Answers
The values of x and y at t=3 are -4.95 and 0.423 respectively.
The value of dx/dt and dy/dt are 0.71 and -2.97 respectively.
The value of the tangent slope at t=3 is 4.21.
The speed at t=3 is 3.05 units/sec.
Given the equation of x as the function of t is
x= 5 cos t
similarly, the equation of y as the function of t is
y= 3 sin t
At t=3 the value of x will be
x (at t=3) = 5 cos 3= 5(-0.989)= -4.95
At t=3 the value of y will be
y (at t=3) = 3 sin 3= 3(0.141)= 0.423
The derivative of the function of x with respect to t will be
dx/dt= d(5 cos t)/dt= 5d(cos t)/dt= -5 sin t
at t=3 the value of dx/dt will be
dx/dt (at t=3) = -5 sin 3= -5(0.141)= 0.71
The derivative of the function of y with respect to t will be
dy/dt= d(3 sin t)/dt= 3d(sin t)/dt= 3 cos t
at t=3 the value of dy/dt will be
dy/dt (at t=3) = 3 cos t= 3(-0.989)= -2.97
The tangent slope is dy/dx which can be calculated by
dy/dx= (dy/dt)(dt/dx)= (dy/dt)/(dx/dt)= 3 cos t/ -5 sin t= (-3/5) cot t
at t=3 the value of tangent slope will be
dy/dx (at t=3) = (-3/5) cot 3= 4.21
The speed at t=3 will be
speed v= [tex]\sqrt{v_{x} ^{2} + v_{y} ^{2} }[/tex]
= √(dx/dt)²+(dy/dt)²
at t=3
= √(0.71)²+(-2.97)²
= √9.325
= 3.05 unit/sec
Therefore the values of x and y at t=3 are -4.95 and 0.423 respectively.
The value of dx/dt and dy/dt are 0.71 and -2.97 respectively.
The value of the tangent slope at t=3 is 4.21.
The speed at t=3 is 3.05 units/sec.
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Related Questions
Need help with number 2 please!!!
Answers
Answer:
Function g(x) is function f(x) vertically stretched by a factor of 6, reflected in the x-axis, and translated 2 units up.
Step-by-step explanation:
The graph of function f(x) is the parent function.
(Parent functions are the simplest form of a given family of functions).
The graph of g(x) is related to the graph of f(x) by a series of transformations. To determine the series of transformations, work out the steps of how to go from f(x) to g(x).
Transformations
For a > 0
[tex]\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of }\:a \\& \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\& \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a \end{aligned}[/tex]
[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]
[tex]y=f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]
Parent function:
[tex]f(x)=x^3[/tex]
Step 1
Multiply the parent function by 6:
[tex]\implies 6f(x)=6x^3[/tex]
Therefore, this is a vertical stretch by a factor of 6.
Step 2
Now make the function negative:
[tex]\implies -6f(x)=-6x^3[/tex]
Therefore, this is a reflection in the x-axis.
Step 3
Finally, add 2 to the function:
[tex]\implies -6f(x)+2=-6x^3+2[/tex]
Therefore, the function has been translated 2 units up.
Conclusion
Function g(x) is function f(x) vertically stretched by a factor of 6, reflected in the x-axis, and translated 2 units up.
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(1 point)Let S be the part of the plane 2x+2y+z= 1 which lies in the first octant, oriented upward. Find the flux of the vector field
F = 2i+2j + 2k across the surface S.
Answers
The flux is 9.
What is Flux?Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface.
Given:
2x+2y+z= 1
F = 2i+2j + 2k
Now,
r = xi + yj + z( 1-2x-2y) K
dr/dx= i - 2k
dr/dy = j-2k
dr/dx* dr/dy
= ( i - 2k) * (j-2k)
= 2i + 2j + k
F(x)= 2i+2j + 2k
F(x). da = 4 +4 +2 = 10 dxdy
Hence, flux
= [tex]\int\limits^1_0 {\int\limits^{1-2y}_0 {10 } \, dx dy } \,[/tex]
= [tex]\int\limits^1_0[/tex] 10(1-2y) dx
= [tex]\int\limits^1_0[/tex] 10-2y
= 10(1) - (1)²
=9
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The plane has intercepts (1/2, 0, 0), (0, 1/2, 0), and (0, 0, 1). Parameterize [tex]S[/tex] by the vector function
[tex]\vec s(u,v) = \dfrac{(1-u)(1-v)}2 \, \vec\imath + \dfrac{u(1-v)}2 \, \vec\jmath + v \,\vec k[/tex]
with [tex]0\le u\le1[/tex] and [tex]0\le v\le1[/tex]. (More explicitly, we have the parameterization
[tex]\vec s(u,v) = (1-v)((1-u) p_1 + u p_2) + v p_3[/tex]
where [tex]p_i[/tex] denote the given points.)
The normal vector to [tex]S[/tex] is
[tex]\vec n = \dfrac{\partial\vec s}{\partial u} \times \dfrac{\partial\vec s}{\partial v} = \dfrac{1-v}2\,\vec\imath + \dfrac{1-v}2\,\vec\jmath + \dfrac{1-v}4\,\vec k[/tex]
Then the flux of [tex]\vec F = 2\,\vec\imath+2\,\vec\jmath+2\,\vec k[/tex] across [tex]S[/tex] is given by the surface integral,
[tex]\displaystyle \iint_S \vec F \cdot d\vec\sigma = \iint_S \vec F \cdot \vec n \, dA[/tex]
[tex]\displaystyle = \int_0^1 \int_0^1 \left(2\,\vec\imath+2\,\vec\jmath+2\,\vec k) \cdot \left(\frac{1-v}2\,\vec\imath + \frac{1-v}2\,\vec\jmath + \frac{1-v}4\,\vec k\right) \, du \, dv[/tex]
[tex]\displaystyle = \frac52 \int_0^1 \int_0^1 (1-v) \, du \, dv[/tex]
[tex]\displaystyle = \frac52 \int_0^1 (1-v) \, dv = \boxed{\frac54}[/tex]
Which graph represents the function f(x)=−3x−2?
Answers
Answer:
Step-by-step explanation:
consider the parabola given by the equation:
f(x)=2x^2+12-9
find the following for this parabola:
a) the vertex
b) the vertical intercept is the point
c) find the coordinates of the two x-intercept of the parabola and write them as a list, separated by commas
Answers
Answer:
First simply it as 2x²+3
(a) vertex (0,3)
(b)f(0)=3
(c) no x-intercept
y 2 +2y+1 Identify a= b= c= Factor m= Factor n= Factored Form :
Answers
Answer:
a = 1
b = 2
c = 1
Factored form: (y + 1)^2 or (y + 1)(y + 1)
Step-by-step explanation:
h(x)=x²-5
Find h(-7)
Simplify your answer.
Answers
Answer:
h(-7) = 44
Step-by-step explanation:
h(x) = h (-7) means x= -7
h(x) = (-7)² - 5
49 - 5
44
Find the midpoint of the line segment whose endpoints are given. (9,3), (10,- 10)
Answers
Answer:
Step-by-step explanation:
(xm , ym ) = x1 + x2 / 2 and y1 + y2 / 2
= 9 +3 / 2 = 10 -10 / 2
= 12/2 = 0/2
= 6 = 0
So midpoints are (6 , 0)
Answer:
midpoint = [tex](9\frac{1}{2} , -3\frac{1}{2} )[/tex]
Step-by-step explanation:
To find the midpoint of a line segment, you have to find the average of the x and y-values of the end-points, i.e., add the x-coordinate values and divide the answer by 2, and do the same for the y-coordinate values.
• midpoint = [tex](\frac{x_{2} + x_1}{2}, \frac{y_2 + y_1}{2} )[/tex]
= [tex](\frac{9 + 10}{2}, \frac{3 + (-10)}{2} )[/tex]
= [tex](\frac{19}{2}, \frac{-7}{2} )[/tex]
= [tex](9\frac{1}{2} , -3\frac{1}{2} )[/tex]
graph x=4y , x+y=7.0
Answers
Answer:
First find the x and y intercepts. Recall that intercepts intersect the x and y axis of a graph, therefore either the x or y value of a coordinate point must be 0 in order for it to be an intercept.
After you find the intercept, plot the them on the cartesian coordinate system and draw a straight line (it’s a linear equation) going through the two intercepts.
Side note: Not sure how credentials work on Quora yet. I meant to say I am a student
The equation of the lines can be plotted on the graph after calculating the coordinates on each line.
What is a linear equation?It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have two linear equation:
x = 4y
x + y = 7.0
To plot the linear equation first we will find the few coordinates to plot on the coordinate plane.
For the equation of line:
x = 4y
x 0 1 2 3 -1 -2 -3
y 0 4 8 12 -4 -8 -12
For the equation of line:
x + y = 7.0
x 0 1 2 3 -1 -2 -3
y 7 6 5 4 8 9 10
Thus, the equation of the lines can be plotted on the graph after calculating the coordinates on each line.
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Two buses leave a station at the same time and travel in opposite directions. One bus travels12m/hrslower than the other. If the two buses are 765 miles apart after 6 hours, what is the rate of each bus?
Answers
distance = speed * time
the first bus speed = x
second bus = x - 12
the sum of distance = 765 miles
first distance = 6x
second distance = 6 (x -12)
6x + 6(x-12) = 765
x + x -12 = 127.5
2x = 139.5
x = 69.75 mi/h which is the faster bus
the second bus speed = 57.75 mi/h
julie ran a race 2 minutes faster than teri did. if teri ran the race in 28 minutes, what equation would be used to find the number of minutes teri took to run the race
Answers
Th equation that can be used to find the umber of minutes Teri ran is m + 2 = 28 minutes.
How many minutes did it take Teri to run the race?Addition is a mathematical operation that is used to determine the sum of two or more numbers.
The total minutes run by Julie = minutes ran by Teri + 2
28 = m + 2
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Using the diagram, if angle 3 + angle 4 is a straight line then what is the total
measure?
Answers
Answer: 180 degrees
Step-by-step explanation:
Angles on a line add to 180 degrees since they form a straight angle.
Match each fraction to a reasonable estimate.
(-6/11)
(-7/9)
(-3/13)
(-1/4)
(-3/4)
(-1/2)
Which one goes with each?
Answers
Answer:
-6/11 goes with -1/2
-7/9 goes with -3/4
-3/13 goes with -1/4
Step-by-step explanation:
6/11 is close to 6/12 which is the same as 1/2, so -6/11 goes with -1/2
7/9 is close to 6.75/9 which is 3/4, so -7/9 is close to -3/4
3/13 is close to 3/12 which is the same as 1/4, so -3/13 goes with -1/4
How many solutions exist for the given equation?
3(x - 2) = 22 -x
Answers
3x - 6 = 22 - x
3x + x = 22 + 6
4x = 28
X = 7
Answer:
One solution
Step-by-step explanation:
The equation can be rewrite as 3x - 6 = 22 - x
so we try to get all the x on one side so we add x and 6 to both sides so we get 4x = 28 then we divide by 4 both side and get x=7
Mountain Climbing Gym has a gym registration fee of $30 and then charges $55 per month for all access climbing.
Susie wanted to model what she has spent in total on the climbing gym at any given month in the future.
Fill in the blanks for the equation if C = total Cost and m = number of months.
Answers
Answer:
C=55m + 30
Step-by-step explanation:
You would multiply 55 by the number of months so you'd get 55m, and since 30 is a one time fee you would just add 30 to your monthly payment.
The function G is defined by g (X) =X^2+2
Find g(4n)
Answers
Answer:
the answer is 4gn Puig IT in
See photo for questions.
Answers
Answer:
1. "a" [tex]u'=6x[/tex]
2. "d" [tex]v'=15x^2[/tex]
3. "b" [tex]y'=75x^4+30x^2+6x[/tex]
Step-by-step explanation:
General outline:For parts 1 & 2, apply power ruleFor part 3, apply product rulePart 1.
Given [tex]u=3x^2+2[/tex], find [tex]\frac{du}{dx} \text{ or } u'[/tex].
[tex]u=3x^2+2[/tex]
Apply a derivative to both sides...
[tex]u'=(3x^2+2)'[/tex]
Derivatives of a sum are the sum of derivatives...
[tex]u'=(3x^2)'+(2)'[/tex]
Scalars factor out of derivatives...
[tex]u'=3(x^2)'+(2)'[/tex]
Apply power rule for derivatives (decrease power by 1; mutliply old power as a factor to the coefficient); Derivative of a constant is zero...
[tex]u'=3(2x)+0[/tex]
Simplify...
[tex]u'=6x[/tex]
So, option "a"
Part 2.
Given [tex]v=5x^3+1[/tex], find [tex]\frac{dv}{dx} \text{ or } v'[/tex].
[tex]v=5x^3+1[/tex]
Apply a derivative to both sides...
[tex]v'=(5x^3+1)'[/tex]
Derivatives of a sum are the sum of derivatives...
[tex]v'=(5x^3)'+(1)'[/tex]
Scalars factor out of derivatives...
[tex]v'=5(x^3)'+(1)'[/tex]
Apply power rule for derivatives (decrease power by 1; mutliply old power as a factor to the coefficient); Derivative of a constant is zero...
[tex]v'=5(3x^2)+0[/tex]
Simplify...
[tex]v'=15x^2[/tex]
So, option "d"
Part 3.
Given [tex]y=(3x^2+2)(5x^3+1)[/tex]
[tex]\text{Then if } u=3x^2+2 \text{ and } v=5x^3+1, y=u*v[/tex]
To find [tex]\frac{dy}{dx} \text{ or } y'[/tex], recall the product rule: [tex]y'=uv'+u'v[/tex]
[tex]y'=uv'+u'v[/tex]
Substituting the expressions found from above...
[tex]y'=(3x^2+2)(15x^2)+(6x)(5x^3+1)[/tex]
Apply the distributive property...
[tex]y'=(45x^4+30x^2)+(30x^4+6x)[/tex]
Use the associative and commutative property of addition to combine like terms, and rewrite in descending order:
[tex]y'=75x^4+30x^2+6x[/tex]
So, option "b"
Solve for x in the inequality |2x + 5| ≤ 11. (If this is an "and" inequality, give your answer as a single compound inequality. If this is an "or" inequality, separate your answers using a comma.) Solve for x in the inequality | 2x + 5 | ≤ 11. ( If this is an " and " inequality , give your answer as a single compound inequality . If this is an " or " inequality , separate your answers using a comma . )
Answers
|2x + 5| ≤ 11
x = 3
2(3) + 5
6 + 5
11 ≤ 11
The solution for the x in the inequality |2x + 5| ≤ 11 is {-8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3}
What is inequality?Inequality shows relation between two expression which are not equal to each others.
The given inequality is,
|2x + 5| ≤ 11
To find the solution for the x, solve the inequality,
|2x + 5| ≤ 11
-11 ≤ 2x + 5 ≤ 11
Subtract 5 from whole the expression,
-11 - 5 ≤ 2x + 5 - 5 ≤ 11 - 5
-16 ≤ 2x ≤ 6
-8 ≤ x ≤ 3
The value of x for the given inequality varies from -8 to 3.
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Given (x – 7)2 = 36, select the values of x.
Answers
Answer:
x = 25
Step-by-step explanation:
Solve by isolating x:
(x-7)2 = 36
x-7 = 18
x = 25
Which of the following best describes the slope of the line below?
A. Negative
B. Undefined
C. Positive
D. Zero
PLEASE HELP
Answers
Answer:
A. negative
Step-by-step explanation:
It is clear from the accompanying graph that the value of y decreases as the value of x grows. The line has a negative slope, and the right answer is C, as shown by the inverse connection between the values of x and y.
Reasoning for other incorrect options:
The slope is positive if the connection between x and y is positive (y rises as x rises, and vice versa). As a result, choice A is incorrect.It is an undefined slope if the value of y varies without the value of x changing. A horizontal line is used to symbolize it. Option B is thus untrue.The slope of a line is zero and is determined by a vertical line if the value of x varies but the value of y stays the same. So, the option D is incorrect.If slope is denoted by m, then the line with various slopes is depicted in the picture below.Steve bought a new car for $22,000 but paid 93% of the list price. How much was the list price
Answers
Answer:
approximately $23,655.91 (rounded to the nearest hundredths place)
Step-by-step explanation:
[tex]22,000=0.93x\\x=23,655.91[/tex]
Answer:
Step-by-step explanation:
let the list price=x
93% of x=22,000
x=22,000 ×100/93
≈23,655.91 $
what is the domain of the ordered pair shown in the graph?
Answers
Answer:
D.
Step-by-step explanation:
It is the only one that contains all the x-values of the points. (Domain is the set of x-values).
A sample of size 400 was drawn and sample mean was found t
be 99. Test whether this sample could have come from a normal
population with mean 100 and variance 64 at 5%
significance.
Answers
Answer:
etrf4f3dvef3rf3rfr2wrgwrf2rg3rf3rgerferferfef I'm
round 0.3391 to the nearest thousandth
Answers
Answer:
0.339
Step-by-step explanation:
Hope it helped!
Hii!
___________________________________________________________
Answer: 0.339
Explanation:
Rounding Rules
There are two rounding rules that will help us whenever we need to round a number! These are the rules.
If the number that you need to round is followed by a digit that is less than 5, you round down.If the number that you need to round is followed by a digit that is either greater than or equal to 5, you round up.---
Now that we know the rules, let's get down to solving our problem! ^^
The nearest thousandth is 3 decimal places.
_._ _ _ <==== Nearest thousandth
The third number after the decimal point is 9. After it is a digit that is less than 5. According to the rounding rules, we should round down.
[tex]\boldsymbol{0.3391=== > 0.339}[/tex]
--
Hope that this helped! Best wishes.
--
Select the correct answer from each drop-down menu. Consider this system of equations: (equation A) (equation B) The solution for the system of equations is .
Answers
The solution for the system of equations is: (99/13, 150/13)
Given the two expression 2/3x+3/5y=12 and 5/2y-3x=6
We have to find solution of two given expression.
To find the value of x, we have to eliminate y by making y the subject of formula in any of the equations.
Multiply equation A by 5/3 t.o get,
5/3(2/3x) + 5/3(3/5y) = 5/3(12)
10/9x + y = 20
y = 20 - 10/9x
substituting for y into equation b, we have:
5/2(20 - 10/9x) - 3x = 6
50 - 25/9x - 3x = 6
52/9x = 44
52x = 396
The expression that gives the value of x is: 52x = 396
Hence, x = 396/52 = 99/13
y = 20 - 10/9(99/13) = 20 - 110/13 = 150/13
Hence The solution for the system of equations is: (99/13, 150/13)
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what is the fourth term in the binomial expansion (a+b)^6)
Answers
Answer:
[tex]20a^3b^3[/tex]
Step-by-step explanation:
Binomial Series
[tex](a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n[/tex]
Factorial is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.
Example: 4! = 4 × 3 × 2 × 1
Therefore, the fourth term in the binomial expansion (a + b)⁶ is:
[tex]\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3[/tex]
[tex]\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3[/tex]
[tex]\implies \dfrac{6!}{3!3!}a^{3}b^3[/tex]
[tex]\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3[/tex]
[tex]\implies \left(\dfrac{120}{6}\right)a^{3}b^3[/tex]
[tex]\implies 20a^3b^3[/tex]
evaluate question 3 only
Answers
Step-by-step explanation:
(4²-x²)³/²
or,(4+X) (4-X)
Substitute [tex]x = 4 \sin(y)[/tex], so that [tex]dx = 4\cos(y)\,dy[/tex]. Part of the integrand reduces to
[tex]16 - x^2 = 16 - (4\sin(y))^2 = 16 - 16 \sin^2(y) = 16 (1 - \sin^2(y)) = 16 \cos^2(y)[/tex]
Note that we want this substitution to be reversible, so we tacitly assume [tex]-\frac\pi2\le y\le \frac\pi2[/tex]. Then [tex]\cos(y)\ge0[/tex], and
[tex](16-x^2)^{3/2} = 16^{3/2} \left(\cos^2(y)\right)^{3/2} = 64 |\cos(y)|^3 = 64 \cos^3(y)[/tex]
(since [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex])
So, the integral we want transforms to
[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 64 \int \cos^3(y) \times 4\cos(y) \, dy = 256 \int \cos^4(y) \, dy[/tex]
Expand the integrand using the identity
[tex]\cos^2(x) = \dfrac{1+\cos(2x)}2[/tex]
to write
[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 256 \int \left(\frac{1 + \cos(2y)}2\right)^2 \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \cos^2(2y)) \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \frac{1 + \cos(4y)}2\right) \, dy \\\\ = 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy[/tex]
Now integrate to get
[tex]\displaystyle 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy = 32 \left(3y + 2 \sin(2y) + \frac14 \sin(4y)\right) + C \\\\ = 96 y + 64 \sin(2y) + 8 \sin(4y) + C[/tex]
Recall the double angle identity,
[tex]\sin(2y) = 2 \sin(y) \cos(y)[/tex]
[tex]\implies \sin(4y) = 2 \sin(2y) \cos(2y) = 4 \sin(y) \cos(y) (\cos^2(y) - \sin^2(y))[/tex]
By the Pythagorean identity,
[tex]\cos(y) = \sqrt{1 - \sin^2(y)} = \sqrt{1 - \dfrac{x^2}{16}} = \dfrac{\sqrt{16-x^2}}4[/tex]
Finally, put the result back in terms of [tex]x[/tex].
[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 128 \frac x4 \frac{\sqrt{16-x^2}}4 + 32 \frac x4 \frac{\sqrt{16-x^2}}4 \left(\frac{16-x^2}{16} - \frac{x^2}{16}\right) + C \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 8 x \sqrt{16 - x^2} + \frac14 x \sqrt{16 - x^2} (8 - x^2) + C \\\\ = \boxed{96 \sin^{-1}\left(\frac x4\right) + \frac14 x \sqrt{16 - x^2} \left(40 - x^2\right) + C}[/tex]
Suppose that prices of recently sold homes in one neighborhood have a mean of $220,000 with a standard deviation of $7450. Using Chebyshev's Theorem, what is the minimum percentage of recently sold homes with prices between $197,650 and $242,350? Round your answer to one decimal place.
Answers
The minimum percentage of recently sold homes with prices between $197,650 and $242,350 is 88.9%.
What is Mean ?Mean is the ratio of the sum of all the data points to the number of data points.
It is given that
mean of $220,000 with a standard deviation of $7450.
The range is given , let the range is represented by x - --y
It is given that x = 197650 and y = 242350
Let the number of homes sold is k
To determine the value of k
upper level = (y-mean)/standard deviation = (242350-220000)/7450 = 3
lower level = (mean-x)/standard deviation = (220000-197650)/7450 = 3
probability = 1-(1/k²)
k= 3
= 1 - (1/3^2)
= 1 - 1/9
= 0.889 or 88.9%
So, the minimum percentage of recently sold homes with prices between $197,650 and $242,350 is 88.9%.
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Wei Xun bought 8 pieces of chocolates and 10 lollipops for $17. The average price of a piece of chocolate was S$1. What was the average price of a lollipop?
Answers
Answer:
$0.90
Step-by-step explanation:
If each piece of chocolate is $1, then 8 pieces is $8. Wei Xun bought 8 pieces of chocolate and 10 lollipops, which came out to $17. The chocolate was $8 total, leaving $9 for the 10 lollipops. 9/10 = 0.9. So, each lollipop was $0.90, or 90 cents.
A consultant needs to make at least $600 this week. She earns $120 for each
new written piece and $60 for each review. Which of the following inequalities
represents the possible combinations of reviews and new written pieces that
she must complete?
OA. 120x+60 y ≤ 600
OB. 120x+60y < 600
O C. 120x+60y 2 600
OD. 120x+60y > 600
SUBMIT
Answers
Find the perimeter of the following shape, given its curves are made from parts of circles.
Give your answers in terms of .
4cm
4cm
4cm
The diagram is not drawn to scale.
