limit x->oo (sqrt(x^2-9x+1)-x)=?

I solved it up until -9x+1/((√x^2-9x+1)+x) but I don't know what to do after this.

1. To find the interest we will use = (D6*D5) - B8,  2. To find the total cost we will use = B6 + D7.

Here we are given the financial information of a firm and are required to give an appropriate formula for total interest and total cost

1.

Here we need to multiply D6 and D7 and subtract B8 from the result. We cannot use any function. Hence we will simply write

= (D6*D5) - B8

The bracket is not necessary but can be put s an added satisfaction that the said formula would multiply the cells first and then only will the loan amount would be subtracted.

2.

Similarly, for cell D8, we need to go to the formula bar and write

= B6 + D7

This will add the cells up to give us the total cost.

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Complete Question

(Image Attached)

T(-1, 7)

→

T′(-1, -7)

U(-1, 8)

→

U′(-1, -8)

V(9, 6)

→

V′(9, -6)

Answer:

Step-by-step explanation:  find the circumference and then consider the shape (circle) after that get rid of options that don't make sense like 7.3 and 7.1, 8 for the radius might be too big leaving you with    7     (use a calculator if needed)

Answer:

Step-by-step explanation:

The students cannot construct any triangles with the given side lengths because the sum of the two shorter sides of a triangle must always be greater than the longest side (i.e., the triangle inequality). However, in this case, 3 + 4 = 7, which is less than 8. Therefore, it is not possible to construct a triangle with sides of length 3, 4, and 8 inches.

So, the correct option is A - "They cannot construct any triangles with the given side lengths."

globe meaning a sphere, and since it has a diameter of 25.8, that means its radius is half that, or 12.9

[tex]\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12.9 \end{cases}\implies V=\cfrac{4\pi (12.9)^3}{3}\implies \stackrel{ using~\pi =3.14 }{V\approx 8987.47}[/tex]

The given angles are 7π/4, 10π/3 & 510°.

Calculations for 7π/4(4th Quadarant)

sin(7π/4) = -1/√2

cos(7π/4) = 1/√2

tan(7π/4) = -1

cosec(7π/4) = -√2

cot(7π/4) = -1

sec(7π/4) = √2

Calculations for 10π/3(3rd Quadarant)

sin( 10π/3) = -√3/2

cos(10π/3) = -1/2

tan(10π/3) = √3

cosec(10π/3) = - 2/√3

cot(10π/3) = 1/√3

sec(10π/3) = -2

Calculations for 510°(2nd Quadarant)

sin( 510°) = 1/2

cos(510°) = -√3/2

tan(510°) = -1/√3

cosec(510°) = 2

cot(510°) = -√3

sec(510°) = -2/√3

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Next, using the matching x and y values for each row of the table, we can place a point for each row and connect it to the other points using a line.

A line represents a one-dimensional straight figure that can go on forever in both directions in geometry. To separate it from a curved or an angle-filled line, it is frequently referred to as a "straight line." Two points on a line define the line, while every other position on the line may be discovered by tracing the line through the two defined points. A line can be made with a pencils or another non-thick tool, and it can have any width or depth. Shape and figures are described and analysed using lines, which are a basic building block of geometry.

given

Minutes Taught Dollars Earned (30, 12, 60, 24)

90 36

120 48

We may plot the minutes taught on the x-axis and the money made on the y-axis to graph the data from the table.

Next, using the matching x and y values for each row of the table, we can place a point for each row and connect it to the other points using a line.

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a) There are 2 x 2 = 4 sample points in the sample space

b) Tree Diagram

O D.\nH\nHe\nT\nH\nT\n

Sample space: D. HH, HT, TH, TT

c) P(no tails) = P(HH)

= 1/4

d) P(exactly one tail) = P(HT, TH)

= 2/4

= 1/2

e) P(2 tails) = P(TT)

= 1/4

f) P(at least one tail) = P(HT, TH, TT)

= 3/4

In mathematics, tree diagrams are often used in probability and statistics to show all the possible outcomes of an event. In computer science, they are used to represent the hierarchical structure of files and directories in a file system

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Answer:

1

Step-by-step explanation:

7+10+1/5

7/10 = 0.7

1/5 = 0.2

0.7+0.2=0.9

Therefore it would be closest to 1.

Answer: 1

Step-by-step explanation:

To find an estimate, you need to round your fractions. Let's start with 7/10. First let's look at the numerator, 7. 7 is a number greater than 5, so we'll round it to 10 and you keep your denominator. so now we have 10/10, or 1. Then round 1/5. 1/5 is lower than 5, so we'll round it to 0. Now, for the final step add them. 1 + 0 = 1, so 1 is the answer

Answer:

B. $7.50

Step-by-step explanation:

We know profit or P-----P(n) where n is the quantity/number of the item) is the difference of the revenue-----R(n)-----and the cost-----C(n)

P(n) = R(n) - C(n)

Revenue is

R(n) = pn

Cost is a combination of

The cost function resembles a linear equation:

C(n) = mn + c

Since we're shown that P = 7.5n - (2.25n + 15), we know that R(n) must be R(n) = 7.5n and C(n) must be C(n) = 2.25n + 15

Thus, we know she charges $7.5 per necklace sold.

The dimensions of each rectangle are x by (x- y) and y by (x - y); option A and D

The area of each rectangle is x² - 2xy + y²  and x² - xy

The total area of the remaining figure is 2x² - 4xy + 2y²

This figure represents the difference of two squares in that x² - y² = (x + y)(x -y)

The area of each rectangle is:

x * (x- y) =  x² -xy

and

y * (x - y) = xy - y²

The total area of the remaining figure is:

x² -xy + xy - y² = x² - y²

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The values of m and b after evaluation is -2 and 23 under the condition that If x=3t+t² and y=7−2t, and  tangent to the curve at t=2.

In orde to evaluate the equation of the tangent to the curve at t=2, we have to calculate the slope of the curve at t=2.
The slope of the curve at t=2 is presented by the derivative of y with respect to x at t=2.
y = 7 - 2t
x = 3t + t²
dy/dx = -2
Then, the slope of the tangent to the curve at t=2 is -2.
Now we have to evaluate the point on the curve at t=2.
x = 3(2) + (2)² = 10
y = 7 - 2(2) = 3
So, the point on the curve at t=2 is (10,3).
Applying  point-slope form of equation of line:
y - y₁ = m(x -x₁)
Here,
m = slope and (x₁,y1) is a point on the line.
Staging m=-2 and (x₁,y₁)=(10,3),
y - 3 = -2(x - 10)
Applying simplification
y = -2x + 23
Then, the equation of the tangent to the curve at t=2 is y=-2x+23.
So, m=-2 and b=23.
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A linear function would best fit the data because as x increases, the y values change by an approximate constant. The rate of change of this function is approximately 8950 people a year.

To determine which type of function best fits the data, we can analyze the difference in the y values (Estimated Population) as x increases.

Differences between consecutive y values:

58,207 - 49,372 = 8,835

66,998 - 58,207 = 8,791

75,798 - 66,998 = 8,800

The differences between consecutive y values are relatively constant as x increases. This suggests that a linear function would be more appropriate than an exponential function

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Answer:

$270:$30

Step-by-step explanation:

add up the ratios = 10

then do 300/10 = 30

so 1 ratio = 30

this means the ratio will be: $270:$30

Let me know if this helped

Let's start by setting up a proportion to represent the ratio of Illinois students to Michigan students:

Illinois students / Michigan students = 6/5

We can simplify this proportion by multiplying both sides by 5:

Illinois students = 6/5 * Michigan students

Next, we can use the information in the table to set up an equation that relates the number of Illinois students, Michigan students, and Indiana students:

Illinois students + Michigan students + Indiana students = 175

We can substitute the expression we obtained for the number of Illinois students into this equation:

6/5 * Michigan students + Michigan students + Indiana students = 175

Multiplying both sides by 5 to eliminate the fraction, we get:

6 * Michigan students + 5 * Michigan students + 5 * Indiana students = 875

Combining like terms, we get:

11 * Michigan students + 5 * Indiana students = 875

Now we can use the fact that the ratio of Illinois students to Michigan students is 6:5 to set up another equation:

Illinois students / Michigan students = 6/5

Substituting the values from the table, we get:

Illinois students / Michigan students = 24/20

Cross-multiplying, we get:

Illinois students * 20 = Michigan students * 24

Simplifying, we get:

Illinois students = 6/5 * Michigan students = 24/20 * Michigan students = 6/5 * 24 Michigan students = 28.8 Michigan students

Since the number of students must be a whole number, we can round 28.8 up to 29. This means that there were 29 Michigan students.

Substituting this into the equation we obtained earlier, we get:

11 * 29 + 5 * Indiana students = 875

Solving for Indiana students, we get:

5 * Indiana students = 875 - 11 * 29 = 546

Dividing both sides by 5, we get:

Indiana students = 546/5 = 109.2

Since the number of students must be a whole number, we can round 109.2 up to 110. This means that there were 110 Indiana students.

Therefore, the answer is 110 students from Indiana.

In a circle, the measure of a central angle is equal to the measure of its intercepted arc. Since ∠RST is a central angle of circle S and its measure is 102 degrees, the measure of its intercepted arc ⌢RT is also 102 degrees.

The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle. Since RS is a radius of circle S and its length is 6 units, the circumference of circle S is C = 2π * 6 = 12π units.

The length of an arc is proportional to its measure in degrees. Since the measure of ⌢RT is 102 degrees and the total measure of a circle is 360 degrees, the length of ⌢RT is (102/360) * 12π = 3.4π units.

Rounded to the nearest hundredth, this is approximately 10.68 units.

Answer:

Step-by-step explanation:

D is the correct answer.

Answer:

D

Step-by-step explanation:

By reading the graph, place the art museum at location (5,5). Then check all the locations to see which statement is true.

A is not true because the art museum is located 4 units east and 1 unit north from the coliseum.

B is not true because the art museum is located 3 units east and 3 units north of the smith's tower.

C is not true because the art museum is located 1 unit east and 2 units north of the state capital.

This is why D is the correct answer.

Therefore , the solution of the given problem of area comes out to be the trapezium has a surface area of 39 square centimetres.

Calculating how much space would be needed for fully covering its exterior will reveal its overall dimensions. The surrounding environment is considered while selecting a comparable product with a rectangular shape. The surface area of anything determines its overall dimensions. The number of sides connecting a cuboid's four trapezoidal shapes determines how much water it can contain.

Here,

We can use the formula for a trapezoid's area if we assume that the shape is a trapezoid with parallel sides that are 9 cm and 4 cm and a height of 6 cm.

=> A = (a + b)h/2

where h is the height, and a and b are the lengths of the parallel sides.

When we enter the values we have, we obtain:

=> A = (9 + 4)(6)/2

=> A = 13(3)

=> A = 39

Consequently, the trapezium has a surface area of 39 square centimetres.

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Therefore, the range of the relation shown is (1, 3, 4, 6, 7). Option C is the correct answer.

In mathematics, a function is a relation between a set of inputs (called the domain) and a set of possible outputs (called the range) with the property that each input is associated with exactly one output. In other words, a function is a rule that assigns a unique output value to each input value. Functions are used to model relationships between variables in many areas of mathematics and other fields such as physics, engineering, economics, and computer science. They are used to describe various phenomena, such as the growth of populations, the trajectory of a projectile, or the behavior of financial markets. Functions are also important tools in calculus, where they are used to study rates of change and continuity, among other things.

Here,

The range of a relation refers to the set of all possible output values or y-values of the relation. Looking at the image reference, we can see that the y-values or the outputs are 1, 3, 4, 6, and 7.

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The equation, for the simple harmonic motion of a particle moving uniformly is s ( t ) = A x cos (ωt).

An object undergoing simple harmonic motion follows a periodic oscillation in a straight line, resembling a sinusoidal curve. Likewise, when an object continuously traverses upon a circle with uniform motion, its projection along the diameter travels back and forth in a simple harmonic motion pattern.

Assuming that the particle commences at the highest point of the simple harmonic motion at time t = 0, either the sine or cosine function is utilized to derive the equation for the simple harmonic motion formula. Thus, let us employ the cosine function in this instance:

s ( t ) = A x cos (ωt)

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The probability of Casey selecting a tie that goes well with the sport coat is 0.517.

The probability of Casey selecting a tie that does not go well with the sport coat is 0.483

The probability of Casey selecting a tie that goes well with the sport coat is:

P(goes well) = 15/29

P(goes well) ≈ 0.517

The probability of Casey selecting a tie that does not go well with the sport coat is:

P(does not go well) = 1 - P(goes well)

P(does not go well) = 1 - 15/29 = 14/29

P(does not go well) ≈ 0.483

The odds in favor of the tie going well with the sport coat are:

P(goes well) : P(does not go well) = 15/29 : 14/29

P(goes well) : P(does not go well) = 15:14

The odds against the tie going well with the sport coat are:

P(does not go well) : P(goes well) = 14/29 : 15/29

P(does not go well) : P(goes well) = 14:15

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Answer:

364 cents or $3.64

Step-by-step explanation:

We can first convert $4 into cents. There are a 100 cents in $1, so there are 400 cents in $4. Now we can subtract.

400 - 36 = 364

Difference is 364 cents or $3.64

The journal entry to record the transaction is given:

Account Debit Credit

Cash $464,000

Common Stock, $3 par value $87,000

Paid-in capital in excess of par  $377,000

A journal entry is used to record a business transaction in the accounting records of a business.

A journal entry is usually recorded in the general ledger. Alternatively, it may be recorded in a subsidiary ledger that is then summarized and rolled forward into the general ledger

Assuming the shares have a $3 par value and sell for $16 cash per share:

Cash reeived from issuance of 29,000 common shares = 29,000 x $16 = $464,000

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The rap about why triangular pyramids are the best shape is given below.

Verse 1:

Listen up, y'all, I'm here to spit some truth

About a shape that's often overlooked, but it's the truth

It's the triangular pyramid, and let me tell you why

It's the best shape out there, and that's no lie

Chorus:

Triangular pyramids, they're the way to go

Strong and sturdy, they're the best, you know

With their pointed tips and angled sides

They're the perfect shape, no need to hide

Verse 2:

When it comes to architecture, they're the top choice

Their shape is so versatile, you can't deny its voice

From ancient pyramids to modern buildings tall

The triangular pyramid can withstand it all

Chorus:

Triangular pyramids, they're the way to go

Strong and sturdy, they're the best, you know

With their pointed tips and angled sides

They're the perfect shape, no need to hide

Verse 3:

And let's not forget their mathematical prowess

Their angles add up to 180, no need to guess

With their faces all congruent, they're a sight to see

The triangular pyramid, it's the shape for me

Chorus:

Triangular pyramids, they're the way to go

Strong and sturdy, they're the best, you know

With their pointed tips and angled sides

They're the perfect shape, no need to hide

Outro:

So there you have it, folks, the triangular pyramid

It's the best shape out there, there's no need to forbid

From its strength to its geometry

The triangular pyramid, it's the shape for me!

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Answer:

A

Step-by-step explanation:

based on summation, this is an integral from 1 to 6

answer choice A makes sense since plugging in K value gives appropriate riemann sum

Using the tangent ratio, the value of x in the right triangle shown is calculated to the nearest tenth as: 2.6  units.

The tangent ratio is part of the trigonometry ratios that is applied when solving a right triangle, and it is expressed as:

tan ∅ = length of the opposite side / length of the adjacent side.

We are given the following information from the image above:

Reference angle (∅) = 43 degrees

length of the opposite side = x

length of the adjacent side = 2.8

Plug in the values:

tan 43 = x/2.8

2.8 * tan 43 = x

x = 2.6 [to the nearest tenth]

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The value of the "trigonometric-expressions' are :

(a) tan(5π/2) is undefined,

(b) sec(315°) is √2.

Part(a) : The expression "tan(5π/2)" is undefined because the tangent function is undefined at odd multiples of π/2, which includes 5π/2.

Part(b) : To find the value of sec(315°), we use the identity: sec(θ) = 1/cos(θ),

First, we convert 315° to radians:

Which is : 315° = (7π/4) radians;

Next, we find the value of cos(7π/4):

⇒ cos(7π/4) = cos(π/4) = (√2)/2;

Finally, we substitute in the identity for sec(θ);

So, Sec(7π/4) = 1/cos(7π/4) = 1/[(√2)/2] = √2.

Therefore, value of sec(315°) is √2.

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The given question is incomplete, the complete question is

Find the value of the trigonometric expressions :

(a) tan(5π/2)

(b) sec(315°)

The distance between the installations is given as follows:

126.42 miles.

The Law of Cosines is a trigonometric formula that relates the lengths of the sides of a triangle to the cosine of one of its angles. It is also known as the Cosine Rule.

The Law of Cosines states that for any triangle with sides a, b, and c and angle B opposite to side b, the following equation holds true:

b^2 = a^2 + c^2 - 2ac cos(B)

The parameters for this problem are given as follows:

a = 143, c = 70, B = 62.1º.

Hence the distance b is obtained as follows:

b² = 143² + 70² - 2 x 143 x 70 x cosine of 62.1 degrees

b² = 15981.

[tex]b = \sqrt{15981}[/tex]

b = 126.42 miles.

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The workers percentile score is given as follows:

69.15%.

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score for this problem is given as follows:

z = 0.5.

Hence the percentile score is of 69.15%, as z = 0.5 has a p-value of 0.6915.

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