Limiting and Excess Reactants POGIL (Extension Questions)

This indicates that the system's energy drops while the energy of the environment grows. As a result, the ultimate temperature is projected to be greater than the beginning temperature of 28 degrees Celsius.

The process sends heat into the environment since it is exothermic. The heat produced by the reaction is transferred to the surrounding environment, raising the temperature.

This is due to the fundamental rule of thermodynamics, which states that energy cannot be created or destroyed, but only moved from one form to another. In this case, the energy released by the reaction is transferred to the surrounding environment as heat energy, causing the temperature to rise.

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A few errors about hydrogen peroxide's breakdown can be found throughout the discourse. Instead of being destroyed, the product is transformed into water and oxygen.

Catalase enzymes are found in both plants and animals, and they catalyse the conversion of hydrogen peroxide into water and oxygen. Water and oxygen are naturally formed from hydrogen peroxide, although the process is extremely slow.

Time how long it takes a disc of filter paper to rise a specified distance in a test tube containing hydrogen peroxide solution as one method of determining the rate.

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The volume of the gold sample containing 1.77x10¹⁹ electrons is approximately 2.51 × 10⁻¹⁸ cm³. This was determined by calculating the mass of the sample first, which was 1.2212 grams, and then using the density of gold to determine the volume.

Assuming that the gold sample is electrically neutral, the number of electrons is equal to the number of protons, which is also the atomic number of gold. Therefore, we can determine the mass of the sample using the atomic weight of gold (196.97 g/mol) and Avogadro's number (6.022 × 10²³ particles/mol):

1.77 × 10¹⁹ electrons x (1 atom Au / 79 electrons) x (196.97 g / 1 mol) x (1 mol / 6.022 × 10²³ atoms) = 4.85 × 10⁻¹⁷ g

Next, we can use the density of gold (19.3 g/cm³) to calculate the volume of the sample:

4.85 × 10 g x (1 cm³ / 19.3 g) = 2.51 × 10⁻¹⁸ cm³

Therefore, the volume of the sample of gold is 2.51 × 10⁻¹⁸ cm³.

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In a 23.5 mol sample of C₇H₅N₃O₆, there are 6.87 moles of nitrogen atoms and 8.79 moles of oxygen atoms.

In order to determine the number of moles of nitrogen and oxygen atoms in a 23.5 mol sample of C₇H₅N₃O₆, we first need to look at the chemical formula for this compound.

From the formula, we can see that there are 7 nitrogen atoms and 9 oxygen atoms present in each molecule of C₇H₅N₃O₆.

To calculate the number of moles of nitrogen atoms, we multiply the total number of moles by the mole fraction of nitrogen in the compound:

Moles of nitrogen = 23.5 mol x (7 nitrogen atoms / 24 total atoms)
Moles of nitrogen = 6.87 mol

Similarly, to calculate the number of moles of oxygen atoms, we use the mole fraction of oxygen in the compound:

Moles of oxygen = 23.5 mol x (9 oxygen atoms / 24 total atoms)
Moles of oxygen = 8.79 mol

Therefore, there are approximately 6.87 moles of nitrogen atoms and 8.79 moles of oxygen atoms in a 23.5 mol sample of C₇H₅N₃O₆.

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The heat released in the formation of 1.99 grams of sodium hydroxide is -9.60 kJ.

The given equation shows that the formation of 2 moles of NaOH releases 215.76 kJ of heat. Therefore, the formation of 1 mole of NaOH releases 107.88 kJ of heat. To calculate the heat released in the formation of 1.99 grams of NaOH, we need to first convert the given mass into moles. The molar mass of NaOH is 40 g/mol, so 1.99 grams of NaOH is equal to 0.04975 moles.

Now we can use the following formula to calculate the heat released:

Therefore, the heat released in the formation of 1.99 grams of NaOH is -5.37 kJ. However, since the reaction gives off heat, the answer should be reported as a positive value. Therefore, the final answer is 9.60 kJ.

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The balanced chemical equation for the reaction between a weak acid, HClO₂, and a strong base, Ba(OH)₂, is:

2 HClO₂(aq) + Ba(OH)₂(aq) → Ba(ClO₂)₂(aq) + 2 H₂O(l)

The balanced chemical equation for the reaction between a weak acid, HClO₂, and a strong base, Ba(OH)₂, is:

2 HClO₂(aq) + Ba(OH)₂(aq) → Ba(ClO₂)₂(aq) + 2 H₂O(l)

In this reaction, the Ba(OH)₂ dissociates completely into Ba²⁺ and 2 OH⁻ ions in solution. The HClO₂ is a weak acid and therefore only partially dissociates into H⁺ and ClO₂⁻ ions in solution. The reaction between these ions forms Ba(ClO₂)₂, a salt, and water.
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The correct matches are:

1.A chemical bond between atoms with similar electronegativities - covalent bond

2. a measure of the ability of an atom to attract electrons within a chemical bond - Electronegativity

3. a bond between atoms of greatly differing electronegativities - Ionic bond

4. the bond formed in metals, holding metals together - Metallic bond

A covalent bond is a bond formed by sharing electrons between two atoms that occur in the bond. It generally forms between atoms with similar electronegativity values.

An ionic bond is a bond formed between two oppositely charged ions of her and held by strong electrostatic attraction. It forms between atoms that have vastly different electronegativities.

Electronegativity is the tendency of an atom in a covalent bond to attract a shared pair of electrons.

A metallic bond is a bond formed by electrostatic attraction between a positively charged metal ion and a conduction electron.

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Answer:

Sharing bond: Covalent

Tendency to attract electrons: Electronegativity

Stable electron configurations: Inert gas

Transferred electrons bond: Ionic

The mass of CO2 produced is 20.9 g

The formula of the limiting reactant is O2

The reactant that produces the smallest amount of product is the limiting reactant.

Number of moles of glucose = 9.91 g/180 g/mol

= 0.055 moles

Number of moles of oxygen = 15.2 g/32 g/mol= 0.475 moles

1 mole of glucose reacts with 6 moles of oxygen

0.055 moles of glucose reacts with 0.055 * 6/1

= 0.33 moles

Thus oxygen is the limiting reactant

Mass of CO2 produced = 0.475 moles * 44 g/mol

= 20.9 g

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The combustion of 5 pounds of glyceryl trioleate would release 137,181 kJ of energy in the form of heat, which is equivalent to 137.181 nutritional calories.

The balanced thermochemical equation for the metabolism of glyceryl trioleate is:

To get rid of 5 pounds of glyceryl trioleate by combustion, we need to calculate the number of moles of the fat, which is:

Then, we can calculate the amount of energy released by combustion:

To convert this to nutritional calories, we divide by 1,000:

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According to the question Given Name: 2-methylbutane IUPAC Name: 2-methylbutane Structure: [tex]CH_3CH_2CH(CH_3)CH_3.[/tex]

Structure is the arrangement or organization of parts or elements in a material, system, or entity. It is essential in understanding how something is composed and how it functions. Examples of structures include the skeletal system of the human body, the structure of a computer program, the structure of a book, or the structure of a business. Structures can be physical or abstract, and are usually determined by the purpose of the material, system, or entity. For example, a bridge is a physical structure designed to support the movement of people, goods, and vehicles across a body of water. A book is an example of an abstract structure, with a specific beginning, middle, and end. The structure of a business might include the organizational hierarchy, the roles and responsibilities of each employee, and the different departments. Knowing the structure of something can help people understand how it works and how to interact with it.

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The types of chemical bonds present in a material determine the arrangement of atoms or molecules at the microscopic level, which in turn determines the properties of the material at the macroscopic level.

For example, materials with ionic bonds tend to have high melting and boiling points due to the strong electrostatic attraction between positively and negatively charged ions. Covalently bonded materials tend to have lower melting and boiling points due to the weaker intermolecular forces between molecules.

Metallic bonding leads to high electrical and thermal conductivity due to the delocalization of electrons within the metal lattice. These different bond types and resulting material properties are important in understanding the behavior and applications of different materials.

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Ethyl 4-aminobenzoate is likely to dissolve in 3 M HCl as it is a base and can react with the acid to form a salt, which is soluble in water.

The three aromatic compounds are ethyl 4-aminobenzoate, 2-nitrotoluene, and 1,3,5-trimethylbenzene. When these solids are placed in 3 M HCl, only the compound with basic properties (ethyl 4-aminobenzoate) is likely to dissolve. This is because HCl is a strong acid that dissociates completely in water to produce H+ ions.

When HCl is added to a basic compound like ethyl 4-aminobenzoate, the H+ ions react with the lone pair of electrons on the nitrogen atom of the amine group, neutralizing the basicity of the compound and producing a water-soluble salt. On the other hand, the other two compounds, which are not basic, will not react with HCl and will not dissolve in the acidic solution. Therefore, ethyl 4-aminobenzoate is the most likely compound to dissolve in 3 M HCl.

The complete question is
If a solid mixture of the three aromatic compounds shown below is placed in 3 m hcl, which is likely to dissolve?

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Materials that slow down or impede the transmission of heat through them are called insulators. So the correct answer is the option: a.

They can be used for a multitude of purposes, from keeping cold drinks icy to keeping buildings warm in the winter, thanks to this ability. Insulators function by either using materials with low thermal conductivity or by creating air pockets between the materials. This slows the rate of heat flow by reducing the transmission of heat energy from one side to the other. Insulators are valuable in electrical applications because they can stop electrical current from passing through them. Option: a is correct.

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--The complete Question is, These are materials that heat passes slowly or not at all

a. Insulators

b. Fuel

c. Sun

d. Conductors

e. Heat --

When working with a heat source, one should always assume that glassware and metal objects are hot. Option A is correct.

Working with a heat source requires special precautions to ensure safety in the laboratory. Heat sources such as Bunsen burners, hot plates, and ovens can generate high temperatures that can cause burns or fires if not handled properly. One important safety rule when working with a heat source is to assume that glassware and metal objects are hot.

This means that one should avoid touching or handling these objects without protective equipment, even if they appear to be cool or inactive. This is because they may still be hot from exposure to the heat source and can cause burns or injuries. Other safety measures when working with a heat source include using appropriate personal protective equipment, such as heat-resistant gloves and safety goggles, and ensuring good ventilation in the laboratory to prevent exposure to fumes or volatile chemicals. Option A is correct.

What should you do when working with a heat source?

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T1 is the initial temperature (35 °C), P2 is the new pressure, and T2 is the new temperature (120 °C). P2 is 6.86 atm.

Temperature is the measure of the average kinetic energy of particles in a substance. It is usually measured in degrees Celsius (°C), Kelvin (K), or Fahrenheit (°F). Temperature can also be described as the degree of hotness or coldness of a substance. Temperature has an effect on the state of matter of a substance, and can cause substances to change state by melting, freezing, vaporizing, or condensing.

The pressure of a gas is directly proportional to its temperature. This means that, when the temperature of the gas increases, its pressure will also increase.
Using the ideal gas law, we can calculate the new pressure of the gas at 120 °C:
P1/T1 = P2/T2
Where P1 is the initial pressure (0.200 atm), T1 is the initial temperature (35 °C), P2 is the new pressure, and T2 is the new temperature (120 °C).
P2 = (0.200 atm x 120 °C) / 35 °C
P2 = 6.86 atm.

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The molar mass of lithium sulfate (Li2SO4) is:

Li2SO4 = 2 x Li + 1 x S + 4 x O = 2(6.94 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 109.94 g/mol

To find the number of moles of lithium sulfate, we need to first find the number of moles of lithium in the sample:

2.94 x 10^23 atoms of Li x (1 mole of Li/6.022 x 10^23 atoms of Li) = 0.488 moles of Li

Since there are two moles of lithium for every one mole of lithium sulfate, the number of moles of lithium sulfate in the sample is:

0.488 moles of Li x (1 mole of Li2SO4/2 moles of Li) = 0.244 moles of Li2SO4

Therefore, the sample contains 0.244 moles of lithium sulfate.

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The ionization energy of the ground-state Li atom can be calculated using the given spectral lines and theyhko l.

Here are the steps:

1. Identify the transition wavelengths: 610.36 nm (transition 1), 460.29 nm (transition 2), 413.23 nm (transition 3), and 670.78 nm (transition 4).
2. Convert wavelengths to frequencies using the formula: frequency = speed of light / wavelength. Use c = 3 x 10^8 m/s and convert wavelengths to meters.
3. Calculate the energy of each transition using the formula: energy = h * frequency, where h is Planck's constant (6.626 x 10^-34 Js).
4. Determine the difference in energy between each transition and the transition from the 2P to 2S term (transition 4).
5. The ionization energy corresponds to the smallest energy difference between the transitions and the ground-state transition (transition 4).

By following these steps, you can calculate the ionization energy of the ground-state Li atom.

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4.28 moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia.

To find out how many moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia, we can use the balanced chemical equation: 4NH3 + 3O2 → 2N2 + 6H2O.

Step 1: Identify the mole ratio between ammonia (NH3) and nitrogen gas (N2). From the balanced equation, we see that 4 moles of NH3 produce 2 moles of N2. This gives us a mole ratio of 4:2 or 2:1.

Step 2: Use the mole ratio to determine the moles of nitrogen gas produced. Since the mole ratio is 2:1, for every 2 moles of NH3 that react, 1 mole of N2 is produced.

Step 3: Calculate the moles of nitrogen gas generated from 8.56 moles of ammonia. Divide the given moles of ammonia by the mole ratio:
8.56 moles NH3 / 2 = 4.28 moles N2

Therefore, 4.28 moles of nitrogen gas are generated by the complete reaction of 8.56 moles of ammonia.

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The concentration of the solution is 0.748 M.

To find the concentration of the solution, we need to calculate the number of moles of calcium carbonate present in the solution.

First, we need to determine the molecular weight of calcium carbonate ([tex]CaCO3[/tex]).

[tex]CaCO3[/tex] = 1 x Ca + 1 x C + 3 x O

= 40.08 g/mol + 12.01 g/mol + (3 x 16.00 g/mol)

= 100.09 g/mol

Next, we can use the formula:

concentration (in mol/L) = moles of solute / volume of solution (in L)

We have 37.5 grams of calcium carbonate in 500 ml of water. To convert ml to L, we divide by 1000:

volume of solution = 500 ml / 1000 ml/L = 0.5 L

moles of calcium carbonate = mass / molecular weight

= 37.5 g / 100.09 g/mol

= 0.374 moles

Therefore, the concentration of the solution is:

concentration = 0.374 moles / 0.5 L

= 0.748 M

The concentration of the solution is 0.748 M.

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Answer:

7.3

Explanation:

The actual yield was 1.329 g Ag.

The balanced equation for the reaction between Zinc and Silver Nitrate is:

Zn + 2AgNO₃ -> 2Ag + Zn(NO₃)₂.

Given: 29 g Zn, and 2 g AgNO₃. Molar masses: Zn = 65 g/mol, AgNO₃ = 169.87 g/mol.

Moles Zn = 29/65 = 0.446 mol

Moles AgNO₃ = 2/169.87 = 0.0118 mol

Since the stoichiometric ratio is 1:2 (Zn:AgNO₃), we need 0.223 mol AgNO₃ for a complete reaction.

We have only 0.0118 mol AgNO₃, making it the limiting reagent.

Theoretical yield of Ag: 2 mol Ag produced from 1 mol AgNO₃.

0.0118 mol AgNO₃ * (2 mol Ag / 1 mol AgNO₃) * 108 g/mol (Ag's molar mass) = 2.54 g Ag

The actual yield was 1.329 g Ag.

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The discrepancy gap between customer expectations and perceptions towards service quality of front office staff/night auditor is commonly referred to as the "service gap."

This gap arises when customers have certain expectations regarding the level of service they will receive, but their actual perceptions of the service fall short of those expectations.

The service gap can be caused by a variety of factors, including inadequate training of front office staff, poor communication between staff and customers, inconsistencies in service delivery, and failure to meet customer needs and preferences.

To reduce the service gap, it is important for organizations to have a clear understanding of customer expectations and to ensure that their service delivery meets or exceeds those expectations.

This may involve implementing better training programs for front office staff, improving communication with customers, and implementing systems for monitoring and measuring customer satisfaction.

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Delta Hfusion is a term used in thermodynamics to refer to the amount of energy that is required to convert a substance from its solid state to its liquid state, or vice versa, at a constant pressure. This energy is typically expressed in terms of Joules per unit mass, such as J/g or kJ/kg.

To calculate the volume of liquid that is frozen, we first need to determine the amount of mass that is required to produce 1 kJ of energy. This can be calculated using the equation:
q = m * Delta Hfusion

where q is the amount of energy produced (in J), m is the mass of the substance being frozen (in kg), and Delta Hfusion is the amount of energy required to freeze the substance (in J/kg). Rearranging this equation to solve for m, we get:

m = q / Delta Hfusion

Substituting the values of q = 1 kJ and Delta Hfusion (which is a known value for the substance being frozen), we can calculate the mass of the substance required to produce 1 kJ of energy. Once we know the mass, we can use the density of the substance to calculate the volume of liquid that is frozen.

For example, let's say we are trying to freeze water to produce 1 kJ of energy. The Delta Hfusion of water is 333.6 kJ/kg. Using the equation above, we can calculate the mass of water required to produce 1 kJ of energy:

m = (1 kJ) / (333.6 kJ/kg) = 0.003 kg
Next, we can use the density of water (which is approximately 1000 kg/m^3) to calculate the volume of water that is frozen:
Volume = mass / density = 0.003 kg / 1000 kg/m^3 = 0.000003 m^3

So, the volume of water that is frozen to produce 1 kJ of energy is approximately 0.000003 cubic meters, or 3 milliliters.In summary, we can use the Delta Hfusion of a substance, along with its density, to calculate the volume of liquid that is frozen to produce a certain amount of energy.

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When you measure current, you are measuring the number of: c. Electrons that pass a point in one second.

When measuring current, you are measuring the number of electrons that pass a point in one second.

Current is defined as the flow of electric charge, which is typically the flow of electrons through a conducting material. The unit of current is the ampere (A), which is defined as the flow of one coulomb of charge per second.

In a circuit, current flows from the negative terminal of the battery (where electrons are pushed out) to the positive terminal (where electrons are absorbed). The amount of current in a circuit is determined by the voltage applied (potential difference) and the resistance of the circuit, according to Ohm's Law (I = V/R).

Therefore, measuring current is a way of quantifying the amount of electric charge that is flowing through a circuit per unit time, and it is directly related to the movement of electrons in the circuit.

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Polonium is a rare and radioactive element that belongs to the group of chalcogens. The coordination number of polonium in a simple cubic lattice is 8.

It is known to crystallize in the simple cubic lattice structure, which is one of the three basic types of crystal lattice structures. In this structure, each polonium atom is located at the corner of a cube, sharing its electrons equally with its neighboring atoms.

The coordination number of an atom in a crystal lattice is the number of nearest neighbor atoms to which it is bonded. In the case of polonium, since each atom is located at the corner of a cube, it is in contact with eight other atoms, which are located at the corners of the adjacent cubes.

The knowledge of the crystal structure and coordination number of polonium is important for understanding its physical and chemical properties, and can also have implications in the fields of materials science, nuclear physics, and medical applications.

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To find the density of ammonia (NH3) at 646 torr and 10°C, we need to use the Ideal gas law equation:

PV = nRT

Where R is the gas constant, n is the number of moles, P is pressure, V is volume, and T is temperature in Kelvin.

We must first change the pressure from torr to atm:

646 torr = 0.852 atm

The temperature is then changed from Celsius to Kelvin:

10°C + 273.15 = 283.15 K

Now, we can rearrange the ideal gas law equation to solve for density (d):

d = (PM) / (RT)

M is the ammonia's molar mass.

With the supplied values and constants, we obtain:

d = (0.852 atm)(17.04 g/mol) / ((0.0821 atm*L)/(mol*K))(283.15 K)

d = 0.736 g/L

Therefore, the density of ammonia at 646 torr and 10°C is 0.736 g/L.

What do you mean by density of ammonia?

The density of ammonia refers to the mass of ammonia gas per unit volume. The standard temperature and pressure (STP), which is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals or 760 millimeters of mercury), is used to measure the density of ammonia, a colorless gas that is lighter than air.

At STP, the density of ammonia gas is approximately 0.771 grams per liter (g/L) or 0.771 kilograms per cubic meter (kg/m3). However, the density of ammonia can vary depending on the temperature, pressure, and other factors such as the presence of impurities or moisture.

The density of ammonia is an important property in many applications, particularly in the chemical industry. It is used to calculate the amount of ammonia needed for a particular reaction or process, and can also be used to determine the mass or volume of ammonia gas in a storage tank or container.

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4666.7 m of sulphur dioxide are formed when 12.5g of iron sulphide ore (pyrite) reacts with oxygen according to the equation at stp.

According to given data,   12.5 g of iron sulphide ore (Pyrite ) reacts with oxygen according to the equation at STP.

We have to find the volume of sulphur dioxide

Mass of iron sulphide = 12.5 g

molar mass of iron sulphide = 120 g/mol

so number of moles of iron sulphide = 12.5/120 = 0.104167 mol

chemical equation of reaction of iron sulphide with oxygen is given as

4FeS₂ + 11O₂ ⇒2Fe₂O₃ + 8SO₂

here  4 mol of FeS₂ gives 8 mole of sulphur dioxide.

⇒1 mol of FeS₂ = 8/4 mol = 2 mol of sulphur dioxide.

⇒0.104167 of FeS₂ = 2 × 0.104167 = 0.208334 mol of Sulphur dioxide.

at STP 1 mol = 22.4 L

so the mass of sulphur dioxide

= 0.208334 × 22.4 L

= 4.6666816 L

= 4666.6816 ml

≈ 4666.7 ml

Therefore the volume of sulphur dioxide is 4666.7 ml.

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Beer's law establishes a connection between a substance's concentration in a solution and its absorbance at a certain wavelength.

By charting the absorbance vs concentration of each solution, a Beer's law plot is created in order to calculate concentrations of a series of copper(II) sulfate solutions with known absorbances at a set wavelength. The resulting graph should be a straight line that the least-squares approach can fit with a linear equation. The molar absorptivity is represented by slope of the best-fit line, and the absorbance at zero concentration is represented by the y-intercept. By measuring the absorbance of the unknown copper(II) sulfate solutions and solving for concentration using the equation, the concentrations of unknown solutions can be found.

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--The complete Question is, Use Beer's law plot and best-fit line to determine the concentrations for a series of copper(II) sulfate solutions with known absorbances at a fixed wavelength. --

175.17 grams of CaCO₃ are produced when 98.2 grams of CaO are reacted with an excess of CO₂ according to the given equation.

To solve this problem, we need to use stoichiometry which deals with the quantitative relationships between reactants and products in chemical reactions.

The balanced chemical equation for the reaction is:

CaO + CO₂ → CaCO₃

This equation tells us that for every 1 mole of CaO and 1 mole of CO₂ that react, we get 1 mole of CaCO₃.

We are given the mass of CaO that is used in the reaction. To calculate the mass of CaCO₃ that is produced, we need to use stoichiometry and the molar mass of CaCO₃.

The molar mass of CaCO₃ is the sum of the atomic masses of one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O). Using the values from the periodic table, we can calculate the molar mass of CaCO₃ as:

molar mass of CaCO₃ = 1 × atomic mass of Ca + 1 × atomic mass of C + 3 × atomic mass of O

                                    = 1 × 40.08 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol

                                    = 100.09 g/mol

To calculate the number of moles of CaO that reacted, we can use the following equation:

n = m/M

where n is the number of moles of CaO, m is the mass of CaO, and M is the molar mass of CaO.

Using the given values, we get:

n = 98.2 g / 56.08 g/mol = 1.749 mol

This is the number of moles of CaO that reacted in the reaction.

Since the reaction is 1:1, meaning that one mole of CaO reacts with one mole of CO₂ to produce one mole of CaCO₃, we know that the number of moles of CaCO₃ produced is also 1.749 mol.

Finally, to calculate the mass of CaCO₃ produced, we can use the following equation:

m = n × M

where m is the mass of CaCO₃ produced, n is the number of moles of CaCO₃ produced, and M is the molar mass of CaCO₃.

Using the given values, we get:

m = 1.749 mol × 100.09 g/mol = 175.17 g

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The rate of appearance of [tex]NO_{2}[/tex] is 8.4 x [tex]10^{-7}[/tex] m/s and the rate of appearance of [tex]O_{2}[/tex] is 2.1 x [tex]10^{-7}[/tex] m/s.

Given the reaction: 2[tex]N_{2}O_{5}[/tex](g) → 4[tex]NO_{2}[/tex](g) + [tex]O_{2}[/tex](g)

The rate of decomposition of [tex]N_{2}O_{5}[/tex] is 4.2 x [tex]10^{-7}[/tex] m/s.

a) To find the rate of appearance of [tex]NO_{2}[/tex], we will look at the stoichiometric coefficients in the balanced reaction. For every 2 moles of [tex]N_{2}O_{5}[/tex] decomposed, 4 moles of [tex]NO_{2}[/tex] are produced. So, the ratio is 4:2, which simplifies to 2:1.

Rate of appearance of [tex]NO_{2}[/tex] = (Rate of decomposition of [tex]N_{2}O_{5}[/tex]) x (2/1)
Rate of appearance of [tex]NO_{2}[/tex] = (4.2 x [tex]10^{-7}[/tex] m/s) x 2
Rate of appearance of [tex]NO_{2}[/tex] = 8.4 x [tex]10^{-7}[/tex] m/s

b) For the rate of appearance of [tex]O_{2}[/tex], we will again look at the stoichiometric coefficients. For every 2 moles of [tex]N_{2}O_{5}[/tex] decomposed, 1 mole of [tex]O_{2}[/tex] is produced. The ratio is 1:2.

Rate of appearance of [tex]O_{2}[/tex] = (Rate of decomposition of [tex]N_{2}O_{5}[/tex] ) x (1/2)
Rate of appearance of [tex]O_{2}[/tex] = (4.2 x [tex]10^{-7}[/tex] m/s) x 1/2
Rate of appearance of [tex]O_{2}[/tex] = 2.1 x [tex]10^{-7}[/tex] m/s

Thus, the rate of appearance of [tex]NO_{2}[/tex] is 8.4 x [tex]10^{-7}[/tex] m/s and the rate of appearance of [tex]O_{2}[/tex] is 2.1 x [tex]10^{-7}[/tex] m/s.

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