz for [tex]f_A[/tex]
[tex]f_{#a} = 3 (440 \ Hz)[/tex]
[tex]f_{3A} = 1320 Hz[/tex]
However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.
i.e.
[tex]f_{2E} = 2f_E[/tex]
[tex]f_E =[/tex] note E fundamental freq.
replacing 659 Hz for [tex]f_E[/tex]
[tex]f_{2E} = 2(659)[/tex]
[tex]f_{2E} = 1318 \ Hz[/tex]
Finally, the beat frequency when the E string is properly tuned is:
[tex]\Delta f = f_{3A}-f_{2E}[/tex]
[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]
[tex]\Delta f = 2.0 \ Hz[/tex]
Thus, the beat frequency = 2.0 Hz