Answer:
20 L
Step-by-step explanation:
I am guessing that you meant should instead of shouldn't.
To solve this we can set the amount of 10% solution needed equal to x. This means that the 60% solution will be the remaining amount needed, so 50 L - x.
We can do 10%*x+60%*(50-x)=50*40%. Solving for x we get:
0.1*x+0.6*50-0.6*x=50*0.4
0.1*x+30-0.6*x=20
-0.5*x=-10
x=20
Use linear equation to calculate intercepts.
x minus one-half y = negative 4
Complete the table with values for a and b.
A 2-column table with 3 rows. Column 1 is labeled x with entries 0, negative 2, b. Column 2 is labeled y with entries a, 4, 0.
a =
b =
The x intercept of the linear equation is -4 and y intercept is 8.
Intercept of the linear equation
The intercept of the linear equation is calculated as follows;
x - y/2 = -4
make y the subject of the formula;
y/2 = x + 4
y = 2x + 8
y intercept is obtained at point, x = 0y = 0 + 8
y = 8
x intercept is obtained at point, y = 00 = 2x + 8
2x = -8
x = -4
Thus, the x intercept of the linear equation is -4 and y intercept is 8.
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Answer:
The x intercept of the linear equation is -4 and y intercept is 8
Step-by-step explanation:
Can you conclude that this parallelogram is a rectangle ? Explain. No;the diagonals do not bisect two angles of the parallelogram. No;the diagonals may not be congruent. Yes; the diagonals are perpendicular
The answer to the question on Parallelograms being rectangles is that; No; the diagonals may not be congruent
How to Identify the properties of a Parallelogram?1) We cannot conclude that the parallelogram is a rectangle but we can say that all rectangles are parallelograms.
2) The explanation for number 1 above is that the parallelogram's diagonals may not be equal or congruent but in rectangles diagonals are always equal and bisect each other.
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James is paid $18 an hour at his new job. He wishes to graph his total pay T, as a function of the number of hours, h. James works between 25 and 40 hours each week. Select from the drop-down menus to correctly complete each statement. To best show this information, the scale for the T-axis of his graph should go from 0 to at least Choose... , and the h-axis of his graph should go from 0 to at least Choose... .
Answer
T-axis of his graph should go from 0 to at least 720, and the h-axis of his graph should go from 0 to at least 40.
Explanation
We know form our problem that is the total pay, is the number of hours, and $18 is the rate per hour, so putting it all into an equation we get:
We also know that James works between 25 and 40 hours each week, so we can replace the number of hours in our equation to get how much he can make per week:
- For
- For
Now we know that he can make between $450 and $720 working between 25 and 40 hours per week. So, to best show this information the T-axis should go from 0 to at least 720; otherwise, we won't be able to show values between $450 and $720. Similarly, the h-axis should go form 0 to at least 40; otherwise, we wont be able to show values between 25 and 40 hours.
A random sample is selected from a population with mean = 100 and standard deviation = 10. Determine the mean and standard deviation of the x sampling distribution for each of the following sample sizes. (Round the answers to three decimal places.)
If N=41
If N=130
The mean and standard deviation of the x sampling distribution for each of the following sample sizes will be [tex]N(100,10/\sqrt{41} ), N(100,10/\sqrt{130} )[/tex].
What is the distribution of the sample mean for large samples?Suppose X has a distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma,[/tex]then,
the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with a mean equal to the mean of X, and a standard deviation equal to [tex]\sigma/\sqrt{n}[/tex]
Symbolically, we write it as:
[tex]X \sim N(\mu, \sigma) \implies \overline{X} \sim N(\mu,\sigma/\sqrt{n} )[/tex]
A random sample is selected from a population with a mean = of 100 and a standard deviation = of 10.
The mean and standard deviation of the x sampling distribution for each of the following sample sizes.
If N=41
[tex]X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{41} )[/tex]
If N=130
[tex]X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{130} )[/tex]
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Use the graph of the function provided to find the indicated values.
a) When x = -2, g(x) = 5.
b) When x = -4, g(x) = 7.
c) When g(x) = 6, x = -3
d) When g(x) = -1, x = 4
The quotient of (x5 – 3x3 – 3x2 – 10x + 15) and (x2 – 5) is a polynomial. What is the quotient?
The quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]
How to determine the quotient?The quotient can be represented as:
[tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]
Start by expanding the dividend
[tex]x^5 + 2x^3 - 5x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]
Rewrite as:
[tex]x^5 + 2x^3 - 3x^2 - 5x^3 - 10x + 15 \div x^2 - 5[/tex]
Factorize the dividend
[tex]x^2(x^3 + 2x - 3) - 5(x^3 + 2x - 3) \div x^2 - 5[/tex]
Factor out x^3 + 2x - 3
[tex](x^2- 5)(x^3 + 2x - 3) \div x^2 - 5[/tex]
Cancel out the common factor
[tex]x^3 + 2x - 3[/tex]
Hence, the quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]
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Answer: x3 + 2x – 3
Step-by-step explanation:
elect the correct answer.
which direction must the graph of f(x) = 2* be shifted to produce the graph of g(x) = 2(x+8)
OA. left
OB. right
O C.
down
OD.
The answer to this question is (A) left.
The midpoint of FG is point H at (–5, 2). One endpoint is G(–9, –6). What is the y-coordinate of the other endpoint? The y-coordinate of the other endpoint is
The y-coordinate of the other endpoint is 10 units.
The given coordinates are H (-5, 2) and G (–9, –6).
We need to find the y-coordinate of the other endpoint.
What is the midpoint formula?The mid-point formula is [tex](x, y)=(\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2})[/tex]
Now, [tex](-5, 2)=(\frac{x_{1} +(-9)}{2} , \frac{y_{1} +(-6)}{2})[/tex]
⇒[tex]2=\frac{y_{1}-6 }{2}[/tex]
⇒[tex]4=y_{1}-6[/tex]
⇒[tex]y_{1}=10[/tex]
Therefore, the y-coordinate of the other endpoint is 10 units.
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f(x)= 2x^3 + 6x^2 -5x - 3, g(x)= 3x-4 find (f-g)(x)
The difference in the given functions is 2x^3 + 6x^2 -8x + 1
Difference of functionsGiven the following function a shown
f(x)= 2x^3 + 6x^2 -5x - 3
g(x)= 3x-4
Take the difference
(f-g)(x) = f(x) - g(x)
Substitute
(f-g)(x) = 2x^3 + 6x^2 -5x - 3 - (3x - 4)
Expand
(f-g)(x) = 2x^3 + 6x^2 -5x - 3 - 3x + 4
(f-g)(x) = 2x^3 + 6x^2 -8x + 1
Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1
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Rationalize the denominator. [tex]\frac{9}{\sqrt{x+3} }[/tex] Simplest form
The result after rationalizing is [tex]\frac{9\sqrt{x+3} }{x+3}[/tex].
What is Rationalization?Rationalization can be considered as the process used to eliminate a radical or an imaginary number from the denominator of an algebraic fraction.
Here, given fraction
[tex]\frac{9}{\sqrt{x+3} }[/tex]
Multiply and divide by [tex]\sqrt{x+3}[/tex], we get
[tex]\frac{9}{\sqrt{x+3} } \frac{\sqrt{x+3} }{\sqrt{x+3} }[/tex] = [tex]\frac{9\sqrt{x+3} }{x+3}[/tex]
Thus, the result after rationalizing is [tex]\frac{9\sqrt{x+3} }{x+3}[/tex].
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Jessica and Josh are selling Entertainment Books to raise money for the art room at their school. One book sells for $15. Jessica received the prize for selling the most books in the school. Jessica sold 15 times more books than Josh. Together they sold 256 books. How many did each one of them sell?
Jessica sells = 240 books,
Josh sells = 16 books.
Given:-The price of one book is = $15
Jessica sold 15 times more books than Josh.
In total, they have sold 256 books.
Solution:-We can easily find the answer using variables.
Let,
Josh sold a total of x books whereas Jessica sold a total number of 15x books.
together they sold 16x books.
So we can form the equation
16x= 256
by solving this equation we will get x=16
So, Josh sold 16 books and Jessica sold 16×15=240 books in total.
Answer:
Jessica=240
Josh=15
Step-by-step explanation:
ASAP AWNSER PLSSS!
Determine how far away the number -2 is from 0. Then, choose a positive number and a negative number that is each farther away from zero than is the number -2.
Answer:
it is 2 spaces away. a positive number from zero would be +2 and a negative number would be -2
Step-by-step explanation:
Please answer BOTH the questions tyyyyyysm
C and A
X = at least 45 and more
This means we need to have a full closed dot.
It's A because the question says more than 75 ft meaning only open dots.
1.8(1.1x−1.3)−1.88=−24.02
The solution will be x= -10
Simplifying the given expression
[tex]1.8(1.1x - 1.3) - 1.88 = - 24.02[/tex]
Step1: Convert decimal to fraction
[tex]1.8( \frac{11x}{10} - 1.3) - 1.88 = - 24.02[/tex]
[tex]1.8( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]
[tex]\frac{18}{10} ( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]
Step2: Make denominator common
[tex]\frac{18}{10} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]
Step3: Simplifying the fraction
[tex]\frac{9}{5} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]
Step4: Make denominator common
[tex] \frac{9(11x - 13)}{5 \times 10} - \frac{1.88 \times 50}{50} = - 24.02[/tex]
[tex] \frac{9(11x - 13)}{50} - \frac{94}{50} = - 24.02[/tex]
[tex] \frac{9(11x - 13 - 94)}{50} = - 24.02[/tex]
[tex] \frac{99x - 117 - 94}{50} = - 24.02[/tex]
Step5: Simplifying
[tex] \frac{99x - 211}{50} = - 24.02[/tex]
[tex] 99x - 211 = - 24.02 \times 50[/tex]
[tex] 99x - 211 = - 1201[/tex]
[tex] 99x = - 1201 + 211[/tex]
[tex] 99x = - 990[/tex]
[tex] x = \frac{ - 990}{99} [/tex]
[tex]x = - 10[/tex]
Hence, the solution x=-10
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How to convert from vertex to standard y=2(x-2)^2 -2 to standard
The quadratic equation in standard form is:
[tex]y = 2x^2 - 8x + 6[/tex]
How to convert from vertex form to standard?
Here we have the quadratic equation:
[tex]y = 2*(x - 2)^2 - 2[/tex]
Here we need to expand the right side, remember:
[tex](a + b)^2 = a^2 + 2ab + b^2[/tex]
Using that, we get:
[tex]y = 2*(x - 2)^2 - 2 = 2*(x^2 - 4x + 4) - 2\\\\y = 2x^2 - 8x + 8 - 2\\\\y = 2x^2 - 8x + 6[/tex]
This is the quadratic equation in standard form.
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Which Graph Represents A function ?
NEED ANSWER ASAP !!!!
Answer:
The very last one is a function
Step-by-step explanation:
The last one is a function because there are no y values that repeat. For example, If the points on one graph are like this; (1, 3) (2, 3); then it cannot be a function, the y values cannot repeat if it is a function.
To make things easier, just try to imagine vertical drawing lines through each point in every graph, if this imaginary vertical line passes more than one point in any graph, then that graph is not a function.
I hope this helps!! :D
Answer:
The last graph represents a function.
Explanation:
A function cannot be one-to-many, i.e., one value of x cannot produce multiple values of y.
In the first graph, when x = 1, y = 3 and y= -2, so it is not a function.
In the second graph, when x = 2, y = 2 and y = -2, so it's not a function.
In the third graph, when x = -3, y = 2 and y = -2, so it's not a function.
∴ In all the graphs except the last, single values of x give multiple values of y on the graph, so they are not functions.
1
2.
3
5 5
6
8
9
12
13
10-
8
6
909
NS
2
-6 -5 -4 -3 -2 -1 1 2 3 4
1 2 3 4 5 6 X
f
-6
-8
-10
-12-
-141
1 1 1
NO
w
f(4) = g(4)
Of(4) = g(-2)
O f2) = g(-2)
Of(-2) = g(-2)
Mark this and return
Answer: f(-3)=g(-3)
Step-by-step explanation:
The graphs intersect at x = -3.
The correct option is f(-3) = g(-3).
What is function?A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Given that two lines are intersecting at point (-3, -4)
Therefore the system of equations of these two have a solution at (-3, -4)
So, if taking the lines as function,
We have f(x) and g(x),
so both of them are intersecting at (-3, -4) so the range when the domain is -3 will be equal.
Hence the correct option is f(-3) = g(-3).
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The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers. ( 4, 5)( -8, -9)(-5, -6)
Answer:
(-5, -6)
Step-by-step explanation:
The smaller integer is x.
The larger integer is x + 1.
x + 1 = 7 + 2x
-x = 6
x = -6
x + 1 = -6 + 1 = -5
Answer: (-5, -6)
There is a 50% chance of rain here and a 25% chance of rain on Mars. Therefore, there is a 75%
chance that it will rain here or on Mars. Explain why this is a false statement.
There is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.
What is probability?It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
There is a 50% chance of rain here and a 25% chance of rain on Mars. Therefore, there is a 75% chance that it will rain here or on Mars.
The probability that it will rain here:
P(rain here) = 50%
P(rain on mars) 50%
P(not rain here) = 100 - 50 = 50%
P(not rain on mars) = 100 - 50 = 50%
P(rain here and not on mars) = 0.5×0.5 = 0.25 or 25%
Thus, there is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.
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At 50 minutes how far is the winning runner use ur equations
Answer:
3.5 km
Step-by-step explanation:
Ms. Mather filled 8 3/4 gallons of gas in her car's fuel tank. The car used up 3 1/2 gallons when she visited a friend in a neighboring town. How many gallons of gas are left in Ms. Mather's fuel tank?
Answer: [tex]5\frac{1}{4}[/tex] gallons are left
Step-by-step explanation:
convert to mixed number...
[tex]8\frac{3}{4} = \frac{35}{4}[/tex]
[tex]3 \frac{1}{2} = \frac{7}{2}[/tex] or [tex]\frac{14}{4}[/tex]
[tex]\frac{35}{4} -\frac{14}{4}=\frac{21}{4}[/tex]
[tex]\frac{21}{4} =5\frac{1}{4}[/tex]
therefore, [tex]5\frac{1}{4}[/tex] gallons are left in Ms. Mather's fuel tank
Answer:
5 1/4 gallons are left... correct
Can you do this because it is confusing to me
A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The volume of the cylinder is 1330.4644 cm³.
What is a cylinder?A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The circular bases' centers overlap each other to form a right cylinder.
Given the height of the cylinder is 14 cm, while the diameter of the cylinder is 11 cm. Therefore, the volume of the cylinder can be written as,
The volume of the cylinder = (π/4)×(D²) × H
= (π/4)×(11)² × 14
= 1330.5 cm³
Hence, the volume of the cylinder is 1330.5cm³.
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This is my last question on my homework. pls help
Answer:
740
Step-by-step explanation:
$415-$230=$185
$185×0.25=740 max miles
Mario was riding a bicycle with wheels 26 inches in diameter. During one minute of Mario’s ride, the wheels made exactly 200 revolutions. At what average speed, in feet per second, was Mario riding during that minute?
The correct answer is A.
Step - by - step answer:
Mario will travel a distance equal to 1 circumference of the wheel for each complete revolution of the wheel.
Circumference of Mario's wheel, C = πD, where D is the diameter of the circle.
Hence, C = 26π inches
Speed = Distance / Time
Distance for 200 revolutions in ft = 26π x 200 x 1/12
Time in sec = 60
So, speed = (26π x 200)/(12 x 60)
= 65π/9
=22.69 is the average speed.
P.s: Answer is copied from https://www.myactguide.com/math/mario-was-riding-a-bicycle-with-wheels-26-inches-in-diameter
Please answer the question down below!! <3
Answer:
4 inches
Step-by-step explanation:
In a regular pentagon, all sides are equal in length
The average THC content of marijuana sold on the street is 10.9%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street
(a) X ≈ N (0.10 , 0.02²)
(b) The probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.
(c) The 60th percentile is 11%.
The complete question is:The average THC content of marijuana sold on the street is 10%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to two decimal places and give THC content in units of percent. For example, for a THC content of 11%, write "11" not 0.11.A. X ~ N( , )
B. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11%.
C. Find the 60th percentile for this distribution.
According to the question,
The random variable X is defined as the THC content for a bag of marijuana that is sold on the street.
(a)The random variable X is Normally distributed with mean, μ = 0.10 and standard deviation, σ = 0.02.
Therefore, X ≈ N (0.10 , 0.02²)
(b) The value of P (X > 0.11) as follows:
P (X > o.11_ = P(X -μ/a > [tex]\frac{0.11-0.10}{0.02} \\[/tex])
= P(Z > 0.50)
= 1 -P (Z <0.50)
= 1- 0.69146
= 0.30854 ≈ 0.31
Hence,
the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.
(c)Let x represent the 60th percentile value.
Then, P (X < x) = 0.60.
⇒ P (Z < z) = 0.60
The value of z is,
z = 0.26.
Now put the value of x as follows:
z = x - μσ
0.26 = x - 0.100.02
x = 0.10+ ( 0.26 x 0.02)
x = 0.1052
x ≈ 0.11
Therefore,
The 60th percentile is 11%
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What system of equations would you use to solve the problem below?
A test is worth 100 points. Multiple-choice questions are worth 3 points and
short-answer questions are worth 5 points. If the test has 28 questions, how
many multiple-choice questions are there?
Let x be multiple-choice questions
Let y be short-answer questions
x + y = 28
3x + 5y = 100
Find the formula for the area of the shaded region in the figure.
x² = 4py
ہے
The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
What is the formula for the area of the shaded region in the figure?Parameters
[tex]$x^{2}=4 p y$[/tex]
[tex]$y=h$[/tex]
[tex]\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\[/tex]
Generally, the equation for the Area is mathematically given as
[tex]& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\[/tex]
[tex]&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
In conclusion, the equation for the Area is
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
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Please answer all 5 xoxo <3
Answer:
First Image: Option D
Second Image: Option D
Third Image: Option C
Fourth Image: Option B
Fifth Image: Option B
Step-by-step explanation:
First Image:
Supplementary angles is two angles whose sum is 180 degrees (straight line)180 - 47 = 133°? is an obtuse angle is any angle greater than 90° which checks the answerSecond Image:
A triangle angles adds up to 180° Two angles are already given72 + 45 + ? = 180° → 117 + ? = 180° → ? = 63°? is an acute angle is an angle that measures between 90° and 0°Third Image:
Supplementary angles is two angles whose sum is 180 degrees (straight line)180 - 110 = 70°? is an acute angle is an angle that measures between 90° and 0°Fourth Image:
Supplementary angles is two angles whose sum is 180 degrees (straight line)180 - 120 = 60°we are shown a right angle which = 90°A triangle adds up to 180° 180 - 90 - 60 = 30? = 30°? is an acute angle is an angle that measures between 90° and 0°Fifth Image:
Supplementary angles is two angles whose sum is 180 degrees (straight line)180 - 85 = 95°? is an obtuse angle is any angle greater than 90° which checks the answerLearn more about Triangles here: https://brainly.com/question/4186813
What number comes next in the sequence?
1, 1, 2, 3, 5, 8, 13, 21, 34, ?
Answer:
55
Step-by-step explanation:
1+1 = 2
1+2 = 3
2+3 = 5
3+5 = 8
5+8 = 13
8+13 = 21
13+21 = 34
21 +34 = 55
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