*picture choice question*

Which is a renewable
resource?

The range of diameters and luminosities displayed by elliptical galaxies is 3000 to 700,000 light years and Mv-23 down to Mv- -16 mag respectively

Elliptical galaxies are type of galaxies with a smooth ellipsoidal shape.

They are the most abundant galaxies in the universe.

Their diameter ranges from 3, 000 to 700, 000 light years.

Their luminosity ranges from Mv-23 down to Mv- -16 mag

Therefore, the range of diameters and luminosities displayed by elliptical galaxies is 3000 to 700,000 light years and Mv-23 down to Mv- -16 mag respectively.

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Answer:

Weight it in beam balance or any other weight mesuring device

Answer:

the micrometre screw gauge is used​ for making precise linear measurements (e.g to measure diameter of a wire)

Answer:

Acceleration of this man: approximately [tex]0.52\; {\rm m\cdot s^{-1}}[/tex] due east.

Accelerate of this woman: approximately [tex]0.78\; {\rm m \cdot s^{-1}}[/tex] due west.

Explanation:

The question implies that the net force on the man is [tex]F = 46\; {\rm N}[/tex] due east. The mass of the man is [tex]m = 89 \; {\rm kg}[/tex]. The acceleration of the man would be:

[tex]\begin{aligned} a &= \frac{F}{m} \\ &= \frac{46\; {\rm N}}{89\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{due east})}{} \\ &\approx 0.52\; {\rm m\cdot s^{-2}} && (\text{due east})\end{aligned}[/tex].

In other words, the acceleration of this man would be approximately [tex]0.52\; {\rm m \cdot s^{-2}}[/tex] due east (same direction as the net force.)

By Newton's Laws of Motion, for every force there is a reaction force that is equal in magnitude but opposite in direction.

The woman in this question is applying a due east [tex]46\; {\rm N}[/tex] force on the man. Thus, this woman would experience a reaction force of the same magnitude ([tex]46\; {\rm N}\![/tex]) and opposite direction (due west) from the man. Under assumptions of the question, the net force on the woman would be [tex]\! 46\; {\rm N}[/tex] due west.

The acceleration of this [tex]m = 59\; {\rm kg}[/tex] woman would be:

[tex]\begin{aligned} a &= \frac{F}{m} \\ &= \frac{46\; {\rm N}}{59\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{due west})}{} \\ &\approx 0.78\; {\rm m\cdot s^{-2}} && (\text{due west})\end{aligned}[/tex].

Because of wave refraction, erosion along an irregular coastline is greatest in headlands.

This is referred to as the bending of light as it passes from one medium to another with its speed being changed.

Refraction causes erosion along an irregular coastline to be greatest in headlands which is the area of land projected out toward the sea.

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Answer:

20 days, 480 hours

The increase in potential energy of a 60.0-kg man who climbs a ladder 10.0 meters high is 5,880 J.

The increase in the potential energy of the man is calculated as follows;

P.E = mgh

where;

P.E = 60 x 9.8 x 10

P.E = 5,880 J

Thus, the increase in potential energy of a 60.0-kg man who climbs a ladder 10.0 meters high is 5,880 J.

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The velocity 2.5 m above the ground will be 49.07 m/sec.

The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;

F = kx

The formula for force is;

F=ma

Equating both the equation;

ma = kx

a=kx/m

a=( 185 N/m × 1.38 m) / 0.53

a  = 481.6 m/s²

The speed is found by Newton's third equation of motion;

v²=u²+2as

v²=0+2as

v²=2 × 481.6 m/s² × 2.5 m

v = 49.07 m/sec

Hence the velocity 2.5 m above the ground will be 49.07 m/sec.

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Red dwarf stars evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.

Red dwarf stars are the smallest and coolest kind of stars on the main sequence.

Red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.

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The distance travelled by the ball, given the data is 7.82 m

The range (i.e distance) travelled by the ball can be obtained as illustrated below:

R = u²Sine(2θ) / g

R = 10² × Sine (2×25) / 9.8

R = 10² × Sine 50 / 9.8

R = 7.82 m

Thus, the distance travelled by the ball is 7.82 m

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Answer:

A

Explanation:

The electrostatic force and strong nuclear force are opposite forces. The electrostatic force causes the repulsion beteween the positively charged protons in the nucleus but the strong force keeps the nucleus glued together but overcoming the electrostatic force. They would both increase upon the addition of a proton or radioactivity will result.

The distance of the point from the axis of rotation of the second hand is 9.1 m.

The point from the axis of rotation of the second hand is the radius of the rotation of the clock.

a = v²/r

v² = ar

v = √ar

V = 2πr/T

√ar = 2πr/T

ar = 4π²r²/T²

a = 4π²r/T²

r = aT²/4π²

r = (0.1 x 60²)/(4π²)

r = 9.1 m

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A drop in temperature would most likely result in a decline in the rate of energy production in a fusion nuclear reactor.

The utilization of nuclear reactions to generate energy is known as nuclear power.

Nuclear power facilities produce the great bulk of the electricity generated by nuclear fission of uranium and plutonium.

The environment should be hot enough for the deuterium and tritium ions' kinetic energies to be sufficient to break through the Coulomb barrier and fuse together.

Therefore, a decrease in temperature would most likely cause a decrease in the rate of energy production in a fusion nuclear reactor.

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The words experiences in Niels Bohr's life that led to his interest in science and the study of the atom is he disliked writing essays and talented in mathematics.

Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.

Neil Bohr loved talking, he had a disliking of writing essays. He was talented in mathematics. He then attracted to the sciences. Physics  interested Neil and when he was a teenager, he started correcting the mistakes in his school's textbooks.

The contributions are present in the modern atomic model. They are: All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.

Thus, Physics interested him to further study for atom.

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True, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

Electric field is the region of space at which electric force is felt.

E = kq/r²

where;

at infinite plane, r → ∞, and E = 0

Thus, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

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The amount of oxygen will be 22.29 gm required to produce 37.15 g co₂.

One or more compounds, known as reactants, are transformed into one or more distinct substances, known as products. Such a process is known as a chemical reaction.

Given reaction;

[tex]\rm C_3h_8 +5O_2 }\rightarrow 3CO_2 +4H_2O[/tex]

The quantity of oxygen is x and the quantity of carbon dioxide is y then the ratio of their composition is found as;

5x=3y

5x=37.15

x=3×37.15/5

x=22.29 gm

Hence the amount of oxygen will be 22.29 gm

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Answer: 45.02 (g O2)

Explanation: The person above me is wrong...but this is the right answer on edge! Ik cuz i just did this assignment and got 100% Hope this helps :D

The total length of the wire required is 63 m.

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is a solenoid is configured to produce a magnetic field of 0.027T at its center. it has radius 1.4 cm and length 40cm and the wire can carry a maximum current of 12.0 A.

Radius, r = 1.4cm = 0.014 m

Length l = 40 cm = 0.4 m

If the current is I, then the magnetic field in solenoid is given by

B =  μ₀ n I

By substituting the values, we get

0.027 = 4π x 10⁻⁷ x n x 0.4

n = 1792 turns/unit length

Total length of wire = circumference x Turns

L = 2πr x N

where N = nl

Plug the values, we get

L = 2π x 0.014 x1792 x 0.4

L = 63 m

Thus, the total length of the wire is 63 m.

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The tensions in the wires at the given angle of inclination is determined as 434.1 N.

The tension in the wires is calculated as follows;

T = Wsinθ

where;

T = 2500 x sin(10)

T = 434.1 N

Thus, the tensions in the wires at the given angle of inclination is determined as 434.1 N.

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Answer:

A) only the wall is involved for both forces (action-reaction)

Answer:

i am pretty sure its 15 m

Explanation:

10 m/s

1.5 seconds

25 angle

10m/1.5s

10x1.5=15

The purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.

The scapula is an important bone which is found in the shoulder and back region of the body.

The scapula enables and increases the range of motion of the arm with its motions.

During arm elevation, the scapula undergoes an upward rotational motion.

Therefore, the  purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.

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The distance of the cliff from where you are is determined as 3,430 m.

Apply the formula for echo.

v = 2d/t

where;

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

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a)The normal force on the luggage cart will be 305.85 N

b)The force would Tony needs to apply at a 30° angle to pull the luggage cart willl be 375 N.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration. Mathematically aion in the different components and balancing the equation gets.Components in the x-direction.

Given data;

The angle of pulling with horizontal. =  30°

Mass of luggage cart=35 kg

Pulling force= 75 N

The force in the y-direction;

N+Fsin30° = mg

N+75 sin 30° = 35 × 9.81

N=305.85 N

The force would Tony need to apply at a 30° angle to pull the luggage cart completely off the ground;

N-mg=Fsin30

Fsin30=75 sin 30

Fsin30=375 N

Hence the normal force on the luggage cart and force would Tony need to apply at a 30° angle to pull the luggage cart willl be 305.85 N and 375 N.

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(a) The frequency observed by the passenger on the east-bound train when they are 1000 m apart is 675.5 Hz.

(b) After 10 seconds, the frequency observed by the passenger on the east-bound train will be greater than the frequency observed when they are 1000 m apart.

The frequency observed by the passenger on east-bound train is calculated by applying Doppler shift formula.

[tex]f = f_0(\frac{v \pm v_0}{v\pm v_s} )[/tex]

where;

[tex]f = 600(\frac{343 +15}{343-25} )\\\\f = 675.5 \ Hz[/tex]

The frequency observed by the passenger increases with decrease in distance between the two trains.

Thus, after 10 seconds, the frequency observed by the passenger on the east-bound train will be greater than the frequency observed when they are 1000 m apart.

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Answer:

1 m/s²

Explanation:

added in the picture

can you write the question because i cant see it

A) Formulate policies to protect wetlands and ensure that the policies are enforced.

B) Wetlands hold important biodiversity. They are a source of foods, medicines, and raw materials. They help with stabilizing the climate.

As a governor of my state, the two most important steps to protect wetlands include:

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To protect the wetlands, I will ensure a strict enforcement of all existing state laws on the conservation of wetlands.

The wetlands are those areas that consists of marshes and swamps. They are of great important to the ecosystem and biodiversity.

a) The two things that I will do to protect wetlands are;

b) Wetlands are very important because;

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Answer:

The image is formed by a convex lens with the object at 2F.

Sample Response: The image created by the object is located on 2F behind the lens, real, inverted, and the same size as the actual object. 

Explanation: EDGE.

Answer:

Positive

when a negatively charged rod is bring near uncharged spherical conductor it attracts positive charge and repels negative charges

so In left side all positive charges appears and in right side all negetive

Types of methods of charging