Julie is cycling at a speed of 3.4 meters/second. If the combined mass of the bicycle and Julie is 30 kilograms, what is the kinetic energy?

A.
1.7 × 102 joules
B.
1.5 × 102 joules
C.
2.0 × 102 joules
D.
2.2 × 102 joules

Answer:

A ( Jack did twice as much work as Jill

Explanation:

Answer:

The electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]

Explanation:

Given

[tex]Radius,\ r = 0.03m\\Charge,\ q =7.6\µC[/tex]

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε [tex]= 8.8542 * 10^{-12}[/tex]

Substitute ε [tex]= 8.8542 * 10^{-12}[/tex] and [tex]q =7.6\µC[/tex]; The formula becomes

Ф = [tex]\frac{7.6\µC}{8.8542 * 10^{-12}}[/tex]

Ф = [tex]\frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}[/tex]

Ф = [tex]\frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}[/tex]

Ф = [tex]\frac{7.6}{8.8542} *10^{12-6}}[/tex]

Ф = [tex]0.85834970974 *10^{12-6}}[/tex]

Ф = [tex]0.85834970974 *10^{6}}[/tex]

Ф = [tex]8.5834970974 *10^{5}}[/tex]

Ф = [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]

Hence, the electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]

Answer: It will not regain its shape, because when it is corked it can not replace the volume of material that you just take out of it.

Explanation:

When you squeeze the bottle, you are changing the volume of the bottle, in this process, you are "expelling" the material inside the bottle.

When you stop squeezing, there is a change in pressure, and the bottle "absorbs" air, until the pressure is equilibrated, and in this process, the bottle returns to the original shape.

Now, if you take the sauce out of the bottle and immediately cored it, then you removed the material inside of the bottle and did not let the bottle to "refill" the empty space with air, so it can not regain its shape.

Answer:

10m/s

Explanation:

[tex]d=v_ot+\dfrac{1}{2}at^2[/tex]

Since there is no initial velocity as the object is dropped, you can write the following equation:

[tex]5=\dfrac{1}{2}(10)t^2 \\\\1=t^2 \\\\t=1[/tex]

Now that you know how long the fall took, you can use another physics equation to find the velocity at that point.

[tex]v_f=v_o+at[/tex]

Since there once again is no initial velocity, you can rewrite this as:

[tex]v_f=at=(10)(1)=10m/s[/tex]

Hope this helps!

The kinetic energy the object has at any point during the fall is exactly the potential energy it lost by falling to that height.

Potential energy = (mass) · (gravity) · (height)

Change of potential energy = (mass) · (gravity) · (change of height)

Change of potential energy = (2 kg) · (10 m/s ) · (-5 m)

Change of potential energy = 100 Joules

Kinetic energy = (1/2) · (mass) · (speed²)

Kinetic energy = (1 kg) · (speed² )

100 J = (1 kg) · (speed²)

Speed² = (100 J) / (1 kg)

Speed² = (100 kg-m²/s²) / (1 kg)

Speed² = (100 m²/s²)

Speed = 10 m/s  

Answer:

K is the spring/elastic constant measured in Newton per metre square (N/m²)

Explanation:

E = ½Ke²

In the equation above,

E is the energy in Joules (J)

K is the elastic/spring constant in Newton per metre square (N/m²)

e is the extension in metre (m)

Answer:

In the equation Ee = ½ × k × e², "k" = spring constant

Explanation:

Answer:

The wavelength of the wave is 2.34 nm.

Explanation:

It is required to find the wavelength of a [tex]1.28\times 10^{17}\ Hz[/tex] wave. A wave moves with a speed of light. Speed of a wave is given in terms of wavelength and frequency. So,

[tex]v=f\lambda[/tex]

[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1.28\times 10^{17}}\\\\\lambda=2.34\times 10^{-9}\ m\\\\\text{or}\\\\\lambda=2.34\ nm[/tex]

So, the wavelength of the wave is 2.34 nm.

The wavelength of the wave is 2.34 × 10⁻⁹ meters.

Given the data in the question;

Wavelength; [tex]\lambda =\ ?[/tex]

To determine the wavelength of the wave, we use the expression for the relations between wavelength, frequency and speed of light.

[tex]\lambda = \frac{c}{f}[/tex]

Where [tex]\lambda[/tex] is wavelength, f is frequency and c is speed of light ( [tex]3*10^8m/s[/tex] )

We substitute our values into the equation

[tex]\lambda = \frac{3*10^8m/s}{1.28*10^{17}Hz} \\\\\lambda = \frac{3*10^8m/s}{1.28*10^{17}s^{-1}} \\\\\lambda = 2.34 * 10^{-9}m[/tex]

Therefore, the wavelength of the wave is 2.34 × 10⁻⁹ meters.

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Answer:

Solar panels have increased in efficiency over the past 20 years

Explanation:

Because if efficiency have increased other technologies will be discovered

Answer:

Solar panels have increased in efficiency over the past 20 years

Explanation:

Answer:

37.1°

Explanation:

Answer: 0.326kg

Explanation:

Given the following :

Mass of copper (Mc) = 253g

Initial temperature of copper (t1) = 85°C

Mass of aluminium(Ma)=?

Initial temperature of aluminum(t1) = 5°C

Specific heat capacity of aluminum(Ca) = 900

Specific heat capacity of copper (Cc) = 387

Final temperature(t2) = 5°C

Q = mc(t2 - t1)

Ma × Ca × (t2 - t1)a = Mc × Cc × (t2 - t1)c

Ma × 900 × (25 - 5) = 0.253 × 387 × (25 - 85)

Ma × 900 × 20 = 0.253 × 387 × 60

Ma × 18000 = 5874.66

Ma = 5874.66 / 18000

Ma = 0.32637

Ma = 0.326kg

The mass of the aluminum chunk dropped into the water is 325.5 g.

The given parameters;

Apply the principle of conservation of energy, the heat gained by the aluminum is equal to heat lost by the copper;

[tex]M_a C_a (t- t_a) = M_c C_c (t_c - t)\\\\M_a\times 0.9 \times (25-5) = 253 \times 0.386 \times (85-25)\\\\18 M_a = 5859.48\\\\M_a = \frac{5859.48}{18} \\\\M_a = 325 .5 \ g[/tex]

Thus, the mass of the aluminum chunk dropped into the water is 325.5 g.

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Answer:

32000 m

Explanation:

1000m in 1 km, so 32000m in 32 km.

Answer:

32000m

Explanation:

1km=1000m

so 32 kn is equals to 32000m

Answer:

80 Percent

Explanation:

E=energy output/energy input×100

E=8000/10000×100

E=0.8×100

E=80 percent.

Mark brianliest if my answer suit your question

If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.

Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.

Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.

As per the data provided in the question,

Total input energy = 10,000 J

Total output energy = 8,000 J

Then, the efficiency (η) of the machine will be,

η = (output energy/input energy) × 100

η = 8000/10000 × 100

η = 80%.

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Answer:

102000N/m2

This is the same as 102KN/m2 (where K = 10^3):

Explanation:

The expression 750 mmHg means 750 height the atmospheric pressure will cause mercury to be suspended due to gravity.

If we brought another fluid under investigation under the influence of the atmospheric pressure the height would be different)

Note that 750 mmHg would be the same as 750/1000 m Hg ( when we convert the mm to m)

0.75mHg

Now to get the pressure in N/m2.

We multiply the height of mercury by the density by the acceleration due to gravity.

This is expressed mathematically thus;

H×d × g ; let d- denote density

Hence we have;

H×d × g = 0.75 × 13600 × 10= 102000N/m2;

Now let's look at the flip.side assuming you don't know the formula for what you require you could use the idea of Unit derivation ;

The unit of interest is N/m2

The unit of height is m

The unit of density is kg/m3

The unit of g is Nkg-1

We would observe if we multiply

m × N/Kg × Kg/m3

We would have (m× N × Kg)/(kg×m3)

Kg cancels out, m cancels out one m from me remaining m2.

Hence our unit becomes N/m2

Note : the unit for density is wrongly expressed remember density is Mass/ volume and their units are respectively kg/m3

The atmospheric pressure on a particular day was measured as 750 mm of Hg. this would be in 102000 N/m²  ( By Assuming the density of

mercury is 13600 kg/m3 and g =10Nkg-1

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied.

The mathematical expression for the pressure

Pressure = Force /Area

the pressure is expressed by the unit pascal or N /m²

As given in the problem The atmospheric pressure on a particular day was measured as 750 mm of Hg.

Atmospheric pressure is measured by the formula

P = ρgh

where ρ is the density of the mercury

g is the acceleration due to gravity

h is the height of the liquid

By substituting the respective values

P = 13600*10*(750/1000)

P = 102000 N/m²

Thus, the atmospheric pressure would be 102000 in N/m².

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Answer:

The answer is Pascal or Pa.

Answer:

Pa or small p

Explanation:

Force over Area. The SI unit is Pascal

Answer:

B. 4.9 m/[tex]s^{2}[/tex]

Explanation:

The parallel vector, [tex]F_{g}[/tex], make the box to accelerate down the plane due to the presence of an unbalanced force.

The perpendicular component of the force will balance the normal force because the box can not accelerate perpendicularly to the plane.

i.e  [tex]F_{N}[/tex] = [tex]F_{g}[/tex]

Since the box slides down the ramp, neglecting friction and air resistance;

[tex]F_{g}[/tex] = ma

mg Sinθ = ma

But; m = 80 kg, θ = [tex]30^{0}[/tex], g = 9.8 m/[tex]s^{2}[/tex]

80 × 9.8 × Sin [tex]30^{0}[/tex] = 80 × a

784 × 0.5 = 80 a

  392 = 80 a

a = [tex]\frac{392}{80}[/tex]

   =  4.9

Thus, the box accelerates down the ramp at 4.9 m/[tex]s^{2}[/tex].

Answer:

b

Explanation:

b

Answer:

The water particles move in the same direction as the vibrating source of the sound wave. ... What best describes the waves produced by the tuning fork? mechanical, because the vibrating tuning fork makes air molecules around it vibrate. A wave is produced in a Slinky as shown.

Explanation:

Answer:

mechanical, because the vibrating tuning fork makes air molecules around it vibrate

Explanation:

Answer:

The second knife-edge must be placed 46.2 cm from the zero mark of the rod.

Explanation:

From the law of equilibrium, ΣF = 0 and ΣM = 0.

Let R be the reaction at the knife edge. Since the weight of the rod and zinc load act downward, and we take downward position as negative

-32 N - 2 N + R = 0

-34 N = -R

R = 34 N

Also, let us assume the knife-edge is x cm from the zero mark. Taking moments about the weight and assuming the knife-edge is right of the weight of the rod. Taking clockwise moments as positive and anti-clockwise moments as negative,

-(45 - 25)2 + (x - 45)R = 0

-(20)2 + (x - 45)34 = 0

-40 = -(x - 45)34  

x - 45 = 40/34

x - 45 = 1.18

x = 45 + 1.18

x = 46.18 cm

x ≅ 46.2 cm

The second knife-edge must be placed 46.2 cm from the zero mark of the rod.

1]F1*D1=F2*D2

10N×2m=5N*3m

20N=15Nm

The seesaw will turn anti clock wise.

2]

F1*D1=F2*D2

3N*4m=2N*6m

12Nm=12Nm

It will neither rotate toward anti clock wise nor clock wise

Explanation:

they would formulate a new hypothesis with the same dependent variable but a different independent variable as a virginal hypothesis .

Answer: A

Heat engine

Explanation: just took the test

Answer:

10 m

Explanation:

Trabajo (W) = 3500 J,   peso de la cuchara (F) = 350 N.

El trabajo es el producto de la fuerza que actúa sobre un objeto y la distancia o desplazamiento. La unidad de trabajo estándar son los joules (J).

Trabajo (W) =  fuerza (F) × distancia (d)

W = F × d

[tex]d=\frac{W}{F} =\frac{3500J}{350}=10m[/tex]

el cubo se elevó a 10 m

The height (distance) to which the bucket was raised is equal to 10 meters.

Given the following data:

To determine the height (distance) to which the bucket was raised:

Mathematically, work done is given by the formula:

[tex]Work\;done = Force \times distance[/tex]

Substituting the given parameters into the formula, we have;

Note: Force = weight.

[tex]3500 = 350 \times distance\\\\Distance = \frac{3500}{350}[/tex]

Distance = 10 meters.

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Answer: experimental design

the accuracy of data-collecting devices

human error

bias in selecting samples

incorrect data analysis

incorrect treatment of the control group

Explanation:

Instrumental, environmental, procedural, and human errors are frequent causes. Depending on how they affect the outcomes, each of these errors can either be random or systematic.

The discrepancy between a measured value and its true value is known as experimental error. In other words, the error or inaccuracies are what prevent us from perceiving a measurement that is 100 percent accurate.

Every measurement has some degree of experimental error, which is fairly common. Due to the widespread belief that some degree of error is inherent to the scientific method, it is not typically seen as a "mistake" in the classic sense.

However, scientists can reduce error and obtain results that are more accurate by embracing and comprehending the ways that experimental error can affect any scientific operation.

The  potential sources of error in experiment are Instrumental, environmental, procedural, and human errors.

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Answer :

.changing chemical energy to thermal energy

.changing nuclear energy to radiant energy

Explanation :

Answer:

.changing chemical energy to thermal energy

.changing nuclear energy to radiant energy

Explanation:

Answer:

Fgrav. = GM1×M2/R2

Explanation:

Gravitational force is mostly related

to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.

Hence in this case the Gravitational force,

Fgrav. = GM1×M2/R2

M1 and M2 are the mass of the two students and R is their distance apart

G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2

Answer:

36.5 kJ

Explanation:

Energy by machine = energy to machine × efficiency

E = 52.1 kJ × 0.70

E = 36.5 kJ

Answer: 0.3m

Explanation:

Given the following :

Speed of radio wave(V) = 3 × 10^8 m/s

If 1M = 10^6

Frequency(F) = 90MHz = 90 × 10^6

Wavelength (λ) =?

Speed of wave (V) = frequency(F) × wavelength(λ)

V = fλ

(3 × 10^8) = (90 × 10^6) × λ

λ = (90 × 10^6) / (3 × 10^8)

λ = 30 × 10^(6 - 8)

λ = 30 × 10^-2

λ = 0.3m

Answer:

A. 16t2 -116t -101=0 B. 8.0s

Explanation:

Known parameters from the question:

Height of Cliff,h0 = 101ft

Velocity of rocket ,v= 116ft/s.

1.Substituting the above to the above formula we have;

h(t) = -16t2 + vt + h0

Since h(t) =0, it means the rocket is falling towards the ground, when it gets to the ground when it's at rest the height h(t) = 0m

{Note the rocket is launched from the height of the Cliff so that would be the initial height of the rocket,h0}

2.Substituting into h(t) = -16t2 + vt + h0

We have;

0 = -16t2 + 116t + 101=> 16t2 -116t -101=0

Using formula method for solving quadratic equation we have;

t = -(-116)+_√[(-116)^2 -( 4× 16 ×-101]/ (2× 16)

t = [116 +_(141.1382)]/32

t = (116 -141.1382)/32 or (116 +141.1382)/32

-0.786s or 8.036s

-0.8s or 8.0s to the nearest tenth.

Now time cannot be negative in real life situation hence the time is 8.0s

Note : the general equation of a quadratic equation with variable t is given below;

at2 + bt + c=0

Formula method for quadratic equation is :

t =( -b+_√[(b^2 -( 4× a×c)] ) / (2× a)

Answer:

k = 2560 N/m

Explanation:

To find the spring constant, you take into account that all the kinetic energy of the block becomes elastic potential energy in the spring, when the block compressed totally the spring:

[tex]K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]

m: mass of the block = 4.0kg

v: velocity of the block just before it hits the spring

x: compression of the spring = 0.25m

k: spring constant = ?

You solve the previous equation for k:

[tex]k=\frac{mv^2}{x^2}[/tex]     (1)

Then, you have to calculate the velocity v of the block. First, you calculate the acceleration of the block by using the second Newton law:

[tex]F=ma[/tex]

F: force over the block = 10.0N

a: acceleration

[tex]a=\frac{F}{m}=\frac{10.0N}{4.0kg}=2.5\frac{m}{s^2}[/tex]

With this value of a you can calculate the final velocity after teh block has traveled a distance of 8.0m:

[tex]v^2=v_o^2+2ad[/tex]

vo: initial velocity = 0m/s

d: distance = 8.0m

[tex]v=\sqrt{2ad}=\sqrt{2(2.5m/s^2)(8.0m)}=6.32\frac{m}{s}[/tex]

Now, you can calculate the spring constant by using the equation (1):

[tex]k=\frac{mv^2}{x^2}=\frac{(4.0kg)(6.32m/s)^2}{(0.25m)^2}=2560\frac{N}{m}[/tex]

hence, the spring constant is 2560 N/m