Nitrogen monoxide (NO) is a pollutant known to
destroy the ozone layer. Nitrogen monoxide reacts
with ozone molecules (0,) to release oxygen and
a nitrogen-containing compound Q. Given that one
molecule of nitrogen monoxide reacts with one
molecule of ozone to produce one molecule of
of Q.
oxygen and one molecule of Q, identify the formula.

Based on the calculations, the number of moles of fluorine atoms present is equal to 12.4 moles.

In order to determine the number of moles of fluorine atoms, we would calculate the number of atoms in 1 mole of an fluorine atoms in accordance with Avogadro's constant.

1 mole of fluorine atom = 6.02 × 10²³ molecules

X moles of fluorine atom = 7.45 × 10²⁴ molecules

Cross-multiplying, we have:

X = 7.45 × 10²⁴/6.02 × 10²³

X = 12.4 moles.

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Answer:

Explanation:

They cannot be separated by distillation since it depends on a liquid's ability to boil at a certain temperature. If you have two liquids with the same boiling temperatures, the proportion of each in the vapor phase will be about equal, making it impossible to separate them. Although they presumably do not have the same freezing point, you might use a different method like chromatography or work with their freezing points instead. You could then selectively crystallize one component while leaving the other as a pure liquid.

____________

Definitions:

Distillation:

#1: The volatilization or evaporation and subsequent condensation of a liquid, as when water is boiled in a retort and then the steam is condensed in a cool receiver.

Answer:

Because different compounds often have different boiling points, the components often separate from a mixture when the mixture is distilled. The boiling point is the temperature at which the vapor pressure of the liquid phase of a compound equals the external pressure acting on the surface of the liquid.

Explanation:

Answer:

So, in 1 mol there are 6.02x10^23 atoms, regardless of the susbtance, only the weight of the mol changes. Doing a simple rule of 3 we can get many of the answers to your questions.

Explanation:

1mol of Ar → 6.02x10^23 atoms

0.25 mol → X

So now what we do is (0.25mol * 6.02x10^23 atoms)/1 mol = X

That gives us 1.505x10^23 atoms in 0.25 mol of Ar.

For this I'm guessing you mean the stable form of oxygen, O2. The Avogadro constant stays well, constant.

1 mol of O2 → 6.02x10^23 molecules

1.0×10^-4 mol of O2 → X molecules

So you can do (1.0×10^-4 * 6.02x10^23) / 1mol = X

(I feel like this is homework, so i will help you, but not give you all the answer, will be good practice to try yourself) :)

For this you need to know the weight of a mol of Be. Luckily the periodic table gives us that number. The number under each element is the weight in grams of 1 mol .

Answer:

C- 2.48925 H- 3.9901 O- 1

Explanation:

Read the instructions

Answer:

Just Barely Base/Neutral

Explanation:

a pH of 8.0 is greater than Neutral (7.0) but is still neutral due to it being more neutral than a base

the equation of the parabola is given as [tex]y = 1/4 (x-6)^2 +1[/tex]. D

Given the focus(6,2) and the directrix, y = 0

Use the formula

[tex]\sqrt{(x-6)^{2} + (y-2)^{2} } }[/tex] = (y - 0)

Find the square of both sides, square root is removed from the side with it and square added on the other side

[tex](x-6)^2 + (y-2)^2 = (y- 0)^{2}[/tex]

Expand the expression and bring all terms to one side

[tex]x^{2} - 6x - 6x + 36 +y^{2} -2y- 2y +4[/tex] = [tex]y^{2} - 0[/tex]

Collect like terms

[tex]x^{2} - 12x -4y + 40 = 0[/tex]

Make 'y' the subject of the formula

[tex]4y = x^{2} - 12x + 40[/tex]

Divide through by 4 and substrate 4 from 40 to give a perfect quadratic equation

[tex]y = 1/4( x^{2} - 12x + 36) + 4[/tex]

1/4 is dividing the quadratic equation [tex]x^2 - 12x +36[/tex]

Then divide factor by 4 to give 1, this is so because of the nature of the options given

[tex]y = 1/4( x^{2} -6x -6x +36) + 1[/tex]

Simplify the expanded quadratic equation

[tex]y = x (x -6) - 6 (x- 6)[/tex], we have [tex](x - 6) ^2[/tex]

Then insert in place into previous equation

[tex]y = 1/4 (x-6)^2 + 1[/tex]

Thus, the equation of the parabola is given as [tex]y = 1/4 (x-6)^2 +1[/tex]

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Answer:

The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.

Explanation:

i know

Answer:

D) The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.

Explanation:

I took the test and got it right.

Answer:

For sp3 hybridized central atoms the only possible molecular geometry is tetrahedral.

The correct answer to this question is option A.

Taking into account the definition of Avogadro's number and molar mass, 3.49334×10²² molecules of sucrose are present.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

In first place, the molar mass of sucrose is 342 g/mole. So, you can apply the following rule of three: If by definition of molar mass 342 grams of the compound are contained in 1 mole, 20 grams of the compound are contained in how many moles?

[tex]amount of moles=\frac{20 gramsx1 mole}{342 grams}[/tex]

amount of moles= 0.058 moles

Now, considering the Avogadro's number, you can apply the following rule of three: If 1 mole of the compound contains 6.023×10²³ molecules, 0.058 moles contains how many molecules?

amount of moleculas= (6.023×10²³ molecules × 0.058 moles)÷ 1 mole

amount of molecules= 3.49334×10²² molecules

Finally, 3.49334×10²² molecules of sucrose are present.

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Answer:

Explanation:

Hi there!

N₂+3H₂⇋2NH₃

The molecular mass of NH₃ is 34

The mass of N₂ is 28 and mass of H₂ is 2.

Then,

2 moles of NH₃ is created by 28 g of N₂

1 moles of NH₃ is created by 28/2 g of N₂  

9.3g  of NH₃ is created by (28/2)*9.3 moles of N₂

Therefore, 130.2 g of N₂ is required to create 9.3 moles of NH₃.

Hope it helps!

N₂+3H₂⇔2NH₃

moles N₂ = 1/2 x 9.3 = 4.65

mass N₂ = 4.65  x 28 g/mol = 130.2 g

Answer:

they help becuz they dont use any extra power and the are reneable

Before the occurance of Fossil fuel, our energy needs were modest. For heat, we relied on the sun—and burned wood, straw, and dried dung For transportation, the muscle of horses and the power of the wind in our sails took us to every corner of the world.

Fossil fuels are made from decomposing plants and animals.

These fuels are found in the Earth's crust and contain carbon and hydrogen, which can be burned for energy.

Coal, oil, and natural gas are examples of fossil fuels.

Hence, Before the occurance of Fossil fuel, our energy needs were modest. For heat, we relied on the sun—and burned wood, straw, and dried dung For transportation, the muscle of horses and the power of the wind in our sails took us to every corner of the world.

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Answer:

B is the answer.

Explanation:

sry if wrong :D

The statement that is correct about the emission spectrum of hydrogen in the visible region is that the line corresponding to the greatest emission of energy is in the ultraviolet region.

Hydrogen spectrum is defined as the dissociation of hydrogen atom upon action of electric current into spectral lines that can be seen in that visible light.

These lines falls under the electromagnetic wave of ultraviolet and infrared regions. But the lines of greatest emission is found in the ultraviolet region.

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Answer:

n

Explanation:

nobody knows

Answer: O

Explanation:

Out of the given elements, oxygen has the highest electronegativity.

Answer:

B it is decomposition reaction

Explanation:

In decomposition reaction compound is broken into two or other elements

The bond length of a chemical bond between bromine and sulfur is 216 picometers.

Given,

Covalent radius of bromine is 114 pm;

and  covalent radius of sulfur is102 pm.

∴  Bond length of the sulfur dibromide= Covalent radius of bromine +  covalent radius of sulfur

∴  Bond length = 114 + 102

∴  Bond length = 216 pm.

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266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.

The mass of a product or reactant can be calculated using stoichiometry as follows:

According to this question, iron oxide reacts with carbon monoxide as follows:

Fe₂O3 + 3CO → 2Fe + 3CO₂

1 mole of Fe2O3 produces 2 moles of Fe

Moles of Fe = 187/56 = 3.34mol

3.34/2 = 1.67 moles of Fe2O3 will be required to produce 3.34 moles of Fe.

mass of Fe2O3 = 1.67 mol × 159.69 g/mol = 266.63g

Therefore, 266.63g of Fe2O3 would be required to make 187 g Fe in accordance with the following equation: Fe₂O3 + 3CO → 2Fe + 3CO₂.

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Answer:

1d and 2d is the answer. Hope it helps

Answer:

CU

Explanation:

Cu is the correct answer if I'm correct

Answer:

measure their densities

Theoretical yield =0.15 g

% yield = 15%

reaction

C6H12O6 → 2C2H5OH + 2CO2

from above reaction, we get to know that,

1 mole of glucose → 2 mole ethanol

for 4 mole of glucose → 8 mole of ethanol

\frac{55.2}{8(46)} = yield of ethanol

yield of ethanol = 0.15g

% yield = (experimental/theoretical )*100

% yield of ethanol = 0.15 x 100 =15%

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The optimum pH of formic acid - formate buffer is 3.75

A substance or a solution which resists any changes in pH, when acid or alkali is added to it.

pH = pKa + log[base] / [acid]

Considering equimolar concentration of acid and base

pH = 3.75 + log(x)/(x)

pH = 3.75 + log (1)

pH = 3.75 + 0

pH = 3.75

Hence,

The optimum pH of formic acid - formate buffer is 3.75

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The formula of hydrated copper(II) sulfate is CuSO4.10H2O

The formula of the hydrated copper (ii) sulfate is determined as follows:

Mass of hydrated salt = 12.5 g

Mass of anhydrous salt = 8.0 g

Mass of water = 12.5 - 8 = 4.5 g

mole ratio of water and anhydrous salt is;

4.5/18 : 8.0/159.5

0.562 : 0.05

10 : 1

Water of crystallization (n) = 10.

Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O

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A spring tide occurs when there is a new or full moon in the solar system.

This is the type of tide which occurs when the sun, moon and earth are in line and occurs between three to four times per year.

Lunar and solar tides also line up and reinforce each other to produce this type of tide.

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The students can determine the rate of reaction by measuring change in concentration of reactant or product with time.

The rate of a reaction is the rate at which reactant molecules are used up or the rate at which product molecules are formed.

The rate of a reaction can be determined by measuring the change in concentration of the reactant at each given time in a reaction.

The rate of reaction can be also be determined by measuring the change in concentration of the product at each given time in a reaction.

Therefore, the students can determine the rate of reaction by measuring change in concentration of reactant or product with time.

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The energy of the snack in calories per gram is 9983.3 Calories/gram.

The energy that is contained in a snack is obtained from a calorimeter when the snack is burnt in a calorimeter. The mass of the snack that is burnt is measured in terms of energy output of the calorimeter.

If  1 calorie = 4.18J

x calorie = 41,800 J

x = 41,800 J * 1 calorie/4.18J

x = 9983.3 Calories/gram

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Answer:

The production process often produces offensive odours and may also create by-products that can contaminate air and ground water. Many industrial separation processes have requirements and consequences that influence where they are located.

Explanation:

hope it's helpful to you

Answer:

A. CO2 and CH4

The two major greenhouse gases are CO₂ and CH₄ and the correct option is option A.

Greenhouse gases are gases in Earth’s atmosphere that trap heat. They let sunlight pass through the atmosphere, but they prevent the heat that the sunlight brings from leaving the atmosphere.

These gases have the property of absorbing infrared radiation (net heat energy) emitted from Earth’s surface and reradiating it back to Earth’s surface, thus contributing to the greenhouse effect.

Each of these gases can remain in the atmosphere for different amounts of time, ranging from a few years to thousands of years.

Examples of greenhouse gases are carbon dioxide, methane and water vapour.

Therefore, the two major greenhouse gases are CO₂ and CH₄ and the correct option is option A.

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