Answer:
Step-by-step explanation:
I am not really sure because u did not finish the question but is u are asking how much time it takes to fit one tyre:
answer is time/tyres
56min./4
14 min. Per type
The function f(x)=2x2−x+4; f ( x ) = 2 x 2 − x + 4 is defined over the domain 0 ≤ x ≤ 3 Find the range of this function. A. 4 < f(x) < 7 B. 4 < f(x )< 19 C. 4 ≤ f(x) ≤ 19 D. 4 ≤ f(x) ≤ 25
Answer:
C. 4 ≤ f(x) ≤ 19 . . . . . . best of bad answer choices
Step-by-step explanation:
When looking for the range of a function on an interval, one must check the function values at the ends of the interval, along with any local maxima or minima.
Here, the function values at the interval ends are ...
f(0) = 4
f(3) = 2·3² -3 +4 = 19
The axis of symmetry is located at ...
x = -b/(2a) = -(-1)/(2(2)) = 1/4
This is a value in the interval, so will be the location of the minimum value of the function.
f(1/4) = 2(1/4)² -1/4 +4 = 3.875
The range of f(x) on the interval [0, 3] is [3.875, 19]:
3.875 ≤ f(x) ≤ 19
__
All of the answer choices are incorrect. Please discuss question this with your teacher.
Express (In 35+ln(1/7))/ In 25 in terms of In 5 and In 7
Properties of the logarithm: for any base of logarithm,
log(a*b) = log(a) + log(b)
If we replace b with 1/b, or b^-1, we have
log(a/b) = log(a) + log(1/b) = log(a) - log(b)
since
log(1/b) = log(b^-1) = - log(b)
using the power property of logarithms,
log(b^n) = n log(b)
Now,
ln35 = ln(5*7) = ln5 + ln7
ln(1/7) = - ln7
ln25 = ln(5^2) = 2 ln5
Putting everything together, we have
(ln35 + ln(1/7))/ln25 = (ln5 + ln7 - ln7)/(2 ln5) = ln5/(2 ln5) = 1/2
The office needs 8 new devices worth $8000. The order consists of new computers (C ) which cost $925 each and printers (P) which cost $1125 each. How many of the new devices are computers and how many are printers?
Answer:
The number of computer is 5 and printer is 3
The probability that a freshman at a certain college takes an introductory statistics class is 0.21. What is the probability that a randomly selected freshman from this college does not take an introductory statistics class
Answer:
[tex] P(A) = 0.21[/tex]
We want to find the probability that a randomly selected freshman from this college does not take an introductory statistics class, so then we can use the complement rule given by:
[tex] P(A') = 1-P(A)[/tex]
Where A is the event of interest (a freshman at a certain college takes an introductory statistics class) and A' the complement (a freshman at a certain college NOT takes an introductory statistics class) and then replacing we got:
[tex] P(A')=1-0.21= 0.79[/tex]
Step-by-step explanation:
For this problem we know that the probability that a freshman at a certain college takes an introductory statistics class is 0.21, let's define of interest as A and we can set the probability like this:
[tex] P(A) = 0.21[/tex]
We want to find the probability that a randomly selected freshman from this college does not take an introductory statistics class, so then we can use the complement rule given by:
[tex] P(A') = 1-P(A)[/tex]
Where A is the event of interest (a freshman at a certain college takes an introductory statistics class) and A' the complement (a freshman at a certain college NOT takes an introductory statistics class) and then replacing we got:
[tex] P(A')=1-0.21= 0.79[/tex]
The following is a Markov (migration) matrix for three locations
[1/5 1/5 2/5
2/5 2/5 1/5
2/5 2/5 2/5]
(a) Initially, there are 130 individuals in location 1, 300 in location 2, and 70 in location 3. How many are in each location after two time periods?
(b) The total number of individuals in the migration process is 500. After a long time, how many are in each location?
Answer:
(a) [tex]\mathbf{P_2 = \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
(b) After an infinite period of time; we will get back to a result similar to after the two time period which will be [tex]= \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
Step-by-step explanation:
The Markov Matrix can be interpret as :
[tex]M = \left[\begin{array}{ccc} \dfrac{1}{5} & \dfrac{2}{5} &\dfrac{1}{5} \\ \\ \dfrac{2}{5}&\dfrac{2}{5}&\dfrac{1}{5}\\ \\ \dfrac{2}{5}& \dfrac{2}{5}& \dfrac{2}{5} \end{array}\right][/tex]
From (a) ; we see that the initial population are as follows: 130 individuals in location 1, 300 in location 2, and 70 in location 3.
Le P represent the Population; So ; [tex]P = \left[\begin{array}{c}130 \\ 300 \\ 70 \end{array}\right][/tex]
The objective is to find How many are in each location after two time periods;
So, after two time period ; we have the population [tex]P_2 = [M]^2 [P][/tex]
where;
[tex][M]^ 2 = \left[\begin{array}{ccc} \dfrac{1}{5} & \dfrac{2}{5} &\dfrac{1}{5} \\ \\ \dfrac{2}{5}&\dfrac{2}{5}&\dfrac{1}{5}\\ \\ \dfrac{2}{5}& \dfrac{2}{5}& \dfrac{2}{5} \end{array}\right] \left[\begin{array}{ccc} \dfrac{1}{5} & \dfrac{2}{5} &\dfrac{1}{5} \\ \\ \dfrac{2}{5}&\dfrac{2}{5}&\dfrac{1}{5}\\ \\ \dfrac{2}{5}& \dfrac{2}{5}& \dfrac{2}{5} \end{array}\right][/tex]
[tex][M]^ 2 = \dfrac{1}{25} \left[\begin{array}{ccc} 1+2+4 & 1+2+4 &1+2+4 \\ \\ 2+2+4&2+2+4&2+2+4\\ \\ 2+4+4&2+4+4& 2+4+4 \end{array}\right][/tex]
[tex][M]^ 2 = \dfrac{1}{25} \left[\begin{array}{ccc}7&7&7 \\ \\ 8 &8&8\\ \\10&10& 10 \end{array}\right][/tex]
Now; Over to after two time period ; when the population [tex]P_2 = [M]^2 [P][/tex]
[tex]P_2 = \dfrac{1}{25} \left[\begin{array}{ccc}7&7&7 \\ \\ 8 &8&8\\ \\10&10& 10 \end{array}\right] \left[\begin{array}{c}130 \\ 300 \\ 70 \end{array}\right][/tex]
[tex]\mathbf{P_2 = \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
(b) The total number of individuals in the migration process is 500. After a long time, how many are in each location?
After a long time; that is referring to an infinite time (n)
So; [tex]P_n = [M]^n [P][/tex]
where ;
[tex][M]^n \ can \ be \ [M]^2 , [M]^3 , [M]^4 .... \infty[/tex]
; if we determine the respective values of [tex][M]^2 , [M]^3 , [M]^4 .... \infty[/tex] we will always result to the value for [tex][M]^n[/tex]; Now if [tex][M]^n[/tex] is said to be a positive integer; then :
After an infinite period of time; we will get back to a result similar to after the two time period which will be [tex]= \left[\begin{array}{c}140 \\ 160 \\ 200 \end{array}\right]}[/tex]
Question 14
For the following system of equations, determine how many solutions there are.
6x + y = -1 and -6x - 4y = 4
Answer:
The system of equations has a one unique solution
Step-by-step explanation:
To quickly determine the number of solutions of a linear system of equations, we need to express each of the equations in slope-intercept form, so we can compare their slopes, and decide:
1) if they intersect at a unique point (when the slopes are different) thus giving a one solution, or
2) if the slopes have the exact same value giving parallel lines (with no intersections, and the y-intercept is different so there is no solution), or
3) if there is an infinite number of solutions (both lines are exactly the same, that is same slope and same y-intercept)
So we write them in slope -intercept form:
First equation:
[tex]6x+y=-1\\y=-6x-1[/tex]
second equation:
[tex]-6x-4y=4\\-6x=4y+4\\-6x-4=4y\\y=-\frac{3}{2} x-1[/tex]
So we see that their slopes are different (for the first one slope = -6, and for the second one slope= -3/2) and then the lines must intercept in a one unique point. Therefore the system of equations has a one unique solution.
Evaluate: 5-^2 =
pls help
Answer:
1/25
Step-by-step explanation:
5^-2
We know that a^ -b = 1/ a^b
5^-2 = 1/ 5^2
= 1/25
The equation 9(u – 2) + 1.5u = 8.25 models the total miles Michael traveled one afternoon while sledding, where u equals the number of hours walking up a hill and (u – 2) equals the number of hours sledding down the hill. Which is the value of u?
Answer:
2.5
Step-by-step explanation:
[tex]9(u-2)+1.5u=8.25 \\\\9u-18+1.5u=8.25\\\\10.5u-18=8.25\\\\10.5u=26.25\\\\u=2.5[/tex]
Hope this helps!
Mileage tests were conducted on a randomly selected sample of 100 newly developed automobile tires. The results showed that the mean tread life was 50,000 miles, with a standard deviation of 3,500 miles. What is the best estimate of the mean tread life in miles for the entire population of these tires?
Answer:
The best estimate of the mean of the population is 50,000 miles, which is the sample mean.
To make a better inference, we know that the 95% confidence interval for the mean is (49,306; 50,694).
Step-by-step explanation:
The unbiased point estimation for the population mean tread life is the sample mean (50,000 miles), as it is the only information we have.
Although, knowing the standard deviation, we can calculate a confidence interval to make a stronger inference.
We calculate a 95% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=50000.
The sample size is N=100.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3500}{\sqrt{100}}=\dfrac{3500}{10}=350[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=100-1=99[/tex]
The t-value for a 95% confidence interval and 99 degrees of freedom is t=1.98.
The margin of error (MOE) can be calculated as:
[tex]MOE=t\cdot s_M=1.98 \cdot 350=694.48[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=M-t \cdot s_M = 50000-694.48=49306\\\\UL=M+t \cdot s_M = 50000+694.48=50694[/tex]
The 95% confidence interval for the mean is (49306, 50694).
A cyclist travels at an average speed of 8 km/h over a distance of 32 km. How many hours does it take him?
Answer:
4 hours.
Step-by-step explanation:
Well we can simply divide 32 by 8 and we get 4 hours:
32 miles ÷ 8 miles = 4 hours
It takes the cyclist 4 hours.
Answer:
4 hours
Step-by-step explanation:
As every speed limit sign tells you, ...
speed = miles/hours
Solving for time and using generic distance units, we get ...
time = distance/speed
Filling in the given values, we have ...
time = 32 km/(8 km/h) = (32/8) h = 4 h
It takes the cyclist 4 hours to travel 32 km.
YOU KNOW THE DRILL 2.0
Answer:
#1
Step-by-step explanation:
The four yellow boxes represent x so together they are 4 * x or 4x. The blue boxes seem to represent -1 and since there are three of them together they are -1 * 3 = -3. 4x + (-3) = 4x - 3.
Five thousand tickets are sold at $1 each for a charity raffle. Tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $ 500 500, 3 prizes of $ 200 200, 5 prizes of $ 10 10, and 20 prizes of $5. What is the expected value of this raffle if you buy 1 ticket?
Answer:
-$0.75
Step-by-step explanation:
For calculation of expected value first we need to find out the probability distribution for this raffle which is shown below:-
Amount Probability
500 - 1 = $499 1 ÷ 5,000
200 - 1 = $199 3 ÷ 5,000
10 - 1 = $9 5 ÷ 5,000
5 - 1 = $4 20 ÷ 5,000
-$1 5,000 - 29 ÷ 5,000 = 4,971 ÷ 5,000
Now, the expected value of raffle will be
[tex]= \$499 \times (\frac{1}{5,000}) + \$199 \times (\frac{3}{5,000}) + \$9 \times (\frac{5}{5,000}) + \$4 \times (\frac{20}{5,000}) - \$1 \times (\frac{4,971}{5,000})[/tex]
= 0.0998 + 0.1194 + 0.009 + 0.016 - 0.9942
= -$0.75
The expected value of this raffle per ticket is $ 0.25.
Given that five thousand tickets are sold at $ 1 each for a charity raffle, and tickets are to be drawn at random and monetary prizes awarded as follows: 1 prize of $ 500, 3 prizes of $ 200, 5 prizes of $ 10, and 20 prizes of $ 5, to determine what is the expected value of this raffle if you buy 1 ticket, the following calculation must be performed:
(500 + 3 x 200 + 5 x 10 + 20 x 5) / 5000 = X (500 + 600 + 50 + 100) / 5000 = X 1250/5000 = X 0.25 = X
Therefore, the expected value of this raffle per ticket is $ 0.25.
Learn more in https://brainly.com/question/22097128
Indicate in standard form equation of the line passing through the given 
Answer:
x + y = 6
Step-by-step explanation:
slope is rise/run so -6/6 = -1
y = -x+b
solve for b by plugging in any point
6 = 0 + b -> b = 6
y = -x+6
x + y = 6
A taxi company manager is trying to decide whether the use of radial tires instead of regular belted tires improves fuel economy. Twelve cars were equipped with radial tires and driven over a prescribed test course. Without changing drivers, the same cars were then equipped with regular belted tires and driven once again over the test course. The gasoline consumption, in kilometers per liter, was recorded as follows:
Car Radial-Tires Belted-Tires
1 4.2 4.1
2 4.7 4.9
3 6.6 6.2
4 7.0 6.9
5 6.7 6.8
6 4.5 4.4
7 5.7 5.7
8 6.0 5.8
9 7.4 6.9
10 4.9 4.7
11 6.1 6.0
12 5.2 4.9
A two-sample t-test was used to compare the mean kilometers per liter for the two types of tires using a .05 level of significance. The resulting p-value was .0152.
State the null and alternate hypotheses, state whether the null hypothesis should be rejected or not rejected and your reason for that conclusion, state the meaning of that conclusion specifically in terms of the problem being studied.
Answer:
Step-by-step explanation:
Corresponding gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used form matched pairs.
The data for the test are the differences between the gasoline consumption when radial tires is used and gasoline consumption when regular belted tires is used.
μd = the gasoline consumption when radial tires is used minus the gasoline consumption when regular belted tires is used.
For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
The resulting p-value was .0152.
Since alpha, 0.05 > than the p value, 0.0152, then we would reject the null hypothesis. Therefore, at 5% significance level, we can conclude that the gasoline consumption when regular belted tires is used is higher than the gasoline consumption when radial tires is used.
12 and 3/6 -5 and 2/12
Answer:
7.33333333333 I think. Hope this helped.
sorry it’s hard to see. please help!!!
which quadrilateral will always have four reflection symmetry
Step-by-step explanation:
a rectangle has reflectional symmetry when reflected over the line through the midpoints of its opposite sides
Answer: A square always has a four reflection symmetry no matter the size.
Write an equation of a line that is parallel to the line 3y=-x+6 and passes through the point (6,2).
Answer:
y = x+2
y =-x+2 shows 0
We want to show 1 both sides
2y = x+2 shows 2
y = x+2 shows 0 as explained below.
Step-by-step explanation:
3y−x=6
Solve for y.
y=2+x3
Rewrite in slope-intercept form.
y=13x+2.
Use the slope-intercept form to find the slope and y-intercept.
Slope: 13 y-intercept: 2
Any line can be graphed using two points. Select two
x values, and plug them into the equation to find the corresponding y values.
xy 02, 33
Graph the line using the slope and the y-intercept, or the points.
Slope:
13y-intercept: 2x y (0,2) (3,3)
what is the solution for this equation [3y+7]=13
Answer:2
Step-by-step explanation:
3y+ 7= 13
3y= 13 - 7
3y= 6
Y = 6/3
Y= 2
If a graph of y=-9x+ 3 were changed to a graph of y=-9x + 1, how would the
y-intercept change?
Answer:
y-intercept decreased by 3-1= 2 points
Step-by-step explanation:
y=-9x+ 3 ⇒ y-intercept= 3
y=-9x + 1 ⇒ y-intercept= 1
y-intercept decreased by 3-1= 2 points = the line shifted down by 2 points
Answer:
Hello!
Answer: y-intercept decreased by 2 points because 3-1=2
I hope I was of help. If not, please let me know! Thanks!
Step-by-step explanation:
What graph is the function y= -2 cos20
Answer:
Step-by-step explanation:
13. Carla drew two acute non-overlapping
angles that share a ray and labeled them
ZJLK and Z KLM. The two angles have
different measures. Carla says
ZILM is
greater than a right angle.
An acute angle is open
less than a right angle.
Answer:
An acute angle is open
Step-by-step explanation:
An acute angle is an angle that is less than [tex]90^{0}[/tex]. Two or more acute angles are set to be complementary if their sum equals a right angle.
Clara's diagram involves two acute angles JLK and KLM with both sharing the side LK.
If the acute angles are complementary angles, then JLM would be a right angle.
If the acute angles are not complementary angles, then JLM would be less than a right angle.
So the appropriate choice to select is an acute angle is open. Which implies that JLM may be a right angle or not depending on the degrees of the acute angles involved.
Solve for x. e^x - e ^ -x / e^x + e ^-x = t
Answer:
D
Step-by-step explanation:
(eˣ − e⁻ˣ) / (eˣ + e⁻ˣ) = t
Multiply by eˣ/eˣ.
(e²ˣ − 1) / (e²ˣ + 1) = t
Solve for e²ˣ.
e²ˣ − 1 = (e²ˣ + 1) t
e²ˣ − 1 = e²ˣ t + t
e²ˣ = 1 + e²ˣ t + t
e²ˣ − e²ˣ t = 1 + t
e²ˣ (1 − t) = 1 + t
e²ˣ = (1 + t) / (1 − t)
Solve for x.
2x = ln[(1 + t) / (1 − t)]
x = ½ ln[(1 + t) / (1 − t)]
Use log rule.
x = ln(√[(1 + t) / (1 − t)])
Which equation can be used to determine the distance between the origin and (–2, –4)? d = StartRoot ((0 minus 2) + (0 minus 4)) squared EndRoot d = StartRoot (0 minus (negative 2)) squared + (0 minus (negative 4)) squared EndRoot d = StartRoot ((0 minus 2) minus (0 minus 4)) squared EndRoot d = StartRoot (0 minus (negative 2)) squared minus (0 minus (negative 4)) squared EndRoot
Answer:person up top is right it’s B
Step-by-step explanation: on edg 2020
Answer:
The answer is B
Step-by-step explanation:
lol yw guys
Based on historical data, your manager believes that 36% of the company's orders come from first-time customers. A random sample of 195 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.34 and 0.49
Answer:
[tex] P(0.34 <\hat p<0.49)[/tex]
And the distribution for the sample proportion is given by;
[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And we can find the mean and deviation for the sample proportion:
[te]\mu_{\hat p}= 0.36[/tex]
[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]
And we can use the z score formula given by:
[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]
[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]
And we can use the normal distribution table and we got:
[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]
Step-by-step explanation:
For this case we know that the sample size is n =195 and the probability of success is p=0.36.
We want to find the following probability:
[tex] P(0.34 <\hat p<0.49)[/tex]
And the distribution for the sample proportion is given by;
[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And we can find the mean and deviation for the sample proportion:
[tex]\mu_{\hat p}= 0.36[/tex]
[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]
And we can use the z score formula given by:
[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]
[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]
And we can use the normal distribution table and we got:
[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]
0.580 80 repeating as a simplified fraction
Answer:
979
Step-by-step explanation:
Answer:
115/198
Step-by-step explanation:
khan
2. A manufacturer produces light bulbs at a Poisson rate of 300 per hour. The probability that a light bulb is defective is 0.012. During production, the light bulbs are tested, one by one, and the defective ones are put in a special can that holds up to a maximum of 50 light bulbs. On average, how long does it take until the can is lled
Answer:
On average it will take 13 hrs 53 minutes before the van is filled
Step-by-step explanation:
The first thing we need to do here is to find find the number of defective light bulbs
Using the poisson process, that would be;
λ * p
where λ is the poisson rate of production which is 300 per hour
and p is the probability that the produced bulb is defective = 0.012
So the number of defective bulbs produced within the hour = 0.012 * 300 = 3.6 light bulbs per hour
Now, let X be the time until 50 light bulbs are produced. Then X is a random variable with the parameter (r, λ) = (50, 3.6)
What we need to find however is E(X)
Thus, the expected value of a gamma random variable X with the parameter (x, λ) is;
E(X) = r/λ = 50/3.6 = 13.89
Thus the amount of time it will take before the Can will be filled is 13 hrs 53 minutes
what is the positive solution for the equation
Answer:
x=3
Step-by-step explanation:
4x^2 - 36 = 0
Add 36 to each side
4x^2 -36 +36 = 0+36
4x^2 = 36
Divide each side by 4
4x^2/4 =36/4
x^2 = 9
Take the square root of each sdie
sqrt(x^2) = ±sqrt(3)
x = -3,+3
We want the positive square root
x=3
What is the slope of the line?
Which size would you see on the box for a new television whose screen measures 36 inches wide by 27 inches high? A. 9" B. 45" C. 50" D. 63"
Answer: b) 45"
Step-by-step explanation:
Tv's are measured by their diagonal length.
Use Pythagorean Theorem to find the diagonal of the tv.
a² + b² = c²
36² + 27² = c²
1296 + 729 = c²
2025 = c²
√2025 = c
45 = c
