Match the function with the graph.
a. y = |x+ 5|
b. y= |x-5| + 2
c. y= |x-5|
d. y=|x| -5

i did a and it was wrong. i don’t understand lol please help

Answer:

The answer is 1: 50000... If you look down here↓:

Step-by-step explanation:

With a scale of 1:20000, a unit length on the map represents a length of 20000. So 1 cm^2 = 1 cm* 1 cm which represents 20000*20000 cm^2 will be = 4*10^8 cm^2.

50 cm^2 represents that 4*50*10^8 cm^2 = 200* 10^8 cm^2.

Now, on the other hand, the map has the same. 200* 10^8 is represented by 8 cm^2. So the scale is sqrt [ 200* 10^8 / 8 ] = sqrt [ 25* 10^8 ] = 5* 10^4 = 50000.

Therefore the scale on the second map is 1: 50000.

Answer:

92

Step-by-step explanation:

46 + 46 = 92

Answer:

625 × 48 = 30,000

[tex]\sqrt[4]{30000} = 10 \sqrt[4]{3} [/tex]

answer = third option

Answer:

4.1968

Explanation:

Given that:

angle: 25°

opposite: x

adjacent: 9

So, use the tan rule:

opposite/adjacent = tan(x)

x/9 = tan(25)

x = 9tan(25)

x = 4.1968

Option A

Answer:

I will assume the equation is supposed to be f(x) = x^2 – 5x + 12 since it is said to be a quadratic equation.

Step-by-step explanation:

See attached graph.

The value of f(–10) = 82     False

      f(-10) = (-10)^2 - 5*(-10) + 12

       f(-10) = (100) +50 + 12

      f(-10) = 162

The graph of the function is a parabola.  True

The graph of the function opens down.   False

The graph contains the point (20, –8).      False

The graph contains the point (0, 0).          False

The equation that represents this number sentence is 1/5n - 3 = 28

Let the unknown number be "n". One-fifth of a number is expressed as 1/5n

Three less than one-fifth of a number is expressed as 1/5n - 3

Finally, if three less than one-fifth of a number is equal to 28, then the final expression will be 1/5n - 3 = 28

The equation that represents this number sentence is 1/5n - 3 = 28

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At 7:00 am Wesley complete his third shift if Wesley and two of his friends are driving cross country nonstop and have agreed to take turns driving in 7-hour shifts option (C) is correct.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have:

Wesley and two of his friends are driving cross country nonstop and have agreed to take driving in 7-hour shifts.

Wesley’s first shift starts at 6:00 am

6:00 am = 6h 0m

= 6 + 7

= 13 h = 1:00 PM (Wesley's starts to rest)

Wesley will take a rest for 14 hours (7 + 7)

First shift = 7 + 14 = 21

Second shift = 7 + 14 = 21

Third shift = 7 = 7

= 21 + 21 + 7 = 49

= 49/24 = 2 days + 1 hour

6h + 1h = 7h = 7:00 am

Thus, at 7:00 am Wesley complete his third shift if Wesley and two of his friends are driving cross country nonstop and have agreed to take turns driving in 7-hour shifts option (C) is correct.

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Answer:

17 batches

Step-by-step explanation:

51/4 ÷ 3/4 = 51/4 x 4/3

                =17

Answer:

The answer is C. -2x -4

Step-by-step explanation:

Your given information.

-3 - 3x - 1 + x

Combine and simplify common numbers/variables.

(-3x + x) + (-3 - 1)

-2x - 4

The value of x = 3/5 or 0.6 will satisfy the equation given.

An equation is a mathematical statement which is formed when two expressions are equated by an equal sign.

It is given that

[tex]\rm \dfrac{1}{3x-1} = \dfrac{2}{x+1}\\[/tex]

It has to be solved and the value of x has to be determined

(x+1) = 2 (3x-1)

x +1 = 6x -2

5x = 3

x = 3/5

Therefore the value of x = 3/5 or 0.6 will satisfy the equation given.

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Using two triangle concepts, it is found that the solution for y is of y = 70º.

Hence:

Then:

x + y + 70 = 180

x + 190 - 3x + 70 = 180.

2x = 80.

x = 40.

Hence:

y = 190 - 3x = 190 - 3(40) = 70º.

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Answer:

38 is the correct solution

Answer:

Before discount = $61.25

After discount = $49.00

Step-by-step explanation:

Given information:

The price of the gift before the discount is 100%.

If the $12.25 discount was 20% of the purchase price, then:

⇒ original price (before discount) = (12.25 / 20) × 100 = $61.25

To find the price after the discount, simply subtract the discount from the found original price:

⇒ $61.25 - $12.25 = $49.00

Conclusion

Answer:

B. 70

Explanation:

A total of 182 pairs of jeans and shorts were sold and the number of shorts sold was 28 fewer than twice the number of jeans. This can be expressed with j being the number of jeans as:

j2 - 28 = number of shorts

As the number of shorts is 28 lower than twice the number of jeans, this means it can not be C or D, as these numbers are larger than 182 when doubled. The process of elimination can be done with the remaining using our equation.

51(2) - 28 = 102 - 28 = 74
70(2) - 28 = 140 - 28 = 112

Now that we have the number of shorts sold by using the equation, we can add them with what number was used as their number of jeans.

74 + 51 = 125
112 + 70 = 182

So the number of jeans sold is B. 70.

The expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)

A cubic equation in algebra is a one-variable equation of the form ax3+bx2+cx+d=0 where an is nonzero. The roots of the cubic function defined by the left side of this equation are the solutions to this equation.

Given expression 2x³-3x²-3x+2 whose one of factor is (x-2)

We have to find second factor of given equation

First we will be rational root theorem to given expression so will get following expression:

[tex]\left(x+1\right)\frac{2x^3-3x^2-3x+2}{x+1}[/tex]

So one factor is (x-1) and now simplifying [tex]\frac{2x^3-3x^2-3x+2}{x+1}[/tex]  we get              2x² - 5x +2 and the factor of 2x² - 5x +2 will be (2x-1)(x-2)

Hence the expression which represents the other factor, or factors, of the given polynomial is option (C) (2x-1)(x+1)

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The solutions to the system of equation f(x) and g(x) are [tex]\frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex] and

[tex]\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]

Quadratic equations are equations that has a leading degree of 2. Given the following functions:

f(x)=2x^(2)-3x-10

g(x)=-3x^(2)+20

To solve, we will use the quadratic formula as shown below;

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

For the quadratic equation f(x)=2x^(2)-3x-10

a = 2

b = -3

c = -10

Substitute

[tex]x=\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(-10)}}{2(2)}\\x=\frac{3\pm\sqrt{89}}{4}\\x= \frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex]

For the quadratic equation -3x² + 20

a =-3

b = 0

c = 20

[tex]x=\frac{0\pm \sqrt{(0)^2-4(-3)(20)}}{2(-3)}\\x=\frac{\pm4\sqrt{15}}{-6}\\x=\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]

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Answer:  [tex]h(x)=\sqrt{x+4}[/tex]

Step-by-step explanation:

The graph of h(x) is the graph of f(x) shifted 4 units left.

Answer:

100% probability or 1/1

Step-by-step explanation:

This is because since the basketball NEVER misses, there is no chance the the ball will not go inside the basket, leaving room for only the ball to GO inside the basket. Hope this helps!! :D

Answer: Option (4)

Step-by-step explanation:

We know that the radius of the circle is 3.

Using the distance formula, the distance from the given point to the center is

[tex]\sqrt{(\sqrt{6}-0)^{2}+(2-0)^{2}} = \sqrt{10} \neq 3[/tex]

Answer:d

Step-by-step explanation:

Answer:

yes,you can buy the textbook

Step-by-step explanation:

determine discount

60 × 0.2(decimal form of 20%)

=12

apply discount

60-12

=48

50>48✓

1. 6 km ≈ 3.73 mi

2. 2.5 L ≈ .66 gal

3. 90 lb ≈ 40.82 kg

Answer:

[tex]\boxed{\bf f(x)=4\cdot \left(\cfrac{7}{4}\right)^x}[/tex]

Step-by-step explanation:

In exponential form, a* b^x,

Where, "a" is value of the function when x=0 and "b" is the constant ratio of f(x) for consecutive for integer values of x.

Y-intercept : (0, 4) so, a = 4.

The graph also passes through (1,7), because 0 and 1 are consecutive integer x-values.

[tex]\bf b=\cfrac{7}{4}[/tex]

So therefore, the equation for f(x) is :-

[tex]\bf f(x)=4\cdot \left(\cfrac{7}{4}\right)^x[/tex]

Answer:

25

Step-by-step explanation:

This is an equilateral triangle so all of its angle measures, and side lengths likewise, are equal.

To find x we can use the following equation:

3x - 5 = 2x + 20 export like terms to the same side of the equation

3x - 2x = 20 + 5 (notice how terms change from "+" to "-" and vice versa)

add/subtract like terms

x = 25

Answer:

pete

Step-by-step explanation:

i think its pete???

[tex]\large\sf{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large \sf{=\frac{\left(\sqrt{1+sin\theta}\right)^{2}+\left(\sqrt{1-sin\theta}\right)^{2}}{\sqrt{(1-sin\theta)(1+sin\theta)}}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{=\frac{1-sin\theta+1+sin\theta}{\sqrt{1^{2}-sin^{2}\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large \sf{=\frac{2}{\sqrt{cos^{2}\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{= \frac{2}{cos\theta}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{= 2sec\theta}[/tex]

[tex]\\[/tex]

[tex]\large\sf{=RHS}[/tex]

Therefore,

[tex]\large\sf\red{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}=2sec\theta}[/tex]