Answer:
1 candy bar is $1.25
2 candy bars is $2.50
3 candy bars is $3.75
4 candy bars is $5
Equation:
y = 1.25x
y being the cost and x being number of candy bars
Apply the Distributive Property to the right side.
12
enter your response herex
enter your response here (Type integers or fractions.)
The rewritten expression of 12 using the distributive property is 3(2 + 2)
Rewriting the equation using the distributive property.From the question, we have the following parameters that can be used in our computation:
12 distributive property
This means that
12
Express as 6 + 6
So, we have
12 = 6 + 6
Factor out 3 from the equation
So, we have
12 = 3(2 + 2)
The above equation has been rewritten using the distributive property.
Hence, the rewritten expression using the distributive property is 3(2 + 2)
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At one store a trophy costs $12.50. Engraving costs $0.40 per letter. At another store, the same trophy costs $14.75. Engraving costs $0.25. How many letters must be engraved for the costs to be the same?
Answer: 15 letters.
Step-by-step explanation:
When p is the number of letters being engraved:
12.5 + .4p = 14.75 + .25p
-12.5 -12.5
.4p = 2.25 + .25p
-.25p -.25p
.15p = 2.25
/.15 /.15
p = 15
There would need to be 15 letters engraved for the cost of the trophies to be the same. Hope this helps!
3. Use the definition of the Riemann Sum to evaluate S12(x3 – 2x)dx. + - 4. Evaluate: S2x2+x=2 5. Given the velocity in meters/second for v(t) = 8 – 2t, 1 st 56 a.) find the displacement of the particle over the given time interval; b.) find the distance traveled by the particle over the given time interval.
Evaluation of S12(x3 – 2x)dx is- 92.875
We can use the definition of the Riemann Sum to evaluate S12(x3 – 2x)dx as follows:
First, we need to choose the width of our intervals.
Let's choose Δx = 1/2, which means we will have 24 subintervals.
Now, we can use the formula for the Riemann Sum to calculate the sum of the areas of the rectangles.
S12(x3 – 2x)dx ≈ ∑[f(xi)Δx] from i=1 to i=24
where xi is the right endpoint of the ith subinterval,
f(xi) = x[tex]i^3[/tex] – 2xi is the height of the rectangle, and Δx = 1/2 is the width of the rectangle.
Evaluating this sum using the given formula, we get:
S12(x3 – 2x)dx ≈ [f(1/2) + f(1) + f(3/2) + ... + f(11)](1/2)
≈ [[tex](1/2)^3[/tex] – 2(1/2) + (1)^3 – 2(1) + (3/2[tex])^3[/tex] – 2(3/2) + ... + (11[tex])^3[/tex] – 2(11)](1/2)
≈ [- 2361/16](1/2)
≈ - 92.875
4) we can simply evaluate the given integral:
S2x2+x=2 = ∫(2[tex]x^2[/tex] + x)dx from 0 to 2
= [[tex]2/3 x^3 + 1/2 x^2[/tex]] from 0 to 2
= [[tex]2/3 (2)^3 + 1/2 (2)^2[/tex]] - [[tex]2/3 (0)^3 + 1/2 (0)^2[/tex]]
= 16/3
5), we can use the following formulas
to find the displacement and distance traveled by the particle over the given time interval:
Displacement = ∫v(t)dt from 1 to 5
Distance traveled = ∫|v(t)|dt from 1 to 5
where v(t) is the velocity function.
a) To find the displacement, we evaluate the integral:
∫v(t)dt = ∫(8 – 2t)dt from 1 to 5
= [8t – t^2] from 1 to 5
= [[tex]8(5) – (5)^2[/tex]] - [8(1) – [tex](1)^2[/tex]]
= 18 meters
b) To find the distance traveled, we evaluate the integral:
∫|v(t)|dt = ∫|8 – 2t|dt from 1 to 5
= ∫(8 – 2t)dt from 1 to 4 + ∫(2t – 8)dt from 4 to 5
= [8t – [tex]t^2[/tex]] from 1 to 4 + [-t^2 + 8t -16] from 4 to 5
= [8(4) – [tex](4)^2[/tex]] - [8(1) – [tex](1)^2[/tex]] + [[tex]-(5)^2[/tex] + 8(5) -16 -(-[tex](4)^2[/tex] + 8(4) -16)]
= 26 meters
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Nosaira solved an equation. her work is shown below: 3(2x 1 ) = 2(x 1) 1 6x 3 = 2x 2 1 6x 3 = 2x 3 4x = 0 x = 0 she determines the equation has no solution. which best describes nosaira’s work and answer? her work is correct, but there is one solution rather than no solution. her work is correct and her interpretation of the answer is correct. her work is incorrect. she distributed incorrectly. her work is incorrect. she moved terms across the equals sign incorrectly.
Nosaira's work is incorrect. Her mistake is in the step where she simplifies the expression 2x+1 on the left side of the equation by multiplying it with 3. She distributed the 3 only to the 2x term, but forgot to distribute it to the 1 term as well.
So, the correct expression on the left side should be 6x+3 instead of 6x+1. This mistake leads to the wrong equation 6x+3=2x^2-1, and when she tries to solve for x, she ends up with the equation 4x=0, which only has one solution, x=0.
Therefore, Nosaira's interpretation of the answer as having no solution is incorrect. The original equation actually does have a solution, which is x=1/2. If we correct the mistake in her work, we can see that the equation becomes [tex]6x+3=2x^2-1[/tex], which simplifies to [tex]2x^2-6x-4=0[/tex]. We can then factor out 2 to get [tex]x^2-3x-2=0[/tex], which can be factored further into (x-2)(x+1)=0. Therefore, the solutions are x=2 and x=-1, but we need to reject the negative solution as it does not satisfy the original equation.
In conclusion, Nosaira made a mistake in distributing the coefficient 3, which led to an incorrect equation and an incorrect interpretation of the answer. It is important to be careful and check our work, especially when dealing with algebraic expressions and equations.
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√50-√18+√8+√128-3√2
Please solve this
Step-by-step explanation:
the
answer
of
this
question
is
9 \sqrt{2}
Do you like this (^__^) ??
Store A's profit is modeled by f(x) =2x, and Store B's profit is modeled by g(x) = 83x. Over what interval is Store A's profit greater than Store B's?
Over (-∞, 0) interval is Store A's profit greater than Store B's.
To determine the interval over which Store A's profit is greater than Store B's, we need to solve the inequality:
f(x) > g(x)
Substituting the given profit functions, we have:
2x > 83x
Simplifying this inequality, we can subtract 83x from both sides:
-81x > 0
Dividing both sides by -81 (and reversing the inequality because we are dividing by a negative number), we get:
x < 0
Therefore, Store A's profit is greater than Store B's for all values of x less than 0. In interval notation, we can write:
(-∞, 0)
So the interval over which Store A's profit is greater than Store B's is the open interval from negative infinity to 0.
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-3 3/7 times 5 5/6 ........
Answer:
the answer for this problem would be -20
Answer:
-20
Step-by-step explanation:
The easiest way to do it is to change -3 3/7 and 5 5/6 into improper fractions. To do that, let’s take -3 3/7 for example. You would add the numerator by the whole number, and then multiply the denominator by the whole number. Getting you -24/7, the other number would be 35/6 then you multiply the two getting you -840/42, which it turned back into a proper fraction by dividing the two numbers, you would get -20. Hope this helps!
Find the area of the triangle. 8 m
5 m
Question content area bottom
Part 1
The area of the triangle is 1 m cubed. (Type a whole number. )
The area of the triangle is 20 square meters.
The formula to find the area of a triangle is A = 1/2 * base * height. In this case, the base of the triangle is 8 meters and the height is 5 meters. Therefore, the area of the triangle is A = 1/2 * 8 m * 5 m = 20 m^2.
We can also check our answer by using the formula A = (b * h) / 2, where b is the base and h is the height of the triangle. Substituting the values given in the question, we get A = (8 m * 5 m) / 2 = 20 m^2. Therefore, the area of the triangle is 20 square meters.
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1. at which location in new york state
would one least expect to find fossils in
the surface bedrock?
One would least expect to find fossils in the surface bedrock in the Adirondack Mountains region of New York State.
This region is known for having some of the oldest rocks in North America, dating back over a billion years. These rocks were formed through volcanic activity and mountain-building processes that occurred long before the evolution of complex life forms.
As a result, the rocks in the Adirondack Mountains are generally not rich in fossils, especially those of plants and animals that evolved much later in Earth's history.
In contrast, other regions of New York State, such as the Hudson Valley and the Finger Lakes region, have rocks that are more conducive to fossil preservation. These regions were covered by shallow seas at various times in the past, allowing for the accumulation of sediment and the preservation of fossils of marine organisms.
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In the united states, the number of children under age 18 per family is skewed right with a mean of 1.9 children and a standard deviation of 1.1 children.
analyst 1 wants to calculate the probability that a randomly selected family from the united states has at least 2 children.
analyst 2 wants to calculate the probability that if 40 families from the united states are randomly selected, the mean number of children per family is at least 2 children.
what sample size does analyst 1 plan to use?
enter an integer. what sample size does analyst 2 plan to use?
enter an integer.
The probability of a randomly selected family from the United States having at least 2 children is 0.2734. The probability that if 40 families from the United States are randomly selected, the mean number of children per family is at least 2 children is 0.1884. Analyst 1 plans to use a sample size of 1 and analyst 2 plans to use a sample size of 40.
Analyst 1 wants to calculate the probability that a randomly selected family from the United States has at least 2 children. Since the number of children under age 18 per family is skewed right with a mean of 1.9 children and a standard deviation of 1.1 children, we can use the normal distribution to solve this problem.
To calculate the probability of a randomly selected family having at least 2 children, we need to find the area under the normal curve to the right of 2.
Using a standard normal distribution table or calculator, we can find that the area to the right of 2 is approximately 0.2734. Therefore, the probability of a randomly selected family from the United States having at least 2 children is 0.2734.
Analyst 2 wants to calculate the probability that if 40 families from the United States are randomly selected, the mean number of children per family is at least 2 children. Since we know that the mean number of children per family in the population is 1.9 children and the standard deviation is 1.1 children, we can use the central limit theorem to approximate the sampling distribution of the sample means.
The central limit theorem tells us that the sampling distribution of the sample means will be approximately normal with a mean of 1.9 children and a standard error of the mean equal to the population standard deviation divided by the square root of the sample size.
We want to find the probability that the mean number of children per family is at least 2, so we need to standardize the sample mean using the formula:
z = (sample mean - population mean) / (standard error of the mean)
Plugging in the values, we get:
z = (2 - 1.9) / (1.1 / sqrt(40)) = 0.889
Using a standard normal distribution table or calculator, we can find that the area to the right of 0.889 is approximately 0.1884. Therefore, the probability that if 40 families from the United States are randomly selected, the mean number of children per family is at least 2 children is 0.1884.
So, analyst 1 plans to use a sample size of 1 and analyst 2 plans to use a sample size of 40.
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Lisa invested money into a bank account. The value of the account after t years can be found using the function f(t)=6320(1.054)t . What is the initial value of the account?
The initial value of the account is: 6320
How to solve compound interest problems?Compound interest is defined as the interest you earn on interest. This can be illustrated by using basic math: if you have $100 and it earns 10% interest each year, you'll have $110 at the end of the first year.
The general formula to find compound interest is:
A = P(1 + r/n)^t
where:
A is final amount
P is initial principal balance
r is interest rate
n is number of times interest applied per time period
t is number of time periods elapsed
We are given the equation as:
f(t) = 6320(1.054)^(t)
Thus, the initial value is 6320
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PLEASE HELP THIS A FRESHMEN QUESTION
Answer:
The total area of the "t" figure is 20 square units.
The figure is made up of a triangle, a square, and a rectangle.
The area of the triangle is (1/2)(base)(height) = (1/2)(4)(3) = 6 square units.
The area of the square is 4^2 = 16 square units.
The area of the rectangle is 2(4)(3) = 24 square units.
The total area of the figure is 6 + 16 + 24 = 46 square units.
However, the question asks for the area of the composite region, which is the shaded region in the figure. The shaded region is a triangle with base 4 units and height 3 units. The area of this triangle is (1/2)(base)(height) = (1/2)(4)(3) = 6 square units.
Therefore, the area of the composite region is 6 square units.
Here is a diagram of the figure with the areas of each shape labeled:
[Image of the "t" figure with the areas of each shape labeled]
Answer:
Step-by-step explanation:
I don't have enough information to answer this.
When creating lines of best fit, do you believe that estimation by inspection of the equation is best or do you think it should be determined exactly? In what situations would it be best to use one over the other?
Your response should be 3-5 sentences long and show that you’ve thought about the topic/question at hand
In general, it is best to determine the equation of the line of best fit exactly rather than relying on estimation by inspection. This is because an exact equation allows for more precise predictions and calculations.
Estimation by inspection can be useful in situations where the data is relatively simple and a rough estimate is sufficient. However, in more complex datasets, it is important to use statistical methods to determine the line of best fit accurately.
It is also worth noting that in some cases, different methods of determining the line of best fit may be appropriate depending on the specific goals of the analysis.For example, in some cases, it may be more important to prioritize the accuracy of the slope of the line over the accuracy of the intercept. In such cases, certain methods, such as minimizing the sum of the squares of the vertical deviations, may be more appropriate than others.
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Town officials want to estimate the number of households that own a dog. Answer the following.
There are 300 households in the town.
Estimate how many households that own a dog
__ households
The estimated number of households that own a dog in the town is 120 households.
To estimate the number of households that own a dog in the town with 300 households, you will need to follow these steps:
1. Collect a random sample of households from the town. The sample size should be large enough to be representative of the entire population.
2. Determine the proportion of sampled households that own a dog.
3. Multiply the proportion of dog-owning households in the sample by the total number of households in the town (300).
For example, let's say you collected data from 50 households and found that 20 of them owned a dog. The proportion of dog-owning households would be 20/50 = 0.4 (40%).
To estimate the total number of households that own a dog in the town, multiply 0.4 by 300:
0.4 * 300 = 120 households
So, the estimated number of households that own a dog in the town is 120 households.
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The number of enterprise instant messaging (IM) accounts is projected to grow according to the function N(t) = 2.97t2 + 11.32t + 59.2 (0 ≤ t ≤ 5) where N(t) is measured in millions and t in years, with t = 0 corresponding to 2006. (a) How many enterprise IM accounts were there in 2006? million (b) What was the expected number of enterprise IM accounts in 2009? million
There were 59.2 million enterprise IM accounts in 2006 and the expected number of enterprise IM accounts in 2009 was 119.89 million.
(a) To find the number of enterprise IM accounts in 2006, we need to evaluate
N(t) at t = 0: N(0) = 2.97(0)^2 + 11.32(0) + 59.2
N(0) = 0 + 0 + 59.2
N(0) = 59.2 million
So, there were 59.2 million enterprise IM accounts in 2006.
(b) To find the expected number of enterprise IM accounts in 2009, we need to evaluate
N(t) at t = 3 (since 2009 corresponds to t = 3): N(3) = 2.97(3)^2 + 11.32(3) + 59.2
N(3) = 2.97(9) + 33.96 + 59.2
N(3) = 26.73 + 33.96 + 59.2
N(3) = 119.89 million
So, the expected number of enterprise IM accounts in 2009 was 119.89 million.
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What’s the answer? I need help please
Answer:
-√3/2
Step-by-step explanation:
sin(x) is equal to 1/2 when x=7π/6 or 11π/6
cos(7π/6) = -√3/2
cos(11π/6) = √3/2
In the question, it says that cos(x) is <0, which means that it has to be negative
So, the answer is -√3/2
Answer: C
Step-by-step explanation:
Think of a unit circle
sin x = -1/2 happens at 7[tex]\pi[/tex]/6 and 11[tex]\pi[/tex]/6, 3rd and 4th quadrant
Out of those 2 quadrants cos x is negative in the 3rd quadrant
So cos x= -√3/2
Select the correct equation that can be used to represent the lumens, L, after x screen layers are added. A. L = 750(0. 975)x B. L = 750(1. 25)x C. L = 750(0. 25)x D. L = 750(0. 75)x
The correct equation that can be used to represent the lumens, L, after x screen layers are added is L = 750(0.75)ˣ. (option d)
Equation A shows that the lumens decrease by 2.5% per layer added. This means that the amount of visible light decreases as more layers are added, which aligns with our common sense understanding.
Equation B shows an increase of 25% per layer added, which does not make sense as more screen layers would not increase the amount of visible light emitted.
Equation C shows a decrease of 75% per layer added, which is too drastic and would result in very low lumens after just a few layers.
Finally, Equation D shows a decrease of 25% per layer added, which is a reasonable amount and aligns with our common sense understanding of how screen layers impact the amount of visible light emitted.
Therefore, the correct equation is D: L = 750(0.75)ˣ.
This equation shows how the lumens decrease by 25% per layer added, which is a reasonable and expected amount.
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For the function f(x) = 2x^4 In x, find f'(x).
To find the derivative (f'(x)) of the function f(x) = 2x^4 In x, we will need to use the product rule and the chain rule of differentiation.
Using the product rule, we have:
f'(x) = [2(In x)](4x^3) + [2x^4](1/x)
Simplifying this expression, we get:
f'(x) = 8x^3 In x + 2x^3
Therefore, the derivative of f(x) is f'(x) = 8x^3 In x + 2x^3.
Hi! To find the derivative f'(x) of the function f(x) = 2x^4 * ln(x), we'll use the product rule. The product rule states that if you have a function h(x) = u(x)v(x), then h'(x) = u'(x)v(x) + u(x)v'(x). In this case, u(x) = 2x^4 and v(x) = ln(x).
First, find the derivatives of u(x) and v(x):
u'(x) = d(2x^4)/dx = 8x^3
v'(x) = d(ln(x))/dx = 1/x
Now, apply the product rule:
f'(x) = u'(x)v(x) + u(x)v'(x)
f'(x) = (8x^3)(ln(x)) + (2x^4)(1/x)
Simplify the expression:
f'(x) = 8x^3 * ln(x) + 2x^3
This is the derivative of the given function.
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Which pair of lines in this figure are perpendicular?
A.
lines B and F
B.
lines F and D
C.
lines C and E
D.
lines A and D
Answer:
D. Lines A and D are perpendicular.
DAnswer:
Step-by-step explanation:
Can u please help me solve this and explain how you got it please.
8xsquared-2-5x=8
Find the x
Using quadratic formula, the value of x in the quadratic equation are 1.47 and -0.85
What is the value of x?To find the value of x, we can either use quadratic formula or factorization method.
8x² - 2 - 5x = 8
Let's rewrite the equation properly
8x² - 5x - 2 - 8 = 0
8x² - 5x - 10 = 0
a = 8, b = -5, c = -10
Using quadratic formula;
-b ±[√b² - 4ac / 2a]
-(-5) ±[√(-5)² - 4(8)(-10) / 2(8)]
x = 5+ √345 / 16 or x = 5 - √345 / 16
x = 1.47 or x = -0.85
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Ranjan is driving to Salt Lake City. His car gets 35. 5 miles per gallon of gasoline. Ranjan starts with his tank full. So far he has made two stops. Each time he stops, ranjan adds gas until his car is full again. At the first stop ranjan adds 6. 7 gallons of gas. At he second stop he adds 3. 4 gallons of gas. How many miles has ranjas drivin so far
After calculating the distance, Ranjan has driven 358.55 miles so far.
To solve this problem, we need to use the formula:
distance = fuel efficiency x fuel consumed
Let's start by calculating the total fuel consumed. At the first stop, Ranjan adds 6.7 gallons of gas, which means he consumed 6.7 gallons of gas since his tank was full at the beginning of the trip. At the second stop, he adds 3.4 gallons of gas, which means he consumed 3.4 gallons of gas between the first and second stops. Therefore, the total fuel consumed is:
6.7 + 3.4 = 10.1 gallons
Now we can calculate the distance driven using the fuel efficiency of 35.5 miles per gallon:
distance = 35.5 miles/gallon x 10.1 gallons = 358.55 miles
Therefore, Ranjan has driven 358.55 miles so far.
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Please help me ill give out brainest
which expression is equivalent to 1/5x(5y+60)
a. 1/5(2xy+3xy+40x)
b. xy+60x
c. y+12x
d. 25xy+300y
e. 13xy
f. x(y+12)
Answer:
The correct answer is ** x(y+12) or f.
We can simplify the expression 1/5x(5y+60) by multiplying the factors in the parentheses and then dividing by 5. This gives us:
```
1/5x(5y+60) = 1/5 * 5xy + 1/5 * 60x = x(y+12)
```
Which equation correctly describes the relationship between x and y in the table?
A. y = 2x - 5
B. y = x
C. y = x - 3
D. y = 1/2x + 1
It's "D"
It's self explanatory but y gets 1/2 of whatever x is and adds 1. So if x = 2, then it'll get half of two (which is one) and add one to it, getting two.
Sharla wanted to know how many minutes per hour a radio station typically plays music. She collected the following data from
stations,
Radio Station Music
36
30 31 32 33 34 35
Minutes per Hour
By how many minutes would her median time change if she added another radio station playing 37 minutes?
O A.
0. 45
OB.
0. 5
OC.
the median did not change
OD.
0. 4
Median time change in 0.5 minutes if she added another radio station playing 37 minutes
To determine how many minutes the median time would change after adding a radio station playing 37 minutes of music per hour, follow these steps:
1. Arrange the given data in ascending order:
30, 31, 32, 33, 34, 35, 36
2. Find the median of the original data:
There are 7 data points, so the median is the middle value: 33 minutes.
3. Add the new radio station data (37 minutes) and arrange in ascending order:
30, 31, 32, 33, 34, 35, 36, 37
4. Find the new median after adding the radio station:
There are now 8 data points, so the median is the average of the two middle values (32 and 33): (32 + 33) / 2 = 32.5 minutes.
5. Determine the change in the median:
New median (32.5) - Original median (33) = -0.5
So, by adding another radio station playing 37 minutes of music per hour, her median time would change by -0.5 minutes (or decrease by 0.5 minutes). The correct answer is B. 0.5 minutes.
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If 3/10 of a number is equal to 1/4 what is the number
Answer:
10/12
Step-by-step explanation:
(3/10)x=1/4
3x=10/4
x=10/12
5. a space shuttle traveling at 17,581 miles per hour decreases its speed by 7,412 miles per hour. estimate the speed of the space shuttle after it has slowed down by rounding each number to the nearest hundred.
The rounding method used, the estimated speed of the space shuttle after it has slowed down is 10,200 miles per hour.
To estimate the speed of the space shuttle after it has slowed down, we round each number to the nearest hundred. The speed before the decrease is rounded to 17,600 miles per hour, and the decrease in speed is rounded to 7,400 miles per hour.
Next, we subtract the rounded decrease in speed from the rounded speed before. So, 17,600 - 7,400 = 10,200 miles per hour. This result represents the estimated speed of the space shuttle after it has slowed down.
Rounding to the nearest hundred is a way to approximate the values and make calculations simpler. However, it is important to note that rounding introduces some degree of error, and the actual speed after the decrease may differ slightly from the estimated value.
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What is the multiplicity of the zero of the polynomial function that represents the volume of a sphere with radius x+5
The graph of the function will touch the x-axis at x = -5, but not cross it, and the behavior of the graph near x = -5 will be determined by the degree of the zero (which is 3 in this case).
The polynomial function that represents the volume of a sphere with radius x+5 is given by:
[tex]V(x) = (4/3)\pi (x+5)^3[/tex]
To find the multiplicity of the zero, we need to factor out the (x+5) term from the polynomial:
V(x) = (4/3)π(x+5)(x+5)(x+5)
We can see that the zero is x = -5, and it has a multiplicity of 3, since there are three factors of (x+5) in the polynomial.
This means that the graph of the function will touch the x-axis at x = -5, but not cross it, and the behavior of the graph near x = -5 will be determined by the degree of the zero (which is 3 in this case).
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F(x): (x+7)/(x+5) and g(x): 7x/(x^2-3x-40)
add the functions and show all steps
explain the steps to solve Rational Function
The value of the addition of the functions:
F(x) + g(x) = (8x² + 34x - 56)/(x²-3x-40).
To add the two rational functions F(x) and g(x), we first need to find a common denominator. In this case, the common denominator is (x+5)(x-8), since both denominators can be factored in this way.
F(x) needs to be multiplied by (x-8) on the top and bottom to get a common denominator of (x+5)(x-8), and g(x) needs to be multiplied by (x+5) on the top and bottom to get the same common denominator.
So, we have:
F(x) = (x+7)/(x+5) * (x-8)/(x-8) = (x² - x - 56)/(x² - 3x - 40)
g(x) = 7x/(x²-3x-40) * (x+5)/(x+5) = 7x(x+5)/(x+5)(x-8) = 7x(x+5)/(x²-3x-40)
Now that both functions have the same denominator, we can add them together:
F(x) + g(x) = (x² - x - 56)/(x² - 3x - 40) + 7x(x+5)/(x²-3x-40)
To simplify this expression, we need to combine the two fractions over the common denominator:
F(x) + g(x) = (x² - x - 56 + 7x² + 35x)/(x²-3x-40)
Combining like terms in the numerator:
F(x) + g(x) = (8x² + 34x - 56)/(x²-3x-40)
So, F(x) + g(x) = (8x² + 34x - 56)/(x²-3x-40).
To solve a rational function, we generally follow these steps:
Factor the numerator and denominator as much as possible.Determine any restrictions on the domain of the function (values of x that make the denominator equal to zero).Simplify the function by canceling any common factors.Write the function in lowest terms.Determine any asymptotes (vertical, horizontal, or slant) and intercepts.Graph the function.In the case of F(x) and g(x), we already simplified the sum of the functions. We can see that the denominator factors as (x+5)(x-8), which means that the function is undefined at x = -5 and x = 8. These are vertical asymptotes.
To find any horizontal asymptotes, we can use the fact that the degree of the numerator is greater than or equal to the degree of the denominator. This means that there is no horizontal asymptote; instead, the function approaches infinity as x approaches infinity or negative infinity.
Finally, we can graph the function using this information and any other relevant points, such as intercepts.
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A rocket can rise to a height of
h(t)=t^3+0.6t^2 feet in t seconds. Find its velocity and acceleration 8 seconds after it is launched,
Velocity = ____
Acceleration = _____
To find the velocity and acceleration 8 seconds after the rocket is launched, we need to find the first and second derivatives of the height function with respect to time.
The first derivative of h(t) gives the velocity function v(t):
v(t) = h'(t) = 3t^2 + 1.2t
Substituting t = 8 into this equation gives us the velocity of the rocket at 8 seconds after launch:
v(8) = 3(8)^2 + 1.2(8) = 204.8 feet per second
So the velocity of the rocket 8 seconds after launch is 204.8 feet per second.
The second derivative of h(t) gives the acceleration function a(t):
a(t) = h''(t) = 6t + 1.2
Substituting t = 8 into this equation gives us the acceleration of the rocket at 8 seconds after launch:
a(8) = 6(8) + 1.2 = 49.2 feet per second squared
So the acceleration of the rocket 8 seconds after launch is 49.2 feet per second squared.
To find the velocity and acceleration of the rocket 8 seconds after it is launched, we need to determine the first and second derivatives of the height function h(t) with respect to time t.
Given h(t) = t^3 + 0.6t^2, let's find its first and second derivatives:
1. Velocity (first derivative of h(t)):
v(t) = dh/dt = 3t^2 + 1.2t
2. Acceleration (second derivative of h(t)):
a(t) = d^2h/dt^2 = d(v(t))/dt = 6t + 1.2
Now, let's evaluate the velocity and acceleration at t = 8 seconds:
Velocity at t=8:
v(8) = 3(8^2) + 1.2(8) = 192 + 9.6 = 201.6 ft/s
Acceleration at t=8:
a(8) = 6(8) + 1.2 = 48 + 1.2 = 49.2 ft/s^2
So, 8 seconds after the rocket is launched, its velocity is 201.6 ft/s and its acceleration is 49.2 ft/s^2.
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Write a polynomial function of least degree with integral coefficients that has the given zeros.
-5, -3-2i
Answer:
[tex]f(x)=x^3+11x^2+43x+65[/tex]
Step-by-step explanation:
If a polynomial function has a complex zero, then the conjugate of that complex zero is also a zero of the polynomial.
So, if (-3 - 2i) is a zero of the polynomial, then its conjugate (-3 + 2i) is also a zero of the polynomial.
Therefore, the three zeros of the polynomial function are:
-5(-3 - 2i)(-3 + 2i)The zero of a polynomial f(x) is the x-value when f(x) = 0.
According to the factor theorem, if f(a) = 0 then (x - a) is a factor of the polynomial f(x).
Therefore, the polynomial function in factored form is:
[tex]\begin{aligned}f(x) &= (x - (-5))(x-(-3-2i))(x-(-3+2i))\\&= (x +5)(x+3+2i)(x+3-2i)\end{aligned}[/tex]
Expand the brackets to write the polynomial in standard form.
[tex]\begin{aligned}f(x) &=(x +5)(x+3+2i)(x+3-2i)\\&=(x+5)(x^2+3x-2xi+3x+9-6i+2ix+6i-4i^2)\\&=(x+5)(x^2+6x+9-4i^2)\\&=(x+5)(x^2+6x+9-4(-1))\\&=(x+5)(x^2+6x+9+4)\\&=(x+5)(x^2+6x+13)\\&=x^3+6x^2+13x+5x^2+30x+65\\&=x^3+11x^2+43x+65\end{aligned}[/tex]
Therefore, the polynomial function of least degree with integral coefficients that has the given zeros -5 and (-3 - 2i) is:
[tex]f(x)=x^3+11x^2+43x+65[/tex]
f(x)=x3+11x²+43x+65