Answer:
b
Explanation:
The 2-mg Car Increases its
speed uniformly from rest to
28 m/s in 30s up the incline road
determine the maximum power
that must supplied by the engine
which operates with an efficiency
of e=0.8 Also find the
average power supplied by the
engine .
Answer:
0.35
Explanation:
Everyday activities do NOT produce significant muscle growth because:
A. Cytokines are released during everyday activities that inhibit (prevent) muscle regeneration.
B. Muscle growth requires going to the gym and lifting weights.
C. The nervous system cannot respond by recruiting more muscle fibers to generate hypertrophy.
D. The body adapts to the repeated demands so that those movements do not produce enough stress to cause hypertrophy (enlarging of the muscle).
Answer:
When elements bond together or when bonds of compounds are broken and form a new substance
Explanation:
Answer:
D
Explanation:
A rocket of mass m is to be launched fromplanet X, which has a mass M and a radius R. What is the minimum speed that the rocket must have for it to escape into space?
Answer:
The minimum speed = [tex]\sqrt{\frac{2GM}{R} }[/tex]
Explanation:
The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.
The minimum speed can be determined by;
Escape velocity = [tex]\sqrt{\frac{2GM}{R} }[/tex]
where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.
If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.
The minimum speed that the rocket must have for it to escape into space is [tex]\sqrt{\frac{2GM}{R} }[/tex].
What is escape velocity?Escape velocity is the minimum speed that the rocket must have for it to escape into space.
The minimum speed (escape velocity) that the rocket must have for it to escape into space is given as;
[tex]V = \sqrt{\frac{2GM}{R} }[/tex]
where;
M is mass of the planetG is gravitational constantR is the radiusThus, the minimum speed that the rocket must have for it to escape into space is [tex]\sqrt{\frac{2GM}{R} }[/tex].
Learn more about escape velocity here: https://brainly.com/question/13726115
A boat can travel in still water at 56 m/s. If the boats sails directly across a river that flows at 126 m/s. What is the boats speed relative to the ground
Answer:
The answer is below
Explanation:
The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:
V² = 56² + 126²
V² = 19012
V = 137.9 m/s
if the ice on the polar of earth melts , how will it affect the duration of the day ? explain
Answer:
When ice of polar caps of earth melts, mass concentrated near the axis of rotation spreads out. Therefore, the moment of inertia I increases. With increase of I,T will increase i.e length of the day will increase.
The gravitational field at the Moon in N/kg due to the Earth is approximately (G = 6.67 × 10-11 N m2/kg2, the mass of the Earth is 5.98 × 1024 kg, and the distance to the Moon is 3.85 × 108 m)
Answer:
F = 2.69 10⁻³ m [ N]
Explanation:
This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law
F = G m M / r²
where m is the mass of the body, M the mass of the Earth and r the distance between the Earth and the Moon
F = (G M / r²) m
F = (6.67 10⁻¹¹ 5.98 10²⁴ / (3.85 10⁸)² ) m
F = 2.69 10⁻³ m [ N]
This force is directed from the Moon towards the Earth, therefore it reduces the weight of the body
PLEASE PROVIDE AN EXPLANATION.
THANKS!!!
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
A car having a total mass of 2250 kg and traveling at 72.0 km/h smashes into a tree. The car is stopped in 0.250 s. The average force acting on the car during the collision is
A. 1.80, 105 N.
B. 80.0 N.
C. 1.80 102 N
D. zero. E. 2.20 104
Answer:
A. 1.8x10⁵
Explanation:
For this question we have
72km/h = speed
Total mass = 2250kg
Stopped at t = 0.2250s
To get average force acting on this car on collision:
72km/3.6 = 20m|s
Impulse = ∆p
This implies:
F∆t = m∆v
F = m∆v/∆t
= 2250x20/0.250
= 180000
= 1.8x10⁵
Therefore option A is correct.
what is Force and Preasure ??
Answer:
Definition: Pressure:- Force per unit area surface is called pressure. P = F/ A Pressure = Force /Area Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Gauge pressure is the pressure relative to the ambient pressure.
Answer:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.
Pressure is defined to be the amount of force exerted per area.
Formula of pressure = P = F÷A
Where, P = Pressure,
F = Force applied and,
A = Unit area.
Examples of Pressure is Air pressure.
If a single circular loop of wire carries a current of 63 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.
Answer:
The radius of the circular loop is 0.233 m
Explanation:
Given;
current on the circular loop, I = 63 A
magnitude of the magnetic field, B = 1.7 x 10⁻⁴ T
The magnetic field at the center of a circular loop is given by;
[tex]B = \frac{\mu I}{2R} \\\\[/tex]
Where;
R is the radius of the circular loop
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
Substitute the givens;
[tex]B = \frac{\mu I}{2R}\\\\R = \frac{\mu I}{2B}\\\\R = \frac{(4\pi*10^{-7})(63) }{2(1.7*10^{-4})}\\\\R = 0.233 \ m[/tex]
Therefore, the radius of the circular loop is 0.233 m
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The radius of the circular loop is 0.233 m.
What is a magnetic field?It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
As we know that current is directly propotional to the induced magnetic field greater the current I, the greater the magnetic field B.
The given data in the problem is;
I is the value of current = 63 A
B is the megnetic field = 1.70 10⁻⁴ T
r is the radius of loop=?
μ is the permeability of free space = 4π x 10⁻⁷ T.m/A
The value of the megnetic field at the center is given by;
[tex]\rm B= \frac{\mu I}{2r} \\\\ \rm r= \frac{\mu I}{2B} \\\\ \rm r= \frac{4\pi \times 63}{2\times 1.7\times 10^{-4}} \\\\ \ \rm r=0.233 m[/tex]
Hence the radius of the circular loop is 0.233 m.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
In the Bohr model of the atom, atomic electrons approximatately 'orbit' the nucleus. The hydrogen atom consists of a proton of mass 1.67 × 10-27 kg and an orbiting electron of mass 9.11 × 10-31 kg. In one of its orbits, the electron is 5.3 × 10-11 m from the proton. What is the mutual attractive gravitational force between the electron and proton
Answer:
[tex]F=3.61\times 10^{-47}\ N[/tex]
Explanation:
Mass of a proton, [tex]m_p=1.67\times 10^{-27}\ kg[/tex]
Mass of an electron, [tex]m_e=9.11\times 10^{-31}\ kg[/tex]
The distance between the electron and the proton is, [tex]r=5.3\times 10^{-11}\ m[/tex]
We need to find the mutual attractive gravitational force between the electron and proton. The gravitational force is given by :
[tex]F=G\dfrac{m_em_p}{r^2}[/tex]
Where G is the universal Gravitational constant
[tex]F=6.67\times 10^{-11}\times \dfrac{9.11\times 10^{-31}\times 1.67\times 10^{-27}}{(5.3\times 10^{-11})^2}\\\\F=3.61\times 10^{-47}\ N[/tex]
So, the force between the electron and proton is [tex]3.61\times 10^{-47}\ N[/tex].
Unscramble heenagwirt
Answer:
weathering
Explanation:
The difference in a brass rod and steel rod is same as 12cm at all temperature .Find the length of the rod at 0°C.(Alpha b =18×10^-6k^-1 and alpha s =12×10^-6k^-1)
Answer:
length of brass=24cm and length of steel rod=36cm
A stationary object is pushed with a force of 400N for 8s, resulting in its having a final velocity of 24m/s. What is its mass?
Answer:
The mass of the object is 133.33 kg
Explanation:
From Newton's second law of motion
F = ma
Where F is the force
m is the mass
and a is the acceleration
From the question,
A stationary object is pushed with a force of 400N, that is F = 400N. To determine the mass of the object,
First, we will determine the acceleration.
From one of the equations of kinematics for linear motion,
v = u + at
Where v is the final velocity
u is the initial velocity
a is the acceleration
and t is time
We can write that
v - u = at
Then, a = (v - u) / t
From the question,
t = 8s
v = 24m/s
u = 0 m/s (Since the object was stationary, that is, it was pushed from rest)
∴ a = (24m/s - 0m/s) / 8s
a = 24 / 8 = 3 m/s²
Therefore, acceleration is 3 m/s²
Now,
From F = ma
m = F / a
From the question
F = 400N
∴ m = 400N / 3m/s²
m = 133.33 kg
Hence, the mass of the object is 133.33 kg.
Doing specific exercises to improve a particular area of fitness is called flexibility? True or false
Answer:
True.
Explanation:
Exercises and yoga are important for the individual's health. The exercise makes the individual, fit, healthy and also reduces the chances of the deadly disease in human beings.
Different types of exercise can be performed by the individual. The aerobic exercises increase the amount of oxygen in the body. With the aerobic exercise, the exercise that can increase the strength, flexibility and total fitness must also be included.
If you are riding your bike west to your friend’s house, and you ride the 1.25 miles in 5 minutes, what is your velocity, in miles per hour?
Answer:
velocity = 15 miles / hourExplanation:
distance = 1.25 mile
time traveled = 5 min.
find velocity in miles / hour
solution:
use the formula: velocity = distance / time
velocity = 1.25 mile x 60 min
5 min 1 hour
velocity = 15 miles / hour
Can someone please help me I don’t understand this please show work plus I got it wrong it’s not C
How long had the Romans ruled those regions?
precisely which regions?
Answer:
Romans have ruled for 450 years
Explanation:
11. How can you determine if there is net force acting
on an
object?
Answer:
Explanation:
Sum all the forces that are acting on the object and what ever the sum is, is what the net force is.
For example if there is a piece of wood sitting on a table the net force would be the sum of the forces that are acting on it, so the force of gravity (which is negative) + the normal force which would equal zero because they are the same value.
5. What is final temperature of the object with a heat capacity of 300 cal and a sp. Heat of
0.5 cal/g°C? The mass of the object is 200 g and the initial temperature is 0 degrees
Celsius.
Answer:
3°C
Explanation:
Given parameters:
Heat capacity = 300cal
Specific heat capacity = 0.5cal/g°C
Mass of the object = 200g
Initial temperature = 0°C
Unknown:
Final temperature = ?
Solution:
The heat capacity is the amount of heat required to raise the temperature of a substance by 1°C;
Mathematically ;
H = m c x (t₂ - t₁)
H is the heat capacity
m is the mass
c is the specific heat capacity
t is the temperature
Insert the parameters and solve;
300 = 200 x 0.5 x (t₂- 0 )
100 t₂ = 300
t₂ = 3°C
A 4.5 kg block is pulled across a table by a horizontal force of 42 N. The frictional force
opposing the motion is 7.5 N. Calculate the acceleration of the object.
Answer:
7.67m/s²
Explanation:
The net force on the block is;
Net force = Force of pull - Frictional force
mass of block = 4.5kg
force of pull = 42N
Frictional force = 7.5N
Net force = 42 - 7.5
Force = mass x acceleration
ma = 34.5
4.5 x a = 34.5
a = [tex]\frac{34.5}{4.5}[/tex] = 7.67m/s²
PLEASE PROVIDE AN EXPLANATION
THANK YOU!
Answer:
(a) 0.993 s
(b) 14.0 N/m
(c) -3.02 m/s
(d) -6.01 m/s²
Explanation:
(a) The block's position can be modeled as a cosine wave:
x(t) = A cos(ωt)
where A is the amplitude (in this case, 50 cm) and ω is the angular frequency.
At t = 0.200 s, x(t) = 15.0 cm.
15.0 cm = 50.0 cm cos((0.200 s) ω)
0.3 = cos((0.2 s) ω)
1.266 rad = (0.2 s) ω
ω = 6.33 rad/s
The period is:
T = (2π rad) (1 s / 6.33 rad)
T = 0.993
(b) For a spring-mass system, ω = √(k/m). The mass of the block is 0.350 kg, so:
ω = √(k/m)
6.33 rad/s = √(k / 0.350 kg)
6.33 rad/s = √(k / 0.350 kg)
40.1 rad/s² = k / 0.350 kg
k = 14.0 N/m
(c) Energy is conserved:
EE₀ = EE + KE
½ kx₀² = ½ kx² + ½ mv²
kx₀² = kx² + mv²
(14.0 N/m) (0.50 m)² = (14.0 N/m) (0.15 m)² + (0.35 kg) v²
v = -3.02 m/s
Alternatively, we can take the derivative of our position equation:
v(t) = -Aω sin(ωt)
v = -(0.50 m) (6.33 rad/s) sin((6.33 rad/s) (0.2 s))
v = -3.02 m/s
(d) Sum of forces on the block:
∑F = ma
-kx = ma
a = -kx / m
a = -(14.0 N/m) (0.15 m) / (0.350 kg)
a = -6.01 m/s²
Alternatively, we can take the derivative of our velocity equation:
a(t) = -Aω² cos(ωt)
a = -(0.50 m) (6.33 rad/s)² cos((6.33 rad/s) (0.2 s))
a = -6.01 m/s²
Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
acceleration of Claudia's 1.80kg foot? B) What is the acceleration of the table if it has a mass
of 20.0kg? (ignore any frictional effects) C) Why would Claudia's toe hurt less if the table had
less mass?
Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more
What are alkaline earth metals used for?
A. solar cells
B. jewelry
C. fireworks
D. insulation
Answer:
C firework
Explanation:
from Quizlet
* WILL GIVE BRAINLIEST TO CORRECT ANSWER *
Name a product that people commonly purchase by mass and not by weight.
I would say food but like they take weight too
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.
Answer:
Q = 50.25 [J]
Explanation:
To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.
Q = m*Cp*(DT)
where:
Q = energy in form of heat [J]
m = mass = 5 [g] = 0.005 [kg]
Cp = specific heat = 1005 [J/kg*°C]
DT = temperature change = 10 [°C]
Now replacing:
Q = 0.005*1005*10
Q = 50.25 [J]
The power rating of a 400-ΩΩ resistor is 0.800 W.
Required:
a. What is the maximum voltage that can be applied across this resistor without damaging it?
b. What is the maximum current it can draw?
Answer:
voltage= 17.88volts
current= 0.04 amps
Explanation:
Step one:
given data
resistance R=400 ohms
Power P= 0.8W
a. What is the maximum voltage that can be applied across this resistor without damaging it?
the expression relating power and voltage is
P=V^2/R
substituting we have
0.8=V^2/400
V^2=0.8*400
V^2=320
V=√320
V=17.88 volts
the maximum voltage is 17.88volts
b.What is the maximum current it can draw?
we know that from Ohm' law
V=IR
17.88=I*400
I=17.88/400
I=0.04amps
Which diagram models the position of a soccer ball when it has the greatest amount of gravitational potential energy?
Answer:
C
Explanation:
Diagram C is the correct answer, because the ball is at the point with the highest height relative to the ground, in this way all the kinetic energy has been transformed into potential energy.
We must remember that potential energy is defined as the product of mass by gravity by height
Ep = m*g*h
where:
m = mass [kg]
g = gravity acceleration [m/s²]
h = elevation [m]
So when we have a great value for h in the above equation, we will have a big value for potential energy.
Two identical conducting spheres each have a charge of 2 C. They have a radius of 0.1 m and are separated by 0.5 meters. If you were to increase the radius of these spheres to 0.2 meters, the electrostatic force between them would
Answer:
The electrostatic force will remain the same
Explanation:
From the question we are told that
The charge on the each conducting sphere is [tex]q = 2 \ C[/tex]
The radius each sphere is [tex]r_1 = r_2 = r = 0. 1\ m[/tex]
Generally electrostatic force between the sphere is mathematically represented as
[tex]F = \frac{k * q_1 q_2 }{d^2}[/tex]
Here k is the coulomb constant ,
d is the distance between the two sphere which is measured from one center of the sphere to the other center of the sphere
Now from the question we are told that the radius of the spheres is doubled (i.e from 0.10 m to 0.2 m ) , this will not affect the distance between the sphere because their center are still in the same position
and given there is no change in the distance between the spheres , the electrostatic force will remain the same
Use Newton’s first law to explain why a book on a desk does not move
Answer:
nothing moves if anything other doesn't move it.
natural position of things is the resting
Explanation:
yeah that's it
Answer:
The book does not move because all the forces acting on the book are in equilibrium, creating a net force of zero magnitude on the book. Since the net force on the book is zero, this means that the book will remain in its present state of motion (which is that the book is motionless).
Explanation:
Newton's first law states that all body will remain in their present state of motion unless acted upon by an external force. In order word, a moving body should continue moving forever, and a body at rest should remain like that forever, unless they are acted upon by a force to either cause them to stop stop or to start moving respectively.
