Malachi asks students in his class, "How long does it take you to get to school?" The histogram
shows the data.
Which statement best describes the distribution?

Answer:

I put the answer on the attachment please look

B = (715x) / (h^2)

Step 1: Get rid of the denominator by multiplying both sides by h^2

(B)(h^2) = 715x

Step 2: Isolate x by dividing both sides by 715

(Bh^2) / 715 = x

Answer: x = Bh^2 / 715

Hope this helps!

The solution for x is -48, the answer is D) -48.

What is Algebraic expression ?

An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It represents a value that can change based on the values assigned to the variables.

Starting with:

x:4 = 12

Multiplying both sides by -1 gives:

(-x÷4) = -12

Simplifying the left side:

x÷4 = -12

Multiplying both sides by 4 gives:

x = -48

Therefore, the solution for x is -48, the answer is D) -48.

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Answer:

Step-by-step explanation:

f(x)=2x

note: putting anything in the f(x) parentheses replaces x in the function with that value

so,

f(-3) = 2(-3) = -6

f(0) = 2*0 = 0

f(2) = 2(2) = 4

The equation 5ʷ ⁺ ³ = 17 when solved for w is approximately w = 0.41

From the question, we have the following parameters that can be used in our computation:

5ʷ ⁺ ³ = 17

Take the logarithm of both sides of the equation

So, we have

w + 3 = ln(17)/ln(3)

Evaluate the quotient on the left side of the equation

This gives

w + 3 = 2.59

So, we have

-3 + w + 3 = 2.59 - 3

Evaluate

w = 0.41

Hence, the equation when solved for w is approximately w = 0.41

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Answer:

[tex]30d^2[/tex]

Step-by-step explanation:

The actual rocket height is 1080 inches and the height of the actual rocket is 90 feet.

If the 1/20 scale model of the rocket stands 54 inches high, we can find the height of the actual rocket by multiplying the height of the model by 20:

Actual rocket height = 54 inches x 20 = 1080 inches

In order to convert inches to feet, we divide by 12:

Actual rocket height = 1080 inches / 12 = 90 feet

Therefore, the height of the actual rocket is 90 feet.

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The 1/20 scale model of the rocket stood 54 inches high What was the height of the actual rocket?

(b) Find the height of the actual rocket in feet.

All the numbers are rational numbers.

We have,

Rational numbers are those numbers that are terminating and recurring non-terminating.

Irrational numbers are those numbers that are non-terminating and non-recurring.

The numbers are:

1)

0.020202

This is non terminating recurring number.

It is a rational number.

2)

0.8

This is a terminating number.

It is a rational number.

3)

0.020202

This is non terminating recurring number.

It is a rational number.

Thus,

All the numbers are rational numbers.

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In ΔFGH,  the length of h is 714.2 cm

Let us assume that in ΔFGH, f represents the opposite side to angle F, g represents the opposite side to angle G,  and h represents the opposite side to angle H.

Consider the following figure.

Using sine rule for triangle FGH,

sin F/f = sin G/g = sin H/h

Consider equation sin G/g = sin H/h

sin(98°) / 910 = sin(51°) / h

We solve this equation for h.

h = (sin(51°) × 910)/ sin(98°)

h =  (0.777 × 910)/ 0.99

h = 714.21

h = 714.2 cm

This is the required length of h.

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The expression for the number of cookies Anna has left is [tex]3c - 8[/tex].

An expression refers to statement that have minimum of two numbers or variables or both and an operator connecting them.

The total number of cookies Anna baked is:

= 3 batches * c cookies/batch

= 3c cookies

After eating 8 cookies, Anna has left:

= 3c cookies - 8 cookies

So, the expression for the number of cookies Anna has left is [tex]3c - 8[/tex].

Full question "Anna baked 3 batches of cookies with c cookies in each batch she then ate 8 cookies. How many cookies does anna have left write your answer as an expression.

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Answer:

S = 2π(14^2) + 2π(14)(154)

= 2π(196) + 2π(2,156)

= 4,704π = 14,778.1 ft^2

Using 3.14 for π:

S = 4,704(3.14) = 14,770.6 ft^2

The solution for x in the equation (x – 7)^2 = 36 are x = 13 and x = 1

We can solve for x by taking the square root of both sides of the equation:

(x – 7)^2 = 36

Taking the square root of both sides:

x - 7 = ±6

Adding 7 to both sides:

x = 7 ± 6

Therefore, the values of x are:

x = 7 + 6 = 13

x = 7 - 6 = 1

So the correct answers are x = 13 and x = 1. The values x = -29 and x = 42 are not solutions to the equation.

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Answer:(a) The rate of decay is 14.4% per day, which can be written as a decimal by dividing by 100: r = 0.144.

(b) The formula for continuous decay is given by:

A = A₀ * e^(-rt)

where A is the remaining amount of the substance after time t, A₀ is the initial amount, r is the rate of decay, and e is the mathematical constant approximately equal to 2.71828.

Plugging in the given values, we get:

A = 140 * e^(-0.144*15)

A = 140 * e^(-2.16)

A ≈ 47.23

Therefore, after 15 days, approximately 47.23 mg of the radioactive substance will be left, rounded to two decimal places.

Step-by-step explanation:

The equation of the line passing through the points (-7, -3) and (1, 2) is [tex]y = \frac{5}{8}x + \frac{11}{8}[/tex].

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

First, we determine the slope of the line.

Given the two points are (-7, -3) and (1, 2)

We can find the slope of the line by using the slope formula:

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Substituting the values, we get:

m = (2 - (-3)) / (1 - (-7))

m = 5/8

Using the point-slope form, plug in one of the given points and slope m = 5/8 to find the equation of the line.

Let's use the point (-7, -3:

y - y₁ = m(x - x₁)

[tex]y - (-3) = \frac{5}{8}( x - (-7) ) \\\\y + 3 = \frac{5}{8}(x + 7 )\\\\y + 3 = \frac{5}{8}x + \frac{35}{8} \\ \\y = \frac{5}{8}x + \frac{35}{8} - 3\\\\y = \frac{5}{8}x + \frac{11}{8}[/tex]

Therefore, the equation of the line is [tex]y = \frac{5}{8}x + \frac{11}{8}[/tex].

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Answer:

90% of 300 = .90 × 300 = 270 high- definition televisions on order.

A graph of the reflection of line segment AB is shown on the coordinate plane below.

In Mathematics, a reflection across the x-axis would maintain the same x-coordinate while the sign of the y-coordinate changes from positive to negative.

Furthermore, a reflection across the line y = x would interchange (switch) the x-coordinate and y-coordinate and this is represented by the following transformation rule:

(x, y)                                    →              (y, x)

Ordered pair A = (4, -1)    →        Ordered pair A' = (-1, 4).

Ordered pair B = (4, 5)    →        Ordered pair B' = (5, 4).

In this exercise, we would use an online graphing calculator to plot the image of line segment AB after a reflection about the line y = x.

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Answer:

The value of the account will be $5,628

Step-by-step explanation:

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have    

substitute in the formula above  

therefore

The value of the account will be $5,628

The probability that either event will occur is 7/25

A probability is a number that reflects the chance or likelihood that a particular event will occur. The certainty of an event is 1 which is equivalent to 100% in percentage.

Probability = sample space /Total outcome

P(A or B) = P(A) +P(B) -P(A and B)

The total element = 25+5+15+5 = 50

therefore total outcome = 50

P(A) = 25/50

P(B) = 15/50

P(A and B) = 5/40

Therefore P(A and B) = 25/50+15/50 - 5/50

= 35/50 = 7/25

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We can rearrange the formula to solve for h:

v = √√2gh

Squaring both sides: v^2 = 2gh

Dividing both sides by 2g: h = v^2 / 2g

Substituting v = 96 ft/s and g = 32 ft/s^2, we get:

h = (96 ft/s)^2 / (2 × 32 ft/s^2)

h = 288 ft

Therefore, the object has fallen 288 feet.

Check the picture below.

The value of the variable w is 56

Algebraic expressions are described as expressions that are composed of terms, variables, factors, coefficients and constants.

Also, algebraic expressions are made up of mathematical or arithmetic operations, such as;

From the information given, we have the algebraic equation as;

w - 54 = 2

To determine the value of the variable, we take the steps;

collect the like terms

w = 2 + 54

Now, add the values

w = 56

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Answer:

$30.25

Step-by-step explanation:

55% of 55$ is $30.25. she wants 45 % off of 55$. which is $24.75. 55-24.75 is 30.25

$30.25

since it's 45% off, you need to subtract 45% from 100%

100%-45%=55%

then turn the % into a decimal

55%/100=0.55

now multiply the original price by 0.55

0.55*55=30.25

Answer:

25

Step-by-step explanation:

To solve this problem you have to use this formula [tex](\frac{b}{2})^{2}[/tex] it. So in this case b is the term next to the x term. This number is 10. So all we have to do is insert it into the formula. This would give us:

[tex]=(\frac{10}{2})^{2}\\\\=(5)^{2}\\\\= 25[/tex]

The constant term is 25.

Could I get Brainilest, please? I'm trying to get to the expert level

In this case, the cube root is = 0

We can use the rule Sarrus to evaluate the determinant

1 w w²

w w² 1

w² 1 w

Starting with the first column, we can wrte out the terms for the diagonal products and

then sum the terms for the products of the diagonal elements that wrap around

(1 x w² x  w) +(w x 1 x w²) + (w² x w x w)    - (w ² x w x 1) - (w x w² x w) - (1 x w x w ²)

Simplifying each term:

w³ +   w³ + w³ -   w³ -w³   - w³

We can see that all the terms cancel   out, leaving us with a determinant of 0. So it is clear that

|1 w w²|

|w w² 1 |

|w² 1 w | = 0

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Evaluate the determinant 1 w w2 , w w2 1, w2 1 w. where w is a cube root of unity.

The accrued value of the account in 10 years is $641.75

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Amount = P * (1 + 0.25r)ᵗ

Where

P = Principal = 600

r = Rate = 2.7% = 0.27

t = time = 10

Substitute the known values in the above equation, so, we have the following representation

Amount = 600 * (1 + 0.25 * 0.27)¹⁰

Evaluate

Amount = 641.75

Hence, the amount is 641.75

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a) Based on the first derivative test, h(x) has a relative minimum at x = -2 and a relative maximum at x = 0.

b)  For x = -2: h''(-2) = 6(-2) + 6 = -6 < 0, so h(x) has a relative maximum at x = -2.

For x = 0: h''(0) = 6(0) + 6 = 6 > 0, so h(x) has a relative minimum at x = 0.

Calculus is a branch of mathematics that deals with the study of rates of change, accumulation, and the properties and behavior of functions.

(a) First derivative test:

The first derivative test involves finding the critical points of the function, where the first derivative is equal to zero or undefined, and then checking the sign of the first derivative in the intervals between the critical points to determine whether the function has relative extrema at those points.

Find the first derivative of h(x):

h'(x) = 3x² + 6x

Set h'(x) = 0 and solve for x to find the critical points:

3x² + 6x = 0

x(x + 2) = 0

x = 0 or x = -2

Test the intervals between the critical points using the sign of the first derivative:

For x < -2: Choose x = -3, h'(-3) = 27 + (-18) = 9 > 0, so h(x) is increasing.

For -2 < x < 0: Choose x = -1, h'(-1) = 3 - 6 = -3 < 0, so h(x) is decreasing.

For x > 0: Choose x = 1, h'(1) = 3 + 6 = 9 > 0, so h(x) is increasing.

Based on the first derivative test, h(x) has a relative minimum at x = -2 and a relative maximum at x = 0.

(b) Second derivative test:

The second derivative test involves finding the critical points of the function using the first derivative, and then checking the sign of the second derivative at those points to determine whether the function has relative extrema at those points.

Find the second derivative of h(x):

h''(x) = 6x + 6

Evaluate the second derivative at the critical points found in step 2 of the first derivative test:

For x = -2: h''(-2) = 6(-2) + 6 = -6 < 0, so h(x) has a relative maximum at x = -2.

For x = 0: h''(0) = 6(0) + 6 = 6 > 0, so h(x) has a relative minimum at x = 0.

Hence, the ease of a test may vary for different individuals and their familiarity with calculus concepts.

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