Jordan can ride her skateboard 75 meters in 30 seconds. How long will it take Jordan to ride her skateboard 1,500 meters? Solve on scrap paper and enter your answer on Zearn. meters seconds 75 30 It will take Jordan seconds to ride her skateboard 1,500 meters.

Answer:

its ur dad

Step-by-step explanation:

Answer:

y=-1.9x-1

Step-by-step explanation:

Answer: 11

Step-by-step explanation:

Answer:

C. Geometric, common ratio = 3

Step-by-step explanation:

Got it right

Answer:

C

Step-by-step explanation:

Answer:

$11.33

Step-by-step explanation:

Keisha will own 307 shares after the split. and the amount of check is 11 dollar.

Given that, NoteQuest Inc. instituted a 3-for-2 split. At that time Keisha owned 205 shares of that stock. The price per share was

$33.99.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

Here, 3+ 2 = 5

Now, let x be the number of shares post split

Then;

3/2 = x/205

x = 3/2 (205)

x = 615/2 = 307.5

Therefore, Keisha will own 307 shares after the split.

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Answer:

The answer is D, h=3Vπr2. The height of the cone is 6 cm

Step-by-step explanation:

The Height of the Cone is 6 cm.

The shape's volume is equal to the product of its area and height. = Height x Base Area = Volume.

The formula for the volume of a cone is V=1/3hπr².

Given:

Volume of Cone= 1/3 πr²h

where r is the radius and h is the height.

Now, if V= 32π cm³ and r= 4 cm

Then, Volume of Cone = 1/3 πr²h

                               32π = 1/3 π(4)²h

                               32 = 1/3  (4)²h      

                                32= 1/3 (16)h

                                h/3 = 2

                               h= 6cm

Hence, the height is 6 cm.

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Answer:

(4,2)

Step-by-step explanation:

i multiplied the S values by the scale factor to get the S dash

The coordinates of the point S' after dilation is S' ( 4 , 2 )

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the triangle be represented as ΔSTU

Now , the coordinates of the triangle are

S ( 2 , 1 ) , T ( 4 , 5 ) and U ( 4 , 1 )

Now , the dilation scale factor is k = 2

So , the coordinates of the triangle after the dilation is

S' ( 4 , 2 ) , T' ( 8 , 10 ) and U' ( 8 , 2 )

Hence , the coordinate of S' is S' ( 4 , 2 )

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Answer:

63 hope this helped

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

The formula of the area of a triangle is 1/2 times base times height

1/2 .4.2 equals 4

Answer:

4

Step-by-step explanation:

I took it on the test its 4

Answer:

slope: 3    y-intercept: 9

Step-by-step explanation: 19-10 is 9, and 6-3 is 3 9/3 is 3.

28-19 equals 9. 19-10 is 9, so 9 fills out that blank beside 10.

Answer:

slope is 3 and in the blank goes 1. and y intercepts line at y=1

Answer:

light blue D-E

Step-by-step explanation:

it is a 180 and leads to F if you continue with the line

yur welcome

Answer:

8 teams is answer

Step-by-step explanation:

Answer:

Answer: 11

Step-by-step explanation:just trust me

The numerical length of LM will be 11.

It is given that point M is on line segment overline LN . Also , MN = 3x , LN = 4x + 9 , and LM = 2x + 7.

We have to determine that what will be the numerical length of LM ?

What will be the value of x in equation ; 3x + 2 = 8 ?

The value of x will be 2.

From the question we can get that ,

MN  + LM = LN

2x + 7 + 3x = 4x + 9

5x + 7 = 4x + 9

x = 2

Now , we can use the value of x to find out length of LM ;

∵ LM = 2x + 7  

⇒ LM = 2 × 2 + 7

⇒ LM = 11.

Thus , the numerical length of LM will be 11.

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Answer:

One answer is 100 yards long and 60 yards wide.

Step-by-step explanation:

The area is bigger, but answers vary.

Answer:

6+5=11

Step-by-step explanation:

6*5=30

Lowest numbers possible

Answer:

The LCM for 4 and 8 is 8. Add both numerator and rewrite it in a single form. By using LCM method, 7/8 is the equivalent fraction by adding 3/4 and 1/8.

Hope This Helps!!! Have a great day!

<3<3

Answer:

[tex]\frac{7}{8}[/tex]  or [tex]\mathrm{Decimal:\ }\:0.875[/tex]

Step-by-step explanation:

[tex]\frac{3}{4}+\frac{1}{8}[/tex]

lcm of 4 and 8 is 8

adjust the fraction base on the lcm

[tex]=\frac{6}{8}+\frac{1}{8}[/tex]

[tex]\mathrm{Apply\:the\:fraction\:rule}:[/tex][tex]\frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}[/tex]

[tex]\mathrm{Add\:the\:numbers:}\:6+1=7[/tex]

[tex]=\frac{7}{8}[/tex]

Answer:

Graph part: Find where it says each letter on the grph and put in the following numbers:

2 -140

4 -280

9 -630

To plot your points:

1 point: find 2 on the X axis and find 140 on the Y axis, plot a point there. For the next 2 points, do the same thing. Find 4 on the X, go up to 280 on the Y.

Step-by-step explanation:

The question says that there are 70 people in a group. Its then asks who many people would be in 2, 4, and 9 groups. Just muliply to get each answer and put it in the graph.

Answer:

2/3

24/36

32/48

are all equivalent to 8/12

Answer:

32/48

Step-by-step explanation:

32 divided by 4 is 8

48 divided by 4 is 12

Answer: 21

Step-by-step explanation:

Given: Number of mango guava and sapota are supplied 108,84 and 60 respectively.

Since, 108 = 2 x 2 x 3 x 3 x 3

84 =  2 x 2 x 3 x 7

60 = 2 x 2 x 3 x 5

HCF(108,84,60) = 2 x 2 x 3 [HCF=Highest common factors]

= 12

Greatest number of plants in each row = 12

Number of rows for mango = [tex]\dfrac{108}{12}=9[/tex]

Number of rows for guava = [tex]\dfrac{84}{12}=7[/tex]

Number of rows for sapota = [tex]\dfrac{60}{12}=5[/tex]

Total rows = 9+7+5= 21

Hence, the minimum number of rows in which they can be planted if in each row same numbers of saplings of the same type are to be planted​ = 21

Answer:

80 percent

Step-by-step explanation:

Dvide 300 by 240 which gives you 80 percent the amount of students that atended.

Answer:

80%

Step-by-step explanation:

240/300=.8

.8=80%

Answer:

lol is this possible i tried doing it but couldnt haha i googled it and well it said 2.6532977e+40

Step-by-step explanation:

Answer:

2.65329771×10 to the power of 40

Step-by-step explanation:

Use scientific notation to get the simplest answer

is the answer 4 ur question

Answer:

a

  P(X \le 250 ) =  0.7564 [/tex]  ,  [tex]P(X <  250 )  =  0.7564 [/tex]   ,

    [tex]P(X <  300 )  =  0.09922 [/tex]

b

[tex]P(100 <  X  < 250 ) =0.644 [/tex]

c

 [tex]   x  = 192.1   [/tex]

Step-by-step explanation:

From the question we are told that

   The value for [tex]\alpha  =  2.6[/tex]

    The value for [tex]\beta = 220[/tex]

Generally the  Weibull distribution function is mathematically represented as

      [tex]F( x , \alpha ,  \beta ) =  \left \{  0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  x < 0} \atop { 1- e^{-(\frac{x}{\beta } )^{\alpha } }}\ \ \ \ \ \ x \ge 0} \right[/tex]

Generally the probability that a specimen's lifetime is at most 250 is mathematically represented as

      [tex]P(X \le  250 ) =  F(250, 2.7 , 220 )[/tex]

      [tex]P(X \le 250 )=1 - e^{- (\frac{250}{220} )^{2.7}}[/tex]

      [tex]P(X \le 250 ) =  1 - 0.2436[/tex]

      [tex]P(X \le 250 ) =  0.7564 [/tex]

Generally the probability that a specimen's lifetime is less than 250

      [tex]P(X <  250 ) =  F(250, 2.7 , 220 )[/tex]

      [texP(X <  250 ) =1 - e^{- (\frac{250}{220} )^{2.7}}[/tex]

      [tex]P(X <  250 )  =  1 - 0.2436[/tex]

      [tex]P(X <  250 )  =  0.7564 [/tex]    

Generally the probability that a specimen's lifetime is more than 300

     [tex]P(X >  300 ) = 1- p(X \le 300 )[/tex]

      [tex]P(X >  300 ) = 1-  F(300, 2.7 , 220 )[/tex]

      [texP(X <  300) =1- [1 - e^{- (\frac{300}{220} )^{2.7}}][/tex]

      [tex]P(X <  300 )  =  0.09922 [/tex]

Generally the probability that a specimen's lifetime is between 100 and 250 is

     [tex]P(100 <  X  < 250 ) =  P(X < 250) - P(X < 100)[/tex]

=>  [tex]P(100 <  X  < 250 ) =F(250 , 2.7 , 220 ) - F(100 , 2.7 , 220 ) [/tex]

=>  [tex]P(100 <  X  < 250 ) =(1 - e^{-(\frac{250}{220})^{2.7}}) - (1 - e^{-(\frac{100}{220})^{2.7}}) [/tex]

=>  [tex]P(100 <  X  < 250 ) = (1 - 0.244 ) - (1- 0.888)[/tex]

=>  [tex]P(100 <  X  < 250 ) =0.644 [/tex]

Generally the value  such that exactly 50% of all specimens

    [tex]P(X > x) = 1-P(X <  x) = 0.50[/tex]

=>  [tex]P(X > x) = 1- (1 - e^{- (\frac{x}{220}) ^{2.7}}) = 0.50[/tex]

=>  [tex] P(X> x ) = e^(- \frac{x}{20})^{2.7}  = 0.50 [/tex]

=>  [tex] P(X> x ) = (- \frac{x}{20})^{2.7}  = ln0.50 [/tex]

=>   [tex] P(X> x ) =  \frac{x}{20}  =[ -ln0.50 ] ^{frac{1}{2.7}}[/tex]

=>   [tex]   x  = 220[ -ln0.50 ] ^{frac{1}{2.7}}[/tex]

=>   [tex]   x  = 192.1   [/tex]

Answer:

Mean = 125.136

Median = 110

Mode = 180

Step-by-step explanation:

Given the data:

75 95 180 136 89 75 110 180 100 136 180 95 180 136 75 100 110 180 180 136 75 90

Frequency distribution:

Value(X) ___freq (F) ____cumm frequency

85 _________ 4 _______ 4

89 _________ 1 _______5

90 __________1 _______6

95 __________2 ______ 8

100 _________ 2 ______10

110 __________2______ 12

136 __________4 _____ 16

180 __________6______22

2) Using the frequency distribution :

Mean = Σfx / Σf

[(85*4) + (89*1) + (90*1) + (95*2) + (100*2) + (110*2) + (136*4) + (180*6)]/ 10

= 2753 / 22

= $125.136

Median of grouped data :

Frequency + 1 / 2 = 23/2 = 11.5 th term

The median value = $110

Mode of the data:

Most frequently occurring = 180 (frequency of 6)

The mean of the frequency distribution is $125.136, the median of the frequency distribution is $110, and the mode of the frequency distribution is $180.

Given :

a) The frequency distribution is given below:

Prices              Frequency       Cumulative Frequency

85                           4                                 4

89                            1                                 5

90                            1                                  6

95                            2                                  8

100                           2                                 10

110                            2                                  12

136                            4                                 16

180                            6                                 22

b) The mean is calculated as:

[tex]\rm Mean = \dfrac{85\times4 + 89\times1 +90\times1 +95\times 2+100\times2 +110\times2 +136\times4 +180\times6 }{10}[/tex]

Simplify the above expression.

Mean = $125.136

c) The median of the frequency distribution is calculated as:

[tex]\rm Term= Frequency + \dfrac{1}{2}=11.5[/tex]

So, the median is $110.

The mode of the frequency distribution is $180.

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