Mr Louis wants to top-up his central heating oil tank.


The oil tank can take up to 1400 litres of oil.


There are already 150 litres of oil in the tank.


The price of oil is 80. 5p per litre.


As a loyal customer, Mr Louis gets a 6. 5% discount on the price of the oil.


How much discount does Mr Louis get on this purchase?


Give your answer in £.

Answer:5

Step-by-step explanation: The median of the lower quartile is 23 and the median of the upper quartile is 28. 28-23=5. The IQR is 5.

Based on simultaneous equations, the number of children and adults who swam at the public pool that hot summer's day is as follows:

Simultaneous equations are two or more equations solved concurrently.

Simultaneous equations are also referred to as a system of equations because the equations are solved at the same time.

The total number of people who used the public swimming pool = 670

The unit price for children = $1.25

The unit price for adults = $2.00

The total amount collected that day = $1,118

Let the number of children who swam at the public pool that day = x

Let the number of adults who swam at the pool that day = y

x + y = 670 ... Equation 1

1.25x + 2y = 1,118 ... Equation 2

Multiply Equation 1 by 2:

2x + 2y = 1,340 Equation 3

Subtract Equation 2 from Equation 3:

2x + 2y = 1,340

-

1.25x + 2y = 1,118

0.75x = 222

x = 296

y = 670 - 296

= 374

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The confidence level represents the degree of certainty that the interval contains the true population parameter.

The statement "determines with 95% confidence that the true mean number of suitable apples produced per tree is between 375 and 520" means that if the farmer were to repeat the sampling process many times and calculate the confidence interval each time, 95% of those intervals would contain the true mean number of suitable apples per tree.

Therefore, we can be 95% confident that the true mean number of suitable apples produced per tree is within the interval of 375 to 520 for this particular sample of 40 trees.

The confidence level represents the degree of certainty that the interval contains the true population parameter.

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The height of the cone that the volume of a cylinder is twice the volume of a cone is 7.5 meters.

Let's first define some variables to represent the dimensions of the cone and cylinder. Let's use r for the radius of both shapes, h for the height of the cone, and 5 for the height of the cylinder.

The volume of a cone is given by V_cone = (1/3)πr^2h, and the volume of a cylinder is given by V_cylinder = πr^2h.

We are told that the volume of the cylinder is twice the volume of the cone:

V_cylinder = 2V_cone

Substituting the formulas for the volumes of the cone and cylinder, we get:

πr^2(5) = 2[(1/3)πr^2h]

Simplifying, we can cancel the π and the r^2 terms on both sides:

5 = (2/3)h

Multiplying both sides by 3/2, we get:

h = 7.5

Therefore, the height of the cone is 7.5 meters.

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Answer:  csc M =  [tex]\frac{\sqrt{86} }{8}[/tex]

Step-by-step explanation:

The csc is related to sin

csc x =  1/sin x

find sin M first  then flip it to find csc M

sin M= opposite/hypotenuse

sin M= [tex]\frac{8}{\sqrt{86} }[/tex]                >flip that

csc M =  1/sin M

csc M =  [tex]\frac{\sqrt{86} }{8}[/tex]              >root cannot be simplified it breaks down into 2 and 43

                                     which are 2 prime numbers

It would take approximately 21.2 minutes for 960 grams of Element X to decay to 295 grams.

The time it takes for 960 grams of Element X with a half-life of 15 minutes to decay to 295 grams can be found using the formula y = a [tex](0.5)^\frac{t}{h}[/tex] .

1: Identify the variables.

a = initial amount = 960 grams
y = final amount = 295 grams
h = half-life = 15 minutes
t = time in minutes (this is what we want to find)

2: Plug the variables into the formula.
295 = 960 [tex](0.5)^\frac{t}{15}[/tex]

3: Solve for t.
Divide both sides by 960.
(295/960) =  [tex](0.5)^\frac{t}{15}[/tex]

4: Take the logarithm of both sides to remove the exponent.
log(295/960) = log  [tex](0.5)^\frac{t}{15}[/tex]

5: Use the logarithm property to move the exponent to the front.
log(295/960) = (t/15) * log(0.5)

6: Solve for t.
t = (15 * log(295/960)) / log(0.5)

7: Calculate t.
t ≈ 21.2 minutes

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Maria's average quiz score is 9.6.

B. The standard deviation of her quizzes is approximately 0.5 (rounded to the nearest tenth).

(a) The average of Maria's quizzes can be found by adding up all her scores and dividing by the total number of quizzes:

Average = (10 + 9 + 10 + 9 + 10) / 5 = 9.6

Therefore, Maria's average quiz score is 9.6.

(b) To calculate the standard deviation of her quizzes, we first need to find the variance. We can do this by finding the average of the squared differences between each score and the mean:

[(10 - 9.6)² + (9 - 9.6)² + (10 - 9.6)² + (9 - 9.6)² + (10 - 9.6)²] / 5 = 0.24

So the variance is 0.24. To find the standard deviation, we take the square root of the variance:

√0.24 ≈ 0.5

So the standard deviation of her quizzes is approximately 0.5 (rounded to the nearest tenth).

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The decay of isotope at compound rate is approximately 0.0140.

To find the continuous compound rate of decay of this isotope, we can use the following formula:

Nₜ = N₀e^(-λᵗ)

Where:
Nₜ is the amount of the isotope present after time t (years),
N₀ is the initial amount of the isotope,
λ is the continuous compound rate of decay, and
t is the time in years.

In this case, 91.9% of the isotope is still present 6 years after the disaster,

so Nₜ = 0.919 * N₀, and t = 6 years.

We want to find λ, the continuous compound rate of decay.

We can rewrite the formula as follows:

0.919 * N₀ = N₀ * e^(-λ * 6)

Divide both sides by N₀:

0.919 = e^(-λ * 6)

Now, take the natural logarithm (ln) of both sides:

ln(0.919) = -λ * 6

Divide by -6 to solve for λ:

λ = ln(0.919) / (-6)

Calculate the value:

λ ≈ 0.0140

So, the continuous compound rate of decay of this particular radioactive isotope is approximately 0.0140.

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sin 2u = -1/2, cos 2u = -1/2, tan 2u = 1, because cot u = sqrt(2) and the range of u is between pi and 3pi/2.

Given cot u = sqrt(2) and the range of trigonometric of u, we can determine the values of sine, cosine, and tangent of 2u using the double-angle formulas. First, we can find the value of cot u by using the fact that cot u = 1/tan u, which gives us tan u = 1/sqrt(2). Since u is in the third quadrant (i.e., between pi and 3pi/2), sine is negative and cosine is negative.

Using the double-angle formulas, we can express sin 2u and cos 2u in terms of sin u and cos u as follows:

sin 2u = 2sin u cos u

cos 2u =[tex]cos^2[/tex] u - [tex]sin^2[/tex] u

Substituting the values of sine and cosine of u, we get:

sin 2u = 2*(-sqrt(2)/2)*(-sqrt(2)/2) = -1/2

cos 2u = (-sqrt(2)/2[tex])^2[/tex] - (-1/2[tex])^2[/tex] = -1/2

To find the value of tangent of 2u, we can use the identity:

tan 2u = (2tan u)/(1-[tex]tan^2[/tex] u)

Substituting the value of tan u, we get:

tan 2u = (2*(1/sqrt(2)))/(1 - (1/sqrt(2)[tex])^2[/tex]) = 1

Therefore, sin 2u = -1/2, cos 2u = -1/2, and tan 2u = 1.

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1) The distance left in the race is  554.93km

2) The total amount earned is $2,178.91

We know that the total race is of 1000km, to find the distance missing, we need to take that total distance and subtract the amounts that the cyclist already traveled.

Then we will get:

distance left = 1000km - 145.8km - 136.65km - 162.62 km

distance left = 554.93km

That is the distance left in the race.

2) We know that each piece costs $19.99, and 109 pieces are sold, then the amount earned is the product between these two numbers.

Earnings = 109*$19.99  = $2,178.91

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The value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

Given, [tex]\lim_{x \to 3} f(x)=0[/tex]

[tex]\lim_{x \to 3} g(x)=4[/tex]

[tex]\lim_{x \to 3} h(x)=2[/tex]

We have to find the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex]

[tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)=\lim_{x \to 3} \frac{6h(x)}{4f(x)+g(x)}[/tex]

[tex]= \frac{\lim_{x \to 3}6h(x)}{\lim_{x \to 3}4f(x)+\lim_{x \to 3}g(x)}[/tex]

[tex]=\frac{6\times 2}{4\times0+4}[/tex]

= 12/4

= 3

Hence, the value of [tex]\lim_{x \to 3} \frac{6h}{4f+g} (x)[/tex] is 3

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The distance traveled by the surveyor is √73 miles. The height of the building that the ladder reaches is √15 meters. The longest line that can be drawn is 5√34 cm. The length of the guy wire that is needed is 5√5 meters. The length of the hypotenuse of the given right triangle is 6√3 inches.

In a right-angled triangle that is a triangle with one of the angles with magnitude 90° following is true according to Pythogaras' Theorem:

[tex]A^2=B^2+C^2[/tex]

where A is the hypotenuse

B is the base

C is the height

1. According to the question,

the distance between the starting and the ending point is the hypotenuse of a right-angled triangle

B = 8 miles

C = 3 miles

A = √(64 + 9)

= √73 miles

2. Hypotenuse in the given question is the length of the ladder, thus,

A = 4 m

B = 1 m

16 = 1 + [tex]C^2[/tex]

C = √15 meters

3. The longest line that can be drawn on the paper is described as the hypotenuse of the triangle

C = √225 + 625

= 5√34 cm

4. The length of the guy wire is the hypotenuse of the triangle.

C = √100 + 25

= 5√5 meters

5. Let the base of the triangle be x

the hypotenuse be 2x

height = 9 inches

[tex]4x^2=x^2[/tex] + 81

[tex]3x^2[/tex] = 81

x = 3√3 inches

Hypotenuse = 2x = 6√3 inches

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The mean of a single roll is given as μ = 3.5, and the variance is given as [tex]σ^2[/tex] = 2.92.

The sample size for the first five rolls is n1 = 5, and the sample size for the remaining ten rolls is n2 = 10.

The mean of the sampling distribution of the difference in sample means x¯1−x¯2 is given as:

μ(x¯1−x¯2) = μ(x¯1) - μ(x¯2) = μ - μ = 0

The variance of the sampling distribution of the difference in sample means x¯1−x¯2 is given as:

σ^2(x¯1−x¯2) = (σ^2(x¯1)/n1) + (σ^2(x¯2)/n2)

where σ^2(x¯1) is the variance of the sample mean for the first five rolls and σ^2(x¯2) is the variance of the sample mean for the remaining ten rolls.

Since each roll of the die is independent, the variance of the sample mean for each sample is given as:

σ^2(x¯1) = σ^2/ n1 = 2.92/5 = 0.584

σ^2(x¯2) = σ^2/ n2 = 2.92/10 = 0.292

Substituting these values in the above equation, we get:

σ^2(x¯1−x¯2) = (0.584/5) + (0.292/10) = 0.1468

Therefore, the standard deviation of the sampling distribution of the difference in sample means x¯1−x¯2 is:

σ(x¯1−x¯2) = sqrt(σ^2(x¯1−x¯2)) = sqrt(0.1468) = 0.3835 (rounded to four decimal places)

Hence, the standard deviation of the sampling distribution of the difference in sample means x¯1−x¯2 is 0.3835.

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To find the maximum concentration of an antibiotic between hours 1 and 7, first find the critical points of the function C(t), then evaluate C(t) at the critical points and endpoints to choose the highest value.

To determine the maximum concentration of the antibiotic between hours 1 and 7, follow these steps:
1. Find the critical points of the function C(t) = 4te^(-397). To do this, find the first derivative of the function, C'(t), and set it equal to 0.
2. Check the value of C(t) at the critical points and the endpoints of the interval, t=1 and t=7.
3. Choose the highest value of C(t) among the critical points and the endpoints.
1: Find the first derivative, C'(t).
C(t) = 4te^(-397)
C'(t) = 4e^(-397)(1-397t)
2: Set the first derivative equal to 0 and solve for t.
4e^(-397)(1-397t) = 0
1 - 397t = 0
t = 1/397
3: Evaluate C(t) at the critical point t = 1/397 and the interval endpoints t = 1 and t = 7.
C(1/397) = 4(1/397)e^(-397(1/397)) ≈ 0.01 ag/mg
C(1) = 4(1)e^(-397(1)) ≈ 0.00 ag/mg
C(7) = 4(7)e^(-397(7)) ≈ 0.00 ag/mg
The maximum concentration of the antibiotic occurs at t = 1/397 hours, with a concentration of approximately 0.01 ag/mg. What is Titration: Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known.

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The value of f(4) rounded to the nearest tenth is approximately 194.9.

The value of f(4) can be found by substituting x=4 in the given function f(x) = [tex]4e^x[/tex], so we get:

f(4) = [tex]4e^4[/tex]

Using a calculator, we can evaluate this expression as:

f(4) ≈ 194.92

Rounding this to the nearest tenth gives:

f(4) ≈ 194.9

Therefore, the value of f(4) rounded to the nearest tenth is approximately 194.9.

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The market value of Sylvia Baxter's property are $68,800.00. The correct answer is (c)

To find the market value of Sylvia Baxter's property, we need to divide the assessed value by the assessment rate and then multiply by 100.

Assessed value of the home = $64,000

Assessed value of the land = $4,800

Assessment rate = 35% = 0.35 (as given in the problem)

So, the total assessed value of the property = $64,000 + $4,800 = $68,800

Now, to find the market value, we need to divide the assessed value by the assessment rate and multiply by 100:

Market value = (Assessed value / Assessment rate) x 100

Market value = ($68,800 / 0.35) x 100 = $196,571.43 (rounded to the nearest cent)

Therefore, the market value of her property is $68,800.00.

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Let's denote the total distance traveled by the object as `d` and time as `t`.

We can use the given information to set up a system of equations:

When t = 10.0 seconds, d = 50.0 meters

50.0 = a(10.0)^2 + b(10.0) + c         (Equation 1)

When t = 20.0 seconds, d = 200.0 meters

200.0 = a(20.0)^2 + b(20.0) + c          (Equation 2)

When t = 0 seconds, d = 0 meters

0 = a(0)^2 + b(0) + c           (Equation 3)

Simplifying Equation 3, we get c = 0.

Substituting c = 0 in Equations 1 and 2, we get:

50.0 = 100a + 10b               (Equation 4)

200.0 = 400a + 20b              (Equation 5)

We can solve Equations 4 and 5 simultaneously to get the values of `a` and `b`:

From Equation 4, we get:

10b = 50 - 100a

b = 5 - 10a

Substituting this value of `b` in Equation 5, we get:

200.0 = 400a + 20(5 - 10a)

200.0 = 400a + 100 - 200a

200.0 = 200a + 100

100.0 = 200a

a = 0.5

Substituting this value of `a` in Equation 4, we get:

50.0 = 100(0.5) + 10b

50.0 = 50 + 10b

b = 0

Therefore, the quadratic function that models the total distance traveled by the object is:

[tex]d = 0.5t^2[/tex]

To find the total distance traveled by the object after 30.0 seconds, we can substitute `t = 30.0` in the above equation:

[tex]d = 0.5(30.0)^2[/tex]

d = 450.0 meters

Therefore, the object will travel a total distance of 450.0 meters after 30.0 seconds.

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Answer:

Rate: 36:3

Unit Rate: 12:1

Step-by-step explanation:

Answer:

m = 6/5

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Points (3, 9) and (8, 15)

We see the y increase by 6 and the x increase by 5, so he slope is

m = 6/5

Answer:

The slope of the points is 6/5.

Step-by-step explanation:

SOLUTION :

Using slope of a line formula to find the slope of the points :

[tex]\quad\dashrightarrow{\sf{m = \dfrac{y_2 - y_1}{x_2 - x_1}}}[/tex]

Substituting all the given values in the formula to find the slope of the points :

[tex]\quad\dashrightarrow{\sf{m = \dfrac{y_2 - y_1}{x_2 - x_1}}}[/tex]

[tex]\quad\dashrightarrow{\sf{m = \dfrac{15 - 9}{8 -3}}}[/tex]

[tex]\quad\dashrightarrow{\sf{m = \dfrac{6}{5}}}[/tex]

[tex]\quad{\star\underline{\boxed{\sf{\red{m = \dfrac{6}{5}}}}}}[/tex]

Hence, the slope of the points is 6/5.

Answer:

y = -2x + 14

Step-by-step explanation:

OK so first u have to do y = -2x + b cuz its parallel

then u gotta just plug in the ordered pair so

6 = -2(4)+b

6 = -8 +b

14 = b

So now u have to do

y = -2x + 14

The correct expression that is equal to 4.6 is option c. [1.6 + (3 × 4)] – (2 ÷ 2)

Let's evaluate each expressions using the BODMAS rule of mathematics,

a. 1.6 + (3 × 4) – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

b. 1.6 + 3 × 4 – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

c. [1.6 + (3 × 4)] – (2 ÷ 2)

= [1.6 + 12] - 1

= 12.6

d. (1.6 + 3) × (4 – 2) ÷ 2

= 4.6 × 2 ÷ 2

= 4.6

BODMAS is an acronym used to remember the order of operations in mathematics: Brackets, Orders, Division, Multiplication, Addition, Subtraction. It is used to perform calculations in the correct order to obtain the correct result. Therefore, the correct answer is (c).

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Complete question - Which expression is equal to 4.6?

a. 1.6 + (3 × 4) – 2 ÷ 2

b. 1.6 + 3 × 4 – 2 ÷ 2

c. [1.6 + (3 × 4)] – (2 ÷ 2)

d. (1.6 + 3) × (4 – 2) ÷ 2

To make the second prism, Jessica needs an additional 25.2 cm of material.

To answer your question, since Jessica wants to create a second triangular prism with a scale factor of 3, she will need 3 times the material used for the first prism.

She used 12.6 cm for the first prism, so for the second prism, she would need 12.6 cm × 3 = 37.8 cm of material.

Jessica already has 300 cm of material, so to find out how much more she needs, subtract the amount used for the first prism: 37.8 cm - 12.6 cm = 25.2 cm.

Jessica needs an additional 25.2 cm of material to make the second prism.

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The number of students who took the test on Monday is found to be 15, hence the correct option is B.

Let us assume that the number of student taking test on Monday is n. The total score for Monday's test is n times the average score of 80.4,

Monday's total score = 80.4n

When the student who missed the test on Monday took the test on Tuesday and scored 90, the total score became,

Total score = 80.4n + 90

The new average score of 81 can be expressed as,

81 = Total score / (n+1)

Substituting the value of the total score, we get,

81 = (80.4n + 90)/(n+1)

Multiplying both sides by n+1, we get,

81(n+1) = 80.4n + 90

Expanding the brackets,

81n + 81 = 80.4n + 90

Simplifying,

0.6n = 9

n = 15, so, the number of students who took the test on Monday is 15.

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Assuming that one snap cube represents one milliliter (ml) of paint, we can use five red snap cubes to represent 5 ml of red paint and three blue snap cubes to represent 3 ml of blue paint. We can arrange these snap cubes in a row to represent the recipe:

RRRRR BBB

This indicates that we mix 5 ml of red paint with 3 ml of blue paint to create the maroon paint.

To draw a sketch of the snap-cube representation of the maroon paint, we can combine the red and blue snap cubes into a single row:

RRRRR BBB

This gives us a row of eight snap cubes, which represents the maroon paint. Visually, the maroon paint will appear as a blend of red and blue, with a darker, richer hue than either color alone.

Each snap cube represents one milliliter (ml) of paint. Therefore, in this representation, each snap cube represents a fixed amount of paint, regardless of the color. In other words, each cube represents a unit of volume, rather than a unit of color or pigment.

(a) P(A red ball is drawn) = 4/9

(b) P(A white ball is drawn) = 7/18

(c) P(A yellow ball is drawn) = 1/6

(d) P(A green ball is drawn) = 0

(a) To find the probability that a red ball is drawn, we'll use the following formula:
P(A red ball is drawn) = (Number of red balls) / (Total number of balls)

There are 8 red balls and a total of 8+7+3 = 18 balls in the jar. So, the probability of drawing a red ball is:
P(A red ball is drawn) = 8/18 = 4/9

(b) To find the probability that a white ball is drawn:
P(A white ball is drawn) = (Number of white balls) / (Total number of balls)

There are 7 white balls, so the probability of drawing a white ball is:
P(A white ball is drawn) = 7/18

(c) To find the probability that a yellow ball is drawn:
P(A yellow ball is drawn) = (Number of yellow balls) / (Total number of balls)

There are 3 yellow balls, so the probability of drawing a yellow ball is:
P(A yellow ball is drawn) = 3/18 = 1/6

(d) To find the probability that a green ball is drawn:
P(A green ball is drawn) = (Number of green balls) / (Total number of balls)

There are no green balls in the jar, so the probability of drawing a green ball is:
P(A green ball is drawn) = 0/18 = 0

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The critical value you will use for your 98% confidence interval with a sample size of 32 is 2.33.

When finding a 98% confidence interval for a normally distributed population with a sample size of 32, you will need to use a critical value from the standard normal (z) distribution.

To find the critical value, you can refer to a z-table or use a calculator with statistical functions. For a 98% confidence interval, you will need the z-score that corresponds to the middle 98% of the data, leaving 1% in each tail. This z-score is approximately 2.33.

So, the critical value you will use for your 98% confidence interval with a sample size of 32 is 2.33.

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If we have 30 total participants in a between-subjects design with three groups, we can assign any number of participants to each group as long as the sum of participants in each group adds up to 30. The number of participants in each group is 10 in the 8-ounce group, 15 in the 24-ounce group, and 5 in the no-caffeine group.

If we have a total of 30 participants in a between-subjects design, we need to divide them into three groups according to the conditions.

Let x be the number of participants who received 8 ounces of a caffeinated beverage, y be the number of participants who received 24 ounces of a caffeinated beverage, and z be the number of participants who received no caffeine. Since we have a total of 30 participants, we can write

x + y + z = 30

We don't know the specific number of participants in each group, but we do know that they must add up to 30.

However, we also know that each participant can only be in one group, which means that we have mutually exclusive groups. Therefore, we can assume that there is no overlap between the groups, which means that the total number of participants in each group is

x + y + z = 30

z = 30 - (x + y)

So, we can assign any value to x and y, as long as the sum of x and y is less than or equal to 30. Then, we can find the value of z using the equation above.

For example, if we assign 10 participants to the 8-ounce group and 15 participants to the 24-ounce group, we would have

x = 10

y = 15

z = 30 - (10 + 15) = 5

So, there would be 10 participants in the 8-ounce group, 15 participants in the 24-ounce group, and 5 participants in the no-caffeine group.

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