Answer:
def check_password(password):
is_short = False
has_uppercase = False
has_lowercase = False
has_digit = False
if len(password) < 8:
is_short = True
for p in password:
if p.isupper():
has_uppercase = True
if p.islower():
has_lowercase = True
if p.isdigit():
has_digit = True
if is_short == False and has_uppercase and has_uppercase and has_digit:
return True
else:
return False
while True:
password = input("Enter your password: ")
password2 = input("Enter your password again: ")
if password == password2 and check_password(password):
break
Explanation:
Create a function named check_password that takes one parameter, password
Inside the function:
Initialize the is_short, has_uppercase, has_lowercase, and has_digit as False. These variables will be used to check each situation
Check the length of the password using len() method. If it is smaller than 8, set is_short as True
Create a for loop that iterates through password. Check each character. If a character is uppercase, set the has_uppercase as True (use isupper() function). If a character is lowercase, set the has_lowercase as True (use islower() function). If a character is a digit, set the has_digit as True (use isdigit() function).
When the loop is done, check the value of is_short, has_uppercase, has_lowercase, and has_digit. If is_short is False and other values are True, return True. Otherwise, return False
Create an indefinite while loop, that asks the user to enter password twice. Check the entered passwords. If they are equal and the check_password function returns True, stop the loop. This implies that both passwords are same and password is valid.
• Open your Netbeans IDE and answer the following question
• Create a folder on the desktop. Rename it with your student name and student number
• Save your work in the folder you created.
At a certain store they sell blank CDs with the following discounts:
* 10% for 120 or more
* 5% for 50 or more
* 1% for 15 or more
* no discount for 14 or less
Write a program that asks for a number of discs bought and outputs the correct discount. Use either a switch statement or if..elseif.. ladder statements. Assuming that each blank disk costs N$3.50. The program should then calculate the total amount paid by the buyer for the discs bought.
Answer:
public static void main(String[] args)
{
int cdCount;
double cdCountAfterDiscount;
DecimalFormat df = new DecimalFormat("$##.##"); // Create a Decimal Formatter for price after discount
System.out.println("Enter the amount of CD's bought");
Scanner cdInput = new Scanner(System.in); // Create a Scanner object
cdCount = Integer.parseInt(cdInput.nextLine()); // Read user input
System.out.println("CD Count is: " + cdCount); // Output user input
if(cdCount <= 14 )
{
System.out.println("There is no discount");
System.out.println("The final price is " + cdCount*3.5);
}
if(cdCount >= 15 && cdCount<=50)
{
System.out.println("You have a 1% discount.");
cdCountAfterDiscount = (cdCount *3.5)-(3.5*.01);
System.out.println("The final price is " + df.format(cdCountAfterDiscount));
}
if(cdCount >= 51 && cdCount<120)
{
System.out.println("You have a 5% discount.");
cdCountAfterDiscount = (cdCount *3.5)-(3.5*.05);
System.out.println("The final price is " + df.format(cdCountAfterDiscount));
}
if(cdCount >= 120)
{
System.out.println("You have a 10% discount.");
cdCountAfterDiscount = (cdCount *3.5)-(3.5*.1);
System.out.println("The final price is " + df.format(cdCountAfterDiscount));
}
}
Write a program with three functions: upper , lower , and reverse . The upper function should accept a pointer to a C-string as it's only argument. It should step through each character in the string, converting it to uppercase. The lower function, too, should accept a pointer to a C-string as it's only argument. It should step through each character in the string, converting it to lowercase. Like upper and lower , reverse should also accept a pointer to a string as it's only argument. As it steps through the string, it should test each character to determine whether it is upper- or lowercase. If a character is uppercase, it should be converted to lowercase. Likewise, if a character is lowercase, it should be converted to uppercase. Test the functions by asking for a string in function main , then passing it to them in the following order: reverse, lower , and upper. Main will then print out the strings to demonstrate the functions worked. Each function accepts exactly one argument. None of the functions return anything. None of the functions (other than main) interacts with the user in anyway. Variables of type string are not allowed.
Answer:
Here is the C++ program:
#include <iostream> //to use input output functions
#include <cstring> //to manipulate C-strings
#include <string> //to manipulate strings
using namespace std; //to access objects cin cout
//function prototypes
void upper(char *); to convert to upper case
void lower(char *); //to convert to lower case
void reverse(char *); //to convert to reverse case
int main() { //start of main method
char input[101]; //creates a char type array to hold input string
cout << "Enter a string: "; //prompts user to enter a string
cin.getline(input, 101); //reads input string from user
upper(input); //calls upper() method to convert the string to upper case
lower(input); //calls lower() method to convert the string to lower case
reverse(input); } //calls reverse() method to convert the string to reverse case
void upper(char *cString){ //method that takes a pointer to a C-string as it's only argument and converts that string to upper case
cout << "String in upper case: "; //displays string in upper case
for(int i = 0; i < strlen(cString); i++){ //iterates through the input string cString until the length of the cString is reached
if(islower(cString[i])) //checks if the character at i-th index of cString is in lower case
cout << (char) toupper(cString[i]); //converts each i-th character of cString to upper case at each iteration
else //if no character of cString is in lower case
cout << cString[i]; } //displays the cString as it is
cout << endl;} //prints a new line
void lower(char *cString){ //method that takes a pointer to a C-string as it's only argument and converts that string to lower case
cout << "String in lower case: "; //displays string in lower case
for(int i = 0; i < strlen(cString); i++){ //iterates through each character using for loop first character to last
if(isupper(cString[i])) //checks if the character at i-th index of cString is in upper case
cout << (char) tolower(cString[i]); //converts each i-th character of cString to lower case at each iteration
else //if no character of cString is in upper case
cout << cString[i]; } //displays the cString as it is
cout << endl; } //prints a new line
void reverse(char *cString){ //method that takes a pointer to a C-string as it's only argument and converts that string to reverse case (upper to lower and vice versa)
cout << "String in reverse case: "; //displays string in reverse case
for(int i = 0; i < strlen(cString); i++){ //iterates through each character using for loop first character to last
if(isupper(cString[i])) //checks if the character at i-th index of cString is in upper case
cout << (char) tolower(cString[i]); //converts character at i-th position of cString to lower
else //if the character is in lower case
cout << (char) toupper(cString[i]); } //converts character at i-th position of cString to upper
cout << endl;} //prints a new line
Explanation:
I will explain the program with an example.
Lets suppose user enters "hi" as input. So
Now first upper() method is called by passing this C-string to it.
It has a for loop that checks at each iteration, if a character of C-string is in lower using islower method which returns true if the character is in lower case. Since both the characters 'h' and 'i' are in lower in case so they are converted to upper case at each iteration using toupper() method. So the output of this part is:
String in upper case: HI
Now next lower() method is called by passing this C-string to it.
It has a for loop that checks at each iteration, if a character of C-string is in upper using isupper method which returns true if the character is in upper case. Since both the characters 'h' and 'i' are in lower in case so the string remains as it is. So the output of this part is:
String in lower case: hi
Now next reverse() method is called by passing this C-string to it.
It has a for loop that checks at each iteration, if a character of C-string is in upper using isupper method which returns true if the character is in upper case. Since both the characters 'h' and 'i' are in lower so else part: cout << (char) toupper(cString[i]); executes which converts these characters to upper case (reverse case). So the output of this part is:
String in reverse case: HI
The screenshot of program output with a different example is attached.
Common lossless compressed audio file formats include
WMA and JIFF
WAV and AU
MP3 and MP4a
FLAC and ALAC
Answer:
The answer to this question is given below in the explanation section. The forth one (FLAC and ALAC) is the correct option.
Explanation:
Common lossless compressed audio file formats include
WMA and JIFF WAV and AU MP3 and MP4a FLAC and ALACLossless compression formats include the common FLAC, WavPack, Monkey's Audio, ALAC (Apple Lossless). Other options are not common lossless compressed audio formats.
Answer:d d
Explanation:
You can copy and paste ________ from excel to powerpoint
Answer: data
Explanation:
Determine whether the compound condition is True or False.
4 < 3 and 5 < 10
4 <3 or 5 < 10
not (5 > 13)
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The given compound statement are:
4 < 3 and 5 < 10
4 <3 or 5 < 10
not (5 > 13)
4 < 3 and 5 < 10 this statement is false because "and" logical operator required that both operand (4<3) and (5<10) are true. Statement (4<3) is a false statement so this statement is false. "and" operator becomes true when all its inputs are true otherwise it becomes false.
4 < 3 or 5 < 10 this statement is true because "or" logical operator to be true if one of its input is true and false when all inputs are false. so in this compound statement, the first statement is false and the second statement is true. so this compound statement is true.
not(5>13) this compound statement is true because it has "not" operator and "not" operator makes a false statement to true and vice versa. so (5>13) is a false statement, and when you append "not" operator before it, then this compound statement will become true statement, so this is a true statement.
The given compound conditions would be considered true or false as follows:
i). 4 < 3 and 5 < 10 - False
ii). 4 <3 or 5 < 10 - True
iii). not (5 > 13) - True
i). 4 < 3 and 5 < 10 would be considered false and the reason behind this is that the logical operator 'and' implies that both are equivalent but here 4 < 3 is incorrect as it differentiates from the meaning conveyed in 5 < 10ii). In the second statement i.e. 4 <3 or 5 < 10, 'or' is the correct logical operator because one of the parts i.e. 5 < 10 is actually true while the latter is false.iii) In the next part "not (5 > 13)" is also true as it adequately uses the operator 'not' to imply that 5 is not bigger than 13 which implies it to be true.
Thus, the first statement is false and the other two are true.
Learn more about 'Compound Condition' here:
brainly.com/question/1600648
who could be involved in the murder of Mr Douglas
Answer:
Freedy Thopson
Explanation:
asking questions is super in this education life
Alan wants to buy camera support equipment that would provide mechanical support to his camera and which could also store extra battery power. Which piece of camera equipment should Alan buy for this purpose?
Alan can use a ____, which would provide mechanical assistance and store extra batteries for his camera.
Answer:
Could it be tripod?
Explanation:
If you did this question do you remember what the answer was?
Answer:
motorized grip
Explanation:
What does the fact that online games are so popular most likely prove?
A. People don't like board games.
B. Online games are an influential medium.
C. All games are addictive.
D. Everyone should play online games.
B. Online games are an influential medium.
In programming, what is a floating-point number?
A number with a decimal, Option A
As a producer you are willing to supply the most goods at the highest price this is because the highest price earns you the
Answer:
most money
Explanation:
common sense
Given four values representing counts of quarters, dimes, nickels and pennies, output the total amount as dollars and cents. Output each floating-point value with two digits after the decimal point, which can be achieved as follows: System.out.printf("Amount: $%.2f\n", dollars); Ex: If the input is: 4 3 2 1 where 4 is the number of quarters, 3 is the number of dimes, 2 is the number of nickels, and 1 is the number of pennies, the output is: Amount: $1.41 For simplicity, assume input is non-negative.
LAB ACTIVITY 2.32.1: LAB: Convert to dollars 0/10 LabProgram.java Load default template. 1 import java.util.Scanner; 2 3 public class LabProgram 4 public static void main(String[] args) { 5 Scanner scnr = new Scanner(System.in); 6 7 /* Type your code here. */|| 8 9) Develop mode Submit mode Run your program as often as you'd like, before submitting for grading. Below, type any needed input values in the first box, then click Run program and observe the program's output in the second box Enter program input (optional) If your code requires input values, provide them here. Run program Input (from above) 1 LabProgram.java (Your program) Output (shown below) Program output displayed here
Answer:
Replace /* Type your code here. */ with the following lines of code
int quarter =scnr.nextInt();
int dime = scnr.nextInt();
int nickel = scnr.nextInt();
int penny = scnr.nextInt();
double dollars = quarter * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;
System.out.printf("Amount: $%.2f\n", dollars);
System.out.print((dollars * 100)+" cents");
Explanation:
The next four lines declare the given currencies as integer
int quarter =scnr.nextInt();
int dime = scnr.nextInt();
int nickel = scnr.nextInt();
int penny = scnr.nextInt();
This line calculates the amount in dollars
double dollars = quarter * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;
The next two lines print the amount in dollars and cents respectively
System.out.printf("Amount: $%.2f\n", dollars);
System.out.print((dollars * 100)+" cents");
Given four values representing counts of quarters, dimes, nickels and pennies, the total amount in dollars and cent can be represented as follows;
#1 quarters = 0.25 dollars
#1 dime = 0.1 dollar.
#1 nickel = 0.05 dollars
#1 penny = 0.01 dollars
#quarters, dimes, nickels and pennies,
x = input("write your input here: ")
for i in x:
quarters = 0.25*float(x[0])
dime = 0.1*float(x[1])
nickel = 0.05*float(x[2])
penny = 0.01*float(x[3])
sum1 = quarters + dime + nickel + penny
print(round(sum1, 2))
Code explanation:The commented section of the code is just the conversion rate of quarters, dime, nickel and penny to dollars.
Variable x is used to store the user's input.Then, we loop through the users inputThen multiply each looped value by it conversion rate to dollars.Finally, we sum the values and print the sum rounded to 2 decimal places as required.learn more on python code here: https://brainly.com/question/24556911?referrer=searchResults
Remy’s manager has asked him to change the background color scheme from reds to blues in the standard template the company uses for employee training presentations. She cautioned him not to change any other elements of the template.
What should Remy do in the Slide Master view to change only the color scheme?
In the Background group, select Colors, and find a color scheme that fits.
Choose Edit Theme, and select a new theme that includes a blue background.
Go to the Master Layout group, click Insert Placeholder, and choose a placeholder with a blue background.
Change the background color to light blue, and save the file as a new presentation rather than as a template.
Answer:
A on edg
Explanation:
I took the assigment
Answer: in the background group, select colors, and find a color scheme that fits.
Explanation:
CNT Books has expanded considerably since you got the network up and running three years
ago. It now occupies an entire floor in the building, and its LAN has grown to include several
servers and more than 60 workstations.
CNT Books has recently purchased another book company and needs more space and
computers. Expansion plans include leasing another floor four stories above the current offices
in the same building and adding 35 workstations and at least one more server immediately,
with additional equipment purchases expected. [15 marks]
i. What type of network is called for—LAN, WAN, MAN, or internetwork?
Answer:
The answer to this question is given below in the explanation section
Explanation:
CNT Books has expanded considerably since you got the network up and running three years ago. It now occupies an entire floor in the building, and its LAN has grown to include several servers and more than 60 workstations.
CNT Books has recently purchased another book company and needs more space and computers. Expansion plans include leasing another floor four stories above the current offices in the same building and adding 35 workstations and at least one more server immediately, with additional equipment purchases expected.
The type of networking CNT Book will use is WAN.
LAN
A local area network (LAN) is a group of computers and peripheral devices that share a common communications line or wireless link to a server within a distinct geographic area. A local area network may serve as few as two or three users in a home-office or several hundred users in a corporation's central office
WAN
A wide area network (WAN) is a geographically distributed private telecommunications network that interconnects multiple local area networks (LANs). A LAN is a group of computers and network devices which are all connected to each other, typically from within a short relative geographical distance.
MAN
A metropolitan area network is a computer network that interconnects users with computer resources in a geographic region of the size of a metropolitan area.
internetworking
Internetworking is the process or technique of connecting different networks by using intermediary devices such as routers or gateway devices. Internetworking ensures data communication among networks owned and operated by different entities using a common data communication and the Internet Routing Protocol. internetworking is not a network type but it is a process or technique of connecting different networks by using intermediary devices.
Read each description below, and then choose the correct term that matches the description from the drop-down menus.
wireless technology that lets you identify and track objects
medical uses of RFID
a low-power radio wave used for short distances
computing device used with Bluetooth Read each description below, and then choose the correct term that matches the description from the drop-down menus.
wireless technology that lets you identify and track objects
medical uses of RFID
a low-power radio wave used for short distances
computing device used with Bluetooth
Answer:
wireless technology that lets you identify and track objects (radio frequency identification)
medical uses of RFID (patient identification)
a low-power radio wave used for short distances (bluetooth)
computing device used with Bluetooth hands-free microphone in car
Explanation:
sorry if late :/
Answer:
Explanation:
edg 2021
Which option in the Caption dialog box configures whether the caption appears above or below the image?
Label
New Label
Position
Numbering
Answer:
label
jhguy
iiy767
jiuuyuihlk
njhuiyyhjjgiug
gugkjbkjhg
Answer:
Position
Explanation:
Programming Project: N-Queens Prerequisites: Chapter 5 For this project you will create a class that solves a variation of the 8-Queens Problem, the N-Queens Problem. If you need a recap of the 8-Queens Problem watch this video. The N-Queens Problem is identical to the 8-Queens Problem except we vary the size of the board. So, we can find the placement of queens on a 4x4 board (the 4-Queens Problem) or a 9x9 board (the 9-Queens Problem), etc. Your solution to the N-Queens Problem will be implemented entirely in the class ChessBoard which will at minimum include:
How would an assignee enter details, such as mileage and billing information, for a task?
Create a new task, and enter the details.
Open the status report, and enter the details.
In the main task window, click the Details button.
Within the assigned task window, scroll to the bottom.
Answer:
It's C
Explanation:
On edg
Answer:
C is correct
Explanation:
I got it on edg
After modifying a numbered list in her presentation, Su notices the numbers and the text are too close to each other. She knows she can solve this issue by using the hanging indent marker. Unfortunately, the ruler is not visible in her PowerPoint workspace.
Which tab and command group should she use to access the ruler? (View, Show or Insert, Add-ins or Home, Paragraph)
After selecting the numbered list, in which direction should she drag the hanging indent marker to increase the space between the numbers and the text? (upward or downward or to the left or to the right)
Answer:
1. View, show
2. to the right
Explanation:
On edg
Answer:
1) View, Show
2) to the right
Explanation:
Passivity can harm relationships because those who are passive
a. Have open relationships with others
b. Tend to store up hurt feelings, leading to resentment
C. Typically have excessive self-esteem
d. Are free from self doubt and worry
Answer:
B. Tend to store up hurt feelings, leading to resentment
Explanation:
May I have brainliest please? :)
Passivity can injure relationships because those who are passive that can tend to store up hurt impressions, leading to resentment.
What is the Passivity?passiveness or Passivity is defined as Only the feeling of repository visitors that pass before his paintings get down me more than this charlatan, and they may have a hunch that they are being duped, but they are unable to accept the information of their eyes.
Passivity can ruin relationships because passive people prefer to hold on to upset sentiments, which can develop to resentment.
Therefore, option b is correct.
Learn more about the Passivity, refer to:
https://brainly.com/question/20924905
#SPJ2
Which insert image option allows a user to compile, modify, and add captions to images?
Pictures
Screenshot
Photo Album
Online Pictures
Answer:
heres my answer and my proof
Explanation:
Photo Album is insert image option allows a user to compile, modify, and add captions to images. Hence, option C is correct.
What is a Photo Album?A piece of software called a digital picture album allows users to upload image files from a computer's hard drive, memory card, scanner, or digital camera to a central database.
A bound or loose-leaf book with blank pages, pockets, envelopes, etc. used for displaying or storing photographs, stamps, and other valuables, as well as for autographs. an audio compilation of various musical selections, a whole drama, an opera, etc.
The paper of your choosing is directly printed with the images for your picture book. In picture albums, photo prints are commonly adhered to the pages. Photo books are frequently lighter and thinner than conventional photo albums, taking up less room on the coffee table or shelf.
Thus, option C is correct.
For more information about Photo Album, click here:
https://brainly.com/question/20719259
#SPJ2
Which three skills are useful for success in any career?
Answer:
Problem solving.
Teamwork. ...
Initiative. ...
Analytical, quantitative. ...
Professionalism, work ethic. ...
Leadership. ...
Detail oriented.
Answer: Multitasking Skills, Resource- Management Skills, Time-Management Skills
Explanation: Got it correct!
When you set the position property for a block element to fixed, the element
Answer:
-is positioned relative to the browser window
Hope this helps!
Answer: When you set the position property for a block element to fixed, the element remains in an exact position on the screen even if the page is scrolled down.
differences between a small office and a big office
A user is asked to type a caption for a photo in a web form's text field. If the caption didn't end with a punctuation mark (. ! ?), a period should automatically be added. A common error is to end with a comma, which should be replaced by a period. Another common error is to end with two periods, which should be changed to one period (however, ending with three periods (or more) indicates elipses so should be kept as is). The corrected caption is output. If the input is "I like pie", the output is "I like pie." If the input is "I like pie!", the output remains "I like pie!" If the input is "Coming soon…", the output remains "Coming soon…"
Answer:
Here is the c++ program:
#include <iostream> //to use input output functions
using namespace std; //to identify objects cin cout
int main() { //start of main function
string caption; //stores the caption
int last_index; //stores the index position of the last character of caption
char last_character; //stores the last character of the caption
cout<<"Please type a caption: "; //prompts user to enter a caption
getline(cin, caption); //reads the complete line of caption from user
last_index = caption.size() - 1; //sets the last_index to the last character of caption
last_character = caption.at(last_index); //sets the last_character to the last character positioned by last_index
if ((last_character == '!') || (last_character == '?')) {} /* checks if the last character of the caption is either ! or ? and if this statement evaluate to true then this does not require any action */
else if (last_character == ',') { //checks if the last character of the caption is a comma
caption.at(last_index) = '.'; } //if the else if condition is true then replace that comma with a period .
else if (last_character != '.') { //checks if the caption does not end with ! ? , .
caption.push_back('.');} //append period to the caption . if above if else condition is true
else if ((last_index > 0) && (last_character == '.') && (caption.at(last_index - 1) == '.')) { //checks if the caption has two periods .
if ((last_index > 1) && (caption.at(last_index - 2) == '.')) {} //checks if the caption has three periods and does nothing if this is true
else { //if caption has two periods
caption.pop_back();}} //removes one period if caption has two periods .
cout << caption << endl;} //displays the caption
Explanation:
I will explain the above program with an example
Lets say user input the caption: I like pie
So
caption = " I like pie"
The first if condition if ((last_character == '!') || (last_character == '?')) evaluate to false because the last character of the caption is not an exclamation mark of a question mark. So the program moves to the next else if statement:
else if (last_character == ',') This statement is also false because the last character of the caption is not a comma. So the program moves to the next else if part.
else if (last_character != '.')
Now this statement evaluate to true because the last character of the caption is not a period . sign. So this part is executed. It has a statement:
caption.push_back('.');
Now this statement uses push_back() method which adds new character i.e. period '.' at the end of the caption string, increasing its length by one.
So the output of the program is:
I like pie.
If the caption = " I like pie!" then this if ((last_character == '!') || (last_character == '?')) condition executes and since it does nothing {} so the caption remains as it is and the output is:
I like pie!
If the caption = "Coming soon…" then this else if ((last_index > 0) && (last_character == '.') && (caption.at(last_index - 1) == '.')) condition executes which checks if the caption has two period. When this condition evaluates to true then the statement inside this else if condition executes which is: if ((last_index > 1) && (caption.at(last_index - 2) == '.')) and this checks if the caption has three periods. Yes the caption has three periods so it does nothing and the caption remains as it is and the output is:
Coming soon…
However if the caption is Coming soon.. with two periods then the else part inside else if ((last_index > 0) && (last_character == '.') && (caption.at(last_index - 1) == '.')) condition executes which is: caption.pop_back(); and this removes one period from the caption and the output is:
Coming soon.
The screenshot of the program and its output is attached.
in a blank excel workbook go to insert tab on the ribbon, which of the following is Not vailable 1 smart art 2 coloumns ( not coloumn chart) 3 shapes 4 pictures
Answer:
hahahahahahahhahahThe rows that are not available in a blank excel workbook go to the insert tab on the ribbon. The correct option is D.
What are ribbons?Click the Ribbon Display Options icon in the document's upper right corner. The Minimize icon is to the left of it. To display the Ribbon with all tabs and all commands, select Show Tabs and Commands from the menu that appears.
Basic units known as cells are created by rows and columns in an Excel workbook. There are only a set number of rows and columns available for the workspace.
There are 1,048,576 rows in the workbook's excel worksheet. It cannot be inserted using the Insert tab on the ribbon. Images, tables, and shapes can be added by selecting the tab or option for the Insert tab.
Therefore, the correct option is D, Rows.
To learn more about rows, refer to the link:
https://brainly.com/question/29889229
#SPJ2
The question is incomplete. Your most probably complete question is given below:
Pictures
Table
Shapes
Rows
Why is it important to explore an Integrated
Development Environment?
A. To learn more about the syntax of Java
B. To learn more about the features of the environment
C. To learn more about error handling
D. To learn more about abstractions
Answer:
The answer to this question is given below in the explanation section. The correct answer is B.
Explanation:
The purpose behind to explore an integrated development environment is to learn more about the features of the environment.
So the correct answer is B.
For example, you can use visual studio to build asp.net application using c#, then you need to explore what features visual studio offering to you.
However, other options are incorrect. Because, you can learn more about syntax, error handling, and abstraction in the programming language, not in the IDE.
______ means locating a file among a set of file
Answer:
computer files
Explanation:
Which change should she make in her outline?
Change Step 2 to “Click the Format tab.”
Change Step 3 to “Open the Chart Title dialog box.”
Change Step 4 to “Type in the chart title.”
Change Step 5 to “Add the Chart Title.”
Answer:
A
Explanation:
Use JavaWrite a program that will simulate a change machine found at cash registers. Input the amount due and amount paid from the keyboard.Tell the user how much change is owed and number of quarters, dimes, nickels, and pennies in change a customer would receive.Pay special attention to roundoff error. Your program should use division and modular division. No if’s or loops may be used. You may assume all change will be a positive number with no more than two decimal places. If more than $1.00 is owed, the full value should be included in the number of quarters returned. For example, $2.50 should be returned as 10 quarters.Hint: Modular division is a great way to find the remainder of a division. Think about how you can use this to calculate the change that is left over after some coins are given.Sample Run:Please Enter the Cost of the Item:4.57Please Enter the Amount Paid:5.00Change Owed: 0.43Quarters: 1Dimes: 1Nickels: 1Pennies: 3
Answer:
Here is the JAVA program:
import java.util.Scanner; //to accept input from user
public class Main { // class name
public static void main(String [] args) { // start of main method
Scanner input = new Scanner(System.in); // creates Scanner class object to take input from user
System.out.println("Please Enter the Cost of the Item: "); // prompts user to enter the cost of item
double itemCost = input.nextDouble(); //scans and reads the input value of item cost
System.out.println("Please Enter the Amount Paid: "); // prompts user to enter the amount paid
double amount = input.nextDouble(); //scans and reads the value of amount from user
int change = (int)(amount * 100 - itemCost * 100); //compute the remaining amount i.e. change
System.out.println("Change Owed: " + change / 100.0); // displays the owed change
int quarters = change / 25; // computes the value for quarters
change = change % 25; // compute the quarters remaining
int dimes = change / 10; // computes dimes
change = change % 10; // computes dimes remaining
int nickels = change / 5; // computes nickels
change = change % 5; // compute nickels remaining
int pennies = change; // computes pennies
System.out.println("Quarters: " + quarters); // displays computed value of quarters
System.out.println("Dimes: " + dimes); // displays value of dimes
System.out.println("Nickels: " + nickels); // displays value of nickels
System.out.println("Pennies: " + pennies); }} //displays value of pennies
Explanation:
I will explain the program with an examples.
Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:
Change is computed as
change = (int)(amount * 100 - itemCost * 100);
This becomes;
change = (int)(5.00 * 100 - 4.57 * 100)
= 500 - 457
change = 43
Now the change owed is computed as:
change / 100.0 = 43/100.0 = 0.43
Hence change owed = 0.43
Next quarters are computed as:
quarters = change / 25;
This becomes:
quarters = 43/25
quarters = 1
Now the remaining is computed as:
change = change % 25;
This becomes:
change = 43 % 25;
change = 18
Next the dimes are computed from remaining value of change as:
dimes = change / 10;
dimes = 18 / 10
dimes = 1
Now the remaining is computed as:
change = change % 10;
This becomes:
change = 18 % 10
change = 8
Next the nickels are computed from remaining value of change as:
nickels = change / 5;
nickels = 8 / 5
nickels = 1
Now the remaining is computed as:
change = change % 5;
This becomes:
change = 8 % 5
change = 3
At last the pennies are computed as:
pennies = change;
pennies = 3
So the output of the entire program is:
Change Owed: 0.43 Quarters: 1 Dimes: 1 Nickels: 1 Pennies: 3
The screenshot of the output is attached.
Given code
#include
#include
using namespace std;
bool weHaveWinner(int a,int b)
{
return (a>=21 && b>=21 && abs(a-b)>1);
}
int main()
{
int aPoints = 0;
int bPoints = 0;
string input;
// ToDo: Write a loop until input is "end" or we have a winner
// the loop should read the input and add a point to aPoints if "A"
// or add a point to bPoints if "B", don't do anything but leave the
// loop if "end"
while(1)
{
cin >> input;
if(input=="end")
break;
if(input=="A")
aPoints++;
if(input=="B")
bPoints++;
if(weHaveWinner(aPoints,bPoints))
break;
}
// Tell the user if we have a winner or not
if(aPoints > bPoints + 1 && aPoints >= 21)
{
cout aPoints + 1 && bPoints >= 21)
{
cout << "Team B won! (" << aPoints << "-" << bPoints << ")" << endl;
}
else
{
cout << "Game ended as a draw. (" << aPoints << "-" << bPoints << ")" << endl;
}
return 0;
}
Answer:
YES
Explanation:
Answer:
yeet
Explanation:
yeet
