Philip ran out of time while taking a multiple-choice test and plans to guess the last 4 questions. Each question has 5 possible choices, one of which is correct. Let X=X=X, equal the number of answers Philip correctly guesses in the last 444 questions. Assume that the results of his guesses are independent.
What is the probability that he answers exactly 1 question correctly in the last 4 questions?

Answer:

( 2, -1)

Step-by-step explanation:

(X1 + X2)/2 , (Y1 + Y2)/2

(6-2)/2 , (3-5)/2

4/2 , -2/2

2 , -1

Answer:

(2, -1)

Step-by-step explanation:

(x1, y1)=(6, 3)

(x2, y2)=(-2, -5)

[(6+(-2))/2, (3+(-5))/2]

=(4/2, -2/2)

=(2, -1)

Answer:

A. 0.78

Step-by-step explanation:

A rational number is a number that you can express as [tex]\frac{x}{y}[/tex] where [tex]y\neq 0[/tex].

1) ∠E and ∠F are supplementary and ∠F and ∠G are supplementary (given)

2) m∠E+m∠F=180 degrees, m∠F+m∠G=180 degrees (supplementary angles have measures that add to 180 degrees)

3) m∠E=m∠G (subtraction property of equality)

4) ∠E≅∠G (angles with equal measure are congruent)

The corresponding part of PQ is WX

The congruent statement is given as:

polygon WXYZ ≅ polygon PQRS.

This means that the corresponding points are:

W and P, X and Q, Y and R, Z and S

When two points Q and P are joined together, we have:

polygon WX ≅ polygon PQ

Hence, the corresponding part of PQ is WX

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Answer:

161 calories

Step-by-step explanation:

1) Divide 230 by 48

4.791666666666667

2) multiply 4.791666666666667 by 33.6

161

Done! Your answer is 161 calories in a 33.6 gram bag. Or just 161.

Hope this helps!

Answer: 31 cm.

explanation:

Given, Radius = 5 cm (near to)

this means the radius is near 5 cm. It can be 4.9, 4.99, 4.999.....or 5.01,5.001,5.001...... and so on.

So, the circumference of the circle is given by:-

Circumference = 2× [tex]\pi[/tex] × r

⇒ 2 × 22/7 × 5    (for the smallest value, we'll consider r as 5 and then round off the circumference to the smallest value)

⇒ 220/7 ≈ 31.43 cm

rounding off to the smallest integer, we have

Circumference = 31 cm.

The smallest value that the circumference could have is 10 [tex]\pi[/tex]cm

Using Formula,

Circumference = 2 [tex]\pi \\[/tex] r

Radius = 5 cm

So, C = 2 [tex]\pi[/tex] 5

C = 10 [tex]\pi[/tex]cm

Therefore circumference is 10 [tex]\pi[/tex]cm.

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Answer:

k = 1

Step-by-step explanation:

Discriminant

[tex]b^2-4ac\quad\textsf{when }\:ax^2+bx+c=0[/tex]

[tex]\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}[/tex]

[tex]\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}[/tex]

[tex]\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}[/tex]

As we need to determine the value of k that will give one solution, set the discriminant to zero.

Given equation:

[tex]y=kx^2-4x+4[/tex]

Therefore:

Substitute these values into the discriminant and solve for k:

[tex]\begin{aligned}b^2-4ac & = 0\\\implies (-4)^2-4(k)(4) & = 0\\16-16k & = 0\\16k & = 16\\\implies k & = 1\end{aligned}[/tex]

The slope of the given line is -2, and since perpendicular lines have negative reciprocal slopes, the slope of the line we want to find is 1/2.

Substituting into point-slope form,

[tex]y+4=\frac{1}{2}(x-8)\\\\y+4=\frac{1}{2}x-4\\\\\boxed{y=\frac{1}{2}x-8}[/tex]

Answer:

Equation of line perpendicular to y= -2x-9 is y=x/2-8 .

Step-by-step explanation:

The slope of a line gives the measure of its steepness and direction. The slope of a curve at a point is equal to the slope of the straight line that is tangent to the curve at that point.

The general equation of a line is y = mx + c, where m is the slope of the line and c is the y-intercept. It is the most common form of the equation of a straight line that is used in geometry.

The product of slopes of two perpendicular lines gives (-1).

m1m2=(-1)

(-2)m2=(-1)

m2=1/2

y=m2x+c

Point (8,-4) satisfies the given equation :

(-4)=1/2 x 8 + c

c = (-8)

Line perpendicular to y= -2x-9 will be -

y=x/2-8

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Since everything to the right of the line is shaded, the linear inequality which represents the graph is equal to: A. y ≥ 1/3x - 4.

In order to determine the linear inequality which represents the graph, we would find the slope of the given points.

Mathematically, the slope of a straight line can be calculated by using this formula;

[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]

Substituting the given points into the formula, we have;

[tex]Slope = \frac{-4\;-\;(-5)}{0\;-\;(-3)}\\\\Slope = \frac{1}{3}[/tex]

Slope = 1/3.

From the standard equation, we have:

y - y₁ = m(x - x₁)

y - (-5) = 1/3(x - (-3))

y + 5 = 1/3x + 1

y = 1/3x + 1 - 5

y = 1/3x - 4

y ≥ 1/3x - 4.

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Answer:

i think the answer is the second one D and A

Step-by-step explanation:

please mark me as brainlest

Answer:

a, b, d

Step-by-step explanation:

its one of those

Answer:

A, the first one

i beilive this is unknown

Answer:

3/8

Step-by-step explanation:

probability = wanted outcomes / total outcomes

odds = wanted outcomes / unwanted outcomes

Odds of 3:5 losing means 3 losing outcomes and 5 winning outcomes.

The total outcomes is 8

The probability of losing which is the probability that the event will fail to occur is 3/8.

Answer:

B. x = 3

Step-by-step explanation:

Simplifying

4 + 3x = 2(3x + -7) + 9

Reorder the terms:

4 + 3x = 2(-7 + 3x) + 9

4 + 3x = (-7 * 2 + 3x * 2) + 9

4 + 3x = (-14 + 6x) + 9

Reorder the terms:

4 + 3x = -14 + 9 + 6x

Combine like terms: -14 + 9 = -5

4 + 3x = -5 + 6x

Solving

4 + 3x = -5 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.

4 + 3x + -6x = -5 + 6x + -6x

Combine like terms: 3x + -6x = -3x

4 + -3x = -5 + 6x + -6x

Combine like terms: 6x + -6x = 0

4 + -3x = -5 + 0

4 + -3x = -5

Add '-4' to each side of the equation.

4 + -4 + -3x = -5 + -4

Combine like terms: 4 + -4 = 0

0 + -3x = -5 + -4

-3x = -5 + -4

Combine like terms: -5 + -4 = -9

-3x = -9

Divide each side by '-3'.

x = 3

Simplifying

x = 3

Answer:

A

Step-by-step explanation:

sin*sec=tan

tan^2+1=sec^2 by an identity

The missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.

It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.

We have:

[tex]\rm F = \dfrac{9}{5}C + 32[/tex]

Make subject C and solve:

[tex]\rm \dfrac{5}{9}(F-32) = \dfrac{5}{9}\times\dfrac{9}{5}C[/tex]

[tex]\rm \dfrac{5}{9}(F-32) = C[/tex]

Plug F = 41

[tex]\rm \dfrac{5}{9}(41-32) = C[/tex]

[tex]\rm \dfrac{5}{9}(9) = C[/tex]

41 degrees F = 5 degrees C

Thus, the missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.

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The inequality equation will be -5x + 20 < -10.

Inequality is defined as an equation that does not contain an equal sign.

The weather report says the temperature is 20°c and will drop 5°c per hour for the next 6 hours.

Daryl plans to be gone at least 6 hours, and he has a plant outside.

If he wants the plant to remain in temperatures above -10° should Daryl move the plant to a warmer location before leaving will be

The inequality equation will be

-5x + 20 < -10

where x is the number of hours.

Then we have

-10 < -5x + 20

5x > 30

   x > 6 hours

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‐10+35=25 and 25 × 20=300

By applying algebraic handling on the two equations, we find the following three solution pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

In this question we have a system formed by a linear equation and a non-linear equation, both with no trascendent elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three solution pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

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Answer:

1780

Step-by-step explanation:

multiply the length value by 1760

and then divide the length value by 3

It is correct to state that a bit can be in one of 2 states, either 1 or 0.

A bit is is a single binary digit. A bit can either be "1" or "0".

We stated that It is correct to indicate that a bit can be in one of 2 states, either 1 or 0. This indicates that 2ⁿ strings must be created in total. The string must then be processed twice.

Hence, Our time is now O(2ⁿ⁺¹) = O(2ⁿ)

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Answer:

1) D because the answer to 8.42*10^3=8420

and 8420 lies between 8400 and 8500

2) C because when you take the absolute value of -2.3 and -3.2, they become positive numbers => 2.3 < 3.2

3)D because 6 < 6.3 < 6.6

Hope it helps!

The second derivative of the first function is s"(x) = = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³.

The second derivative of the second function is; k''(t) = (36t² - 6)e^(-3t²)

1)  We are given the function;

s(x) = 4/(1 + 2e^(-0.2x)

First derivative is;

ds/dx = [8e^(x/5)]/5(e^(x/5) + 2)²

Second Derivative is;

d²s/dx² = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³

At x = 0;

d²s/dx² = -[8e^(0/5) - 2]e^(0/5)/25(e^(0/5) + 2)³

d²s/dx² = 8/675

B) We are given the function;

k(t) = e^(-3t²)

The first derivative is;

dk/dt = -6te^(-3t²)

The second derivative is;

k''(t) = (36t² - 6)e^(-3t²)

At t = 1, we have;

k''(t) = (36(1)² - 6)e^(-3(1²))

k"(t) = 1.494

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Answer:

K

Step-by-step explanation:

(1*500 * 5) + (10 * 3*500)

Answer:

[tex]x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]

Step-by-step explanation:

Given equation:

[tex]x^2+3x-9=0[/tex]

Completing the square

Move the constant to the right side by adding 9 to both sides:

[tex]\implies x^2+3x=9[/tex]

Add the square of half the coefficient of x to both sides:

[tex]\implies x^2+3x+\left(\dfrac{3}{2}\right)^2=9+\left(\dfrac{3}{2}\right)^2[/tex]

[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{45}{4}[/tex]

Factor the trinomial on the left side:

[tex]\implies \left(x+\dfrac{3}{2}\right)^2=\dfrac{45}{4}[/tex]

Square root both sides:

[tex]\implies x+\dfrac{3}{2}=\pm\sqrt{\dfrac{45}{4}}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{45}}{\sqrt{4}}}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9 \cdot 5}}{2}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9} \sqrt{5}}{2}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{3\sqrt{5}}{2}[/tex]

Subtract 3/2 from both sides:

[tex]\implies x=\pm\dfrac{3\sqrt{5}}{2}-\dfrac{3}{2}[/tex]

[tex]\implies x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]