Jones Corporation has the following budgeted sales for the selected four-month period: Month Unit Sales July 20,000 August 35,000 September 25,000 October 30,000 Sales price per unit is $180 Plans are to have an inventory of finished product equal to 20 percent of the unit sales for the next month. There were 4,000 units in beginning inventory on July 1. Three pounds of materials are required for each unit produced. Each pound of material costs $20. Inventory levels for materials equal 30 percent of the needs for the next month. Desired ending inventory for September is 25,200 pounds of material. Beginning inventory for July was 20,700 pounds of material. Each unit requires 0. 6 hours of direct labor and the average wage rate is $16 per hour. Variable overhead rate is $3. 50 per direct labor hour. There is also fixed overhead of $22,000 per month. The company pays a 3% commission on sales. The Company has fixed selling and administrative expenses as follows: Rent $6,000/month Utilities $1,200/month Advertising $400/month Office Salaries $35,000/month Required: If required, round your answers to two decimal places. A. Prepare a sales budget for July, August, and September and in total for the quarter. Jones Corporation Sales Budget July August September Total Units to be sold fill in the blank 6165fff8cfc9fd8_1 fill in the blank 6165fff8cfc9fd8_2 fill in the blank 6165fff8cfc9fd8_3 fill in the blank 6165fff8cfc9fd8_4 Sales price $fill in the blank 6165fff8cfc9fd8_5 $fill in the blank 6165fff8cfc9fd8_6 $fill in the blank 6165fff8cfc9fd8_7 $fill in the blank 6165fff8cfc9fd8_8 Total sales dollars $fill in the blank 6165fff8cfc9fd8_9 $fill in the blank 6165fff8cfc9fd8_10 $fill in the blank 6165fff8cfc9fd8_11 $fill in the blank 6165fff8cfc9fd8_12 B. Prepare a production budget for July, August, and September and in total for the quarter. Jones Corporation Production Budget July August September Total Sales fill in the blank e6b46cf35019f97_1 fill in the blank e6b46cf35019f97_2 fill in the blank e6b46cf35019f97

Answers

Answer 1

Answer:

Step-by-step explanation:

A. Sales Budget:

To prepare the sales budget, we need to multiply the unit sales by the sales price per unit for each month. The sales budget for July, August, September, and the total quarter is as follows:

Jones Corporation Sales Budget

Month Unit Sales Sales price Total sales dollars

July 20,000 $180 $3,600,000

August 35,000 $180 $6,300,000

Sept 25,000 $180 $4,500,000

Total 80,000 $180 $14,400,000

B. Production Budget:

To prepare the production budget, we need to calculate the number of units to be produced each month to meet the sales demand and maintain the desired ending inventory level. The production budget for July, August, September, and the total quarter is as follows:

Jones Corporation Production Budget

Month Unit Sales Add: Desired Ending Inventory Total Units Needed Less: Beginning Inventory Units to be Produced

July 20,000 4,000 24,000 - 24,000

August 35,000 5,000 40,250 20,000 20,250

Sept 25,000 7,000 28,750 15,250 13,500

Total 80,000 16,000 93,000 35,250 57,750

Note: The desired ending inventory for finished goods for each month is calculated as 20% of the unit sales for the next month. For materials, the desired ending inventory for September is given as 25,200 pounds.

Therefore, we can calculate the total materials needed for September and subtract the desired ending inventory to find the materials to be purchased for September.

The production budget takes into account the inventory levels for both finished goods and materials.

We can now calculate the total direct materials needed, direct labor hours needed, and total manufacturing overhead costs for the quarter.

C. Direct Materials Budget:

To prepare the direct materials budget, we need to calculate the total materials needed for production and deduct the beginning inventory and desired ending inventory levels to determine the materials to be purchased each month.

The direct materials budget for July, August, September, and the total quarter is as follows:

Jones Corporation Direct Materials Budget

Month Units to be Produced Materials required per unit Total Materials Needed Add: Desired Ending Inventory Total Materials Required Less: Beginning Inventory Materials to be Purchased

July 24,000 3 72,000 - 72,000 20,700 51,300

August 20,250 3 60,750 7,500 68,250 51,300 16,950

Sept 13,500 3 40,500 25,200 65,700 36,300 29,400

Total      

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Related Questions

A digital timer counts down from 5 minutes (5:00) to 0:00 one second at a time. For how many seconds does at least one of the three digits show a 2?

Answers

84 seconds
At seconds 2,12,22,32,42,and 52 of minutes 0,1,3,4 that is 24 seconds plus all 60 seconds of minute 2

The required answer is the total number of seconds in which at least one of the three digits shows a 2 is 10 + 20 = 30 seconds. In other words, during the countdown from 5 minutes to 0:00, there are 30 seconds in which at least one of the three digits shows a 2.

To determine the number of seconds in which at least one of the three digits on a digital timer shows a 2 while counting down from 5 minutes (5:00) to 0:00, we need to consider the various possibilities.

Step 1: Determine the total number of seconds in 5 minutes.

There are 60 seconds in a minute, so 5 minutes would be equal to 5 * 60 = 300 seconds.

Step 2: Consider each second from 0 to 300 and check if any of the three digits (hundreds, tens, or ones) contains the digit 2.

To simplify the calculation, we can focus on the ones digit for the first 60 seconds (from 0:00 to 0:59). In this range, the ones digit contains the digit 2 ten times (2, 12, 22, 32, 42, 52, 62, 72, 82, 92). So, in the first minute, there are 10 seconds in which the ones digit shows a 2.

For the remaining 240 seconds (from 1:00 to 4:59), we need to consider both the tens and ones digits. In each minute within this range, the tens digit can have a digit 2 for all ten seconds (20, 21, 22, ..., 29). Additionally, the ones digit can have a digit 2 for ten seconds in each minute. So, in the remaining 240 seconds, there are 10 * 2 = 20 seconds in which at least one of the tens or ones digits shows a 2.

Therefore, the total number of seconds in which at least one of the three digits shows a 2 is 10 + 20 = 30 seconds.

Hence, during the countdown from 5 minutes to 0:00, there are 30 seconds in which at least one of the three digits shows a 2.

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Find u × v, v x u, and v x v.
u = 2i + 6k
v = 4i + 7j - 5k.

Answers

To find u × v, we use the cross product formula:

u × v = | i    j    k |
           | 2    0    6 |
           | 4    7   -5 |

Expanding the determinant, we get:

u × v = (0*-5 - 6*7) i - (2*-5 - 6*4) j + (2*7 - 0*4) k
u × v = -42i - 22j + 14k

To find v × u, we use the same formula but switch the order of u and v:

v × u = | i    j    k |
           | 4    7   -5 |
           | 2    0    6 |

Expanding the determinant, we get:

v × u = (7*6 - (-5)*0) i - (4*6 - (-5)*2) j + (4*0 - 7*2) k
v × u = 42i + 18j - 14k

Finally, to find v × v, we again use the cross product formula with v as both inputs:

v × v = | i    j    k |
           | 4    7   -5 |
           | 4    7   -5 |

Expanding the determinant, we get:

v × v = (7*(-5) - (-5)*7) i - (4*(-5) - (-5)*4) j + (4*7 - 7*4) k
v × v = 0i - 0j + 0k
v × v = 0

So the cross product of v with itself is the zero vector.
To find u × v, v × u, and v × v, we'll use the cross product formula:

u × v = (u_yv_z - u_zv_y)i + (u_zv_x - u_xv_z)j + (u_xv_y - u_yv_x)k

Given u = 2i + 6k and v = 4i + 7j - 5k, we have:

u_x = 2, u_y = 0, u_z = 6
v_x = 4, v_y = 7, v_z = -5

Now, calculate u × v:
(0 * (-5) - 6 * 7)i + (6 * 4 - 2 * (-5))j + (2 * 7 - 0 * 4)k
= (-42)i + (34)j + (14)k

u × v = -42i + 34j + 14k

Next, calculate v × u:
(7 * 6 - (-5) * 0)i + ((-5) * 2 - 4 * 6)j + (4 * 0 - 7 * 2)k
= (42)i + (-34)j + (-14)k

v × u = 42i - 34j - 14k

Finally, calculate v × v:
(7 * (-5) - (-5) * 7)i + ((-5) * 4 - 4 * (-5))j + (4 * 7 - 7 * 4)k
= (0)i + (0)j + (0)k

v × v = 0i + 0j + 0k

In summary:
u × v = -42i + 34j + 14k
v × u = 42i - 34j - 14k
v × v = 0i + 0j + 0k

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The figure 2 is dilated from figure 1. Find the scale factor.

Answers

Scale factor is 9/6 which simplifies to 3/2

Jayce has a cylindrical dowel that she cuts in parallel to the base , What is the circumference of the horizontal cross section of the dowel rounded to the nearest whole number

Answers

If the dowel has a radius of 3.5 cm, we can round it to 4 cm and use the formula to find an estimated circumference of C ≈ 2π(4) ≈ 25.1 cm.

When Jayce cuts the cylindrical dowel in parallel to the base, she creates a circular cross section. The circumference of a circle is the distance around its perimeter, and it can be calculated using the formula C = 2πr, where C is the circumference, π is the mathematical constant pi (approximately 3.14), and r is the radius of the circle.

Since the dowel is cylindrical, its cross section will also be a circle. Therefore, to find the circumference of the horizontal cross section of the dowel, we need to know the radius of the circle.

However, we can estimate the circumference by rounding the radius to the nearest whole number. For example, if the dowel has a radius of 3.5 cm, we can round it to 4 cm and use the formula to find an estimated circumference of C ≈ 2π(4) ≈ 25.1 cm. Rounded to the nearest whole number, the circumference would be 25 cm.

In summary, to find the circumference of the horizontal cross section of a cylindrical dowel that has been cut in parallel to the base, we need to know the radius of the resulting circle. We can estimate the circumference by rounding the radius to the nearest whole number and using the formula C = 2πr.

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Lesson 10. 3 name two streets that appear to be parallel

Answers

Answer:

Step-by-step explanation:

where are the streets

The prism is completely filled with 135 cubes that have edge length of 13ft. What is the volume of the prism?Enter your answer in the box

Answers

The volume of the prism is 2.98×10⁵ cubic feets according to the stated number and dimensions of constituting prism.

The volume of any shape is it's capacity to contain the item in it. It is the product of all its sides.

Volume of cube = side × side × side

Since there are multiple prisms of specific sides completely contained in the prism, their number will also be multiplied.

Volume of cube = 136 × 13 × 13 × 13

Performing multiplication on Right Hand Side of the equation

Volume of cube = 298,792 cubic feets

Hence, the volume of cube is 2.98×10⁵ cubic feet.

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The gcf of 16mn and 24m

Answers

1,2,4,8 because it’s the gcf
Answer: 8m

You’d first have to find all the favors of both numbers.

The highest number they both share is going to be your Greatest Common Factor (GCF).
If they share any letters, add those as well.

Hope this helps!

Kevin needs 2/3 of a yard to make a pillow. He has 3 1/3 yards of fabric. How many pillows can he make? A). 2 2/9 B. ) 3 2/3 C. ) 5 D. ) 6

Answers

The number of pillows requiring [tex]\frac{2}{3}[/tex] yards that can be made from [tex]3\frac{1}{3}[/tex] yards is 5. Thus the right answer to the given question is C.

Material required for making one pillow = [tex]\frac{2}{3}[/tex] yards

Total material = [tex]3\frac{1}{3}[/tex] yards

To find the number of pillows made we have to divide the material required for one pillow by the total material available to Kevin for making pillows

Number of pillows = [tex]3\frac{1}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex]

=  [tex]\frac{10}{3}[/tex] ÷ [tex]\frac{2}{3}[/tex]

To divide two fractions, we take the reciprocal of the second number and multiply it by the first number.

=  [tex]\frac{10}{3}[/tex] * [tex]\frac{3}{2}[/tex]

= 5

Thus, the number of pillows made is 5.

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For the week, Castle Manufacturing has a beginning cash balance of 100,000. They spend 99,000 on direct materials, 19,000 on direct labor, and 29,000 on manufacturing overhead. They also have cash sales of 10,000, accounts receivable collections of 220,000 and asset sales of 30,000. They also purchased assets in the amount of 20,000 and had sales commissions and other administrative expenses in the amount of 40,000. What was Castle Manufacturing cash balance at the end of the week?

Answers

Castle Manufacturing's cash balance at the end of the week would be $153,000.

To determine the cash balance, we must consider the beginning cash balance, cash inflows and cash outflows.

Beginning cash balance: $100,000
Cash inflows:
- Cash sales: $10,000
- Accounts receivable collections: $220,000
- Asset sales: $30,000
Total cash inflows: $260,000

Cash outflows:
- Direct materials: $99,000
- Direct labor: $19,000
- Manufacturing overhead: $29,000
- Purchase of assets: $20,000
- Sales commissions and administrative expenses: $40,000
Total cash outflows: $207,000

Ending cash balance: Beginning cash balance + Total cash inflows - Total cash outflows
= $100,000 + $260,000 - $207,000
= $153,000

Therefore, Castle Manufacturing's cash balance at the end of the week would be $153,000.

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QR has endpoints at Q(5, –6) and R(6, 3). Find the midpoint M of QR.

Answers

Answer:

(5.5, -1.5)

Step-by-step explanation:

(x, y)midpoint = (x1 + x2)/2 , (y1 + y2)/2

= (6 + 5)/2, (3 - 6)/2

= (11/2, -3/2)

= (5.5, -1.5)

Mr. ross needed a box for his tools. he knew that the box had to be between 100 cubic inches and 150 cubic inches. which dimension shows the tool he can use

Answers

Mr. Ross can choose any dimensions for the length, width, and height as long as their product falls within the given volume range of 4 * 5 * 5 to 6 * 5 * 5 cubic inches.

To help you find the dimensions for Mr. Ross's tool box that can hold between 100 and 150 cubic inches, let's consider the following terms: volume, length, width, and height.

1. Volume: The space occupied by the tool box, which should be between 100 and 150 cubic inches.


2. Length, Width, and Height: The dimensions of the tool box that will determine its volume.

To find the dimensions for the tool box that meets Mr. Ross's requirements, we can use the formula for volume of a rectangular box:

Volume = Length × Width × Height

We need to find the Length, Width, and Height such that 100 ≤ Volume ≤ 150.

Unfortunately, without more specific information about the dimensions Mr. Ross prefers or the shape of the box, we cannot provide an exact set of dimensions. However, he can choose any dimensions for the length, width, and height as long as their product falls within the given volume range of 100 to 150 cubic inches.

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Find the area of the following shape. You must show all work to recive credit.

this is a writting question

Answers

The total area of the given figure is 12 units²

In the given figure, we have 3 shapes. One is rectangle and the other two are triangles. We can find areas of all three shapes and add to find the total area.

Finding area of the triangle ABC,

base of the triangle ABC = 4 units

height of the triangle ABC = 4 units

Area of the triangle ABC = 1/2 x base x height = 1/2 x 4 x 4 = 8 units²

Finding area of the triangle CDE,

base of the triangle CDE = 2 units

height of the triangle CDE = 2 units

Area of the triangle CDE = 1/2 x base x height = 1/2 x 2 x 2 = 2 units²

Finding area of the rectangle,

length of the rectangle = 2 units

breadth of the rectangle = 1 unit

Area of the rectangle = length x breadth = 2 x 1 = 2 units²

So, total area of the given figure = 8 units² + 2 units² + 2 units² = 12 units²

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A snack mix recipe calls for 5 3/4 cups of cereal and 3 5/12 cups less of raisins. how many cups of raisins are needed? write in simplest form

Answers

Answer is 7/3 cups.


To determine the amount of raisins needed for the snack mix, subtract 3 5/12 cups from 5 3/4 cups of cereal.

First, convert the mixed numbers to improper fractions:
5 3/4 = (5 × 4 + 3)/4 = 23/4
3 5/12 = (3 × 12 + 5)/12 = 41/12

Next, subtract the two fractions:
23/4 - 41/12

To subtract, find a common denominator. The least common multiple of 4 and 12 is 12. Convert both fractions to equivalent fractions with a denominator of 12:
(23/4) × (3/3) = 69/12
(41/12) × (1/1) = 41/12

Now, subtract the fractions:
69/12 - 41/12 = 28/12

Finally, simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor (4):
28/12 = (28 ÷ 4)/(12 ÷ 4) = 7/3

So, you need 7/3 cups of raisins for the snack mix.

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Order from least to greatest
30.
4,0.91,8
50

Answers

Answer:

0.91

30.4

850

Step-by-step explanation:

Cathy works at a restaurant. On Monday, she served 9 tables with 6 people at each table. On Tuesday, she served 86 people. She wants to know how many more people she served on Tuesday than on Monday.



Select the correct operations from the drop-down menus to represent this problem using equations.



9


Choose.


6 = m



86


Choose.


54 = d

Answers

Cathy served 32 more people on Tuesday than on Monday.

Given, on Monday, Cathy served 9 tables with 6 people at each table. On Tuesday, Cathy served 86 people. We have to find the number of people she served more on Tuesday than on Monday.

So, on Monday she served = 9 tables x 6 people per table

= 54 people.

To find out how many more people Cathy served on Tuesday than on Monday, we can subtract the number of people served on Monday from the number served on Tuesday.

i.e. 86 - 54 = 32.

Therefore, Cathy served 32 more people on Tuesday than on Monday.

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What is the lateral area of the cone to the nearest whole number? The figure is not drawn to scale.
*
Captionless Image
34311 m^2
18918 m^2
15394 m^2
28742 m^2

Answers

The lateral area of the cone is 18918 m²

How to find the lateral area of the cone?

The lateral area of the cone can be determined using the formula:

A[tex]_{L}[/tex] = πrL

Where is the r is the radius of circular base of the cone and L is the slant height

In this case:

r = 140/2 = 70m

L = √(50² + 70²)   (Pythagoras theorem)

L = 10√74 m

A[tex]_{L}[/tex] = π * 70 * 10√74

A[tex]_{L}[/tex] = 18918 m²

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A study of the demand for air travel between two cities depends on the airfare according to the following demand equation. q=55.1−0.023p

Answers

The demand equation can be used to estimate the demand for air travel at different price levels, and can help airlines make pricing decisions based on the expected demand.

The demand equation is given as:

q = 55.1 - 0.023p

where q is the quantity demanded and p is the price of the airfare.

This equation shows an inverse relationship between price and quantity demanded. As the price of the airfare increases, the quantity demanded decreases, and vice versa.

For example, if the airfare price is $100, we can calculate the quantity demanded as:

q = 55.1 - 0.023(100) = 52.8

This means that at a price of $100, the quantity demanded is approximately 52.8 units.

Similarly, if the airfare price is $200, we can calculate the quantity demanded as:

q = 55.1 - 0.023(200) = 50.4

This means that at a price of $200, the quantity demanded is approximately 50.4 units.

So, demand equation can be used to estimate the demand for air travel at different price levels, and can help airlines make pricing decisions based on the expected demand.

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1
(Lesson 8.2) Which statement about the graph of the rational function given is true? (1/2 point)
4. f(x) = 3*-7
x+2
A. The graph has no asymptotes.
B.
The graph has a vertical asymptote at x = -2.
C. The graph has a horizontal asymptote at y =
+

Answers

The statement about the graph of rational function which is true is option B.  that is "The graph has a vertical asymptote at x = -2

What is a rational function?

A rational function in mathematics is any function that can be described by a rational fraction, which is an algebraic fraction in which both the numerator and denominator are polynomials.

So the statement about the graph of the rational function indicated above is true, this is because the denominator of the rational function is (x+2), which equals zero when x=-2. Therefore, the function is undefined at x=-2 and the graph has a vertical asymptote at that point.

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Solve the equation and check your solution: -2(x - 1) = 2 - 2x

Answers

-2x+2=2-2x
-2+2x=2-2
X=0

Making this equation true as both sides have the same answer

The world's population can be projected using the following exponential growth

model. using this function, a= pert, at the start of the year 2022, the world's

population will be around 7. 95 billion. the current growth rate is 1. 8%. in what

year would you expect the world's population to exceed 10 billion?

Answers

We can expect the world's population to exceed 10 billion around the year 2038, based on the given growth rate and exponential growth model.

Using the exponential growth model, the world's population (P) can be projected with the formula P = P0 * e^(rt), where P0 represents the initial population, r is the growth rate, t is time in years, and e is the base of the natural logarithm (approximately 2.718).

In this case, the initial population (P0) at the start of 2022 is 7.95 billion, and the current growth rate (r) is 1.8%, or 0.018 in decimal form.

To estimate when the population will exceed 10 billion, we can rearrange the formula as follows: t = ln(P/P0) / r. We want to find the year (t) when the population (P) surpasses 10 billion.

By plugging in the values, we get: t = ln(10/7.95) / 0.018. Calculating this, t ≈ 15.96 years.

Since we're starting from 2022, we need to add this value to the initial year: 2022 + 15.96 ≈ 2038.

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We would expect the world's population to exceed 10 billion in the year 2036 (2022 + 14.6).

How to find the  growth population?

The exponential growth model is given by:

P(t) = P0 * [tex]e^(^r^t^)[/tex]

where P0 is the initial population, r is the annual growth rate as a decimal, and t is the time in years.

From the problem, we know that:

P0 = 7.95 billion

r = 0.018 (1.8% as a decimal)

P(t) = 10 billion

We want to solve for t in the equation P(t) = 10 billion. Substituting in the values we know, we get:

10 billion = 7.95 billion *[tex]e^(0^.^0^1^8^t^)[/tex]

Dividing both sides by 7.95 billion, we get:

1.26 = [tex]e^(0^.^0^1^8^t^)[/tex]

Taking the natural logarithm of both sides, we get:

ln(1.26) = 0.018t

Solving for t, we get:

t = ln(1.26)/0.018

Using a calculator, we get:

t ≈ 14.6 years

So, we would expect the world's population to exceed 10 billion in the year 2036 (2022 + 14.6).

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A measure of goodness of fit for the estimated regression equation is the.

Answers

A measure of goodness of fit for the estimated regression equation is the residual standard error (RSE)

It is a measure of goodness of fit for the estimated regression equation. It measures the average amount that the response variable (y) deviates from the estimated regression line, in the units of the response variable.

The RSE is calculated as the square root of the sum of squared residuals divided by the degrees of freedom. A smaller RSE indicates a better fit of the regression line to the data.

It represents the proportion of the variation in the dependent variable that is explained by the independent variable(s) in the model. The value of R-squared ranges from 0 to 1, with higher values indicating a better fit of the model to the data.

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When he was 30, Kearney began investing $200 per month in various securities for his retirement savings. His investments averaged a 5. 5% annual rate of return until he retired at age 68. What was the value of Kearney's retirement savings when he retired? Assume monthly compounding of interest

Answers

To calculate the value of Kearney's retirement savings when he retired, we need to use the formula for compound interest:

A = P(1 + r/n)^(nt)

where:
A = final amount
P = initial principal (the amount Kearney invested each month)
r = annual interest rate (5.5%)
n = number of times interest is compounded per year (12, since we're assuming monthly compounding)
t = number of years

First, we need to calculate the total number of payments Kearney made into his retirement savings:

68 - 30 = 38 years

Since Kearney made monthly payments, the total number of payments is:

38 years x 12 months/year = 456 payments

Next, we need to calculate the value of each payment after it has earned interest. We can use the same formula as above, but with t = 1 (since we're calculating the value of one payment period):

P' = P(1 + r/n)^(nt)
P' = 200(1 + 0.055/12)^(12*1)
P' = 200(1.00458333333)^12
P' = 200(1.00458333333)^12
P' = 200(1.00458333333)^12
P' = 243.382740047

So each $200 payment is worth $243.38 after one month of earning interest.

Now we can use the formula for the future value of an annuity to calculate the total value of Kearney's retirement savings:

A = P'[(1 + r/n)^(nt) - 1]/(r/n)
A = 243.38[(1 + 0.055/12)^(12*38) - 1]/(0.055/12)
A = 243.38[1.93378208462 - 1]/(0.055/12)
A = 243.38[34.3478377249]
A = $8,351.53

Therefore, the value of Kearney's retirement savings when he retired was approximately $8,351.53.

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When Kearney retired at age 68, the value of his retirement savings was $557,123.35.

To find the value of Kearney's retirement savings when he retired, we'll use the Future Value of an Annuity formula. Here are the given values and the formula:

Monthly investment (PMT) = $200

Annual interest rate (r) = 5.5% = 0.055

Monthly interest rate (i) = (1 + r)^(1/12) - 1 ≈ 0.004434

Number of years of investment (n) = 68 - 30 = 38 years

Number of months of investment (t) = 38 years * 12 months = 456 months

Future Value of Annuity (FV) formula:

FV = PMT * [(1 + i)^t - 1] / i

Now, we'll plug in the values and calculate the Future Value:

FV = 200 * [(1 + 0.004434)^456 - 1] / 0.004434

FV ≈ 200 * [12.2883] / 0.004434

FV ≈ 557123.35

The value of his retirement savings was approximately $557,123.35.

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Adcb is a rectangle. ac = 16 and bd = 2x + 4, find the value of x.

Answers

In a rectangle, the diagonals are equal in length. So we can write the equation: AC = BD or 16 = 2x + 4. Solving for x, we get x = 6.

List the defining attributes of each 3-D figure. Then name the figure.

Answers

Vertices faces and edges are only a few of the many attributes of three-dimensional shapes. The 3D shapes' faces are their flat exteriors. An edge is the section of a line where two faces converge.

List out the attributes of 3-D figures.

1) cube

A vertex is the intersection of three edges. A solid or three-dimensional form with six square faces is called a cube. These are the characteristics of the cube.

Every edge is equal.

8 vertex

6 faces  

12 edges

2) Cuboid

When the faces of a cuboid are rectangular, it is often referred to as a rectangular prism. The angles are all 90 degrees each. It has a cuboid.

8 vertex

6 faces

12 edges

3) Prism

A prism is a three-dimensional form with two equal ends, flat faces, and identical sides.l cross-section down the length of it. The prism is typically referred to as a triangular prism since its cross-section resembles a triangle. There is no bend to the prism. A prism has also

6 vertex

9 edges

2 triangles and 3 rectangles

5 faces.

4) Pyramid

A pyramid is a solid object with triangle exterior faces that converge at a single point at its summit. The base of the pyramid may be triangular, square, quadrilateral, or any other polygonal shape. The square pyramid, which has a square base and four triangular faces, is the type of pyramid that is most frequently employed. Take a look at a square pyramid.

5 vertices

5 faces

8 edges

5) Cylinder

The term "cylinder" refers to a three-dimensional geometrical shape.two circular bases joined by a curving surface make up this figure. In a cylinder,

no vertex

2 edges

2 circles on flat faces

one curving face

6) Cone

A cone is a three-dimensional thing or solid with a single vertex and a circular base. A geometric shape known as a cone has a smooth downward slope from its flat, circular base to its top point or apex. In a cone

one vertex

1 edge

1 circle with a flat face.

one curving face

7) Sphere

A sphere is a perfectly round, three-dimensional solid figure, and every point on its surface is equally spaced from the point, which is known as the center. The radius of the sphere is the predetermined distance from the sphere's center.

a sphere is

zero vertex

zero edges

one curving face

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Find the area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2

Answers

The area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2 is 96π/5 square units.

To find the area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2, we can use the formula for surface area of revolution:
A = 2π ∫_a^b f(x) √(1+(f'(x))^2) dx
In this case, we need to first find the function y = f(x) that represents the curve. Using the given parametric equations, we can eliminate θ to get:
x = 6 cos^3 θ
x = 6 (1-sin^2 θ) cos^2 θ
y = 6 sin^3 θ
y = 6 (1-x/6)^(3/2)

So the function that represents the curve is y = 6 (1-x/6)^(3/2). Now we can use the formula for surface area of revolution:
A = 2π ∫_0^6 (6 (1-x/6)^(3/2)) √(1+(-3/4 (1-x/6)^(-1/2))^2) dx
A = 2π ∫_0^6 (6 (1-x/6)^(3/2)) √(1+9/16 (1-x/6)^(-1)) dx
A = 2π ∫_0^6 (6 (1-x/6)^(3/2)) √((25-9x)/(16(1-x/6))) dx
This integral can be evaluated using substitution and partial fractions. The final answer is:
A = 96π/5

Therefore, the area of the surface obtained by rotating the curve of parametric equations x = 6 cos^3 θ, y = 6sin^3 θ, 0 ≤ θ ≤ π/2 is 96π/5 square units.

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Find the value of m if third quartile (Q3) of the data given below is 128. (Income Rs. ) 0-30, 30-60, 60-90, 90-120, 120-150, 150-180 (No. Of Labour) 2, 8 ,22 ,24 ,m ,9​

Answers

The value of median m that makes Q₃ equal to 128 is approximately 18.75.

What is median?

The median is the value that divides the higher half of a population, a probability distribution, or a sample of data from the lower half. It can be conceptualised as a data set's "middle" value to put it simply.

To find the value of m, we need to first calculate the median and third quartile of the data.

To calculate the median, we need to find the value that splits the data into two halves. Since the data is already sorted into intervals, we can find the cumulative frequency for each interval and use it to determine the median interval. The median interval is the interval that contains the median. We can then use the formula for the median of grouped data to calculate the median value.

Cumulative frequency for each interval:

- Interval 0-30: 2

- Interval 30-60: 2+8=10

- Interval 60-90: 10+22=32

- Interval 90-120: 32+24=56

- Interval 120-150: 56+m

- Interval 150-180: 56+m+9=65+m

Since there are 6 intervals, the median interval is the 3rd interval, which is 60-90. The lower limit of this interval is 60, and the cumulative frequency up to this interval is 32. The frequency of this interval is 22. Using the formula for the median of grouped data:

Median = L + ((n/2 - CF) / f) * w

where L is the lower limit of the median interval, CF is the cumulative frequency up to the median interval, n is the total sample size, f is the frequency of the median interval, and w is the width of the interval.

Plugging in the values, we get:

Median = 60 + ((50 - 32) / 22) * 30

Median = 60 + (18 / 22) * 30

Median = 60 + 15.45

Median ≈ 75.45

Now, to find the third quartile (Q₃), we need to find the value that splits the upper 50% of the data. Since Q₃ is the 75th percentile, the cumulative frequency up to Q₃ is 0.75 times the total sample size:

Q₃ = L + ((0.75 * n - CF) / f) * w

We know that Q₃ is 128, and we can plug in the values for L, n, CF, f, and w that correspond to the interval that contains Q₃:

128 = 120 + ((0.75 * 85 - 56 - m) / (24)) * 30

Simplifying and solving for m, we get:

m = 120 + ((0.75 * 85 - 56) / (24)) * 30 - 128

m ≈ 18.75

Therefore, the value of m that makes Q₃ equal to 128 is approximately 18.75.

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What is the solution to the equation log(4x + 4) = 2 ? show your work

Answers

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x = −1/2

Decimal Form:

x = −0.5

Step-by-step explanation:

Answer:

x = 24

Step-by-step explanation:

using the rule of logarithms

[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]

note that log x represents [tex]log_{10}[/tex] x

given

log(4x + 4) = 2 , then

4x + 4 = 10² = 100 ( subtract 4 from both sides )

4x = 96 ( divide both sides by 4 )

x = 24

Certain pieces of antique furniture increased very rapidly in price in the 1970s and 1980s. For example, the value of a particular rocking chair is well approximated by V = 115(1.6), where V is in dollars andtis the number of years since 1975. Find the rate, in dollars per year, at which the price is increasing.
rate = dollars/yr

Answers

The given equation for the value of the rocking chair is V = 115(1.6)^t, where t is the number of years since 1975. To find the rate at which the price is increasing, we need to find the derivative of this equation with respect to time:

dV/dt = 115(1.6)^t * ln(1.6)

This tells us that the rate of increase in value is proportional to the current value of the chair, which makes sense since the value is increasing at a faster rate as the chair becomes more valuable.

To find the rate in dollars per year, we can evaluate the derivative at t = 0 (since we want to know the rate at the present time, which is 2021 - 1975 = 46 years after 1975):

dV/dt = 115(1.6)^0 * ln(1.6) = 30.03

Therefore, the rate at which the price of the rocking chair is increasing is approximately $30.03 per year.
It seems that there is a missing exponent in the given formula for the value of the rocking chair. The correct formula should include an exponent 't' as in V = 115(1.6)^t, where V is the value in dollars and t is the number of years since 1975.

To find the rate at which the price is increasing, we need to find the derivative of the value function with respect to time (t). The derivative of V = 115(1.6)^t is dV/dt = 115 * ln(1.6) * (1.6)^t.

To find the rate in dollars per year, we need to evaluate this expression at a specific time (t). For example, to find the rate in the year 1980 (5 years since 1975), we can plug in t = 5:

Rate = 115 * ln(1.6) * (1.6)⁵ ≈ $419.20 per year

So, in 1980, the price of the rocking chair was increasing at a rate of approximately $419.20 per year.

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If θ is an angle in standard position whose terminal side passes through the point (4, 3), then tan2θ = _____.



3/2


24/7


7/24


21/32

Answers

To find the value of tan(θ), we first need to calculate the values of sine and cosine for the given point (4, 3) terminal side. We can use the Pythagorean theorem to find the length of the hypotenuse (r):

r = √((4)^2 + (3)^2) = √(16 + 9) = √25 = 5

Now, we can find sin(θ) and cos(θ) at the terminal side:

sin(θ) = opposite/hypotenuse = 3/5
cos(θ) = adjacent/hypotenuse = 4/5

Then, we can calculate tan(θ):

tan(θ) = sin(θ) / cos(θ) = (3/5) / (4/5) = 3/4

Now we need to find tan(2θ). We can use the double-angle formula for tangent:

tan(2θ) = (2 * tan(θ)) / (1 - tan^2(θ))

Substitute the value of tan(θ):

tan(2θ) = (2 * (3/4)) / (1 - (3/4)^2) = (3/2) / (1 - 9/16) = (3/2) / (7/16)

Now, we'll multiply by the reciprocal to solve for tan(2θ):

tan(2θ) = (3/2) * (16/7) = 24/7

So, tan2θ = 24/7. Your answer is: 24/7

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A toy train set has a circular track piece. The inner radius of the piece is 6 cm. One sector of the track has an arc length of 33 cm on the inside and 55 cm on the outside. What is the width of the track? *respost since people thought it would be funny to troll on my last. :/

Answers

The width of the toy train track is 4 cm.

To find the width of the toy train track, we need to consider the inner radius, the arc length of the inner sector, and the arc length of the outer sector.

Given:
Inner radius (r1) = 6 cm
Inner arc length (s1) = 33 cm
Outer arc length (s2) = 55 cm

Step 1: Find the central angle (θ) using the inner arc length and inner radius.
θ = s1/r1 = 33 cm / 6 cm = 5.5 radians

Step 2: Find the outer radius (r2) using the central angle and the outer arc length.
s2 = r2 × θ
55 cm = r2 × 5.5 radians
r2 = 55 cm / 5.5 radians = 10 cm

Step 3: Calculate the width of the track.
Width = Outer radius - Inner radius
Width = r2 - r1 = 10 cm - 6 cm = 4 cm

The width of the toy train track is 4 cm.

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