Answer:
atoms
Explanation:
Hormones are derived from amino acids or lipids. Amine hormones originate from the amino acids tryptophan or tyrosine. Larger amino acid hormones include peptides and protein hormones. Steroid hormones are derived from cholesterol.
Water has a heat capacity of 4.184 J/g °C. If 50 g of water has a temperature of 30ºC and a piece of hot copper is added to the water causing the temperature to increase to 70ºC. What is the amount of heat absorbed by the water?
The amount of heat absorbed by the water will be 8368 J.
What are heat gain and heat loss?Heat gain is defined as the amount of heat required to increase the temperature of a substance by some degree of Celsius. While heat loss is inverse to heat gain.
It is given by the formula as ;
[tex]\rm Q= mcdt[/tex]
The given data in the problem is;
Equilibrium temperature = 30°C.
mass of water = 50 g ,
Temperature change = 70ºC
The specific heat of water =4.184 J//g °C
The amount of heat absorbed by the water is;
[tex]\rm Q= mcdt \\\\ Q=50 \times 4.184 \times (70^0 -30^0)C\\\\ Q= 8368 J[/tex]
Hence, the amount of heat absorbed by the water will be 8368 J.
To learn more about the heat gain refer to the link;
https://brainly.com/question/26268921
#SPJ2
As a glacier melts, the volume V of the ice, measured in cubic kilometers, decreases at a rate modeled by the differential equation dVdt=kV , where t is measured in years. The volume of the glacier is 400km3 at time t=0 . At the moment when the volume of the glacier is 300km3 , the volume is decreasing at the rate of 15km3 per year. What is the volume V in terms of time
Solve the differential equation:
dV/dt = k V → 1/V dV/dt = k
→ d/dt [ln(V)] = k
→ ln(V) = k t + C
→ V (t )= exp(k t + C ) = C exp(k t ) = C e ᵏᵗ
At t = 0, the glacier has volume 400 km³ of ice, so
V (0) = 400 → C e⁰ = C = 400
Find when the glacier's volume is 300 km³:
V (t ) = 400 e ᵏᵗ = 300 → e ᵏᵗ = 3/4
→ k t = ln(3/4)
→ t = 1/k ln(3/4)
At this time, the volume is decreasing at a rate of 15 km³/yr, so
V ' (t ) = C k e ᵏᵗ → V ' (1/k ln(3/4)) = 400 k exp(k × 1/k ln(3/4)) = -15
→ 3/4 k = -3/80
→ k = -1/20
Then the volume V (t ) of the glacier at time t is
V (t ) = 400 exp(-1/20 t )
The volume in terms of time will be "V(t) = 400 exp (-[tex]\frac{1}{20}[/tex] t)".
Differential equation and VolumeAccording to the question,
Glacier's volume, V(0) = 400 km³
→ [tex]\frac{dV}{dt}[/tex] = kV
[tex]\frac{1}{V}[/tex] [tex]\frac{dV}{dt}[/tex] = k
ln(V) = kt + C
Now,
V (t) = exp (kt + C)
= C exp (kt)
= C[tex]e^{kt}[/tex]
When volume of glacier be "300 km³",
V(t) = 400 [tex]e^{kt}[/tex] = 300
[tex]e^{kt}[/tex] = [tex]\frac{3}{4}[/tex]
By taking log,
kt = ln([tex]\frac{3}{4}[/tex])
t = [tex]\frac{1}{k}[/tex] ln([tex]\frac{3}{4}[/tex])
When volume decrease at 15 km³/yr, then
→ V'(t) = Ck[tex]e^{kt}[/tex]
= 400 k exp (k × [tex]\frac{1}{k}[/tex] kn ([tex]\frac{3}{4}[/tex]))
= -15
Now,
[tex]\frac{3}{4}[/tex] k = - [tex]\frac{3}{80}[/tex]
By applying cross-multiplication,
k = - [tex]\frac{1}{20}[/tex]
Thus the response above is correct.
Find out more information about volume here:
https://brainly.com/question/5398201
Which of the following are vectors? *
2 points
Distance
Displacement
Speed
Time
Velocity
Answer:
Displacement and Velocity
Rank the following objects by their accelerations down an incline (assume each object rolls without slipping) from least to greatest:
a. Hollow Cylinder
b. Solid Cylinder
c. Hollow Sphere
d. Solid Sphere
Answer:
acceleration are
hollow cylinder < hollow sphere < solid cylinder < solid sphere
Explanation:
To answer this question, let's analyze the problem. Let's use conservation of energy
Starting point. Highest point
Em₀ = U = m g h
Final point. To get off the ramp
Em_f = K = ½ mv² + ½ I w²
notice that we include the kinetic energy of translation and rotation
energy is conserved
Em₀ = Em_f
mgh = ½ m v² +1/2 I w²
angular and linear velocity are related
v = w r
w = v / r
we substitute
mg h = ½ v² (m + I / r²)
v² = 2 gh [tex]\frac{m}{m+ \frac{I}{r^2} }[/tex]
v² = 2gh [tex]\frac{1}{1 + \frac{I}{m r^2} }[/tex]
this is the velocity at the bottom of the plane ,, indicate that it stops from rest, so we can use the kinematics relationship to find the acceleration in the axis ax (parallel to the plane)
v² = v₀² + 2 a L
where L is the length of the plane
v² = 2 a L
a = v² / 2L
we substitute
a = [tex]g \ \frac{h}{L} \ \frac{1}{1+ \frac{I}{m r^2 } }[/tex]
let's use trigonometry
sin θ = h / L
we substitute
a = g sin θ \ \frac{h}{L} \ \frac{1}{1+ \frac{I}{m r^2 } }
the moment of inertia of each object is tabulated, let's find the acceleration of each object
a) Hollow cylinder
I = m r²
we look for the acerleracion
a₁ = g sin θ [tex]\frac{1}{1 + \frac{mr^2 }{m r^2 } }[/tex]1/1 + mr² / mr² =
a₁ = g sin θ ½
b) solid cylinder
I = ½ m r²
a₂ = g sin θ [tex]\frac{1}{1 + \frac{1}{2} \frac{mr^2}{mr^2} }[/tex] = g sin θ [tex]\frac{1}{1+ \frac{1}{2} }[/tex]
a₂ = g sin θ ⅔
c) hollow sphere
I = 2/3 m r²
a₃ = g sin θ [tex]\frac{1}{1 + \frac{2}{3} }[/tex]
a₃ = g sin θ [tex]\frac{3}{5}[/tex]
d) solid sphere
I = 2/5 m r²
a₄ = g sin θ [tex]\frac{1 }{1 + \frac{2}{5} }[/tex]
a₄ = g sin θ [tex]\frac{5}{7}[/tex]
We already have all the accelerations, to facilitate the comparison let's place the fractions with the same denominator (the greatest common denominator is 210)
a) a₁ = g sin θ ½ = g sin θ [tex]\frac{105}{210}[/tex]
b) a₂ = g sinθ ⅔ = g sin θ [tex]\frac{140}{210}[/tex]
c) a₃ = g sin θ [tex]\frac{3}{5}[/tex]= g sin θ [tex]\frac{126}{210}[/tex]
d) a₄ = g sin θ [tex]\frac{5}{7}[/tex] = g sin θ [tex]\frac{150}{210}[/tex]
the order of acceleration from lower to higher is
a₁ <a₃ <a₂ <a₄
acceleration are
hollow cylinder < hollow sphere < solid cylinder < solid sphere
what is 60mph (miles per hour) in meters per second? ( A mile is 5280ft)
please someone help me
Answer:
60mph=26.8224meters per second
Explanation:
what happens to the work done when a force is doubled and the distance moved remain the same?
Answer:
Work done gets doubled.
Explanation:
The work done by a force is given by :
W = Fd
Where
F is force and d is distance move
If the force is doubled and the distance moved remain the same, it would mean that the work done becomes double of the initial work done.
At the time when force is doubled and distance moved remain the same so Work done gets doubled.
The following information should be considered:
The work done by a force is given by :
W = Fd
Where
F is force and d is distance move
In the case when the force is doubled and the distance moved remain the same, it would mean that the work done becomes double of the initial work done.
Learn more: brainly.com/question/16911495
when drawing electric field lines ___________ charges have vectors point away/out and______ charges have vectors point toward/in.
Answer:
Positive, Negative
Explanation:
The image I've attached shows that vectors point into the negative source and vectors point away from the positive source.
Two rubber bullets (each of the same mass) are fired at the same velocity towards two different blocks of equal mass. One block is made of clay and the bullet gets stuck in it, the clay block bullet begins to move in the direction the bullet was fired. The other block is made of aluminum and the bullet bounces off the block, the aluminum block also begins to move in the direction the bullet was fired. Which block (clay or aluminum) will move with greater velocity after being struck by the bullet
Answer:
Aluminum board will move with a higher velocity
Explanation:
The velocity of the block will be higher when the impulse imparted by the bullet is higher.
In case of bullet bouncing off, the impulse imparted on the aluminum board is high and hence, it will move with a high velocity as compared to that of the clay board.
What is the specific heat of a substance that absorbs 1600 joules of heat when a sample
of 18 g of the substance increases in temperature from 20 °C to 31°C? Round your answer
to two decimal places if necessary.
Answer:
8.08 J/g °C
Explanation:
Q=m*Cp*ΔT-->
Cp=Q/(m*ΔT) -->
Cp=1600/[18*(31-20)]-->
Cp=8.08 J/g °C
