After considering the given data and performing the evaluation regarding the convertion of energy units the answer derived is 6.61 x 10⁶ J = 1577.16 kcal.
In order to alter joules (J) to kilocalories (kcal), the below conversion can be applied.
1 kcal = 4.184 kJ.
We start by, converting J to kJ by dividing by 1000:
6.61 x 10⁶ J = 6.61 x 10³ kJ
Next step we convert kJ to kcal by dividing by 4.184:
= 6.61 x 10³ kJ ÷ 4.184
= 1577.16 kcal (rounded to five significant figures)
1 joule (J) is the amount of energy needed to apply a force of 1 newton (N) over a distance of 1 meter (m).
1 kilocalorie (kcal), on the other hand, is described as the amount of energy required to increase the temperature of 1 kilogram (kg) of water by 1 degree Celsius (°C), which is equal to 4184 joules (J).
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Given Equation (Balance it) :
C2H4O2 + NaHCO3 —> NaC2H3O2 + H2O + CO2
Word Problem:
If you have 100 mg of Acetic Acid (C2H4O2) and 10 mg of NaHCO3 (Sodium Bicarbonate), how many grams of CO2 can be produced ?
also determine the theoretical yield of the chemical reaction.
C₂H₄O₂ + NaHCO₃ —> NaC₂H₃O₂ + H₂O + CO₂ the amount of Carbon dioxide produced is 5.28 mg.
Is the reaction between acetic acid and sodium bicarbonate exothermic or endothermic?Water, CO₂ , and C₂H₃NaO₂ were produced when acetic acid and NaHCO₃ were combined. The chemistry is as follows: The reaction between vinegar and baking soda was endothermic.
Acetic acid: 2(12.01 g/mol) + 4(1.01 g/mol) + 2(16.00 g/mol)
= 60.05 g/mol
NaHCO₃ 22.99 g/mol + 1.01 g/mol + 3(16.00 g/mol)
= 84.01 g/mol
100 mg of Acetic acid is equal to 0.1 g, and 10 mg of NaHCO₃ is equal to 0.01 g.
Number of moles of Acetic acid = 0.1 g / 60.05 g/mol
= 0.00167 mol
Number of moles of NaHCO₃ = 0.01 g / 84.01 g/mol
= 0.00012 mol
Since NaHCO₃ has fewer moles, it is the limiting reactant.
Therefore, 0.00012 mol of NaHCO₃ will produce 0.00012 mol of CO₂
The mass of CO₂ produced can be calculated as follows:
Mass of CO₂ = Number of moles of CO₂ x Molar mass of CO₂
Mass of CO₂ = 0.00012 mol x 44.01 g/mol
= 0.00528 g or 5.28 mg
Therefore, the amount of CO₂ produced is 5.28 mg.
The theoretical yield of CO₂ is 0.00012 mol x 44.01 g/mol
= 0.00528 g or 5.28 mg.
This is equal to the actual yield of CO₂ produced.
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A gas sample originally occupies 436 mL at 24 C. When the volume is expanded to 612 mL and the temperature is increased to 97 C, the pressure becomes 526 mm Hg. What was the original pressure?
Initially, there was a 266.8 mm Hg pressure.
solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas sample. The formula is:
(P1 × V1) ÷ (T1) = (P2 × V2) ÷ (T2)
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
We are given that:
- V1 = 436 mL
- V2 = 612 mL
- T1 = 24 C + 273.15 = 297.15 K (convert from Celsius to Kelvin)
- T2 = 97 C + 273.15 = 370.15 K
- P2 = 526 mm Hg
We want to find P1, the original pressure.
Plugging in the values, we get:
(P1 × 436 mL) ÷ (297.15 K) = (526 mm Hg × 612 mL) ÷ (370.15 K)
Solving for P1, we get:
P1 = (526 mm Hg × 612 mL × 297.15 K) ÷ (436 mL × 370.15 K) = 266.8 mm Hg
Therefore, the original pressure was 266.8 mm Hg.
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25 points and I’ll mark as brainliest!!! Tasks are in the picture.
Answer:
5. 0.566 g
6. A. 100 times more
Explanation:
5. The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration. For a solution with pH=2, the concentration of hydrogen ions is 10^-2 mol/L. Since HBr is a strong acid, it dissociates completely in water to produce H+ and Br- ions. Therefore, the concentration of HBr in the solution is also 10^-2 mol/L.
The molar mass of HBr is 80.91194 g/mol
So, in a 700 mL solution (0.7 L), there are
0.7 L * 10^-2 mol/L = 0.007 mol of HBr.
This corresponds to 0.007 mol * 80.91194 g/mol = 0.566 g of HBr dissolved in the solution.
6. The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration. This means that for each decrease in pH by 1 unit, the hydrogen ion concentration increases by a factor of 10. Since the difference in pH between the two solutions is 3 units (6-3=3), the hydrogen ion concentration in the solution with pH=3 is 10^3 = 100 times more than in the solution with pH=6.
which one have least PH
a. CH3CH2COOH
b. CH2CLCH2COOH
c. CH3CHCL2COOH
d. CH3CH2CH2COOH
CH₃CHCl₂COOH is 2,2-dichloropropanoic acid, with the least pH, option (c) is correct.
pH is a measure of the acidity or basicity of a solution. A lower pH indicates a higher acidity. Acidity is due to the presence of hydrogen ions (H⁺) in a solution. The more the concentration of H⁺, the lower the pH. CH₃CH₂COOH is propanoic acid, which has a pH of around 4.9.
CH₂ClCH₂COOH is 2-chloropropanoic acid, which has a pH of around 2.8 due to the electron-withdrawing effect of the chlorine atom. CH₃CH₂CH₂COOH is butanoic acid, which has a pH of around 4.8. Thus, CH₃CHCl₂COOH is 2,2-dichloropropanoic acid, which has the least pH among the given options, around 1.5 due to the presence of two electron-withdrawing chlorine atoms, option (c) is correct.
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A gas‑filled weather balloon has a volume of 56.0 L
at ground level, where the pressure is 761 mmHg
and the temperature is 23.1 ∘C.
After being released, the balloon rises to an altitude where the temperature is −6.97 ∘C
and the pressure is 0.0772 atm.
What is the weather balloon's volume at the higher altitude?
What is the pH of a solution that has a H+ concentration of 1.9x10-6?
The pH of the solution is 5.72, which is slightly acidic.
pH is a measure of the acidity or basicity of a solution. It is defined as the negative logarithm of the hydrogen ion concentration (H+) in a solution. The pH scale ranges from 0 to 14, where a pH of 7 is neutral, pH below 7 is acidic, and pH above 7 is basic. The formula to calculate pH is pH = -log[H+], where [H+] represents the concentration of hydrogen ions in moles per liter.
Given the H+ concentration of 1.9x10-6, we can calculate the pH of the solution as follows:
pH = -log(1.9x10-6) = 5.72
It is important to note that pH is an important factor in various chemical and biological processes. It can affect the solubility of certain substances, enzymatic activity, and the growth and survival of living organisms. Maintaining the appropriate pH is crucial for the proper functioning of these processes.
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Please help thanks so much!!!!!!!!!!!!
The total mass of products obtained when 130 g of zinc react completely with HCl is 274 g (3rd option)
How do i determine the total mass of products obtained?First, we shall determine the mass of each product obtained. Details below:
For ZnCl₂
2HCl + Zn -> ZnCl₂ + H₂
Molar mass of Zn = 65 g/molMass of Zn from the balanced equation = 1 × 65 = 65 g Molar mass of ZnCl₂ = 135 g/molMass of ZnCl₂ from the balanced equation = 1 × 135 = 135 gFrom the balanced equation above,
65 g of Zn reacted to produce 135 g of ZnCl₂
Therefore,
130 g of Zn will react to produce = (130 × 135) / 65 = 270 g of ZnCl₂
Thus, the mass of ZnCl₂ obtained is 270 g
For H₂
2HCl + Zn -> ZnCl₂ + H₂
Molar mass of Zn = 65 g/molMass of Zn from the balanced equation = 1 × 65 = 65 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 1 × 2 = 2 gFrom the balanced equation above,
65 g of Zn reacted to produce 2 g of H₂
Therefore,
130 g of Zn will react to produce = (130 × 2) / 65 = 4 g of H₂
Thus, the mass of H₂ obtained is 4 g
Finally, we shall determine the total mass of the product produced. Details below:
Mass of ZnCl₂ = 270 gMass of H₂ = 4 gTotal mass of product =?Total mass of product = mass of ZnCl₂ + mass of H₂
Total mass of product = 270 + 4
Total mass of product = 274 g (3rd option)
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A sample of gas is contained in a 245 mL flask at a temperature of 23.5°C. The gas pressure is 37.8 mm Hg. The gas is moved to a new flask, which is then immersed in ice water, and which has a volume of 54 mL. What is the pressure of the gas in the smaller flask at the new temperature?
The pressure of the gas in the smaller flask at the new temperature is approximately 168.5 mm Hg.
To solve this problem, we can use the combined gas law equation, which relates the initial and final states of a gas sample undergoing changes in pressure, volume, and temperature. The equation is:
[tex]P_1V_1/T_1 = P_2V_2/T_2[/tex]
where [tex]P_1[/tex] and [tex]P_2[/tex] are the initial pressure and final pressure, [tex]V_1[/tex] and [tex]V_2[/tex] are the initial and final volumes, and [tex]T_1[/tex] and [tex]T_2[/tex] are the initial and final temperatures in Kelvin.
[tex]V_1[/tex] = 245 mL
[tex]T_1[/tex] = 23.5°C + 273.15 = 296.65 K
[tex]P_1[/tex] = 37.8 mm Hg
[tex]V_2[/tex] = 54 mL
[tex]T_2[/tex] = 0°C (ice water) + 273.15 = 273.15 K
We need to find [tex]P_2[/tex] . Plug the given values into the equation and solve for [tex]P_2[/tex] :
(37.8 mm Hg * 245 mL) / 296.65 K = (P2 * 54 mL) / 273.15 K
Rearrange the equation to isolate [tex]P_2[/tex] :
[tex]P_2[/tex] = (37.8 mm Hg * 245 mL * 273.15 K) / (296.65 K * 54 mL)
[tex]P_2[/tex] ≈ 168.5 mm Hg
So, the pressure of the gas is approximately 168.5 mm Hg in the smaller flask at the new temperature.
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The nuclear reaction entails the breakdown of an element and the subsequent release of radioactive particles. This process can occur naturally or be produced purposefully. As a result, the reaction equation is balanced. The radon element is transmuted into polonium and an alpha particle in the provided question. Since an alpha particle was emitted, the equation is balanced.
The alpha decay of radon is shown by;
222/86Rn ----> 218/84Po + 4/2He
What is the alpha decay of radon?Radon undergoes alpha decay by emitting an alpha particle, which consists of two protons and two neutrons.
Let us note that when there is an alpha decay, the parent nucleus would loose a helium nucleus and the daughter nucleus would less than than the parent in mass by four units and less than the parent in charge by 2 units and this would satisfy the mass and charge balance of the equation. The decay equation is; 222/86Rn ----> 218/84Po + 4/2He
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Missing parts;
Use the equation to complete the activity.
219 86Rn → 215 84Po + a
The nuclear equation shows the transmutation of a form of radon into polonium and an alpha particle. In one to two sentences, explain whether or not the reaction is balanced.
7. What is the reason that methemoglobinemia was isolated to Troublesome Creek area of KY? (In other
words why was the disorder only prevalent in KY; why didn't other states see cases like this?)
Methemoglobinemia was caused by contaminated well water and a genetic predisposition in the population of Troublesome Creek, KY.
Methemoglobinemia was detached to the Problematic Rivulet area of KY in view of the novel blend of ecological variables and hereditary inclination in the populace. The issue was brought about by the utilization of well water polluted with elevated degrees of nitrate and nitrite, which can cause the arrangement of methemoglobin in the blood. The populace in this space was to a great extent slipped from a little gathering of trailblazers who settled there during the 1800s, which might have added to a higher pervasiveness of the hereditary characteristic that inclines people toward the issue. The particular mix of hereditary defenselessness and ecological openness in this populace probably prompted the secluded flare-up of methemoglobinemia around here.
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ichiometry in space
A typical space shuttle crew consists of six individuals and
each CCC contains 750 g of LIOH. Assuming that each crew
member expels 42.0 g of CO₂ per hour on average, and that
a mission is scheduled to last 18 days, how many CCCS must
be carried on board the space
shuttle?
- By knowing the recipe (balanced chemical equation), and
some molar masses, I can calculate this answer.
We need to carry at least 187 CCCs on board the space shuttle to absorb all the CO2 produced by the crew during the 18-day mission.
What is the amount of CO2 absorbed?To solve this problem, we need to use the following information:
Each crew member expels 42.0 g of CO2 per hour.The mission is scheduled to last 18 days.There are 6 crew members on board.Each CCC contains 750 g of LIOH.First, we need to calculate the total amount of CO2 that will be expelled during the mission:
Total CO2 = 6 crew members x 42.0 g CO2/hour x 24 hours/day x 18 days = 136,080 g CO2
Next, we need to calculate the amount of LIOH needed to absorb this CO2. The balanced chemical equation for the reaction between CO2 and LIOH is:
CO2 + 2 LIOH → Li2CO3 + H2O
The molar mass of CO2 is 44.01 g/mol, and the molar mass of LIOH is 23.95 g/mol.
This means that 2 moles of LIOH are needed to absorb 1 mole of CO2.
So, to absorb 136,080 g of CO2, we need:
136,080 g CO2 x (1 mol CO2/44.01 g) x (2 mol LIOH/1 mol CO2) x (23.95 g LIOH/1 mol) = 139,648 g LIOH
Since each CCC contains 750 g of LIOH, we need:
139,648 g LIOH / 750 g CCC = 186.2 CCCs
Therefore, we need to carry at least 187 CCCs on board the space shuttle to absorb all the CO2 produced by the crew during the 18-day mission.
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Does anyone have Personal Care services on E2020
Here are some questions on Personal Care services on E2020 are:
A client with a new ileostomy has been home for four days. The HHA is giving the client a bath and notices that the pouch is full. The HHA should say to the client: D. "I'll empty the pouch for you."A client is bedridden at home and has an infected draining sacral wound. The infection control supplies that should be kept in the home is: Gloves.What is infection?An infection is the entrance and growth of dangerous microorganisms in the body that harm the host, such as bacteria, viruses, fungus, or parasites.
Infections can be systemic (affecting the entire body) or localized (affecting a particular area of the body), and they can be moderate to severe.
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Pleas help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
_______________________________
2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g)
Moles of NA = Given Mass (g) ÷ Molecular Mass (g/mol)
= 27.5 ÷ 22.9897
= 1.196 mol
Moles of H2 Produced = Mol of NA × 1 mol H2 ÷ 2 Mol NA
= 1.196 × 1 ÷ 2
= 0.60 mol
Number of Molecules = Moles × Avogadro's Number
= 0.60 × 6.023 × 10²³ mol - 1
= 3.61 × 10²³
The Number of Molecules of Hydrogen Gas Produced When Added To Water Is 3.61 × 10²³
_________________________________
How many grams of O are in 615g of N2O?
There are approximately 223.2 grams of oxygen in 615 grams of N2O.
To find the number of grams of O in 615g of N2O, we first need to understand the chemical formula of N2O. N2O is a compound made up of two nitrogen atoms (N) and one oxygen atom (O). Therefore, the molecular weight of N2O would be:
(2 x atomic weight of N) + (1 x atomic weight of O)
= (2 x 14.01 g/mol) + (1 x 16.00 g/mol)
= 44.01 g/mol
Now, to calculate the number of grams of O in 615g of N2O, we need to know the proportion of O in the compound. Since there is only one oxygen atom in each molecule of N2O, we can find the proportion of O by dividing the atomic weight of O by the molecular weight of N2O:
Atomic weight of O / Molecular weight of N2O
= 16.00 g/mol / 44.01 g/mol
= 0.363
This means that oxygen makes up 36.3% of the total weight of N2O. To find the number of grams of O in 615g of N2O, we can multiply the total weight by the proportion of O:
615g x 0.363
= 223.2g
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draw the lewis structure of ch3br
The Lewis structure of the compound[tex]CH_{3} Br[/tex] is shown in the image attached.
What is the Lewis structure?The Lewis structure of a molecule or ion is produced by arranging the atoms in a manner that lessens the attraction between their valence electron pairs and then distributes the valence electrons among the atoms to form covalent bonds.
The octet rule, which states that atoms normally gain or lose electrons to obtain a stable configuration with eight valence electrons, frequently serves as a guidance when arranging electrons in the Lewis structure.
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The change in enthalpy (AH, ) for a reaction is -25.8 kJ mol.
The equilibrium constant for the reaction is 1.4 × 103 at 298 K.
What is the equilibrium constant for the reaction at 655 K?
The equilibrium constant for the reaction at 655 K is [tex]e^{6.96}[/tex] ≈ 1.05 × 10^3.
The equilibrium constant (K) for a reaction is related to the change in Gibbs free energy (ΔG) through the equation:
ΔG = -RTlnK
where R is the gas constant, T is the temperature in kelvin, and ln is the natural logarithm. Since ΔG and ΔH (the change in enthalpy) are related by the equation:
ΔG = ΔH - TΔS
where ΔS is the change in entropy, we can rearrange the first equation to get:
lnK = -ΔH ÷ RT + ΔS ÷ R
At 298 K, we can use the given values of ΔH and K to solve for ΔS:
lnK = -ΔH ÷ RT + ΔS ÷ R
ln(1.4 × 10³) = (-(-25.8 × 10³ J/mol) ÷ (8.314 J/mol K × 298 K)) + ΔS ÷ 8.314 J/mol K
ΔS = 78.2 J/mol K
Now we can use the equation above to solve for lnK at 655 K, using the same value of ΔH and the newly calculated value of ΔS:
lnK = -ΔH ÷ RT + ΔS ÷ R
lnK = -(-25.8 × 10³ J/mol) ÷ (8.314 J/mol K × 655 K) + (78.2 J/mol K) ÷ 8.314 J/mol K
lnK = 6.96
e ≈ 1.05 × 10³
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Iron pyrite (FeS2) is the form in which much of
the sulfur exists in coal. In the combustion of
coal, oxygen reacts with iron pyrite to produce
iron(III) oxide and sulfur dioxide, which is a
major source of air pollution and a substantial
contributor to acid rain. What mass of Fe2O3
is produced from 74 L of oxygen at 2.97 atm
and 161◦C with an excess of iron pyrite?
Answer in units of g
The mass of Fe₂O₃ produced is 101.9 g.
How to calculate mass ?The balanced chemical equation for the combustion of iron pyrite is:
4FeS₂(s) + 11O₂(g) → 2Fe₂O3(s) + 8SO₂(g)
From the equation, 11 moles of oxygen are required to produce 2 moles of Fe₂O₃. Convert the given volume of oxygen to moles:
n(O2) = PV/RT = (2.97 atm)(74 L)/(0.0821 L·atm/mol·K)(161 + 273 K) = 3.51 mol
Since the reaction requires 11 moles of O₂ for every 2 moles of Fe₂O₃, calculate the moles of Fe₂O₃ produced:
n(Fe₂O₃) = (2/11) × n(O₂) = (2/11) × 3.51 mol = 0.638 mol
Finally, use the molar mass of Fe₂O₃ to convert moles to grams:
m(Fe₂O₃) = n(Fe₂O₃) × M(Fe₂O₃) = 0.638 mol × 159.69 g/mol = 101.9 g
Therefore, the mass of Fe₂O₃ produced is 101.9 g.
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Water can dissolve many substances because-
-
it has a partial charge on each side of its molecules
it has a linear molecular shape
it has a nonpolar molecular structure
it has the molecular formula H₂O
Answer:
Water can dissolve many substances because it has a partial charge on each side of its molecules.
Explanation:
Water is a polar molecule, meaning that it has an uneven distribution of electrons between its hydrogen and oxygen atoms. This creates a partial negative charge on the oxygen side of the molecule and a partial positive charge on the hydrogen side. These partial charges allow water molecules to attract and surround other charged or polar molecules, such as ions and polar compounds, and separate them from each other. This process of surrounding and separating other substances in a solution is known as hydration or dissolution, and it is what allows water to dissolve many substances. Therefore, the correct option is: "it has a partial charge on each side of its molecules."
A zinc chloride solution is prepared by dissolving 0.316 g of anhydrous zinc chloride in 100.0 mL of H2O.
What mass of zinc chloride is present in 19.97 mL of that solution.
A zinc chloride solution is prepared by dissolving 0.316 g of anhydrous zinc chloride in 100.0 mL of [tex]H_2O[/tex] . The mass of zinc chloride present in 19.97 mL of the solution is 0.316 g.
We can use the formula:
C1V1 = C2V2
where C1 is the concentration of the original solution, V1 is the volume of the original solution, C2 is the concentration of the final solution, and V2 is the volume of the final solution.
First, let's calculate the concentration of the original solution:
concentration = (0.316 g) / (100.0 mL) = 0.00316 g/mL
Now, we can use the formula to find the mass of zinc chloride in 19.97 mL of the solution:
C1V1 = C2V2
0.00316 g/mL x 100.0 mL = C2 x 19.97 mL
C2 = (0.00316 g/mL x 100.0 mL) / 19.97 mL
C2 = 0.01583 g/mL
So the concentration of zinc chloride in the final solution is 0.01583 g/mL.
Now we can use this concentration to calculate the mass of zinc chloride in 19.97 mL of the solution:
mass = concentration x volume
mass = 0.01583 g/mL x 19.97 mL
mass = 0.316 g
Therefore, there are 0.316 g of zinc chloride present in 19.97 mL of the solution.
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The characteristics of two different types of reactions are shown below:
Reaction A: An atom loses electrons during the reaction.
Reaction B: An atom loses protons and neutrons during the reaction.
Which statement is true about the two reactions?
Both reactions retain the identity of the elements.
Both reactions change the identity of the elements.
Reaction A produces more energy than Reaction B.
Reaction B produces more energy than Reaction A.
The statement that is true about the reactions is
Both reactions retain the identity of the elements.How to identify the true statementIn Reactions A and B, the participating atoms preserve their elemental identity despite losing electrons (in Reaction A) or protons and neutrons (in Reaction B). This can give rise to distinct isotopes or ions of the same element while preserving its fundamental attributes.
The statements concerning energy production aren't necessarily accurate or linked with the reaction's traits. Energy output depends on many variables, such as specific reactants involved and their conditions during reactions.
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1. Which of the following stars has a temperature of approximately 9000 K and luminosity about to
20 times greater than the Surfs luminos
a Sirius
b. Procyon
c. Figel
d. Polaris
2. Which of the following types of stars is considered part of the main sequera
a Supergants
b. Red giants
c. Red dwarts
d. White dwarfs
3. Which of the following stars is cooler than the
Surf
a. Procyon B
b. Pigel
C. Barnard's Star
d. Sirius
4. The Sun is classified with which of the following types of stars?
a. Supergiants
b. Red giants
c. Main sequence
d. White dwars
5. Which of the forces listed below is most responsible for the formation of start?
a. Gravity
b. Magnetism
c. Bectromagnetism
d. Light
6. Which star has a higher luminosity and a lower temperature than the Sun?
a. Pigel
b. Barnard's Star
c. Alpha Centauri
d. Aldebaran
7. Compared to the temperature and luminosity of the star Polars, the star Srus is
a. hotter and more luminous
b. hotter and less luminous
c. cooler and more luminous cooler and less luminous
1. The star that has a temperature of approximately 9000 K and luminosity about 20 times greater than the Sun’s luminosity is Vega.
2. The type of star that is considered part of the main sequence is red dwarfs.
3. The star that is cooler than the Sun is Barnard’s Star.
4. The Sun is classified as a main sequence star.
5. The force most responsible for the formation of stars is gravity.
6. The star that has a higher luminosity and a lower temperature than the Sun is Aldebaran.
7. Compared to the temperature and luminosity of the star Polaris, the star Sirius is hotter and more luminous.
6. A 90.0 gram sample of an unknown solid is heated to 80 °C and placed into a calorimeter containing 120 grams of water at 24 °C. If the final temperature of the solid sample and the water is 32 °C, what is the specific heat of solid?
PLEASE SHOW WORK
Answer:
1.02 J/g°C.
Explanation:
We can use the equation:
q = m * c * ΔT
where q is the heat absorbed or released, m is the mass of the substance (in grams), c is the specific heat, and ΔT is the change in temperature (in Celsius).
First, we can calculate the heat gained by the water:
q_water = m_water * c_water * ΔT_water
where m_water is the mass of the water (in grams), c_water is the specific heat of water (4.184 J/g°C), and ΔT_water is the change in temperature of the water.
m_water = 120 g
c_water = 4.184 J/g°C
ΔT_water = (32°C - 24°C) = 8°C
q_water = (120 g) * (4.184 J/g°C) * (8°C) = 4009 J
This means that the heat lost by the unknown solid is equal to the heat gained by the water:
q_solid = -q_water
q_solid = -4009 J
Next, we can calculate the change in temperature of the solid:
ΔT_solid = (32°C - 80°C) = -48°C
Now, we can solve for the specific heat of the solid:
q_solid = m_solid * c_solid * ΔT_solid
-4009 J = (90.0 g) * c_solid * (-48°C)
c_solid = -4009 J / (90.0 g * -48°C)
c_solid = 1.02 J/g°C
Therefore, the specific heat of the unknown solid is 1.02 J/g°C.
If an atom loses an electron, what will its resulting charge be?
Answer:
If an atom loses or gains electrons, it will become a positively or negatively charged particle, called an ion. The loss of one or more electrons results in more protons than electrons and an overall positively charged ion, called a cation.
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Convert the following number
into correct scientific notation.
0.0602 x 10^25
[ ? ] × 10 [ ? ]
The number is converted to 60. 2 × 10²²
What are index forms?Index forms are simply described as mathematical forms that are used in the representation of numbers that are too small or too large in more convenient forms.
These index forms are also referred to as scientific notation or standard forms.
Some rules of index forms are;
Add the exponents when multiplying forms of the same basesSubtract the exponents when dividing forms of the same basesFrom the information given, we have that;
0. 0602 × 10 ²⁵
Subtract three from the exponent value and move three spaces right, we have;
60. 2 × 10²⁵⁻³
60. 2 × 10²²
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1. How many joules of heat is needed to heat 68.00 grams of aluminum foil from 55.00 °C to 93.00 °C if aluminum has a specific heat of 0.90 J/g °C?
2. Which of the following equations is an exothermic reaction?
Answer:
7. C. 2326 J
8. B
Explanation:
7. Use the equation q=m*c* change in temp, where m is mass, c is specific heat capacity.
q= 68 g* (0.9 J/g*c) * (93-55) C
q= 2326 J
8. An exothermic reaction is characterized by a negative delta H (change in enthalpy) since energy is released during the reaction. B is the only choice with a negative delta H.
The specific heat of gold is 0.129 J/g C. A king gets sold a gold crown but he's unsure if it's pure gold. He takes the crown which weighs 1,130 grams, heats it to 98.8 C, and then places it in 1.34 L of water with a starting point of 25.83 C. The final temperature of the water is 27.84 C. What is the specific heat of the crown and is it pure gold?
We can use the formula:
Q = mcΔT
where Q is the heat absorbed or released, m is the mass, c is the specific heat, and ΔT is the change in temperature.
First, let's calculate the heat absorbed by the crown:
Q1 = mcΔT
Q1 = (1130 g)(0.129 J/g C)(98.8 C - 25.83 C)
Q1 = 107,776.6 J
Next, let's calculate the heat released by the crown into the water:
Q2 = mcΔT
Q2 = (m)(c)(ΔT)
Q2 = (1340 g)(4.184 J/g C)(27.84 C - 25.83 C)
Q2 = 11096.64 J
Since Q1 = -Q2 (heat lost by the crown is equal to heat gained by the water),
mcΔT = -mcΔT
We can then solve for the specific heat of the crown:
c = -(Q2/mΔT)
c = -(11096.64 J)/(1130 g)(27.84 C - 25.83 C)
c = 0.131 J/g C
The specific heat of pure gold is 0.129 J/g C, and the specific heat of the crown is 0.131 J/g C. Since the specific heat of the crown is slightly higher than that of pure gold, it is possible that the crown is not pure gold. However, other factors such as impurities or alloying metals can also affect the specific heat, so further analysis would be necessary to confirm if the crown is pure gold.
How are models used in chemistry? How does evidence change these models?
Answer: As they develop theories, chemists use models to attempt to explain their findings. Chemists assess the model they are using as new evidence becomes available and, if required, continue to refine it by making modifications.
Explanation:
How many grams of KOH are needed to make 185.5 ml with a concentration of 5 M?
Type your answer...
To calculate the mass of KOH needed to make a 5 M solution in 185.5 mL, we need to use the formula:
mass = moles × molar mass
where moles is the amount of KOH in moles and molar mass is the mass of one mole of KOH.
We can calculate the moles of KOH as follows:
moles = Molarity × Volume (in liters)
First, we need to convert the volume from milliliters to liters:
185.5 mL = 0.1855 L
Now we can calculate the moles of KOH:
moles = 5 M × 0.1855 L = 0.9275 moles
The molar mass of KOH is 56.11 g/mol. Therefore, the mass of KOH needed is:
mass = 0.9275 moles × 56.11 g/mol = 52.05 g
Therefore, 52.05 grams of KOH are needed to make a 5 M solution in 185.5 mL.
Which
thermochemical
equation
corresponds to
the graph?
Answer: C
Explanation:
Answer: C
Explanation:
You want to have a barbecue this weekend! But you're worried about global warming. You only want to release a maximum of 0.750 kg of carbon dioxide from your propane grill. Using the below equation to answer the following questions.
CH3(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
ΔHrxn = -2220.1 kJ
a. How many kilojoules will you be able to release?
b. If it requires 1900 kJ to cook one hamburger, how many hamburgers can you cook?
a. We will be able to release 37,827 kJ. b. You can cook a maximum of 19 hamburgers without exceeding the limit of 0.750 kg of carbon dioxide.
a. We need to use the balanced chemical equation and the enthalpy change of the reaction.
Therefore, moles [tex]CO_2[/tex] produced are[tex]0.750 kg / 44.01 g/mol = 17.03 mol.[/tex]
The enthalpy change of the reaction is -2220.1 kJ/mol. Thus, the maximum number of kilojoules that can be released is:
[tex]\Delta Hrxn * moles of[/tex] [tex]CO_2[/tex] = [tex]-2220.1 kJ/mol * 17.03 mol = -37,827 kJ[/tex]
We need to reverse the sign of the answer, giving us 37,827 kJ.
b. If it requires 1900 kJ to cook one hamburger, we can divide the maximum number of kilojoules that can be released by the energy required to cook one hamburger:
37,827 kJ / 1900 kJ/hamburger = 19.91 hamburgers
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