no guess please explain

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

Answer:

A-using the associative property

Step-by-step explanation:

Answer:

The null hypothesis is that all the different teaching methods have the same average test scores.

H0: μ1 = μ2 = μ3 = μ4 = μ5

The alternative hypothesis is that at least one of the teaching methods have a different mean.

Ha: at least one mean is different. (μ1 ≠ μi)

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above, let μ represent the average test scores for the teaching methods:

The null hypothesis is that all the different teaching methods have the same average test scores.

H0: μ1 = μ2 = μ3 = μ4 = μ5

The alternative hypothesis is that at least one of the teaching methods have a different mean.

Ha: at least one mean is different. (μ1 ≠ μi)

Answer:

Among mildly obese people, 95% of the people have between 251 and 495 minutes of activity per day.

Among lean people, 95% of the people have between 317 and 733 minutes of activity per day.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Within what limits do the active minutes for 95% of the people in each group fall

By the Empirical Rule, within 2 standard deviations of the mean.

Mildly obese:

Mean = 373, standard deviation = 61.

373 - 2*61 = 251 minutes

373 + 2*61 = 495 minutes

Among mildly obese people, 95% of the people have between 251 and 495 minutes of activity per day.

Lean people:

Mean = 525, standard deviation = 104

525 - 2*104 = 317 minutes

525 + 2*104 = 733 minutes

Among lean people, 95% of the people have between 317 and 733 minutes of activity per day.

Answer:

Null hypothesis:[tex]\mu \leq 6[/tex]      

Alternative hypothesis:[tex]\mu > 6[/tex]      

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)      

Replacing the info we got:

[tex]t=\frac{6.178-6}{\frac{0.68}{\sqrt{26}}}=1.335[/tex]

[tex]p_v =P(t_{25}>1.335)=0.097[/tex]  

And for this case the p value is higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is at most 6 minutes

Step-by-step explanation:

Information given

[tex]\bar X=370.69/60 =6.178[/tex] represent the sample mean

[tex]s=24.36/36=0.68[/tex] represent the standard deviation for the sample    

[tex]n=26[/tex] sample size      

[tex]\mu_o =6[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

System of hypothesis

We want to test if the true mean is at least 6 minutes, the system of hypothesis would be:      

Null hypothesis:[tex]\mu \leq 6[/tex]      

Alternative hypothesis:[tex]\mu > 6[/tex]      

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)      

Replacing the info we got:

[tex]t=\frac{6.178-6}{\frac{0.68}{\sqrt{26}}}=1.335[/tex]      

The degrees of freedom are:

[tex]df=n-1=26-1=25[/tex]  

The p value would be given by:

[tex]p_v =P(t_{25}>1.335)=0.097[/tex]  

And for this case the p value is higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is at most 6 minutes.

Answer:

1:3

Step-by-step explanation:

divide 4 ...............

.............

ps: idk the explanation

Answer:

The answer is D.

Step-by-step explanation:

You have to apply Indices Law,

[tex] { ({a}^{m}) }^{n} \: ⇒ \: {a}^{mn} [/tex]

So for this question :

[tex] { ({6}^{7}) }^{3} [/tex]

[tex] = {6}^{7 \times 3} [/tex]

[tex] = {6}^{21} [/tex]

Answer:

  the sum of the prices divided by 7

Step-by-step explanation:

The mean is the sum of the elements of a set, divided by the number of elements in the set. This set has 7 members, so its mean is ...

  the sum of the prices divided by 7

Answer:

a = 13

b = 0

Step-by-step explanation:

Conjugate of -3 + 2i is -3 - 2i

(-3 + 2i) (-3 - 2i)

We need to expand:

9 + 6i + -6i + -4i^2

-4i^2 =(-4)(-1) = 4

9 + 4 = 13

a = 13

b = 0

Answer:

Which of these factors will affect the friction on a road

Step-by-step explanation:

Answer:

66

Step-by-step explanation:

Answer:

[tex] \bar x = 40, s =10[/tex]

And from these values we can estimate the sample variance like this:

[tex] s^2 = 10^2 =100[/tex]

And we can also estimate the coeffcient of variation given by:

[tex] \hat{CV} =\frac{s}{\bar x}[/tex]

And replacing we got:

[tex] \hat{CV} = \frac{10}{40}= 0.25[/tex]

And this coefficient is useful in order to see the variability in terms of the mean for this case since is lower than 1 we can conclude that this variation around the mean is low.

Step-by-step explanation:

For this case we have the following info given:

[tex] \bar x = 40, s =10[/tex]

And from these values we can estimate the sample variance like this:

[tex] s^2 = 10^2 =100[/tex]

And we can also estimate the coeffcient of variation given by:

[tex] \hat{CV} =\frac{s}{\bar x}[/tex]

And replacing we got:

[tex] \hat{CV} = \frac{10}{40}= 0.25[/tex]

And this coefficient is useful in order to see the variability in terms of the mean for this case since is lower than 1 we can conclude that this variation around the mean is low.

Answer:

Step-by-step explanation:Srry it's bit rough...

Answer:

Set the height up to 4

Step-by-step explanation:

Since there are 4 numbers between 1-5, set the height up to 4

Answer:

4 temperature recordings.

Step-by-step explanation:

2, 2, 4, 5

There are 4 recordings in the range of 1-5°C.

Answer:

4

Step-by-step explanation:

Set the height of the missing bar to 4 as there are 4 quantities between 21-25.

Complete Question:

Amit found and labeled the areas of each of the faces of the triangular prism as shown.

Which area calculation did Amit calculate incorrectly?

Rectangular face with area 30 cm2

Rectangular face with area 40 cm2

Rectangular face with area 50 cm2

Triangular faces with areas 48 cm2

Answer:

Triangular faces with areas 48 cm2

Step-by-step Explanation:

To find out which area calculation Amit got wrong, let's calculate each faces of the given triangular prism attached below:

There area of theb5 faces should be as follows:

Area  of rectangular face with L = 10 and B = 5 would be ==> 10*5= 50cm²

Area  of rectangular face with L = 8 and B = 5 would be 8*5 = 40cm²

Area  of rectangular face with L = 6 and B = 5 would 6*5 = 30cm²

Area  of each of the triangular faces will be ½*8*6 = 48/2 = 24cm²

From our calculations, we'd observe that Amit didn't calculate the area of the triangular faces correctly. Amit got 48cm² instead of 24cm²

Answer:

Triangular faces with areas 48 cm2

Step-by-step explanation:

Answer:  The answer is C 90

Step-by-step explanation: Rotations is ¼ and the Radians is π/2

Answer:

Step-by-step explanation:

a) The %tax comes from the "Rate" column on the line "up to $9525". It is 10%.

__

b) Simply compute the difference shown:

  $38,700 -$9,525 = $29,175

__

c) 22% of $9,300 is ...

  0.22 × $9,300 = $2,046

__

d) The total from the three previous calculations is ...

  $952.50 +3,501.00 +2,046.00 = $6,499.50

Answer:

10%

$29,175

$2,046

$6,499.50

got it right on ttm.  

Step-by-step explanation:

just believe me it works

Answer:

(3/2,-3/2)

Step-by-step explanation:

The midpoint of (2,-1)(1,-2) is (3/2,-3/2)

Answer:

(1.5,-1.5)

You have to remember the formula to find mid-point and that is:

[tex]midpoint = ( \frac{x1 + x2}{2} ,\frac{y1 + y2}{2} )[/tex]

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

Answer:

1/3 left

Step-by-step explanation:

The total sandwich is 1 or in fraction form 6/6

He ate 2/6

6/6 -2/6 = 4/6

Then he ate 2/6 more

4/6 -2/6 = 2/6

He has 2/6 left

Simplifying

2/6 =1/3

Answer:

144

Step-by-step explanation:

Answer:

116

Step-by-step explanation:

3x4=12

12x4=48

8x4=32

32-3=29

29x4=116

Hope it's clear

Answer:

I think it is 288.6 ft. Lol hope this helps

Step-by-step explanation:

Answer:

7/9

Step-by-step explanation:

7/15 ÷ 3/5

Copy dot flip

7/15 * 5/3

7/3 * 5/15

7/3 * 1/3

7/9

Answer:

d. 10th  e. 26th

Step-by-step explanation:

22-12=10

12+14=26

Answer:

96

Step-by-step explanation:

60% * 160 = 0.6 * 160 = 96.

Answer:

None

Step-by-step explanation:

There is no Forest Green iPhone XR's only the 11 Pros have that color.

Answer:

Answere is X= 8

Step-by-step explanation:

Use sine law

Sin(angle) = Opposite/ Hypotenuse

Sin (30) = 4 /X

X = 4 / sin (30)

X = 8

Answer:

B

Step-by-step explanation:

They are increasing by 1 vertically. Hope this helps!! :)

Answer:

91.92% of pregnancies last beyond 246 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 267, \sigma = 15[/tex]

What percentage of pregnancies last beyond 246 days?

We have to find 1 subtracted by the pvalue of Z when X = 246. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{246 - 267}{15}[/tex]

[tex]Z = -1.4[/tex]

[tex]Z = -1.4[/tex] has a pvalue of 0.0808

1 - 0.0808 = 0.9192

91.92% of pregnancies last beyond 246 days

Answer:

The probability that if Sunday is sunny, then Tuesday is also sunny is 0.86.

Step-by-step explanation:

Let us denote the events as follows:

Event 1: a sunny day

Event 2: a rainy day

From the provided data we know that the transition probability matrix is:

                 [tex]\left\begin{array}{ccc}1&\ \ \ \ 2\end{array}\right[/tex]

[tex]\text{P}=\left\begin{array}{c}1&2\end{array}\right[/tex]  [tex]\left[\begin{array}{cc}0.90&0.10\\0.50&0.50\end{array}\right][/tex]

In this case we need to compute that if Sunday is sunny, what is the probability that Tuesday is also sunny.

This implies that we need to compute the value of P₁₁².

Compute the value of P² as follows:

[tex]P^{2}=P\cdot P[/tex]

     [tex]=\left[\begin{array}{cc}0.90&0.10\\0.50&0.50\end{array}\right]\cdot \left[\begin{array}{cc}0.90&0.10\\0.50&0.50\end{array}\right]\\\\=\left[\begin{array}{cc}0.86&0.14\\0.70&0.30\end{array}\right][/tex]

The value of P₁₁² is 0.86.

Thus, the probability that if Sunday is sunny, then Tuesday is also sunny is 0.86.

Answer:

Step-by-step explanation:

Let X denote the life span of a car battery and it follows and exponential distribution with average of 6 years.

Thus , the parameter of the exponential distribution is calculated as,

μ = 6

[tex]\frac{1}{\lambda} =6[/tex]

[tex]\lambda = \frac{1}{6}[/tex]

a) The required probability is

[tex]P(X>4)=1-P(X\leq 4)\\\\=1-F(4)\\\\1-(1-e^{- \lambda x})\\\\=e^{-\frac{4}{6}[/tex]

= 0.513

Hence, the probability that a randomly selected car battery will last more than four years is 0.513

b) The variance of the battery span is calculated as

[tex]\sigma ^2=\frac{1}{(\frac{1}{\lambda})^2 }\\\\\sigma ^2=\frac{1}{(\frac{1}{6})^2 } \\\\=6^2=36[/tex]

The 95% percentile [tex]x_{a=0.05}[/tex] (α = 5%) of the battery span is calculated

[tex]x_{0.05}=-\frac{log(\alpha) }{\lambda} \\\\=-\frac{log(0.05)}{1/6} \\\\=-6log(0.05)\\\\=17.97 \ years[/tex]

c)  

Let [tex]X_r[/tex] denote the remaining life time of a car battery

i)the probability the battery will last an additional five years is calculated below

[tex]P(X_r>5)=e^{-5\lambda}\\\\=e^{-\frac{5}{6} }\\\\=0.4346[/tex]

ii) The average time that the battery is expected to last is calculated

[tex]E(X_r)=\frac{1}{\lambda} \\\\=6[/tex]

Answer:

work is shown and pictured